Rekenen met wortels (reeks 5)

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Maak de noemer wortelvrij

1. \(\frac{5}{\sqrt{19}}\)
2. \(\frac{59}{\sqrt{15}}\)
3. \(\frac{49}{\sqrt{17}}\)
4. \(\frac{24}{\sqrt{13}}\)
5. \(\frac{24}{\sqrt{11}}\)
6. \(\frac{10}{\sqrt{17}}\)
7. \(\frac{21}{\sqrt{8}}\)
8. \(\frac{41}{\sqrt{13}}\)
9. \(\frac{8}{\sqrt{3}}\)
10. \(\frac{9}{\sqrt{14}}\)
11. \(\frac{60}{\sqrt{17}}\)
12. \(\frac{26}{\sqrt{6}}\)

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Maak de noemer wortelvrij

Verbetersleutel

1. \(\frac{5}{\sqrt{19}}=\frac{5\cdot \color{red}{\sqrt{19}} }{\sqrt{19}\cdot \color{red}{\sqrt{19}} }=\frac{5\cdot\sqrt{19}}{19}\)
2. \(\frac{59}{\sqrt{15}}=\frac{59\cdot \color{red}{\sqrt{15}} }{\sqrt{15}\cdot \color{red}{\sqrt{15}} }=\frac{59\cdot\sqrt{15}}{15}\)
3. \(\frac{49}{\sqrt{17}}=\frac{49\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{49\cdot\sqrt{17}}{17}\)
4. \(\frac{24}{\sqrt{13}}=\frac{24\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{24\cdot\sqrt{13}}{13}\)
5. \(\frac{24}{\sqrt{11}}=\frac{24\cdot \color{red}{\sqrt{11}} }{\sqrt{11}\cdot \color{red}{\sqrt{11}} }=\frac{24\cdot\sqrt{11}}{11}\)
6. \(\frac{10}{\sqrt{17}}=\frac{10\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{10\cdot\sqrt{17}}{17}\)
7. \(\frac{21}{\sqrt{8}}=\frac{21\cdot \color{red}{\sqrt{8}} }{\sqrt{8}\cdot \color{red}{\sqrt{8}} }=\frac{21\cdot\sqrt{8}}{8}\)
8. \(\frac{41}{\sqrt{13}}=\frac{41\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{41\cdot\sqrt{13}}{13}\)
9. \(\frac{8}{\sqrt{3}}=\frac{8\cdot \color{red}{\sqrt{3}} }{\sqrt{3}\cdot \color{red}{\sqrt{3}} }=\frac{8\cdot\sqrt{3}}{3}\)
10. \(\frac{9}{\sqrt{14}}=\frac{9\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{9\cdot\sqrt{14}}{14}\)
11. \(\frac{60}{\sqrt{17}}=\frac{60\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{60\cdot\sqrt{17}}{17}\)
12. \(\frac{26}{\sqrt{6}}=\frac{26\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{26\cdot\sqrt{6}}{6}=\frac{13\cdot\sqrt{6}}{3}\)