Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(+\left(\frac{-11}{14}\right)-\left(\frac{-7}{12}\right)\)
  2. \(-\left(\frac{-8}{-11}\right)-\left(\frac{-8}{-7}\right)\)
  3. \(+\left(\frac{5}{-2}\right)-\left(\frac{9}{-2}\right)\)
  4. \(-\left(\frac{8}{9}\right)-\left(\frac{-9}{-4}\right)\)
  5. \(+\left(\frac{-6}{-13}\right)+\left(\frac{11}{12}\right)\)
  6. \(-\left(\frac{-13}{8}\right)-\left(\frac{-13}{-5}\right)\)
  7. \(-\left(\frac{-9}{-10}\right)-\left(\frac{-9}{-2}\right)\)
  8. \(+\left(\frac{7}{3}\right)+\left(\frac{4}{-3}\right)\)
  9. \(+\left(\frac{-9}{2}\right)+\left(\frac{-15}{-11}\right)\)
  10. \(-\left(\frac{8}{-3}\right)+\left(\frac{3}{13}\right)\)
  11. \(-\left(\frac{8}{7}\right)-\left(\frac{-10}{7}\right)\)
  12. \(+\left(\frac{-14}{11}\right)+\left(\frac{-5}{14}\right)\)

Bereken

Verbetersleutel

  1. \(+\left(\frac{-11}{14}\right)-\left(\frac{-7}{12}\right)\\= \frac{-11}{14}+\frac{7}{12}\\=\frac{-66}{84}+\frac{49}{84}\\=\frac{-66+49}{84}\\=\frac{-17}{84}\)
  2. \(-\left(\frac{-8}{-11}\right)-\left(\frac{-8}{-7}\right)\\= \frac{-8}{11}-\frac{8}{7}\\=\frac{-56}{77}-\frac{88}{77}\\=\frac{-56-88}{77}\\=\frac{-144}{77}\)
  3. \(+\left(\frac{5}{-2}\right)-\left(\frac{9}{-2}\right)\\= \frac{-5}{2}+\frac{9}{2}\\=\frac{-5+9}{2}\\=\frac{4}{2}\\=\frac{2}{1}\)
  4. \(-\left(\frac{8}{9}\right)-\left(\frac{-9}{-4}\right)\\= \frac{-8}{9}-\frac{9}{4}\\=\frac{-32}{36}-\frac{81}{36}\\=\frac{-32-81}{36}\\=\frac{-113}{36}\)
  5. \(+\left(\frac{-6}{-13}\right)+\left(\frac{11}{12}\right)\\= \frac{6}{13}+\frac{11}{12}\\=\frac{72}{156}+\frac{143}{156}\\=\frac{72+143}{156}\\=\frac{215}{156}\)
  6. \(-\left(\frac{-13}{8}\right)-\left(\frac{-13}{-5}\right)\\= \frac{13}{8}-\frac{13}{5}\\=\frac{65}{40}-\frac{104}{40}\\=\frac{65-104}{40}\\=\frac{-39}{40}\)
  7. \(-\left(\frac{-9}{-10}\right)-\left(\frac{-9}{-2}\right)\\= \frac{-9}{10}-\frac{9}{2}\\=\frac{-9-9}{10}\\=\frac{-18}{10}\\=\frac{-9}{5}\)
  8. \(+\left(\frac{7}{3}\right)+\left(\frac{4}{-3}\right)\\= \frac{7}{3}-\frac{4}{3}\\=\frac{7-4}{3}\\=\frac{3}{3}\\=\frac{1}{1}\)
  9. \(+\left(\frac{-9}{2}\right)+\left(\frac{-15}{-11}\right)\\= \frac{-9}{2}+\frac{15}{11}\\=\frac{-99}{22}+\frac{30}{22}\\=\frac{-99+30}{22}\\=\frac{-69}{22}\)
  10. \(-\left(\frac{8}{-3}\right)+\left(\frac{3}{13}\right)\\= \frac{8}{3}+\frac{3}{13}\\=\frac{104}{39}+\frac{9}{39}\\=\frac{104+9}{39}\\=\frac{113}{39}\)
  11. \(-\left(\frac{8}{7}\right)-\left(\frac{-10}{7}\right)\\= \frac{-8}{7}+\frac{10}{7}\\=\frac{-8+10}{7}\\=\frac{2}{7}\)
  12. \(+\left(\frac{-14}{11}\right)+\left(\frac{-5}{14}\right)\\= \frac{-14}{11}-\frac{5}{14}\\=\frac{-196}{154}-\frac{55}{154}\\=\frac{-196-55}{154}\\=\frac{-251}{154}\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-17 00:33:33
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