Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(225s^{6}-60s^3+4\)
  2. \(169p^{12}-9x^2\)
  3. \(64b^{10}-208b^5+169\)
  4. \(x^2-10x+25\)
  5. \(b^2-14b+49\)
  6. \(100b^{8}-180b^4+81\)
  7. \(s^{12}-25x^2\)
  8. \(81b^{10}-16\)
  9. \(169a^{8}+286a^4s+121s^2\)
  10. \(y^2-20y+100\)
  11. \(s^2-4\)
  12. \(25b^{6}-49y^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(225s^{6}-60s^3+4=(15s^3-2)^2\)
  2. \(169p^{12}-9x^2=(13p^6+3x)(13p^6-3x)\)
  3. \(64b^{10}-208b^5+169=(8b^5-13)^2\)
  4. \(x^2-10x+25=(x-5)^2\)
  5. \(b^2-14b+49=(b-7)^2\)
  6. \(100b^{8}-180b^4+81=(10b^4-9)^2\)
  7. \(s^{12}-25x^2=(s^6+5x)(s^6-5x)\)
  8. \(81b^{10}-16=(9b^5+4)(9b^5-4)\)
  9. \(169a^{8}+286a^4s+121s^2=(13a^4+11s)^2\)
  10. \(y^2-20y+100=(y-10)^2\)
  11. \(s^2-4=(s+2)(s-2)\)
  12. \(25b^{6}-49y^2=(5b^3+7y)(5b^3-7y)\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-30 19:40:14
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