Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(9y^2-64s^{12}\)
  2. \(81q^{6}-234q^3y+169y^2\)
  3. \(49x^2-100p^{8}\)
  4. \(196p^{10}+28p^5+1\)
  5. \(121p^2+44p+4\)
  6. \(169x^2-225\)
  7. \(4s^2+12s+9\)
  8. \(4b^2+4b+1\)
  9. \(169p^{10}+312p^5y+144y^2\)
  10. \(81-100b^{4}\)
  11. \(169-25p^{14}\)
  12. \(a^2-100\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(9y^2-64s^{12}=(3y-8s^6)(3y+8s^6)\)
  2. \(81q^{6}-234q^3y+169y^2=(9q^3-13y)^2\)
  3. \(49x^2-100p^{8}=(7x-10p^4)(7x+10p^4)\)
  4. \(196p^{10}+28p^5+1=(14p^5+1)^2\)
  5. \(121p^2+44p+4=(11p+2)^2\)
  6. \(169x^2-225=(13x+15)(13x-15)\)
  7. \(4s^2+12s+9=(2s+3)^2\)
  8. \(4b^2+4b+1=(2b+1)^2\)
  9. \(169p^{10}+312p^5y+144y^2=(13p^5+12y)^2\)
  10. \(81-100b^{4}=(9-10b^2)(9+10b^2)\)
  11. \(169-25p^{14}=(13-5p^7)(13+5p^7)\)
  12. \(a^2-100=(a+10)(a-10)\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-08 16:42:10
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