Rekenen met wortels (reeks 3)

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1. \(-\frac{\sqrt{726}}{\sqrt{6}}\)
2. \(\sqrt{10}\cdot\sqrt{490}\)
3. \(\frac{\sqrt{507}}{\sqrt{3}}\)
4. \(\frac{\sqrt{1183}}{\sqrt{7}}\)
5. \(\sqrt{10}\cdot\sqrt{1210}\)
6. \(-\sqrt{3}\cdot\sqrt{147}\)
7. \(\sqrt{2}\cdot\sqrt{98}\)
8. \(\frac{\sqrt{1734}}{\sqrt{6}}\)
9. \(\frac{\sqrt{1053}}{\sqrt{13}}\)
10. \(-\frac{\sqrt{490}}{\sqrt{10}}\)
11. \(\frac{\sqrt{405}}{\sqrt{5}}\)
12. \(-\sqrt{6}\cdot\sqrt{726}\)

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Verbetersleutel

1. \(-\frac{\sqrt{726}}{\sqrt{6}}=-\sqrt{ \frac{726}{6}}=-\sqrt{ 121}=-11\)
2. \(\sqrt{10}\cdot\sqrt{490}=\sqrt{10 \cdot 490}=\sqrt{10 \cdot 10 \cdot 49}=\sqrt{10 \cdot 10} \cdot \sqrt{49}=10\cdot7=70\)
3. \(\frac{\sqrt{507}}{\sqrt{3}}=\sqrt{ \frac{507}{3}}=\sqrt{ 169}=13\)
4. \(\frac{\sqrt{1183}}{\sqrt{7}}=\sqrt{ \frac{1183}{7}}=\sqrt{ 169}=13\)
5. \(\sqrt{10}\cdot\sqrt{1210}=\sqrt{10 \cdot 1210}=\sqrt{10 \cdot 10 \cdot 121}=\sqrt{10 \cdot 10} \cdot \sqrt{121}=10\cdot11=110\)
6. \(-\sqrt{3}\cdot\sqrt{147}=-\sqrt{3 \cdot 147}=-\sqrt{3 \cdot 3 \cdot 49}=-\sqrt{3 \cdot 3} \cdot \sqrt{49}=-3\cdot7=-21\)
7. \(\sqrt{2}\cdot\sqrt{98}=\sqrt{2 \cdot 98}=\sqrt{2 \cdot 2 \cdot 49}=\sqrt{2 \cdot 2} \cdot \sqrt{49}=2\cdot7=14\)
8. \(\frac{\sqrt{1734}}{\sqrt{6}}=\sqrt{ \frac{1734}{6}}=\sqrt{ 289}=17\)
9. \(\frac{\sqrt{1053}}{\sqrt{13}}=\sqrt{ \frac{1053}{13}}=\sqrt{ 81}=9\)
10. \(-\frac{\sqrt{490}}{\sqrt{10}}=-\sqrt{ \frac{490}{10}}=-\sqrt{ 49}=-7\)
11. \(\frac{\sqrt{405}}{\sqrt{5}}=\sqrt{ \frac{405}{5}}=\sqrt{ 81}=9\)
12. \(-\sqrt{6}\cdot\sqrt{726}=-\sqrt{6 \cdot 726}=-\sqrt{6 \cdot 6 \cdot 121}=-\sqrt{6 \cdot 6} \cdot \sqrt{121}=-6\cdot11=-66\)