Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(121b^{12}-225\)
  2. \(-25a^2+36\)
  3. \(81b^{6}+90b^3s+25s^2\)
  4. \(225-49s^{16}\)
  5. \(q^2-144\)
  6. \(225x^{6}+210x^3+49\)
  7. \(196p^2-121\)
  8. \(49b^{4}+168b^2x+144x^2\)
  9. \(256a^{4}-160a^2+25\)
  10. \(9q^2-64p^{6}\)
  11. \(144a^{4}+24a^2q+1q^2\)
  12. \(169-144x^{12}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(121b^{12}-225=(11b^6+15)(11b^6-15)\)
  2. \(-25a^2+36=(6-5a)(6+5a)\)
  3. \(81b^{6}+90b^3s+25s^2=(9b^3+5s)^2\)
  4. \(225-49s^{16}=(15-7s^8)(15+7s^8)\)
  5. \(q^2-144=(q-12)(q+12)\)
  6. \(225x^{6}+210x^3+49=(15x^3+7)^2\)
  7. \(196p^2-121=(14p+11)(14p-11)\)
  8. \(49b^{4}+168b^2x+144x^2=(7b^2+12x)^2\)
  9. \(256a^{4}-160a^2+25=(16a^2-5)^2\)
  10. \(9q^2-64p^{6}=(3q-8p^3)(3q+8p^3)\)
  11. \(144a^{4}+24a^2q+1q^2=(12a^2+q)^2\)
  12. \(169-144x^{12}=(13-12x^6)(13+12x^6)\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-31 01:01:13
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