Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
\(-(10-28x)=-8x^2-(12-11x)\)
\(-(10-28x)=-8x^2-(12-11x) \\
\Leftrightarrow -10+28x=-8x^2-12+11x \\
\Leftrightarrow 8x^2+17x+2=0 \\\text{We zoeken de oplossingen van } \color{blue}{8x^2+17x+2=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (17)^2-4.8.2 & &\\
& = 289-64 & & \\
& = 225 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-17-\sqrt225}{2.8} & & = \frac{-17+\sqrt225}{2.8} \\
& = \frac{-32}{16} & & = \frac{-2}{16} \\
& = -2 & & = \frac{-1}{8} \\ \\ V &= \Big\{ -2 ; \frac{-1}{8} \Big\} & &\end{align} \\ -----------------\)