Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
\(4x^2+\frac{15}{4}x-\frac{1}{4}=0\)
\(4x^2+\frac{15}{4}x-\frac{1}{4}=0\\
\Leftrightarrow \color{red}{4.} \left(4x^2+\frac{15}{4}x-\frac{1}{4}\right)=0 \color{red}{.4} \\
\Leftrightarrow 16x^2+15x-1=0 \\\text{We zoeken de oplossingen van } \color{blue}{16x^2+15x-1=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (15)^2-4.16.(-1) & &\\
& = 225+64 & & \\
& = 289 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-15-\sqrt289}{2.16} & & = \frac{-15+\sqrt289}{2.16} \\
& = \frac{-32}{32} & & = \frac{2}{32} \\
& = -1 & & = \frac{1}{16} \\ \\ V &= \Big\{ -1 ; \frac{1}{16} \Big\} & &\end{align} \\ -----------------\)