Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(+\left(\frac{-13}{2}\right)-\left(\frac{-2}{7}\right)\)
  2. \(+\left(\frac{-5}{2}\right)-\left(\frac{-5}{3}\right)\)
  3. \(-\left(\frac{6}{13}\right)+\left(\frac{-11}{-5}\right)\)
  4. \(+\left(\frac{-12}{5}\right)+\left(\frac{11}{6}\right)\)
  5. \(+\left(\frac{-11}{-7}\right)+\left(\frac{14}{3}\right)\)
  6. \(-\left(\frac{-4}{5}\right)-\left(\frac{7}{-3}\right)\)
  7. \(+\left(\frac{-4}{-9}\right)+\left(\frac{14}{-11}\right)\)
  8. \(-\left(\frac{-9}{-5}\right)-\left(\frac{10}{3}\right)\)
  9. \(-\left(\frac{8}{-7}\right)+\left(\frac{-8}{5}\right)\)
  10. \(+\left(\frac{-6}{-5}\right)-\left(\frac{-7}{2}\right)\)
  11. \(+\left(\frac{-3}{-4}\right)-\left(\frac{15}{4}\right)\)
  12. \(+\left(\frac{-5}{2}\right)+\left(\frac{14}{9}\right)\)

Bereken

Verbetersleutel

  1. \(+\left(\frac{-13}{2}\right)-\left(\frac{-2}{7}\right)\\= \frac{-13}{2}+\frac{2}{7}\\=\frac{-91}{14}+\frac{4}{14}\\=\frac{-91+4}{14}\\=\frac{-87}{14}\)
  2. \(+\left(\frac{-5}{2}\right)-\left(\frac{-5}{3}\right)\\= \frac{-5}{2}+\frac{5}{3}\\=\frac{-15}{6}+\frac{10}{6}\\=\frac{-15+10}{6}\\=\frac{-5}{6}\)
  3. \(-\left(\frac{6}{13}\right)+\left(\frac{-11}{-5}\right)\\= \frac{-6}{13}+\frac{11}{5}\\=\frac{-30}{65}+\frac{143}{65}\\=\frac{-30+143}{65}\\=\frac{113}{65}\)
  4. \(+\left(\frac{-12}{5}\right)+\left(\frac{11}{6}\right)\\= \frac{-12}{5}+\frac{11}{6}\\=\frac{-72}{30}+\frac{55}{30}\\=\frac{-72+55}{30}\\=\frac{-17}{30}\)
  5. \(+\left(\frac{-11}{-7}\right)+\left(\frac{14}{3}\right)\\= \frac{11}{7}+\frac{14}{3}\\=\frac{33}{21}+\frac{98}{21}\\=\frac{33+98}{21}\\=\frac{131}{21}\)
  6. \(-\left(\frac{-4}{5}\right)-\left(\frac{7}{-3}\right)\\= \frac{4}{5}+\frac{7}{3}\\=\frac{12}{15}+\frac{35}{15}\\=\frac{12+35}{15}\\=\frac{47}{15}\)
  7. \(+\left(\frac{-4}{-9}\right)+\left(\frac{14}{-11}\right)\\= \frac{4}{9}-\frac{14}{11}\\=\frac{44}{99}-\frac{126}{99}\\=\frac{44-126}{99}\\=\frac{-82}{99}\)
  8. \(-\left(\frac{-9}{-5}\right)-\left(\frac{10}{3}\right)\\= \frac{-9}{5}-\frac{10}{3}\\=\frac{-27}{15}-\frac{50}{15}\\=\frac{-27-50}{15}\\=\frac{-77}{15}\)
  9. \(-\left(\frac{8}{-7}\right)+\left(\frac{-8}{5}\right)\\= \frac{8}{7}-\frac{8}{5}\\=\frac{40}{35}-\frac{56}{35}\\=\frac{40-56}{35}\\=\frac{-16}{35}\)
  10. \(+\left(\frac{-6}{-5}\right)-\left(\frac{-7}{2}\right)\\= \frac{6}{5}+\frac{7}{2}\\=\frac{12}{10}+\frac{35}{10}\\=\frac{12+35}{10}\\=\frac{47}{10}\)
  11. \(+\left(\frac{-3}{-4}\right)-\left(\frac{15}{4}\right)\\= \frac{3}{4}-\frac{15}{4}\\=\frac{3-15}{4}\\=\frac{-12}{4}\\=\frac{-3}{1}\)
  12. \(+\left(\frac{-5}{2}\right)+\left(\frac{14}{9}\right)\\= \frac{-5}{2}+\frac{14}{9}\\=\frac{-45}{18}+\frac{28}{18}\\=\frac{-45+28}{18}\\=\frac{-17}{18}\)
Oefeningengenerator wiskundeoefeningen.be 2026-09-16 00:40:38
Een site van Busleyden Atheneum Mechelen