Rekenen met wortels (reeks 5)

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Maak de noemer wortelvrij

1. \(\frac{36}{\sqrt{7}}\)
2. \(\frac{41}{\sqrt{6}}\)
3. \(\frac{21}{\sqrt{10}}\)
4. \(\frac{22}{\sqrt{10}}\)
5. \(\frac{22}{\sqrt{15}}\)
6. \(\frac{23}{\sqrt{7}}\)
7. \(\frac{6}{\sqrt{19}}\)
8. \(\frac{55}{\sqrt{3}}\)
9. \(\frac{35}{\sqrt{8}}\)
10. \(\frac{6}{\sqrt{17}}\)
11. \(\frac{54}{\sqrt{7}}\)
12. \(\frac{13}{\sqrt{14}}\)

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Maak de noemer wortelvrij

Verbetersleutel

1. \(\frac{36}{\sqrt{7}}=\frac{36\cdot \color{red}{\sqrt{7}} }{\sqrt{7}\cdot \color{red}{\sqrt{7}} }=\frac{36\cdot\sqrt{7}}{7}\)
2. \(\frac{41}{\sqrt{6}}=\frac{41\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{41\cdot\sqrt{6}}{6}\)
3. \(\frac{21}{\sqrt{10}}=\frac{21\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{21\cdot\sqrt{10}}{10}\)
4. \(\frac{22}{\sqrt{10}}=\frac{22\cdot \color{red}{\sqrt{10}} }{\sqrt{10}\cdot \color{red}{\sqrt{10}} }=\frac{22\cdot\sqrt{10}}{10}=\frac{11\cdot\sqrt{10}}{5}\)
5. \(\frac{22}{\sqrt{15}}=\frac{22\cdot \color{red}{\sqrt{15}} }{\sqrt{15}\cdot \color{red}{\sqrt{15}} }=\frac{22\cdot\sqrt{15}}{15}\)
6. \(\frac{23}{\sqrt{7}}=\frac{23\cdot \color{red}{\sqrt{7}} }{\sqrt{7}\cdot \color{red}{\sqrt{7}} }=\frac{23\cdot\sqrt{7}}{7}\)
7. \(\frac{6}{\sqrt{19}}=\frac{6\cdot \color{red}{\sqrt{19}} }{\sqrt{19}\cdot \color{red}{\sqrt{19}} }=\frac{6\cdot\sqrt{19}}{19}\)
8. \(\frac{55}{\sqrt{3}}=\frac{55\cdot \color{red}{\sqrt{3}} }{\sqrt{3}\cdot \color{red}{\sqrt{3}} }=\frac{55\cdot\sqrt{3}}{3}\)
9. \(\frac{35}{\sqrt{8}}=\frac{35\cdot \color{red}{\sqrt{8}} }{\sqrt{8}\cdot \color{red}{\sqrt{8}} }=\frac{35\cdot\sqrt{8}}{8}\)
10. \(\frac{6}{\sqrt{17}}=\frac{6\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{6\cdot\sqrt{17}}{17}\)
11. \(\frac{54}{\sqrt{7}}=\frac{54\cdot \color{red}{\sqrt{7}} }{\sqrt{7}\cdot \color{red}{\sqrt{7}} }=\frac{54\cdot\sqrt{7}}{7}\)
12. \(\frac{13}{\sqrt{14}}=\frac{13\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{13\cdot\sqrt{14}}{14}\)