Basis breuken

\(14,622\ldots\)

\(x = 14,6\textbf{2}\textbf{2}\ldots\Leftrightarrow \begin{array}{ r | r }100x & 1462{,}22\ldots \\10x & 146{,}22\ldots \\\hline90x & 1316,00\ldots \end{array}\Leftrightarrow x = \dfrac{1316}{90}= \dfrac{658}{45}\)