Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{3}{-4}\right)+\left(\frac{-11}{3}\right)\)
2. \(-\left(\frac{-10}{-7}\right)-\left(\frac{-7}{13}\right)\)
3. \(+\left(\frac{-10}{7}\right)-\left(\frac{-13}{-6}\right)\)
4. \(+\left(\frac{-5}{13}\right)+\left(\frac{10}{-3}\right)\)
5. \(+\left(\frac{13}{-14}\right)+\left(\frac{-14}{-9}\right)\)
6. \(-\left(\frac{-3}{11}\right)-\left(\frac{3}{11}\right)\)
7. \(+\left(\frac{5}{-11}\right)-\left(\frac{-6}{13}\right)\)
8. \(+\left(\frac{-11}{5}\right)+\left(\frac{5}{4}\right)\)
9. \(-\left(\frac{-11}{-7}\right)-\left(\frac{13}{10}\right)\)
10. \(+\left(\frac{15}{-4}\right)-\left(\frac{-7}{-8}\right)\)
11. \(+\left(\frac{-11}{-6}\right)+\left(\frac{-3}{7}\right)\)
12. \(-\left(\frac{-8}{-3}\right)-\left(\frac{4}{3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{3}{-4}\right)+\left(\frac{-11}{3}\right)\\= \frac{3}{4}-\frac{11}{3}\\=\frac{9}{12}-\frac{44}{12}\\=\frac{9-44}{12}\\=\frac{-35}{12}\)
2. \(-\left(\frac{-10}{-7}\right)-\left(\frac{-7}{13}\right)\\= \frac{-10}{7}+\frac{7}{13}\\=\frac{-130}{91}+\frac{49}{91}\\=\frac{-130+49}{91}\\=\frac{-81}{91}\)
3. \(+\left(\frac{-10}{7}\right)-\left(\frac{-13}{-6}\right)\\= \frac{-10}{7}-\frac{13}{6}\\=\frac{-60}{42}-\frac{91}{42}\\=\frac{-60-91}{42}\\=\frac{-151}{42}\)
4. \(+\left(\frac{-5}{13}\right)+\left(\frac{10}{-3}\right)\\= \frac{-5}{13}-\frac{10}{3}\\=\frac{-15}{39}-\frac{130}{39}\\=\frac{-15-130}{39}\\=\frac{-145}{39}\)
5. \(+\left(\frac{13}{-14}\right)+\left(\frac{-14}{-9}\right)\\= \frac{-13}{14}+\frac{14}{9}\\=\frac{-117}{126}+\frac{196}{126}\\=\frac{-117+196}{126}\\=\frac{79}{126}\)
6. \(-\left(\frac{-3}{11}\right)-\left(\frac{3}{11}\right)\\= \frac{3}{11}-\frac{3}{11}\\=\frac{3-3}{11}\\=\frac{0}{11}\\=\frac{0}{1}\)
7. \(+\left(\frac{5}{-11}\right)-\left(\frac{-6}{13}\right)\\= \frac{-5}{11}+\frac{6}{13}\\=\frac{-65}{143}+\frac{66}{143}\\=\frac{-65+66}{143}\\=\frac{1}{143}\)
8. \(+\left(\frac{-11}{5}\right)+\left(\frac{5}{4}\right)\\= \frac{-11}{5}+\frac{5}{4}\\=\frac{-44}{20}+\frac{25}{20}\\=\frac{-44+25}{20}\\=\frac{-19}{20}\)
9. \(-\left(\frac{-11}{-7}\right)-\left(\frac{13}{10}\right)\\= \frac{-11}{7}-\frac{13}{10}\\=\frac{-110}{70}-\frac{91}{70}\\=\frac{-110-91}{70}\\=\frac{-201}{70}\)
10. \(+\left(\frac{15}{-4}\right)-\left(\frac{-7}{-8}\right)\\= \frac{-15}{4}-\frac{7}{8}\\=\frac{-30}{8}-\frac{7}{8}\\=\frac{-30-7}{8}\\=\frac{-37}{8}\)
11. \(+\left(\frac{-11}{-6}\right)+\left(\frac{-3}{7}\right)\\= \frac{11}{6}-\frac{3}{7}\\=\frac{77}{42}-\frac{18}{42}\\=\frac{77-18}{42}\\=\frac{59}{42}\)
12. \(-\left(\frac{-8}{-3}\right)-\left(\frac{4}{3}\right)\\= \frac{-8}{3}-\frac{4}{3}\\=\frac{-8-4}{3}\\=\frac{-12}{3}\\=\frac{-4}{1}\)