Vgln. eerste graad (reeks 2)

Bepaal de waarde van x. Meerdere manieren van oplossen mogelijk

\(x-7=-12+10x\)

\(\begin{align} & x \color{red}{-7}& = & -12 \color{red}{ +10x } \\\Leftrightarrow & x \color{red}{-7}\color{blue}{+7-10x } & = & -12 \color{red}{ +10x }\color{blue}{+7-10x } \\\Leftrightarrow & x \color{blue}{-10x } & = & -12 \color{blue}{+7} \\\Leftrightarrow &-9x & = &-5\\\Leftrightarrow & \color{red}{-9}x & = &-5\\\Leftrightarrow & \frac{\color{red}{-9}x}{ \color{blue}{ -9}} & = & \frac{-5}{-9} \\\Leftrightarrow & \color{green}{ x = \frac{5}{9} } & & \\ & V = \left\{ \frac{5}{9} \right\} & \\\end{align}\)