Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{14}{-11}\right)-\left(\frac{4}{3}\right)\)
2. \(-\left(\frac{-8}{-5}\right)-\left(\frac{-8}{-5}\right)\)
3. \(-\left(\frac{-12}{-7}\right)-\left(\frac{13}{-4}\right)\)
4. \(-\left(\frac{8}{-11}\right)+\left(\frac{15}{11}\right)\)
5. \(-\left(\frac{14}{13}\right)+\left(\frac{10}{-3}\right)\)
6. \(+\left(\frac{13}{-2}\right)+\left(\frac{14}{-3}\right)\)
7. \(+\left(\frac{-12}{7}\right)-\left(\frac{-4}{-5}\right)\)
8. \(+\left(\frac{4}{13}\right)+\left(\frac{5}{2}\right)\)
9. \(-\left(\frac{9}{5}\right)-\left(\frac{-7}{5}\right)\)
10. \(+\left(\frac{5}{6}\right)+\left(\frac{10}{-7}\right)\)
11. \(+\left(\frac{-6}{7}\right)+\left(\frac{8}{-3}\right)\)
12. \(-\left(\frac{-15}{2}\right)+\left(\frac{-9}{-10}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{14}{-11}\right)-\left(\frac{4}{3}\right)\\= \frac{-14}{11}-\frac{4}{3}\\=\frac{-42}{33}-\frac{44}{33}\\=\frac{-42-44}{33}\\=\frac{-86}{33}\)
2. \(-\left(\frac{-8}{-5}\right)-\left(\frac{-8}{-5}\right)\\= \frac{-8}{5}-\frac{8}{5}\\=\frac{-8-8}{5}\\=\frac{-16}{5}\)
3. \(-\left(\frac{-12}{-7}\right)-\left(\frac{13}{-4}\right)\\= \frac{-12}{7}+\frac{13}{4}\\=\frac{-48}{28}+\frac{91}{28}\\=\frac{-48+91}{28}\\=\frac{43}{28}\)
4. \(-\left(\frac{8}{-11}\right)+\left(\frac{15}{11}\right)\\= \frac{8}{11}+\frac{15}{11}\\=\frac{8+15}{11}\\=\frac{23}{11}\)
5. \(-\left(\frac{14}{13}\right)+\left(\frac{10}{-3}\right)\\= \frac{-14}{13}-\frac{10}{3}\\=\frac{-42}{39}-\frac{130}{39}\\=\frac{-42-130}{39}\\=\frac{-172}{39}\)
6. \(+\left(\frac{13}{-2}\right)+\left(\frac{14}{-3}\right)\\= \frac{-13}{2}-\frac{14}{3}\\=\frac{-39}{6}-\frac{28}{6}\\=\frac{-39-28}{6}\\=\frac{-67}{6}\)
7. \(+\left(\frac{-12}{7}\right)-\left(\frac{-4}{-5}\right)\\= \frac{-12}{7}-\frac{4}{5}\\=\frac{-60}{35}-\frac{28}{35}\\=\frac{-60-28}{35}\\=\frac{-88}{35}\)
8. \(+\left(\frac{4}{13}\right)+\left(\frac{5}{2}\right)\\= \frac{4}{13}+\frac{5}{2}\\=\frac{8}{26}+\frac{65}{26}\\=\frac{8+65}{26}\\=\frac{73}{26}\)
9. \(-\left(\frac{9}{5}\right)-\left(\frac{-7}{5}\right)\\= \frac{-9}{5}+\frac{7}{5}\\=\frac{-9+7}{5}\\=\frac{-2}{5}\)
10. \(+\left(\frac{5}{6}\right)+\left(\frac{10}{-7}\right)\\= \frac{5}{6}-\frac{10}{7}\\=\frac{35}{42}-\frac{60}{42}\\=\frac{35-60}{42}\\=\frac{-25}{42}\)
11. \(+\left(\frac{-6}{7}\right)+\left(\frac{8}{-3}\right)\\= \frac{-6}{7}-\frac{8}{3}\\=\frac{-18}{21}-\frac{56}{21}\\=\frac{-18-56}{21}\\=\frac{-74}{21}\)
12. \(-\left(\frac{-15}{2}\right)+\left(\frac{-9}{-10}\right)\\= \frac{15}{2}+\frac{9}{10}\\=\frac{75}{10}+\frac{9}{10}\\=\frac{75+9}{10}\\=\frac{84}{10}\\=\frac{42}{5}\)