Vgln. eerste graad

Bepaal de waarde x. Bij wiskundetaal en vraagstukken, gebruik x om op te lossen.

\(7(5x+\frac{4}{3})=-6x+\frac{7}{10}\)

\(\text{(1) Haakjes (2) Breuken weg (3) + - (4) . /} \\ \begin{align} & \color{red}{7} (5x+\frac{4}{3})& = & -6x+\frac{7}{10} \\\Leftrightarrow & 35x+\frac{28}{3}& = & -6x+\frac{7}{10} \\ & & & \text{kgv van noemers 3 en 10 is 30} \\\Leftrightarrow & \color{blue}{30} .(\frac{1050}{ \color{blue}{30} }x+ \frac{280}{ \color{blue}{30} })& = & (\frac{-180}{ \color{blue}{30} }x+ \frac{21}{ \color{blue}{30} }). \color{blue}{30} \\\Leftrightarrow & 1050x \color{red}{+280} & = & \color{red}{-180x} +21 \\\Leftrightarrow & 1050x \color{red}{+280} \color{blue}{-280} \color{blue}{+180x} & = & \color{red}{-180x} +21 \color{blue}{+180x} \color{blue}{-280} \\\Leftrightarrow & 1050x+180x& = & 21-280 \\\Leftrightarrow & \color{red}{1230} x& = & -259 \\\Leftrightarrow & x = \frac{-259}{1230} & & \\ & V = \left\{ \frac{-259}{1230} \right\} & \\\end{align}\)