Ontbinden in factoren (1)

Hoofdmenu Eentje per keer 

Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(9a^{8}-84a^4q+196q^2\)
  2. \(81a^2-1\)
  3. \(100q^{10}+220q^5+121\)
  4. \(49y^2+112y+64\)
  5. \(q^{8}-9x^2\)
  6. \(256a^{4}-96a^2q+9q^2\)
  7. \(256p^{16}-81\)
  8. \(64b^{10}-208b^5x+169x^2\)
  9. \(p^2+30p+225\)
  10. \(4p^{8}+4p^4q+1q^2\)
  11. \(-169x^2+144\)
  12. \(144a^2-121\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(9a^{8}-84a^4q+196q^2=(3a^4-14q)^2\)
  2. \(81a^2-1=(9a+1)(9a-1)\)
  3. \(100q^{10}+220q^5+121=(10q^5+11)^2\)
  4. \(49y^2+112y+64=(7y+8)^2\)
  5. \(q^{8}-9x^2=(q^4+3x)(q^4-3x)\)
  6. \(256a^{4}-96a^2q+9q^2=(16a^2-3q)^2\)
  7. \(256p^{16}-81=(16p^8+9)(16p^8-9)\)
  8. \(64b^{10}-208b^5x+169x^2=(8b^5-13x)^2\)
  9. \(p^2+30p+225=(p+15)^2\)
  10. \(4p^{8}+4p^4q+1q^2=(2p^4+q)^2\)
  11. \(-169x^2+144=(12-13x)(12+13x)\)
  12. \(144a^2-121=(12a+11)(12a-11)\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-19 10:34:14
Een site van Busleyden Atheneum Mechelen