Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(256q^{4}-288q^2+81\)
  2. \(144b^2+24b+1\)
  3. \(x^2-14x+49\)
  4. \(64q^{10}+112q^5x+49x^2\)
  5. \(p^2-196\)
  6. \(225s^2+330s+121\)
  7. \(-4q^2+81\)
  8. \(196a^{16}-169s^2\)
  9. \(121-81p^{12}\)
  10. \(16q^2-121\)
  11. \(196a^{8}+252a^4y+81y^2\)
  12. \(p^2+22p+121\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(256q^{4}-288q^2+81=(16q^2-9)^2\)
  2. \(144b^2+24b+1=(12b+1)^2\)
  3. \(x^2-14x+49=(x-7)^2\)
  4. \(64q^{10}+112q^5x+49x^2=(8q^5+7x)^2\)
  5. \(p^2-196=(p-14)(p+14)\)
  6. \(225s^2+330s+121=(15s+11)^2\)
  7. \(-4q^2+81=(9-2q)(9+2q)\)
  8. \(196a^{16}-169s^2=(14a^8+13s)(14a^8-13s)\)
  9. \(121-81p^{12}=(11-9p^6)(11+9p^6)\)
  10. \(16q^2-121=(4q+11)(4q-11)\)
  11. \(196a^{8}+252a^4y+81y^2=(14a^4+9y)^2\)
  12. \(p^2+22p+121=(p+11)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-02 20:22:39
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