Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(81x^2-16q^{8}\)
  2. \(121s^2-196b^{6}\)
  3. \(121q^{8}-220q^4+100\)
  4. \(9p^{4}-84p^2+196\)
  5. \(81-121s^{4}\)
  6. \(256q^{4}-160q^2+25\)
  7. \(q^2+10q+25\)
  8. \(49q^2+42q+9\)
  9. \(81-25y^{8}\)
  10. \(-144q^2+169\)
  11. \(100q^2-81\)
  12. \(4s^{8}+28s^4y+49y^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(81x^2-16q^{8}=(9x-4q^4)(9x+4q^4)\)
  2. \(121s^2-196b^{6}=(11s-14b^3)(11s+14b^3)\)
  3. \(121q^{8}-220q^4+100=(11q^4-10)^2\)
  4. \(9p^{4}-84p^2+196=(3p^2-14)^2\)
  5. \(81-121s^{4}=(9-11s^2)(9+11s^2)\)
  6. \(256q^{4}-160q^2+25=(16q^2-5)^2\)
  7. \(q^2+10q+25=(q+5)^2\)
  8. \(49q^2+42q+9=(7q+3)^2\)
  9. \(81-25y^{8}=(9-5y^4)(9+5y^4)\)
  10. \(-144q^2+169=(13-12q)(13+12q)\)
  11. \(100q^2-81=(10q+9)(10q-9)\)
  12. \(4s^{8}+28s^4y+49y^2=(2s^4+7y)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-15 23:10:34
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