Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(q^2+8q+16\)
  2. \(49p^{16}-4q^2\)
  3. \(q^2-196\)
  4. \(4p^{6}+4p^3y+1y^2\)
  5. \(p^2-169\)
  6. \(256x^{4}-1\)
  7. \(4a^2-25\)
  8. \(25-64q^{12}\)
  9. \(121b^{4}+264b^2p+144p^2\)
  10. \(64a^{6}-169q^2\)
  11. \(-16s^2+49\)
  12. \(256q^{10}+288q^5x+81x^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(q^2+8q+16=(q+4)^2\)
  2. \(49p^{16}-4q^2=(7p^8+2q)(7p^8-2q)\)
  3. \(q^2-196=(q+14)(q-14)\)
  4. \(4p^{6}+4p^3y+1y^2=(2p^3+y)^2\)
  5. \(p^2-169=(p-13)(p+13)\)
  6. \(256x^{4}-1=(16x^2+1)(16x^2-1)\)
  7. \(4a^2-25=(2a+5)(2a-5)\)
  8. \(25-64q^{12}=(5-8q^6)(5+8q^6)\)
  9. \(121b^{4}+264b^2p+144p^2=(11b^2+12p)^2\)
  10. \(64a^{6}-169q^2=(8a^3+13q)(8a^3-13q)\)
  11. \(-16s^2+49=(7-4s)(7+4s)\)
  12. \(256q^{10}+288q^5x+81x^2=(16q^5+9x)^2\)
Oefeningengenerator wiskundeoefeningen.be 2026-04-05 02:03:47
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