Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-2}{-13}\right)-\left(\frac{-4}{-11}\right)\)
2. \(+\left(\frac{8}{9}\right)+\left(\frac{14}{9}\right)\)
3. \(-\left(\frac{5}{11}\right)-\left(\frac{-6}{-7}\right)\)
4. \(-\left(\frac{-3}{4}\right)+\left(\frac{9}{2}\right)\)
5. \(-\left(\frac{12}{11}\right)-\left(\frac{10}{7}\right)\)
6. \(+\left(\frac{3}{-5}\right)-\left(\frac{4}{-3}\right)\)
7. \(-\left(\frac{-12}{5}\right)+\left(\frac{-9}{-4}\right)\)
8. \(+\left(\frac{-5}{-8}\right)-\left(\frac{-13}{-9}\right)\)
9. \(+\left(\frac{-11}{4}\right)+\left(\frac{-9}{7}\right)\)
10. \(-\left(\frac{8}{5}\right)-\left(\frac{9}{8}\right)\)
11. \(-\left(\frac{3}{-10}\right)+\left(\frac{-11}{-4}\right)\)
12. \(+\left(\frac{-7}{3}\right)+\left(\frac{-14}{9}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{-2}{-13}\right)-\left(\frac{-4}{-11}\right)\\= \frac{-2}{13}-\frac{4}{11}\\=\frac{-22}{143}-\frac{52}{143}\\=\frac{-22-52}{143}\\=\frac{-74}{143}\)
2. \(+\left(\frac{8}{9}\right)+\left(\frac{14}{9}\right)\\= \frac{8}{9}+\frac{14}{9}\\=\frac{8+14}{9}\\=\frac{22}{9}\)
3. \(-\left(\frac{5}{11}\right)-\left(\frac{-6}{-7}\right)\\= \frac{-5}{11}-\frac{6}{7}\\=\frac{-35}{77}-\frac{66}{77}\\=\frac{-35-66}{77}\\=\frac{-101}{77}\)
4. \(-\left(\frac{-3}{4}\right)+\left(\frac{9}{2}\right)\\= \frac{3}{4}+\frac{9}{2}\\=\frac{3+9}{4}\\=\frac{12}{4}\\=\frac{3}{1}\)
5. \(-\left(\frac{12}{11}\right)-\left(\frac{10}{7}\right)\\= \frac{-12}{11}-\frac{10}{7}\\=\frac{-84}{77}-\frac{110}{77}\\=\frac{-84-110}{77}\\=\frac{-194}{77}\)
6. \(+\left(\frac{3}{-5}\right)-\left(\frac{4}{-3}\right)\\= \frac{-3}{5}+\frac{4}{3}\\=\frac{-9}{15}+\frac{20}{15}\\=\frac{-9+20}{15}\\=\frac{11}{15}\)
7. \(-\left(\frac{-12}{5}\right)+\left(\frac{-9}{-4}\right)\\= \frac{12}{5}+\frac{9}{4}\\=\frac{48}{20}+\frac{45}{20}\\=\frac{48+45}{20}\\=\frac{93}{20}\)
8. \(+\left(\frac{-5}{-8}\right)-\left(\frac{-13}{-9}\right)\\= \frac{5}{8}-\frac{13}{9}\\=\frac{45}{72}-\frac{104}{72}\\=\frac{45-104}{72}\\=\frac{-59}{72}\)
9. \(+\left(\frac{-11}{4}\right)+\left(\frac{-9}{7}\right)\\= \frac{-11}{4}-\frac{9}{7}\\=\frac{-77}{28}-\frac{36}{28}\\=\frac{-77-36}{28}\\=\frac{-113}{28}\)
10. \(-\left(\frac{8}{5}\right)-\left(\frac{9}{8}\right)\\= \frac{-8}{5}-\frac{9}{8}\\=\frac{-64}{40}-\frac{45}{40}\\=\frac{-64-45}{40}\\=\frac{-109}{40}\)
11. \(-\left(\frac{3}{-10}\right)+\left(\frac{-11}{-4}\right)\\= \frac{3}{10}+\frac{11}{4}\\=\frac{6}{20}+\frac{55}{20}\\=\frac{6+55}{20}\\=\frac{61}{20}\)
12. \(+\left(\frac{-7}{3}\right)+\left(\frac{-14}{9}\right)\\= \frac{-7}{3}-\frac{14}{9}\\=\frac{-21}{9}-\frac{14}{9}\\=\frac{-21-14}{9}\\=\frac{-35}{9}\)