Breuken haakjesregel (reeks 2)

Bereken

\(-\left(\frac{-3}{-7}\right) -\left(\frac{8}{-8}\right) +\left(\frac{10}{12}\right)\)

\(-\left(\frac{-3}{-7}\right) -\left(\frac{8}{-8}\right) +\left(\frac{10}{12}\right)\\= \frac{-3}{7}+ \frac{8}{8}+\frac{10}{12}\\=\frac{-3}{7}+\frac{1}{1}+\frac{5}{6}\\=\frac{-18}{42}+\frac{42}{42}+\frac{35}{42}\\=\frac{-18+42+35}{42}\\=\frac{59}{42}\)