Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(169b^{12}-1\)
  2. \(256b^{10}+288b^5+81\)
  3. \(25x^{6}+110x^3y+121y^2\)
  4. \(144y^{4}+168y^2+49\)
  5. \(y^2+30y+225\)
  6. \(81p^2-4b^{10}\)
  7. \(9a^2-84a+196\)
  8. \(a^{16}-9q^2\)
  9. \(25y^2-144p^{10}\)
  10. \(s^2-169\)
  11. \(49s^{4}-126s^2+81\)
  12. \(81y^2+198y+121\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(169b^{12}-1=(13b^6+1)(13b^6-1)\)
  2. \(256b^{10}+288b^5+81=(16b^5+9)^2\)
  3. \(25x^{6}+110x^3y+121y^2=(5x^3+11y)^2\)
  4. \(144y^{4}+168y^2+49=(12y^2+7)^2\)
  5. \(y^2+30y+225=(y+15)^2\)
  6. \(81p^2-4b^{10}=(9p-2b^5)(9p+2b^5)\)
  7. \(9a^2-84a+196=(3a-14)^2\)
  8. \(a^{16}-9q^2=(a^8+3q)(a^8-3q)\)
  9. \(25y^2-144p^{10}=(5y-12p^5)(5y+12p^5)\)
  10. \(s^2-169=(s-13)(s+13)\)
  11. \(49s^{4}-126s^2+81=(7s^2-9)^2\)
  12. \(81y^2+198y+121=(9y+11)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-21 11:05:09
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