Bepaal de waarde van x.
- \(12x+11=1\)
- \(6x-10=-6\)
- \(9x+5=-1\)
- \(x+6=-3\)
- \(13x-2=14\)
- \(3x+12=7\)
- \(8x+13=10\)
- \(3x+8=-13\)
- \(-10x+10=-7\)
- \(3x-12=-4\)
- \(11x-4=13\)
- \(6x+14=8\)
Bepaal de waarde van x.
Verbetersleutel
- \(\begin{align} & 12x \color{red}{+11}& = &1 \\\Leftrightarrow & 12x \color{red}{+11}\color{blue}{-11}
& = &1\color{blue}{-11} \\\Leftrightarrow &12x
& = &-10\\\Leftrightarrow & \color{red}{12}x
& = &-10\\\Leftrightarrow & \frac{\color{red}{12}x}{ \color{blue}12}
& = & \frac{-10}{12} \\\Leftrightarrow & \color{green}{ x = \frac{-5}{6} } & & \\ & V = \left\{ \frac{-5}{6} \right\} & \\\end{align}\)
- \(\begin{align} & 6x \color{red}{-10}& = &-6 \\\Leftrightarrow & 6x \color{red}{-10}\color{blue}{+10}
& = &-6\color{blue}{+10} \\\Leftrightarrow &6x
& = &4\\\Leftrightarrow & \color{red}{6}x
& = &4\\\Leftrightarrow & \frac{\color{red}{6}x}{ \color{blue}6}
& = & \frac{4}{6} \\\Leftrightarrow & \color{green}{ x = \frac{2}{3} } & & \\ & V = \left\{ \frac{2}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 9x \color{red}{+5}& = &-1 \\\Leftrightarrow & 9x \color{red}{+5}\color{blue}{-5}
& = &-1\color{blue}{-5} \\\Leftrightarrow &9x
& = &-6\\\Leftrightarrow & \color{red}{9}x
& = &-6\\\Leftrightarrow & \frac{\color{red}{9}x}{ \color{blue}9}
& = & \frac{-6}{9} \\\Leftrightarrow & \color{green}{ x = \frac{-2}{3} } & & \\ & V = \left\{ \frac{-2}{3} \right\} & \\\end{align}\)
- \(\begin{align} & x \color{red}{+6}& = &-3 \\\Leftrightarrow & x \color{red}{+6}\color{blue}{-6}
& = &-3\color{blue}{-6} \\\Leftrightarrow &x
& = &-9\\\Leftrightarrow & \color{red}{}x
& = &-9\\\Leftrightarrow & \frac{\color{red}{}x}{ \color{blue}1}
& = & -9 \\\Leftrightarrow & \color{green}{ x = -9 } & & \\ & V = \left\{ -9 \right\} & \\\end{align}\)
- \(\begin{align} & 13x \color{red}{-2}& = &14 \\\Leftrightarrow & 13x \color{red}{-2}\color{blue}{+2}
& = &14\color{blue}{+2} \\\Leftrightarrow &13x
& = &16\\\Leftrightarrow & \color{red}{13}x
& = &16\\\Leftrightarrow & \frac{\color{red}{13}x}{ \color{blue}13}
& = & \frac{16}{13} \\\Leftrightarrow & \color{green}{ x = \frac{16}{13} } & & \\ & V = \left\{ \frac{16}{13} \right\} & \\\end{align}\)
- \(\begin{align} & 3x \color{red}{+12}& = &7 \\\Leftrightarrow & 3x \color{red}{+12}\color{blue}{-12}
& = &7\color{blue}{-12} \\\Leftrightarrow &3x
& = &-5\\\Leftrightarrow & \color{red}{3}x
& = &-5\\\Leftrightarrow & \frac{\color{red}{3}x}{ \color{blue}3}
& = & \frac{-5}{3} \\\Leftrightarrow & \color{green}{ x = \frac{-5}{3} } & & \\ & V = \left\{ \frac{-5}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 8x \color{red}{+13}& = &10 \\\Leftrightarrow & 8x \color{red}{+13}\color{blue}{-13}
& = &10\color{blue}{-13} \\\Leftrightarrow &8x
& = &-3\\\Leftrightarrow & \color{red}{8}x
& = &-3\\\Leftrightarrow & \frac{\color{red}{8}x}{ \color{blue}8}
& = & \frac{-3}{8} \\\Leftrightarrow & \color{green}{ x = \frac{-3}{8} } & & \\ & V = \left\{ \frac{-3}{8} \right\} & \\\end{align}\)
- \(\begin{align} & 3x \color{red}{+8}& = &-13 \\\Leftrightarrow & 3x \color{red}{+8}\color{blue}{-8}
& = &-13\color{blue}{-8} \\\Leftrightarrow &3x
& = &-21\\\Leftrightarrow & \color{red}{3}x
& = &-21\\\Leftrightarrow & \frac{\color{red}{3}x}{ \color{blue}3}
& = & \frac{-21}{3} \\\Leftrightarrow & \color{green}{ x = -7 } & & \\ & V = \left\{ -7 \right\} & \\\end{align}\)
- \(\begin{align} & -10x \color{red}{+10}& = &-7 \\\Leftrightarrow & -10x \color{red}{+10}\color{blue}{-10}
& = &-7\color{blue}{-10} \\\Leftrightarrow &-10x
& = &-17\\\Leftrightarrow & \color{red}{-10}x
& = &-17\\\Leftrightarrow & \frac{\color{red}{-10}x}{ \color{blue}-10}
& = & \frac{-17}{-10} \\\Leftrightarrow & \color{green}{ x = \frac{17}{10} } & & \\ & V = \left\{ \frac{17}{10} \right\} & \\\end{align}\)
- \(\begin{align} & 3x \color{red}{-12}& = &-4 \\\Leftrightarrow & 3x \color{red}{-12}\color{blue}{+12}
& = &-4\color{blue}{+12} \\\Leftrightarrow &3x
& = &8\\\Leftrightarrow & \color{red}{3}x
& = &8\\\Leftrightarrow & \frac{\color{red}{3}x}{ \color{blue}3}
& = & \frac{8}{3} \\\Leftrightarrow & \color{green}{ x = \frac{8}{3} } & & \\ & V = \left\{ \frac{8}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 11x \color{red}{-4}& = &13 \\\Leftrightarrow & 11x \color{red}{-4}\color{blue}{+4}
& = &13\color{blue}{+4} \\\Leftrightarrow &11x
& = &17\\\Leftrightarrow & \color{red}{11}x
& = &17\\\Leftrightarrow & \frac{\color{red}{11}x}{ \color{blue}11}
& = & \frac{17}{11} \\\Leftrightarrow & \color{green}{ x = \frac{17}{11} } & & \\ & V = \left\{ \frac{17}{11} \right\} & \\\end{align}\)
- \(\begin{align} & 6x \color{red}{+14}& = &8 \\\Leftrightarrow & 6x \color{red}{+14}\color{blue}{-14}
& = &8\color{blue}{-14} \\\Leftrightarrow &6x
& = &-6\\\Leftrightarrow & \color{red}{6}x
& = &-6\\\Leftrightarrow & \frac{\color{red}{6}x}{ \color{blue}6}
& = & \frac{-6}{6} \\\Leftrightarrow & \color{green}{ x = -1 } & & \\ & V = \left\{ -1 \right\} & \\\end{align}\)