Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(s^2-81\)
  2. \(16p^2+72p+81\)
  3. \(121p^2-169\)
  4. \(9q^2-64a^{4}\)
  5. \(144b^{4}+168b^2p+49p^2\)
  6. \(121a^{10}+22a^5q+1q^2\)
  7. \(81p^{4}-234p^2+169\)
  8. \(s^2-8s+16\)
  9. \(64y^{14}-1\)
  10. \(196a^{6}-169q^2\)
  11. \(100p^{4}+140p^2x+49x^2\)
  12. \(256q^2-81\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(s^2-81=(s+9)(s-9)\)
  2. \(16p^2+72p+81=(4p+9)^2\)
  3. \(121p^2-169=(11p+13)(11p-13)\)
  4. \(9q^2-64a^{4}=(3q-8a^2)(3q+8a^2)\)
  5. \(144b^{4}+168b^2p+49p^2=(12b^2+7p)^2\)
  6. \(121a^{10}+22a^5q+1q^2=(11a^5+q)^2\)
  7. \(81p^{4}-234p^2+169=(9p^2-13)^2\)
  8. \(s^2-8s+16=(s-4)^2\)
  9. \(64y^{14}-1=(8y^7+1)(8y^7-1)\)
  10. \(196a^{6}-169q^2=(14a^3+13q)(14a^3-13q)\)
  11. \(100p^{4}+140p^2x+49x^2=(10p^2+7x)^2\)
  12. \(256q^2-81=(16q+9)(16q-9)\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-07 12:35:36
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