Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(121y^{10}+132y^5+36\)
  2. \(x^2-169\)
  3. \(36a^{4}-132a^2+121\)
  4. \(196p^{8}+28p^4s+1s^2\)
  5. \(25-169s^{10}\)
  6. \(9q^2-66q+121\)
  7. \(25q^2-90q+81\)
  8. \(16x^2+8x+1\)
  9. \(225q^{6}+210q^3s+49s^2\)
  10. \(225q^2-49\)
  11. \(169p^2-81\)
  12. \(225p^{6}-4q^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(121y^{10}+132y^5+36=(11y^5+6)^2\)
  2. \(x^2-169=(x+13)(x-13)\)
  3. \(36a^{4}-132a^2+121=(6a^2-11)^2\)
  4. \(196p^{8}+28p^4s+1s^2=(14p^4+s)^2\)
  5. \(25-169s^{10}=(5-13s^5)(5+13s^5)\)
  6. \(9q^2-66q+121=(3q-11)^2\)
  7. \(25q^2-90q+81=(5q-9)^2\)
  8. \(16x^2+8x+1=(4x+1)^2\)
  9. \(225q^{6}+210q^3s+49s^2=(15q^3+7s)^2\)
  10. \(225q^2-49=(15q+7)(15q-7)\)
  11. \(169p^2-81=(13p+9)(13p-9)\)
  12. \(225p^{6}-4q^2=(15p^3+2q)(15p^3-2q)\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-13 02:42:58
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