Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(64y^{8}-81\)
  2. \(y^2-28y+196\)
  3. \(-225b^2+1\)
  4. \(36p^2+12p+1\)
  5. \(81p^{10}-1\)
  6. \(100s^2-81a^{14}\)
  7. \(16q^{12}-81s^2\)
  8. \(144p^2-169b^{6}\)
  9. \(196y^{6}-308y^3+121\)
  10. \(225a^{6}+210a^3+49\)
  11. \(169b^2-4\)
  12. \(b^2-10b+25\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(64y^{8}-81=(8y^4+9)(8y^4-9)\)
  2. \(y^2-28y+196=(y-14)^2\)
  3. \(-225b^2+1=(1-15b)(1+15b)\)
  4. \(36p^2+12p+1=(6p+1)^2\)
  5. \(81p^{10}-1=(9p^5+1)(9p^5-1)\)
  6. \(100s^2-81a^{14}=(10s-9a^7)(10s+9a^7)\)
  7. \(16q^{12}-81s^2=(4q^6+9s)(4q^6-9s)\)
  8. \(144p^2-169b^{6}=(12p-13b^3)(12p+13b^3)\)
  9. \(196y^{6}-308y^3+121=(14y^3-11)^2\)
  10. \(225a^{6}+210a^3+49=(15a^3+7)^2\)
  11. \(169b^2-4=(13b+2)(13b-2)\)
  12. \(b^2-10b+25=(b-5)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-04-03 09:53:46
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