Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(121q^2-64a^{6}\)
  2. \(4a^2+4a+1\)
  3. \(169b^{6}-144s^2\)
  4. \(1-16q^{8}\)
  5. \(49x^{10}-224x^5+256\)
  6. \(256a^{10}+416a^5y+169y^2\)
  7. \(9-196b^{16}\)
  8. \(a^2-2a+1\)
  9. \(169x^2-81q^{12}\)
  10. \(81a^{6}-234a^3+169\)
  11. \(4s^{6}+20s^3+25\)
  12. \(196-9x^{4}\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(121q^2-64a^{6}=(11q-8a^3)(11q+8a^3)\)
  2. \(4a^2+4a+1=(2a+1)^2\)
  3. \(169b^{6}-144s^2=(13b^3+12s)(13b^3-12s)\)
  4. \(1-16q^{8}=(1-4q^4)(1+4q^4)\)
  5. \(49x^{10}-224x^5+256=(7x^5-16)^2\)
  6. \(256a^{10}+416a^5y+169y^2=(16a^5+13y)^2\)
  7. \(9-196b^{16}=(3-14b^8)(3+14b^8)\)
  8. \(a^2-2a+1=(a-1)^2\)
  9. \(169x^2-81q^{12}=(13x-9q^6)(13x+9q^6)\)
  10. \(81a^{6}-234a^3+169=(9a^3-13)^2\)
  11. \(4s^{6}+20s^3+25=(2s^3+5)^2\)
  12. \(196-9x^{4}=(14-3x^2)(14+3x^2)\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-25 22:43:15
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