Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-7}{-12}\right)+\left(\frac{10}{7}\right)\)
2. \(+\left(\frac{-12}{11}\right)-\left(\frac{-12}{-11}\right)\)
3. \(-\left(\frac{13}{-9}\right)+\left(\frac{-6}{-7}\right)\)
4. \(+\left(\frac{5}{-6}\right)+\left(\frac{7}{-4}\right)\)
5. \(+\left(\frac{11}{9}\right)-\left(\frac{4}{3}\right)\)
6. \(-\left(\frac{-6}{11}\right)+\left(\frac{-2}{-13}\right)\)
7. \(+\left(\frac{2}{5}\right)+\left(\frac{-12}{5}\right)\)
8. \(+\left(\frac{-14}{-13}\right)+\left(\frac{-6}{-5}\right)\)
9. \(-\left(\frac{-10}{11}\right)-\left(\frac{-2}{9}\right)\)
10. \(-\left(\frac{-10}{11}\right)-\left(\frac{14}{-9}\right)\)
11. \(+\left(\frac{-10}{-11}\right)-\left(\frac{-7}{-6}\right)\)
12. \(-\left(\frac{-10}{7}\right)-\left(\frac{8}{11}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{-7}{-12}\right)+\left(\frac{10}{7}\right)\\= \frac{-7}{12}+\frac{10}{7}\\=\frac{-49}{84}+\frac{120}{84}\\=\frac{-49+120}{84}\\=\frac{71}{84}\)
2. \(+\left(\frac{-12}{11}\right)-\left(\frac{-12}{-11}\right)\\= \frac{-12}{11}-\frac{12}{11}\\=\frac{-12-12}{11}\\=\frac{-24}{11}\)
3. \(-\left(\frac{13}{-9}\right)+\left(\frac{-6}{-7}\right)\\= \frac{13}{9}+\frac{6}{7}\\=\frac{91}{63}+\frac{54}{63}\\=\frac{91+54}{63}\\=\frac{145}{63}\)
4. \(+\left(\frac{5}{-6}\right)+\left(\frac{7}{-4}\right)\\= \frac{-5}{6}-\frac{7}{4}\\=\frac{-10}{12}-\frac{21}{12}\\=\frac{-10-21}{12}\\=\frac{-31}{12}\)
5. \(+\left(\frac{11}{9}\right)-\left(\frac{4}{3}\right)\\= \frac{11}{9}-\frac{4}{3}\\=\frac{11-4}{9}\\=\frac{7}{9}\)
6. \(-\left(\frac{-6}{11}\right)+\left(\frac{-2}{-13}\right)\\= \frac{6}{11}+\frac{2}{13}\\=\frac{78}{143}+\frac{22}{143}\\=\frac{78+22}{143}\\=\frac{100}{143}\)
7. \(+\left(\frac{2}{5}\right)+\left(\frac{-12}{5}\right)\\= \frac{2}{5}-\frac{12}{5}\\=\frac{2-12}{5}\\=\frac{-10}{5}\\=\frac{-2}{1}\)
8. \(+\left(\frac{-14}{-13}\right)+\left(\frac{-6}{-5}\right)\\= \frac{14}{13}+\frac{6}{5}\\=\frac{70}{65}+\frac{78}{65}\\=\frac{70+78}{65}\\=\frac{148}{65}\)
9. \(-\left(\frac{-10}{11}\right)-\left(\frac{-2}{9}\right)\\= \frac{10}{11}+\frac{2}{9}\\=\frac{90}{99}+\frac{22}{99}\\=\frac{90+22}{99}\\=\frac{112}{99}\)
10. \(-\left(\frac{-10}{11}\right)-\left(\frac{14}{-9}\right)\\= \frac{10}{11}+\frac{14}{9}\\=\frac{90}{99}+\frac{154}{99}\\=\frac{90+154}{99}\\=\frac{244}{99}\)
11. \(+\left(\frac{-10}{-11}\right)-\left(\frac{-7}{-6}\right)\\= \frac{10}{11}-\frac{7}{6}\\=\frac{60}{66}-\frac{77}{66}\\=\frac{60-77}{66}\\=\frac{-17}{66}\)
12. \(-\left(\frac{-10}{7}\right)-\left(\frac{8}{11}\right)\\= \frac{10}{7}-\frac{8}{11}\\=\frac{110}{77}-\frac{56}{77}\\=\frac{110-56}{77}\\=\frac{54}{77}\)