Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-8}{-9}\right)\)
2. \(-\left(\frac{10}{9}\right)-\left(\frac{8}{3}\right)\)
3. \(-\left(\frac{-6}{11}\right)-\left(\frac{-7}{3}\right)\)
4. \(-\left(\frac{3}{4}\right)+\left(\frac{3}{7}\right)\)
5. \(-\left(\frac{10}{7}\right)+\left(\frac{-9}{-2}\right)\)
6. \(-\left(\frac{-3}{-13}\right)-\left(\frac{15}{14}\right)\)
7. \(-\left(\frac{10}{9}\right)+\left(\frac{13}{-7}\right)\)
8. \(+\left(\frac{7}{2}\right)+\left(\frac{-6}{-5}\right)\)
9. \(-\left(\frac{5}{8}\right)+\left(\frac{-3}{14}\right)\)
10. \(-\left(\frac{5}{-3}\right)-\left(\frac{11}{6}\right)\)
11. \(+\left(\frac{-4}{9}\right)+\left(\frac{9}{11}\right)\)
12. \(-\left(\frac{4}{-3}\right)+\left(\frac{-14}{-9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-8}{-9}\right)\\= \frac{12}{5}+\frac{8}{9}\\=\frac{108}{45}+\frac{40}{45}\\=\frac{108+40}{45}\\=\frac{148}{45}\)
2. \(-\left(\frac{10}{9}\right)-\left(\frac{8}{3}\right)\\= \frac{-10}{9}-\frac{8}{3}\\=\frac{-10-8}{9}\\=\frac{-18}{9}\\=\frac{-2}{1}\)
3. \(-\left(\frac{-6}{11}\right)-\left(\frac{-7}{3}\right)\\= \frac{6}{11}+\frac{7}{3}\\=\frac{18}{33}+\frac{77}{33}\\=\frac{18+77}{33}\\=\frac{95}{33}\)
4. \(-\left(\frac{3}{4}\right)+\left(\frac{3}{7}\right)\\= \frac{-3}{4}+\frac{3}{7}\\=\frac{-21}{28}+\frac{12}{28}\\=\frac{-21+12}{28}\\=\frac{-9}{28}\)
5. \(-\left(\frac{10}{7}\right)+\left(\frac{-9}{-2}\right)\\= \frac{-10}{7}+\frac{9}{2}\\=\frac{-20}{14}+\frac{63}{14}\\=\frac{-20+63}{14}\\=\frac{43}{14}\)
6. \(-\left(\frac{-3}{-13}\right)-\left(\frac{15}{14}\right)\\= \frac{-3}{13}-\frac{15}{14}\\=\frac{-42}{182}-\frac{195}{182}\\=\frac{-42-195}{182}\\=\frac{-237}{182}\)
7. \(-\left(\frac{10}{9}\right)+\left(\frac{13}{-7}\right)\\= \frac{-10}{9}-\frac{13}{7}\\=\frac{-70}{63}-\frac{117}{63}\\=\frac{-70-117}{63}\\=\frac{-187}{63}\)
8. \(+\left(\frac{7}{2}\right)+\left(\frac{-6}{-5}\right)\\= \frac{7}{2}+\frac{6}{5}\\=\frac{35}{10}+\frac{12}{10}\\=\frac{35+12}{10}\\=\frac{47}{10}\)
9. \(-\left(\frac{5}{8}\right)+\left(\frac{-3}{14}\right)\\= \frac{-5}{8}-\frac{3}{14}\\=\frac{-35}{56}-\frac{12}{56}\\=\frac{-35-12}{56}\\=\frac{-47}{56}\)
10. \(-\left(\frac{5}{-3}\right)-\left(\frac{11}{6}\right)\\= \frac{5}{3}-\frac{11}{6}\\=\frac{10}{6}-\frac{11}{6}\\=\frac{10-11}{6}\\=\frac{-1}{6}\)
11. \(+\left(\frac{-4}{9}\right)+\left(\frac{9}{11}\right)\\= \frac{-4}{9}+\frac{9}{11}\\=\frac{-44}{99}+\frac{81}{99}\\=\frac{-44+81}{99}\\=\frac{37}{99}\)
12. \(-\left(\frac{4}{-3}\right)+\left(\frac{-14}{-9}\right)\\= \frac{4}{3}+\frac{14}{9}\\=\frac{12}{9}+\frac{14}{9}\\=\frac{12+14}{9}\\=\frac{26}{9}\)