Breuken haakjesregel (reeks 2)

Bereken

\(+\left(\frac{7}{6}\right) +\left(\frac{10}{7}\right) +\left(\frac{2}{-2}\right)\)

\(+\left(\frac{7}{6}\right) +\left(\frac{10}{7}\right) +\left(\frac{2}{-2}\right)\\= \frac{7}{6}+ \frac{10}{7}-\frac{2}{2}\\=\frac{7}{6}+\frac{10}{7}-\frac{1}{1}\\=\frac{49}{42}+\frac{60}{42}-\frac{42}{42}\\=\frac{49+60-42}{42}\\=\frac{67}{42}\)