Bepaal de waarde van x.
- \(-x+6=-1\)
- \(-12x-4=-7\)
- \(5x-6=3\)
- \(-4x-7=-8\)
- \(-12x-15=-10\)
- \(11x+15=2\)
- \(-x+12=7\)
- \(-13x-4=-12\)
- \(-10x+11=-1\)
- \(2x+3=14\)
- \(12x-6=5\)
- \(9x+2=5\)
Bepaal de waarde van x.
Verbetersleutel
- \(\begin{align} & -x \color{red}{+6}& = &-1 \\\Leftrightarrow & -x \color{red}{+6}\color{blue}{-6}
& = &-1\color{blue}{-6} \\\Leftrightarrow &-x
& = &-7\\\Leftrightarrow & \color{red}{-}x
& = &-7\\\Leftrightarrow & \frac{\color{red}{-}x}{ \color{blue}-1}
& = & \frac{-7}{-1} \\\Leftrightarrow & \color{green}{ x = 7 } & & \\ & V = \left\{ 7 \right\} & \\\end{align}\)
- \(\begin{align} & -12x \color{red}{-4}& = &-7 \\\Leftrightarrow & -12x \color{red}{-4}\color{blue}{+4}
& = &-7\color{blue}{+4} \\\Leftrightarrow &-12x
& = &-3\\\Leftrightarrow & \color{red}{-12}x
& = &-3\\\Leftrightarrow & \frac{\color{red}{-12}x}{ \color{blue}-12}
& = & \frac{-3}{-12} \\\Leftrightarrow & \color{green}{ x = \frac{1}{4} } & & \\ & V = \left\{ \frac{1}{4} \right\} & \\\end{align}\)
- \(\begin{align} & 5x \color{red}{-6}& = &3 \\\Leftrightarrow & 5x \color{red}{-6}\color{blue}{+6}
& = &3\color{blue}{+6} \\\Leftrightarrow &5x
& = &9\\\Leftrightarrow & \color{red}{5}x
& = &9\\\Leftrightarrow & \frac{\color{red}{5}x}{ \color{blue}5}
& = & \frac{9}{5} \\\Leftrightarrow & \color{green}{ x = \frac{9}{5} } & & \\ & V = \left\{ \frac{9}{5} \right\} & \\\end{align}\)
- \(\begin{align} & -4x \color{red}{-7}& = &-8 \\\Leftrightarrow & -4x \color{red}{-7}\color{blue}{+7}
& = &-8\color{blue}{+7} \\\Leftrightarrow &-4x
& = &-1\\\Leftrightarrow & \color{red}{-4}x
& = &-1\\\Leftrightarrow & \frac{\color{red}{-4}x}{ \color{blue}-4}
& = & \frac{-1}{-4} \\\Leftrightarrow & \color{green}{ x = \frac{1}{4} } & & \\ & V = \left\{ \frac{1}{4} \right\} & \\\end{align}\)
- \(\begin{align} & -12x \color{red}{-15}& = &-10 \\\Leftrightarrow & -12x \color{red}{-15}\color{blue}{+15}
& = &-10\color{blue}{+15} \\\Leftrightarrow &-12x
& = &5\\\Leftrightarrow & \color{red}{-12}x
& = &5\\\Leftrightarrow & \frac{\color{red}{-12}x}{ \color{blue}-12}
& = & \frac{5}{-12} \\\Leftrightarrow & \color{green}{ x = \frac{-5}{12} } & & \\ & V = \left\{ \frac{-5}{12} \right\} & \\\end{align}\)
- \(\begin{align} & 11x \color{red}{+15}& = &2 \\\Leftrightarrow & 11x \color{red}{+15}\color{blue}{-15}
& = &2\color{blue}{-15} \\\Leftrightarrow &11x
& = &-13\\\Leftrightarrow & \color{red}{11}x
& = &-13\\\Leftrightarrow & \frac{\color{red}{11}x}{ \color{blue}11}
& = & \frac{-13}{11} \\\Leftrightarrow & \color{green}{ x = \frac{-13}{11} } & & \\ & V = \left\{ \frac{-13}{11} \right\} & \\\end{align}\)
- \(\begin{align} & -x \color{red}{+12}& = &7 \\\Leftrightarrow & -x \color{red}{+12}\color{blue}{-12}
& = &7\color{blue}{-12} \\\Leftrightarrow &-x
& = &-5\\\Leftrightarrow & \color{red}{-}x
& = &-5\\\Leftrightarrow & \frac{\color{red}{-}x}{ \color{blue}-1}
& = & \frac{-5}{-1} \\\Leftrightarrow & \color{green}{ x = 5 } & & \\ & V = \left\{ 5 \right\} & \\\end{align}\)
- \(\begin{align} & -13x \color{red}{-4}& = &-12 \\\Leftrightarrow & -13x \color{red}{-4}\color{blue}{+4}
& = &-12\color{blue}{+4} \\\Leftrightarrow &-13x
& = &-8\\\Leftrightarrow & \color{red}{-13}x
& = &-8\\\Leftrightarrow & \frac{\color{red}{-13}x}{ \color{blue}-13}
& = & \frac{-8}{-13} \\\Leftrightarrow & \color{green}{ x = \frac{8}{13} } & & \\ & V = \left\{ \frac{8}{13} \right\} & \\\end{align}\)
- \(\begin{align} & -10x \color{red}{+11}& = &-1 \\\Leftrightarrow & -10x \color{red}{+11}\color{blue}{-11}
& = &-1\color{blue}{-11} \\\Leftrightarrow &-10x
& = &-12\\\Leftrightarrow & \color{red}{-10}x
& = &-12\\\Leftrightarrow & \frac{\color{red}{-10}x}{ \color{blue}-10}
& = & \frac{-12}{-10} \\\Leftrightarrow & \color{green}{ x = \frac{6}{5} } & & \\ & V = \left\{ \frac{6}{5} \right\} & \\\end{align}\)
- \(\begin{align} & 2x \color{red}{+3}& = &14 \\\Leftrightarrow & 2x \color{red}{+3}\color{blue}{-3}
& = &14\color{blue}{-3} \\\Leftrightarrow &2x
& = &11\\\Leftrightarrow & \color{red}{2}x
& = &11\\\Leftrightarrow & \frac{\color{red}{2}x}{ \color{blue}2}
& = & \frac{11}{2} \\\Leftrightarrow & \color{green}{ x = \frac{11}{2} } & & \\ & V = \left\{ \frac{11}{2} \right\} & \\\end{align}\)
- \(\begin{align} & 12x \color{red}{-6}& = &5 \\\Leftrightarrow & 12x \color{red}{-6}\color{blue}{+6}
& = &5\color{blue}{+6} \\\Leftrightarrow &12x
& = &11\\\Leftrightarrow & \color{red}{12}x
& = &11\\\Leftrightarrow & \frac{\color{red}{12}x}{ \color{blue}12}
& = & \frac{11}{12} \\\Leftrightarrow & \color{green}{ x = \frac{11}{12} } & & \\ & V = \left\{ \frac{11}{12} \right\} & \\\end{align}\)
- \(\begin{align} & 9x \color{red}{+2}& = &5 \\\Leftrightarrow & 9x \color{red}{+2}\color{blue}{-2}
& = &5\color{blue}{-2} \\\Leftrightarrow &9x
& = &3\\\Leftrightarrow & \color{red}{9}x
& = &3\\\Leftrightarrow & \frac{\color{red}{9}x}{ \color{blue}9}
& = & \frac{3}{9} \\\Leftrightarrow & \color{green}{ x = \frac{1}{3} } & & \\ & V = \left\{ \frac{1}{3} \right\} & \\\end{align}\)