Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(256p^2-9\)
  2. \(169b^{16}-4p^2\)
  3. \(196a^{6}+28a^3y+1y^2\)
  4. \(225p^{8}-60p^4y+4y^2\)
  5. \(-25y^2+81\)
  6. \(9s^2-121\)
  7. \(36a^2-49\)
  8. \(121b^{4}-352b^2x+256x^2\)
  9. \(121-16p^{10}\)
  10. \(81y^2-64\)
  11. \(4q^{8}+60q^4y+225y^2\)
  12. \(121a^{8}+330a^4q+225q^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(256p^2-9=(16p+3)(16p-3)\)
  2. \(169b^{16}-4p^2=(13b^8+2p)(13b^8-2p)\)
  3. \(196a^{6}+28a^3y+1y^2=(14a^3+y)^2\)
  4. \(225p^{8}-60p^4y+4y^2=(15p^4-2y)^2\)
  5. \(-25y^2+81=(9-5y)(9+5y)\)
  6. \(9s^2-121=(3s+11)(3s-11)\)
  7. \(36a^2-49=(6a+7)(6a-7)\)
  8. \(121b^{4}-352b^2x+256x^2=(11b^2-16x)^2\)
  9. \(121-16p^{10}=(11-4p^5)(11+4p^5)\)
  10. \(81y^2-64=(9y+8)(9y-8)\)
  11. \(4q^{8}+60q^4y+225y^2=(2q^4+15y)^2\)
  12. \(121a^{8}+330a^4q+225q^2=(11a^4+15q)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-02 08:53:32
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