Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-11}{-13}\right)-\left(\frac{-12}{5}\right)\)
2. \(-\left(\frac{-10}{-7}\right)-\left(\frac{-2}{3}\right)\)
3. \(+\left(\frac{-10}{-7}\right)+\left(\frac{9}{-7}\right)\)
4. \(-\left(\frac{-2}{7}\right)+\left(\frac{13}{-4}\right)\)
5. \(-\left(\frac{3}{14}\right)-\left(\frac{-5}{-6}\right)\)
6. \(-\left(\frac{9}{2}\right)+\left(\frac{-11}{-3}\right)\)
7. \(+\left(\frac{3}{4}\right)+\left(\frac{3}{-7}\right)\)
8. \(+\left(\frac{4}{11}\right)+\left(\frac{4}{13}\right)\)
9. \(-\left(\frac{13}{5}\right)+\left(\frac{11}{-3}\right)\)
10. \(+\left(\frac{14}{-11}\right)+\left(\frac{-10}{-3}\right)\)
11. \(-\left(\frac{3}{-7}\right)+\left(\frac{12}{-7}\right)\)
12. \(-\left(\frac{-15}{-7}\right)+\left(\frac{-4}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-11}{-13}\right)-\left(\frac{-12}{5}\right)\\= \frac{-11}{13}+\frac{12}{5}\\=\frac{-55}{65}+\frac{156}{65}\\=\frac{-55+156}{65}\\=\frac{101}{65}\)
2. \(-\left(\frac{-10}{-7}\right)-\left(\frac{-2}{3}\right)\\= \frac{-10}{7}+\frac{2}{3}\\=\frac{-30}{21}+\frac{14}{21}\\=\frac{-30+14}{21}\\=\frac{-16}{21}\)
3. \(+\left(\frac{-10}{-7}\right)+\left(\frac{9}{-7}\right)\\= \frac{10}{7}-\frac{9}{7}\\=\frac{10-9}{7}\\=\frac{1}{7}\)
4. \(-\left(\frac{-2}{7}\right)+\left(\frac{13}{-4}\right)\\= \frac{2}{7}-\frac{13}{4}\\=\frac{8}{28}-\frac{91}{28}\\=\frac{8-91}{28}\\=\frac{-83}{28}\)
5. \(-\left(\frac{3}{14}\right)-\left(\frac{-5}{-6}\right)\\= \frac{-3}{14}-\frac{5}{6}\\=\frac{-9}{42}-\frac{35}{42}\\=\frac{-9-35}{42}\\=\frac{-44}{42}\\=\frac{-22}{21}\)
6. \(-\left(\frac{9}{2}\right)+\left(\frac{-11}{-3}\right)\\= \frac{-9}{2}+\frac{11}{3}\\=\frac{-27}{6}+\frac{22}{6}\\=\frac{-27+22}{6}\\=\frac{-5}{6}\)
7. \(+\left(\frac{3}{4}\right)+\left(\frac{3}{-7}\right)\\= \frac{3}{4}-\frac{3}{7}\\=\frac{21}{28}-\frac{12}{28}\\=\frac{21-12}{28}\\=\frac{9}{28}\)
8. \(+\left(\frac{4}{11}\right)+\left(\frac{4}{13}\right)\\= \frac{4}{11}+\frac{4}{13}\\=\frac{52}{143}+\frac{44}{143}\\=\frac{52+44}{143}\\=\frac{96}{143}\)
9. \(-\left(\frac{13}{5}\right)+\left(\frac{11}{-3}\right)\\= \frac{-13}{5}-\frac{11}{3}\\=\frac{-39}{15}-\frac{55}{15}\\=\frac{-39-55}{15}\\=\frac{-94}{15}\)
10. \(+\left(\frac{14}{-11}\right)+\left(\frac{-10}{-3}\right)\\= \frac{-14}{11}+\frac{10}{3}\\=\frac{-42}{33}+\frac{110}{33}\\=\frac{-42+110}{33}\\=\frac{68}{33}\)
11. \(-\left(\frac{3}{-7}\right)+\left(\frac{12}{-7}\right)\\= \frac{3}{7}-\frac{12}{7}\\=\frac{3-12}{7}\\=\frac{-9}{7}\)
12. \(-\left(\frac{-15}{-7}\right)+\left(\frac{-4}{-13}\right)\\= \frac{-15}{7}+\frac{4}{13}\\=\frac{-195}{91}+\frac{28}{91}\\=\frac{-195+28}{91}\\=\frac{-167}{91}\)