Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(4s^2-9a^{12}\)
  2. \(64p^{8}+208p^4y+169y^2\)
  3. \(81y^2-4\)
  4. \(169x^2-196p^{14}\)
  5. \(b^2+14b+49\)
  6. \(9a^{4}-196\)
  7. \(y^2-49\)
  8. \(81x^2-16b^{6}\)
  9. \(a^2-10a+25\)
  10. \(225p^{8}-49\)
  11. \(64s^2+16s+1\)
  12. \(81p^{6}-72p^3x+16x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(4s^2-9a^{12}=(2s-3a^6)(2s+3a^6)\)
  2. \(64p^{8}+208p^4y+169y^2=(8p^4+13y)^2\)
  3. \(81y^2-4=(9y+2)(9y-2)\)
  4. \(169x^2-196p^{14}=(13x-14p^7)(13x+14p^7)\)
  5. \(b^2+14b+49=(b+7)^2\)
  6. \(9a^{4}-196=(3a^2+14)(3a^2-14)\)
  7. \(y^2-49=(y+7)(y-7)\)
  8. \(81x^2-16b^{6}=(9x-4b^3)(9x+4b^3)\)
  9. \(a^2-10a+25=(a-5)^2\)
  10. \(225p^{8}-49=(15p^4+7)(15p^4-7)\)
  11. \(64s^2+16s+1=(8s+1)^2\)
  12. \(81p^{6}-72p^3x+16x^2=(9p^3-4x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2025-12-02 06:21:20
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