Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-11}{-5}\right)+\left(\frac{-4}{-7}\right)\)
2. \(+\left(\frac{5}{2}\right)+\left(\frac{13}{-2}\right)\)
3. \(+\left(\frac{12}{-11}\right)-\left(\frac{6}{5}\right)\)
4. \(+\left(\frac{6}{7}\right)-\left(\frac{-7}{-6}\right)\)
5. \(+\left(\frac{-9}{-7}\right)-\left(\frac{-10}{13}\right)\)
6. \(+\left(\frac{3}{-10}\right)+\left(\frac{9}{-10}\right)\)
7. \(-\left(\frac{10}{3}\right)+\left(\frac{-4}{-3}\right)\)
8. \(-\left(\frac{9}{-10}\right)-\left(\frac{-5}{-8}\right)\)
9. \(-\left(\frac{5}{-3}\right)+\left(\frac{3}{-13}\right)\)
10. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-15}{13}\right)\)
11. \(-\left(\frac{-12}{-7}\right)+\left(\frac{6}{-5}\right)\)
12. \(-\left(\frac{-14}{11}\right)-\left(\frac{13}{5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-11}{-5}\right)+\left(\frac{-4}{-7}\right)\\= \frac{11}{5}+\frac{4}{7}\\=\frac{77}{35}+\frac{20}{35}\\=\frac{77+20}{35}\\=\frac{97}{35}\)
2. \(+\left(\frac{5}{2}\right)+\left(\frac{13}{-2}\right)\\= \frac{5}{2}-\frac{13}{2}\\=\frac{5-13}{2}\\=\frac{-8}{2}\\=\frac{-4}{1}\)
3. \(+\left(\frac{12}{-11}\right)-\left(\frac{6}{5}\right)\\= \frac{-12}{11}-\frac{6}{5}\\=\frac{-60}{55}-\frac{66}{55}\\=\frac{-60-66}{55}\\=\frac{-126}{55}\)
4. \(+\left(\frac{6}{7}\right)-\left(\frac{-7}{-6}\right)\\= \frac{6}{7}-\frac{7}{6}\\=\frac{36}{42}-\frac{49}{42}\\=\frac{36-49}{42}\\=\frac{-13}{42}\)
5. \(+\left(\frac{-9}{-7}\right)-\left(\frac{-10}{13}\right)\\= \frac{9}{7}+\frac{10}{13}\\=\frac{117}{91}+\frac{70}{91}\\=\frac{117+70}{91}\\=\frac{187}{91}\)
6. \(+\left(\frac{3}{-10}\right)+\left(\frac{9}{-10}\right)\\= \frac{-3}{10}-\frac{9}{10}\\=\frac{-3-9}{10}\\=\frac{-12}{10}\\=\frac{-6}{5}\)
7. \(-\left(\frac{10}{3}\right)+\left(\frac{-4}{-3}\right)\\= \frac{-10}{3}+\frac{4}{3}\\=\frac{-10+4}{3}\\=\frac{-6}{3}\\=\frac{-2}{1}\)
8. \(-\left(\frac{9}{-10}\right)-\left(\frac{-5}{-8}\right)\\= \frac{9}{10}-\frac{5}{8}\\=\frac{36}{40}-\frac{25}{40}\\=\frac{36-25}{40}\\=\frac{11}{40}\)
9. \(-\left(\frac{5}{-3}\right)+\left(\frac{3}{-13}\right)\\= \frac{5}{3}-\frac{3}{13}\\=\frac{65}{39}-\frac{9}{39}\\=\frac{65-9}{39}\\=\frac{56}{39}\)
10. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-15}{13}\right)\\= \frac{12}{5}-\frac{15}{13}\\=\frac{156}{65}-\frac{75}{65}\\=\frac{156-75}{65}\\=\frac{81}{65}\)
11. \(-\left(\frac{-12}{-7}\right)+\left(\frac{6}{-5}\right)\\= \frac{-12}{7}-\frac{6}{5}\\=\frac{-60}{35}-\frac{42}{35}\\=\frac{-60-42}{35}\\=\frac{-102}{35}\)
12. \(-\left(\frac{-14}{11}\right)-\left(\frac{13}{5}\right)\\= \frac{14}{11}-\frac{13}{5}\\=\frac{70}{55}-\frac{143}{55}\\=\frac{70-143}{55}\\=\frac{-73}{55}\)