Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(256y^2-121\)
  2. \(256b^{8}+32b^4p+1p^2\)
  3. \(144x^2-25\)
  4. \(25q^{4}-40q^2+16\)
  5. \(256x^2+32x+1\)
  6. \(p^2-24p+144\)
  7. \(y^2+6y+9\)
  8. \(169q^2-16a^{8}\)
  9. \(196p^2-169a^{10}\)
  10. \(p^2+30p+225\)
  11. \(144b^{10}+168b^5y+49y^2\)
  12. \(25p^{6}-4x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(256y^2-121=(16y+11)(16y-11)\)
  2. \(256b^{8}+32b^4p+1p^2=(16b^4+p)^2\)
  3. \(144x^2-25=(12x+5)(12x-5)\)
  4. \(25q^{4}-40q^2+16=(5q^2-4)^2\)
  5. \(256x^2+32x+1=(16x+1)^2\)
  6. \(p^2-24p+144=(p-12)^2\)
  7. \(y^2+6y+9=(y+3)^2\)
  8. \(169q^2-16a^{8}=(13q-4a^4)(13q+4a^4)\)
  9. \(196p^2-169a^{10}=(14p-13a^5)(14p+13a^5)\)
  10. \(p^2+30p+225=(p+15)^2\)
  11. \(144b^{10}+168b^5y+49y^2=(12b^5+7y)^2\)
  12. \(25p^{6}-4x^2=(5p^3+2x)(5p^3-2x)\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-06 17:39:22
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