Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-7}{-5}\right)+\left(\frac{9}{4}\right)\)
2. \(-\left(\frac{-10}{9}\right)+\left(\frac{7}{10}\right)\)
3. \(-\left(\frac{-7}{-9}\right)-\left(\frac{15}{-11}\right)\)
4. \(+\left(\frac{11}{-12}\right)+\left(\frac{-14}{-13}\right)\)
5. \(+\left(\frac{-5}{3}\right)+\left(\frac{-10}{3}\right)\)
6. \(-\left(\frac{13}{-5}\right)-\left(\frac{-4}{3}\right)\)
7. \(-\left(\frac{-5}{-12}\right)+\left(\frac{15}{7}\right)\)
8. \(-\left(\frac{12}{-7}\right)-\left(\frac{5}{11}\right)\)
9. \(-\left(\frac{-6}{5}\right)-\left(\frac{5}{-2}\right)\)
10. \(-\left(\frac{-2}{-3}\right)+\left(\frac{-8}{-3}\right)\)
11. \(+\left(\frac{15}{2}\right)-\left(\frac{9}{-5}\right)\)
12. \(+\left(\frac{-12}{-5}\right)-\left(\frac{-12}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-7}{-5}\right)+\left(\frac{9}{4}\right)\\= \frac{-7}{5}+\frac{9}{4}\\=\frac{-28}{20}+\frac{45}{20}\\=\frac{-28+45}{20}\\=\frac{17}{20}\)
2. \(-\left(\frac{-10}{9}\right)+\left(\frac{7}{10}\right)\\= \frac{10}{9}+\frac{7}{10}\\=\frac{100}{90}+\frac{63}{90}\\=\frac{100+63}{90}\\=\frac{163}{90}\)
3. \(-\left(\frac{-7}{-9}\right)-\left(\frac{15}{-11}\right)\\= \frac{-7}{9}+\frac{15}{11}\\=\frac{-77}{99}+\frac{135}{99}\\=\frac{-77+135}{99}\\=\frac{58}{99}\)
4. \(+\left(\frac{11}{-12}\right)+\left(\frac{-14}{-13}\right)\\= \frac{-11}{12}+\frac{14}{13}\\=\frac{-143}{156}+\frac{168}{156}\\=\frac{-143+168}{156}\\=\frac{25}{156}\)
5. \(+\left(\frac{-5}{3}\right)+\left(\frac{-10}{3}\right)\\= \frac{-5}{3}-\frac{10}{3}\\=\frac{-5-10}{3}\\=\frac{-15}{3}\\=\frac{-5}{1}\)
6. \(-\left(\frac{13}{-5}\right)-\left(\frac{-4}{3}\right)\\= \frac{13}{5}+\frac{4}{3}\\=\frac{39}{15}+\frac{20}{15}\\=\frac{39+20}{15}\\=\frac{59}{15}\)
7. \(-\left(\frac{-5}{-12}\right)+\left(\frac{15}{7}\right)\\= \frac{-5}{12}+\frac{15}{7}\\=\frac{-35}{84}+\frac{180}{84}\\=\frac{-35+180}{84}\\=\frac{145}{84}\)
8. \(-\left(\frac{12}{-7}\right)-\left(\frac{5}{11}\right)\\= \frac{12}{7}-\frac{5}{11}\\=\frac{132}{77}-\frac{35}{77}\\=\frac{132-35}{77}\\=\frac{97}{77}\)
9. \(-\left(\frac{-6}{5}\right)-\left(\frac{5}{-2}\right)\\= \frac{6}{5}+\frac{5}{2}\\=\frac{12}{10}+\frac{25}{10}\\=\frac{12+25}{10}\\=\frac{37}{10}\)
10. \(-\left(\frac{-2}{-3}\right)+\left(\frac{-8}{-3}\right)\\= \frac{-2}{3}+\frac{8}{3}\\=\frac{-2+8}{3}\\=\frac{6}{3}\\=\frac{2}{1}\)
11. \(+\left(\frac{15}{2}\right)-\left(\frac{9}{-5}\right)\\= \frac{15}{2}+\frac{9}{5}\\=\frac{75}{10}+\frac{18}{10}\\=\frac{75+18}{10}\\=\frac{93}{10}\)
12. \(+\left(\frac{-12}{-5}\right)-\left(\frac{-12}{-13}\right)\\= \frac{12}{5}-\frac{12}{13}\\=\frac{156}{65}-\frac{60}{65}\\=\frac{156-60}{65}\\=\frac{96}{65}\)