Bepaal modulus en argument
- \(-1-6i\)
- \(-6-10i\)
- \(-8-5i\)
- \(1+10i\)
- \(-7+3i\)
- \(-7\)
- \(8-3i\)
- \(4+2i\)
- \(-3-3i\)
- \(4-i\)
- \(-7-10i\)
- \(2+7i\)
Bepaal modulus en argument
Verbetersleutel
- \(-1-6i\\ r = \sqrt{(-1)^2+(-6)^2} = \sqrt{37} \\ \alpha = tan^{-1}(\frac{-6}{-1}) \Leftrightarrow \alpha =80^\circ 32' 15{,}6"\text{ of } \alpha = 260^\circ 32' 15{,}6"\\-1-6i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 260^\circ 32' 15{,}6"\)
- \(-6-10i\\ r = \sqrt{(-6)^2+(-10)^2} = \sqrt{136} \\ \alpha = tan^{-1}(\frac{-10}{-6}) \Leftrightarrow \alpha =59^\circ 2' 10{,}5"\text{ of } \alpha = 239^\circ 2' 10{,}5"\\-6-10i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 239^\circ 2' 10{,}5"\)
- \(-8-5i\\ r = \sqrt{(-8)^2+(-5)^2} = \sqrt{89} \\ \alpha = tan^{-1}(\frac{-5}{-8}) \Leftrightarrow \alpha =32^\circ 0' 19{,}4"\text{ of } \alpha = 212^\circ 0' 19{,}4"\\-8-5i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 212^\circ 0' 19{,}4"\)
- \(1+10i\\ r = \sqrt{1^2+10^2} = \sqrt{101} \\ \alpha = tan^{-1}(\frac{10}{1}) \Leftrightarrow \alpha =84^\circ 17' 21{,}9"\text{ of } \alpha = 264^\circ 17' 21{,}9"\\1+10i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 84^\circ 17' 21{,}9"\)
- \(-7+3i\\ r = \sqrt{(-7)^2+3^2} = \sqrt{58} \\ \alpha = tan^{-1}(\frac{3}{-7}) \Leftrightarrow \alpha =156^\circ 48' 5{,}1"\text{ of } \alpha = 336^\circ 48' 5{,}1"\\-7+3i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 156^\circ 48' 5{,}1"\)
- \(-7\\ \text{ Dit complex getal ligt op het negatief gedeelte van de x-as. We hebben geen berekeningen nodig om r of } \alpha \text{ te berekenen.} \\\text{r = }7\\\alpha = 180 ^\circ \\\)
- \(8-3i\\ r = \sqrt{8^2+(-3)^2} = \sqrt{73} \\ \alpha = tan^{-1}(\frac{-3}{8}) \Leftrightarrow \alpha =159^\circ 26' 38{,}2"\text{ of } \alpha = 339^\circ 26' 38{,}2"\\8-3i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 339^\circ 26' 38{,}2"\)
- \(4+2i\\ r = \sqrt{4^2+2^2} = \sqrt{20} \\ \alpha = tan^{-1}(\frac{2}{4}) \Leftrightarrow \alpha =26^\circ 33' 54{,}2"\text{ of } \alpha = 206^\circ 33' 54{,}2"\\4+2i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 26^\circ 33' 54{,}2"\)
- \(-3-3i\\ r = \sqrt{(-3)^2+(-3)^2} = \sqrt{18} \\ \alpha = tan^{-1}(\frac{-3}{-3}) \Leftrightarrow \alpha =45^\circ \text{ of } \alpha = 225^\circ \\-3-3i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 225^\circ \)
- \(4-i\\ r = \sqrt{4^2+(-1)^2} = \sqrt{17} \\ \alpha = tan^{-1}(\frac{-1}{4}) \Leftrightarrow \alpha =165^\circ 57' 49{,}5"\text{ of } \alpha = 345^\circ 57' 49{,}5"\\4-i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 345^\circ 57' 49{,}5"\)
- \(-7-10i\\ r = \sqrt{(-7)^2+(-10)^2} = \sqrt{149} \\ \alpha = tan^{-1}(\frac{-10}{-7}) \Leftrightarrow \alpha =55^\circ 0' 28{,}7"\text{ of } \alpha = 235^\circ 0' 28{,}7"\\-7-10i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 235^\circ 0' 28{,}7"\)
- \(2+7i\\ r = \sqrt{2^2+7^2} = \sqrt{53} \\ \alpha = tan^{-1}(\frac{7}{2}) \Leftrightarrow \alpha =74^\circ 3' 16{,}6"\text{ of } \alpha = 254^\circ 3' 16{,}6"\\2+7i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 74^\circ 3' 16{,}6"\)