Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-12}{-7}\right)+\left(\frac{-6}{5}\right)\)
2. \(+\left(\frac{3}{4}\right)+\left(\frac{4}{5}\right)\)
3. \(+\left(\frac{-2}{-3}\right)+\left(\frac{-11}{3}\right)\)
4. \(-\left(\frac{2}{7}\right)+\left(\frac{-10}{-13}\right)\)
5. \(+\left(\frac{-15}{-13}\right)-\left(\frac{-15}{4}\right)\)
6. \(+\left(\frac{-2}{7}\right)-\left(\frac{-11}{10}\right)\)
7. \(-\left(\frac{14}{-13}\right)+\left(\frac{3}{5}\right)\)
8. \(+\left(\frac{13}{-4}\right)+\left(\frac{15}{13}\right)\)
9. \(-\left(\frac{4}{5}\right)+\left(\frac{-15}{7}\right)\)
10. \(-\left(\frac{2}{3}\right)+\left(\frac{9}{7}\right)\)
11. \(+\left(\frac{6}{5}\right)-\left(\frac{6}{5}\right)\)
12. \(+\left(\frac{13}{9}\right)+\left(\frac{-13}{4}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-12}{-7}\right)+\left(\frac{-6}{5}\right)\\= \frac{-12}{7}-\frac{6}{5}\\=\frac{-60}{35}-\frac{42}{35}\\=\frac{-60-42}{35}\\=\frac{-102}{35}\)
2. \(+\left(\frac{3}{4}\right)+\left(\frac{4}{5}\right)\\= \frac{3}{4}+\frac{4}{5}\\=\frac{15}{20}+\frac{16}{20}\\=\frac{15+16}{20}\\=\frac{31}{20}\)
3. \(+\left(\frac{-2}{-3}\right)+\left(\frac{-11}{3}\right)\\= \frac{2}{3}-\frac{11}{3}\\=\frac{2-11}{3}\\=\frac{-9}{3}\\=\frac{-3}{1}\)
4. \(-\left(\frac{2}{7}\right)+\left(\frac{-10}{-13}\right)\\= \frac{-2}{7}+\frac{10}{13}\\=\frac{-26}{91}+\frac{70}{91}\\=\frac{-26+70}{91}\\=\frac{44}{91}\)
5. \(+\left(\frac{-15}{-13}\right)-\left(\frac{-15}{4}\right)\\= \frac{15}{13}+\frac{15}{4}\\=\frac{60}{52}+\frac{195}{52}\\=\frac{60+195}{52}\\=\frac{255}{52}\)
6. \(+\left(\frac{-2}{7}\right)-\left(\frac{-11}{10}\right)\\= \frac{-2}{7}+\frac{11}{10}\\=\frac{-20}{70}+\frac{77}{70}\\=\frac{-20+77}{70}\\=\frac{57}{70}\)
7. \(-\left(\frac{14}{-13}\right)+\left(\frac{3}{5}\right)\\= \frac{14}{13}+\frac{3}{5}\\=\frac{70}{65}+\frac{39}{65}\\=\frac{70+39}{65}\\=\frac{109}{65}\)
8. \(+\left(\frac{13}{-4}\right)+\left(\frac{15}{13}\right)\\= \frac{-13}{4}+\frac{15}{13}\\=\frac{-169}{52}+\frac{60}{52}\\=\frac{-169+60}{52}\\=\frac{-109}{52}\)
9. \(-\left(\frac{4}{5}\right)+\left(\frac{-15}{7}\right)\\= \frac{-4}{5}-\frac{15}{7}\\=\frac{-28}{35}-\frac{75}{35}\\=\frac{-28-75}{35}\\=\frac{-103}{35}\)
10. \(-\left(\frac{2}{3}\right)+\left(\frac{9}{7}\right)\\= \frac{-2}{3}+\frac{9}{7}\\=\frac{-14}{21}+\frac{27}{21}\\=\frac{-14+27}{21}\\=\frac{13}{21}\)
11. \(+\left(\frac{6}{5}\right)-\left(\frac{6}{5}\right)\\= \frac{6}{5}-\frac{6}{5}\\=\frac{6-6}{5}\\=\frac{0}{5}\\=\frac{0}{1}\)
12. \(+\left(\frac{13}{9}\right)+\left(\frac{-13}{4}\right)\\= \frac{13}{9}-\frac{13}{4}\\=\frac{52}{36}-\frac{117}{36}\\=\frac{52-117}{36}\\=\frac{-65}{36}\)