Stelsels met breuken

Hoofdmenu Eentje per keer  🖨

Substitutie of combinatie

1. \(\left\{\begin{matrix}-4x-2y=\frac{79}{21}\\-6x=-y+\frac{-17}{14}\end{matrix}\right.\)
2. \(\left\{\begin{matrix}-6x-6y=\frac{39}{14}\\x-6y=\frac{67}{14}\end{matrix}\right.\)
3. \(\left\{\begin{matrix}5y=\frac{205}{52}-4x\\x-y=\frac{227}{260}\end{matrix}\right.\)
4. \(\left\{\begin{matrix}-4x+5y=\frac{-127}{4}\\-x+2y=\frac{-23}{2}\end{matrix}\right.\)
5. \(\left\{\begin{matrix}6x+4y=\frac{-20}{13}\\2x-y=\frac{-37}{13}\end{matrix}\right.\)
6. \(\left\{\begin{matrix}6x+2y=\frac{-116}{11}\\x+2y=\frac{-111}{11}\end{matrix}\right.\)
7. \(\left\{\begin{matrix}-5x+y=\frac{-89}{28}\\2x=6y+\frac{-27}{14}\end{matrix}\right.\)
8. \(\left\{\begin{matrix}-x-3y=\frac{389}{154}\\2x+2y=\frac{-279}{77}\end{matrix}\right.\)
9. \(\left\{\begin{matrix}-2x+2y=\frac{-157}{44}\\x+y=\frac{-3}{88}\end{matrix}\right.\)
10. \(\left\{\begin{matrix}2y=\frac{-61}{3}+5x\\-x-4y=\frac{100}{3}\end{matrix}\right.\)
11. \(\left\{\begin{matrix}4y=\frac{424}{19}+5x\\-5x-y=\frac{369}{19}\end{matrix}\right.\)
12. \(\left\{\begin{matrix}-3y=\frac{13}{4}-6x\\x+4y=\frac{14}{3}\end{matrix}\right.\)

---

Substitutie of combinatie

Verbetersleutel

1. \(\left\{\begin{matrix}-4x-2y=\frac{79}{21}\\-6x=-y+\frac{-17}{14}\end{matrix}\right.\qquad V=\{(\frac{-1}{12},\frac{-12}{7})\}\)
2. \(\left\{\begin{matrix}-6x-6y=\frac{39}{14}\\x-6y=\frac{67}{14}\end{matrix}\right.\qquad V=\{(\frac{2}{7},\frac{-3}{4})\}\)
3. \(\left\{\begin{matrix}5y=\frac{205}{52}-4x\\x-y=\frac{227}{260}\end{matrix}\right.\qquad V=\{(\frac{12}{13},\frac{1}{20})\}\)
4. \(\left\{\begin{matrix}-4x+5y=\frac{-127}{4}\\-x+2y=\frac{-23}{2}\end{matrix}\right.\qquad V=\{(2,\frac{-19}{4})\}\)
5. \(\left\{\begin{matrix}6x+4y=\frac{-20}{13}\\2x-y=\frac{-37}{13}\end{matrix}\right.\qquad V=\{(\frac{-12}{13},1)\}\)
6. \(\left\{\begin{matrix}6x+2y=\frac{-116}{11}\\x+2y=\frac{-111}{11}\end{matrix}\right.\qquad V=\{(\frac{-1}{11},-5)\}\)
7. \(\left\{\begin{matrix}-5x+y=\frac{-89}{28}\\2x=6y+\frac{-27}{14}\end{matrix}\right.\qquad V=\{(\frac{3}{4},\frac{4}{7})\}\)
8. \(\left\{\begin{matrix}-x-3y=\frac{389}{154}\\2x+2y=\frac{-279}{77}\end{matrix}\right.\qquad V=\{(\frac{-16}{11},\frac{-5}{14})\}\)
9. \(\left\{\begin{matrix}-2x+2y=\frac{-157}{44}\\x+y=\frac{-3}{88}\end{matrix}\right.\qquad V=\{(\frac{7}{8},\frac{-10}{11})\}\)
10. \(\left\{\begin{matrix}2y=\frac{-61}{3}+5x\\-x-4y=\frac{100}{3}\end{matrix}\right.\qquad V=\{(\frac{2}{3},\frac{-17}{2})\}\)
11. \(\left\{\begin{matrix}4y=\frac{424}{19}+5x\\-5x-y=\frac{369}{19}\end{matrix}\right.\qquad V=\{(-4,\frac{11}{19})\}\)
12. \(\left\{\begin{matrix}-3y=\frac{13}{4}-6x\\x+4y=\frac{14}{3}\end{matrix}\right.\qquad V=\{(1,\frac{11}{12})\}\)