Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(b^2+22b+121\)
  2. \(81a^{14}-100x^2\)
  3. \(144b^{6}+24b^3+1\)
  4. \(9-16q^{4}\)
  5. \(s^2-100\)
  6. \(49b^2+42b+9\)
  7. \(256p^{8}-288p^4s+81s^2\)
  8. \(36b^{4}-25\)
  9. \(9y^{6}-16\)
  10. \(x^2+28x+196\)
  11. \(-121a^2+64\)
  12. \(100s^{4}+140s^2x+49x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(b^2+22b+121=(b+11)^2\)
  2. \(81a^{14}-100x^2=(9a^7+10x)(9a^7-10x)\)
  3. \(144b^{6}+24b^3+1=(12b^3+1)^2\)
  4. \(9-16q^{4}=(3-4q^2)(3+4q^2)\)
  5. \(s^2-100=(s-10)(s+10)\)
  6. \(49b^2+42b+9=(7b+3)^2\)
  7. \(256p^{8}-288p^4s+81s^2=(16p^4-9s)^2\)
  8. \(36b^{4}-25=(6b^2+5)(6b^2-5)\)
  9. \(9y^{6}-16=(3y^3+4)(3y^3-4)\)
  10. \(x^2+28x+196=(x+14)^2\)
  11. \(-121a^2+64=(8-11a)(8+11a)\)
  12. \(100s^{4}+140s^2x+49x^2=(10s^2+7x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-29 23:48:25
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