Breuken haakjesregel (reeks 1)

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Bereken

1. \(+\left(\frac{-15}{7}\right)-\left(\frac{13}{12}\right)\)
2. \(+\left(\frac{6}{11}\right)-\left(\frac{-12}{-11}\right)\)
3. \(+\left(\frac{2}{11}\right)-\left(\frac{-10}{11}\right)\)
4. \(+\left(\frac{-15}{7}\right)-\left(\frac{-5}{6}\right)\)
5. \(-\left(\frac{4}{-13}\right)+\left(\frac{-14}{-3}\right)\)
6. \(+\left(\frac{3}{10}\right)-\left(\frac{4}{-3}\right)\)
7. \(+\left(\frac{3}{2}\right)-\left(\frac{15}{-13}\right)\)
8. \(-\left(\frac{-9}{13}\right)-\left(\frac{5}{14}\right)\)
9. \(+\left(\frac{-5}{6}\right)+\left(\frac{12}{7}\right)\)
10. \(+\left(\frac{-6}{13}\right)-\left(\frac{8}{7}\right)\)
11. \(+\left(\frac{5}{8}\right)-\left(\frac{11}{-3}\right)\)
12. \(-\left(\frac{7}{8}\right)-\left(\frac{11}{-12}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-15}{7}\right)-\left(\frac{13}{12}\right)\\= \frac{-15}{7}-\frac{13}{12}\\=\frac{-180}{84}-\frac{91}{84}\\=\frac{-180-91}{84}\\=\frac{-271}{84}\)
2. \(+\left(\frac{6}{11}\right)-\left(\frac{-12}{-11}\right)\\= \frac{6}{11}-\frac{12}{11}\\=\frac{6-12}{11}\\=\frac{-6}{11}\)
3. \(+\left(\frac{2}{11}\right)-\left(\frac{-10}{11}\right)\\= \frac{2}{11}+\frac{10}{11}\\=\frac{2+10}{11}\\=\frac{12}{11}\)
4. \(+\left(\frac{-15}{7}\right)-\left(\frac{-5}{6}\right)\\= \frac{-15}{7}+\frac{5}{6}\\=\frac{-90}{42}+\frac{35}{42}\\=\frac{-90+35}{42}\\=\frac{-55}{42}\)
5. \(-\left(\frac{4}{-13}\right)+\left(\frac{-14}{-3}\right)\\= \frac{4}{13}+\frac{14}{3}\\=\frac{12}{39}+\frac{182}{39}\\=\frac{12+182}{39}\\=\frac{194}{39}\)
6. \(+\left(\frac{3}{10}\right)-\left(\frac{4}{-3}\right)\\= \frac{3}{10}+\frac{4}{3}\\=\frac{9}{30}+\frac{40}{30}\\=\frac{9+40}{30}\\=\frac{49}{30}\)
7. \(+\left(\frac{3}{2}\right)-\left(\frac{15}{-13}\right)\\= \frac{3}{2}+\frac{15}{13}\\=\frac{39}{26}+\frac{30}{26}\\=\frac{39+30}{26}\\=\frac{69}{26}\)
8. \(-\left(\frac{-9}{13}\right)-\left(\frac{5}{14}\right)\\= \frac{9}{13}-\frac{5}{14}\\=\frac{126}{182}-\frac{65}{182}\\=\frac{126-65}{182}\\=\frac{61}{182}\)
9. \(+\left(\frac{-5}{6}\right)+\left(\frac{12}{7}\right)\\= \frac{-5}{6}+\frac{12}{7}\\=\frac{-35}{42}+\frac{72}{42}\\=\frac{-35+72}{42}\\=\frac{37}{42}\)
10. \(+\left(\frac{-6}{13}\right)-\left(\frac{8}{7}\right)\\= \frac{-6}{13}-\frac{8}{7}\\=\frac{-42}{91}-\frac{104}{91}\\=\frac{-42-104}{91}\\=\frac{-146}{91}\)
11. \(+\left(\frac{5}{8}\right)-\left(\frac{11}{-3}\right)\\= \frac{5}{8}+\frac{11}{3}\\=\frac{15}{24}+\frac{88}{24}\\=\frac{15+88}{24}\\=\frac{103}{24}\)
12. \(-\left(\frac{7}{8}\right)-\left(\frac{11}{-12}\right)\\= \frac{-7}{8}+\frac{11}{12}\\=\frac{-21}{24}+\frac{22}{24}\\=\frac{-21+22}{24}\\=\frac{1}{24}\)