Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(36p^{6}+12p^3+1\)
  2. \(81x^2-256b^{8}\)
  3. \(121q^2-110q+25\)
  4. \(-25a^2+169\)
  5. \(144s^{10}-264s^5x+121x^2\)
  6. \(a^2-196\)
  7. \(-49q^2+1\)
  8. \(100p^{8}-49q^2\)
  9. \(121-144y^{12}\)
  10. \(121p^2-44p+4\)
  11. \(100a^{12}-9y^2\)
  12. \(4b^{10}-169\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(36p^{6}+12p^3+1=(6p^3+1)^2\)
  2. \(81x^2-256b^{8}=(9x-16b^4)(9x+16b^4)\)
  3. \(121q^2-110q+25=(11q-5)^2\)
  4. \(-25a^2+169=(13-5a)(13+5a)\)
  5. \(144s^{10}-264s^5x+121x^2=(12s^5-11x)^2\)
  6. \(a^2-196=(a-14)(a+14)\)
  7. \(-49q^2+1=(1-7q)(1+7q)\)
  8. \(100p^{8}-49q^2=(10p^4+7q)(10p^4-7q)\)
  9. \(121-144y^{12}=(11-12y^6)(11+12y^6)\)
  10. \(121p^2-44p+4=(11p-2)^2\)
  11. \(100a^{12}-9y^2=(10a^6+3y)(10a^6-3y)\)
  12. \(4b^{10}-169=(2b^5+13)(2b^5-13)\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-03 19:02:31
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