Rekenen met wortels (reeks 3)

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  1. \(\frac{\sqrt{75}}{\sqrt{3}}\)
  2. \(-\frac{\sqrt{2023}}{\sqrt{7}}\)
  3. \(-\frac{\sqrt{2475}}{\sqrt{11}}\)
  4. \(-\sqrt{5}\cdot\sqrt{20}\)
  5. \(-\sqrt{6}\cdot\sqrt{294}\)
  6. \(-\frac{\sqrt{2548}}{\sqrt{13}}\)
  7. \(-\sqrt{2}\cdot\sqrt{242}\)
  8. \(-\sqrt{6}\cdot\sqrt{150}\)
  9. \(-\frac{\sqrt{1573}}{\sqrt{13}}\)
  10. \(-\frac{\sqrt{180}}{\sqrt{5}}\)
  11. \(\sqrt{2}\cdot\sqrt{50}\)
  12. \(\sqrt{2}\cdot\sqrt{98}\)

Reken uit

Verbetersleutel

  1. \(\frac{\sqrt{75}}{\sqrt{3}}=\sqrt{ \frac{75}{3}}=\sqrt{ 25}=5\)
  2. \(-\frac{\sqrt{2023}}{\sqrt{7}}=-\sqrt{ \frac{2023}{7}}=-\sqrt{ 289}=-17\)
  3. \(-\frac{\sqrt{2475}}{\sqrt{11}}=-\sqrt{ \frac{2475}{11}}=-\sqrt{ 225}=-15\)
  4. \(-\sqrt{5}\cdot\sqrt{20}=-\sqrt{5 \cdot 20}=-\sqrt{5 \cdot 5 \cdot 4}=-\sqrt{5 \cdot 5} \cdot \sqrt{4}=-5\cdot2=-10\)
  5. \(-\sqrt{6}\cdot\sqrt{294}=-\sqrt{6 \cdot 294}=-\sqrt{6 \cdot 6 \cdot 49}=-\sqrt{6 \cdot 6} \cdot \sqrt{49}=-6\cdot7=-42\)
  6. \(-\frac{\sqrt{2548}}{\sqrt{13}}=-\sqrt{ \frac{2548}{13}}=-\sqrt{ 196}=-14\)
  7. \(-\sqrt{2}\cdot\sqrt{242}=-\sqrt{2 \cdot 242}=-\sqrt{2 \cdot 2 \cdot 121}=-\sqrt{2 \cdot 2} \cdot \sqrt{121}=-2\cdot11=-22\)
  8. \(-\sqrt{6}\cdot\sqrt{150}=-\sqrt{6 \cdot 150}=-\sqrt{6 \cdot 6 \cdot 25}=-\sqrt{6 \cdot 6} \cdot \sqrt{25}=-6\cdot5=-30\)
  9. \(-\frac{\sqrt{1573}}{\sqrt{13}}=-\sqrt{ \frac{1573}{13}}=-\sqrt{ 121}=-11\)
  10. \(-\frac{\sqrt{180}}{\sqrt{5}}=-\sqrt{ \frac{180}{5}}=-\sqrt{ 36}=-6\)
  11. \(\sqrt{2}\cdot\sqrt{50}=\sqrt{2 \cdot 50}=\sqrt{2 \cdot 2 \cdot 25}=\sqrt{2 \cdot 2} \cdot \sqrt{25}=2\cdot5=10\)
  12. \(\sqrt{2}\cdot\sqrt{98}=\sqrt{2 \cdot 98}=\sqrt{2 \cdot 2 \cdot 49}=\sqrt{2 \cdot 2} \cdot \sqrt{49}=2\cdot7=14\)
Oefeningengenerator wiskundeoefeningen.be 2026-02-13 01:43:06
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