Maak de noemer wortelvrij
- \(\frac{16}{\sqrt{8}}\)
- \(\frac{2}{\sqrt{5}}\)
- \(\frac{32}{\sqrt{14}}\)
- \(\frac{31}{\sqrt{7}}\)
- \(\frac{46}{\sqrt{2}}\)
- \(\frac{40}{\sqrt{10}}\)
- \(\frac{19}{\sqrt{17}}\)
- \(\frac{2}{\sqrt{7}}\)
- \(\frac{2}{\sqrt{8}}\)
- \(\frac{38}{\sqrt{11}}\)
- \(\frac{4}{\sqrt{13}}\)
- \(\frac{26}{\sqrt{6}}\)
Maak de noemer wortelvrij
Verbetersleutel
- \(\frac{16}{\sqrt{8}}=\frac{16\cdot \color{red}{\sqrt{8}} }{\sqrt{8}\cdot \color{red}{\sqrt{8}} }=\frac{16\cdot\sqrt{8}}{8}=2\cdot\sqrt{8}\)
- \(\frac{2}{\sqrt{5}}=\frac{2\cdot \color{red}{\sqrt{5}} }{\sqrt{5}\cdot \color{red}{\sqrt{5}} }=\frac{2\cdot\sqrt{5}}{5}\)
- \(\frac{32}{\sqrt{14}}=\frac{32\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{32\cdot\sqrt{14}}{14}=\frac{16\cdot\sqrt{14}}{7}\)
- \(\frac{31}{\sqrt{7}}=\frac{31\cdot \color{red}{\sqrt{7}} }{\sqrt{7}\cdot \color{red}{\sqrt{7}} }=\frac{31\cdot\sqrt{7}}{7}\)
- \(\frac{46}{\sqrt{2}}=\frac{46\cdot \color{red}{\sqrt{2}} }{\sqrt{2}\cdot \color{red}{\sqrt{2}} }=\frac{46\cdot\sqrt{2}}{2}=23\cdot\sqrt{2}\)
- \(\frac{40}{\sqrt{10}}=\frac{40\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{40\cdot\sqrt{10}}{10}=4\cdot\sqrt{10}\)
- \(\frac{19}{\sqrt{17}}=\frac{19\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{19\cdot\sqrt{17}}{17}\)
- \(\frac{2}{\sqrt{7}}=\frac{2\cdot \color{red}{\sqrt{7}} }{\sqrt{7}\cdot \color{red}{\sqrt{7}} }=\frac{2\cdot\sqrt{7}}{7}\)
- \(\frac{2}{\sqrt{8}}=\frac{2\cdot \color{red}{\sqrt{8}} }{\sqrt{8}\cdot \color{red}{\sqrt{8}} }=\frac{2\cdot\sqrt{8}}{8}=\frac{\sqrt{8}}{4}\)
- \(\frac{38}{\sqrt{11}}=\frac{38\cdot \color{red}{\sqrt{11}} }{\sqrt{11}\cdot \color{red}{\sqrt{11}} }=\frac{38\cdot\sqrt{11}}{11}\)
- \(\frac{4}{\sqrt{13}}=\frac{4\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{4\cdot\sqrt{13}}{13}\)
- \(\frac{26}{\sqrt{6}}=\frac{26\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{26\cdot\sqrt{6}}{6}=\frac{13\cdot\sqrt{6}}{3}\)