Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{6}{13}\right)+\left(\frac{-11}{-12}\right)\)
2. \(-\left(\frac{-11}{-13}\right)-\left(\frac{10}{11}\right)\)
3. \(+\left(\frac{10}{3}\right)-\left(\frac{8}{-3}\right)\)
4. \(-\left(\frac{9}{-2}\right)+\left(\frac{4}{-3}\right)\)
5. \(+\left(\frac{9}{-13}\right)+\left(\frac{-9}{-10}\right)\)
6. \(+\left(\frac{-4}{-13}\right)-\left(\frac{12}{-11}\right)\)
7. \(-\left(\frac{-9}{-7}\right)+\left(\frac{-7}{10}\right)\)
8. \(-\left(\frac{-6}{-11}\right)+\left(\frac{-4}{3}\right)\)
9. \(+\left(\frac{5}{11}\right)-\left(\frac{2}{-3}\right)\)
10. \(+\left(\frac{-10}{-7}\right)-\left(\frac{5}{-7}\right)\)
11. \(-\left(\frac{7}{8}\right)-\left(\frac{15}{-2}\right)\)
12. \(-\left(\frac{2}{-3}\right)+\left(\frac{3}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{6}{13}\right)+\left(\frac{-11}{-12}\right)\\= \frac{6}{13}+\frac{11}{12}\\=\frac{72}{156}+\frac{143}{156}\\=\frac{72+143}{156}\\=\frac{215}{156}\)
2. \(-\left(\frac{-11}{-13}\right)-\left(\frac{10}{11}\right)\\= \frac{-11}{13}-\frac{10}{11}\\=\frac{-121}{143}-\frac{130}{143}\\=\frac{-121-130}{143}\\=\frac{-251}{143}\)
3. \(+\left(\frac{10}{3}\right)-\left(\frac{8}{-3}\right)\\= \frac{10}{3}+\frac{8}{3}\\=\frac{10+8}{3}\\=\frac{18}{3}\\=\frac{6}{1}\)
4. \(-\left(\frac{9}{-2}\right)+\left(\frac{4}{-3}\right)\\= \frac{9}{2}-\frac{4}{3}\\=\frac{27}{6}-\frac{8}{6}\\=\frac{27-8}{6}\\=\frac{19}{6}\)
5. \(+\left(\frac{9}{-13}\right)+\left(\frac{-9}{-10}\right)\\= \frac{-9}{13}+\frac{9}{10}\\=\frac{-90}{130}+\frac{117}{130}\\=\frac{-90+117}{130}\\=\frac{27}{130}\)
6. \(+\left(\frac{-4}{-13}\right)-\left(\frac{12}{-11}\right)\\= \frac{4}{13}+\frac{12}{11}\\=\frac{44}{143}+\frac{156}{143}\\=\frac{44+156}{143}\\=\frac{200}{143}\)
7. \(-\left(\frac{-9}{-7}\right)+\left(\frac{-7}{10}\right)\\= \frac{-9}{7}-\frac{7}{10}\\=\frac{-90}{70}-\frac{49}{70}\\=\frac{-90-49}{70}\\=\frac{-139}{70}\)
8. \(-\left(\frac{-6}{-11}\right)+\left(\frac{-4}{3}\right)\\= \frac{-6}{11}-\frac{4}{3}\\=\frac{-18}{33}-\frac{44}{33}\\=\frac{-18-44}{33}\\=\frac{-62}{33}\)
9. \(+\left(\frac{5}{11}\right)-\left(\frac{2}{-3}\right)\\= \frac{5}{11}+\frac{2}{3}\\=\frac{15}{33}+\frac{22}{33}\\=\frac{15+22}{33}\\=\frac{37}{33}\)
10. \(+\left(\frac{-10}{-7}\right)-\left(\frac{5}{-7}\right)\\= \frac{10}{7}+\frac{5}{7}\\=\frac{10+5}{7}\\=\frac{15}{7}\)
11. \(-\left(\frac{7}{8}\right)-\left(\frac{15}{-2}\right)\\= \frac{-7}{8}+\frac{15}{2}\\=\frac{-7+15}{8}\\=\frac{8}{8}\\=\frac{1}{1}\)
12. \(-\left(\frac{2}{-3}\right)+\left(\frac{3}{-13}\right)\\= \frac{2}{3}-\frac{3}{13}\\=\frac{26}{39}-\frac{9}{39}\\=\frac{26-9}{39}\\=\frac{17}{39}\)