Volgorde van bewerkingen (gevorderd)

Hoofdmenu Eentje per keer 

Reken uit

  1. \(-8.\sqrt{\frac{49}{100}}-\left[(\frac{11}{11}-9)-(-2)^3\right]\)
  2. \(10+45:(-5)\)
  3. \(-8.11^2+6\)
  4. \(4+6.6-8:2+10\)
  5. \(-9.\sqrt{\frac{121}{81}}-\left[(\frac{16}{17}-3)-(-4)^3\right]\)
  6. \(\dfrac{6}{5}-\dfrac{3}{5}\cdot\dfrac{5}{3}\)
  7. \(90-15:5+8\)
  8. \(\sqrt{\dfrac{4}{9}}-\left(\dfrac{5}{6}\right)^2\)
  9. \(7+3.(2^2-5)\)
  10. \(\left(-\dfrac{6}{2}\cdot\dfrac{16}{66}-\dfrac{1}{11}\right)^2\)
  11. \(-8.\sqrt{\frac{361}{64}}-\left[(\frac{-4}{8}-7)-(-4)^3\right]\)
  12. \(\sqrt{\dfrac{100}{49}}-\left(\dfrac{5}{14}\right)^2\)

Reken uit

Verbetersleutel

  1. \(-8.\sqrt{\frac{49}{100}}-\left[(\frac{11}{11}-9)-(-2)^3\right]=-8.\frac{7}{10}-\left[(1-9)+8\right]=\frac{-28}{5}-\left[(-8)+8\right]=\frac{-28}{5}-\left[0\right]=\frac{-28}{5}\)
  2. \(10+45:(-5)=10+ (-9)=1\)
  3. \(-8.11^2+6=-8.121+6=-968+6=-962\)
  4. \(4+6.6-8:2+10=4+36-4+10=46\)
  5. \(-9.\sqrt{\frac{121}{81}}-\left[(\frac{16}{17}-3)-(-4)^3\right]=-9.\frac{11}{9}-\left[(\frac{16}{17}-3)+64\right]=-11-\left[(\frac{-35}{17})+64\right]=-11-\left[\frac{1053}{17}\right]=\frac{-1240}{17}\)
  6. \(\dfrac{6}{5}-\dfrac{3}{5}\cdot\dfrac{5}{3}= \dfrac{6}{5}-\dfrac{3\cdot 5}{5\cdot3}= \dfrac{6}{5}-\dfrac{5}{5}= \dfrac{6-5}{5}= \dfrac{1}{5}\)
  7. \(90-15:5+8=90-3+8=95\)
  8. \(\sqrt{\dfrac{4}{9}}-\left(\dfrac{5}{6}\right)^2= \dfrac{2}{3} - \dfrac{25}{36}= \dfrac{24}{36} - \dfrac{25}{36}= \dfrac{-1}{36}\)
  9. \(7+3.(2^2-5)=7+3.(4-5)=7+3.(-1)=7+-3=4\)
  10. \(\left(-\dfrac{6}{2}\cdot\dfrac{16}{66}-\dfrac{1}{11}\right)^2= \left(-\dfrac{6.16}{2.66}-\dfrac{1}{11}\right)^2= \left(-\dfrac{8}{11}-\dfrac{1}{11}\right)^2= \left(-\dfrac{8}{11}-\dfrac{1}{11}\right)^2= \left(\dfrac{-9}{11}\right)^2= \dfrac{81}{121}\)
  11. \(-8.\sqrt{\frac{361}{64}}-\left[(\frac{-4}{8}-7)-(-4)^3\right]=-8.\frac{19}{8}-\left[(\frac{-1}{2}-7)+64\right]=-19-\left[(\frac{-15}{2})+64\right]=-19-\left[\frac{113}{2}\right]=\frac{-151}{2}\)
  12. \(\sqrt{\dfrac{100}{49}}-\left(\dfrac{5}{14}\right)^2= \dfrac{10}{7} - \dfrac{25}{196}= \dfrac{280}{196} - \dfrac{25}{196}= \dfrac{255}{196}\)
Oefeningengenerator wiskundeoefeningen.be 2026-03-04 13:48:53
Een site van Busleyden Atheneum Mechelen