Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(169-256x^{4}\)
  2. \(49-81p^{8}\)
  3. \(196a^{6}+364a^3y+169y^2\)
  4. \(49a^{4}+28a^2+4\)
  5. \(x^2-10x+25\)
  6. \(y^2-8y+16\)
  7. \(49s^2-42s+9\)
  8. \(225q^{10}+120q^5s+16s^2\)
  9. \(64b^2-1\)
  10. \(81p^{4}-1\)
  11. \(25-4a^{16}\)
  12. \(25y^2-36a^{6}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(169-256x^{4}=(13-16x^2)(13+16x^2)\)
  2. \(49-81p^{8}=(7-9p^4)(7+9p^4)\)
  3. \(196a^{6}+364a^3y+169y^2=(14a^3+13y)^2\)
  4. \(49a^{4}+28a^2+4=(7a^2+2)^2\)
  5. \(x^2-10x+25=(x-5)^2\)
  6. \(y^2-8y+16=(y-4)^2\)
  7. \(49s^2-42s+9=(7s-3)^2\)
  8. \(225q^{10}+120q^5s+16s^2=(15q^5+4s)^2\)
  9. \(64b^2-1=(8b+1)(8b-1)\)
  10. \(81p^{4}-1=(9p^2+1)(9p^2-1)\)
  11. \(25-4a^{16}=(5-2a^8)(5+2a^8)\)
  12. \(25y^2-36a^{6}=(5y-6a^3)(5y+6a^3)\)
Oefeningengenerator wiskundeoefeningen.be 2026-09-20 05:29:35
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