Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(s^2-100\)
  2. \(49s^{12}-25x^2\)
  3. \(100a^{4}+60a^2+9\)
  4. \(1-225x^{6}\)
  5. \(169y^{6}-156y^3+36\)
  6. \(49y^{10}-140y^5+100\)
  7. \(36a^2-60a+25\)
  8. \(q^2-49\)
  9. \(144y^{10}+312y^5+169\)
  10. \(q^2+2q+1\)
  11. \(9a^{14}-25s^2\)
  12. \(256p^{6}+288p^3q+81q^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(s^2-100=(s-10)(s+10)\)
  2. \(49s^{12}-25x^2=(7s^6+5x)(7s^6-5x)\)
  3. \(100a^{4}+60a^2+9=(10a^2+3)^2\)
  4. \(1-225x^{6}=(1-15x^3)(1+15x^3)\)
  5. \(169y^{6}-156y^3+36=(13y^3-6)^2\)
  6. \(49y^{10}-140y^5+100=(7y^5-10)^2\)
  7. \(36a^2-60a+25=(6a-5)^2\)
  8. \(q^2-49=(q-7)(q+7)\)
  9. \(144y^{10}+312y^5+169=(12y^5+13)^2\)
  10. \(q^2+2q+1=(q+1)^2\)
  11. \(9a^{14}-25s^2=(3a^7+5s)(3a^7-5s)\)
  12. \(256p^{6}+288p^3q+81q^2=(16p^3+9q)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-09-27 07:12:26
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