Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(81a^{8}-72a^4x+16x^2\)
  2. \(196p^{8}-25x^2\)
  3. \(9s^{6}+48s^3y+64y^2\)
  4. \(81q^2+126q+49\)
  5. \(36a^{10}+12a^5s+1s^2\)
  6. \(81y^{10}-25\)
  7. \(169p^2-16b^{12}\)
  8. \(49-81b^{12}\)
  9. \(a^2-169\)
  10. \(16b^2-9\)
  11. \(a^2-4\)
  12. \(49x^2-25a^{16}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(81a^{8}-72a^4x+16x^2=(9a^4-4x)^2\)
  2. \(196p^{8}-25x^2=(14p^4+5x)(14p^4-5x)\)
  3. \(9s^{6}+48s^3y+64y^2=(3s^3+8y)^2\)
  4. \(81q^2+126q+49=(9q+7)^2\)
  5. \(36a^{10}+12a^5s+1s^2=(6a^5+s)^2\)
  6. \(81y^{10}-25=(9y^5+5)(9y^5-5)\)
  7. \(169p^2-16b^{12}=(13p-4b^6)(13p+4b^6)\)
  8. \(49-81b^{12}=(7-9b^6)(7+9b^6)\)
  9. \(a^2-169=(a+13)(a-13)\)
  10. \(16b^2-9=(4b+3)(4b-3)\)
  11. \(a^2-4=(a-2)(a+2)\)
  12. \(49x^2-25a^{16}=(7x-5a^8)(7x+5a^8)\)
Oefeningengenerator wiskundeoefeningen.be 2026-09-01 16:55:20
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