Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(64a^{6}-225\)
  2. \(-225b^2+49\)
  3. \(25s^{10}-90s^5+81\)
  4. \(121a^{4}-9b^2\)
  5. \(25b^{10}+90b^5+81\)
  6. \(225q^{10}-169\)
  7. \(-25y^2+81\)
  8. \(196s^{8}-9\)
  9. \(-16q^2+49\)
  10. \(-225b^2+64\)
  11. \(25p^{8}+110p^4+121\)
  12. \(-16a^2+25\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(64a^{6}-225=(8a^3+15)(8a^3-15)\)
  2. \(-225b^2+49=(7-15b)(7+15b)\)
  3. \(25s^{10}-90s^5+81=(5s^5-9)^2\)
  4. \(121a^{4}-9b^2=(11a^2+3b)(11a^2-3b)\)
  5. \(25b^{10}+90b^5+81=(5b^5+9)^2\)
  6. \(225q^{10}-169=(15q^5+13)(15q^5-13)\)
  7. \(-25y^2+81=(9-5y)(9+5y)\)
  8. \(196s^{8}-9=(14s^4+3)(14s^4-3)\)
  9. \(-16q^2+49=(7-4q)(7+4q)\)
  10. \(-225b^2+64=(8-15b)(8+15b)\)
  11. \(25p^{8}+110p^4+121=(5p^4+11)^2\)
  12. \(-16a^2+25=(5-4a)(5+4a)\)
Oefeningengenerator wiskundeoefeningen.be 2026-05-29 20:55:12
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