Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(121p^2-4b^{4}\)
  2. \(16p^{6}-9y^2\)
  3. \(256x^{4}-1\)
  4. \(121x^{10}-154x^5+49\)
  5. \(49b^{4}+56b^2+16\)
  6. \(225a^{10}-16y^2\)
  7. \(49s^2+168s+144\)
  8. \(-256y^2+121\)
  9. \(256q^{10}+32q^5x+1x^2\)
  10. \(121q^2+22q+1\)
  11. \(256x^{8}-121\)
  12. \(100p^{4}-49q^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(121p^2-4b^{4}=(11p-2b^2)(11p+2b^2)\)
  2. \(16p^{6}-9y^2=(4p^3+3y)(4p^3-3y)\)
  3. \(256x^{4}-1=(16x^2+1)(16x^2-1)\)
  4. \(121x^{10}-154x^5+49=(11x^5-7)^2\)
  5. \(49b^{4}+56b^2+16=(7b^2+4)^2\)
  6. \(225a^{10}-16y^2=(15a^5+4y)(15a^5-4y)\)
  7. \(49s^2+168s+144=(7s+12)^2\)
  8. \(-256y^2+121=(11-16y)(11+16y)\)
  9. \(256q^{10}+32q^5x+1x^2=(16q^5+x)^2\)
  10. \(121q^2+22q+1=(11q+1)^2\)
  11. \(256x^{8}-121=(16x^4+11)(16x^4-11)\)
  12. \(100p^{4}-49q^2=(10p^2+7q)(10p^2-7q)\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-06 07:38:20
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