Vgln. eerste graad (reeks 2)

Bepaal de waarde van x. Meerdere manieren van oplossen mogelijk

\(15x-3=-1+11x\)

\(\begin{align} & 15x \color{red}{-3}& = & -1 \color{red}{ +11x } \\\Leftrightarrow & 15x \color{red}{-3}\color{blue}{+3-11x } & = & -1 \color{red}{ +11x }\color{blue}{+3-11x } \\\Leftrightarrow & 15x \color{blue}{-11x } & = & -1 \color{blue}{+3} \\\Leftrightarrow &4x & = &2\\\Leftrightarrow & \color{red}{4}x & = &2\\\Leftrightarrow & \frac{\color{red}{4}x}{ \color{blue}{ 4}} & = & \frac{2}{4} \\\Leftrightarrow & \color{green}{ x = \frac{1}{2} } & & \\ & V = \left\{ \frac{1}{2} \right\} & \\\end{align}\)