Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(121b^{12}-169y^2\)
  2. \(100q^{8}-260q^4x+169x^2\)
  3. \(81y^{12}-100\)
  4. \(49q^{4}-224q^2y+256y^2\)
  5. \(196p^{14}-81y^2\)
  6. \(49a^2-225\)
  7. \(36q^{10}-132q^5+121\)
  8. \(144y^{8}-264y^4+121\)
  9. \(121b^{6}-220b^3p+100p^2\)
  10. \(196s^2+28s+1\)
  11. \(256p^{8}+32p^4+1\)
  12. \(9b^{10}-30b^5p+25p^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(121b^{12}-169y^2=(11b^6+13y)(11b^6-13y)\)
  2. \(100q^{8}-260q^4x+169x^2=(10q^4-13x)^2\)
  3. \(81y^{12}-100=(9y^6+10)(9y^6-10)\)
  4. \(49q^{4}-224q^2y+256y^2=(7q^2-16y)^2\)
  5. \(196p^{14}-81y^2=(14p^7+9y)(14p^7-9y)\)
  6. \(49a^2-225=(7a+15)(7a-15)\)
  7. \(36q^{10}-132q^5+121=(6q^5-11)^2\)
  8. \(144y^{8}-264y^4+121=(12y^4-11)^2\)
  9. \(121b^{6}-220b^3p+100p^2=(11b^3-10p)^2\)
  10. \(196s^2+28s+1=(14s+1)^2\)
  11. \(256p^{8}+32p^4+1=(16p^4+1)^2\)
  12. \(9b^{10}-30b^5p+25p^2=(3b^5-5p)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-12 16:09:51
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