Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(256b^{8}+160b^4p+25p^2\)
  2. \(81b^{4}-234b^2q+169q^2\)
  3. \(169y^{10}+78y^5+9\)
  4. \(4a^{6}+4a^3q+1q^2\)
  5. \(256a^{8}-480a^4+225\)
  6. \(256x^2-25\)
  7. \(121y^2-256p^{10}\)
  8. \(121x^{14}-144\)
  9. \(196x^{6}-252x^3+81\)
  10. \(p^2-6p+9\)
  11. \(225a^2-420a+196\)
  12. \(a^2-25\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(256b^{8}+160b^4p+25p^2=(16b^4+5p)^2\)
  2. \(81b^{4}-234b^2q+169q^2=(9b^2-13q)^2\)
  3. \(169y^{10}+78y^5+9=(13y^5+3)^2\)
  4. \(4a^{6}+4a^3q+1q^2=(2a^3+q)^2\)
  5. \(256a^{8}-480a^4+225=(16a^4-15)^2\)
  6. \(256x^2-25=(16x+5)(16x-5)\)
  7. \(121y^2-256p^{10}=(11y-16p^5)(11y+16p^5)\)
  8. \(121x^{14}-144=(11x^7+12)(11x^7-12)\)
  9. \(196x^{6}-252x^3+81=(14x^3-9)^2\)
  10. \(p^2-6p+9=(p-3)^2\)
  11. \(225a^2-420a+196=(15a-14)^2\)
  12. \(a^2-25=(a+5)(a-5)\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-26 12:07:25
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