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- \(2+13-13.(-14)\)
- \(2+3.(10^2-6)\)
- \(5+3.(6^2-9)\)
- \(-15+19.(-20)\)
- \(-14-4.(-4-13)+2\)
- \(8-\sqrt{481-3.12^2}\)
- \(\dfrac{5}{4}-\dfrac{1}{4}\cdot\dfrac{12}{1}\)
- \(\sqrt{\dfrac{121}{4}}-\left(\dfrac{15}{4}\right)^2\)
- \(\left(-\dfrac{7}{4}\cdot\dfrac{32}{77}-\dfrac{1}{11}\right)^2\)
- \(2.4^2+(2.4)^2\)
- \(-5-5.(-10-3)+10\)
- \(\dfrac{7}{5}-\dfrac{4}{5}\cdot\dfrac{3}{4}\)
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Verbetersleutel
- \(2+13-13.(-14)=2+13+182=197\)
- \(2+3.(10^2-6)=2+3.(100-6)=2+3.(94)=2+282=284\)
- \(5+3.(6^2-9)=5+3.(36-9)=5+3.(27)=5+81=86\)
- \(-15+19.(-20)=-15+(-380)=-395\)
- \(-14-4.(-4-13)+2=-14-4.(-17)+2=-14-(-68)+2=56\)
- \(8-\sqrt{481-3.12^2}=8-\sqrt{481-3.144}=8-\sqrt{481-432}=8-\sqrt{49}=8-7=1\)
- \(\dfrac{5}{4}-\dfrac{1}{4}\cdot\dfrac{12}{1}= \dfrac{5}{4}-\dfrac{1\cdot 12}{4\cdot1}= \dfrac{5}{4}-\dfrac{12}{4}= \dfrac{5-12}{4}= \dfrac{-7}{4}\)
- \(\sqrt{\dfrac{121}{4}}-\left(\dfrac{15}{4}\right)^2= \dfrac{11}{2} - \dfrac{225}{16}= \dfrac{88}{16} - \dfrac{225}{16}= \dfrac{-137}{16}\)
- \(\left(-\dfrac{7}{4}\cdot\dfrac{32}{77}-\dfrac{1}{11}\right)^2= \left(-\dfrac{7.32}{4.77}-\dfrac{1}{11}\right)^2= \left(-\dfrac{8}{11}-\dfrac{1}{11}\right)^2= \left(-\dfrac{8}{11}-\dfrac{1}{11}\right)^2= \left(\dfrac{-9}{11}\right)^2= \dfrac{81}{121}\)
- \(2.4^2+(2.4)^2=2.4^2+(8)^2=2.16+64=32+64=96\)
- \(-5-5.(-10-3)+10=-5-5.(-13)+10=-5-(-65)+10=70\)
- \(\dfrac{7}{5}-\dfrac{4}{5}\cdot\dfrac{3}{4}= \dfrac{7}{5}-\dfrac{4\cdot 3}{5\cdot4}= \dfrac{7}{5}-\dfrac{3}{5}= \dfrac{7-3}{5}= \dfrac{4}{5}\)