Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(-256p^2+121\)
  2. \(-144x^2+49\)
  3. \(100b^{6}-169\)
  4. \(169a^{6}-4s^2\)
  5. \(64y^2-49\)
  6. \(196b^{8}+28b^4x+1x^2\)
  7. \(169p^{8}+26p^4x+1x^2\)
  8. \(196q^{10}-364q^5x+169x^2\)
  9. \(25x^{4}-40x^2+16\)
  10. \(q^2-2q+1\)
  11. \(81x^2-25p^{6}\)
  12. \(16q^2-121a^{4}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(-256p^2+121=(11-16p)(11+16p)\)
  2. \(-144x^2+49=(7-12x)(7+12x)\)
  3. \(100b^{6}-169=(10b^3+13)(10b^3-13)\)
  4. \(169a^{6}-4s^2=(13a^3+2s)(13a^3-2s)\)
  5. \(64y^2-49=(8y+7)(8y-7)\)
  6. \(196b^{8}+28b^4x+1x^2=(14b^4+x)^2\)
  7. \(169p^{8}+26p^4x+1x^2=(13p^4+x)^2\)
  8. \(196q^{10}-364q^5x+169x^2=(14q^5-13x)^2\)
  9. \(25x^{4}-40x^2+16=(5x^2-4)^2\)
  10. \(q^2-2q+1=(q-1)^2\)
  11. \(81x^2-25p^{6}=(9x-5p^3)(9x+5p^3)\)
  12. \(16q^2-121a^{4}=(4q-11a^2)(4q+11a^2)\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-01 13:23:51
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