Stelsels met breuken

Hoofdmenu Eentje per keer  🖨

Substitutie of combinatie

1. \(\left\{\begin{matrix}-3x-5y=-4\\3x=y+\frac{-7}{2}\end{matrix}\right.\)
2. \(\left\{\begin{matrix}4x+2y=\frac{140}{187}\\-6x-y=\frac{-686}{187}\end{matrix}\right.\)
3. \(\left\{\begin{matrix}3x+3y=\frac{-192}{13}\\6x=y+\frac{-391}{13}\end{matrix}\right.\)
4. \(\left\{\begin{matrix}-3x+3y=\frac{-111}{17}\\3x=-y+\frac{-25}{17}\end{matrix}\right.\)
5. \(\left\{\begin{matrix}-4x+4y=\frac{-41}{35}\\-4x=y+\frac{-409}{140}\end{matrix}\right.\)
6. \(\left\{\begin{matrix}6x+y=\frac{23}{3}\\2x+2y=\frac{16}{3}\end{matrix}\right.\)
7. \(\left\{\begin{matrix}-y=\frac{41}{10}+3x\\6x+3y=\frac{-54}{5}\end{matrix}\right.\)
8. \(\left\{\begin{matrix}-x+3y=\frac{-239}{130}\\-3x=6y+\frac{933}{130}\end{matrix}\right.\)
9. \(\left\{\begin{matrix}-y=\frac{-1392}{95}-6x\\-5x+3y=\frac{193}{19}\end{matrix}\right.\)
10. \(\left\{\begin{matrix}5y=\frac{499}{76}+6x\\x+y=\frac{-93}{152}\end{matrix}\right.\)
11. \(\left\{\begin{matrix}4y=\frac{-57}{10}+x\\-6x+5y=-19\end{matrix}\right.\)
12. \(\left\{\begin{matrix}3x+5y=\frac{53}{12}\\x=-4y+\frac{55}{12}\end{matrix}\right.\)

---

Substitutie of combinatie

Verbetersleutel

1. \(\left\{\begin{matrix}-3x-5y=-4\\3x=y+\frac{-7}{2}\end{matrix}\right.\qquad V=\{(\frac{-3}{4},\frac{5}{4})\}\)
2. \(\left\{\begin{matrix}4x+2y=\frac{140}{187}\\-6x-y=\frac{-686}{187}\end{matrix}\right.\qquad V=\{(\frac{14}{17},\frac{-14}{11})\}\)
3. \(\left\{\begin{matrix}3x+3y=\frac{-192}{13}\\6x=y+\frac{-391}{13}\end{matrix}\right.\qquad V=\{(-5,\frac{1}{13})\}\)
4. \(\left\{\begin{matrix}-3x+3y=\frac{-111}{17}\\3x=-y+\frac{-25}{17}\end{matrix}\right.\qquad V=\{(\frac{3}{17},-2)\}\)
5. \(\left\{\begin{matrix}-4x+4y=\frac{-41}{35}\\-4x=y+\frac{-409}{140}\end{matrix}\right.\qquad V=\{(\frac{9}{14},\frac{7}{20})\}\)
6. \(\left\{\begin{matrix}6x+y=\frac{23}{3}\\2x+2y=\frac{16}{3}\end{matrix}\right.\qquad V=\{(1,\frac{5}{3})\}\)
7. \(\left\{\begin{matrix}-y=\frac{41}{10}+3x\\6x+3y=\frac{-54}{5}\end{matrix}\right.\qquad V=\{(\frac{-1}{2},\frac{-13}{5})\}\)
8. \(\left\{\begin{matrix}-x+3y=\frac{-239}{130}\\-3x=6y+\frac{933}{130}\end{matrix}\right.\qquad V=\{(\frac{-7}{10},\frac{-11}{13})\}\)
9. \(\left\{\begin{matrix}-y=\frac{-1392}{95}-6x\\-5x+3y=\frac{193}{19}\end{matrix}\right.\qquad V=\{(\frac{-13}{5},\frac{-18}{19})\}\)
10. \(\left\{\begin{matrix}5y=\frac{499}{76}+6x\\x+y=\frac{-93}{152}\end{matrix}\right.\qquad V=\{(\frac{-7}{8},\frac{5}{19})\}\)
11. \(\left\{\begin{matrix}4y=\frac{-57}{10}+x\\-6x+5y=-19\end{matrix}\right.\qquad V=\{(\frac{5}{2},\frac{-4}{5})\}\)
12. \(\left\{\begin{matrix}3x+5y=\frac{53}{12}\\x=-4y+\frac{55}{12}\end{matrix}\right.\qquad V=\{(\frac{-3}{4},\frac{4}{3})\}\)