Substitutie
\(\left\{\begin{matrix}-x-5y=40\\-6x-3y=-3\end{matrix}\right.\)
\(\left\{\begin{matrix}-x-5y=40\\-6x-3y=-3\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}-5y-40=x\\-6x-3y=-3\end{matrix}\right.\text{(Afzonderen onbekende met coëff. 1)}\\ \Leftrightarrow \left\{\begin{matrix}x=-5y-40\\ -6.\left(-5y-40\right)-3y=-3\end{matrix}\right.\text{(Substitutie!)}\\ \Leftrightarrow \left\{\begin{matrix}x=-5y-40\\ 30y+240-3y=-3\end{matrix}\right.\text{(Distributie)}\\ \Leftrightarrow \left\{\begin{matrix}x=-5y-40\\ 27y=-3-240=-243\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x=-5y-40\\ y=\frac{-243}{27}=-9\end{matrix}\right.\\ \Leftrightarrow \left\{\begin{matrix}x=-5.(-9)-40=5\\ y=-9\end{matrix}\right.\\ \qquad V=\{(5,-9)\}\)
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wiskundeoefeningen.be 2026-02-17 21:56:42 Een site van Busleyden Atheneum Mechelen