Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{5}{-8}\right)+\left(\frac{-8}{5}\right)\)
2. \(+\left(\frac{-12}{7}\right)+\left(\frac{-10}{3}\right)\)
3. \(-\left(\frac{-2}{3}\right)+\left(\frac{11}{8}\right)\)
4. \(+\left(\frac{9}{8}\right)+\left(\frac{-12}{-13}\right)\)
5. \(-\left(\frac{-2}{9}\right)-\left(\frac{9}{-5}\right)\)
6. \(+\left(\frac{13}{10}\right)-\left(\frac{9}{-11}\right)\)
7. \(-\left(\frac{-5}{-2}\right)+\left(\frac{-9}{10}\right)\)
8. \(-\left(\frac{-7}{-12}\right)-\left(\frac{-5}{14}\right)\)
9. \(+\left(\frac{3}{-2}\right)+\left(\frac{10}{-3}\right)\)
10. \(-\left(\frac{-4}{-5}\right)+\left(\frac{4}{13}\right)\)
11. \(-\left(\frac{6}{5}\right)+\left(\frac{2}{-3}\right)\)
12. \(-\left(\frac{4}{-13}\right)-\left(\frac{14}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{5}{-8}\right)+\left(\frac{-8}{5}\right)\\= \frac{-5}{8}-\frac{8}{5}\\=\frac{-25}{40}-\frac{64}{40}\\=\frac{-25-64}{40}\\=\frac{-89}{40}\)
2. \(+\left(\frac{-12}{7}\right)+\left(\frac{-10}{3}\right)\\= \frac{-12}{7}-\frac{10}{3}\\=\frac{-36}{21}-\frac{70}{21}\\=\frac{-36-70}{21}\\=\frac{-106}{21}\)
3. \(-\left(\frac{-2}{3}\right)+\left(\frac{11}{8}\right)\\= \frac{2}{3}+\frac{11}{8}\\=\frac{16}{24}+\frac{33}{24}\\=\frac{16+33}{24}\\=\frac{49}{24}\)
4. \(+\left(\frac{9}{8}\right)+\left(\frac{-12}{-13}\right)\\= \frac{9}{8}+\frac{12}{13}\\=\frac{117}{104}+\frac{96}{104}\\=\frac{117+96}{104}\\=\frac{213}{104}\)
5. \(-\left(\frac{-2}{9}\right)-\left(\frac{9}{-5}\right)\\= \frac{2}{9}+\frac{9}{5}\\=\frac{10}{45}+\frac{81}{45}\\=\frac{10+81}{45}\\=\frac{91}{45}\)
6. \(+\left(\frac{13}{10}\right)-\left(\frac{9}{-11}\right)\\= \frac{13}{10}+\frac{9}{11}\\=\frac{143}{110}+\frac{90}{110}\\=\frac{143+90}{110}\\=\frac{233}{110}\)
7. \(-\left(\frac{-5}{-2}\right)+\left(\frac{-9}{10}\right)\\= \frac{-5}{2}-\frac{9}{10}\\=\frac{-25}{10}-\frac{9}{10}\\=\frac{-25-9}{10}\\=\frac{-34}{10}\\=\frac{-17}{5}\)
8. \(-\left(\frac{-7}{-12}\right)-\left(\frac{-5}{14}\right)\\= \frac{-7}{12}+\frac{5}{14}\\=\frac{-49}{84}+\frac{30}{84}\\=\frac{-49+30}{84}\\=\frac{-19}{84}\)
9. \(+\left(\frac{3}{-2}\right)+\left(\frac{10}{-3}\right)\\= \frac{-3}{2}-\frac{10}{3}\\=\frac{-9}{6}-\frac{20}{6}\\=\frac{-9-20}{6}\\=\frac{-29}{6}\)
10. \(-\left(\frac{-4}{-5}\right)+\left(\frac{4}{13}\right)\\= \frac{-4}{5}+\frac{4}{13}\\=\frac{-52}{65}+\frac{20}{65}\\=\frac{-52+20}{65}\\=\frac{-32}{65}\)
11. \(-\left(\frac{6}{5}\right)+\left(\frac{2}{-3}\right)\\= \frac{-6}{5}-\frac{2}{3}\\=\frac{-18}{15}-\frac{10}{15}\\=\frac{-18-10}{15}\\=\frac{-28}{15}\)
12. \(-\left(\frac{4}{-13}\right)-\left(\frac{14}{-5}\right)\\= \frac{4}{13}+\frac{14}{5}\\=\frac{20}{65}+\frac{182}{65}\\=\frac{20+182}{65}\\=\frac{202}{65}\)