Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(121s^{8}+22s^4+1\)
  2. \(121a^{6}+198a^3y+81y^2\)
  3. \(169s^{6}-1\)
  4. \(256a^{12}-81\)
  5. \(169p^{10}-196x^2\)
  6. \(-144x^2+1\)
  7. \(s^2-49\)
  8. \(s^2-30s+225\)
  9. \(p^2-196\)
  10. \(196y^2-121\)
  11. \(49q^{4}+14q^2s+1s^2\)
  12. \(196a^{4}+364a^2+169\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(121s^{8}+22s^4+1=(11s^4+1)^2\)
  2. \(121a^{6}+198a^3y+81y^2=(11a^3+9y)^2\)
  3. \(169s^{6}-1=(13s^3+1)(13s^3-1)\)
  4. \(256a^{12}-81=(16a^6+9)(16a^6-9)\)
  5. \(169p^{10}-196x^2=(13p^5+14x)(13p^5-14x)\)
  6. \(-144x^2+1=(1-12x)(1+12x)\)
  7. \(s^2-49=(s+7)(s-7)\)
  8. \(s^2-30s+225=(s-15)^2\)
  9. \(p^2-196=(p+14)(p-14)\)
  10. \(196y^2-121=(14y+11)(14y-11)\)
  11. \(49q^{4}+14q^2s+1s^2=(7q^2+s)^2\)
  12. \(196a^{4}+364a^2+169=(14a^2+13)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-04-20 17:44:37
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