Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{8}{5}\right)-\left(\frac{10}{-11}\right)\)
2. \(-\left(\frac{14}{9}\right)-\left(\frac{10}{3}\right)\)
3. \(+\left(\frac{14}{11}\right)-\left(\frac{8}{7}\right)\)
4. \(-\left(\frac{-11}{-7}\right)-\left(\frac{-15}{13}\right)\)
5. \(-\left(\frac{-3}{10}\right)+\left(\frac{15}{11}\right)\)
6. \(-\left(\frac{-13}{-14}\right)-\left(\frac{-12}{11}\right)\)
7. \(+\left(\frac{15}{-8}\right)-\left(\frac{-3}{11}\right)\)
8. \(-\left(\frac{4}{-9}\right)+\left(\frac{-13}{9}\right)\)
9. \(+\left(\frac{-4}{-3}\right)-\left(\frac{8}{-3}\right)\)
10. \(+\left(\frac{15}{11}\right)-\left(\frac{-11}{-9}\right)\)
11. \(-\left(\frac{-11}{13}\right)-\left(\frac{-14}{9}\right)\)
12. \(-\left(\frac{-6}{13}\right)+\left(\frac{13}{-2}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{8}{5}\right)-\left(\frac{10}{-11}\right)\\= \frac{8}{5}+\frac{10}{11}\\=\frac{88}{55}+\frac{50}{55}\\=\frac{88+50}{55}\\=\frac{138}{55}\)
2. \(-\left(\frac{14}{9}\right)-\left(\frac{10}{3}\right)\\= \frac{-14}{9}-\frac{10}{3}\\=\frac{-14-10}{9}\\=\frac{-24}{9}\\=\frac{-8}{3}\)
3. \(+\left(\frac{14}{11}\right)-\left(\frac{8}{7}\right)\\= \frac{14}{11}-\frac{8}{7}\\=\frac{98}{77}-\frac{88}{77}\\=\frac{98-88}{77}\\=\frac{10}{77}\)
4. \(-\left(\frac{-11}{-7}\right)-\left(\frac{-15}{13}\right)\\= \frac{-11}{7}+\frac{15}{13}\\=\frac{-143}{91}+\frac{105}{91}\\=\frac{-143+105}{91}\\=\frac{-38}{91}\)
5. \(-\left(\frac{-3}{10}\right)+\left(\frac{15}{11}\right)\\= \frac{3}{10}+\frac{15}{11}\\=\frac{33}{110}+\frac{150}{110}\\=\frac{33+150}{110}\\=\frac{183}{110}\)
6. \(-\left(\frac{-13}{-14}\right)-\left(\frac{-12}{11}\right)\\= \frac{-13}{14}+\frac{12}{11}\\=\frac{-143}{154}+\frac{168}{154}\\=\frac{-143+168}{154}\\=\frac{25}{154}\)
7. \(+\left(\frac{15}{-8}\right)-\left(\frac{-3}{11}\right)\\= \frac{-15}{8}+\frac{3}{11}\\=\frac{-165}{88}+\frac{24}{88}\\=\frac{-165+24}{88}\\=\frac{-141}{88}\)
8. \(-\left(\frac{4}{-9}\right)+\left(\frac{-13}{9}\right)\\= \frac{4}{9}-\frac{13}{9}\\=\frac{4-13}{9}\\=\frac{-9}{9}\\=\frac{-1}{1}\)
9. \(+\left(\frac{-4}{-3}\right)-\left(\frac{8}{-3}\right)\\= \frac{4}{3}+\frac{8}{3}\\=\frac{4+8}{3}\\=\frac{12}{3}\\=\frac{4}{1}\)
10. \(+\left(\frac{15}{11}\right)-\left(\frac{-11}{-9}\right)\\= \frac{15}{11}-\frac{11}{9}\\=\frac{135}{99}-\frac{121}{99}\\=\frac{135-121}{99}\\=\frac{14}{99}\)
11. \(-\left(\frac{-11}{13}\right)-\left(\frac{-14}{9}\right)\\= \frac{11}{13}+\frac{14}{9}\\=\frac{99}{117}+\frac{182}{117}\\=\frac{99+182}{117}\\=\frac{281}{117}\)
12. \(-\left(\frac{-6}{13}\right)+\left(\frac{13}{-2}\right)\\= \frac{6}{13}-\frac{13}{2}\\=\frac{12}{26}-\frac{169}{26}\\=\frac{12-169}{26}\\=\frac{-157}{26}\)