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1. \(-\sqrt{10}\cdot\sqrt{490}\)
2. \(\frac{\sqrt{2925}}{\sqrt{13}}\)
3. \(\sqrt{5}\cdot\sqrt{20}\)
4. \(-\sqrt{2}\cdot\sqrt{242}\)
5. \(-\sqrt{6}\cdot\sqrt{150}\)
6. \(\sqrt{2}\cdot\sqrt{50}\)
7. \(-\sqrt{6}\cdot\sqrt{294}\)
8. \(\frac{\sqrt{150}}{\sqrt{6}}\)
9. \(\sqrt{3}\cdot\sqrt{147}\)
10. \(-\sqrt{3}\cdot\sqrt{12}\)
11. \(-\frac{\sqrt{1690}}{\sqrt{10}}\)
12. \(-\sqrt{6}\cdot\sqrt{726}\)

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Verbetersleutel

1. \(-\sqrt{10}\cdot\sqrt{490}=-\sqrt{10 \cdot 490}=-\sqrt{10 \cdot 10 \cdot 49}=-\sqrt{10 \cdot 10} \cdot \sqrt{49}=-10\cdot7=-70\)
2. \(\frac{\sqrt{2925}}{\sqrt{13}}=\sqrt{ \frac{2925}{13}}=\sqrt{ 225}=15\)
3. \(\sqrt{5}\cdot\sqrt{20}=\sqrt{5 \cdot 20}=\sqrt{5 \cdot 5 \cdot 4}=\sqrt{5 \cdot 5} \cdot \sqrt{4}=5\cdot2=10\)
4. \(-\sqrt{2}\cdot\sqrt{242}=-\sqrt{2 \cdot 242}=-\sqrt{2 \cdot 2 \cdot 121}=-\sqrt{2 \cdot 2} \cdot \sqrt{121}=-2\cdot11=-22\)
5. \(-\sqrt{6}\cdot\sqrt{150}=-\sqrt{6 \cdot 150}=-\sqrt{6 \cdot 6 \cdot 25}=-\sqrt{6 \cdot 6} \cdot \sqrt{25}=-6\cdot5=-30\)
6. \(\sqrt{2}\cdot\sqrt{50}=\sqrt{2 \cdot 50}=\sqrt{2 \cdot 2 \cdot 25}=\sqrt{2 \cdot 2} \cdot \sqrt{25}=2\cdot5=10\)
7. \(-\sqrt{6}\cdot\sqrt{294}=-\sqrt{6 \cdot 294}=-\sqrt{6 \cdot 6 \cdot 49}=-\sqrt{6 \cdot 6} \cdot \sqrt{49}=-6\cdot7=-42\)
8. \(\frac{\sqrt{150}}{\sqrt{6}}=\sqrt{ \frac{150}{6}}=\sqrt{ 25}=5\)
9. \(\sqrt{3}\cdot\sqrt{147}=\sqrt{3 \cdot 147}=\sqrt{3 \cdot 3 \cdot 49}=\sqrt{3 \cdot 3} \cdot \sqrt{49}=3\cdot7=21\)
10. \(-\sqrt{3}\cdot\sqrt{12}=-\sqrt{3 \cdot 12}=-\sqrt{3 \cdot 3 \cdot 4}=-\sqrt{3 \cdot 3} \cdot \sqrt{4}=-3\cdot2=-6\)
11. \(-\frac{\sqrt{1690}}{\sqrt{10}}=-\sqrt{ \frac{1690}{10}}=-\sqrt{ 169}=-13\)
12. \(-\sqrt{6}\cdot\sqrt{726}=-\sqrt{6 \cdot 726}=-\sqrt{6 \cdot 6 \cdot 121}=-\sqrt{6 \cdot 6} \cdot \sqrt{121}=-6\cdot11=-66\)