Bepaal modulus en argument
- \(8-9i\)
- \(-4+2i\)
- \(-7+6i\)
- \(-6-9i\)
- \(-3+2i\)
- \(4-4i\)
- \(2+i\)
- \(8+6i\)
- \(-5+i\)
- \(-9-6i\)
- \(6+2i\)
- \(5+5i\)
Bepaal modulus en argument
Verbetersleutel
- \(8-9i\\ r = \sqrt{8^2+(-9)^2} = \sqrt{145} \\ \alpha = tan^{-1}(\frac{-9}{8}) \Leftrightarrow \alpha =131^\circ 38' 0{,}7"\text{ of } \alpha = 311^\circ 38' 0{,}7"\\8-9i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 311^\circ 38' 0{,}7"\)
- \(-4+2i\\ r = \sqrt{(-4)^2+2^2} = \sqrt{20} \\ \alpha = tan^{-1}(\frac{2}{-4}) \Leftrightarrow \alpha =153^\circ 26' 5{,}8"\text{ of } \alpha = 333^\circ 26' 5{,}8"\\-4+2i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 153^\circ 26' 5{,}8"\)
- \(-7+6i\\ r = \sqrt{(-7)^2+6^2} = \sqrt{85} \\ \alpha = tan^{-1}(\frac{6}{-7}) \Leftrightarrow \alpha =139^\circ 23' 55{,}3"\text{ of } \alpha = 319^\circ 23' 55{,}3"\\-7+6i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 139^\circ 23' 55{,}3"\)
- \(-6-9i\\ r = \sqrt{(-6)^2+(-9)^2} = \sqrt{117} \\ \alpha = tan^{-1}(\frac{-9}{-6}) \Leftrightarrow \alpha =56^\circ 18' 35{,}8"\text{ of } \alpha = 236^\circ 18' 35{,}8"\\-6-9i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 236^\circ 18' 35{,}8"\)
- \(-3+2i\\ r = \sqrt{(-3)^2+2^2} = \sqrt{13} \\ \alpha = tan^{-1}(\frac{2}{-3}) \Leftrightarrow \alpha =146^\circ 18' 35{,}8"\text{ of } \alpha = 326^\circ 18' 35{,}8"\\-3+2i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 146^\circ 18' 35{,}8"\)
- \(4-4i\\ r = \sqrt{4^2+(-4)^2} = \sqrt{32} \\ \alpha = tan^{-1}(\frac{-4}{4}) \Leftrightarrow \alpha =135^\circ \text{ of } \alpha = 315^\circ \\4-4i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 315^\circ \)
- \(2+i\\ r = \sqrt{2^2+1^2} = \sqrt{5} \\ \alpha = tan^{-1}(\frac{1}{2}) \Leftrightarrow \alpha =26^\circ 33' 54{,}2"\text{ of } \alpha = 206^\circ 33' 54{,}2"\\2+i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 26^\circ 33' 54{,}2"\)
- \(8+6i\\ r = \sqrt{8^2+6^2} = \sqrt{100} \\ \alpha = tan^{-1}(\frac{6}{8}) \Leftrightarrow \alpha =36^\circ 52' 11{,}6"\text{ of } \alpha = 216^\circ 52' 11{,}6"\\8+6i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 36^\circ 52' 11{,}6"\)
- \(-5+i\\ r = \sqrt{(-5)^2+1^2} = \sqrt{26} \\ \alpha = tan^{-1}(\frac{1}{-5}) \Leftrightarrow \alpha =168^\circ 41' 24{,}2"\text{ of } \alpha = 348^\circ 41' 24{,}2"\\-5+i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 168^\circ 41' 24{,}2"\)
- \(-9-6i\\ r = \sqrt{(-9)^2+(-6)^2} = \sqrt{117} \\ \alpha = tan^{-1}(\frac{-6}{-9}) \Leftrightarrow \alpha =33^\circ 41' 24{,}2"\text{ of } \alpha = 213^\circ 41' 24{,}2"\\-9-6i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 213^\circ 41' 24{,}2"\)
- \(6+2i\\ r = \sqrt{6^2+2^2} = \sqrt{40} \\ \alpha = tan^{-1}(\frac{2}{6}) \Leftrightarrow \alpha =18^\circ 26' 5{,}8"\text{ of } \alpha = 198^\circ 26' 5{,}8"\\6+2i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 18^\circ 26' 5{,}8"\)
- \(5+5i\\ r = \sqrt{5^2+5^2} = \sqrt{50} \\ \alpha = tan^{-1}(\frac{5}{5}) \Leftrightarrow \alpha =45^\circ \text{ of } \alpha = 225^\circ \\5+5i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 45^\circ \)