Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
\(-(12-24x)=-x^2-(120-3x)\)
\(-(12-24x)=-x^2-(120-3x) \\
\Leftrightarrow -12+24x=-x^2-120+3x \\
\Leftrightarrow x^2+21x+108=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+21x+108=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (21)^2-4.1.108 & &\\
& = 441-432 & & \\
& = 9 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-21-\sqrt9}{2.1} & & = \frac{-21+\sqrt9}{2.1} \\
& = \frac{-24}{2} & & = \frac{-18}{2} \\
& = -12 & & = -9 \\ \\ V &= \Big\{ -12 ; -9 \Big\} & &\end{align} \\ -----------------\)