Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(q^2+8q+16\)
  2. \(b^2+18b+81\)
  3. \(p^2+4p+4\)
  4. \(x^2-20x+100\)
  5. \(225y^2-420y+196\)
  6. \(196a^{4}+28a^2+1\)
  7. \(100x^2-81b^{4}\)
  8. \(64a^{6}-81\)
  9. \(169a^{8}-81p^2\)
  10. \(81p^{6}-16y^2\)
  11. \(25b^2-20b+4\)
  12. \(121b^{6}-176b^3p+64p^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(q^2+8q+16=(q+4)^2\)
  2. \(b^2+18b+81=(b+9)^2\)
  3. \(p^2+4p+4=(p+2)^2\)
  4. \(x^2-20x+100=(x-10)^2\)
  5. \(225y^2-420y+196=(15y-14)^2\)
  6. \(196a^{4}+28a^2+1=(14a^2+1)^2\)
  7. \(100x^2-81b^{4}=(10x-9b^2)(10x+9b^2)\)
  8. \(64a^{6}-81=(8a^3+9)(8a^3-9)\)
  9. \(169a^{8}-81p^2=(13a^4+9p)(13a^4-9p)\)
  10. \(81p^{6}-16y^2=(9p^3+4y)(9p^3-4y)\)
  11. \(25b^2-20b+4=(5b-2)^2\)
  12. \(121b^{6}-176b^3p+64p^2=(11b^3-8p)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-02-08 03:05:33
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