Rekenen met wortels (reeks 3)

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  1. \(\sqrt{10}\cdot\sqrt{490}\)
  2. \(-\frac{\sqrt{726}}{\sqrt{6}}\)
  3. \(\sqrt{6}\cdot\sqrt{150}\)
  4. \(-\sqrt{10}\cdot\sqrt{90}\)
  5. \(-\frac{\sqrt{12}}{\sqrt{3}}\)
  6. \(-\frac{\sqrt{28}}{\sqrt{7}}\)
  7. \(-\sqrt{2}\cdot\sqrt{50}\)
  8. \(-\frac{\sqrt{44}}{\sqrt{11}}\)
  9. \(\sqrt{3}\cdot\sqrt{48}\)
  10. \(\sqrt{2}\cdot\sqrt{18}\)
  11. \(\sqrt{5}\cdot\sqrt{45}\)
  12. \(-\sqrt{6}\cdot\sqrt{726}\)

Reken uit

Verbetersleutel

  1. \(\sqrt{10}\cdot\sqrt{490}=\sqrt{10 \cdot 490}=\sqrt{10 \cdot 10 \cdot 49}=\sqrt{10 \cdot 10} \cdot \sqrt{49}=10\cdot7=70\)
  2. \(-\frac{\sqrt{726}}{\sqrt{6}}=-\sqrt{ \frac{726}{6}}=-\sqrt{ 121}=-11\)
  3. \(\sqrt{6}\cdot\sqrt{150}=\sqrt{6 \cdot 150}=\sqrt{6 \cdot 6 \cdot 25}=\sqrt{6 \cdot 6} \cdot \sqrt{25}=6\cdot5=30\)
  4. \(-\sqrt{10}\cdot\sqrt{90}=-\sqrt{10 \cdot 90}=-\sqrt{10 \cdot 10 \cdot 9}=-\sqrt{10 \cdot 10} \cdot \sqrt{9}=-10\cdot3=-30\)
  5. \(-\frac{\sqrt{12}}{\sqrt{3}}=-\sqrt{ \frac{12}{3}}=-\sqrt{ 4}=-2\)
  6. \(-\frac{\sqrt{28}}{\sqrt{7}}=-\sqrt{ \frac{28}{7}}=-\sqrt{ 4}=-2\)
  7. \(-\sqrt{2}\cdot\sqrt{50}=-\sqrt{2 \cdot 50}=-\sqrt{2 \cdot 2 \cdot 25}=-\sqrt{2 \cdot 2} \cdot \sqrt{25}=-2\cdot5=-10\)
  8. \(-\frac{\sqrt{44}}{\sqrt{11}}=-\sqrt{ \frac{44}{11}}=-\sqrt{ 4}=-2\)
  9. \(\sqrt{3}\cdot\sqrt{48}=\sqrt{3 \cdot 48}=\sqrt{3 \cdot 3 \cdot 16}=\sqrt{3 \cdot 3} \cdot \sqrt{16}=3\cdot4=12\)
  10. \(\sqrt{2}\cdot\sqrt{18}=\sqrt{2 \cdot 18}=\sqrt{2 \cdot 2 \cdot 9}=\sqrt{2 \cdot 2} \cdot \sqrt{9}=2\cdot3=6\)
  11. \(\sqrt{5}\cdot\sqrt{45}=\sqrt{5 \cdot 45}=\sqrt{5 \cdot 5 \cdot 9}=\sqrt{5 \cdot 5} \cdot \sqrt{9}=5\cdot3=15\)
  12. \(-\sqrt{6}\cdot\sqrt{726}=-\sqrt{6 \cdot 726}=-\sqrt{6 \cdot 6 \cdot 121}=-\sqrt{6 \cdot 6} \cdot \sqrt{121}=-6\cdot11=-66\)
Oefeningengenerator wiskundeoefeningen.be 2025-04-26 07:05:58
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