Breuken optellen (reeks 2)

Hoofdmenu Eentje per keer 

Tel de breuken op

  1. \(\frac{7}{8}+\frac{6}{5}\)
  2. \(\frac{14}{13}+\frac{6}{7}\)
  3. \(\frac{14}{15}+\frac{16}{9}\)
  4. \(\frac{5}{11}+\frac{10}{19}\)
  5. \(\frac{-1}{20}+\frac{14}{11}\)
  6. \(\frac{-20}{3}+\frac{9}{4}\)
  7. \(\frac{-6}{7}+\frac{3}{2}\)
  8. \(\frac{-11}{3}+\frac{16}{3}\)
  9. \(\frac{-3}{7}+\frac{3}{4}\)
  10. \(\frac{-7}{18}+\frac{3}{2}\)
  11. \(\frac{5}{13}+\frac{10}{7}\)
  12. \(\frac{-5}{3}+\frac{17}{11}\)

Tel de breuken op

Verbetersleutel

  1. \(\frac{7}{8}+\frac{6}{5}\\=\frac{35}{40}+\frac{48}{40}\\=\frac{35+48}{40}\\=\frac{83}{40}\)
  2. \(\frac{14}{13}+\frac{6}{7}\\=\frac{98}{91}+\frac{78}{91}\\=\frac{98+78}{91}\\=\frac{176}{91}\)
  3. \(\frac{14}{15}+\frac{16}{9}\\=\frac{42}{45}+\frac{80}{45}\\=\frac{42+80}{45}\\=\frac{122}{45}\)
  4. \(\frac{5}{11}+\frac{10}{19}\\=\frac{95}{209}+\frac{110}{209}\\=\frac{95+110}{209}\\=\frac{205}{209}\)
  5. \(\frac{-1}{20}+\frac{14}{11}\\=\frac{-11}{220}+\frac{280}{220}\\=\frac{-11+280}{220}\\=\frac{269}{220}\)
  6. \(\frac{-20}{3}+\frac{9}{4}\\=\frac{-80}{12}+\frac{27}{12}\\=\frac{-80+27}{12}\\=\frac{-53}{12}\\=\frac{53}{-12}\)
  7. \(\frac{-6}{7}+\frac{3}{2}\\=\frac{-12}{14}+\frac{21}{14}\\=\frac{-12+21}{14}\\=\frac{9}{14}\)
  8. \(\frac{-11}{3}+\frac{16}{3}\\=\frac{-11+16}{3}\\=\frac{5}{3}\)
  9. \(\frac{-3}{7}+\frac{3}{4}\\=\frac{-12}{28}+\frac{21}{28}\\=\frac{-12+21}{28}\\=\frac{9}{28}\)
  10. \(\frac{-7}{18}+\frac{3}{2}\\=\frac{-7+3}{18}\\=\frac{-4}{18}\\=\frac{-2}{9}\)
  11. \(\frac{5}{13}+\frac{10}{7}\\=\frac{35}{91}+\frac{130}{91}\\=\frac{35+130}{91}\\=\frac{165}{91}\)
  12. \(\frac{-5}{3}+\frac{17}{11}\\=\frac{-55}{33}+\frac{51}{33}\\=\frac{-55+51}{33}\\=\frac{-4}{33}\)
Oefeningengenerator wiskundeoefeningen.be 2026-04-08 10:42:39
Een site van Busleyden Atheneum Mechelen