Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(y^2-9\)
  2. \(81-196b^{16}\)
  3. \(144b^{4}+24b^2+1\)
  4. \(1-16p^{4}\)
  5. \(49a^{8}-169\)
  6. \(-49b^2+64\)
  7. \(y^2+16y+64\)
  8. \(-49x^2+100\)
  9. \(225p^{8}+210p^4y+49y^2\)
  10. \(196s^2-225p^{14}\)
  11. \(4q^{8}-169x^2\)
  12. \(169a^{4}+234a^2+81\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(y^2-9=(y-3)(y+3)\)
  2. \(81-196b^{16}=(9-14b^8)(9+14b^8)\)
  3. \(144b^{4}+24b^2+1=(12b^2+1)^2\)
  4. \(1-16p^{4}=(1-4p^2)(1+4p^2)\)
  5. \(49a^{8}-169=(7a^4+13)(7a^4-13)\)
  6. \(-49b^2+64=(8-7b)(8+7b)\)
  7. \(y^2+16y+64=(y+8)^2\)
  8. \(-49x^2+100=(10-7x)(10+7x)\)
  9. \(225p^{8}+210p^4y+49y^2=(15p^4+7y)^2\)
  10. \(196s^2-225p^{14}=(14s-15p^7)(14s+15p^7)\)
  11. \(4q^{8}-169x^2=(2q^4+13x)(2q^4-13x)\)
  12. \(169a^{4}+234a^2+81=(13a^2+9)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-15 16:35:04
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