Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(49b^{4}-182b^2+169\)
  2. \(196a^{6}-252a^3q+81q^2\)
  3. \(81b^{14}-121\)
  4. \(a^2+18a+81\)
  5. \(169-100s^{8}\)
  6. \(256b^{6}+416b^3y+169y^2\)
  7. \(25x^{6}+120x^3+144\)
  8. \(b^{4}-49y^2\)
  9. \(81y^2+72y+16\)
  10. \(64s^{10}-1\)
  11. \(25q^{4}-36y^2\)
  12. \(121b^{10}+22b^5y+1y^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(49b^{4}-182b^2+169=(7b^2-13)^2\)
  2. \(196a^{6}-252a^3q+81q^2=(14a^3-9q)^2\)
  3. \(81b^{14}-121=(9b^7+11)(9b^7-11)\)
  4. \(a^2+18a+81=(a+9)^2\)
  5. \(169-100s^{8}=(13-10s^4)(13+10s^4)\)
  6. \(256b^{6}+416b^3y+169y^2=(16b^3+13y)^2\)
  7. \(25x^{6}+120x^3+144=(5x^3+12)^2\)
  8. \(b^{4}-49y^2=(b^2+7y)(b^2-7y)\)
  9. \(81y^2+72y+16=(9y+4)^2\)
  10. \(64s^{10}-1=(8s^5+1)(8s^5-1)\)
  11. \(25q^{4}-36y^2=(5q^2+6y)(5q^2-6y)\)
  12. \(121b^{10}+22b^5y+1y^2=(11b^5+y)^2\)
Oefeningengenerator wiskundeoefeningen.be 2024-11-21 07:23:27
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