Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(225b^{10}-210b^5q+49q^2\)
  2. \(b^2+18b+81\)
  3. \(64s^{16}-225y^2\)
  4. \(169s^2+78s+9\)
  5. \(81s^2-16\)
  6. \(256a^{10}-288a^5+81\)
  7. \(b^2-49\)
  8. \(a^2-22a+121\)
  9. \(16y^2-88y+121\)
  10. \(49-25s^{14}\)
  11. \(225p^{8}-64s^2\)
  12. \(121a^{6}-110a^3+25\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(225b^{10}-210b^5q+49q^2=(15b^5-7q)^2\)
  2. \(b^2+18b+81=(b+9)^2\)
  3. \(64s^{16}-225y^2=(8s^8+15y)(8s^8-15y)\)
  4. \(169s^2+78s+9=(13s+3)^2\)
  5. \(81s^2-16=(9s+4)(9s-4)\)
  6. \(256a^{10}-288a^5+81=(16a^5-9)^2\)
  7. \(b^2-49=(b+7)(b-7)\)
  8. \(a^2-22a+121=(a-11)^2\)
  9. \(16y^2-88y+121=(4y-11)^2\)
  10. \(49-25s^{14}=(7-5s^7)(7+5s^7)\)
  11. \(225p^{8}-64s^2=(15p^4+8s)(15p^4-8s)\)
  12. \(121a^{6}-110a^3+25=(11a^3-5)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-03-10 19:16:20
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