Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(1-225p^{12}\)
  2. \(256a^{8}-160a^4+25\)
  3. \(-49s^2+25\)
  4. \(64p^{10}-169\)
  5. \(25q^2-144p^{8}\)
  6. \(225x^{6}-330x^3+121\)
  7. \(121-4b^{4}\)
  8. \(36s^2-1\)
  9. \(-100p^2+49\)
  10. \(144b^2-a^{10}\)
  11. \(169a^{12}-81b^2\)
  12. \(49a^{8}-121x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(1-225p^{12}=(1-15p^6)(1+15p^6)\)
  2. \(256a^{8}-160a^4+25=(16a^4-5)^2\)
  3. \(-49s^2+25=(5-7s)(5+7s)\)
  4. \(64p^{10}-169=(8p^5+13)(8p^5-13)\)
  5. \(25q^2-144p^{8}=(5q-12p^4)(5q+12p^4)\)
  6. \(225x^{6}-330x^3+121=(15x^3-11)^2\)
  7. \(121-4b^{4}=(11-2b^2)(11+2b^2)\)
  8. \(36s^2-1=(6s+1)(6s-1)\)
  9. \(-100p^2+49=(7-10p)(7+10p)\)
  10. \(144b^2-a^{10}=(12b-a^5)(12b+a^5)\)
  11. \(169a^{12}-81b^2=(13a^6+9b)(13a^6-9b)\)
  12. \(49a^{8}-121x^2=(7a^4+11x)(7a^4-11x)\)
Oefeningengenerator wiskundeoefeningen.be 2026-04-06 13:54:32
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