Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(+\left(\frac{-10}{-3}\right)+\left(\frac{4}{-11}\right)\)
  2. \(+\left(\frac{-15}{-13}\right)+\left(\frac{-3}{2}\right)\)
  3. \(+\left(\frac{-8}{5}\right)+\left(\frac{3}{-13}\right)\)
  4. \(+\left(\frac{-6}{-13}\right)+\left(\frac{-15}{11}\right)\)
  5. \(-\left(\frac{-11}{-12}\right)-\left(\frac{6}{-11}\right)\)
  6. \(-\left(\frac{-6}{11}\right)+\left(\frac{4}{-11}\right)\)
  7. \(+\left(\frac{-3}{-7}\right)+\left(\frac{10}{-3}\right)\)
  8. \(-\left(\frac{-3}{10}\right)-\left(\frac{-15}{-4}\right)\)
  9. \(+\left(\frac{15}{-13}\right)+\left(\frac{11}{-4}\right)\)
  10. \(+\left(\frac{-8}{-3}\right)-\left(\frac{-13}{-4}\right)\)
  11. \(+\left(\frac{4}{-9}\right)-\left(\frac{-11}{4}\right)\)
  12. \(-\left(\frac{-2}{13}\right)+\left(\frac{2}{-11}\right)\)

Bereken

Verbetersleutel

  1. \(+\left(\frac{-10}{-3}\right)+\left(\frac{4}{-11}\right)\\= \frac{10}{3}-\frac{4}{11}\\=\frac{110}{33}-\frac{12}{33}\\=\frac{110-12}{33}\\=\frac{98}{33}\)
  2. \(+\left(\frac{-15}{-13}\right)+\left(\frac{-3}{2}\right)\\= \frac{15}{13}-\frac{3}{2}\\=\frac{30}{26}-\frac{39}{26}\\=\frac{30-39}{26}\\=\frac{-9}{26}\)
  3. \(+\left(\frac{-8}{5}\right)+\left(\frac{3}{-13}\right)\\= \frac{-8}{5}-\frac{3}{13}\\=\frac{-104}{65}-\frac{15}{65}\\=\frac{-104-15}{65}\\=\frac{-119}{65}\)
  4. \(+\left(\frac{-6}{-13}\right)+\left(\frac{-15}{11}\right)\\= \frac{6}{13}-\frac{15}{11}\\=\frac{66}{143}-\frac{195}{143}\\=\frac{66-195}{143}\\=\frac{-129}{143}\)
  5. \(-\left(\frac{-11}{-12}\right)-\left(\frac{6}{-11}\right)\\= \frac{-11}{12}+\frac{6}{11}\\=\frac{-121}{132}+\frac{72}{132}\\=\frac{-121+72}{132}\\=\frac{-49}{132}\)
  6. \(-\left(\frac{-6}{11}\right)+\left(\frac{4}{-11}\right)\\= \frac{6}{11}-\frac{4}{11}\\=\frac{6-4}{11}\\=\frac{2}{11}\)
  7. \(+\left(\frac{-3}{-7}\right)+\left(\frac{10}{-3}\right)\\= \frac{3}{7}-\frac{10}{3}\\=\frac{9}{21}-\frac{70}{21}\\=\frac{9-70}{21}\\=\frac{-61}{21}\)
  8. \(-\left(\frac{-3}{10}\right)-\left(\frac{-15}{-4}\right)\\= \frac{3}{10}-\frac{15}{4}\\=\frac{6}{20}-\frac{75}{20}\\=\frac{6-75}{20}\\=\frac{-69}{20}\)
  9. \(+\left(\frac{15}{-13}\right)+\left(\frac{11}{-4}\right)\\= \frac{-15}{13}-\frac{11}{4}\\=\frac{-60}{52}-\frac{143}{52}\\=\frac{-60-143}{52}\\=\frac{-203}{52}\)
  10. \(+\left(\frac{-8}{-3}\right)-\left(\frac{-13}{-4}\right)\\= \frac{8}{3}-\frac{13}{4}\\=\frac{32}{12}-\frac{39}{12}\\=\frac{32-39}{12}\\=\frac{-7}{12}\)
  11. \(+\left(\frac{4}{-9}\right)-\left(\frac{-11}{4}\right)\\= \frac{-4}{9}+\frac{11}{4}\\=\frac{-16}{36}+\frac{99}{36}\\=\frac{-16+99}{36}\\=\frac{83}{36}\)
  12. \(-\left(\frac{-2}{13}\right)+\left(\frac{2}{-11}\right)\\= \frac{2}{13}-\frac{2}{11}\\=\frac{22}{143}-\frac{26}{143}\\=\frac{22-26}{143}\\=\frac{-4}{143}\)
Oefeningengenerator wiskundeoefeningen.be 2025-12-28 15:39:54
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