Wiskunde

\( a = \sqrt{10^2+7^2} \approx 12{,}207 \text{ (Pythagoras)} \\ \text{sin}(B)=\frac{10}{12{,}207} \Leftrightarrow B = \text{arcsin}(\frac{10}{12{,}206555615734}) \approx 55{,}008=55^\circ 0' 28{,}7" \text{ (Formule sinus)}\\ \text{sin}(C)=\frac{7}{12{,}207} \Leftrightarrow C = \text{arcsin}(\frac{7}{12{,}206555615734}) \approx 34{,}992=34^\circ 59' 31{,}3" \text{ (Formule sinus)}\\ -----alternatief----\\ \text{tan}(B)=\frac{10}{7} \Leftrightarrow B = \text{arctan}(\frac{10}{7})\approx 55{,}008=55^\circ 0' 28{,}7" \text{ (Formule tangens)}\\ \text{tan}(C)=\frac{7}{10} \Leftrightarrow C = \text{arctan}(\frac{7}{10})\approx 34{,}992=34^\circ 59' 31{,}3" \text{ (Formule tangens)}\\ -----controle-----\\ B + C = 90^\circ \Leftrightarrow 55^\circ 0' 28{,}7"+34^\circ 59' 31{,}3" = 90^\circ \text{(Complementaire hoeken)}\)

Goniometrie