Breuken optellen (reeks 1)

Hoofdmenu Eentje per keer 

Tel de breuken op

  1. \(\frac{6}{7}+\frac{8}{11}\)
  2. \(\frac{7}{6}+\frac{2}{3}\)
  3. \(\frac{4}{3}+\frac{2}{5}\)
  4. \(\frac{9}{10}+\frac{8}{9}\)
  5. \(\frac{3}{10}+\frac{2}{7}\)
  6. \(\frac{5}{2}+\frac{8}{5}\)
  7. \(\frac{8}{3}+\frac{8}{3}\)
  8. \(\frac{7}{2}+\frac{10}{7}\)
  9. \(\frac{9}{8}+\frac{8}{9}\)
  10. \(\frac{6}{5}+\frac{2}{5}\)
  11. \(\frac{7}{8}+\frac{5}{7}\)
  12. \(\frac{10}{7}+\frac{6}{11}\)

Tel de breuken op

Verbetersleutel

  1. \(\frac{6}{7}+\frac{8}{11}\\=\frac{66}{77}+\frac{56}{77}\\=\frac{66+56}{77}\\=\frac{122}{77}\)
  2. \(\frac{7}{6}+\frac{2}{3}\\=\frac{7+2}{6}\\=\frac{9}{6}\\=\frac{3}{2}\)
  3. \(\frac{4}{3}+\frac{2}{5}\\=\frac{20}{15}+\frac{6}{15}\\=\frac{20+6}{15}\\=\frac{26}{15}\)
  4. \(\frac{9}{10}+\frac{8}{9}\\=\frac{81}{90}+\frac{80}{90}\\=\frac{81+80}{90}\\=\frac{161}{90}\)
  5. \(\frac{3}{10}+\frac{2}{7}\\=\frac{21}{70}+\frac{20}{70}\\=\frac{21+20}{70}\\=\frac{41}{70}\)
  6. \(\frac{5}{2}+\frac{8}{5}\\=\frac{25}{10}+\frac{16}{10}\\=\frac{25+16}{10}\\=\frac{41}{10}\)
  7. \(\frac{8}{3}+\frac{8}{3}\\=\frac{8+8}{3}\\=\frac{16}{3}\)
  8. \(\frac{7}{2}+\frac{10}{7}\\=\frac{49}{14}+\frac{20}{14}\\=\frac{49+20}{14}\\=\frac{69}{14}\)
  9. \(\frac{9}{8}+\frac{8}{9}\\=\frac{81}{72}+\frac{64}{72}\\=\frac{81+64}{72}\\=\frac{145}{72}\)
  10. \(\frac{6}{5}+\frac{2}{5}\\=\frac{6+2}{5}\\=\frac{8}{5}\)
  11. \(\frac{7}{8}+\frac{5}{7}\\=\frac{49}{56}+\frac{40}{56}\\=\frac{49+40}{56}\\=\frac{89}{56}\)
  12. \(\frac{10}{7}+\frac{6}{11}\\=\frac{110}{77}+\frac{42}{77}\\=\frac{110+42}{77}\\=\frac{152}{77}\)
Oefeningengenerator wiskundeoefeningen.be 2026-03-14 05:34:10
Een site van Busleyden Atheneum Mechelen