Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(144q^{6}-264q^3x+121x^2\)
  2. \(p^2-16\)
  3. \(100p^{10}+220p^5+121\)
  4. \(49p^{6}-224p^3y+256y^2\)
  5. \(a^2+22a+121\)
  6. \(q^2-9\)
  7. \(9p^{14}-49x^2\)
  8. \(4q^{8}-81x^2\)
  9. \(196s^2+252s+81\)
  10. \(81x^2-256p^{12}\)
  11. \(a^2-6a+9\)
  12. \(49a^{10}-225p^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(144q^{6}-264q^3x+121x^2=(12q^3-11x)^2\)
  2. \(p^2-16=(p+4)(p-4)\)
  3. \(100p^{10}+220p^5+121=(10p^5+11)^2\)
  4. \(49p^{6}-224p^3y+256y^2=(7p^3-16y)^2\)
  5. \(a^2+22a+121=(a+11)^2\)
  6. \(q^2-9=(q-3)(q+3)\)
  7. \(9p^{14}-49x^2=(3p^7+7x)(3p^7-7x)\)
  8. \(4q^{8}-81x^2=(2q^4+9x)(2q^4-9x)\)
  9. \(196s^2+252s+81=(14s+9)^2\)
  10. \(81x^2-256p^{12}=(9x-16p^6)(9x+16p^6)\)
  11. \(a^2-6a+9=(a-3)^2\)
  12. \(49a^{10}-225p^2=(7a^5+15p)(7a^5-15p)\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-27 11:43:29
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