Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(x^2+14x+49\)
  2. \(256q^{6}+224q^3s+49s^2\)
  3. \(25-36b^{8}\)
  4. \(-121q^2+100\)
  5. \(169-4q^{12}\)
  6. \(b^2-1\)
  7. \(256b^{10}+32b^5+1\)
  8. \(49b^{6}-225\)
  9. \(225y^2-196b^{4}\)
  10. \(225q^2-196\)
  11. \(81s^{6}+72s^3+16\)
  12. \(256p^{10}-160p^5x+25x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(x^2+14x+49=(x+7)^2\)
  2. \(256q^{6}+224q^3s+49s^2=(16q^3+7s)^2\)
  3. \(25-36b^{8}=(5-6b^4)(5+6b^4)\)
  4. \(-121q^2+100=(10-11q)(10+11q)\)
  5. \(169-4q^{12}=(13-2q^6)(13+2q^6)\)
  6. \(b^2-1=(b-1)(b+1)\)
  7. \(256b^{10}+32b^5+1=(16b^5+1)^2\)
  8. \(49b^{6}-225=(7b^3+15)(7b^3-15)\)
  9. \(225y^2-196b^{4}=(15y-14b^2)(15y+14b^2)\)
  10. \(225q^2-196=(15q+14)(15q-14)\)
  11. \(81s^{6}+72s^3+16=(9s^3+4)^2\)
  12. \(256p^{10}-160p^5x+25x^2=(16p^5-5x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-20 08:59:45
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