Wiskunde

\( a = \sqrt{14^2+4^2} \approx 14{,}56 \text{ (Pythagoras)} \\ \text{sin}(B)=\frac{14}{14{,}56} \Leftrightarrow B = \text{arcsin}(\frac{14}{14{,}560219778561}) \approx 74{,}055=74^\circ 3' 16{,}6" \text{ (Formule sinus)}\\ \text{sin}(C)=\frac{4}{14{,}56} \Leftrightarrow C = \text{arcsin}(\frac{4}{14{,}560219778561}) \approx 15{,}945=15^\circ 56' 43{,}4" \text{ (Formule sinus)}\\ -----alternatief----\\ \text{tan}(B)=\frac{14}{4} \Leftrightarrow B = \text{arctan}(\frac{14}{4})\approx 74{,}055=74^\circ 3' 16{,}6" \text{ (Formule tangens)}\\ \text{tan}(C)=\frac{4}{14} \Leftrightarrow C = \text{arctan}(\frac{4}{14})\approx 15{,}945=15^\circ 56' 43{,}4" \text{ (Formule tangens)}\\ -----controle-----\\ B + C = 90^\circ \Leftrightarrow 74^\circ 3' 16{,}6"+15^\circ 56' 43{,}4" = 90^\circ \text{(Complementaire hoeken)}\)

Pythagoras, sin, cos, tan