Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(196a^2-81\)
  2. \(4y^2-49a^{10}\)
  3. \(225q^2+390q+169\)
  4. \(36a^{10}-132a^5+121\)
  5. \(9q^2-4\)
  6. \(196y^{10}+28y^5+1\)
  7. \(a^2+30a+225\)
  8. \(196y^{6}+252y^3+81\)
  9. \(100p^{16}-9\)
  10. \(q^2+18q+81\)
  11. \(64s^2-9q^{10}\)
  12. \(36b^{4}+132b^2p+121p^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(196a^2-81=(14a+9)(14a-9)\)
  2. \(4y^2-49a^{10}=(2y-7a^5)(2y+7a^5)\)
  3. \(225q^2+390q+169=(15q+13)^2\)
  4. \(36a^{10}-132a^5+121=(6a^5-11)^2\)
  5. \(9q^2-4=(3q+2)(3q-2)\)
  6. \(196y^{10}+28y^5+1=(14y^5+1)^2\)
  7. \(a^2+30a+225=(a+15)^2\)
  8. \(196y^{6}+252y^3+81=(14y^3+9)^2\)
  9. \(100p^{16}-9=(10p^8+3)(10p^8-3)\)
  10. \(q^2+18q+81=(q+9)^2\)
  11. \(64s^2-9q^{10}=(8s-3q^5)(8s+3q^5)\)
  12. \(36b^{4}+132b^2p+121p^2=(6b^2+11p)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-04-19 16:50:45
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