Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(121x^{8}-176x^4+64\)
  2. \(25a^{10}-90a^5s+81s^2\)
  3. \(169-121s^{6}\)
  4. \(b^2+30b+225\)
  5. \(81p^2-196b^{4}\)
  6. \(b^2-169\)
  7. \(64p^{8}+144p^4+81\)
  8. \(q^2-121\)
  9. \(1-169q^{6}\)
  10. \(49q^{6}+112q^3y+64y^2\)
  11. \(169y^2+130y+25\)
  12. \(9p^2-256a^{16}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(121x^{8}-176x^4+64=(11x^4-8)^2\)
  2. \(25a^{10}-90a^5s+81s^2=(5a^5-9s)^2\)
  3. \(169-121s^{6}=(13-11s^3)(13+11s^3)\)
  4. \(b^2+30b+225=(b+15)^2\)
  5. \(81p^2-196b^{4}=(9p-14b^2)(9p+14b^2)\)
  6. \(b^2-169=(b-13)(b+13)\)
  7. \(64p^{8}+144p^4+81=(8p^4+9)^2\)
  8. \(q^2-121=(q-11)(q+11)\)
  9. \(1-169q^{6}=(1-13q^3)(1+13q^3)\)
  10. \(49q^{6}+112q^3y+64y^2=(7q^3+8y)^2\)
  11. \(169y^2+130y+25=(13y+5)^2\)
  12. \(9p^2-256a^{16}=(3p-16a^8)(3p+16a^8)\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-26 02:22:29
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