Ontbinden in factoren (1)

Hoofdmenu Eentje per keer 

Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(b^2+28b+196\)
  2. \(100a^{6}-180a^3+81\)
  3. \(4x^{8}+4x^4+1\)
  4. \(196x^{10}-308x^5+121\)
  5. \(144s^{4}-1\)
  6. \(-196p^2+169\)
  7. \(36a^2+84a+49\)
  8. \(9y^{4}-84y^2+196\)
  9. \(100q^{4}+140q^2+49\)
  10. \(81b^{10}-72b^5+16\)
  11. \(121b^{8}+22b^4p+1p^2\)
  12. \(225p^2+210p+49\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(b^2+28b+196=(b+14)^2\)
  2. \(100a^{6}-180a^3+81=(10a^3-9)^2\)
  3. \(4x^{8}+4x^4+1=(2x^4+1)^2\)
  4. \(196x^{10}-308x^5+121=(14x^5-11)^2\)
  5. \(144s^{4}-1=(12s^2+1)(12s^2-1)\)
  6. \(-196p^2+169=(13-14p)(13+14p)\)
  7. \(36a^2+84a+49=(6a+7)^2\)
  8. \(9y^{4}-84y^2+196=(3y^2-14)^2\)
  9. \(100q^{4}+140q^2+49=(10q^2+7)^2\)
  10. \(81b^{10}-72b^5+16=(9b^5-4)^2\)
  11. \(121b^{8}+22b^4p+1p^2=(11b^4+p)^2\)
  12. \(225p^2+210p+49=(15p+7)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-31 04:32:40
Een site van Busleyden Atheneum Mechelen