Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{8}{-7}\right)-\left(\frac{12}{13}\right)\)
2. \(+\left(\frac{-6}{-5}\right)+\left(\frac{11}{-7}\right)\)
3. \(+\left(\frac{-12}{5}\right)-\left(\frac{7}{-5}\right)\)
4. \(+\left(\frac{-15}{4}\right)+\left(\frac{-2}{13}\right)\)
5. \(-\left(\frac{-3}{-2}\right)-\left(\frac{3}{-4}\right)\)
6. \(-\left(\frac{-12}{-5}\right)+\left(\frac{3}{7}\right)\)
7. \(+\left(\frac{-5}{-3}\right)+\left(\frac{-3}{10}\right)\)
8. \(-\left(\frac{3}{-14}\right)+\left(\frac{-12}{-13}\right)\)
9. \(-\left(\frac{11}{-8}\right)+\left(\frac{-2}{5}\right)\)
10. \(+\left(\frac{-9}{-5}\right)-\left(\frac{9}{11}\right)\)
11. \(+\left(\frac{-11}{4}\right)+\left(\frac{5}{-11}\right)\)
12. \(+\left(\frac{-15}{-4}\right)+\left(\frac{10}{9}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{8}{-7}\right)-\left(\frac{12}{13}\right)\\= \frac{8}{7}-\frac{12}{13}\\=\frac{104}{91}-\frac{84}{91}\\=\frac{104-84}{91}\\=\frac{20}{91}\)
2. \(+\left(\frac{-6}{-5}\right)+\left(\frac{11}{-7}\right)\\= \frac{6}{5}-\frac{11}{7}\\=\frac{42}{35}-\frac{55}{35}\\=\frac{42-55}{35}\\=\frac{-13}{35}\)
3. \(+\left(\frac{-12}{5}\right)-\left(\frac{7}{-5}\right)\\= \frac{-12}{5}+\frac{7}{5}\\=\frac{-12+7}{5}\\=\frac{-5}{5}\\=\frac{-1}{1}\)
4. \(+\left(\frac{-15}{4}\right)+\left(\frac{-2}{13}\right)\\= \frac{-15}{4}-\frac{2}{13}\\=\frac{-195}{52}-\frac{8}{52}\\=\frac{-195-8}{52}\\=\frac{-203}{52}\)
5. \(-\left(\frac{-3}{-2}\right)-\left(\frac{3}{-4}\right)\\= \frac{-3}{2}+\frac{3}{4}\\=\frac{-6}{4}+\frac{3}{4}\\=\frac{-6+3}{4}\\=\frac{-3}{4}\)
6. \(-\left(\frac{-12}{-5}\right)+\left(\frac{3}{7}\right)\\= \frac{-12}{5}+\frac{3}{7}\\=\frac{-84}{35}+\frac{15}{35}\\=\frac{-84+15}{35}\\=\frac{-69}{35}\)
7. \(+\left(\frac{-5}{-3}\right)+\left(\frac{-3}{10}\right)\\= \frac{5}{3}-\frac{3}{10}\\=\frac{50}{30}-\frac{9}{30}\\=\frac{50-9}{30}\\=\frac{41}{30}\)
8. \(-\left(\frac{3}{-14}\right)+\left(\frac{-12}{-13}\right)\\= \frac{3}{14}+\frac{12}{13}\\=\frac{39}{182}+\frac{168}{182}\\=\frac{39+168}{182}\\=\frac{207}{182}\)
9. \(-\left(\frac{11}{-8}\right)+\left(\frac{-2}{5}\right)\\= \frac{11}{8}-\frac{2}{5}\\=\frac{55}{40}-\frac{16}{40}\\=\frac{55-16}{40}\\=\frac{39}{40}\)
10. \(+\left(\frac{-9}{-5}\right)-\left(\frac{9}{11}\right)\\= \frac{9}{5}-\frac{9}{11}\\=\frac{99}{55}-\frac{45}{55}\\=\frac{99-45}{55}\\=\frac{54}{55}\)
11. \(+\left(\frac{-11}{4}\right)+\left(\frac{5}{-11}\right)\\= \frac{-11}{4}-\frac{5}{11}\\=\frac{-121}{44}-\frac{20}{44}\\=\frac{-121-20}{44}\\=\frac{-141}{44}\)
12. \(+\left(\frac{-15}{-4}\right)+\left(\frac{10}{9}\right)\\= \frac{15}{4}+\frac{10}{9}\\=\frac{135}{36}+\frac{40}{36}\\=\frac{135+40}{36}\\=\frac{175}{36}\)