Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(a^2-28a+196\)
  2. \(121-81a^{6}\)
  3. \(4a^{14}-169q^2\)
  4. \(64y^2-80y+25\)
  5. \(256p^{10}+32p^5+1\)
  6. \(x^2-36\)
  7. \(9s^2-30s+25\)
  8. \(s^2-10s+25\)
  9. \(64q^{8}-240q^4s+225s^2\)
  10. \(25x^{4}-40x^2+16\)
  11. \(1-256s^{14}\)
  12. \(64q^{6}-112q^3x+49x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(a^2-28a+196=(a-14)^2\)
  2. \(121-81a^{6}=(11-9a^3)(11+9a^3)\)
  3. \(4a^{14}-169q^2=(2a^7+13q)(2a^7-13q)\)
  4. \(64y^2-80y+25=(8y-5)^2\)
  5. \(256p^{10}+32p^5+1=(16p^5+1)^2\)
  6. \(x^2-36=(x-6)(x+6)\)
  7. \(9s^2-30s+25=(3s-5)^2\)
  8. \(s^2-10s+25=(s-5)^2\)
  9. \(64q^{8}-240q^4s+225s^2=(8q^4-15s)^2\)
  10. \(25x^{4}-40x^2+16=(5x^2-4)^2\)
  11. \(1-256s^{14}=(1-16s^7)(1+16s^7)\)
  12. \(64q^{6}-112q^3x+49x^2=(8q^3-7x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-03 17:36:24
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