Breuken delen (reeks 1)

Hoofdmenu Eentje per keer  🖨

Deel de breuken

1. \(\frac{12}{15} : \frac{4}{13}\)
2. \(\frac{6}{11} : \frac{6}{11}\)
3. \(\frac{4}{5} : \frac{2}{14}\)
4. \(\frac{12}{4} : \frac{3}{4}\)
5. \(\frac{12}{13} : \frac{4}{9}\)
6. \(\frac{3}{2} : \frac{12}{3}\)
7. \(\frac{4}{11} : \frac{9}{6}\)
8. \(\frac{8}{6} : \frac{3}{11}\)
9. \(\frac{4}{14} : \frac{5}{3}\)
10. \(\frac{11}{9} : \frac{7}{15}\)
11. \(\frac{3}{12} : \frac{5}{4}\)
12. \(\frac{2}{5} : \frac{8}{14}\)

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Deel de breuken

Verbetersleutel

1. \(\frac{12}{15} : \frac{4}{13}\\=\frac{4}{5} : \frac{4}{13}\\=\frac{4}{5} . \frac{13}{4}\\=\frac{4.13}{5.4}\\=\frac{52}{20}\\=\frac{13}{5}\)
2. \(\frac{6}{11} : \frac{6}{11}\\=\frac{6}{11} . \frac{11}{6}\\=\frac{6.11}{11.6}\\=\frac{66}{66}\\=\frac{1}{1}= 1\)
3. \(\frac{4}{5} : \frac{2}{14}\\=\frac{4}{5} : \frac{1}{7}\\=\frac{4}{5} . \frac{7}{1}\\=\frac{4.7}{5.1}\\=\frac{28}{5}\)
4. \(\frac{12}{4} : \frac{3}{4}\\=\frac{3}{1} : \frac{3}{4}\\=\frac{3}{1} . \frac{4}{3}\\=\frac{3.4}{1.3}\\=\frac{12}{3}\\=\frac{4}{1}= 4\)
5. \(\frac{12}{13} : \frac{4}{9}\\=\frac{12}{13} . \frac{9}{4}\\=\frac{12.9}{13.4}\\=\frac{108}{52}\\=\frac{27}{13}\)
6. \(\frac{3}{2} : \frac{12}{3}\\=\frac{3}{2} : \frac{4}{1}\\=\frac{3}{2} . \frac{1}{4}\\=\frac{3.1}{2.4}\\=\frac{3}{8}\)
7. \(\frac{4}{11} : \frac{9}{6}\\=\frac{4}{11} : \frac{3}{2}\\=\frac{4}{11} . \frac{2}{3}\\=\frac{4.2}{11.3}\\=\frac{8}{33}\)
8. \(\frac{8}{6} : \frac{3}{11}\\=\frac{4}{3} : \frac{3}{11}\\=\frac{4}{3} . \frac{11}{3}\\=\frac{4.11}{3.3}\\=\frac{44}{9}\)
9. \(\frac{4}{14} : \frac{5}{3}\\=\frac{2}{7} : \frac{5}{3}\\=\frac{2}{7} . \frac{3}{5}\\=\frac{2.3}{7.5}\\=\frac{6}{35}\)
10. \(\frac{11}{9} : \frac{7}{15}\\=\frac{11}{9} . \frac{15}{7}\\=\frac{11.15}{9.7}\\=\frac{165}{63}\\=\frac{55}{21}\)
11. \(\frac{3}{12} : \frac{5}{4}\\=\frac{1}{4} : \frac{5}{4}\\=\frac{1}{4} . \frac{4}{5}\\=\frac{1.4}{4.5}\\=\frac{4}{20}\\=\frac{1}{5}\)
12. \(\frac{2}{5} : \frac{8}{14}\\=\frac{2}{5} : \frac{4}{7}\\=\frac{2}{5} . \frac{7}{4}\\=\frac{2.7}{5.4}\\=\frac{14}{20}\\=\frac{7}{10}\)