Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(16s^2-225b^{8}\)
  2. \(100a^2+140a+49\)
  3. \(225-64y^{14}\)
  4. \(-81q^2+1\)
  5. \(144a^2-1\)
  6. \(25a^2+10a+1\)
  7. \(25p^2-144b^{4}\)
  8. \(64q^{4}+176q^2s+121s^2\)
  9. \(4b^{8}-81y^2\)
  10. \(16-81p^{16}\)
  11. \(196p^{10}+28p^5+1\)
  12. \(16p^{14}-9q^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(16s^2-225b^{8}=(4s-15b^4)(4s+15b^4)\)
  2. \(100a^2+140a+49=(10a+7)^2\)
  3. \(225-64y^{14}=(15-8y^7)(15+8y^7)\)
  4. \(-81q^2+1=(1-9q)(1+9q)\)
  5. \(144a^2-1=(12a+1)(12a-1)\)
  6. \(25a^2+10a+1=(5a+1)^2\)
  7. \(25p^2-144b^{4}=(5p-12b^2)(5p+12b^2)\)
  8. \(64q^{4}+176q^2s+121s^2=(8q^2+11s)^2\)
  9. \(4b^{8}-81y^2=(2b^4+9y)(2b^4-9y)\)
  10. \(16-81p^{16}=(4-9p^8)(4+9p^8)\)
  11. \(196p^{10}+28p^5+1=(14p^5+1)^2\)
  12. \(16p^{14}-9q^2=(4p^7+3q)(4p^7-3q)\)
Oefeningengenerator wiskundeoefeningen.be 2026-03-12 22:53:13
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