Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{14}{11}\right)-\left(\frac{8}{11}\right)\)
2. \(+\left(\frac{-8}{13}\right)+\left(\frac{-7}{9}\right)\)
3. \(+\left(\frac{-15}{4}\right)-\left(\frac{-7}{-8}\right)\)
4. \(+\left(\frac{-10}{-3}\right)+\left(\frac{9}{7}\right)\)
5. \(+\left(\frac{7}{2}\right)-\left(\frac{4}{-13}\right)\)
6. \(-\left(\frac{-3}{-10}\right)+\left(\frac{4}{11}\right)\)
7. \(+\left(\frac{-12}{-11}\right)-\left(\frac{-4}{-11}\right)\)
8. \(-\left(\frac{15}{8}\right)-\left(\frac{-11}{-3}\right)\)
9. \(+\left(\frac{-2}{3}\right)-\left(\frac{-12}{-11}\right)\)
10. \(-\left(\frac{3}{7}\right)-\left(\frac{6}{5}\right)\)
11. \(+\left(\frac{-5}{-2}\right)+\left(\frac{14}{13}\right)\)
12. \(-\left(\frac{11}{3}\right)+\left(\frac{8}{3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{14}{11}\right)-\left(\frac{8}{11}\right)\\= \frac{14}{11}-\frac{8}{11}\\=\frac{14-8}{11}\\=\frac{6}{11}\)
2. \(+\left(\frac{-8}{13}\right)+\left(\frac{-7}{9}\right)\\= \frac{-8}{13}-\frac{7}{9}\\=\frac{-72}{117}-\frac{91}{117}\\=\frac{-72-91}{117}\\=\frac{-163}{117}\)
3. \(+\left(\frac{-15}{4}\right)-\left(\frac{-7}{-8}\right)\\= \frac{-15}{4}-\frac{7}{8}\\=\frac{-30}{8}-\frac{7}{8}\\=\frac{-30-7}{8}\\=\frac{-37}{8}\)
4. \(+\left(\frac{-10}{-3}\right)+\left(\frac{9}{7}\right)\\= \frac{10}{3}+\frac{9}{7}\\=\frac{70}{21}+\frac{27}{21}\\=\frac{70+27}{21}\\=\frac{97}{21}\)
5. \(+\left(\frac{7}{2}\right)-\left(\frac{4}{-13}\right)\\= \frac{7}{2}+\frac{4}{13}\\=\frac{91}{26}+\frac{8}{26}\\=\frac{91+8}{26}\\=\frac{99}{26}\)
6. \(-\left(\frac{-3}{-10}\right)+\left(\frac{4}{11}\right)\\= \frac{-3}{10}+\frac{4}{11}\\=\frac{-33}{110}+\frac{40}{110}\\=\frac{-33+40}{110}\\=\frac{7}{110}\)
7. \(+\left(\frac{-12}{-11}\right)-\left(\frac{-4}{-11}\right)\\= \frac{12}{11}-\frac{4}{11}\\=\frac{12-4}{11}\\=\frac{8}{11}\)
8. \(-\left(\frac{15}{8}\right)-\left(\frac{-11}{-3}\right)\\= \frac{-15}{8}-\frac{11}{3}\\=\frac{-45}{24}-\frac{88}{24}\\=\frac{-45-88}{24}\\=\frac{-133}{24}\)
9. \(+\left(\frac{-2}{3}\right)-\left(\frac{-12}{-11}\right)\\= \frac{-2}{3}-\frac{12}{11}\\=\frac{-22}{33}-\frac{36}{33}\\=\frac{-22-36}{33}\\=\frac{-58}{33}\)
10. \(-\left(\frac{3}{7}\right)-\left(\frac{6}{5}\right)\\= \frac{-3}{7}-\frac{6}{5}\\=\frac{-15}{35}-\frac{42}{35}\\=\frac{-15-42}{35}\\=\frac{-57}{35}\)
11. \(+\left(\frac{-5}{-2}\right)+\left(\frac{14}{13}\right)\\= \frac{5}{2}+\frac{14}{13}\\=\frac{65}{26}+\frac{28}{26}\\=\frac{65+28}{26}\\=\frac{93}{26}\)
12. \(-\left(\frac{11}{3}\right)+\left(\frac{8}{3}\right)\\= \frac{-11}{3}+\frac{8}{3}\\=\frac{-11+8}{3}\\=\frac{-3}{3}\\=\frac{-1}{1}\)