Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-12}{7}\right)+\left(\frac{4}{3}\right)\)
2. \(+\left(\frac{-2}{5}\right)+\left(\frac{13}{-4}\right)\)
3. \(-\left(\frac{-11}{13}\right)+\left(\frac{-15}{-4}\right)\)
4. \(-\left(\frac{14}{9}\right)+\left(\frac{2}{-11}\right)\)
5. \(-\left(\frac{-3}{-11}\right)+\left(\frac{-6}{-5}\right)\)
6. \(+\left(\frac{-3}{4}\right)+\left(\frac{13}{-2}\right)\)
7. \(+\left(\frac{-5}{-11}\right)-\left(\frac{-2}{-13}\right)\)
8. \(-\left(\frac{7}{-5}\right)+\left(\frac{-13}{-12}\right)\)
9. \(+\left(\frac{13}{11}\right)-\left(\frac{-10}{3}\right)\)
10. \(-\left(\frac{-11}{-13}\right)+\left(\frac{12}{5}\right)\)
11. \(-\left(\frac{-11}{-4}\right)+\left(\frac{-15}{-11}\right)\)
12. \(-\left(\frac{10}{-13}\right)-\left(\frac{-10}{-9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-12}{7}\right)+\left(\frac{4}{3}\right)\\= \frac{-12}{7}+\frac{4}{3}\\=\frac{-36}{21}+\frac{28}{21}\\=\frac{-36+28}{21}\\=\frac{-8}{21}\)
2. \(+\left(\frac{-2}{5}\right)+\left(\frac{13}{-4}\right)\\= \frac{-2}{5}-\frac{13}{4}\\=\frac{-8}{20}-\frac{65}{20}\\=\frac{-8-65}{20}\\=\frac{-73}{20}\)
3. \(-\left(\frac{-11}{13}\right)+\left(\frac{-15}{-4}\right)\\= \frac{11}{13}+\frac{15}{4}\\=\frac{44}{52}+\frac{195}{52}\\=\frac{44+195}{52}\\=\frac{239}{52}\)
4. \(-\left(\frac{14}{9}\right)+\left(\frac{2}{-11}\right)\\= \frac{-14}{9}-\frac{2}{11}\\=\frac{-154}{99}-\frac{18}{99}\\=\frac{-154-18}{99}\\=\frac{-172}{99}\)
5. \(-\left(\frac{-3}{-11}\right)+\left(\frac{-6}{-5}\right)\\= \frac{-3}{11}+\frac{6}{5}\\=\frac{-15}{55}+\frac{66}{55}\\=\frac{-15+66}{55}\\=\frac{51}{55}\)
6. \(+\left(\frac{-3}{4}\right)+\left(\frac{13}{-2}\right)\\= \frac{-3}{4}-\frac{13}{2}\\=\frac{-3-13}{4}\\=\frac{-16}{4}\\=\frac{-4}{1}\)
7. \(+\left(\frac{-5}{-11}\right)-\left(\frac{-2}{-13}\right)\\= \frac{5}{11}-\frac{2}{13}\\=\frac{65}{143}-\frac{22}{143}\\=\frac{65-22}{143}\\=\frac{43}{143}\)
8. \(-\left(\frac{7}{-5}\right)+\left(\frac{-13}{-12}\right)\\= \frac{7}{5}+\frac{13}{12}\\=\frac{84}{60}+\frac{65}{60}\\=\frac{84+65}{60}\\=\frac{149}{60}\)
9. \(+\left(\frac{13}{11}\right)-\left(\frac{-10}{3}\right)\\= \frac{13}{11}+\frac{10}{3}\\=\frac{39}{33}+\frac{110}{33}\\=\frac{39+110}{33}\\=\frac{149}{33}\)
10. \(-\left(\frac{-11}{-13}\right)+\left(\frac{12}{5}\right)\\= \frac{-11}{13}+\frac{12}{5}\\=\frac{-55}{65}+\frac{156}{65}\\=\frac{-55+156}{65}\\=\frac{101}{65}\)
11. \(-\left(\frac{-11}{-4}\right)+\left(\frac{-15}{-11}\right)\\= \frac{-11}{4}+\frac{15}{11}\\=\frac{-121}{44}+\frac{60}{44}\\=\frac{-121+60}{44}\\=\frac{-61}{44}\)
12. \(-\left(\frac{10}{-13}\right)-\left(\frac{-10}{-9}\right)\\= \frac{10}{13}-\frac{10}{9}\\=\frac{90}{117}-\frac{130}{117}\\=\frac{90-130}{117}\\=\frac{-40}{117}\)