Ontbinden in factoren (1)

Hoofdmenu Eentje per keer 

Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(1-36a^{8}\)
  2. \(49q^{12}-25\)
  3. \(25p^{8}+110p^4q+121q^2\)
  4. \(169b^2-416b+256\)
  5. \(100b^{8}+20b^4q+1q^2\)
  6. \(121a^2+176a+64\)
  7. \(196a^{10}+28a^5+1\)
  8. \(196q^2+28q+1\)
  9. \(81s^2+252s+196\)
  10. \(196b^{4}-25x^2\)
  11. \(a^2-20a+100\)
  12. \(49s^2-81a^{10}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(1-36a^{8}=(1-6a^4)(1+6a^4)\)
  2. \(49q^{12}-25=(7q^6+5)(7q^6-5)\)
  3. \(25p^{8}+110p^4q+121q^2=(5p^4+11q)^2\)
  4. \(169b^2-416b+256=(13b-16)^2\)
  5. \(100b^{8}+20b^4q+1q^2=(10b^4+q)^2\)
  6. \(121a^2+176a+64=(11a+8)^2\)
  7. \(196a^{10}+28a^5+1=(14a^5+1)^2\)
  8. \(196q^2+28q+1=(14q+1)^2\)
  9. \(81s^2+252s+196=(9s+14)^2\)
  10. \(196b^{4}-25x^2=(14b^2+5x)(14b^2-5x)\)
  11. \(a^2-20a+100=(a-10)^2\)
  12. \(49s^2-81a^{10}=(7s-9a^5)(7s+9a^5)\)
Oefeningengenerator wiskundeoefeningen.be 2026-05-09 00:06:27
Een site van Busleyden Atheneum Mechelen