Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{15}{7}\right)-\left(\frac{10}{-3}\right)\)
2. \(-\left(\frac{-8}{3}\right)-\left(\frac{12}{11}\right)\)
3. \(-\left(\frac{-4}{9}\right)+\left(\frac{-9}{10}\right)\)
4. \(-\left(\frac{3}{2}\right)+\left(\frac{-13}{9}\right)\)
5. \(-\left(\frac{-15}{-4}\right)+\left(\frac{-4}{9}\right)\)
6. \(-\left(\frac{-5}{-6}\right)+\left(\frac{-15}{13}\right)\)
7. \(+\left(\frac{-15}{-7}\right)-\left(\frac{4}{9}\right)\)
8. \(+\left(\frac{-5}{11}\right)-\left(\frac{-3}{-13}\right)\)
9. \(+\left(\frac{-13}{-14}\right)-\left(\frac{8}{-11}\right)\)
10. \(-\left(\frac{-9}{5}\right)+\left(\frac{15}{-2}\right)\)
11. \(+\left(\frac{-14}{13}\right)-\left(\frac{10}{-3}\right)\)
12. \(-\left(\frac{-8}{-5}\right)+\left(\frac{-9}{-4}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{15}{7}\right)-\left(\frac{10}{-3}\right)\\= \frac{15}{7}+\frac{10}{3}\\=\frac{45}{21}+\frac{70}{21}\\=\frac{45+70}{21}\\=\frac{115}{21}\)
2. \(-\left(\frac{-8}{3}\right)-\left(\frac{12}{11}\right)\\= \frac{8}{3}-\frac{12}{11}\\=\frac{88}{33}-\frac{36}{33}\\=\frac{88-36}{33}\\=\frac{52}{33}\)
3. \(-\left(\frac{-4}{9}\right)+\left(\frac{-9}{10}\right)\\= \frac{4}{9}-\frac{9}{10}\\=\frac{40}{90}-\frac{81}{90}\\=\frac{40-81}{90}\\=\frac{-41}{90}\)
4. \(-\left(\frac{3}{2}\right)+\left(\frac{-13}{9}\right)\\= \frac{-3}{2}-\frac{13}{9}\\=\frac{-27}{18}-\frac{26}{18}\\=\frac{-27-26}{18}\\=\frac{-53}{18}\)
5. \(-\left(\frac{-15}{-4}\right)+\left(\frac{-4}{9}\right)\\= \frac{-15}{4}-\frac{4}{9}\\=\frac{-135}{36}-\frac{16}{36}\\=\frac{-135-16}{36}\\=\frac{-151}{36}\)
6. \(-\left(\frac{-5}{-6}\right)+\left(\frac{-15}{13}\right)\\= \frac{-5}{6}-\frac{15}{13}\\=\frac{-65}{78}-\frac{90}{78}\\=\frac{-65-90}{78}\\=\frac{-155}{78}\)
7. \(+\left(\frac{-15}{-7}\right)-\left(\frac{4}{9}\right)\\= \frac{15}{7}-\frac{4}{9}\\=\frac{135}{63}-\frac{28}{63}\\=\frac{135-28}{63}\\=\frac{107}{63}\)
8. \(+\left(\frac{-5}{11}\right)-\left(\frac{-3}{-13}\right)\\= \frac{-5}{11}-\frac{3}{13}\\=\frac{-65}{143}-\frac{33}{143}\\=\frac{-65-33}{143}\\=\frac{-98}{143}\)
9. \(+\left(\frac{-13}{-14}\right)-\left(\frac{8}{-11}\right)\\= \frac{13}{14}+\frac{8}{11}\\=\frac{143}{154}+\frac{112}{154}\\=\frac{143+112}{154}\\=\frac{255}{154}\)
10. \(-\left(\frac{-9}{5}\right)+\left(\frac{15}{-2}\right)\\= \frac{9}{5}-\frac{15}{2}\\=\frac{18}{10}-\frac{75}{10}\\=\frac{18-75}{10}\\=\frac{-57}{10}\)
11. \(+\left(\frac{-14}{13}\right)-\left(\frac{10}{-3}\right)\\= \frac{-14}{13}+\frac{10}{3}\\=\frac{-42}{39}+\frac{130}{39}\\=\frac{-42+130}{39}\\=\frac{88}{39}\)
12. \(-\left(\frac{-8}{-5}\right)+\left(\frac{-9}{-4}\right)\\= \frac{-8}{5}+\frac{9}{4}\\=\frac{-32}{20}+\frac{45}{20}\\=\frac{-32+45}{20}\\=\frac{13}{20}\)