Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(9b^{6}-84b^3q+196q^2\)
  2. \(64p^{6}-112p^3q+49q^2\)
  3. \(x^2-121\)
  4. \(256a^2-288a+81\)
  5. \(1-100p^{14}\)
  6. \(81b^2-234b+169\)
  7. \(b^{6}-9p^2\)
  8. \(64y^2+144y+81\)
  9. \(q^2-26q+169\)
  10. \(9s^{6}-121x^2\)
  11. \(256p^2+32p+1\)
  12. \(9b^{8}+6b^4+1\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(9b^{6}-84b^3q+196q^2=(3b^3-14q)^2\)
  2. \(64p^{6}-112p^3q+49q^2=(8p^3-7q)^2\)
  3. \(x^2-121=(x+11)(x-11)\)
  4. \(256a^2-288a+81=(16a-9)^2\)
  5. \(1-100p^{14}=(1-10p^7)(1+10p^7)\)
  6. \(81b^2-234b+169=(9b-13)^2\)
  7. \(b^{6}-9p^2=(b^3+3p)(b^3-3p)\)
  8. \(64y^2+144y+81=(8y+9)^2\)
  9. \(q^2-26q+169=(q-13)^2\)
  10. \(9s^{6}-121x^2=(3s^3+11x)(3s^3-11x)\)
  11. \(256p^2+32p+1=(16p+1)^2\)
  12. \(9b^{8}+6b^4+1=(3b^4+1)^2\)
Oefeningengenerator wiskundeoefeningen.be 2025-12-02 23:07:18
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