Vermenigvuldigen en delen (a+bi)

Bereken

\(\frac{-4-9i}{3+4i}\)

\(\frac{-4-9i}{3+4i}= \frac{-4-9i}{3+4i} \cdot \frac{3-4i}{3-4i} = \frac{-12+16i -27 i+36i^2 }{(3)^2-(4i)^2} = \frac{-12+16i -27 i-36}{9 + 16} = \frac{-48-11i }{25} = \frac{-48}{25} + \frac{-11}{25}i \)