Breuken haakjesregel (reeks 2)

Bereken

\(-\left(\frac{4}{-3}\right) -\left(\frac{8}{-5}\right) +\left(\frac{10}{2}\right)\)

\(-\left(\frac{4}{-3}\right) -\left(\frac{8}{-5}\right) +\left(\frac{10}{2}\right)\\= \frac{4}{3}+ \frac{8}{5}+\frac{10}{2}\\=\frac{4}{3}+\frac{8}{5}+\frac{5}{1}\\=\frac{20}{15}+\frac{24}{15}+\frac{75}{15}\\=\frac{20+24+75}{15}\\=\frac{119}{15}\)