Vermenigvuldigen en delen (a+bi)

Bereken

\(\frac{3+3i}{6+8i}\)

\(\frac{3+3i}{6+8i}= \frac{3+3i}{6+8i} \cdot \frac{6-8i}{6-8i} = \frac{18-24i +18 i-24i^2 }{(6)^2-(8i)^2} = \frac{18-24i +18 i+24}{36 + 64} = \frac{42-6i }{100} = \frac{21}{50} + \frac{-3}{50}i \)