Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(144b^{14}-25\)
  2. \(y^2+24y+144\)
  3. \(16p^{12}-121\)
  4. \(169p^{4}+78p^2x+9x^2\)
  5. \(25x^2-121q^{6}\)
  6. \(121-36a^{4}\)
  7. \(196p^{8}+28p^4+1\)
  8. \(25b^2+60b+36\)
  9. \(q^2-196\)
  10. \(121y^{16}-1\)
  11. \(-196y^2+9\)
  12. \(225a^{4}+30a^2+1\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(144b^{14}-25=(12b^7+5)(12b^7-5)\)
  2. \(y^2+24y+144=(y+12)^2\)
  3. \(16p^{12}-121=(4p^6+11)(4p^6-11)\)
  4. \(169p^{4}+78p^2x+9x^2=(13p^2+3x)^2\)
  5. \(25x^2-121q^{6}=(5x-11q^3)(5x+11q^3)\)
  6. \(121-36a^{4}=(11-6a^2)(11+6a^2)\)
  7. \(196p^{8}+28p^4+1=(14p^4+1)^2\)
  8. \(25b^2+60b+36=(5b+6)^2\)
  9. \(q^2-196=(q-14)(q+14)\)
  10. \(121y^{16}-1=(11y^8+1)(11y^8-1)\)
  11. \(-196y^2+9=(3-14y)(3+14y)\)
  12. \(225a^{4}+30a^2+1=(15a^2+1)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-09 06:27:22
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