Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(y^2+22y+121\)
  2. \(25a^{4}+10a^2y+1y^2\)
  3. \(256a^{10}-288a^5+81\)
  4. \(81x^{4}+36x^2+4\)
  5. \(p^2-22p+121\)
  6. \(169s^{14}-1\)
  7. \(169p^{14}-16y^2\)
  8. \(64y^{4}+80y^2+25\)
  9. \(-9p^2+16\)
  10. \(4p^{8}-9\)
  11. \(256p^{12}-49\)
  12. \(225a^{6}-16q^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(y^2+22y+121=(y+11)^2\)
  2. \(25a^{4}+10a^2y+1y^2=(5a^2+y)^2\)
  3. \(256a^{10}-288a^5+81=(16a^5-9)^2\)
  4. \(81x^{4}+36x^2+4=(9x^2+2)^2\)
  5. \(p^2-22p+121=(p-11)^2\)
  6. \(169s^{14}-1=(13s^7+1)(13s^7-1)\)
  7. \(169p^{14}-16y^2=(13p^7+4y)(13p^7-4y)\)
  8. \(64y^{4}+80y^2+25=(8y^2+5)^2\)
  9. \(-9p^2+16=(4-3p)(4+3p)\)
  10. \(4p^{8}-9=(2p^4+3)(2p^4-3)\)
  11. \(256p^{12}-49=(16p^6+7)(16p^6-7)\)
  12. \(225a^{6}-16q^2=(15a^3+4q)(15a^3-4q)\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-10 11:44:12
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