Bepaal modulus en argument

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Bepaal modulus en argument

1. \(8-3i\)
2. \(7-3i\)
3. \(5-i\)
4. \(2+10i\)
5. \(-9-3i\)
6. \(3-2i\)
7. \(1+10i\)
8. \(-2+10i\)
9. \(-3-6i\)
10. \(5+5i\)
11. \(10\)
12. \(-9-5i\)

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Bepaal modulus en argument

Verbetersleutel

1. \(8-3i\\ r = \sqrt{8^2+(-3)^2} = \sqrt{73} \\ \alpha = tan^{-1}(\frac{-3}{8}) \Leftrightarrow \alpha =159^\circ 26' 38{,}2"\text{ of } \alpha = 339^\circ 26' 38{,}2"\\8-3i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 339^\circ 26' 38{,}2"\)
2. \(7-3i\\ r = \sqrt{7^2+(-3)^2} = \sqrt{58} \\ \alpha = tan^{-1}(\frac{-3}{7}) \Leftrightarrow \alpha =156^\circ 48' 5{,}1"\text{ of } \alpha = 336^\circ 48' 5{,}1"\\7-3i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 336^\circ 48' 5{,}1"\)
3. \(5-i\\ r = \sqrt{5^2+(-1)^2} = \sqrt{26} \\ \alpha = tan^{-1}(\frac{-1}{5}) \Leftrightarrow \alpha =168^\circ 41' 24{,}2"\text{ of } \alpha = 348^\circ 41' 24{,}2"\\5-i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 348^\circ 41' 24{,}2"\)
4. \(2+10i\\ r = \sqrt{2^2+10^2} = \sqrt{104} \\ \alpha = tan^{-1}(\frac{10}{2}) \Leftrightarrow \alpha =78^\circ 41' 24{,}2"\text{ of } \alpha = 258^\circ 41' 24{,}2"\\2+10i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 78^\circ 41' 24{,}2"\)
5. \(-9-3i\\ r = \sqrt{(-9)^2+(-3)^2} = \sqrt{90} \\ \alpha = tan^{-1}(\frac{-3}{-9}) \Leftrightarrow \alpha =18^\circ 26' 5{,}8"\text{ of } \alpha = 198^\circ 26' 5{,}8"\\-9-3i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 198^\circ 26' 5{,}8"\)
6. \(3-2i\\ r = \sqrt{3^2+(-2)^2} = \sqrt{13} \\ \alpha = tan^{-1}(\frac{-2}{3}) \Leftrightarrow \alpha =146^\circ 18' 35{,}8"\text{ of } \alpha = 326^\circ 18' 35{,}8"\\3-2i\text{ ligt in kwadrant }4, \alpha \text{ ligt dus tussen }270^\circ \text{ en }360^\circ\\ \alpha = 326^\circ 18' 35{,}8"\)
7. \(1+10i\\ r = \sqrt{1^2+10^2} = \sqrt{101} \\ \alpha = tan^{-1}(\frac{10}{1}) \Leftrightarrow \alpha =84^\circ 17' 21{,}9"\text{ of } \alpha = 264^\circ 17' 21{,}9"\\1+10i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 84^\circ 17' 21{,}9"\)
8. \(-2+10i\\ r = \sqrt{(-2)^2+10^2} = \sqrt{104} \\ \alpha = tan^{-1}(\frac{10}{-2}) \Leftrightarrow \alpha =101^\circ 18' 35{,}8"\text{ of } \alpha = 281^\circ 18' 35{,}8"\\-2+10i\text{ ligt in kwadrant }2, \alpha \text{ ligt dus tussen }90^\circ \text{ en }180^\circ\\ \alpha = 101^\circ 18' 35{,}8"\)
9. \(-3-6i\\ r = \sqrt{(-3)^2+(-6)^2} = \sqrt{45} \\ \alpha = tan^{-1}(\frac{-6}{-3}) \Leftrightarrow \alpha =63^\circ 26' 5{,}8"\text{ of } \alpha = 243^\circ 26' 5{,}8"\\-3-6i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 243^\circ 26' 5{,}8"\)
10. \(5+5i\\ r = \sqrt{5^2+5^2} = \sqrt{50} \\ \alpha = tan^{-1}(\frac{5}{5}) \Leftrightarrow \alpha =45^\circ \text{ of } \alpha = 225^\circ \\5+5i\text{ ligt in kwadrant }1, \alpha \text{ ligt dus tussen }0^\circ \text{ en }90^\circ\\ \alpha = 45^\circ \)
11. \(10\\ \text{ Dit complex getal ligt op het positief gedeelte van de x-as. We hebben geen berekeningen nodig om r of } \alpha \text{ te berekenen.} \\\text{r = }10\\\alpha = 0 ^\circ \\\)
12. \(-9-5i\\ r = \sqrt{(-9)^2+(-5)^2} = \sqrt{106} \\ \alpha = tan^{-1}(\frac{-5}{-9}) \Leftrightarrow \alpha =29^\circ 3' 16{,}6"\text{ of } \alpha = 209^\circ 3' 16{,}6"\\-9-5i\text{ ligt in kwadrant }3, \alpha \text{ ligt dus tussen }180^\circ \text{ en }270^\circ\\ \alpha = 209^\circ 3' 16{,}6"\)