Vermenigvuldigen en delen (a+bi)

Bereken

\(\frac{5+2i}{8+3i}\)

\(\frac{5+2i}{8+3i}= \frac{5+2i}{8+3i} \cdot \frac{8-3i}{8-3i} = \frac{40-15i +16 i-6i^2 }{(8)^2-(3i)^2} = \frac{40-15i +16 i+6}{64 + 9} = \frac{46+i }{73} = \frac{46}{73} - \frac{-1}{73}i \)