Vgln. eerste graad (reeks 2)

Bepaal de waarde van x. Meerdere manieren van oplossen mogelijk

\(15x+9=4+7x\)

\(\begin{align} & 15x \color{red}{+9}& = & 4 \color{red}{ +7x } \\\Leftrightarrow & 15x \color{red}{+9}\color{blue}{-9-7x } & = & 4 \color{red}{ +7x }\color{blue}{-9-7x } \\\Leftrightarrow & 15x \color{blue}{-7x } & = & 4 \color{blue}{-9} \\\Leftrightarrow &8x & = &-5\\\Leftrightarrow & \color{red}{8}x & = &-5\\\Leftrightarrow & \frac{\color{red}{8}x}{ \color{blue}{ 8}} & = & \frac{-5}{8} \\\Leftrightarrow & \color{green}{ x = \frac{-5}{8} } & & \\ & V = \left\{ \frac{-5}{8} \right\} & \\\end{align}\)