Rekenen met wortels (reeks 5)

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Maak de noemer wortelvrij

  1. \(\frac{8}{\sqrt{19}}\)
  2. \(\frac{19}{\sqrt{2}}\)
  3. \(\frac{54}{\sqrt{14}}\)
  4. \(\frac{35}{\sqrt{19}}\)
  5. \(\frac{52}{\sqrt{6}}\)
  6. \(\frac{21}{\sqrt{19}}\)
  7. \(\frac{20}{\sqrt{2}}\)
  8. \(\frac{40}{\sqrt{14}}\)
  9. \(\frac{50}{\sqrt{17}}\)
  10. \(\frac{32}{\sqrt{13}}\)
  11. \(\frac{22}{\sqrt{14}}\)
  12. \(\frac{26}{\sqrt{5}}\)

Maak de noemer wortelvrij

Verbetersleutel

  1. \(\frac{8}{\sqrt{19}}=\frac{8\cdot \color{red}{\sqrt{19}} }{\sqrt{19}\cdot \color{red}{\sqrt{19}} }=\frac{8\cdot\sqrt{19}}{19}\)
  2. \(\frac{19}{\sqrt{2}}=\frac{19\cdot \color{red}{\sqrt{2}} }{\sqrt{2}\cdot \color{red}{\sqrt{2}} }=\frac{19\cdot\sqrt{2}}{2}\)
  3. \(\frac{54}{\sqrt{14}}=\frac{54\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{54\cdot\sqrt{14}}{14}=\frac{27\cdot\sqrt{14}}{7}\)
  4. \(\frac{35}{\sqrt{19}}=\frac{35\cdot \color{red}{\sqrt{19}} }{\sqrt{19}\cdot \color{red}{\sqrt{19}} }=\frac{35\cdot\sqrt{19}}{19}\)
  5. \(\frac{52}{\sqrt{6}}=\frac{52\cdot \color{red}{\sqrt{6}} }{\sqrt{6}\cdot \color{red}{\sqrt{6}} }=\frac{52\cdot\sqrt{6}}{6}=\frac{26\cdot\sqrt{6}}{3}\)
  6. \(\frac{21}{\sqrt{19}}=\frac{21\cdot \color{red}{\sqrt{19}} }{\sqrt{19}\cdot \color{red}{\sqrt{19}} }=\frac{21\cdot\sqrt{19}}{19}\)
  7. \(\frac{20}{\sqrt{2}}=\frac{20\cdot \color{red}{\sqrt{2}} }{\sqrt{2}\cdot \color{red}{\sqrt{2}} }=\frac{20\cdot\sqrt{2}}{2}=10\cdot\sqrt{2}\)
  8. \(\frac{40}{\sqrt{14}}=\frac{40\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{40\cdot\sqrt{14}}{14}=\frac{20\cdot\sqrt{14}}{7}\)
  9. \(\frac{50}{\sqrt{17}}=\frac{50\cdot \color{red}{\sqrt{17}} }{\sqrt{17}\cdot \color{red}{\sqrt{17}} }=\frac{50\cdot\sqrt{17}}{17}\)
  10. \(\frac{32}{\sqrt{13}}=\frac{32\cdot \color{red}{\sqrt{13}} }{\sqrt{13}\cdot \color{red}{\sqrt{13}} }=\frac{32\cdot\sqrt{13}}{13}\)
  11. \(\frac{22}{\sqrt{14}}=\frac{22\cdot \color{red}{\sqrt{14}} }{\sqrt{14}\cdot \color{red}{\sqrt{14}} }=\frac{22\cdot\sqrt{14}}{14}=\frac{11\cdot\sqrt{14}}{7}\)
  12. \(\frac{26}{\sqrt{5}}=\frac{26\cdot \color{red}{\sqrt{5}} }{\sqrt{5}\cdot \color{red}{\sqrt{5}} }=\frac{26\cdot\sqrt{5}}{5}\)
Oefeningengenerator wiskundeoefeningen.be 2026-06-14 22:43:53
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