Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-10}{-11}\right)-\left(\frac{-2}{-3}\right)\)
2. \(+\left(\frac{-11}{4}\right)-\left(\frac{-3}{7}\right)\)
3. \(+\left(\frac{-8}{-7}\right)+\left(\frac{-7}{8}\right)\)
4. \(-\left(\frac{6}{7}\right)+\left(\frac{-14}{-13}\right)\)
5. \(-\left(\frac{-11}{4}\right)-\left(\frac{6}{5}\right)\)
6. \(-\left(\frac{-13}{7}\right)+\left(\frac{-9}{-4}\right)\)
7. \(-\left(\frac{5}{-6}\right)-\left(\frac{-3}{-2}\right)\)
8. \(+\left(\frac{-13}{-12}\right)-\left(\frac{8}{3}\right)\)
9. \(+\left(\frac{-2}{-11}\right)+\left(\frac{11}{9}\right)\)
10. \(-\left(\frac{7}{2}\right)+\left(\frac{3}{-2}\right)\)
11. \(-\left(\frac{-13}{14}\right)+\left(\frac{5}{-7}\right)\)
12. \(-\left(\frac{12}{-11}\right)-\left(\frac{5}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-10}{-11}\right)-\left(\frac{-2}{-3}\right)\\= \frac{-10}{11}-\frac{2}{3}\\=\frac{-30}{33}-\frac{22}{33}\\=\frac{-30-22}{33}\\=\frac{-52}{33}\)
2. \(+\left(\frac{-11}{4}\right)-\left(\frac{-3}{7}\right)\\= \frac{-11}{4}+\frac{3}{7}\\=\frac{-77}{28}+\frac{12}{28}\\=\frac{-77+12}{28}\\=\frac{-65}{28}\)
3. \(+\left(\frac{-8}{-7}\right)+\left(\frac{-7}{8}\right)\\= \frac{8}{7}-\frac{7}{8}\\=\frac{64}{56}-\frac{49}{56}\\=\frac{64-49}{56}\\=\frac{15}{56}\)
4. \(-\left(\frac{6}{7}\right)+\left(\frac{-14}{-13}\right)\\= \frac{-6}{7}+\frac{14}{13}\\=\frac{-78}{91}+\frac{98}{91}\\=\frac{-78+98}{91}\\=\frac{20}{91}\)
5. \(-\left(\frac{-11}{4}\right)-\left(\frac{6}{5}\right)\\= \frac{11}{4}-\frac{6}{5}\\=\frac{55}{20}-\frac{24}{20}\\=\frac{55-24}{20}\\=\frac{31}{20}\)
6. \(-\left(\frac{-13}{7}\right)+\left(\frac{-9}{-4}\right)\\= \frac{13}{7}+\frac{9}{4}\\=\frac{52}{28}+\frac{63}{28}\\=\frac{52+63}{28}\\=\frac{115}{28}\)
7. \(-\left(\frac{5}{-6}\right)-\left(\frac{-3}{-2}\right)\\= \frac{5}{6}-\frac{3}{2}\\=\frac{5-3}{6}\\=\frac{2}{6}\\=\frac{1}{3}\)
8. \(+\left(\frac{-13}{-12}\right)-\left(\frac{8}{3}\right)\\= \frac{13}{12}-\frac{8}{3}\\=\frac{13-8}{12}\\=\frac{5}{12}\)
9. \(+\left(\frac{-2}{-11}\right)+\left(\frac{11}{9}\right)\\= \frac{2}{11}+\frac{11}{9}\\=\frac{18}{99}+\frac{121}{99}\\=\frac{18+121}{99}\\=\frac{139}{99}\)
10. \(-\left(\frac{7}{2}\right)+\left(\frac{3}{-2}\right)\\= \frac{-7}{2}-\frac{3}{2}\\=\frac{-7-3}{2}\\=\frac{-10}{2}\\=\frac{-5}{1}\)
11. \(-\left(\frac{-13}{14}\right)+\left(\frac{5}{-7}\right)\\= \frac{13}{14}-\frac{5}{7}\\=\frac{13-5}{14}\\=\frac{8}{14}\\=\frac{4}{7}\)
12. \(-\left(\frac{12}{-11}\right)-\left(\frac{5}{-11}\right)\\= \frac{12}{11}+\frac{5}{11}\\=\frac{12+5}{11}\\=\frac{17}{11}\)