Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{5}{2}\right)-\left(\frac{-11}{-10}\right)\)
2. \(+\left(\frac{-13}{-14}\right)-\left(\frac{8}{3}\right)\)
3. \(+\left(\frac{2}{3}\right)-\left(\frac{14}{-3}\right)\)
4. \(-\left(\frac{-4}{13}\right)-\left(\frac{15}{-7}\right)\)
5. \(+\left(\frac{4}{-9}\right)+\left(\frac{7}{8}\right)\)
6. \(+\left(\frac{5}{13}\right)+\left(\frac{-14}{3}\right)\)
7. \(-\left(\frac{11}{12}\right)-\left(\frac{3}{-11}\right)\)
8. \(+\left(\frac{5}{-13}\right)-\left(\frac{-14}{-3}\right)\)
9. \(+\left(\frac{11}{-7}\right)+\left(\frac{15}{2}\right)\)
10. \(-\left(\frac{8}{9}\right)-\left(\frac{6}{5}\right)\)
11. \(+\left(\frac{-14}{-13}\right)-\left(\frac{-6}{-5}\right)\)
12. \(+\left(\frac{3}{8}\right)+\left(\frac{14}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{5}{2}\right)-\left(\frac{-11}{-10}\right)\\= \frac{5}{2}-\frac{11}{10}\\=\frac{25}{10}-\frac{11}{10}\\=\frac{25-11}{10}\\=\frac{14}{10}\\=\frac{7}{5}\)
2. \(+\left(\frac{-13}{-14}\right)-\left(\frac{8}{3}\right)\\= \frac{13}{14}-\frac{8}{3}\\=\frac{39}{42}-\frac{112}{42}\\=\frac{39-112}{42}\\=\frac{-73}{42}\)
3. \(+\left(\frac{2}{3}\right)-\left(\frac{14}{-3}\right)\\= \frac{2}{3}+\frac{14}{3}\\=\frac{2+14}{3}\\=\frac{16}{3}\)
4. \(-\left(\frac{-4}{13}\right)-\left(\frac{15}{-7}\right)\\= \frac{4}{13}+\frac{15}{7}\\=\frac{28}{91}+\frac{195}{91}\\=\frac{28+195}{91}\\=\frac{223}{91}\)
5. \(+\left(\frac{4}{-9}\right)+\left(\frac{7}{8}\right)\\= \frac{-4}{9}+\frac{7}{8}\\=\frac{-32}{72}+\frac{63}{72}\\=\frac{-32+63}{72}\\=\frac{31}{72}\)
6. \(+\left(\frac{5}{13}\right)+\left(\frac{-14}{3}\right)\\= \frac{5}{13}-\frac{14}{3}\\=\frac{15}{39}-\frac{182}{39}\\=\frac{15-182}{39}\\=\frac{-167}{39}\)
7. \(-\left(\frac{11}{12}\right)-\left(\frac{3}{-11}\right)\\= \frac{-11}{12}+\frac{3}{11}\\=\frac{-121}{132}+\frac{36}{132}\\=\frac{-121+36}{132}\\=\frac{-85}{132}\)
8. \(+\left(\frac{5}{-13}\right)-\left(\frac{-14}{-3}\right)\\= \frac{-5}{13}-\frac{14}{3}\\=\frac{-15}{39}-\frac{182}{39}\\=\frac{-15-182}{39}\\=\frac{-197}{39}\)
9. \(+\left(\frac{11}{-7}\right)+\left(\frac{15}{2}\right)\\= \frac{-11}{7}+\frac{15}{2}\\=\frac{-22}{14}+\frac{105}{14}\\=\frac{-22+105}{14}\\=\frac{83}{14}\)
10. \(-\left(\frac{8}{9}\right)-\left(\frac{6}{5}\right)\\= \frac{-8}{9}-\frac{6}{5}\\=\frac{-40}{45}-\frac{54}{45}\\=\frac{-40-54}{45}\\=\frac{-94}{45}\)
11. \(+\left(\frac{-14}{-13}\right)-\left(\frac{-6}{-5}\right)\\= \frac{14}{13}-\frac{6}{5}\\=\frac{70}{65}-\frac{78}{65}\\=\frac{70-78}{65}\\=\frac{-8}{65}\)
12. \(+\left(\frac{3}{8}\right)+\left(\frac{14}{-5}\right)\\= \frac{3}{8}-\frac{14}{5}\\=\frac{15}{40}-\frac{112}{40}\\=\frac{15-112}{40}\\=\frac{-97}{40}\)