Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(49-100a^{6}\)
  2. \(y^2-81\)
  3. \(100x^{4}+220x^2+121\)
  4. \(256s^2-1\)
  5. \(25y^2-36p^{14}\)
  6. \(9y^{4}+30y^2+25\)
  7. \(64a^{8}-112a^4p+49p^2\)
  8. \(256y^{6}+480y^3+225\)
  9. \(49x^{16}-9y^2\)
  10. \(49q^{14}-81\)
  11. \(s^2-24s+144\)
  12. \(9x^2-1\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(49-100a^{6}=(7-10a^3)(7+10a^3)\)
  2. \(y^2-81=(y+9)(y-9)\)
  3. \(100x^{4}+220x^2+121=(10x^2+11)^2\)
  4. \(256s^2-1=(16s+1)(16s-1)\)
  5. \(25y^2-36p^{14}=(5y-6p^7)(5y+6p^7)\)
  6. \(9y^{4}+30y^2+25=(3y^2+5)^2\)
  7. \(64a^{8}-112a^4p+49p^2=(8a^4-7p)^2\)
  8. \(256y^{6}+480y^3+225=(16y^3+15)^2\)
  9. \(49x^{16}-9y^2=(7x^8+3y)(7x^8-3y)\)
  10. \(49q^{14}-81=(7q^7+9)(7q^7-9)\)
  11. \(s^2-24s+144=(s-12)^2\)
  12. \(9x^2-1=(3x+1)(3x-1)\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-13 18:15:25
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