Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(16a^{8}-9b^2\)
  2. \(256a^{6}-81\)
  3. \(225p^{4}+390p^2+169\)
  4. \(16b^{8}-25s^2\)
  5. \(121b^{16}-49\)
  6. \(s^2-169\)
  7. \(49p^{6}+112p^3q+64q^2\)
  8. \(100a^2-1\)
  9. \(256x^{4}+32x^2+1\)
  10. \(y^2-81\)
  11. \(256a^2+32a+1\)
  12. \(9y^2-49a^{12}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(16a^{8}-9b^2=(4a^4+3b)(4a^4-3b)\)
  2. \(256a^{6}-81=(16a^3+9)(16a^3-9)\)
  3. \(225p^{4}+390p^2+169=(15p^2+13)^2\)
  4. \(16b^{8}-25s^2=(4b^4+5s)(4b^4-5s)\)
  5. \(121b^{16}-49=(11b^8+7)(11b^8-7)\)
  6. \(s^2-169=(s+13)(s-13)\)
  7. \(49p^{6}+112p^3q+64q^2=(7p^3+8q)^2\)
  8. \(100a^2-1=(10a+1)(10a-1)\)
  9. \(256x^{4}+32x^2+1=(16x^2+1)^2\)
  10. \(y^2-81=(y+9)(y-9)\)
  11. \(256a^2+32a+1=(16a+1)^2\)
  12. \(9y^2-49a^{12}=(3y-7a^6)(3y+7a^6)\)
Oefeningengenerator wiskundeoefeningen.be 2025-11-21 22:05:26
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