Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{3}\right)+\left(\frac{-4}{5}\right)\)
2. \(+\left(\frac{-6}{5}\right)+\left(\frac{7}{2}\right)\)
3. \(-\left(\frac{14}{-9}\right)-\left(\frac{14}{-13}\right)\)
4. \(+\left(\frac{10}{-11}\right)+\left(\frac{-4}{-7}\right)\)
5. \(-\left(\frac{6}{7}\right)-\left(\frac{2}{-11}\right)\)
6. \(+\left(\frac{-5}{-13}\right)+\left(\frac{6}{5}\right)\)
7. \(+\left(\frac{-8}{-7}\right)-\left(\frac{-11}{2}\right)\)
8. \(-\left(\frac{5}{2}\right)+\left(\frac{6}{5}\right)\)
9. \(+\left(\frac{6}{5}\right)+\left(\frac{8}{11}\right)\)
10. \(-\left(\frac{5}{-7}\right)-\left(\frac{-13}{-8}\right)\)
11. \(-\left(\frac{2}{-7}\right)+\left(\frac{-2}{-11}\right)\)
12. \(+\left(\frac{15}{-14}\right)+\left(\frac{-10}{3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{10}{3}\right)+\left(\frac{-4}{5}\right)\\= \frac{10}{3}-\frac{4}{5}\\=\frac{50}{15}-\frac{12}{15}\\=\frac{50-12}{15}\\=\frac{38}{15}\)
2. \(+\left(\frac{-6}{5}\right)+\left(\frac{7}{2}\right)\\= \frac{-6}{5}+\frac{7}{2}\\=\frac{-12}{10}+\frac{35}{10}\\=\frac{-12+35}{10}\\=\frac{23}{10}\)
3. \(-\left(\frac{14}{-9}\right)-\left(\frac{14}{-13}\right)\\= \frac{14}{9}+\frac{14}{13}\\=\frac{182}{117}+\frac{126}{117}\\=\frac{182+126}{117}\\=\frac{308}{117}\)
4. \(+\left(\frac{10}{-11}\right)+\left(\frac{-4}{-7}\right)\\= \frac{-10}{11}+\frac{4}{7}\\=\frac{-70}{77}+\frac{44}{77}\\=\frac{-70+44}{77}\\=\frac{-26}{77}\)
5. \(-\left(\frac{6}{7}\right)-\left(\frac{2}{-11}\right)\\= \frac{-6}{7}+\frac{2}{11}\\=\frac{-66}{77}+\frac{14}{77}\\=\frac{-66+14}{77}\\=\frac{-52}{77}\)
6. \(+\left(\frac{-5}{-13}\right)+\left(\frac{6}{5}\right)\\= \frac{5}{13}+\frac{6}{5}\\=\frac{25}{65}+\frac{78}{65}\\=\frac{25+78}{65}\\=\frac{103}{65}\)
7. \(+\left(\frac{-8}{-7}\right)-\left(\frac{-11}{2}\right)\\= \frac{8}{7}+\frac{11}{2}\\=\frac{16}{14}+\frac{77}{14}\\=\frac{16+77}{14}\\=\frac{93}{14}\)
8. \(-\left(\frac{5}{2}\right)+\left(\frac{6}{5}\right)\\= \frac{-5}{2}+\frac{6}{5}\\=\frac{-25}{10}+\frac{12}{10}\\=\frac{-25+12}{10}\\=\frac{-13}{10}\)
9. \(+\left(\frac{6}{5}\right)+\left(\frac{8}{11}\right)\\= \frac{6}{5}+\frac{8}{11}\\=\frac{66}{55}+\frac{40}{55}\\=\frac{66+40}{55}\\=\frac{106}{55}\)
10. \(-\left(\frac{5}{-7}\right)-\left(\frac{-13}{-8}\right)\\= \frac{5}{7}-\frac{13}{8}\\=\frac{40}{56}-\frac{91}{56}\\=\frac{40-91}{56}\\=\frac{-51}{56}\)
11. \(-\left(\frac{2}{-7}\right)+\left(\frac{-2}{-11}\right)\\= \frac{2}{7}+\frac{2}{11}\\=\frac{22}{77}+\frac{14}{77}\\=\frac{22+14}{77}\\=\frac{36}{77}\)
12. \(+\left(\frac{15}{-14}\right)+\left(\frac{-10}{3}\right)\\= \frac{-15}{14}-\frac{10}{3}\\=\frac{-45}{42}-\frac{140}{42}\\=\frac{-45-140}{42}\\=\frac{-185}{42}\)