Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(-256x^2+1\)
  2. \(121-49x^{16}\)
  3. \(64y^{6}+16y^3+1\)
  4. \(225a^{10}+240a^5q+64q^2\)
  5. \(64-81a^{10}\)
  6. \(144y^2-264y+121\)
  7. \(144b^{6}-1\)
  8. \(256b^{6}-225s^2\)
  9. \(16s^2-25q^{10}\)
  10. \(121q^2-36p^{14}\)
  11. \(25p^2-256a^{8}\)
  12. \(9s^2-4b^{12}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(-256x^2+1=(1-16x)(1+16x)\)
  2. \(121-49x^{16}=(11-7x^8)(11+7x^8)\)
  3. \(64y^{6}+16y^3+1=(8y^3+1)^2\)
  4. \(225a^{10}+240a^5q+64q^2=(15a^5+8q)^2\)
  5. \(64-81a^{10}=(8-9a^5)(8+9a^5)\)
  6. \(144y^2-264y+121=(12y-11)^2\)
  7. \(144b^{6}-1=(12b^3+1)(12b^3-1)\)
  8. \(256b^{6}-225s^2=(16b^3+15s)(16b^3-15s)\)
  9. \(16s^2-25q^{10}=(4s-5q^5)(4s+5q^5)\)
  10. \(121q^2-36p^{14}=(11q-6p^7)(11q+6p^7)\)
  11. \(25p^2-256a^{8}=(5p-16a^4)(5p+16a^4)\)
  12. \(9s^2-4b^{12}=(3s-2b^6)(3s+2b^6)\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-11 11:42:34
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