Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(81a^{4}-234a^2b+169b^2\)
  2. \(4a^{10}-9s^2\)
  3. \(9p^{4}+84p^2+196\)
  4. \(-81y^2+64\)
  5. \(196b^2+140b+25\)
  6. \(p^2-8p+16\)
  7. \(y^2-2y+1\)
  8. \(64p^2+208p+169\)
  9. \(-16a^2+81\)
  10. \(9b^{6}+24b^3+16\)
  11. \(b^2-26b+169\)
  12. \(4b^{4}+4b^2s+1s^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(81a^{4}-234a^2b+169b^2=(9a^2-13b)^2\)
  2. \(4a^{10}-9s^2=(2a^5+3s)(2a^5-3s)\)
  3. \(9p^{4}+84p^2+196=(3p^2+14)^2\)
  4. \(-81y^2+64=(8-9y)(8+9y)\)
  5. \(196b^2+140b+25=(14b+5)^2\)
  6. \(p^2-8p+16=(p-4)^2\)
  7. \(y^2-2y+1=(y-1)^2\)
  8. \(64p^2+208p+169=(8p+13)^2\)
  9. \(-16a^2+81=(9-4a)(9+4a)\)
  10. \(9b^{6}+24b^3+16=(3b^3+4)^2\)
  11. \(b^2-26b+169=(b-13)^2\)
  12. \(4b^{4}+4b^2s+1s^2=(2b^2+s)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-08 11:22:02
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