Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{6}{-5}\right)-\left(\frac{15}{-7}\right)\)
2. \(+\left(\frac{-4}{-7}\right)-\left(\frac{-11}{9}\right)\)
3. \(-\left(\frac{-5}{-2}\right)-\left(\frac{-7}{-2}\right)\)
4. \(+\left(\frac{-2}{-9}\right)-\left(\frac{-5}{2}\right)\)
5. \(-\left(\frac{-15}{13}\right)-\left(\frac{12}{-5}\right)\)
6. \(-\left(\frac{-3}{-7}\right)-\left(\frac{11}{12}\right)\)
7. \(-\left(\frac{-8}{-3}\right)+\left(\frac{-3}{4}\right)\)
8. \(-\left(\frac{-5}{11}\right)-\left(\frac{10}{-7}\right)\)
9. \(-\left(\frac{-7}{-6}\right)+\left(\frac{3}{-8}\right)\)
10. \(+\left(\frac{6}{11}\right)-\left(\frac{-15}{7}\right)\)
11. \(-\left(\frac{-6}{5}\right)+\left(\frac{-4}{-3}\right)\)
12. \(-\left(\frac{-2}{-5}\right)+\left(\frac{-12}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{6}{-5}\right)-\left(\frac{15}{-7}\right)\\= \frac{-6}{5}+\frac{15}{7}\\=\frac{-42}{35}+\frac{75}{35}\\=\frac{-42+75}{35}\\=\frac{33}{35}\)
2. \(+\left(\frac{-4}{-7}\right)-\left(\frac{-11}{9}\right)\\= \frac{4}{7}+\frac{11}{9}\\=\frac{36}{63}+\frac{77}{63}\\=\frac{36+77}{63}\\=\frac{113}{63}\)
3. \(-\left(\frac{-5}{-2}\right)-\left(\frac{-7}{-2}\right)\\= \frac{-5}{2}-\frac{7}{2}\\=\frac{-5-7}{2}\\=\frac{-12}{2}\\=\frac{-6}{1}\)
4. \(+\left(\frac{-2}{-9}\right)-\left(\frac{-5}{2}\right)\\= \frac{2}{9}+\frac{5}{2}\\=\frac{4}{18}+\frac{45}{18}\\=\frac{4+45}{18}\\=\frac{49}{18}\)
5. \(-\left(\frac{-15}{13}\right)-\left(\frac{12}{-5}\right)\\= \frac{15}{13}+\frac{12}{5}\\=\frac{75}{65}+\frac{156}{65}\\=\frac{75+156}{65}\\=\frac{231}{65}\)
6. \(-\left(\frac{-3}{-7}\right)-\left(\frac{11}{12}\right)\\= \frac{-3}{7}-\frac{11}{12}\\=\frac{-36}{84}-\frac{77}{84}\\=\frac{-36-77}{84}\\=\frac{-113}{84}\)
7. \(-\left(\frac{-8}{-3}\right)+\left(\frac{-3}{4}\right)\\= \frac{-8}{3}-\frac{3}{4}\\=\frac{-32}{12}-\frac{9}{12}\\=\frac{-32-9}{12}\\=\frac{-41}{12}\)
8. \(-\left(\frac{-5}{11}\right)-\left(\frac{10}{-7}\right)\\= \frac{5}{11}+\frac{10}{7}\\=\frac{35}{77}+\frac{110}{77}\\=\frac{35+110}{77}\\=\frac{145}{77}\)
9. \(-\left(\frac{-7}{-6}\right)+\left(\frac{3}{-8}\right)\\= \frac{-7}{6}-\frac{3}{8}\\=\frac{-28}{24}-\frac{9}{24}\\=\frac{-28-9}{24}\\=\frac{-37}{24}\)
10. \(+\left(\frac{6}{11}\right)-\left(\frac{-15}{7}\right)\\= \frac{6}{11}+\frac{15}{7}\\=\frac{42}{77}+\frac{165}{77}\\=\frac{42+165}{77}\\=\frac{207}{77}\)
11. \(-\left(\frac{-6}{5}\right)+\left(\frac{-4}{-3}\right)\\= \frac{6}{5}+\frac{4}{3}\\=\frac{18}{15}+\frac{20}{15}\\=\frac{18+20}{15}\\=\frac{38}{15}\)
12. \(-\left(\frac{-2}{-5}\right)+\left(\frac{-12}{-11}\right)\\= \frac{-2}{5}+\frac{12}{11}\\=\frac{-22}{55}+\frac{60}{55}\\=\frac{-22+60}{55}\\=\frac{38}{55}\)