Bepaal de waarde van x.
- \(2x+1=-9\)
- \(2x+2=3\)
- \(-15x-9=15\)
- \(-x-8=-3\)
- \(10x+4=-7\)
- \(-13x+4=3\)
- \(-3x-2=5\)
- \(-6x-15=1\)
- \(5x-12=2\)
- \(5x-5=-2\)
- \(-13x-3=-8\)
- \(-x+9=-7\)
Bepaal de waarde van x.
Verbetersleutel
- \(\begin{align} & 2x \color{red}{+1}& = &-9 \\\Leftrightarrow & 2x \color{red}{+1}\color{blue}{-1}
& = &-9\color{blue}{-1} \\\Leftrightarrow &2x
& = &-10\\\Leftrightarrow & \color{red}{2}x
& = &-10\\\Leftrightarrow & \frac{\color{red}{2}x}{ \color{blue}2}
& = & \frac{-10}{2} \\\Leftrightarrow & \color{green}{ x = -5 } & & \\ & V = \left\{ -5 \right\} & \\\end{align}\)
- \(\begin{align} & 2x \color{red}{+2}& = &3 \\\Leftrightarrow & 2x \color{red}{+2}\color{blue}{-2}
& = &3\color{blue}{-2} \\\Leftrightarrow &2x
& = &1\\\Leftrightarrow & \color{red}{2}x
& = &1\\\Leftrightarrow & \frac{\color{red}{2}x}{ \color{blue}2}
& = & \frac{1}{2} \\\Leftrightarrow & \color{green}{ x = \frac{1}{2} } & & \\ & V = \left\{ \frac{1}{2} \right\} & \\\end{align}\)
- \(\begin{align} & -15x \color{red}{-9}& = &15 \\\Leftrightarrow & -15x \color{red}{-9}\color{blue}{+9}
& = &15\color{blue}{+9} \\\Leftrightarrow &-15x
& = &24\\\Leftrightarrow & \color{red}{-15}x
& = &24\\\Leftrightarrow & \frac{\color{red}{-15}x}{ \color{blue}-15}
& = & \frac{24}{-15} \\\Leftrightarrow & \color{green}{ x = \frac{-8}{5} } & & \\ & V = \left\{ \frac{-8}{5} \right\} & \\\end{align}\)
- \(\begin{align} & -x \color{red}{-8}& = &-3 \\\Leftrightarrow & -x \color{red}{-8}\color{blue}{+8}
& = &-3\color{blue}{+8} \\\Leftrightarrow &-x
& = &5\\\Leftrightarrow & \color{red}{-}x
& = &5\\\Leftrightarrow & \frac{\color{red}{-}x}{ \color{blue}-1}
& = & \frac{5}{-1} \\\Leftrightarrow & \color{green}{ x = -5 } & & \\ & V = \left\{ -5 \right\} & \\\end{align}\)
- \(\begin{align} & 10x \color{red}{+4}& = &-7 \\\Leftrightarrow & 10x \color{red}{+4}\color{blue}{-4}
& = &-7\color{blue}{-4} \\\Leftrightarrow &10x
& = &-11\\\Leftrightarrow & \color{red}{10}x
& = &-11\\\Leftrightarrow & \frac{\color{red}{10}x}{ \color{blue}10}
& = & \frac{-11}{10} \\\Leftrightarrow & \color{green}{ x = \frac{-11}{10} } & & \\ & V = \left\{ \frac{-11}{10} \right\} & \\\end{align}\)
- \(\begin{align} & -13x \color{red}{+4}& = &3 \\\Leftrightarrow & -13x \color{red}{+4}\color{blue}{-4}
& = &3\color{blue}{-4} \\\Leftrightarrow &-13x
& = &-1\\\Leftrightarrow & \color{red}{-13}x
& = &-1\\\Leftrightarrow & \frac{\color{red}{-13}x}{ \color{blue}-13}
& = & \frac{-1}{-13} \\\Leftrightarrow & \color{green}{ x = \frac{1}{13} } & & \\ & V = \left\{ \frac{1}{13} \right\} & \\\end{align}\)
- \(\begin{align} & -3x \color{red}{-2}& = &5 \\\Leftrightarrow & -3x \color{red}{-2}\color{blue}{+2}
& = &5\color{blue}{+2} \\\Leftrightarrow &-3x
& = &7\\\Leftrightarrow & \color{red}{-3}x
& = &7\\\Leftrightarrow & \frac{\color{red}{-3}x}{ \color{blue}-3}
& = & \frac{7}{-3} \\\Leftrightarrow & \color{green}{ x = \frac{-7}{3} } & & \\ & V = \left\{ \frac{-7}{3} \right\} & \\\end{align}\)
- \(\begin{align} & -6x \color{red}{-15}& = &1 \\\Leftrightarrow & -6x \color{red}{-15}\color{blue}{+15}
& = &1\color{blue}{+15} \\\Leftrightarrow &-6x
& = &16\\\Leftrightarrow & \color{red}{-6}x
& = &16\\\Leftrightarrow & \frac{\color{red}{-6}x}{ \color{blue}-6}
& = & \frac{16}{-6} \\\Leftrightarrow & \color{green}{ x = \frac{-8}{3} } & & \\ & V = \left\{ \frac{-8}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 5x \color{red}{-12}& = &2 \\\Leftrightarrow & 5x \color{red}{-12}\color{blue}{+12}
& = &2\color{blue}{+12} \\\Leftrightarrow &5x
& = &14\\\Leftrightarrow & \color{red}{5}x
& = &14\\\Leftrightarrow & \frac{\color{red}{5}x}{ \color{blue}5}
& = & \frac{14}{5} \\\Leftrightarrow & \color{green}{ x = \frac{14}{5} } & & \\ & V = \left\{ \frac{14}{5} \right\} & \\\end{align}\)
- \(\begin{align} & 5x \color{red}{-5}& = &-2 \\\Leftrightarrow & 5x \color{red}{-5}\color{blue}{+5}
& = &-2\color{blue}{+5} \\\Leftrightarrow &5x
& = &3\\\Leftrightarrow & \color{red}{5}x
& = &3\\\Leftrightarrow & \frac{\color{red}{5}x}{ \color{blue}5}
& = & \frac{3}{5} \\\Leftrightarrow & \color{green}{ x = \frac{3}{5} } & & \\ & V = \left\{ \frac{3}{5} \right\} & \\\end{align}\)
- \(\begin{align} & -13x \color{red}{-3}& = &-8 \\\Leftrightarrow & -13x \color{red}{-3}\color{blue}{+3}
& = &-8\color{blue}{+3} \\\Leftrightarrow &-13x
& = &-5\\\Leftrightarrow & \color{red}{-13}x
& = &-5\\\Leftrightarrow & \frac{\color{red}{-13}x}{ \color{blue}-13}
& = & \frac{-5}{-13} \\\Leftrightarrow & \color{green}{ x = \frac{5}{13} } & & \\ & V = \left\{ \frac{5}{13} \right\} & \\\end{align}\)
- \(\begin{align} & -x \color{red}{+9}& = &-7 \\\Leftrightarrow & -x \color{red}{+9}\color{blue}{-9}
& = &-7\color{blue}{-9} \\\Leftrightarrow &-x
& = &-16\\\Leftrightarrow & \color{red}{-}x
& = &-16\\\Leftrightarrow & \frac{\color{red}{-}x}{ \color{blue}-1}
& = & \frac{-16}{-1} \\\Leftrightarrow & \color{green}{ x = 16 } & & \\ & V = \left\{ 16 \right\} & \\\end{align}\)