Bepaal modulus en argument
- \(-10+10i\)
- \(-i\)
- \(-1-9i\)
- \(5-2i\)
- \(5+8i\)
- \(7-7i\)
- \(-5+5i\)
- \(9-2i\)
- \(9+10i\)
- \(2-6i\)
- \(7+9i\)
- \(9-7i\)
Bepaal modulus en argument
Verbetersleutel
- \(-10+10i\\ r = \sqrt{(-10)^2+10^2} = \sqrt{200} \\ \alpha = tan^{-1}(\frac{10}{-10}) \Leftrightarrow \alpha =135^\circ \text{ of } \alpha = 315^\circ \\-10+10i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 135^\circ \)
- \(-i\\ \text{ Dit complex getal ligt op het negatief gedeelte van de y-as. We hebben geen berekeningen nodig om r of } \alpha \text{ te berekenen.} \\\text{r = }1\\\alpha = 270 ^\circ \\\)
- \(-1-9i\\ r = \sqrt{(-1)^2+(-9)^2} = \sqrt{82} \\ \alpha = tan^{-1}(\frac{-9}{-1}) \Leftrightarrow \alpha =83^\circ 39' 35{,}3"\text{ of } \alpha = 263^\circ 39' 35{,}3"\\-1-9i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 263^\circ 39' 35{,}3"\)
- \(5-2i\\ r = \sqrt{5^2+(-2)^2} = \sqrt{29} \\ \alpha = tan^{-1}(\frac{-2}{5}) \Leftrightarrow \alpha =158^\circ 11' 54{,}9"\text{ of } \alpha = 338^\circ 11' 54{,}9"\\5-2i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 338^\circ 11' 54{,}9"\)
- \(5+8i\\ r = \sqrt{5^2+8^2} = \sqrt{89} \\ \alpha = tan^{-1}(\frac{8}{5}) \Leftrightarrow \alpha =57^\circ 59' 40{,}6"\text{ of } \alpha = 237^\circ 59' 40{,}6"\\5+8i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 57^\circ 59' 40{,}6"\)
- \(7-7i\\ r = \sqrt{7^2+(-7)^2} = \sqrt{98} \\ \alpha = tan^{-1}(\frac{-7}{7}) \Leftrightarrow \alpha =135^\circ \text{ of } \alpha = 315^\circ \\7-7i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 315^\circ \)
- \(-5+5i\\ r = \sqrt{(-5)^2+5^2} = \sqrt{50} \\ \alpha = tan^{-1}(\frac{5}{-5}) \Leftrightarrow \alpha =135^\circ \text{ of } \alpha = 315^\circ \\-5+5i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 135^\circ \)
- \(9-2i\\ r = \sqrt{9^2+(-2)^2} = \sqrt{85} \\ \alpha = tan^{-1}(\frac{-2}{9}) \Leftrightarrow \alpha =167^\circ 28' 16{,}3"\text{ of } \alpha = 347^\circ 28' 16{,}3"\\9-2i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 347^\circ 28' 16{,}3"\)
- \(9+10i\\ r = \sqrt{9^2+10^2} = \sqrt{181} \\ \alpha = tan^{-1}(\frac{10}{9}) \Leftrightarrow \alpha =48^\circ 0' 46"\text{ of } \alpha = 228^\circ 0' 46"\\9+10i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 48^\circ 0' 46"\)
- \(2-6i\\ r = \sqrt{2^2+(-6)^2} = \sqrt{40} \\ \alpha = tan^{-1}(\frac{-6}{2}) \Leftrightarrow \alpha =108^\circ 26' 5{,}8"\text{ of } \alpha = 288^\circ 26' 5{,}8"\\2-6i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 288^\circ 26' 5{,}8"\)
- \(7+9i\\ r = \sqrt{7^2+9^2} = \sqrt{130} \\ \alpha = tan^{-1}(\frac{9}{7}) \Leftrightarrow \alpha =52^\circ 7' 30{,}1"\text{ of } \alpha = 232^\circ 7' 30{,}1"\\7+9i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 52^\circ 7' 30{,}1"\)
- \(9-7i\\ r = \sqrt{9^2+(-7)^2} = \sqrt{130} \\ \alpha = tan^{-1}(\frac{-7}{9}) \Leftrightarrow \alpha =142^\circ 7' 30{,}1"\text{ of } \alpha = 322^\circ 7' 30{,}1"\\9-7i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 322^\circ 7' 30{,}1"\)