Bepaal modulus en argument
- \(5+4i\)
- \(-1+4i\)
- \(2-i\)
- \(-8+8i\)
- \(-6+9i\)
- \(-5-7i\)
- \(-10+6i\)
- \(-5-6i\)
- \(8-5i\)
- \(1-10i\)
- \(-1-i\)
- \(-1+i\)
Bepaal modulus en argument
Verbetersleutel
- \(5+4i\\ r = \sqrt{5^2+4^2} = \sqrt{41} \\ \alpha = tan^{-1}(\frac{4}{5}) \Leftrightarrow \alpha =38^\circ 39' 35{,}3"\text{ of } \alpha = 218^\circ 39' 35{,}3"\\5+4i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 38^\circ 39' 35{,}3"\)
- \(-1+4i\\ r = \sqrt{(-1)^2+4^2} = \sqrt{17} \\ \alpha = tan^{-1}(\frac{4}{-1}) \Leftrightarrow \alpha =104^\circ 2' 10{,}5"\text{ of } \alpha = 284^\circ 2' 10{,}5"\\-1+4i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 104^\circ 2' 10{,}5"\)
- \(2-i\\ r = \sqrt{2^2+(-1)^2} = \sqrt{5} \\ \alpha = tan^{-1}(\frac{-1}{2}) \Leftrightarrow \alpha =153^\circ 26' 5{,}8"\text{ of } \alpha = 333^\circ 26' 5{,}8"\\2-i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 333^\circ 26' 5{,}8"\)
- \(-8+8i\\ r = \sqrt{(-8)^2+8^2} = \sqrt{128} \\ \alpha = tan^{-1}(\frac{8}{-8}) \Leftrightarrow \alpha =135^\circ \text{ of } \alpha = 315^\circ \\-8+8i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 135^\circ \)
- \(-6+9i\\ r = \sqrt{(-6)^2+9^2} = \sqrt{117} \\ \alpha = tan^{-1}(\frac{9}{-6}) \Leftrightarrow \alpha =123^\circ 41' 24{,}2"\text{ of } \alpha = 303^\circ 41' 24{,}2"\\-6+9i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 123^\circ 41' 24{,}2"\)
- \(-5-7i\\ r = \sqrt{(-5)^2+(-7)^2} = \sqrt{74} \\ \alpha = tan^{-1}(\frac{-7}{-5}) \Leftrightarrow \alpha =54^\circ 27' 44{,}4"\text{ of } \alpha = 234^\circ 27' 44{,}4"\\-5-7i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 234^\circ 27' 44{,}4"\)
- \(-10+6i\\ r = \sqrt{(-10)^2+6^2} = \sqrt{136} \\ \alpha = tan^{-1}(\frac{6}{-10}) \Leftrightarrow \alpha =149^\circ 2' 10{,}5"\text{ of } \alpha = 329^\circ 2' 10{,}5"\\-10+6i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 149^\circ 2' 10{,}5"\)
- \(-5-6i\\ r = \sqrt{(-5)^2+(-6)^2} = \sqrt{61} \\ \alpha = tan^{-1}(\frac{-6}{-5}) \Leftrightarrow \alpha =50^\circ 11' 39{,}9"\text{ of } \alpha = 230^\circ 11' 39{,}9"\\-5-6i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 230^\circ 11' 39{,}9"\)
- \(8-5i\\ r = \sqrt{8^2+(-5)^2} = \sqrt{89} \\ \alpha = tan^{-1}(\frac{-5}{8}) \Leftrightarrow \alpha =147^\circ 59' 40{,}6"\text{ of } \alpha = 327^\circ 59' 40{,}6"\\8-5i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 327^\circ 59' 40{,}6"\)
- \(1-10i\\ r = \sqrt{1^2+(-10)^2} = \sqrt{101} \\ \alpha = tan^{-1}(\frac{-10}{1}) \Leftrightarrow \alpha =95^\circ 42' 38{,}1"\text{ of } \alpha = 275^\circ 42' 38{,}1"\\1-10i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 275^\circ 42' 38{,}1"\)
- \(-1-i\\ r = \sqrt{(-1)^2+(-1)^2} = \sqrt{2} \\ \alpha = tan^{-1}(\frac{-1}{-1}) \Leftrightarrow \alpha =45^\circ \text{ of } \alpha = 225^\circ \\-1-i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 225^\circ \)
- \(-1+i\\ r = \sqrt{(-1)^2+1^2} = \sqrt{2} \\ \alpha = tan^{-1}(\frac{1}{-1}) \Leftrightarrow \alpha =135^\circ \text{ of } \alpha = 315^\circ \\-1+i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 135^\circ \)