Volgorde van bewerkingen (gevorderd)

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  1. \(2+13-13.(-14)\)
  2. \(2+3.(10^2-6)\)
  3. \(5+3.(6^2-9)\)
  4. \(-15+19.(-20)\)
  5. \(-14-4.(-4-13)+2\)
  6. \(8-\sqrt{481-3.12^2}\)
  7. \(\dfrac{5}{4}-\dfrac{1}{4}\cdot\dfrac{12}{1}\)
  8. \(\sqrt{\dfrac{121}{4}}-\left(\dfrac{15}{4}\right)^2\)
  9. \(\left(-\dfrac{7}{4}\cdot\dfrac{32}{77}-\dfrac{1}{11}\right)^2\)
  10. \(2.4^2+(2.4)^2\)
  11. \(-5-5.(-10-3)+10\)
  12. \(\dfrac{7}{5}-\dfrac{4}{5}\cdot\dfrac{3}{4}\)

Reken uit

Verbetersleutel

  1. \(2+13-13.(-14)=2+13+182=197\)
  2. \(2+3.(10^2-6)=2+3.(100-6)=2+3.(94)=2+282=284\)
  3. \(5+3.(6^2-9)=5+3.(36-9)=5+3.(27)=5+81=86\)
  4. \(-15+19.(-20)=-15+(-380)=-395\)
  5. \(-14-4.(-4-13)+2=-14-4.(-17)+2=-14-(-68)+2=56\)
  6. \(8-\sqrt{481-3.12^2}=8-\sqrt{481-3.144}=8-\sqrt{481-432}=8-\sqrt{49}=8-7=1\)
  7. \(\dfrac{5}{4}-\dfrac{1}{4}\cdot\dfrac{12}{1}= \dfrac{5}{4}-\dfrac{1\cdot 12}{4\cdot1}= \dfrac{5}{4}-\dfrac{12}{4}= \dfrac{5-12}{4}= \dfrac{-7}{4}\)
  8. \(\sqrt{\dfrac{121}{4}}-\left(\dfrac{15}{4}\right)^2= \dfrac{11}{2} - \dfrac{225}{16}= \dfrac{88}{16} - \dfrac{225}{16}= \dfrac{-137}{16}\)
  9. \(\left(-\dfrac{7}{4}\cdot\dfrac{32}{77}-\dfrac{1}{11}\right)^2= \left(-\dfrac{7.32}{4.77}-\dfrac{1}{11}\right)^2= \left(-\dfrac{8}{11}-\dfrac{1}{11}\right)^2= \left(-\dfrac{8}{11}-\dfrac{1}{11}\right)^2= \left(\dfrac{-9}{11}\right)^2= \dfrac{81}{121}\)
  10. \(2.4^2+(2.4)^2=2.4^2+(8)^2=2.16+64=32+64=96\)
  11. \(-5-5.(-10-3)+10=-5-5.(-13)+10=-5-(-65)+10=70\)
  12. \(\dfrac{7}{5}-\dfrac{4}{5}\cdot\dfrac{3}{4}= \dfrac{7}{5}-\dfrac{4\cdot 3}{5\cdot4}= \dfrac{7}{5}-\dfrac{3}{5}= \dfrac{7-3}{5}= \dfrac{4}{5}\)
Oefeningengenerator wiskundeoefeningen.be 2025-09-18 15:26:03
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