Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-4}{-3}\right)+\left(\frac{2}{7}\right)\)
2. \(-\left(\frac{-6}{5}\right)-\left(\frac{5}{-14}\right)\)
3. \(-\left(\frac{11}{10}\right)+\left(\frac{-4}{13}\right)\)
4. \(+\left(\frac{-5}{-3}\right)+\left(\frac{14}{5}\right)\)
5. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-9}{8}\right)\)
6. \(+\left(\frac{-10}{-7}\right)+\left(\frac{-5}{4}\right)\)
7. \(-\left(\frac{13}{9}\right)+\left(\frac{2}{7}\right)\)
8. \(+\left(\frac{9}{-13}\right)-\left(\frac{-9}{13}\right)\)
9. \(-\left(\frac{-6}{-11}\right)-\left(\frac{2}{5}\right)\)
10. \(-\left(\frac{-9}{-2}\right)-\left(\frac{12}{5}\right)\)
11. \(-\left(\frac{10}{11}\right)+\left(\frac{9}{-5}\right)\)
12. \(+\left(\frac{-3}{14}\right)+\left(\frac{-5}{14}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-4}{-3}\right)+\left(\frac{2}{7}\right)\\= \frac{-4}{3}+\frac{2}{7}\\=\frac{-28}{21}+\frac{6}{21}\\=\frac{-28+6}{21}\\=\frac{-22}{21}\)
2. \(-\left(\frac{-6}{5}\right)-\left(\frac{5}{-14}\right)\\= \frac{6}{5}+\frac{5}{14}\\=\frac{84}{70}+\frac{25}{70}\\=\frac{84+25}{70}\\=\frac{109}{70}\)
3. \(-\left(\frac{11}{10}\right)+\left(\frac{-4}{13}\right)\\= \frac{-11}{10}-\frac{4}{13}\\=\frac{-143}{130}-\frac{40}{130}\\=\frac{-143-40}{130}\\=\frac{-183}{130}\)
4. \(+\left(\frac{-5}{-3}\right)+\left(\frac{14}{5}\right)\\= \frac{5}{3}+\frac{14}{5}\\=\frac{25}{15}+\frac{42}{15}\\=\frac{25+42}{15}\\=\frac{67}{15}\)
5. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-9}{8}\right)\\= \frac{-6}{11}+\frac{9}{8}\\=\frac{-48}{88}+\frac{99}{88}\\=\frac{-48+99}{88}\\=\frac{51}{88}\)
6. \(+\left(\frac{-10}{-7}\right)+\left(\frac{-5}{4}\right)\\= \frac{10}{7}-\frac{5}{4}\\=\frac{40}{28}-\frac{35}{28}\\=\frac{40-35}{28}\\=\frac{5}{28}\)
7. \(-\left(\frac{13}{9}\right)+\left(\frac{2}{7}\right)\\= \frac{-13}{9}+\frac{2}{7}\\=\frac{-91}{63}+\frac{18}{63}\\=\frac{-91+18}{63}\\=\frac{-73}{63}\)
8. \(+\left(\frac{9}{-13}\right)-\left(\frac{-9}{13}\right)\\= \frac{-9}{13}+\frac{9}{13}\\=\frac{-9+9}{13}\\=\frac{0}{13}\\=\frac{0}{1}\)
9. \(-\left(\frac{-6}{-11}\right)-\left(\frac{2}{5}\right)\\= \frac{-6}{11}-\frac{2}{5}\\=\frac{-30}{55}-\frac{22}{55}\\=\frac{-30-22}{55}\\=\frac{-52}{55}\)
10. \(-\left(\frac{-9}{-2}\right)-\left(\frac{12}{5}\right)\\= \frac{-9}{2}-\frac{12}{5}\\=\frac{-45}{10}-\frac{24}{10}\\=\frac{-45-24}{10}\\=\frac{-69}{10}\)
11. \(-\left(\frac{10}{11}\right)+\left(\frac{9}{-5}\right)\\= \frac{-10}{11}-\frac{9}{5}\\=\frac{-50}{55}-\frac{99}{55}\\=\frac{-50-99}{55}\\=\frac{-149}{55}\)
12. \(+\left(\frac{-3}{14}\right)+\left(\frac{-5}{14}\right)\\= \frac{-3}{14}-\frac{5}{14}\\=\frac{-3-5}{14}\\=\frac{-8}{14}\\=\frac{-4}{7}\)