Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(64q^{14}-81s^2\)
  2. \(144a^{6}+312a^3b+169b^2\)
  3. \(81a^2-49\)
  4. \(x^2-196\)
  5. \(100p^2-49\)
  6. \(-25p^2+121\)
  7. \(9b^{6}+60b^3p+100p^2\)
  8. \(s^2-144\)
  9. \(25x^{6}-121y^2\)
  10. \(16s^{16}-49y^2\)
  11. \(100s^2-9\)
  12. \(81p^{6}+72p^3+16\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(64q^{14}-81s^2=(8q^7+9s)(8q^7-9s)\)
  2. \(144a^{6}+312a^3b+169b^2=(12a^3+13b)^2\)
  3. \(81a^2-49=(9a+7)(9a-7)\)
  4. \(x^2-196=(x-14)(x+14)\)
  5. \(100p^2-49=(10p+7)(10p-7)\)
  6. \(-25p^2+121=(11-5p)(11+5p)\)
  7. \(9b^{6}+60b^3p+100p^2=(3b^3+10p)^2\)
  8. \(s^2-144=(s+12)(s-12)\)
  9. \(25x^{6}-121y^2=(5x^3+11y)(5x^3-11y)\)
  10. \(16s^{16}-49y^2=(4s^8+7y)(4s^8-7y)\)
  11. \(100s^2-9=(10s+3)(10s-3)\)
  12. \(81p^{6}+72p^3+16=(9p^3+4)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-05-12 22:07:42
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