Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(b^2-12b+36\)
  2. \(q^2-196\)
  3. \(36p^2+12p+1\)
  4. \(4s^{6}-81x^2\)
  5. \(49q^2-64a^{10}\)
  6. \(64s^{16}-9y^2\)
  7. \(q^2-121\)
  8. \(25p^2+20p+4\)
  9. \(25x^{10}-4y^2\)
  10. \(196b^{6}+364b^3x+169x^2\)
  11. \(25x^{6}-140x^3y+196y^2\)
  12. \(64q^{6}+144q^3+81\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(b^2-12b+36=(b-6)^2\)
  2. \(q^2-196=(q+14)(q-14)\)
  3. \(36p^2+12p+1=(6p+1)^2\)
  4. \(4s^{6}-81x^2=(2s^3+9x)(2s^3-9x)\)
  5. \(49q^2-64a^{10}=(7q-8a^5)(7q+8a^5)\)
  6. \(64s^{16}-9y^2=(8s^8+3y)(8s^8-3y)\)
  7. \(q^2-121=(q-11)(q+11)\)
  8. \(25p^2+20p+4=(5p+2)^2\)
  9. \(25x^{10}-4y^2=(5x^5+2y)(5x^5-2y)\)
  10. \(196b^{6}+364b^3x+169x^2=(14b^3+13x)^2\)
  11. \(25x^{6}-140x^3y+196y^2=(5x^3-14y)^2\)
  12. \(64q^{6}+144q^3+81=(8q^3+9)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-09-24 01:24:36
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