Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(100p^{8}-169x^2\)
  2. \(36y^2-25s^{14}\)
  3. \(256b^{10}-9\)
  4. \(25b^2-70b+49\)
  5. \(121a^{10}-176a^5+64\)
  6. \(y^2-28y+196\)
  7. \(p^2-25\)
  8. \(81b^{16}-1\)
  9. \(169b^{8}-25\)
  10. \(121s^{10}-81x^2\)
  11. \(a^2-10a+25\)
  12. \(9b^{8}-48b^4x+64x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(100p^{8}-169x^2=(10p^4+13x)(10p^4-13x)\)
  2. \(36y^2-25s^{14}=(6y-5s^7)(6y+5s^7)\)
  3. \(256b^{10}-9=(16b^5+3)(16b^5-3)\)
  4. \(25b^2-70b+49=(5b-7)^2\)
  5. \(121a^{10}-176a^5+64=(11a^5-8)^2\)
  6. \(y^2-28y+196=(y-14)^2\)
  7. \(p^2-25=(p-5)(p+5)\)
  8. \(81b^{16}-1=(9b^8+1)(9b^8-1)\)
  9. \(169b^{8}-25=(13b^4+5)(13b^4-5)\)
  10. \(121s^{10}-81x^2=(11s^5+9x)(11s^5-9x)\)
  11. \(a^2-10a+25=(a-5)^2\)
  12. \(9b^{8}-48b^4x+64x^2=(3b^4-8x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2025-12-27 07:23:02
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