Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(4p^{8}+28p^4q+49q^2\)
  2. \(-100y^2+1\)
  3. \(100a^{8}+140a^4p+49p^2\)
  4. \(-100s^2+81\)
  5. \(16a^2-88a+121\)
  6. \(256p^{6}+352p^3+121\)
  7. \(225s^2-121a^{8}\)
  8. \(225a^{6}-64q^2\)
  9. \(36q^2+12q+1\)
  10. \(144p^{6}+168p^3+49\)
  11. \(9p^{4}+30p^2q+25q^2\)
  12. \(16y^2+120y+225\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(4p^{8}+28p^4q+49q^2=(2p^4+7q)^2\)
  2. \(-100y^2+1=(1-10y)(1+10y)\)
  3. \(100a^{8}+140a^4p+49p^2=(10a^4+7p)^2\)
  4. \(-100s^2+81=(9-10s)(9+10s)\)
  5. \(16a^2-88a+121=(4a-11)^2\)
  6. \(256p^{6}+352p^3+121=(16p^3+11)^2\)
  7. \(225s^2-121a^{8}=(15s-11a^4)(15s+11a^4)\)
  8. \(225a^{6}-64q^2=(15a^3+8q)(15a^3-8q)\)
  9. \(36q^2+12q+1=(6q+1)^2\)
  10. \(144p^{6}+168p^3+49=(12p^3+7)^2\)
  11. \(9p^{4}+30p^2q+25q^2=(3p^2+5q)^2\)
  12. \(16y^2+120y+225=(4y+15)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-11-15 19:20:05
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