Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(4s^2+4s+1\)
  2. \(9x^2-121\)
  3. \(169a^{10}-4q^2\)
  4. \(49b^{6}-140b^3p+100p^2\)
  5. \(25b^2-16\)
  6. \(144x^{8}-264x^4y+121y^2\)
  7. \(9b^{8}+24b^4s+16s^2\)
  8. \(s^2-121\)
  9. \(25s^{10}-49\)
  10. \(64q^{10}+16q^5+1\)
  11. \(256p^{10}+224p^5+49\)
  12. \(16p^{6}+8p^3x+1x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(4s^2+4s+1=(2s+1)^2\)
  2. \(9x^2-121=(3x+11)(3x-11)\)
  3. \(169a^{10}-4q^2=(13a^5+2q)(13a^5-2q)\)
  4. \(49b^{6}-140b^3p+100p^2=(7b^3-10p)^2\)
  5. \(25b^2-16=(5b+4)(5b-4)\)
  6. \(144x^{8}-264x^4y+121y^2=(12x^4-11y)^2\)
  7. \(9b^{8}+24b^4s+16s^2=(3b^4+4s)^2\)
  8. \(s^2-121=(s-11)(s+11)\)
  9. \(25s^{10}-49=(5s^5+7)(5s^5-7)\)
  10. \(64q^{10}+16q^5+1=(8q^5+1)^2\)
  11. \(256p^{10}+224p^5+49=(16p^5+7)^2\)
  12. \(16p^{6}+8p^3x+1x^2=(4p^3+x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-22 08:03:31
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