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1. \(\sqrt{5}\cdot\sqrt{20}\)
2. \(-\sqrt{10}\cdot\sqrt{1210}\)
3. \(\frac{\sqrt{810}}{\sqrt{10}}\)
4. \(-\frac{\sqrt{2890}}{\sqrt{10}}\)
5. \(\frac{\sqrt{52}}{\sqrt{13}}\)
6. \(-\sqrt{6}\cdot\sqrt{150}\)
7. \(\sqrt{10}\cdot\sqrt{490}\)
8. \(-\sqrt{10}\cdot\sqrt{810}\)
9. \(\frac{\sqrt{722}}{\sqrt{2}}\)
10. \(-\frac{\sqrt{1083}}{\sqrt{3}}\)
11. \(-\frac{\sqrt{363}}{\sqrt{3}}\)
12. \(\frac{\sqrt{891}}{\sqrt{11}}\)

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Verbetersleutel

1. \(\sqrt{5}\cdot\sqrt{20}=\sqrt{5 \cdot 20}=\sqrt{5 \cdot 5 \cdot 4}=\sqrt{5 \cdot 5} \cdot \sqrt{4}=5\cdot2=10\)
2. \(-\sqrt{10}\cdot\sqrt{1210}=-\sqrt{10 \cdot 1210}=-\sqrt{10 \cdot 10 \cdot 121}=-\sqrt{10 \cdot 10} \cdot \sqrt{121}=-10\cdot11=-110\)
3. \(\frac{\sqrt{810}}{\sqrt{10}}=\sqrt{ \frac{810}{10}}=\sqrt{ 81}=9\)
4. \(-\frac{\sqrt{2890}}{\sqrt{10}}=-\sqrt{ \frac{2890}{10}}=-\sqrt{ 289}=-17\)
5. \(\frac{\sqrt{52}}{\sqrt{13}}=\sqrt{ \frac{52}{13}}=\sqrt{ 4}=2\)
6. \(-\sqrt{6}\cdot\sqrt{150}=-\sqrt{6 \cdot 150}=-\sqrt{6 \cdot 6 \cdot 25}=-\sqrt{6 \cdot 6} \cdot \sqrt{25}=-6\cdot5=-30\)
7. \(\sqrt{10}\cdot\sqrt{490}=\sqrt{10 \cdot 490}=\sqrt{10 \cdot 10 \cdot 49}=\sqrt{10 \cdot 10} \cdot \sqrt{49}=10\cdot7=70\)
8. \(-\sqrt{10}\cdot\sqrt{810}=-\sqrt{10 \cdot 810}=-\sqrt{10 \cdot 10 \cdot 81}=-\sqrt{10 \cdot 10} \cdot \sqrt{81}=-10\cdot9=-90\)
9. \(\frac{\sqrt{722}}{\sqrt{2}}=\sqrt{ \frac{722}{2}}=\sqrt{ 361}=19\)
10. \(-\frac{\sqrt{1083}}{\sqrt{3}}=-\sqrt{ \frac{1083}{3}}=-\sqrt{ 361}=-19\)
11. \(-\frac{\sqrt{363}}{\sqrt{3}}=-\sqrt{ \frac{363}{3}}=-\sqrt{ 121}=-11\)
12. \(\frac{\sqrt{891}}{\sqrt{11}}=\sqrt{ \frac{891}{11}}=\sqrt{ 81}=9\)