Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(225q^2-420q+196\)
  2. \(121y^2-144a^{8}\)
  3. \(256a^{6}-160a^3p+25p^2\)
  4. \(49b^2-182b+169\)
  5. \(144x^{4}+120x^2+25\)
  6. \(-25s^2+121\)
  7. \(196a^{6}+28a^3+1\)
  8. \(x^2+30x+225\)
  9. \(144b^{10}-169\)
  10. \(81a^{10}-234a^5s+169s^2\)
  11. \(144a^{16}-169p^2\)
  12. \(121-81y^{12}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(225q^2-420q+196=(15q-14)^2\)
  2. \(121y^2-144a^{8}=(11y-12a^4)(11y+12a^4)\)
  3. \(256a^{6}-160a^3p+25p^2=(16a^3-5p)^2\)
  4. \(49b^2-182b+169=(7b-13)^2\)
  5. \(144x^{4}+120x^2+25=(12x^2+5)^2\)
  6. \(-25s^2+121=(11-5s)(11+5s)\)
  7. \(196a^{6}+28a^3+1=(14a^3+1)^2\)
  8. \(x^2+30x+225=(x+15)^2\)
  9. \(144b^{10}-169=(12b^5+13)(12b^5-13)\)
  10. \(81a^{10}-234a^5s+169s^2=(9a^5-13s)^2\)
  11. \(144a^{16}-169p^2=(12a^8+13p)(12a^8-13p)\)
  12. \(121-81y^{12}=(11-9y^6)(11+9y^6)\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-21 16:18:43
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