Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{4}{11}\right)+\left(\frac{15}{7}\right)\)
2. \(+\left(\frac{8}{-13}\right)-\left(\frac{-4}{7}\right)\)
3. \(+\left(\frac{-12}{5}\right)-\left(\frac{6}{5}\right)\)
4. \(+\left(\frac{-8}{13}\right)+\left(\frac{3}{-8}\right)\)
5. \(+\left(\frac{-9}{-2}\right)+\left(\frac{-14}{9}\right)\)
6. \(-\left(\frac{-15}{14}\right)-\left(\frac{-14}{-9}\right)\)
7. \(+\left(\frac{-3}{-8}\right)+\left(\frac{7}{-6}\right)\)
8. \(-\left(\frac{-14}{13}\right)+\left(\frac{-10}{-9}\right)\)
9. \(+\left(\frac{-6}{-11}\right)-\left(\frac{2}{5}\right)\)
10. \(-\left(\frac{6}{7}\right)+\left(\frac{12}{-11}\right)\)
11. \(+\left(\frac{11}{-4}\right)+\left(\frac{2}{-7}\right)\)
12. \(-\left(\frac{11}{3}\right)+\left(\frac{-7}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{4}{11}\right)+\left(\frac{15}{7}\right)\\= \frac{-4}{11}+\frac{15}{7}\\=\frac{-28}{77}+\frac{165}{77}\\=\frac{-28+165}{77}\\=\frac{137}{77}\)
2. \(+\left(\frac{8}{-13}\right)-\left(\frac{-4}{7}\right)\\= \frac{-8}{13}+\frac{4}{7}\\=\frac{-56}{91}+\frac{52}{91}\\=\frac{-56+52}{91}\\=\frac{-4}{91}\)
3. \(+\left(\frac{-12}{5}\right)-\left(\frac{6}{5}\right)\\= \frac{-12}{5}-\frac{6}{5}\\=\frac{-12-6}{5}\\=\frac{-18}{5}\)
4. \(+\left(\frac{-8}{13}\right)+\left(\frac{3}{-8}\right)\\= \frac{-8}{13}-\frac{3}{8}\\=\frac{-64}{104}-\frac{39}{104}\\=\frac{-64-39}{104}\\=\frac{-103}{104}\)
5. \(+\left(\frac{-9}{-2}\right)+\left(\frac{-14}{9}\right)\\= \frac{9}{2}-\frac{14}{9}\\=\frac{81}{18}-\frac{28}{18}\\=\frac{81-28}{18}\\=\frac{53}{18}\)
6. \(-\left(\frac{-15}{14}\right)-\left(\frac{-14}{-9}\right)\\= \frac{15}{14}-\frac{14}{9}\\=\frac{135}{126}-\frac{196}{126}\\=\frac{135-196}{126}\\=\frac{-61}{126}\)
7. \(+\left(\frac{-3}{-8}\right)+\left(\frac{7}{-6}\right)\\= \frac{3}{8}-\frac{7}{6}\\=\frac{9}{24}-\frac{28}{24}\\=\frac{9-28}{24}\\=\frac{-19}{24}\)
8. \(-\left(\frac{-14}{13}\right)+\left(\frac{-10}{-9}\right)\\= \frac{14}{13}+\frac{10}{9}\\=\frac{126}{117}+\frac{130}{117}\\=\frac{126+130}{117}\\=\frac{256}{117}\)
9. \(+\left(\frac{-6}{-11}\right)-\left(\frac{2}{5}\right)\\= \frac{6}{11}-\frac{2}{5}\\=\frac{30}{55}-\frac{22}{55}\\=\frac{30-22}{55}\\=\frac{8}{55}\)
10. \(-\left(\frac{6}{7}\right)+\left(\frac{12}{-11}\right)\\= \frac{-6}{7}-\frac{12}{11}\\=\frac{-66}{77}-\frac{84}{77}\\=\frac{-66-84}{77}\\=\frac{-150}{77}\)
11. \(+\left(\frac{11}{-4}\right)+\left(\frac{2}{-7}\right)\\= \frac{-11}{4}-\frac{2}{7}\\=\frac{-77}{28}-\frac{8}{28}\\=\frac{-77-8}{28}\\=\frac{-85}{28}\)
12. \(-\left(\frac{11}{3}\right)+\left(\frac{-7}{-11}\right)\\= \frac{-11}{3}+\frac{7}{11}\\=\frac{-121}{33}+\frac{21}{33}\\=\frac{-121+21}{33}\\=\frac{-100}{33}\)