Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(9b^{8}-66b^4p+121p^2\)
  2. \(49q^{4}-140q^2y+100y^2\)
  3. \(q^2-1\)
  4. \(169y^{6}-156y^3+36\)
  5. \(121p^2-176p+64\)
  6. \(256x^{10}-225\)
  7. \(121a^2+330a+225\)
  8. \(256a^{4}+352a^2x+121x^2\)
  9. \(p^2-2p+1\)
  10. \(4p^{12}-81\)
  11. \(s^2+10s+25\)
  12. \(256x^2-9\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(9b^{8}-66b^4p+121p^2=(3b^4-11p)^2\)
  2. \(49q^{4}-140q^2y+100y^2=(7q^2-10y)^2\)
  3. \(q^2-1=(q+1)(q-1)\)
  4. \(169y^{6}-156y^3+36=(13y^3-6)^2\)
  5. \(121p^2-176p+64=(11p-8)^2\)
  6. \(256x^{10}-225=(16x^5+15)(16x^5-15)\)
  7. \(121a^2+330a+225=(11a+15)^2\)
  8. \(256a^{4}+352a^2x+121x^2=(16a^2+11x)^2\)
  9. \(p^2-2p+1=(p-1)^2\)
  10. \(4p^{12}-81=(2p^6+9)(2p^6-9)\)
  11. \(s^2+10s+25=(s+5)^2\)
  12. \(256x^2-9=(16x+3)(16x-3)\)
Oefeningengenerator wiskundeoefeningen.be 2026-04-16 04:58:25
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