Ontbinden in factoren (1)

Hoofdmenu Eentje per keer 

Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(4p^2-81\)
  2. \(64p^{6}-25\)
  3. \(y^2-2y+1\)
  4. \(81y^2-100\)
  5. \(9b^{10}+60b^5s+100s^2\)
  6. \(4a^2+36a+81\)
  7. \(4s^2-169q^{8}\)
  8. \(121b^2-64\)
  9. \(16q^2-p^{10}\)
  10. \(225x^{8}-420x^4+196\)
  11. \(144a^{6}-25b^2\)
  12. \(25q^{10}-140q^5+196\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(4p^2-81=(2p+9)(2p-9)\)
  2. \(64p^{6}-25=(8p^3+5)(8p^3-5)\)
  3. \(y^2-2y+1=(y-1)^2\)
  4. \(81y^2-100=(9y+10)(9y-10)\)
  5. \(9b^{10}+60b^5s+100s^2=(3b^5+10s)^2\)
  6. \(4a^2+36a+81=(2a+9)^2\)
  7. \(4s^2-169q^{8}=(2s-13q^4)(2s+13q^4)\)
  8. \(121b^2-64=(11b+8)(11b-8)\)
  9. \(16q^2-p^{10}=(4q-p^5)(4q+p^5)\)
  10. \(225x^{8}-420x^4+196=(15x^4-14)^2\)
  11. \(144a^{6}-25b^2=(12a^3+5b)(12a^3-5b)\)
  12. \(25q^{10}-140q^5+196=(5q^5-14)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-01 11:42:54
Een site van Busleyden Atheneum Mechelen