Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-11}{10}\right)+\left(\frac{-2}{-3}\right)\)
2. \(-\left(\frac{-13}{2}\right)-\left(\frac{-11}{13}\right)\)
3. \(+\left(\frac{12}{7}\right)+\left(\frac{2}{11}\right)\)
4. \(+\left(\frac{-6}{-13}\right)+\left(\frac{2}{-3}\right)\)
5. \(+\left(\frac{-13}{14}\right)+\left(\frac{-3}{14}\right)\)
6. \(-\left(\frac{8}{5}\right)+\left(\frac{9}{13}\right)\)
7. \(+\left(\frac{9}{-13}\right)-\left(\frac{8}{13}\right)\)
8. \(+\left(\frac{13}{9}\right)+\left(\frac{-10}{3}\right)\)
9. \(+\left(\frac{-7}{5}\right)-\left(\frac{4}{7}\right)\)
10. \(-\left(\frac{6}{-11}\right)+\left(\frac{-15}{-13}\right)\)
11. \(+\left(\frac{9}{-14}\right)+\left(\frac{-11}{-4}\right)\)
12. \(+\left(\frac{2}{-3}\right)+\left(\frac{-5}{-12}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-11}{10}\right)+\left(\frac{-2}{-3}\right)\\= \frac{-11}{10}+\frac{2}{3}\\=\frac{-33}{30}+\frac{20}{30}\\=\frac{-33+20}{30}\\=\frac{-13}{30}\)
2. \(-\left(\frac{-13}{2}\right)-\left(\frac{-11}{13}\right)\\= \frac{13}{2}+\frac{11}{13}\\=\frac{169}{26}+\frac{22}{26}\\=\frac{169+22}{26}\\=\frac{191}{26}\)
3. \(+\left(\frac{12}{7}\right)+\left(\frac{2}{11}\right)\\= \frac{12}{7}+\frac{2}{11}\\=\frac{132}{77}+\frac{14}{77}\\=\frac{132+14}{77}\\=\frac{146}{77}\)
4. \(+\left(\frac{-6}{-13}\right)+\left(\frac{2}{-3}\right)\\= \frac{6}{13}-\frac{2}{3}\\=\frac{18}{39}-\frac{26}{39}\\=\frac{18-26}{39}\\=\frac{-8}{39}\)
5. \(+\left(\frac{-13}{14}\right)+\left(\frac{-3}{14}\right)\\= \frac{-13}{14}-\frac{3}{14}\\=\frac{-13-3}{14}\\=\frac{-16}{14}\\=\frac{-8}{7}\)
6. \(-\left(\frac{8}{5}\right)+\left(\frac{9}{13}\right)\\= \frac{-8}{5}+\frac{9}{13}\\=\frac{-104}{65}+\frac{45}{65}\\=\frac{-104+45}{65}\\=\frac{-59}{65}\)
7. \(+\left(\frac{9}{-13}\right)-\left(\frac{8}{13}\right)\\= \frac{-9}{13}-\frac{8}{13}\\=\frac{-9-8}{13}\\=\frac{-17}{13}\)
8. \(+\left(\frac{13}{9}\right)+\left(\frac{-10}{3}\right)\\= \frac{13}{9}-\frac{10}{3}\\=\frac{13-10}{9}\\=\frac{3}{9}\\=\frac{1}{3}\)
9. \(+\left(\frac{-7}{5}\right)-\left(\frac{4}{7}\right)\\= \frac{-7}{5}-\frac{4}{7}\\=\frac{-49}{35}-\frac{20}{35}\\=\frac{-49-20}{35}\\=\frac{-69}{35}\)
10. \(-\left(\frac{6}{-11}\right)+\left(\frac{-15}{-13}\right)\\= \frac{6}{11}+\frac{15}{13}\\=\frac{78}{143}+\frac{165}{143}\\=\frac{78+165}{143}\\=\frac{243}{143}\)
11. \(+\left(\frac{9}{-14}\right)+\left(\frac{-11}{-4}\right)\\= \frac{-9}{14}+\frac{11}{4}\\=\frac{-18}{28}+\frac{77}{28}\\=\frac{-18+77}{28}\\=\frac{59}{28}\)
12. \(+\left(\frac{2}{-3}\right)+\left(\frac{-5}{-12}\right)\\= \frac{-2}{3}+\frac{5}{12}\\=\frac{-8}{12}+\frac{5}{12}\\=\frac{-8+5}{12}\\=\frac{-3}{12}\\=\frac{-1}{4}\)