Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(25a^{8}+80a^4q+64q^2\)
  2. \(4s^2-121p^{6}\)
  3. \(16y^{8}-1\)
  4. \(x^2-6x+9\)
  5. \(100s^{4}-180s^2x+81x^2\)
  6. \(b^2-9\)
  7. \(25x^2+140x+196\)
  8. \(9p^2+6p+1\)
  9. \(4s^2-1\)
  10. \(121q^{4}-286q^2y+169y^2\)
  11. \(-256p^2+81\)
  12. \(16q^{10}+104q^5+169\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(25a^{8}+80a^4q+64q^2=(5a^4+8q)^2\)
  2. \(4s^2-121p^{6}=(2s-11p^3)(2s+11p^3)\)
  3. \(16y^{8}-1=(4y^4+1)(4y^4-1)\)
  4. \(x^2-6x+9=(x-3)^2\)
  5. \(100s^{4}-180s^2x+81x^2=(10s^2-9x)^2\)
  6. \(b^2-9=(b+3)(b-3)\)
  7. \(25x^2+140x+196=(5x+14)^2\)
  8. \(9p^2+6p+1=(3p+1)^2\)
  9. \(4s^2-1=(2s+1)(2s-1)\)
  10. \(121q^{4}-286q^2y+169y^2=(11q^2-13y)^2\)
  11. \(-256p^2+81=(9-16p)(9+16p)\)
  12. \(16q^{10}+104q^5+169=(4q^5+13)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-03 14:08:40
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