Wiskunde

\( a = \sqrt{8^2+16^2} \approx 17{,}889 \text{ (Pythagoras)} \\ \text{sin}(B)=\frac{8}{17{,}889} \Leftrightarrow B = \text{arcsin}(\frac{8}{17{,}888543819998}) \approx 26{,}565=26^\circ 33' 54{,}2" \text{ (Formule sinus)}\\ \text{sin}(C)=\frac{16}{17{,}889} \Leftrightarrow C = \text{arcsin}(\frac{16}{17{,}888543819998}) \approx 63{,}435=63^\circ 26' 5{,}8" \text{ (Formule sinus)}\\ -----alternatief----\\ \text{tan}(B)=\frac{8}{16} \Leftrightarrow B = \text{arctan}(\frac{8}{16})\approx 26{,}565=26^\circ 33' 54{,}2" \text{ (Formule tangens)}\\ \text{tan}(C)=\frac{16}{8} \Leftrightarrow C = \text{arctan}(\frac{16}{8})\approx 63{,}435=63^\circ 26' 5{,}8" \text{ (Formule tangens)}\\ -----controle-----\\ B + C = 90^\circ \Leftrightarrow 26^\circ 33' 54{,}2"+63^\circ 26' 5{,}8" = 90^\circ \text{(Complementaire hoeken)}\)

Pythagoras, sin, cos, tan