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- \(\left(-\dfrac{7}{2}\cdot\dfrac{12}{63}-\dfrac{1}{9}\right)^2\)
- \(\sqrt{\dfrac{4}{49}}-\left(\dfrac{11}{14}\right)^2\)
- \(10.(-9)-2.(-5)-4\)
- \(\dfrac{11}{2}-\dfrac{9}{2}\cdot\dfrac{10}{9}\)
- \(-13.5^2+17\)
- \(\sqrt{\dfrac{144}{49}}-\left(\dfrac{15}{14}\right)^2\)
- \(2.4^2+(2.4)^2\)
- \(\dfrac{11}{4}-\dfrac{9}{4}\cdot\dfrac{7}{9}\)
- \((-15).(-10)+3\)
- \(\sqrt{\dfrac{9}{49}}-\left(\dfrac{11}{14}\right)^2\)
- \(\left(-\dfrac{5}{3}\cdot\dfrac{12}{40}-\dfrac{1}{8}\right)^2\)
- \(5+15-20.(-13)\)
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Verbetersleutel
- \(\left(-\dfrac{7}{2}\cdot\dfrac{12}{63}-\dfrac{1}{9}\right)^2= \left(-\dfrac{7.12}{2.63}-\dfrac{1}{9}\right)^2= \left(-\dfrac{2}{3}-\dfrac{1}{9}\right)^2= \left(-\dfrac{6}{9}-\dfrac{1}{9}\right)^2= \left(\dfrac{-7}{9}\right)^2= \dfrac{49}{81}\)
- \(\sqrt{\dfrac{4}{49}}-\left(\dfrac{11}{14}\right)^2= \dfrac{2}{7} - \dfrac{121}{196}= \dfrac{56}{196} - \dfrac{121}{196}= \dfrac{-65}{196}\)
- \(10.(-9)-2.(-5)-4=-90+10-4=-84\)
- \(\dfrac{11}{2}-\dfrac{9}{2}\cdot\dfrac{10}{9}= \dfrac{11}{2}-\dfrac{9\cdot 10}{2\cdot9}= \dfrac{11}{2}-\dfrac{10}{2}= \dfrac{11-10}{2}= \dfrac{1}{2}\)
- \(-13.5^2+17=-13.25+17=-325+17=-308\)
- \(\sqrt{\dfrac{144}{49}}-\left(\dfrac{15}{14}\right)^2= \dfrac{12}{7} - \dfrac{225}{196}= \dfrac{336}{196} - \dfrac{225}{196}= \dfrac{111}{196}\)
- \(2.4^2+(2.4)^2=2.4^2+(8)^2=2.16+64=32+64=96\)
- \(\dfrac{11}{4}-\dfrac{9}{4}\cdot\dfrac{7}{9}= \dfrac{11}{4}-\dfrac{9\cdot 7}{4\cdot9}= \dfrac{11}{4}-\dfrac{7}{4}= \dfrac{11-7}{4}= \dfrac{4}{4}= \dfrac{1}{1}\)
- \((-15).(-10)+3=150+3=153\)
- \(\sqrt{\dfrac{9}{49}}-\left(\dfrac{11}{14}\right)^2= \dfrac{3}{7} - \dfrac{121}{196}= \dfrac{84}{196} - \dfrac{121}{196}= \dfrac{-37}{196}\)
- \(\left(-\dfrac{5}{3}\cdot\dfrac{12}{40}-\dfrac{1}{8}\right)^2= \left(-\dfrac{5.12}{3.40}-\dfrac{1}{8}\right)^2= \left(-\dfrac{1}{2}-\dfrac{1}{8}\right)^2= \left(-\dfrac{4}{8}-\dfrac{1}{8}\right)^2= \left(\dfrac{-5}{8}\right)^2= \dfrac{25}{64}\)
- \(5+15-20.(-13)=5+15+260=280\)