Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(81y^2+234y+169\)
  2. \(q^2-121\)
  3. \(-16a^2+121\)
  4. \(-256s^2+49\)
  5. \(64b^{16}-9x^2\)
  6. \(256b^{10}-480b^5+225\)
  7. \(169-81q^{8}\)
  8. \(169x^2-9\)
  9. \(196b^{8}+28b^4y+1y^2\)
  10. \(9b^{16}-25s^2\)
  11. \(49b^{8}-224b^4x+256x^2\)
  12. \(25b^{8}+110b^4p+121p^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(81y^2+234y+169=(9y+13)^2\)
  2. \(q^2-121=(q+11)(q-11)\)
  3. \(-16a^2+121=(11-4a)(11+4a)\)
  4. \(-256s^2+49=(7-16s)(7+16s)\)
  5. \(64b^{16}-9x^2=(8b^8+3x)(8b^8-3x)\)
  6. \(256b^{10}-480b^5+225=(16b^5-15)^2\)
  7. \(169-81q^{8}=(13-9q^4)(13+9q^4)\)
  8. \(169x^2-9=(13x+3)(13x-3)\)
  9. \(196b^{8}+28b^4y+1y^2=(14b^4+y)^2\)
  10. \(9b^{16}-25s^2=(3b^8+5s)(3b^8-5s)\)
  11. \(49b^{8}-224b^4x+256x^2=(7b^4-16x)^2\)
  12. \(25b^{8}+110b^4p+121p^2=(5b^4+11p)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-29 18:13:29
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