Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-3}{-10}\right)-\left(\frac{7}{11}\right)\)
2. \(+\left(\frac{6}{-11}\right)+\left(\frac{-6}{-7}\right)\)
3. \(-\left(\frac{3}{7}\right)+\left(\frac{-11}{-6}\right)\)
4. \(-\left(\frac{-3}{-8}\right)+\left(\frac{13}{-8}\right)\)
5. \(+\left(\frac{14}{3}\right)-\left(\frac{-9}{-4}\right)\)
6. \(+\left(\frac{4}{3}\right)-\left(\frac{-4}{9}\right)\)
7. \(-\left(\frac{-2}{3}\right)-\left(\frac{4}{-11}\right)\)
8. \(+\left(\frac{-12}{-5}\right)-\left(\frac{-11}{10}\right)\)
9. \(-\left(\frac{13}{-5}\right)+\left(\frac{-13}{-14}\right)\)
10. \(-\left(\frac{8}{3}\right)-\left(\frac{3}{13}\right)\)
11. \(+\left(\frac{9}{14}\right)+\left(\frac{9}{4}\right)\)
12. \(+\left(\frac{13}{-10}\right)-\left(\frac{3}{11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-3}{-10}\right)-\left(\frac{7}{11}\right)\\= \frac{-3}{10}-\frac{7}{11}\\=\frac{-33}{110}-\frac{70}{110}\\=\frac{-33-70}{110}\\=\frac{-103}{110}\)
2. \(+\left(\frac{6}{-11}\right)+\left(\frac{-6}{-7}\right)\\= \frac{-6}{11}+\frac{6}{7}\\=\frac{-42}{77}+\frac{66}{77}\\=\frac{-42+66}{77}\\=\frac{24}{77}\)
3. \(-\left(\frac{3}{7}\right)+\left(\frac{-11}{-6}\right)\\= \frac{-3}{7}+\frac{11}{6}\\=\frac{-18}{42}+\frac{77}{42}\\=\frac{-18+77}{42}\\=\frac{59}{42}\)
4. \(-\left(\frac{-3}{-8}\right)+\left(\frac{13}{-8}\right)\\= \frac{-3}{8}-\frac{13}{8}\\=\frac{-3-13}{8}\\=\frac{-16}{8}\\=\frac{-2}{1}\)
5. \(+\left(\frac{14}{3}\right)-\left(\frac{-9}{-4}\right)\\= \frac{14}{3}-\frac{9}{4}\\=\frac{56}{12}-\frac{27}{12}\\=\frac{56-27}{12}\\=\frac{29}{12}\)
6. \(+\left(\frac{4}{3}\right)-\left(\frac{-4}{9}\right)\\= \frac{4}{3}+\frac{4}{9}\\=\frac{12}{9}+\frac{4}{9}\\=\frac{12+4}{9}\\=\frac{16}{9}\)
7. \(-\left(\frac{-2}{3}\right)-\left(\frac{4}{-11}\right)\\= \frac{2}{3}+\frac{4}{11}\\=\frac{22}{33}+\frac{12}{33}\\=\frac{22+12}{33}\\=\frac{34}{33}\)
8. \(+\left(\frac{-12}{-5}\right)-\left(\frac{-11}{10}\right)\\= \frac{12}{5}+\frac{11}{10}\\=\frac{24}{10}+\frac{11}{10}\\=\frac{24+11}{10}\\=\frac{35}{10}\\=\frac{7}{2}\)
9. \(-\left(\frac{13}{-5}\right)+\left(\frac{-13}{-14}\right)\\= \frac{13}{5}+\frac{13}{14}\\=\frac{182}{70}+\frac{65}{70}\\=\frac{182+65}{70}\\=\frac{247}{70}\)
10. \(-\left(\frac{8}{3}\right)-\left(\frac{3}{13}\right)\\= \frac{-8}{3}-\frac{3}{13}\\=\frac{-104}{39}-\frac{9}{39}\\=\frac{-104-9}{39}\\=\frac{-113}{39}\)
11. \(+\left(\frac{9}{14}\right)+\left(\frac{9}{4}\right)\\= \frac{9}{14}+\frac{9}{4}\\=\frac{18}{28}+\frac{63}{28}\\=\frac{18+63}{28}\\=\frac{81}{28}\)
12. \(+\left(\frac{13}{-10}\right)-\left(\frac{3}{11}\right)\\= \frac{-13}{10}-\frac{3}{11}\\=\frac{-143}{110}-\frac{30}{110}\\=\frac{-143-30}{110}\\=\frac{-173}{110}\)