Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(9x^2-4s^{8}\)
  2. \(s^2-225\)
  3. \(64b^{16}-9y^2\)
  4. \(25p^2-256a^{8}\)
  5. \(s^2-16\)
  6. \(25p^{10}-169\)
  7. \(25p^2-36b^{4}\)
  8. \(144y^{10}-264y^5+121\)
  9. \(49-100p^{14}\)
  10. \(4x^2-b^{4}\)
  11. \(144a^{12}-1\)
  12. \(4a^{8}+36a^4x+81x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(9x^2-4s^{8}=(3x-2s^4)(3x+2s^4)\)
  2. \(s^2-225=(s-15)(s+15)\)
  3. \(64b^{16}-9y^2=(8b^8+3y)(8b^8-3y)\)
  4. \(25p^2-256a^{8}=(5p-16a^4)(5p+16a^4)\)
  5. \(s^2-16=(s-4)(s+4)\)
  6. \(25p^{10}-169=(5p^5+13)(5p^5-13)\)
  7. \(25p^2-36b^{4}=(5p-6b^2)(5p+6b^2)\)
  8. \(144y^{10}-264y^5+121=(12y^5-11)^2\)
  9. \(49-100p^{14}=(7-10p^7)(7+10p^7)\)
  10. \(4x^2-b^{4}=(2x-b^2)(2x+b^2)\)
  11. \(144a^{12}-1=(12a^6+1)(12a^6-1)\)
  12. \(4a^{8}+36a^4x+81x^2=(2a^4+9x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-13 11:50:15
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