Tel de breuken op
- \(\frac{-3}{7}+\frac{10}{3}\)
- \(\frac{-9}{19}+\frac{6}{5}\)
- \(\frac{-2}{15}+\frac{15}{8}\)
- \(\frac{9}{14}+\frac{8}{13}\)
- \(\frac{-2}{13}+\frac{4}{9}\)
- \(\frac{15}{4}+\frac{10}{9}\)
- \(\frac{3}{14}+\frac{20}{17}\)
- \(\frac{7}{3}+\frac{14}{9}\)
- \(\frac{-3}{13}+\frac{15}{2}\)
- \(\frac{-18}{11}+\frac{2}{7}\)
- \(\frac{3}{2}+\frac{7}{9}\)
- \(\frac{1}{4}+\frac{4}{9}\)
Tel de breuken op
Verbetersleutel
- \(\frac{-3}{7}+\frac{10}{3}\\=\frac{-9}{21}+\frac{70}{21}\\=\frac{-9+70}{21}\\=\frac{61}{21}\)
- \(\frac{-9}{19}+\frac{6}{5}\\=\frac{-45}{95}+\frac{114}{95}\\=\frac{-45+114}{95}\\=\frac{69}{95}\)
- \(\frac{-2}{15}+\frac{15}{8}\\=\frac{-16}{120}+\frac{225}{120}\\=\frac{-16+225}{120}\\=\frac{209}{120}\)
- \(\frac{9}{14}+\frac{8}{13}\\=\frac{117}{182}+\frac{112}{182}\\=\frac{117+112}{182}\\=\frac{229}{182}\)
- \(\frac{-2}{13}+\frac{4}{9}\\=\frac{-18}{117}+\frac{52}{117}\\=\frac{-18+52}{117}\\=\frac{34}{117}\)
- \(\frac{15}{4}+\frac{10}{9}\\=\frac{135}{36}+\frac{40}{36}\\=\frac{135+40}{36}\\=\frac{175}{36}\)
- \(\frac{3}{14}+\frac{20}{17}\\=\frac{51}{238}+\frac{280}{238}\\=\frac{51+280}{238}\\=\frac{331}{238}\)
- \(\frac{7}{3}+\frac{14}{9}\\=\frac{21}{9}+\frac{14}{9}\\=\frac{21+14}{9}\\=\frac{35}{9}\)
- \(\frac{-3}{13}+\frac{15}{2}\\=\frac{-6}{26}+\frac{195}{26}\\=\frac{-6+195}{26}\\=\frac{189}{26}\)
- \(\frac{-18}{11}+\frac{2}{7}\\=\frac{-126}{77}+\frac{22}{77}\\=\frac{-126+22}{77}\\=\frac{-104}{77}\\=\frac{104}{-77}\)
- \(\frac{3}{2}+\frac{7}{9}\\=\frac{27}{18}+\frac{14}{18}\\=\frac{27+14}{18}\\=\frac{41}{18}\)
- \(\frac{1}{4}+\frac{4}{9}\\=\frac{9}{36}+\frac{16}{36}\\=\frac{9+16}{36}\\=\frac{25}{36}\)