Breuken haakjesregel (reeks 2)

Bereken

\(+\left(\frac{10}{7}\right) +\left(\frac{4}{-5}\right) +\left(\frac{4}{-10}\right)\)

\(+\left(\frac{10}{7}\right) +\left(\frac{4}{-5}\right) +\left(\frac{4}{-10}\right)\\= \frac{10}{7}- \frac{4}{5}-\frac{4}{10}\\=\frac{10}{7}-\frac{4}{5}-\frac{2}{5}\\=\frac{50}{35}-\frac{28}{35}-\frac{14}{35}\\=\frac{50-28-14}{35}\\=\frac{8}{35}\)