Rekenen met wortels (reeks 5)

Hoofdmenu Eentje per keer  🖨

Maak de noemer wortelvrij

1. \(\frac{3}{\sqrt{3}}\)
2. \(\frac{6}{\sqrt{11}}\)
3. \(\frac{9}{\sqrt{15}}\)
4. \(\frac{26}{\sqrt{13}}\)
5. \(\frac{35}{\sqrt{7}}\)
6. \(\frac{34}{\sqrt{13}}\)
7. \(\frac{45}{\sqrt{10}}\)
8. \(\frac{31}{\sqrt{19}}\)
9. \(\frac{26}{\sqrt{14}}\)
10. \(\frac{59}{\sqrt{13}}\)
11. \(\frac{57}{\sqrt{17}}\)
12. \(\frac{9}{\sqrt{11}}\)

---

Maak de noemer wortelvrij

Verbetersleutel

1. \(\frac{3}{\sqrt{3}}=\frac{3\cdot \color{red}{\sqrt{3}} }{\sqrt{3}\cdot \color{red}{\sqrt{3}} }=\frac{3\cdot\sqrt{3}}{3}=\frac{\sqrt{3}}{1}\)
2. \(\frac{6}{\sqrt{11}}=\frac{6\cdot \color{red}{\sqrt{11}} }{\sqrt{11}\cdot \color{red}{\sqrt{11}} }=\frac{6\cdot\sqrt{11}}{11}\)
3. \(\frac{9}{\sqrt{15}}=\frac{9\cdot \color{red}{\sqrt{15}} }{\sqrt{15}\cdot \color{red}{\sqrt{15}} }=\frac{9\cdot\sqrt{15}}{15}=\frac{3\cdot\sqrt{15}}{5}\)
4. \(\frac{26}{\sqrt{13}}=\frac{26\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{26\cdot\sqrt{13}}{13}=2\cdot\sqrt{13}\)
5. \(\frac{35}{\sqrt{7}}=\frac{35\cdot \color{red}{\sqrt{7}} }{\sqrt{7}\cdot \color{red}{\sqrt{7}} }=\frac{35\cdot\sqrt{7}}{7}=5\cdot\sqrt{7}\)
6. \(\frac{34}{\sqrt{13}}=\frac{34\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{34\cdot\sqrt{13}}{13}\)
7. \(\frac{45}{\sqrt{10}}=\frac{45\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{45\cdot\sqrt{10}}{10}=\frac{9\cdot\sqrt{10}}{2}\)
8. \(\frac{31}{\sqrt{19}}=\frac{31\cdot \color{red}{\sqrt{19}} }{\sqrt{19}\cdot \color{red}{\sqrt{19}} }=\frac{31\cdot\sqrt{19}}{19}\)
9. \(\frac{26}{\sqrt{14}}=\frac{26\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{26\cdot\sqrt{14}}{14}=\frac{13\cdot\sqrt{14}}{7}\)
10. \(\frac{59}{\sqrt{13}}=\frac{59\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{59\cdot\sqrt{13}}{13}\)
11. \(\frac{57}{\sqrt{17}}=\frac{57\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{57\cdot\sqrt{17}}{17}\)
12. \(\frac{9}{\sqrt{11}}=\frac{9\cdot \color{red}{\sqrt{11}} }{\sqrt{11}\cdot \color{red}{\sqrt{11}} }=\frac{9\cdot\sqrt{11}}{11}\)