Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(121p^{4}+22p^2q+1q^2\)
  2. \(p^2-49\)
  3. \(64s^{8}+240s^4+225\)
  4. \(81x^2-256s^{12}\)
  5. \(196a^2-25\)
  6. \(b^2-9\)
  7. \(25p^{4}-140p^2+196\)
  8. \(100p^{4}+260p^2+169\)
  9. \(p^2-25\)
  10. \(9-16a^{10}\)
  11. \(100s^2-180s+81\)
  12. \(196b^{10}+252b^5p+81p^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(121p^{4}+22p^2q+1q^2=(11p^2+q)^2\)
  2. \(p^2-49=(p-7)(p+7)\)
  3. \(64s^{8}+240s^4+225=(8s^4+15)^2\)
  4. \(81x^2-256s^{12}=(9x-16s^6)(9x+16s^6)\)
  5. \(196a^2-25=(14a+5)(14a-5)\)
  6. \(b^2-9=(b-3)(b+3)\)
  7. \(25p^{4}-140p^2+196=(5p^2-14)^2\)
  8. \(100p^{4}+260p^2+169=(10p^2+13)^2\)
  9. \(p^2-25=(p-5)(p+5)\)
  10. \(9-16a^{10}=(3-4a^5)(3+4a^5)\)
  11. \(100s^2-180s+81=(10s-9)^2\)
  12. \(196b^{10}+252b^5p+81p^2=(14b^5+9p)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-28 19:39:16
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