Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(81b^{4}-72b^2p+16p^2\)
  2. \(169q^{4}-156q^2+36\)
  3. \(121y^2-81\)
  4. \(121b^{4}-44b^2+4\)
  5. \(64a^{16}-81\)
  6. \(q^2+16q+64\)
  7. \(49b^{6}+168b^3p+144p^2\)
  8. \(y^2-14y+49\)
  9. \(b^{8}-25y^2\)
  10. \(225a^{4}-330a^2y+121y^2\)
  11. \(81a^{14}-100q^2\)
  12. \(100x^{6}-1\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(81b^{4}-72b^2p+16p^2=(9b^2-4p)^2\)
  2. \(169q^{4}-156q^2+36=(13q^2-6)^2\)
  3. \(121y^2-81=(11y+9)(11y-9)\)
  4. \(121b^{4}-44b^2+4=(11b^2-2)^2\)
  5. \(64a^{16}-81=(8a^8+9)(8a^8-9)\)
  6. \(q^2+16q+64=(q+8)^2\)
  7. \(49b^{6}+168b^3p+144p^2=(7b^3+12p)^2\)
  8. \(y^2-14y+49=(y-7)^2\)
  9. \(b^{8}-25y^2=(b^4+5y)(b^4-5y)\)
  10. \(225a^{4}-330a^2y+121y^2=(15a^2-11y)^2\)
  11. \(81a^{14}-100q^2=(9a^7+10q)(9a^7-10q)\)
  12. \(100x^{6}-1=(10x^3+1)(10x^3-1)\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-17 05:57:33
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