Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(x^2+2x+1\)
  2. \(121y^2-225q^{12}\)
  3. \(b^2-196\)
  4. \(196q^{10}-252q^5s+81s^2\)
  5. \(81y^2-100p^{10}\)
  6. \(4b^{6}+44b^3+121\)
  7. \(y^2+24y+144\)
  8. \(4a^{4}+4a^2+1\)
  9. \(b^2-16b+64\)
  10. \(36q^2-121\)
  11. \(25b^{8}-90b^4+81\)
  12. \(25p^{8}-140p^4x+196x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(x^2+2x+1=(x+1)^2\)
  2. \(121y^2-225q^{12}=(11y-15q^6)(11y+15q^6)\)
  3. \(b^2-196=(b-14)(b+14)\)
  4. \(196q^{10}-252q^5s+81s^2=(14q^5-9s)^2\)
  5. \(81y^2-100p^{10}=(9y-10p^5)(9y+10p^5)\)
  6. \(4b^{6}+44b^3+121=(2b^3+11)^2\)
  7. \(y^2+24y+144=(y+12)^2\)
  8. \(4a^{4}+4a^2+1=(2a^2+1)^2\)
  9. \(b^2-16b+64=(b-8)^2\)
  10. \(36q^2-121=(6q+11)(6q-11)\)
  11. \(25b^{8}-90b^4+81=(5b^4-9)^2\)
  12. \(25p^{8}-140p^4x+196x^2=(5p^4-14x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-03-23 08:18:12
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