Ontbinden in factoren (1)

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Ontbind in factoren door gebruik te maken van merkwaardige producten

  1. \(64s^{6}-208s^3y+169y^2\)
  2. \(16a^{10}-9x^2\)
  3. \(49x^{10}-140x^5+100\)
  4. \(y^2-28y+196\)
  5. \(64x^2+16x+1\)
  6. \(81b^2-100\)
  7. \(169y^2+78y+9\)
  8. \(b^2+12b+36\)
  9. \(25-64a^{4}\)
  10. \(64q^{10}-121s^2\)
  11. \(p^2-169\)
  12. \(16a^{16}-25b^2\)

Ontbind in factoren door gebruik te maken van merkwaardige producten

Verbetersleutel

  1. \(64s^{6}-208s^3y+169y^2=(8s^3-13y)^2\)
  2. \(16a^{10}-9x^2=(4a^5+3x)(4a^5-3x)\)
  3. \(49x^{10}-140x^5+100=(7x^5-10)^2\)
  4. \(y^2-28y+196=(y-14)^2\)
  5. \(64x^2+16x+1=(8x+1)^2\)
  6. \(81b^2-100=(9b+10)(9b-10)\)
  7. \(169y^2+78y+9=(13y+3)^2\)
  8. \(b^2+12b+36=(b+6)^2\)
  9. \(25-64a^{4}=(5-8a^2)(5+8a^2)\)
  10. \(64q^{10}-121s^2=(8q^5+11s)(8q^5-11s)\)
  11. \(p^2-169=(p-13)(p+13)\)
  12. \(16a^{16}-25b^2=(4a^8+5b)(4a^8-5b)\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-10 15:21:24
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