Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(256a^{6}+224a^3x+49x^2\)
  2. \(49b^{6}-16s^2\)
  3. \(81p^{8}+198p^4s+121s^2\)
  4. \(169-225b^{4}\)
  5. \(s^2-81\)
  6. \(49x^2+182x+169\)
  7. \(64b^{8}+48b^4q+9q^2\)
  8. \(9b^{10}-66b^5+121\)
  9. \(36q^{8}+12q^4y+1y^2\)
  10. \(16a^{10}-49b^2\)
  11. \(a^2-36\)
  12. \(100q^2-49p^{6}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(256a^{6}+224a^3x+49x^2=(16a^3+7x)^2\)
  2. \(49b^{6}-16s^2=(7b^3+4s)(7b^3-4s)\)
  3. \(81p^{8}+198p^4s+121s^2=(9p^4+11s)^2\)
  4. \(169-225b^{4}=(13-15b^2)(13+15b^2)\)
  5. \(s^2-81=(s+9)(s-9)\)
  6. \(49x^2+182x+169=(7x+13)^2\)
  7. \(64b^{8}+48b^4q+9q^2=(8b^4+3q)^2\)
  8. \(9b^{10}-66b^5+121=(3b^5-11)^2\)
  9. \(36q^{8}+12q^4y+1y^2=(6q^4+y)^2\)
  10. \(16a^{10}-49b^2=(4a^5+7b)(4a^5-7b)\)
  11. \(a^2-36=(a-6)(a+6)\)
  12. \(100q^2-49p^{6}=(10q-7p^3)(10q+7p^3)\)
Oefeningengenerator wiskundeoefeningen.be 2026-09-15 08:42:39
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