Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-10}{3}\right)+\left(\frac{-4}{3}\right)\)
2. \(-\left(\frac{9}{-8}\right)-\left(\frac{3}{2}\right)\)
3. \(+\left(\frac{10}{-7}\right)+\left(\frac{-9}{-2}\right)\)
4. \(-\left(\frac{-9}{-14}\right)+\left(\frac{8}{3}\right)\)
5. \(+\left(\frac{-9}{-10}\right)+\left(\frac{9}{8}\right)\)
6. \(+\left(\frac{-5}{-11}\right)+\left(\frac{15}{7}\right)\)
7. \(+\left(\frac{-6}{5}\right)+\left(\frac{-13}{14}\right)\)
8. \(+\left(\frac{-2}{-9}\right)-\left(\frac{-15}{-13}\right)\)
9. \(-\left(\frac{-11}{-12}\right)+\left(\frac{11}{6}\right)\)
10. \(-\left(\frac{11}{-2}\right)+\left(\frac{-4}{-9}\right)\)
11. \(-\left(\frac{-7}{4}\right)+\left(\frac{-7}{13}\right)\)
12. \(-\left(\frac{10}{3}\right)-\left(\frac{-12}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-10}{3}\right)+\left(\frac{-4}{3}\right)\\= \frac{-10}{3}-\frac{4}{3}\\=\frac{-10-4}{3}\\=\frac{-14}{3}\)
2. \(-\left(\frac{9}{-8}\right)-\left(\frac{3}{2}\right)\\= \frac{9}{8}-\frac{3}{2}\\=\frac{9-3}{8}\\=\frac{6}{8}\\=\frac{3}{4}\)
3. \(+\left(\frac{10}{-7}\right)+\left(\frac{-9}{-2}\right)\\= \frac{-10}{7}+\frac{9}{2}\\=\frac{-20}{14}+\frac{63}{14}\\=\frac{-20+63}{14}\\=\frac{43}{14}\)
4. \(-\left(\frac{-9}{-14}\right)+\left(\frac{8}{3}\right)\\= \frac{-9}{14}+\frac{8}{3}\\=\frac{-27}{42}+\frac{112}{42}\\=\frac{-27+112}{42}\\=\frac{85}{42}\)
5. \(+\left(\frac{-9}{-10}\right)+\left(\frac{9}{8}\right)\\= \frac{9}{10}+\frac{9}{8}\\=\frac{36}{40}+\frac{45}{40}\\=\frac{36+45}{40}\\=\frac{81}{40}\)
6. \(+\left(\frac{-5}{-11}\right)+\left(\frac{15}{7}\right)\\= \frac{5}{11}+\frac{15}{7}\\=\frac{35}{77}+\frac{165}{77}\\=\frac{35+165}{77}\\=\frac{200}{77}\)
7. \(+\left(\frac{-6}{5}\right)+\left(\frac{-13}{14}\right)\\= \frac{-6}{5}-\frac{13}{14}\\=\frac{-84}{70}-\frac{65}{70}\\=\frac{-84-65}{70}\\=\frac{-149}{70}\)
8. \(+\left(\frac{-2}{-9}\right)-\left(\frac{-15}{-13}\right)\\= \frac{2}{9}-\frac{15}{13}\\=\frac{26}{117}-\frac{135}{117}\\=\frac{26-135}{117}\\=\frac{-109}{117}\)
9. \(-\left(\frac{-11}{-12}\right)+\left(\frac{11}{6}\right)\\= \frac{-11}{12}+\frac{11}{6}\\=\frac{-11+11}{12}\\=\frac{0}{12}\\=\frac{0}{1}\)
10. \(-\left(\frac{11}{-2}\right)+\left(\frac{-4}{-9}\right)\\= \frac{11}{2}+\frac{4}{9}\\=\frac{99}{18}+\frac{8}{18}\\=\frac{99+8}{18}\\=\frac{107}{18}\)
11. \(-\left(\frac{-7}{4}\right)+\left(\frac{-7}{13}\right)\\= \frac{7}{4}-\frac{7}{13}\\=\frac{91}{52}-\frac{28}{52}\\=\frac{91-28}{52}\\=\frac{63}{52}\)
12. \(-\left(\frac{10}{3}\right)-\left(\frac{-12}{-7}\right)\\= \frac{-10}{3}-\frac{12}{7}\\=\frac{-70}{21}-\frac{36}{21}\\=\frac{-70-36}{21}\\=\frac{-106}{21}\)