Volgorde van bewerkingen (gevorderd)

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1. \(-13+6.(-5)\)
2. \(-6.\sqrt{\frac{25}{16}}-\left[(\frac{9}{6}-5)-(-2)^3\right]\)
3. \(4+5.(8^2-7)\)
4. \(10+3.(4^2-4)\)
5. \(\dfrac{8}{3}-\dfrac{7}{3}\cdot\dfrac{2}{7}\)
6. \(4+6.6-60:6+2\)
7. \(-13-8.(-3-3)+6\)
8. \(10+12:(-4)\)
9. \(2.(-8)-9.(-7)-4\)
10. \(36-9:3+7\)
11. \(\left(-\dfrac{6}{4}\cdot\dfrac{24}{54}-\dfrac{1}{9}\right)^2\)
12. \(5+2.9^2-5\)

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Verbetersleutel

1. \(-13+6.(-5)=-13+(-30)=-43\)
2. \(-6.\sqrt{\frac{25}{16}}-\left[(\frac{9}{6}-5)-(-2)^3\right]=-6.\frac{5}{4}-\left[(\frac{3}{2}-5)+8\right]=\frac{-15}{2}-\left[(\frac{-7}{2})+8\right]=\frac{-15}{2}-\left[\frac{9}{2}\right]=-12\)
3. \(4+5.(8^2-7)=4+5.(64-7)=4+5.(57)=4+285=289\)
4. \(10+3.(4^2-4)=10+3.(16-4)=10+3.(12)=10+36=46\)
5. \(\dfrac{8}{3}-\dfrac{7}{3}\cdot\dfrac{2}{7}= \dfrac{8}{3}-\dfrac{7\cdot 2}{3\cdot7}= \dfrac{8}{3}-\dfrac{2}{3}= \dfrac{8-2}{3}= \dfrac{6}{3}= \dfrac{2}{1}\)
6. \(4+6.6-60:6+2=4+36-10+2=32\)
7. \(-13-8.(-3-3)+6=-13-8.(-6)+6=-13-(-48)+6=41\)
8. \(10+12:(-4)=10+ (-3)=7\)
9. \(2.(-8)-9.(-7)-4=-16+63-4=43\)
10. \(36-9:3+7=36-3+7=40\)
11. \(\left(-\dfrac{6}{4}\cdot\dfrac{24}{54}-\dfrac{1}{9}\right)^2= \left(-\dfrac{6.24}{4.54}-\dfrac{1}{9}\right)^2= \left(-\dfrac{2}{3}-\dfrac{1}{9}\right)^2= \left(-\dfrac{6}{9}-\dfrac{1}{9}\right)^2= \left(\dfrac{-7}{9}\right)^2= \dfrac{49}{81}\)
12. \(5+2.9^2-5=5+2.81-5=5+162-5=162\)