Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(169p^2+234p+81\)
  2. \(169-225y^{14}\)
  3. \(81x^2-169q^{4}\)
  4. \(225-64y^{14}\)
  5. \(s^2-36\)
  6. \(-169y^2+49\)
  7. \(q^2-9\)
  8. \(25-144x^{12}\)
  9. \(q^2-26q+169\)
  10. \(196a^{16}-9b^2\)
  11. \(16s^{10}-24s^5y+9y^2\)
  12. \(144a^{4}+120a^2+25\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(169p^2+234p+81=(13p+9)^2\)
  2. \(169-225y^{14}=(13-15y^7)(13+15y^7)\)
  3. \(81x^2-169q^{4}=(9x-13q^2)(9x+13q^2)\)
  4. \(225-64y^{14}=(15-8y^7)(15+8y^7)\)
  5. \(s^2-36=(s-6)(s+6)\)
  6. \(-169y^2+49=(7-13y)(7+13y)\)
  7. \(q^2-9=(q+3)(q-3)\)
  8. \(25-144x^{12}=(5-12x^6)(5+12x^6)\)
  9. \(q^2-26q+169=(q-13)^2\)
  10. \(196a^{16}-9b^2=(14a^8+3b)(14a^8-3b)\)
  11. \(16s^{10}-24s^5y+9y^2=(4s^5-3y)^2\)
  12. \(144a^{4}+120a^2+25=(12a^2+5)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-11-06 15:21:17
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