Breuken haakjesregel (reeks 2)

Bereken

\(+\left(\frac{4}{5}\right) +\left(\frac{2}{3}\right) +\left(\frac{-12}{5}\right)\)

\(+\left(\frac{4}{5}\right) +\left(\frac{2}{3}\right) +\left(\frac{-12}{5}\right)\\= \frac{4}{5}+ \frac{2}{3}-\frac{12}{5}\\=\frac{12}{15}+\frac{10}{15}-\frac{36}{15}\\=\frac{12+10-36}{15}\\=\frac{-14}{15}\)