Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-8}{-3}\right)+\left(\frac{6}{-5}\right)\)
2. \(-\left(\frac{9}{11}\right)-\left(\frac{-7}{-2}\right)\)
3. \(-\left(\frac{14}{-13}\right)-\left(\frac{-11}{-10}\right)\)
4. \(-\left(\frac{2}{9}\right)-\left(\frac{-5}{6}\right)\)
5. \(-\left(\frac{12}{-7}\right)-\left(\frac{-10}{13}\right)\)
6. \(+\left(\frac{-10}{-11}\right)-\left(\frac{-15}{11}\right)\)
7. \(+\left(\frac{-2}{13}\right)-\left(\frac{15}{-11}\right)\)
8. \(-\left(\frac{-15}{-11}\right)-\left(\frac{-12}{-7}\right)\)
9. \(-\left(\frac{-8}{-11}\right)-\left(\frac{-13}{9}\right)\)
10. \(-\left(\frac{-13}{-14}\right)-\left(\frac{15}{7}\right)\)
11. \(-\left(\frac{2}{3}\right)+\left(\frac{-2}{11}\right)\)
12. \(+\left(\frac{2}{-3}\right)-\left(\frac{13}{8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-8}{-3}\right)+\left(\frac{6}{-5}\right)\\= \frac{8}{3}-\frac{6}{5}\\=\frac{40}{15}-\frac{18}{15}\\=\frac{40-18}{15}\\=\frac{22}{15}\)
2. \(-\left(\frac{9}{11}\right)-\left(\frac{-7}{-2}\right)\\= \frac{-9}{11}-\frac{7}{2}\\=\frac{-18}{22}-\frac{77}{22}\\=\frac{-18-77}{22}\\=\frac{-95}{22}\)
3. \(-\left(\frac{14}{-13}\right)-\left(\frac{-11}{-10}\right)\\= \frac{14}{13}-\frac{11}{10}\\=\frac{140}{130}-\frac{143}{130}\\=\frac{140-143}{130}\\=\frac{-3}{130}\)
4. \(-\left(\frac{2}{9}\right)-\left(\frac{-5}{6}\right)\\= \frac{-2}{9}+\frac{5}{6}\\=\frac{-4}{18}+\frac{15}{18}\\=\frac{-4+15}{18}\\=\frac{11}{18}\)
5. \(-\left(\frac{12}{-7}\right)-\left(\frac{-10}{13}\right)\\= \frac{12}{7}+\frac{10}{13}\\=\frac{156}{91}+\frac{70}{91}\\=\frac{156+70}{91}\\=\frac{226}{91}\)
6. \(+\left(\frac{-10}{-11}\right)-\left(\frac{-15}{11}\right)\\= \frac{10}{11}+\frac{15}{11}\\=\frac{10+15}{11}\\=\frac{25}{11}\)
7. \(+\left(\frac{-2}{13}\right)-\left(\frac{15}{-11}\right)\\= \frac{-2}{13}+\frac{15}{11}\\=\frac{-22}{143}+\frac{195}{143}\\=\frac{-22+195}{143}\\=\frac{173}{143}\)
8. \(-\left(\frac{-15}{-11}\right)-\left(\frac{-12}{-7}\right)\\= \frac{-15}{11}-\frac{12}{7}\\=\frac{-105}{77}-\frac{132}{77}\\=\frac{-105-132}{77}\\=\frac{-237}{77}\)
9. \(-\left(\frac{-8}{-11}\right)-\left(\frac{-13}{9}\right)\\= \frac{-8}{11}+\frac{13}{9}\\=\frac{-72}{99}+\frac{143}{99}\\=\frac{-72+143}{99}\\=\frac{71}{99}\)
10. \(-\left(\frac{-13}{-14}\right)-\left(\frac{15}{7}\right)\\= \frac{-13}{14}-\frac{15}{7}\\=\frac{-13-15}{14}\\=\frac{-28}{14}\\=\frac{-2}{1}\)
11. \(-\left(\frac{2}{3}\right)+\left(\frac{-2}{11}\right)\\= \frac{-2}{3}-\frac{2}{11}\\=\frac{-22}{33}-\frac{6}{33}\\=\frac{-22-6}{33}\\=\frac{-28}{33}\)
12. \(+\left(\frac{2}{-3}\right)-\left(\frac{13}{8}\right)\\= \frac{-2}{3}-\frac{13}{8}\\=\frac{-16}{24}-\frac{39}{24}\\=\frac{-16-39}{24}\\=\frac{-55}{24}\)