Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-7}{-2}\right)+\left(\frac{9}{4}\right)\)
2. \(-\left(\frac{-3}{-14}\right)-\left(\frac{-14}{11}\right)\)
3. \(+\left(\frac{13}{-6}\right)-\left(\frac{2}{7}\right)\)
4. \(-\left(\frac{-2}{-11}\right)+\left(\frac{12}{-13}\right)\)
5. \(+\left(\frac{-2}{9}\right)+\left(\frac{12}{13}\right)\)
6. \(-\left(\frac{-6}{11}\right)+\left(\frac{-13}{-3}\right)\)
7. \(-\left(\frac{-3}{10}\right)-\left(\frac{4}{-7}\right)\)
8. \(+\left(\frac{3}{-7}\right)+\left(\frac{5}{2}\right)\)
9. \(+\left(\frac{10}{3}\right)+\left(\frac{-14}{-3}\right)\)
10. \(+\left(\frac{-11}{10}\right)+\left(\frac{2}{7}\right)\)
11. \(-\left(\frac{6}{11}\right)-\left(\frac{2}{3}\right)\)
12. \(-\left(\frac{5}{-14}\right)-\left(\frac{-7}{-8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-7}{-2}\right)+\left(\frac{9}{4}\right)\\= \frac{7}{2}+\frac{9}{4}\\=\frac{14}{4}+\frac{9}{4}\\=\frac{14+9}{4}\\=\frac{23}{4}\)
2. \(-\left(\frac{-3}{-14}\right)-\left(\frac{-14}{11}\right)\\= \frac{-3}{14}+\frac{14}{11}\\=\frac{-33}{154}+\frac{196}{154}\\=\frac{-33+196}{154}\\=\frac{163}{154}\)
3. \(+\left(\frac{13}{-6}\right)-\left(\frac{2}{7}\right)\\= \frac{-13}{6}-\frac{2}{7}\\=\frac{-91}{42}-\frac{12}{42}\\=\frac{-91-12}{42}\\=\frac{-103}{42}\)
4. \(-\left(\frac{-2}{-11}\right)+\left(\frac{12}{-13}\right)\\= \frac{-2}{11}-\frac{12}{13}\\=\frac{-26}{143}-\frac{132}{143}\\=\frac{-26-132}{143}\\=\frac{-158}{143}\)
5. \(+\left(\frac{-2}{9}\right)+\left(\frac{12}{13}\right)\\= \frac{-2}{9}+\frac{12}{13}\\=\frac{-26}{117}+\frac{108}{117}\\=\frac{-26+108}{117}\\=\frac{82}{117}\)
6. \(-\left(\frac{-6}{11}\right)+\left(\frac{-13}{-3}\right)\\= \frac{6}{11}+\frac{13}{3}\\=\frac{18}{33}+\frac{143}{33}\\=\frac{18+143}{33}\\=\frac{161}{33}\)
7. \(-\left(\frac{-3}{10}\right)-\left(\frac{4}{-7}\right)\\= \frac{3}{10}+\frac{4}{7}\\=\frac{21}{70}+\frac{40}{70}\\=\frac{21+40}{70}\\=\frac{61}{70}\)
8. \(+\left(\frac{3}{-7}\right)+\left(\frac{5}{2}\right)\\= \frac{-3}{7}+\frac{5}{2}\\=\frac{-6}{14}+\frac{35}{14}\\=\frac{-6+35}{14}\\=\frac{29}{14}\)
9. \(+\left(\frac{10}{3}\right)+\left(\frac{-14}{-3}\right)\\= \frac{10}{3}+\frac{14}{3}\\=\frac{10+14}{3}\\=\frac{24}{3}\\=\frac{8}{1}\)
10. \(+\left(\frac{-11}{10}\right)+\left(\frac{2}{7}\right)\\= \frac{-11}{10}+\frac{2}{7}\\=\frac{-77}{70}+\frac{20}{70}\\=\frac{-77+20}{70}\\=\frac{-57}{70}\)
11. \(-\left(\frac{6}{11}\right)-\left(\frac{2}{3}\right)\\= \frac{-6}{11}-\frac{2}{3}\\=\frac{-18}{33}-\frac{22}{33}\\=\frac{-18-22}{33}\\=\frac{-40}{33}\)
12. \(-\left(\frac{5}{-14}\right)-\left(\frac{-7}{-8}\right)\\= \frac{5}{14}-\frac{7}{8}\\=\frac{20}{56}-\frac{49}{56}\\=\frac{20-49}{56}\\=\frac{-29}{56}\)