Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(9a^{10}-66a^5+121\)
  2. \(144b^{10}+120b^5+25\)
  3. \(16b^{14}-9s^2\)
  4. \(4s^{10}+4s^5+1\)
  5. \(121p^{14}-144\)
  6. \(256y^2+32y+1\)
  7. \(144q^{6}-264q^3s+121s^2\)
  8. \(9a^{10}-4\)
  9. \(196x^2-225a^{10}\)
  10. \(256q^{10}+32q^5y+1y^2\)
  11. \(q^2-25\)
  12. \(b^2-16\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(9a^{10}-66a^5+121=(3a^5-11)^2\)
  2. \(144b^{10}+120b^5+25=(12b^5+5)^2\)
  3. \(16b^{14}-9s^2=(4b^7+3s)(4b^7-3s)\)
  4. \(4s^{10}+4s^5+1=(2s^5+1)^2\)
  5. \(121p^{14}-144=(11p^7+12)(11p^7-12)\)
  6. \(256y^2+32y+1=(16y+1)^2\)
  7. \(144q^{6}-264q^3s+121s^2=(12q^3-11s)^2\)
  8. \(9a^{10}-4=(3a^5+2)(3a^5-2)\)
  9. \(196x^2-225a^{10}=(14x-15a^5)(14x+15a^5)\)
  10. \(256q^{10}+32q^5y+1y^2=(16q^5+y)^2\)
  11. \(q^2-25=(q+5)(q-5)\)
  12. \(b^2-16=(b-4)(b+4)\)
Oefeningengenerator wiskundeoefeningen.be 2025-12-02 15:15:29
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