Bepaal de waarde van x.
- \(-12x+15=-11\)
- \(4x+2=7\)
- \(-4x-1=-13\)
- \(2x+9=-9\)
- \(7x-7=13\)
- \(2x-13=-10\)
- \(-13x-11=2\)
- \(-3x+11=14\)
- \(-15x+3=5\)
- \(10x-13=2\)
- \(8x-2=-10\)
- \(2x+14=-3\)
Bepaal de waarde van x.
Verbetersleutel
- \(\begin{align} & -12x \color{red}{+15}& = &-11 \\\Leftrightarrow & -12x \color{red}{+15}\color{blue}{-15}
& = &-11\color{blue}{-15} \\\Leftrightarrow &-12x
& = &-26\\\Leftrightarrow & \color{red}{-12}x
& = &-26\\\Leftrightarrow & \frac{\color{red}{-12}x}{ \color{blue}-12}
& = & \frac{-26}{-12} \\\Leftrightarrow & \color{green}{ x = \frac{13}{6} } & & \\ & V = \left\{ \frac{13}{6} \right\} & \\\end{align}\)
- \(\begin{align} & 4x \color{red}{+2}& = &7 \\\Leftrightarrow & 4x \color{red}{+2}\color{blue}{-2}
& = &7\color{blue}{-2} \\\Leftrightarrow &4x
& = &5\\\Leftrightarrow & \color{red}{4}x
& = &5\\\Leftrightarrow & \frac{\color{red}{4}x}{ \color{blue}4}
& = & \frac{5}{4} \\\Leftrightarrow & \color{green}{ x = \frac{5}{4} } & & \\ & V = \left\{ \frac{5}{4} \right\} & \\\end{align}\)
- \(\begin{align} & -4x \color{red}{-1}& = &-13 \\\Leftrightarrow & -4x \color{red}{-1}\color{blue}{+1}
& = &-13\color{blue}{+1} \\\Leftrightarrow &-4x
& = &-12\\\Leftrightarrow & \color{red}{-4}x
& = &-12\\\Leftrightarrow & \frac{\color{red}{-4}x}{ \color{blue}-4}
& = & \frac{-12}{-4} \\\Leftrightarrow & \color{green}{ x = 3 } & & \\ & V = \left\{ 3 \right\} & \\\end{align}\)
- \(\begin{align} & 2x \color{red}{+9}& = &-9 \\\Leftrightarrow & 2x \color{red}{+9}\color{blue}{-9}
& = &-9\color{blue}{-9} \\\Leftrightarrow &2x
& = &-18\\\Leftrightarrow & \color{red}{2}x
& = &-18\\\Leftrightarrow & \frac{\color{red}{2}x}{ \color{blue}2}
& = & \frac{-18}{2} \\\Leftrightarrow & \color{green}{ x = -9 } & & \\ & V = \left\{ -9 \right\} & \\\end{align}\)
- \(\begin{align} & 7x \color{red}{-7}& = &13 \\\Leftrightarrow & 7x \color{red}{-7}\color{blue}{+7}
& = &13\color{blue}{+7} \\\Leftrightarrow &7x
& = &20\\\Leftrightarrow & \color{red}{7}x
& = &20\\\Leftrightarrow & \frac{\color{red}{7}x}{ \color{blue}7}
& = & \frac{20}{7} \\\Leftrightarrow & \color{green}{ x = \frac{20}{7} } & & \\ & V = \left\{ \frac{20}{7} \right\} & \\\end{align}\)
- \(\begin{align} & 2x \color{red}{-13}& = &-10 \\\Leftrightarrow & 2x \color{red}{-13}\color{blue}{+13}
& = &-10\color{blue}{+13} \\\Leftrightarrow &2x
& = &3\\\Leftrightarrow & \color{red}{2}x
& = &3\\\Leftrightarrow & \frac{\color{red}{2}x}{ \color{blue}2}
& = & \frac{3}{2} \\\Leftrightarrow & \color{green}{ x = \frac{3}{2} } & & \\ & V = \left\{ \frac{3}{2} \right\} & \\\end{align}\)
- \(\begin{align} & -13x \color{red}{-11}& = &2 \\\Leftrightarrow & -13x \color{red}{-11}\color{blue}{+11}
& = &2\color{blue}{+11} \\\Leftrightarrow &-13x
& = &13\\\Leftrightarrow & \color{red}{-13}x
& = &13\\\Leftrightarrow & \frac{\color{red}{-13}x}{ \color{blue}-13}
& = & \frac{13}{-13} \\\Leftrightarrow & \color{green}{ x = -1 } & & \\ & V = \left\{ -1 \right\} & \\\end{align}\)
- \(\begin{align} & -3x \color{red}{+11}& = &14 \\\Leftrightarrow & -3x \color{red}{+11}\color{blue}{-11}
& = &14\color{blue}{-11} \\\Leftrightarrow &-3x
& = &3\\\Leftrightarrow & \color{red}{-3}x
& = &3\\\Leftrightarrow & \frac{\color{red}{-3}x}{ \color{blue}-3}
& = & \frac{3}{-3} \\\Leftrightarrow & \color{green}{ x = -1 } & & \\ & V = \left\{ -1 \right\} & \\\end{align}\)
- \(\begin{align} & -15x \color{red}{+3}& = &5 \\\Leftrightarrow & -15x \color{red}{+3}\color{blue}{-3}
& = &5\color{blue}{-3} \\\Leftrightarrow &-15x
& = &2\\\Leftrightarrow & \color{red}{-15}x
& = &2\\\Leftrightarrow & \frac{\color{red}{-15}x}{ \color{blue}-15}
& = & \frac{2}{-15} \\\Leftrightarrow & \color{green}{ x = \frac{-2}{15} } & & \\ & V = \left\{ \frac{-2}{15} \right\} & \\\end{align}\)
- \(\begin{align} & 10x \color{red}{-13}& = &2 \\\Leftrightarrow & 10x \color{red}{-13}\color{blue}{+13}
& = &2\color{blue}{+13} \\\Leftrightarrow &10x
& = &15\\\Leftrightarrow & \color{red}{10}x
& = &15\\\Leftrightarrow & \frac{\color{red}{10}x}{ \color{blue}10}
& = & \frac{15}{10} \\\Leftrightarrow & \color{green}{ x = \frac{3}{2} } & & \\ & V = \left\{ \frac{3}{2} \right\} & \\\end{align}\)
- \(\begin{align} & 8x \color{red}{-2}& = &-10 \\\Leftrightarrow & 8x \color{red}{-2}\color{blue}{+2}
& = &-10\color{blue}{+2} \\\Leftrightarrow &8x
& = &-8\\\Leftrightarrow & \color{red}{8}x
& = &-8\\\Leftrightarrow & \frac{\color{red}{8}x}{ \color{blue}8}
& = & \frac{-8}{8} \\\Leftrightarrow & \color{green}{ x = -1 } & & \\ & V = \left\{ -1 \right\} & \\\end{align}\)
- \(\begin{align} & 2x \color{red}{+14}& = &-3 \\\Leftrightarrow & 2x \color{red}{+14}\color{blue}{-14}
& = &-3\color{blue}{-14} \\\Leftrightarrow &2x
& = &-17\\\Leftrightarrow & \color{red}{2}x
& = &-17\\\Leftrightarrow & \frac{\color{red}{2}x}{ \color{blue}2}
& = & \frac{-17}{2} \\\Leftrightarrow & \color{green}{ x = \frac{-17}{2} } & & \\ & V = \left\{ \frac{-17}{2} \right\} & \\\end{align}\)