Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{8}{-7}\right)-\left(\frac{2}{-13}\right)\)
2. \(+\left(\frac{8}{13}\right)+\left(\frac{-7}{-11}\right)\)
3. \(+\left(\frac{12}{5}\right)+\left(\frac{4}{-9}\right)\)
4. \(+\left(\frac{-9}{14}\right)-\left(\frac{14}{3}\right)\)
5. \(-\left(\frac{15}{-13}\right)+\left(\frac{9}{-14}\right)\)
6. \(-\left(\frac{-8}{-9}\right)-\left(\frac{14}{-11}\right)\)
7. \(+\left(\frac{-5}{9}\right)-\left(\frac{8}{11}\right)\)
8. \(+\left(\frac{-5}{11}\right)+\left(\frac{-2}{-3}\right)\)
9. \(+\left(\frac{2}{-5}\right)-\left(\frac{4}{-3}\right)\)
10. \(-\left(\frac{-11}{-3}\right)+\left(\frac{10}{9}\right)\)
11. \(-\left(\frac{-12}{-5}\right)+\left(\frac{-13}{10}\right)\)
12. \(+\left(\frac{-12}{7}\right)-\left(\frac{-11}{9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{8}{-7}\right)-\left(\frac{2}{-13}\right)\\= \frac{-8}{7}+\frac{2}{13}\\=\frac{-104}{91}+\frac{14}{91}\\=\frac{-104+14}{91}\\=\frac{-90}{91}\)
2. \(+\left(\frac{8}{13}\right)+\left(\frac{-7}{-11}\right)\\= \frac{8}{13}+\frac{7}{11}\\=\frac{88}{143}+\frac{91}{143}\\=\frac{88+91}{143}\\=\frac{179}{143}\)
3. \(+\left(\frac{12}{5}\right)+\left(\frac{4}{-9}\right)\\= \frac{12}{5}-\frac{4}{9}\\=\frac{108}{45}-\frac{20}{45}\\=\frac{108-20}{45}\\=\frac{88}{45}\)
4. \(+\left(\frac{-9}{14}\right)-\left(\frac{14}{3}\right)\\= \frac{-9}{14}-\frac{14}{3}\\=\frac{-27}{42}-\frac{196}{42}\\=\frac{-27-196}{42}\\=\frac{-223}{42}\)
5. \(-\left(\frac{15}{-13}\right)+\left(\frac{9}{-14}\right)\\= \frac{15}{13}-\frac{9}{14}\\=\frac{210}{182}-\frac{117}{182}\\=\frac{210-117}{182}\\=\frac{93}{182}\)
6. \(-\left(\frac{-8}{-9}\right)-\left(\frac{14}{-11}\right)\\= \frac{-8}{9}+\frac{14}{11}\\=\frac{-88}{99}+\frac{126}{99}\\=\frac{-88+126}{99}\\=\frac{38}{99}\)
7. \(+\left(\frac{-5}{9}\right)-\left(\frac{8}{11}\right)\\= \frac{-5}{9}-\frac{8}{11}\\=\frac{-55}{99}-\frac{72}{99}\\=\frac{-55-72}{99}\\=\frac{-127}{99}\)
8. \(+\left(\frac{-5}{11}\right)+\left(\frac{-2}{-3}\right)\\= \frac{-5}{11}+\frac{2}{3}\\=\frac{-15}{33}+\frac{22}{33}\\=\frac{-15+22}{33}\\=\frac{7}{33}\)
9. \(+\left(\frac{2}{-5}\right)-\left(\frac{4}{-3}\right)\\= \frac{-2}{5}+\frac{4}{3}\\=\frac{-6}{15}+\frac{20}{15}\\=\frac{-6+20}{15}\\=\frac{14}{15}\)
10. \(-\left(\frac{-11}{-3}\right)+\left(\frac{10}{9}\right)\\= \frac{-11}{3}+\frac{10}{9}\\=\frac{-33}{9}+\frac{10}{9}\\=\frac{-33+10}{9}\\=\frac{-23}{9}\)
11. \(-\left(\frac{-12}{-5}\right)+\left(\frac{-13}{10}\right)\\= \frac{-12}{5}-\frac{13}{10}\\=\frac{-24}{10}-\frac{13}{10}\\=\frac{-24-13}{10}\\=\frac{-37}{10}\)
12. \(+\left(\frac{-12}{7}\right)-\left(\frac{-11}{9}\right)\\= \frac{-12}{7}+\frac{11}{9}\\=\frac{-108}{63}+\frac{77}{63}\\=\frac{-108+77}{63}\\=\frac{-31}{63}\)