Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(169-36s^{8}\)
  2. \(9p^{10}+78p^5x+169x^2\)
  3. \(a^2-22a+121\)
  4. \(121p^2-16\)
  5. \(x^2-36\)
  6. \(16a^{6}-225\)
  7. \(169-225b^{16}\)
  8. \(a^2+24a+144\)
  9. \(-49s^2+81\)
  10. \(9a^{6}-84a^3+196\)
  11. \(169a^2-130a+25\)
  12. \(169a^{6}+260a^3b+100b^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(169-36s^{8}=(13-6s^4)(13+6s^4)\)
  2. \(9p^{10}+78p^5x+169x^2=(3p^5+13x)^2\)
  3. \(a^2-22a+121=(a-11)^2\)
  4. \(121p^2-16=(11p+4)(11p-4)\)
  5. \(x^2-36=(x-6)(x+6)\)
  6. \(16a^{6}-225=(4a^3+15)(4a^3-15)\)
  7. \(169-225b^{16}=(13-15b^8)(13+15b^8)\)
  8. \(a^2+24a+144=(a+12)^2\)
  9. \(-49s^2+81=(9-7s)(9+7s)\)
  10. \(9a^{6}-84a^3+196=(3a^3-14)^2\)
  11. \(169a^2-130a+25=(13a-5)^2\)
  12. \(169a^{6}+260a^3b+100b^2=(13a^3+10b)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-17 19:27:39
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