Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(36b^{16}-169p^2\)
  2. \(81p^{10}-144p^5+64\)
  3. \(s^2-9\)
  4. \(121x^2+198x+81\)
  5. \(25x^2-256a^{14}\)
  6. \(p^2+20p+100\)
  7. \(169p^2+26p+1\)
  8. \(9a^{10}-48a^5x+64x^2\)
  9. \(9s^2+60s+100\)
  10. \(1-9p^{16}\)
  11. \(q^2-81\)
  12. \(144b^{10}+24b^5p+1p^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(36b^{16}-169p^2=(6b^8+13p)(6b^8-13p)\)
  2. \(81p^{10}-144p^5+64=(9p^5-8)^2\)
  3. \(s^2-9=(s+3)(s-3)\)
  4. \(121x^2+198x+81=(11x+9)^2\)
  5. \(25x^2-256a^{14}=(5x-16a^7)(5x+16a^7)\)
  6. \(p^2+20p+100=(p+10)^2\)
  7. \(169p^2+26p+1=(13p+1)^2\)
  8. \(9a^{10}-48a^5x+64x^2=(3a^5-8x)^2\)
  9. \(9s^2+60s+100=(3s+10)^2\)
  10. \(1-9p^{16}=(1-3p^8)(1+3p^8)\)
  11. \(q^2-81=(q-9)(q+9)\)
  12. \(144b^{10}+24b^5p+1p^2=(12b^5+p)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-05-28 07:41:54
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