Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(64-49y^{12}\)
  2. \(4-25y^{4}\)
  3. \(49b^{4}-28b^2q+4q^2\)
  4. \(16q^2+24q+9\)
  5. \(-25x^2+1\)
  6. \(x^2+28x+196\)
  7. \(64y^{10}+48y^5+9\)
  8. \(49a^{10}+14a^5b+1b^2\)
  9. \(225s^{8}+210s^4y+49y^2\)
  10. \(121x^2-9p^{14}\)
  11. \(196b^{6}+28b^3+1\)
  12. \(9q^2-16a^{14}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(64-49y^{12}=(8-7y^6)(8+7y^6)\)
  2. \(4-25y^{4}=(2-5y^2)(2+5y^2)\)
  3. \(49b^{4}-28b^2q+4q^2=(7b^2-2q)^2\)
  4. \(16q^2+24q+9=(4q+3)^2\)
  5. \(-25x^2+1=(1-5x)(1+5x)\)
  6. \(x^2+28x+196=(x+14)^2\)
  7. \(64y^{10}+48y^5+9=(8y^5+3)^2\)
  8. \(49a^{10}+14a^5b+1b^2=(7a^5+b)^2\)
  9. \(225s^{8}+210s^4y+49y^2=(15s^4+7y)^2\)
  10. \(121x^2-9p^{14}=(11x-3p^7)(11x+3p^7)\)
  11. \(196b^{6}+28b^3+1=(14b^3+1)^2\)
  12. \(9q^2-16a^{14}=(3q-4a^7)(3q+4a^7)\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-25 01:30:08
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