Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-15}{14}\right)+\left(\frac{-12}{5}\right)\)
2. \(+\left(\frac{-9}{-10}\right)-\left(\frac{-3}{-10}\right)\)
3. \(-\left(\frac{-14}{-5}\right)-\left(\frac{-11}{7}\right)\)
4. \(+\left(\frac{5}{4}\right)-\left(\frac{7}{-10}\right)\)
5. \(+\left(\frac{-4}{-5}\right)+\left(\frac{-7}{-2}\right)\)
6. \(-\left(\frac{-4}{3}\right)-\left(\frac{-15}{-4}\right)\)
7. \(+\left(\frac{-2}{3}\right)+\left(\frac{11}{3}\right)\)
8. \(+\left(\frac{15}{14}\right)-\left(\frac{3}{4}\right)\)
9. \(-\left(\frac{12}{-5}\right)-\left(\frac{-3}{4}\right)\)
10. \(-\left(\frac{9}{4}\right)-\left(\frac{6}{5}\right)\)
11. \(-\left(\frac{-2}{-7}\right)+\left(\frac{15}{-13}\right)\)
12. \(-\left(\frac{11}{-2}\right)+\left(\frac{-4}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-15}{14}\right)+\left(\frac{-12}{5}\right)\\= \frac{15}{14}-\frac{12}{5}\\=\frac{75}{70}-\frac{168}{70}\\=\frac{75-168}{70}\\=\frac{-93}{70}\)
2. \(+\left(\frac{-9}{-10}\right)-\left(\frac{-3}{-10}\right)\\= \frac{9}{10}-\frac{3}{10}\\=\frac{9-3}{10}\\=\frac{6}{10}\\=\frac{3}{5}\)
3. \(-\left(\frac{-14}{-5}\right)-\left(\frac{-11}{7}\right)\\= \frac{-14}{5}+\frac{11}{7}\\=\frac{-98}{35}+\frac{55}{35}\\=\frac{-98+55}{35}\\=\frac{-43}{35}\)
4. \(+\left(\frac{5}{4}\right)-\left(\frac{7}{-10}\right)\\= \frac{5}{4}+\frac{7}{10}\\=\frac{25}{20}+\frac{14}{20}\\=\frac{25+14}{20}\\=\frac{39}{20}\)
5. \(+\left(\frac{-4}{-5}\right)+\left(\frac{-7}{-2}\right)\\= \frac{4}{5}+\frac{7}{2}\\=\frac{8}{10}+\frac{35}{10}\\=\frac{8+35}{10}\\=\frac{43}{10}\)
6. \(-\left(\frac{-4}{3}\right)-\left(\frac{-15}{-4}\right)\\= \frac{4}{3}-\frac{15}{4}\\=\frac{16}{12}-\frac{45}{12}\\=\frac{16-45}{12}\\=\frac{-29}{12}\)
7. \(+\left(\frac{-2}{3}\right)+\left(\frac{11}{3}\right)\\= \frac{-2}{3}+\frac{11}{3}\\=\frac{-2+11}{3}\\=\frac{9}{3}\\=\frac{3}{1}\)
8. \(+\left(\frac{15}{14}\right)-\left(\frac{3}{4}\right)\\= \frac{15}{14}-\frac{3}{4}\\=\frac{30}{28}-\frac{21}{28}\\=\frac{30-21}{28}\\=\frac{9}{28}\)
9. \(-\left(\frac{12}{-5}\right)-\left(\frac{-3}{4}\right)\\= \frac{12}{5}+\frac{3}{4}\\=\frac{48}{20}+\frac{15}{20}\\=\frac{48+15}{20}\\=\frac{63}{20}\)
10. \(-\left(\frac{9}{4}\right)-\left(\frac{6}{5}\right)\\= \frac{-9}{4}-\frac{6}{5}\\=\frac{-45}{20}-\frac{24}{20}\\=\frac{-45-24}{20}\\=\frac{-69}{20}\)
11. \(-\left(\frac{-2}{-7}\right)+\left(\frac{15}{-13}\right)\\= \frac{-2}{7}-\frac{15}{13}\\=\frac{-26}{91}-\frac{105}{91}\\=\frac{-26-105}{91}\\=\frac{-131}{91}\)
12. \(-\left(\frac{11}{-2}\right)+\left(\frac{-4}{-11}\right)\\= \frac{11}{2}+\frac{4}{11}\\=\frac{121}{22}+\frac{8}{22}\\=\frac{121+8}{22}\\=\frac{129}{22}\)