Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{11}{-12}\right)+\left(\frac{4}{7}\right)\)
2. \(+\left(\frac{-15}{-11}\right)-\left(\frac{-13}{10}\right)\)
3. \(-\left(\frac{-11}{-4}\right)-\left(\frac{11}{-14}\right)\)
4. \(+\left(\frac{-3}{8}\right)+\left(\frac{-15}{-2}\right)\)
5. \(+\left(\frac{-6}{-11}\right)+\left(\frac{13}{-14}\right)\)
6. \(-\left(\frac{3}{-10}\right)+\left(\frac{4}{5}\right)\)
7. \(+\left(\frac{14}{13}\right)-\left(\frac{-14}{11}\right)\)
8. \(-\left(\frac{-4}{5}\right)+\left(\frac{-7}{-3}\right)\)
9. \(+\left(\frac{-5}{-11}\right)-\left(\frac{-12}{-11}\right)\)
10. \(-\left(\frac{-2}{-13}\right)+\left(\frac{6}{11}\right)\)
11. \(-\left(\frac{15}{-4}\right)+\left(\frac{4}{-13}\right)\)
12. \(-\left(\frac{-4}{3}\right)-\left(\frac{5}{-8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{11}{-12}\right)+\left(\frac{4}{7}\right)\\= \frac{-11}{12}+\frac{4}{7}\\=\frac{-77}{84}+\frac{48}{84}\\=\frac{-77+48}{84}\\=\frac{-29}{84}\)
2. \(+\left(\frac{-15}{-11}\right)-\left(\frac{-13}{10}\right)\\= \frac{15}{11}+\frac{13}{10}\\=\frac{150}{110}+\frac{143}{110}\\=\frac{150+143}{110}\\=\frac{293}{110}\)
3. \(-\left(\frac{-11}{-4}\right)-\left(\frac{11}{-14}\right)\\= \frac{-11}{4}+\frac{11}{14}\\=\frac{-77}{28}+\frac{22}{28}\\=\frac{-77+22}{28}\\=\frac{-55}{28}\)
4. \(+\left(\frac{-3}{8}\right)+\left(\frac{-15}{-2}\right)\\= \frac{-3}{8}+\frac{15}{2}\\=\frac{-3+15}{8}\\=\frac{12}{8}\\=\frac{3}{2}\)
5. \(+\left(\frac{-6}{-11}\right)+\left(\frac{13}{-14}\right)\\= \frac{6}{11}-\frac{13}{14}\\=\frac{84}{154}-\frac{143}{154}\\=\frac{84-143}{154}\\=\frac{-59}{154}\)
6. \(-\left(\frac{3}{-10}\right)+\left(\frac{4}{5}\right)\\= \frac{3}{10}+\frac{4}{5}\\=\frac{3+4}{10}\\=\frac{7}{10}\)
7. \(+\left(\frac{14}{13}\right)-\left(\frac{-14}{11}\right)\\= \frac{14}{13}+\frac{14}{11}\\=\frac{154}{143}+\frac{182}{143}\\=\frac{154+182}{143}\\=\frac{336}{143}\)
8. \(-\left(\frac{-4}{5}\right)+\left(\frac{-7}{-3}\right)\\= \frac{4}{5}+\frac{7}{3}\\=\frac{12}{15}+\frac{35}{15}\\=\frac{12+35}{15}\\=\frac{47}{15}\)
9. \(+\left(\frac{-5}{-11}\right)-\left(\frac{-12}{-11}\right)\\= \frac{5}{11}-\frac{12}{11}\\=\frac{5-12}{11}\\=\frac{-7}{11}\)
10. \(-\left(\frac{-2}{-13}\right)+\left(\frac{6}{11}\right)\\= \frac{-2}{13}+\frac{6}{11}\\=\frac{-22}{143}+\frac{78}{143}\\=\frac{-22+78}{143}\\=\frac{56}{143}\)
11. \(-\left(\frac{15}{-4}\right)+\left(\frac{4}{-13}\right)\\= \frac{15}{4}-\frac{4}{13}\\=\frac{195}{52}-\frac{16}{52}\\=\frac{195-16}{52}\\=\frac{179}{52}\)
12. \(-\left(\frac{-4}{3}\right)-\left(\frac{5}{-8}\right)\\= \frac{4}{3}+\frac{5}{8}\\=\frac{32}{24}+\frac{15}{24}\\=\frac{32+15}{24}\\=\frac{47}{24}\)