Bepaal modulus en argument
- \(-3-7i\)
- \(9-3i\)
- \(-8+10i\)
- \(-10-7i\)
- \(-2-10i\)
- \(8i\)
- \(3+8i\)
- \(2+8i\)
- \(-8-5i\)
- \(-2+10i\)
- \(-4+2i\)
- \(5-2i\)
Bepaal modulus en argument
Verbetersleutel
- \(-3-7i\\ r = \sqrt{(-3)^2+(-7)^2} = \sqrt{58} \\ \alpha = tan^{-1}(\frac{-7}{-3}) \Leftrightarrow \alpha =66^\circ 48' 5{,}1"\text{ of } \alpha = 246^\circ 48' 5{,}1"\\-3-7i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 246^\circ 48' 5{,}1"\)
- \(9-3i\\ r = \sqrt{9^2+(-3)^2} = \sqrt{90} \\ \alpha = tan^{-1}(\frac{-3}{9}) \Leftrightarrow \alpha =161^\circ 33' 54{,}2"\text{ of } \alpha = 341^\circ 33' 54{,}2"\\9-3i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 341^\circ 33' 54{,}2"\)
- \(-8+10i\\ r = \sqrt{(-8)^2+10^2} = \sqrt{164} \\ \alpha = tan^{-1}(\frac{10}{-8}) \Leftrightarrow \alpha =128^\circ 39' 35{,}3"\text{ of } \alpha = 308^\circ 39' 35{,}3"\\-8+10i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 128^\circ 39' 35{,}3"\)
- \(-10-7i\\ r = \sqrt{(-10)^2+(-7)^2} = \sqrt{149} \\ \alpha = tan^{-1}(\frac{-7}{-10}) \Leftrightarrow \alpha =34^\circ 59' 31{,}3"\text{ of } \alpha = 214^\circ 59' 31{,}3"\\-10-7i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 214^\circ 59' 31{,}3"\)
- \(-2-10i\\ r = \sqrt{(-2)^2+(-10)^2} = \sqrt{104} \\ \alpha = tan^{-1}(\frac{-10}{-2}) \Leftrightarrow \alpha =78^\circ 41' 24{,}2"\text{ of } \alpha = 258^\circ 41' 24{,}2"\\-2-10i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 258^\circ 41' 24{,}2"\)
- \(8i\\ \text{ Dit complex getal ligt op het positief gedeelte van de y-as. We hebben geen berekeningen nodig om r of } \alpha \text{ te berekenen.} \\\text{r = }8\\\alpha = 90 ^\circ \\\)
- \(3+8i\\ r = \sqrt{3^2+8^2} = \sqrt{73} \\ \alpha = tan^{-1}(\frac{8}{3}) \Leftrightarrow \alpha =69^\circ 26' 38{,}2"\text{ of } \alpha = 249^\circ 26' 38{,}2"\\3+8i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 69^\circ 26' 38{,}2"\)
- \(2+8i\\ r = \sqrt{2^2+8^2} = \sqrt{68} \\ \alpha = tan^{-1}(\frac{8}{2}) \Leftrightarrow \alpha =75^\circ 57' 49{,}5"\text{ of } \alpha = 255^\circ 57' 49{,}5"\\2+8i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 75^\circ 57' 49{,}5"\)
- \(-8-5i\\ r = \sqrt{(-8)^2+(-5)^2} = \sqrt{89} \\ \alpha = tan^{-1}(\frac{-5}{-8}) \Leftrightarrow \alpha =32^\circ 0' 19{,}4"\text{ of } \alpha = 212^\circ 0' 19{,}4"\\-8-5i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 212^\circ 0' 19{,}4"\)
- \(-2+10i\\ r = \sqrt{(-2)^2+10^2} = \sqrt{104} \\ \alpha = tan^{-1}(\frac{10}{-2}) \Leftrightarrow \alpha =101^\circ 18' 35{,}8"\text{ of } \alpha = 281^\circ 18' 35{,}8"\\-2+10i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 101^\circ 18' 35{,}8"\)
- \(-4+2i\\ r = \sqrt{(-4)^2+2^2} = \sqrt{20} \\ \alpha = tan^{-1}(\frac{2}{-4}) \Leftrightarrow \alpha =153^\circ 26' 5{,}8"\text{ of } \alpha = 333^\circ 26' 5{,}8"\\-4+2i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 153^\circ 26' 5{,}8"\)
- \(5-2i\\ r = \sqrt{5^2+(-2)^2} = \sqrt{29} \\ \alpha = tan^{-1}(\frac{-2}{5}) \Leftrightarrow \alpha =158^\circ 11' 54{,}9"\text{ of } \alpha = 338^\circ 11' 54{,}9"\\5-2i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 338^\circ 11' 54{,}9"\)