Vgln. eerste graad (reeks 1)

Hoofdmenu Eentje per keer 

Bepaal de waarde van x.

  1. \(-9x+11=-1\)
  2. \(5x+7=-9\)
  3. \(3x-4=-4\)
  4. \(-13x-10=-7\)
  5. \(-3x-10=5\)
  6. \(-15x-1=12\)
  7. \(-5x-11=-14\)
  8. \(14x-9=-8\)
  9. \(4x-8=-12\)
  10. \(-12x-9=-10\)
  11. \(-x+8=14\)
  12. \(-5x+12=5\)

Bepaal de waarde van x.

Verbetersleutel

  1. \(\begin{align} & -9x \color{red}{+11}& = &-1 \\\Leftrightarrow & -9x \color{red}{+11}\color{blue}{-11} & = &-1\color{blue}{-11} \\\Leftrightarrow &-9x & = &-12\\\Leftrightarrow & \color{red}{-9}x & = &-12\\\Leftrightarrow & \frac{\color{red}{-9}x}{ \color{blue}-9} & = & \frac{-12}{-9} \\\Leftrightarrow & \color{green}{ x = \frac{4}{3} } & & \\ & V = \left\{ \frac{4}{3} \right\} & \\\end{align}\)
  2. \(\begin{align} & 5x \color{red}{+7}& = &-9 \\\Leftrightarrow & 5x \color{red}{+7}\color{blue}{-7} & = &-9\color{blue}{-7} \\\Leftrightarrow &5x & = &-16\\\Leftrightarrow & \color{red}{5}x & = &-16\\\Leftrightarrow & \frac{\color{red}{5}x}{ \color{blue}5} & = & \frac{-16}{5} \\\Leftrightarrow & \color{green}{ x = \frac{-16}{5} } & & \\ & V = \left\{ \frac{-16}{5} \right\} & \\\end{align}\)
  3. \(\begin{align} & 3x \color{red}{-4}& = &-4 \\\Leftrightarrow & 3x \color{red}{-4}\color{blue}{+4} & = &-4\color{blue}{+4} \\\Leftrightarrow &3x & = &0\\\Leftrightarrow & \color{red}{3}x & = &0\\\Leftrightarrow & \frac{\color{red}{3}x}{ \color{blue}3} & = & \frac{0}{3} \\\Leftrightarrow & \color{green}{ x = 0 } & & \\ & V = \left\{ 0 \right\} & \\\end{align}\)
  4. \(\begin{align} & -13x \color{red}{-10}& = &-7 \\\Leftrightarrow & -13x \color{red}{-10}\color{blue}{+10} & = &-7\color{blue}{+10} \\\Leftrightarrow &-13x & = &3\\\Leftrightarrow & \color{red}{-13}x & = &3\\\Leftrightarrow & \frac{\color{red}{-13}x}{ \color{blue}-13} & = & \frac{3}{-13} \\\Leftrightarrow & \color{green}{ x = \frac{-3}{13} } & & \\ & V = \left\{ \frac{-3}{13} \right\} & \\\end{align}\)
  5. \(\begin{align} & -3x \color{red}{-10}& = &5 \\\Leftrightarrow & -3x \color{red}{-10}\color{blue}{+10} & = &5\color{blue}{+10} \\\Leftrightarrow &-3x & = &15\\\Leftrightarrow & \color{red}{-3}x & = &15\\\Leftrightarrow & \frac{\color{red}{-3}x}{ \color{blue}-3} & = & \frac{15}{-3} \\\Leftrightarrow & \color{green}{ x = -5 } & & \\ & V = \left\{ -5 \right\} & \\\end{align}\)
  6. \(\begin{align} & -15x \color{red}{-1}& = &12 \\\Leftrightarrow & -15x \color{red}{-1}\color{blue}{+1} & = &12\color{blue}{+1} \\\Leftrightarrow &-15x & = &13\\\Leftrightarrow & \color{red}{-15}x & = &13\\\Leftrightarrow & \frac{\color{red}{-15}x}{ \color{blue}-15} & = & \frac{13}{-15} \\\Leftrightarrow & \color{green}{ x = \frac{-13}{15} } & & \\ & V = \left\{ \frac{-13}{15} \right\} & \\\end{align}\)
  7. \(\begin{align} & -5x \color{red}{-11}& = &-14 \\\Leftrightarrow & -5x \color{red}{-11}\color{blue}{+11} & = &-14\color{blue}{+11} \\\Leftrightarrow &-5x & = &-3\\\Leftrightarrow & \color{red}{-5}x & = &-3\\\Leftrightarrow & \frac{\color{red}{-5}x}{ \color{blue}-5} & = & \frac{-3}{-5} \\\Leftrightarrow & \color{green}{ x = \frac{3}{5} } & & \\ & V = \left\{ \frac{3}{5} \right\} & \\\end{align}\)
  8. \(\begin{align} & 14x \color{red}{-9}& = &-8 \\\Leftrightarrow & 14x \color{red}{-9}\color{blue}{+9} & = &-8\color{blue}{+9} \\\Leftrightarrow &14x & = &1\\\Leftrightarrow & \color{red}{14}x & = &1\\\Leftrightarrow & \frac{\color{red}{14}x}{ \color{blue}14} & = & \frac{1}{14} \\\Leftrightarrow & \color{green}{ x = \frac{1}{14} } & & \\ & V = \left\{ \frac{1}{14} \right\} & \\\end{align}\)
  9. \(\begin{align} & 4x \color{red}{-8}& = &-12 \\\Leftrightarrow & 4x \color{red}{-8}\color{blue}{+8} & = &-12\color{blue}{+8} \\\Leftrightarrow &4x & = &-4\\\Leftrightarrow & \color{red}{4}x & = &-4\\\Leftrightarrow & \frac{\color{red}{4}x}{ \color{blue}4} & = & \frac{-4}{4} \\\Leftrightarrow & \color{green}{ x = -1 } & & \\ & V = \left\{ -1 \right\} & \\\end{align}\)
  10. \(\begin{align} & -12x \color{red}{-9}& = &-10 \\\Leftrightarrow & -12x \color{red}{-9}\color{blue}{+9} & = &-10\color{blue}{+9} \\\Leftrightarrow &-12x & = &-1\\\Leftrightarrow & \color{red}{-12}x & = &-1\\\Leftrightarrow & \frac{\color{red}{-12}x}{ \color{blue}-12} & = & \frac{-1}{-12} \\\Leftrightarrow & \color{green}{ x = \frac{1}{12} } & & \\ & V = \left\{ \frac{1}{12} \right\} & \\\end{align}\)
  11. \(\begin{align} & -x \color{red}{+8}& = &14 \\\Leftrightarrow & -x \color{red}{+8}\color{blue}{-8} & = &14\color{blue}{-8} \\\Leftrightarrow &-x & = &6\\\Leftrightarrow & \color{red}{-}x & = &6\\\Leftrightarrow & \frac{\color{red}{-}x}{ \color{blue}-1} & = & \frac{6}{-1} \\\Leftrightarrow & \color{green}{ x = -6 } & & \\ & V = \left\{ -6 \right\} & \\\end{align}\)
  12. \(\begin{align} & -5x \color{red}{+12}& = &5 \\\Leftrightarrow & -5x \color{red}{+12}\color{blue}{-12} & = &5\color{blue}{-12} \\\Leftrightarrow &-5x & = &-7\\\Leftrightarrow & \color{red}{-5}x & = &-7\\\Leftrightarrow & \frac{\color{red}{-5}x}{ \color{blue}-5} & = & \frac{-7}{-5} \\\Leftrightarrow & \color{green}{ x = \frac{7}{5} } & & \\ & V = \left\{ \frac{7}{5} \right\} & \\\end{align}\)
Oefeningengenerator wiskundeoefeningen.be 2026-03-23 15:49:43
Een site van Busleyden Atheneum Mechelen