Rekenen met wortels (reeks 3)

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Reken uit

  1. \(-\sqrt{5}\cdot\sqrt{605}\)
  2. \(-\sqrt{3}\cdot\sqrt{12}\)
  3. \(\frac{\sqrt{4212}}{\sqrt{13}}\)
  4. \(-\sqrt{2}\cdot\sqrt{50}\)
  5. \(-\frac{\sqrt{1690}}{\sqrt{10}}\)
  6. \(-\sqrt{10}\cdot\sqrt{490}\)
  7. \(\frac{\sqrt{1734}}{\sqrt{6}}\)
  8. \(-\sqrt{10}\cdot\sqrt{1210}\)
  9. \(-\frac{\sqrt{1083}}{\sqrt{3}}\)
  10. \(-\sqrt{5}\cdot\sqrt{245}\)
  11. \(\sqrt{3}\cdot\sqrt{147}\)
  12. \(\frac{\sqrt{192}}{\sqrt{3}}\)

Reken uit

Verbetersleutel

  1. \(-\sqrt{5}\cdot\sqrt{605}=-\sqrt{5 \cdot 605}=-\sqrt{5 \cdot 5 \cdot 121}=-\sqrt{5 \cdot 5} \cdot \sqrt{121}=-5\cdot11=-55\)
  2. \(-\sqrt{3}\cdot\sqrt{12}=-\sqrt{3 \cdot 12}=-\sqrt{3 \cdot 3 \cdot 4}=-\sqrt{3 \cdot 3} \cdot \sqrt{4}=-3\cdot2=-6\)
  3. \(\frac{\sqrt{4212}}{\sqrt{13}}=\sqrt{ \frac{4212}{13}}=\sqrt{ 324}=18\)
  4. \(-\sqrt{2}\cdot\sqrt{50}=-\sqrt{2 \cdot 50}=-\sqrt{2 \cdot 2 \cdot 25}=-\sqrt{2 \cdot 2} \cdot \sqrt{25}=-2\cdot5=-10\)
  5. \(-\frac{\sqrt{1690}}{\sqrt{10}}=-\sqrt{ \frac{1690}{10}}=-\sqrt{ 169}=-13\)
  6. \(-\sqrt{10}\cdot\sqrt{490}=-\sqrt{10 \cdot 490}=-\sqrt{10 \cdot 10 \cdot 49}=-\sqrt{10 \cdot 10} \cdot \sqrt{49}=-10\cdot7=-70\)
  7. \(\frac{\sqrt{1734}}{\sqrt{6}}=\sqrt{ \frac{1734}{6}}=\sqrt{ 289}=17\)
  8. \(-\sqrt{10}\cdot\sqrt{1210}=-\sqrt{10 \cdot 1210}=-\sqrt{10 \cdot 10 \cdot 121}=-\sqrt{10 \cdot 10} \cdot \sqrt{121}=-10\cdot11=-110\)
  9. \(-\frac{\sqrt{1083}}{\sqrt{3}}=-\sqrt{ \frac{1083}{3}}=-\sqrt{ 361}=-19\)
  10. \(-\sqrt{5}\cdot\sqrt{245}=-\sqrt{5 \cdot 245}=-\sqrt{5 \cdot 5 \cdot 49}=-\sqrt{5 \cdot 5} \cdot \sqrt{49}=-5\cdot7=-35\)
  11. \(\sqrt{3}\cdot\sqrt{147}=\sqrt{3 \cdot 147}=\sqrt{3 \cdot 3 \cdot 49}=\sqrt{3 \cdot 3} \cdot \sqrt{49}=3\cdot7=21\)
  12. \(\frac{\sqrt{192}}{\sqrt{3}}=\sqrt{ \frac{192}{3}}=\sqrt{ 64}=8\)
Oefeningengenerator wiskundeoefeningen.be 2025-12-12 23:10:15
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