Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(16p^2+8p+1\)
  2. \(4a^{4}+4a^2x+1x^2\)
  3. \(25-121b^{16}\)
  4. \(4y^2-9\)
  5. \(81p^2-234p+169\)
  6. \(49s^2-100p^{16}\)
  7. \(x^2-9\)
  8. \(64b^{10}+16b^5+1\)
  9. \(16p^{10}-121\)
  10. \(64b^{4}+144b^2q+81q^2\)
  11. \(9a^{12}-25\)
  12. \(64b^{8}+112b^4p+49p^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(16p^2+8p+1=(4p+1)^2\)
  2. \(4a^{4}+4a^2x+1x^2=(2a^2+x)^2\)
  3. \(25-121b^{16}=(5-11b^8)(5+11b^8)\)
  4. \(4y^2-9=(2y+3)(2y-3)\)
  5. \(81p^2-234p+169=(9p-13)^2\)
  6. \(49s^2-100p^{16}=(7s-10p^8)(7s+10p^8)\)
  7. \(x^2-9=(x+3)(x-3)\)
  8. \(64b^{10}+16b^5+1=(8b^5+1)^2\)
  9. \(16p^{10}-121=(4p^5+11)(4p^5-11)\)
  10. \(64b^{4}+144b^2q+81q^2=(8b^2+9q)^2\)
  11. \(9a^{12}-25=(3a^6+5)(3a^6-5)\)
  12. \(64b^{8}+112b^4p+49p^2=(8b^4+7p)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-04 22:08:13
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