Ontbinden in factoren (1)

Hoofdmenu Eentje per keer 

Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(25b^{6}+120b^3x+144x^2\)
  2. \(b^2-4b+4\)
  3. \(q^2+2q+1\)
  4. \(q^2+26q+169\)
  5. \(100q^{10}+140q^5s+49s^2\)
  6. \(16b^{10}+88b^5x+121x^2\)
  7. \(25-49p^{8}\)
  8. \(225s^2-64\)
  9. \(-225a^2+169\)
  10. \(16p^{8}+40p^4x+25x^2\)
  11. \(y^2+22y+121\)
  12. \(121-196b^{6}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(25b^{6}+120b^3x+144x^2=(5b^3+12x)^2\)
  2. \(b^2-4b+4=(b-2)^2\)
  3. \(q^2+2q+1=(q+1)^2\)
  4. \(q^2+26q+169=(q+13)^2\)
  5. \(100q^{10}+140q^5s+49s^2=(10q^5+7s)^2\)
  6. \(16b^{10}+88b^5x+121x^2=(4b^5+11x)^2\)
  7. \(25-49p^{8}=(5-7p^4)(5+7p^4)\)
  8. \(225s^2-64=(15s+8)(15s-8)\)
  9. \(-225a^2+169=(13-15a)(13+15a)\)
  10. \(16p^{8}+40p^4x+25x^2=(4p^4+5x)^2\)
  11. \(y^2+22y+121=(y+11)^2\)
  12. \(121-196b^{6}=(11-14b^3)(11+14b^3)\)
Oefeningengenerator wiskundeoefeningen.be 2025-12-31 06:01:08
Een site van Busleyden Atheneum Mechelen