Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(-\left(\frac{-10}{11}\right)-\left(\frac{10}{3}\right)\)
  2. \(+\left(\frac{-14}{3}\right)+\left(\frac{-9}{8}\right)\)
  3. \(-\left(\frac{3}{13}\right)+\left(\frac{-10}{-3}\right)\)
  4. \(+\left(\frac{7}{-9}\right)-\left(\frac{-13}{-4}\right)\)
  5. \(-\left(\frac{-12}{-5}\right)-\left(\frac{6}{7}\right)\)
  6. \(+\left(\frac{5}{-14}\right)-\left(\frac{8}{9}\right)\)
  7. \(-\left(\frac{2}{3}\right)+\left(\frac{11}{10}\right)\)
  8. \(+\left(\frac{-11}{7}\right)-\left(\frac{11}{-5}\right)\)
  9. \(+\left(\frac{-3}{-7}\right)-\left(\frac{9}{-13}\right)\)
  10. \(-\left(\frac{-4}{-5}\right)+\left(\frac{-9}{-7}\right)\)
  11. \(-\left(\frac{-6}{11}\right)+\left(\frac{3}{8}\right)\)
  12. \(-\left(\frac{14}{3}\right)-\left(\frac{8}{7}\right)\)

Bereken

Verbetersleutel

  1. \(-\left(\frac{-10}{11}\right)-\left(\frac{10}{3}\right)\\= \frac{10}{11}-\frac{10}{3}\\=\frac{30}{33}-\frac{110}{33}\\=\frac{30-110}{33}\\=\frac{-80}{33}\)
  2. \(+\left(\frac{-14}{3}\right)+\left(\frac{-9}{8}\right)\\= \frac{-14}{3}-\frac{9}{8}\\=\frac{-112}{24}-\frac{27}{24}\\=\frac{-112-27}{24}\\=\frac{-139}{24}\)
  3. \(-\left(\frac{3}{13}\right)+\left(\frac{-10}{-3}\right)\\= \frac{-3}{13}+\frac{10}{3}\\=\frac{-9}{39}+\frac{130}{39}\\=\frac{-9+130}{39}\\=\frac{121}{39}\)
  4. \(+\left(\frac{7}{-9}\right)-\left(\frac{-13}{-4}\right)\\= \frac{-7}{9}-\frac{13}{4}\\=\frac{-28}{36}-\frac{117}{36}\\=\frac{-28-117}{36}\\=\frac{-145}{36}\)
  5. \(-\left(\frac{-12}{-5}\right)-\left(\frac{6}{7}\right)\\= \frac{-12}{5}-\frac{6}{7}\\=\frac{-84}{35}-\frac{30}{35}\\=\frac{-84-30}{35}\\=\frac{-114}{35}\)
  6. \(+\left(\frac{5}{-14}\right)-\left(\frac{8}{9}\right)\\= \frac{-5}{14}-\frac{8}{9}\\=\frac{-45}{126}-\frac{112}{126}\\=\frac{-45-112}{126}\\=\frac{-157}{126}\)
  7. \(-\left(\frac{2}{3}\right)+\left(\frac{11}{10}\right)\\= \frac{-2}{3}+\frac{11}{10}\\=\frac{-20}{30}+\frac{33}{30}\\=\frac{-20+33}{30}\\=\frac{13}{30}\)
  8. \(+\left(\frac{-11}{7}\right)-\left(\frac{11}{-5}\right)\\= \frac{-11}{7}+\frac{11}{5}\\=\frac{-55}{35}+\frac{77}{35}\\=\frac{-55+77}{35}\\=\frac{22}{35}\)
  9. \(+\left(\frac{-3}{-7}\right)-\left(\frac{9}{-13}\right)\\= \frac{3}{7}+\frac{9}{13}\\=\frac{39}{91}+\frac{63}{91}\\=\frac{39+63}{91}\\=\frac{102}{91}\)
  10. \(-\left(\frac{-4}{-5}\right)+\left(\frac{-9}{-7}\right)\\= \frac{-4}{5}+\frac{9}{7}\\=\frac{-28}{35}+\frac{45}{35}\\=\frac{-28+45}{35}\\=\frac{17}{35}\)
  11. \(-\left(\frac{-6}{11}\right)+\left(\frac{3}{8}\right)\\= \frac{6}{11}+\frac{3}{8}\\=\frac{48}{88}+\frac{33}{88}\\=\frac{48+33}{88}\\=\frac{81}{88}\)
  12. \(-\left(\frac{14}{3}\right)-\left(\frac{8}{7}\right)\\= \frac{-14}{3}-\frac{8}{7}\\=\frac{-98}{21}-\frac{24}{21}\\=\frac{-98-24}{21}\\=\frac{-122}{21}\)
Oefeningengenerator wiskundeoefeningen.be 2026-10-16 02:25:31
Een site van Busleyden Atheneum Mechelen