Breuken verm. (reeks 1)

Hoofdmenu Eentje per keer 

Vermenigvuldig de breuken

  1. \(\frac{9}{4} . \frac{9}{11}\)
  2. \(\frac{8}{9} . \frac{8}{7}\)
  3. \(\frac{8}{3} . \frac{8}{11}\)
  4. \(\frac{12}{12} . \frac{5}{9}\)
  5. \(\frac{5}{8} . \frac{12}{4}\)
  6. \(\frac{3}{6} . \frac{10}{10}\)
  7. \(\frac{10}{2} . \frac{4}{7}\)
  8. \(\frac{2}{10} . \frac{3}{10}\)
  9. \(\frac{7}{6} . \frac{11}{9}\)
  10. \(\frac{3}{5} . \frac{12}{9}\)
  11. \(\frac{2}{7} . \frac{8}{12}\)
  12. \(\frac{3}{2} . \frac{9}{8}\)

Vermenigvuldig de breuken

Verbetersleutel

  1. \(\frac{9}{4} . \frac{9}{11}\\=\frac{9.9}{4.11}\\=\frac{81}{44}\)
  2. \(\frac{8}{9} . \frac{8}{7}\\=\frac{8.8}{9.7}\\=\frac{64}{63}\)
  3. \(\frac{8}{3} . \frac{8}{11}\\=\frac{8.8}{3.11}\\=\frac{64}{33}\)
  4. \(\frac{12}{12} . \frac{5}{9}\\=\frac{1}{1} . \frac{5}{9}\\=\frac{1.5}{1.9}\\=\frac{5}{9}\)
  5. \(\frac{5}{8} . \frac{12}{4}\\=\frac{5}{8} . \frac{3}{1}\\=\frac{5.3}{8.1}\\=\frac{15}{8}\)
  6. \(\frac{3}{6} . \frac{10}{10}\\=\frac{1}{2} . \frac{1}{1}\\=\frac{1.1}{2.1}\\=\frac{1}{2}\)
  7. \(\frac{10}{2} . \frac{4}{7}\\=\frac{5}{1} . \frac{4}{7}\\=\frac{5.4}{1.7}\\=\frac{20}{7}\)
  8. \(\frac{2}{10} . \frac{3}{10}\\=\frac{1}{5} . \frac{3}{10}\\=\frac{1.3}{5.10}\\=\frac{3}{50}\)
  9. \(\frac{7}{6} . \frac{11}{9}\\=\frac{7.11}{6.9}\\=\frac{77}{54}\)
  10. \(\frac{3}{5} . \frac{12}{9}\\=\frac{3}{5} . \frac{4}{3}\\=\frac{3.4}{5.3}\\=\frac{12}{15}\\=\frac{4}{5}\)
  11. \(\frac{2}{7} . \frac{8}{12}\\=\frac{2}{7} . \frac{2}{3}\\=\frac{2.2}{7.3}\\=\frac{4}{21}\)
  12. \(\frac{3}{2} . \frac{9}{8}\\=\frac{3.9}{2.8}\\=\frac{27}{16}\)
Oefeningengenerator wiskundeoefeningen.be 2025-12-05 08:39:15
Een site van Busleyden Atheneum Mechelen