Bepaal modulus en argument
- \(-9\)
- \(8+2i\)
- \(-9+3i\)
- \(10+7i\)
- \(-9+5i\)
- \(7-5i\)
- \(6-5i\)
- \(-2+i\)
- \(-10-10i\)
- \(-3-7i\)
- \(2+5i\)
- \(7-7i\)
Bepaal modulus en argument
Verbetersleutel
- \(-9\\ \text{ Dit complex getal ligt op het negatief gedeelte van de x-as. We hebben geen berekeningen nodig om r of } \alpha \text{ te berekenen.} \\\text{r = }9\\\alpha = 180 ^\circ \\\)
- \(8+2i\\ r = \sqrt{8^2+2^2} = \sqrt{68} \\ \alpha = tan^{-1}(\frac{2}{8}) \Leftrightarrow \alpha =14^\circ 2' 10{,}5"\text{ of } \alpha = 194^\circ 2' 10{,}5"\\8+2i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 14^\circ 2' 10{,}5"\)
- \(-9+3i\\ r = \sqrt{(-9)^2+3^2} = \sqrt{90} \\ \alpha = tan^{-1}(\frac{3}{-9}) \Leftrightarrow \alpha =161^\circ 33' 54{,}2"\text{ of } \alpha = 341^\circ 33' 54{,}2"\\-9+3i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 161^\circ 33' 54{,}2"\)
- \(10+7i\\ r = \sqrt{10^2+7^2} = \sqrt{149} \\ \alpha = tan^{-1}(\frac{7}{10}) \Leftrightarrow \alpha =34^\circ 59' 31{,}3"\text{ of } \alpha = 214^\circ 59' 31{,}3"\\10+7i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 34^\circ 59' 31{,}3"\)
- \(-9+5i\\ r = \sqrt{(-9)^2+5^2} = \sqrt{106} \\ \alpha = tan^{-1}(\frac{5}{-9}) \Leftrightarrow \alpha =150^\circ 56' 43{,}4"\text{ of } \alpha = 330^\circ 56' 43{,}4"\\-9+5i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 150^\circ 56' 43{,}4"\)
- \(7-5i\\ r = \sqrt{7^2+(-5)^2} = \sqrt{74} \\ \alpha = tan^{-1}(\frac{-5}{7}) \Leftrightarrow \alpha =144^\circ 27' 44{,}4"\text{ of } \alpha = 324^\circ 27' 44{,}4"\\7-5i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 324^\circ 27' 44{,}4"\)
- \(6-5i\\ r = \sqrt{6^2+(-5)^2} = \sqrt{61} \\ \alpha = tan^{-1}(\frac{-5}{6}) \Leftrightarrow \alpha =140^\circ 11' 39{,}9"\text{ of } \alpha = 320^\circ 11' 39{,}9"\\6-5i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 320^\circ 11' 39{,}9"\)
- \(-2+i\\ r = \sqrt{(-2)^2+1^2} = \sqrt{5} \\ \alpha = tan^{-1}(\frac{1}{-2}) \Leftrightarrow \alpha =153^\circ 26' 5{,}8"\text{ of } \alpha = 333^\circ 26' 5{,}8"\\-2+i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 153^\circ 26' 5{,}8"\)
- \(-10-10i\\ r = \sqrt{(-10)^2+(-10)^2} = \sqrt{200} \\ \alpha = tan^{-1}(\frac{-10}{-10}) \Leftrightarrow \alpha =45^\circ \text{ of } \alpha = 225^\circ \\-10-10i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 225^\circ \)
- \(-3-7i\\ r = \sqrt{(-3)^2+(-7)^2} = \sqrt{58} \\ \alpha = tan^{-1}(\frac{-7}{-3}) \Leftrightarrow \alpha =66^\circ 48' 5{,}1"\text{ of } \alpha = 246^\circ 48' 5{,}1"\\-3-7i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 246^\circ 48' 5{,}1"\)
- \(2+5i\\ r = \sqrt{2^2+5^2} = \sqrt{29} \\ \alpha = tan^{-1}(\frac{5}{2}) \Leftrightarrow \alpha =68^\circ 11' 54{,}9"\text{ of } \alpha = 248^\circ 11' 54{,}9"\\2+5i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 68^\circ 11' 54{,}9"\)
- \(7-7i\\ r = \sqrt{7^2+(-7)^2} = \sqrt{98} \\ \alpha = tan^{-1}(\frac{-7}{7}) \Leftrightarrow \alpha =135^\circ \text{ of } \alpha = 315^\circ \\7-7i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 315^\circ \)