Breuken haakjesregel (reeks 2)

Bereken

\(-\left(\frac{6}{-5}\right) +\left(\frac{-9}{-3}\right) +\left(\frac{3}{10}\right)\)

\(-\left(\frac{6}{-5}\right) +\left(\frac{-9}{-3}\right) +\left(\frac{3}{10}\right)\\= \frac{6}{5}+ \frac{9}{3}+\frac{3}{10}\\=\frac{6}{5}+\frac{3}{1}+\frac{3}{10}\\=\frac{12}{10}+\frac{30}{10}+\frac{3}{10}\\=\frac{12+30+3}{10}\\=\frac{45}{10}\\=\frac{9}{2}\)