Ontbinden in factoren (1)

Hoofdmenu Eentje per keer 

Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(196p^{16}-81y^2\)
  2. \(64b^{14}-121s^2\)
  3. \(225-4a^{6}\)
  4. \(196b^{10}+84b^5+9\)
  5. \(36p^{8}+60p^4+25\)
  6. \(64p^2+80p+25\)
  7. \(y^2-16\)
  8. \(16b^{8}-120b^4x+225x^2\)
  9. \(25p^{4}-90p^2+81\)
  10. \(225b^{10}+330b^5+121\)
  11. \(256b^{4}+32b^2+1\)
  12. \(225q^{10}-49\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(196p^{16}-81y^2=(14p^8+9y)(14p^8-9y)\)
  2. \(64b^{14}-121s^2=(8b^7+11s)(8b^7-11s)\)
  3. \(225-4a^{6}=(15-2a^3)(15+2a^3)\)
  4. \(196b^{10}+84b^5+9=(14b^5+3)^2\)
  5. \(36p^{8}+60p^4+25=(6p^4+5)^2\)
  6. \(64p^2+80p+25=(8p+5)^2\)
  7. \(y^2-16=(y-4)(y+4)\)
  8. \(16b^{8}-120b^4x+225x^2=(4b^4-15x)^2\)
  9. \(25p^{4}-90p^2+81=(5p^2-9)^2\)
  10. \(225b^{10}+330b^5+121=(15b^5+11)^2\)
  11. \(256b^{4}+32b^2+1=(16b^2+1)^2\)
  12. \(225q^{10}-49=(15q^5+7)(15q^5-7)\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-07 08:13:04
Een site van Busleyden Atheneum Mechelen