Bepaal de waarde van x.
- \(9x+2=8\)
- \(-13x+12=13\)
- \(-15x-8=-13\)
- \(-12x-7=9\)
- \(2x-12=8\)
- \(8x-12=15\)
- \(-15x-7=-4\)
- \(6x-2=-2\)
- \(-12x+3=4\)
- \(-6x+14=-12\)
- \(12x+7=11\)
- \(-5x+13=1\)
Bepaal de waarde van x.
Verbetersleutel
- \(\begin{align} & 9x \color{red}{+2}& = &8 \\\Leftrightarrow & 9x \color{red}{+2}\color{blue}{-2}
& = &8\color{blue}{-2} \\\Leftrightarrow &9x
& = &6\\\Leftrightarrow & \color{red}{9}x
& = &6\\\Leftrightarrow & \frac{\color{red}{9}x}{ \color{blue}9}
& = & \frac{6}{9} \\\Leftrightarrow & \color{green}{ x = \frac{2}{3} } & & \\ & V = \left\{ \frac{2}{3} \right\} & \\\end{align}\)
- \(\begin{align} & -13x \color{red}{+12}& = &13 \\\Leftrightarrow & -13x \color{red}{+12}\color{blue}{-12}
& = &13\color{blue}{-12} \\\Leftrightarrow &-13x
& = &1\\\Leftrightarrow & \color{red}{-13}x
& = &1\\\Leftrightarrow & \frac{\color{red}{-13}x}{ \color{blue}-13}
& = & \frac{1}{-13} \\\Leftrightarrow & \color{green}{ x = \frac{-1}{13} } & & \\ & V = \left\{ \frac{-1}{13} \right\} & \\\end{align}\)
- \(\begin{align} & -15x \color{red}{-8}& = &-13 \\\Leftrightarrow & -15x \color{red}{-8}\color{blue}{+8}
& = &-13\color{blue}{+8} \\\Leftrightarrow &-15x
& = &-5\\\Leftrightarrow & \color{red}{-15}x
& = &-5\\\Leftrightarrow & \frac{\color{red}{-15}x}{ \color{blue}-15}
& = & \frac{-5}{-15} \\\Leftrightarrow & \color{green}{ x = \frac{1}{3} } & & \\ & V = \left\{ \frac{1}{3} \right\} & \\\end{align}\)
- \(\begin{align} & -12x \color{red}{-7}& = &9 \\\Leftrightarrow & -12x \color{red}{-7}\color{blue}{+7}
& = &9\color{blue}{+7} \\\Leftrightarrow &-12x
& = &16\\\Leftrightarrow & \color{red}{-12}x
& = &16\\\Leftrightarrow & \frac{\color{red}{-12}x}{ \color{blue}-12}
& = & \frac{16}{-12} \\\Leftrightarrow & \color{green}{ x = \frac{-4}{3} } & & \\ & V = \left\{ \frac{-4}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 2x \color{red}{-12}& = &8 \\\Leftrightarrow & 2x \color{red}{-12}\color{blue}{+12}
& = &8\color{blue}{+12} \\\Leftrightarrow &2x
& = &20\\\Leftrightarrow & \color{red}{2}x
& = &20\\\Leftrightarrow & \frac{\color{red}{2}x}{ \color{blue}2}
& = & \frac{20}{2} \\\Leftrightarrow & \color{green}{ x = 10 } & & \\ & V = \left\{ 10 \right\} & \\\end{align}\)
- \(\begin{align} & 8x \color{red}{-12}& = &15 \\\Leftrightarrow & 8x \color{red}{-12}\color{blue}{+12}
& = &15\color{blue}{+12} \\\Leftrightarrow &8x
& = &27\\\Leftrightarrow & \color{red}{8}x
& = &27\\\Leftrightarrow & \frac{\color{red}{8}x}{ \color{blue}8}
& = & \frac{27}{8} \\\Leftrightarrow & \color{green}{ x = \frac{27}{8} } & & \\ & V = \left\{ \frac{27}{8} \right\} & \\\end{align}\)
- \(\begin{align} & -15x \color{red}{-7}& = &-4 \\\Leftrightarrow & -15x \color{red}{-7}\color{blue}{+7}
& = &-4\color{blue}{+7} \\\Leftrightarrow &-15x
& = &3\\\Leftrightarrow & \color{red}{-15}x
& = &3\\\Leftrightarrow & \frac{\color{red}{-15}x}{ \color{blue}-15}
& = & \frac{3}{-15} \\\Leftrightarrow & \color{green}{ x = \frac{-1}{5} } & & \\ & V = \left\{ \frac{-1}{5} \right\} & \\\end{align}\)
- \(\begin{align} & 6x \color{red}{-2}& = &-2 \\\Leftrightarrow & 6x \color{red}{-2}\color{blue}{+2}
& = &-2\color{blue}{+2} \\\Leftrightarrow &6x
& = &0\\\Leftrightarrow & \color{red}{6}x
& = &0\\\Leftrightarrow & \frac{\color{red}{6}x}{ \color{blue}6}
& = & \frac{0}{6} \\\Leftrightarrow & \color{green}{ x = 0 } & & \\ & V = \left\{ 0 \right\} & \\\end{align}\)
- \(\begin{align} & -12x \color{red}{+3}& = &4 \\\Leftrightarrow & -12x \color{red}{+3}\color{blue}{-3}
& = &4\color{blue}{-3} \\\Leftrightarrow &-12x
& = &1\\\Leftrightarrow & \color{red}{-12}x
& = &1\\\Leftrightarrow & \frac{\color{red}{-12}x}{ \color{blue}-12}
& = & \frac{1}{-12} \\\Leftrightarrow & \color{green}{ x = \frac{-1}{12} } & & \\ & V = \left\{ \frac{-1}{12} \right\} & \\\end{align}\)
- \(\begin{align} & -6x \color{red}{+14}& = &-12 \\\Leftrightarrow & -6x \color{red}{+14}\color{blue}{-14}
& = &-12\color{blue}{-14} \\\Leftrightarrow &-6x
& = &-26\\\Leftrightarrow & \color{red}{-6}x
& = &-26\\\Leftrightarrow & \frac{\color{red}{-6}x}{ \color{blue}-6}
& = & \frac{-26}{-6} \\\Leftrightarrow & \color{green}{ x = \frac{13}{3} } & & \\ & V = \left\{ \frac{13}{3} \right\} & \\\end{align}\)
- \(\begin{align} & 12x \color{red}{+7}& = &11 \\\Leftrightarrow & 12x \color{red}{+7}\color{blue}{-7}
& = &11\color{blue}{-7} \\\Leftrightarrow &12x
& = &4\\\Leftrightarrow & \color{red}{12}x
& = &4\\\Leftrightarrow & \frac{\color{red}{12}x}{ \color{blue}12}
& = & \frac{4}{12} \\\Leftrightarrow & \color{green}{ x = \frac{1}{3} } & & \\ & V = \left\{ \frac{1}{3} \right\} & \\\end{align}\)
- \(\begin{align} & -5x \color{red}{+13}& = &1 \\\Leftrightarrow & -5x \color{red}{+13}\color{blue}{-13}
& = &1\color{blue}{-13} \\\Leftrightarrow &-5x
& = &-12\\\Leftrightarrow & \color{red}{-5}x
& = &-12\\\Leftrightarrow & \frac{\color{red}{-5}x}{ \color{blue}-5}
& = & \frac{-12}{-5} \\\Leftrightarrow & \color{green}{ x = \frac{12}{5} } & & \\ & V = \left\{ \frac{12}{5} \right\} & \\\end{align}\)