Stelsels met breuken

Hoofdmenu Eentje per keer  🖨

Substitutie of combinatie

1. \(\left\{\begin{matrix}-x-6y=\frac{7}{9}\\3x-2y=\frac{8}{3}\end{matrix}\right.\)
2. \(\left\{\begin{matrix}-y=\frac{-110}{9}-5x\\4x+3y=\frac{83}{9}\end{matrix}\right.\)
3. \(\left\{\begin{matrix}-3y=\frac{-39}{20}+3x\\-x+3y=\frac{-61}{20}\end{matrix}\right.\)
4. \(\left\{\begin{matrix}-5y=\frac{1}{6}+3x\\4x-y=\frac{-16}{3}\end{matrix}\right.\)
5. \(\left\{\begin{matrix}-2x+5y=\frac{127}{30}\\-3x+y=\frac{121}{60}\end{matrix}\right.\)
6. \(\left\{\begin{matrix}-2y=\frac{111}{14}+x\\4x+4y=\frac{-202}{7}\end{matrix}\right.\)
7. \(\left\{\begin{matrix}-3x-2y=\frac{-41}{7}\\-2x-y=\frac{-24}{7}\end{matrix}\right.\)
8. \(\left\{\begin{matrix}x+2y=\frac{-181}{105}\\4x+6y=\frac{-634}{105}\end{matrix}\right.\)
9. \(\left\{\begin{matrix}3y=\frac{-1}{2}+2x\\x-6y=\frac{-17}{4}\end{matrix}\right.\)
10. \(\left\{\begin{matrix}5y=\frac{301}{19}+6x\\5x+y=\frac{-644}{57}\end{matrix}\right.\)
11. \(\left\{\begin{matrix}-y=\frac{181}{3}-4x\\2x+4y=\frac{86}{3}\end{matrix}\right.\)
12. \(\left\{\begin{matrix}5x+2y=\frac{-88}{3}\\-3x=y+\frac{53}{3}\end{matrix}\right.\)

---

Substitutie of combinatie

Verbetersleutel

1. \(\left\{\begin{matrix}-x-6y=\frac{7}{9}\\3x-2y=\frac{8}{3}\end{matrix}\right.\qquad V=\{(\frac{13}{18},\frac{-1}{4})\}\)
2. \(\left\{\begin{matrix}-y=\frac{-110}{9}-5x\\4x+3y=\frac{83}{9}\end{matrix}\right.\qquad V=\{(\frac{-13}{9},5)\}\)
3. \(\left\{\begin{matrix}-3y=\frac{-39}{20}+3x\\-x+3y=\frac{-61}{20}\end{matrix}\right.\qquad V=\{(\frac{5}{4},\frac{-3}{5})\}\)
4. \(\left\{\begin{matrix}-5y=\frac{1}{6}+3x\\4x-y=\frac{-16}{3}\end{matrix}\right.\qquad V=\{(\frac{-7}{6},\frac{2}{3})\}\)
5. \(\left\{\begin{matrix}-2x+5y=\frac{127}{30}\\-3x+y=\frac{121}{60}\end{matrix}\right.\qquad V=\{(\frac{-9}{20},\frac{2}{3})\}\)
6. \(\left\{\begin{matrix}-2y=\frac{111}{14}+x\\4x+4y=\frac{-202}{7}\end{matrix}\right.\qquad V=\{(\frac{-13}{2},\frac{-5}{7})\}\)
7. \(\left\{\begin{matrix}-3x-2y=\frac{-41}{7}\\-2x-y=\frac{-24}{7}\end{matrix}\right.\qquad V=\{(1,\frac{10}{7})\}\)
8. \(\left\{\begin{matrix}x+2y=\frac{-181}{105}\\4x+6y=\frac{-634}{105}\end{matrix}\right.\qquad V=\{(\frac{-13}{15},\frac{-3}{7})\}\)
9. \(\left\{\begin{matrix}3y=\frac{-1}{2}+2x\\x-6y=\frac{-17}{4}\end{matrix}\right.\qquad V=\{(\frac{7}{4},1)\}\)
10. \(\left\{\begin{matrix}5y=\frac{301}{19}+6x\\5x+y=\frac{-644}{57}\end{matrix}\right.\qquad V=\{(\frac{-7}{3},\frac{7}{19})\}\)
11. \(\left\{\begin{matrix}-y=\frac{181}{3}-4x\\2x+4y=\frac{86}{3}\end{matrix}\right.\qquad V=\{(15,\frac{-1}{3})\}\)
12. \(\left\{\begin{matrix}5x+2y=\frac{-88}{3}\\-3x=y+\frac{53}{3}\end{matrix}\right.\qquad V=\{(-6,\frac{1}{3})\}\)