Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{9}{-11}\right)+\left(\frac{12}{-5}\right)\)
2. \(-\left(\frac{-8}{-7}\right)-\left(\frac{14}{-5}\right)\)
3. \(+\left(\frac{5}{-12}\right)-\left(\frac{7}{4}\right)\)
4. \(+\left(\frac{-3}{5}\right)+\left(\frac{-8}{11}\right)\)
5. \(+\left(\frac{-10}{9}\right)-\left(\frac{-14}{9}\right)\)
6. \(+\left(\frac{12}{-5}\right)-\left(\frac{-11}{-10}\right)\)
7. \(+\left(\frac{9}{-8}\right)+\left(\frac{-7}{-8}\right)\)
8. \(-\left(\frac{-12}{5}\right)-\left(\frac{7}{4}\right)\)
9. \(+\left(\frac{13}{-4}\right)-\left(\frac{6}{-11}\right)\)
10. \(+\left(\frac{-4}{3}\right)-\left(\frac{-10}{3}\right)\)
11. \(+\left(\frac{-13}{-4}\right)+\left(\frac{11}{-8}\right)\)
12. \(-\left(\frac{10}{3}\right)+\left(\frac{4}{9}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{9}{-11}\right)+\left(\frac{12}{-5}\right)\\= \frac{-9}{11}-\frac{12}{5}\\=\frac{-45}{55}-\frac{132}{55}\\=\frac{-45-132}{55}\\=\frac{-177}{55}\)
2. \(-\left(\frac{-8}{-7}\right)-\left(\frac{14}{-5}\right)\\= \frac{-8}{7}+\frac{14}{5}\\=\frac{-40}{35}+\frac{98}{35}\\=\frac{-40+98}{35}\\=\frac{58}{35}\)
3. \(+\left(\frac{5}{-12}\right)-\left(\frac{7}{4}\right)\\= \frac{-5}{12}-\frac{7}{4}\\=\frac{-5-7}{12}\\=\frac{-12}{12}\\=\frac{-1}{1}\)
4. \(+\left(\frac{-3}{5}\right)+\left(\frac{-8}{11}\right)\\= \frac{-3}{5}-\frac{8}{11}\\=\frac{-33}{55}-\frac{40}{55}\\=\frac{-33-40}{55}\\=\frac{-73}{55}\)
5. \(+\left(\frac{-10}{9}\right)-\left(\frac{-14}{9}\right)\\= \frac{-10}{9}+\frac{14}{9}\\=\frac{-10+14}{9}\\=\frac{4}{9}\)
6. \(+\left(\frac{12}{-5}\right)-\left(\frac{-11}{-10}\right)\\= \frac{-12}{5}-\frac{11}{10}\\=\frac{-24}{10}-\frac{11}{10}\\=\frac{-24-11}{10}\\=\frac{-35}{10}\\=\frac{-7}{2}\)
7. \(+\left(\frac{9}{-8}\right)+\left(\frac{-7}{-8}\right)\\= \frac{-9}{8}+\frac{7}{8}\\=\frac{-9+7}{8}\\=\frac{-2}{8}\\=\frac{-1}{4}\)
8. \(-\left(\frac{-12}{5}\right)-\left(\frac{7}{4}\right)\\= \frac{12}{5}-\frac{7}{4}\\=\frac{48}{20}-\frac{35}{20}\\=\frac{48-35}{20}\\=\frac{13}{20}\)
9. \(+\left(\frac{13}{-4}\right)-\left(\frac{6}{-11}\right)\\= \frac{-13}{4}+\frac{6}{11}\\=\frac{-143}{44}+\frac{24}{44}\\=\frac{-143+24}{44}\\=\frac{-119}{44}\)
10. \(+\left(\frac{-4}{3}\right)-\left(\frac{-10}{3}\right)\\= \frac{-4}{3}+\frac{10}{3}\\=\frac{-4+10}{3}\\=\frac{6}{3}\\=\frac{2}{1}\)
11. \(+\left(\frac{-13}{-4}\right)+\left(\frac{11}{-8}\right)\\= \frac{13}{4}-\frac{11}{8}\\=\frac{26}{8}-\frac{11}{8}\\=\frac{26-11}{8}\\=\frac{15}{8}\)
12. \(-\left(\frac{10}{3}\right)+\left(\frac{4}{9}\right)\\= \frac{-10}{3}+\frac{4}{9}\\=\frac{-30}{9}+\frac{4}{9}\\=\frac{-30+4}{9}\\=\frac{-26}{9}\)