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1. \(-\sqrt{10}\cdot\sqrt{1210}\)
2. \(\frac{\sqrt{1690}}{\sqrt{10}}\)
3. \(\frac{\sqrt{147}}{\sqrt{3}}\)
4. \(\sqrt{6}\cdot\sqrt{726}\)
5. \(-\frac{\sqrt{44}}{\sqrt{11}}\)
6. \(\frac{\sqrt{20}}{\sqrt{5}}\)
7. \(-\sqrt{2}\cdot\sqrt{98}\)
8. \(\sqrt{2}\cdot\sqrt{162}\)
9. \(-\frac{\sqrt{605}}{\sqrt{5}}\)
10. \(\frac{\sqrt{175}}{\sqrt{7}}\)
11. \(\sqrt{6}\cdot\sqrt{150}\)
12. \(\frac{\sqrt{162}}{\sqrt{2}}\)

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Verbetersleutel

1. \(-\sqrt{10}\cdot\sqrt{1210}=-\sqrt{10 \cdot 1210}=-\sqrt{10 \cdot 10 \cdot 121}=-\sqrt{10 \cdot 10} \cdot \sqrt{121}=-10\cdot11=-110\)
2. \(\frac{\sqrt{1690}}{\sqrt{10}}=\sqrt{ \frac{1690}{10}}=\sqrt{ 169}=13\)
3. \(\frac{\sqrt{147}}{\sqrt{3}}=\sqrt{ \frac{147}{3}}=\sqrt{ 49}=7\)
4. \(\sqrt{6}\cdot\sqrt{726}=\sqrt{6 \cdot 726}=\sqrt{6 \cdot 6 \cdot 121}=\sqrt{6 \cdot 6} \cdot \sqrt{121}=6\cdot11=66\)
5. \(-\frac{\sqrt{44}}{\sqrt{11}}=-\sqrt{ \frac{44}{11}}=-\sqrt{ 4}=-2\)
6. \(\frac{\sqrt{20}}{\sqrt{5}}=\sqrt{ \frac{20}{5}}=\sqrt{ 4}=2\)
7. \(-\sqrt{2}\cdot\sqrt{98}=-\sqrt{2 \cdot 98}=-\sqrt{2 \cdot 2 \cdot 49}=-\sqrt{2 \cdot 2} \cdot \sqrt{49}=-2\cdot7=-14\)
8. \(\sqrt{2}\cdot\sqrt{162}=\sqrt{2 \cdot 162}=\sqrt{2 \cdot 2 \cdot 81}=\sqrt{2 \cdot 2} \cdot \sqrt{81}=2\cdot9=18\)
9. \(-\frac{\sqrt{605}}{\sqrt{5}}=-\sqrt{ \frac{605}{5}}=-\sqrt{ 121}=-11\)
10. \(\frac{\sqrt{175}}{\sqrt{7}}=\sqrt{ \frac{175}{7}}=\sqrt{ 25}=5\)
11. \(\sqrt{6}\cdot\sqrt{150}=\sqrt{6 \cdot 150}=\sqrt{6 \cdot 6 \cdot 25}=\sqrt{6 \cdot 6} \cdot \sqrt{25}=6\cdot5=30\)
12. \(\frac{\sqrt{162}}{\sqrt{2}}=\sqrt{ \frac{162}{2}}=\sqrt{ 81}=9\)