Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(4x^{4}+4x^2+1\)
  2. \(s^2+22s+121\)
  3. \(b^2+20b+100\)
  4. \(121b^{12}-64x^2\)
  5. \(256p^2+32p+1\)
  6. \(144b^{10}+312b^5q+169q^2\)
  7. \(a^2-100\)
  8. \(81s^{6}-198s^3+121\)
  9. \(64y^{6}+208y^3+169\)
  10. \(81p^{8}-36p^4+4\)
  11. \(x^2-4x+4\)
  12. \(121y^{6}+22y^3+1\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(4x^{4}+4x^2+1=(2x^2+1)^2\)
  2. \(s^2+22s+121=(s+11)^2\)
  3. \(b^2+20b+100=(b+10)^2\)
  4. \(121b^{12}-64x^2=(11b^6+8x)(11b^6-8x)\)
  5. \(256p^2+32p+1=(16p+1)^2\)
  6. \(144b^{10}+312b^5q+169q^2=(12b^5+13q)^2\)
  7. \(a^2-100=(a-10)(a+10)\)
  8. \(81s^{6}-198s^3+121=(9s^3-11)^2\)
  9. \(64y^{6}+208y^3+169=(8y^3+13)^2\)
  10. \(81p^{8}-36p^4+4=(9p^4-2)^2\)
  11. \(x^2-4x+4=(x-2)^2\)
  12. \(121y^{6}+22y^3+1=(11y^3+1)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-01-12 18:25:12
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