Vermenigvuldigen en delen (a+bi)

Bereken

\(\frac{-8-10i}{-3+8i}\)

\(\frac{-8-10i}{-3+8i}= \frac{-8-10i}{-3+8i} \cdot \frac{-3-8i}{-3-8i} = \frac{24+64i +30 i+80i^2 }{(-3)^2-(8i)^2} = \frac{24+64i +30 i-80}{9 + 64} = \frac{-56+94i }{73} = \frac{-56}{73} - \frac{-94}{73}i \)