Los op. Vermijd indien mogelijk het gebruik van de discriminant.
\(8x^2+\frac{25}{6}x+\frac{1}{2}=0\)
\(8x^2+\frac{25}{6}x+\frac{1}{2}=0\\
\Leftrightarrow \color{red}{6.} \left(8x^2+\frac{25}{6}x+\frac{1}{2}\right)=0 \color{red}{.6} \\
\Leftrightarrow 48x^2+25x+3=0 \\\text{We zoeken de oplossingen van } \color{blue}{48x^2+25x+3=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (25)^2-4.48.3 & &\\
& = 625-576 & & \\
& = 49 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-25-\sqrt49}{2.48} & & = \frac{-25+\sqrt49}{2.48} \\
& = \frac{-32}{96} & & = \frac{-18}{96} \\
& = \frac{-1}{3} & & = \frac{-3}{16} \\ \\ V &= \Big\{ \frac{-1}{3} ; \frac{-3}{16} \Big\} & &\end{align} \\ -----------------\)