Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(y^2-20y+100\)
  2. \(49-100y^{6}\)
  3. \(1-225p^{8}\)
  4. \(y^2+20y+100\)
  5. \(49-25s^{16}\)
  6. \(9p^{10}+6p^5x+1x^2\)
  7. \(64q^{4}+240q^2s+225s^2\)
  8. \(144s^2-49q^{10}\)
  9. \(49-81b^{12}\)
  10. \(169x^2-36a^{14}\)
  11. \(225x^2-64p^{10}\)
  12. \(169x^{6}-156x^3+36\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(y^2-20y+100=(y-10)^2\)
  2. \(49-100y^{6}=(7-10y^3)(7+10y^3)\)
  3. \(1-225p^{8}=(1-15p^4)(1+15p^4)\)
  4. \(y^2+20y+100=(y+10)^2\)
  5. \(49-25s^{16}=(7-5s^8)(7+5s^8)\)
  6. \(9p^{10}+6p^5x+1x^2=(3p^5+x)^2\)
  7. \(64q^{4}+240q^2s+225s^2=(8q^2+15s)^2\)
  8. \(144s^2-49q^{10}=(12s-7q^5)(12s+7q^5)\)
  9. \(49-81b^{12}=(7-9b^6)(7+9b^6)\)
  10. \(169x^2-36a^{14}=(13x-6a^7)(13x+6a^7)\)
  11. \(225x^2-64p^{10}=(15x-8p^5)(15x+8p^5)\)
  12. \(169x^{6}-156x^3+36=(13x^3-6)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-09-21 01:21:48
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