Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{9}{2}\right)-\left(\frac{7}{6}\right)\)
2. \(-\left(\frac{-12}{-5}\right)-\left(\frac{-5}{4}\right)\)
3. \(+\left(\frac{-2}{3}\right)+\left(\frac{-12}{-5}\right)\)
4. \(+\left(\frac{-12}{-5}\right)+\left(\frac{3}{-2}\right)\)
5. \(+\left(\frac{-15}{-14}\right)+\left(\frac{5}{-12}\right)\)
6. \(+\left(\frac{10}{3}\right)+\left(\frac{-2}{5}\right)\)
7. \(-\left(\frac{-7}{13}\right)-\left(\frac{14}{3}\right)\)
8. \(-\left(\frac{-4}{13}\right)+\left(\frac{-14}{9}\right)\)
9. \(-\left(\frac{14}{-9}\right)+\left(\frac{-10}{-7}\right)\)
10. \(-\left(\frac{2}{7}\right)+\left(\frac{-14}{-9}\right)\)
11. \(+\left(\frac{-13}{12}\right)+\left(\frac{7}{-8}\right)\)
12. \(-\left(\frac{-11}{-8}\right)+\left(\frac{-10}{13}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{9}{2}\right)-\left(\frac{7}{6}\right)\\= \frac{9}{2}-\frac{7}{6}\\=\frac{27}{6}-\frac{7}{6}\\=\frac{27-7}{6}\\=\frac{20}{6}\\=\frac{10}{3}\)
2. \(-\left(\frac{-12}{-5}\right)-\left(\frac{-5}{4}\right)\\= \frac{-12}{5}+\frac{5}{4}\\=\frac{-48}{20}+\frac{25}{20}\\=\frac{-48+25}{20}\\=\frac{-23}{20}\)
3. \(+\left(\frac{-2}{3}\right)+\left(\frac{-12}{-5}\right)\\= \frac{-2}{3}+\frac{12}{5}\\=\frac{-10}{15}+\frac{36}{15}\\=\frac{-10+36}{15}\\=\frac{26}{15}\)
4. \(+\left(\frac{-12}{-5}\right)+\left(\frac{3}{-2}\right)\\= \frac{12}{5}-\frac{3}{2}\\=\frac{24}{10}-\frac{15}{10}\\=\frac{24-15}{10}\\=\frac{9}{10}\)
5. \(+\left(\frac{-15}{-14}\right)+\left(\frac{5}{-12}\right)\\= \frac{15}{14}-\frac{5}{12}\\=\frac{90}{84}-\frac{35}{84}\\=\frac{90-35}{84}\\=\frac{55}{84}\)
6. \(+\left(\frac{10}{3}\right)+\left(\frac{-2}{5}\right)\\= \frac{10}{3}-\frac{2}{5}\\=\frac{50}{15}-\frac{6}{15}\\=\frac{50-6}{15}\\=\frac{44}{15}\)
7. \(-\left(\frac{-7}{13}\right)-\left(\frac{14}{3}\right)\\= \frac{7}{13}-\frac{14}{3}\\=\frac{21}{39}-\frac{182}{39}\\=\frac{21-182}{39}\\=\frac{-161}{39}\)
8. \(-\left(\frac{-4}{13}\right)+\left(\frac{-14}{9}\right)\\= \frac{4}{13}-\frac{14}{9}\\=\frac{36}{117}-\frac{182}{117}\\=\frac{36-182}{117}\\=\frac{-146}{117}\)
9. \(-\left(\frac{14}{-9}\right)+\left(\frac{-10}{-7}\right)\\= \frac{14}{9}+\frac{10}{7}\\=\frac{98}{63}+\frac{90}{63}\\=\frac{98+90}{63}\\=\frac{188}{63}\)
10. \(-\left(\frac{2}{7}\right)+\left(\frac{-14}{-9}\right)\\= \frac{-2}{7}+\frac{14}{9}\\=\frac{-18}{63}+\frac{98}{63}\\=\frac{-18+98}{63}\\=\frac{80}{63}\)
11. \(+\left(\frac{-13}{12}\right)+\left(\frac{7}{-8}\right)\\= \frac{-13}{12}-\frac{7}{8}\\=\frac{-26}{24}-\frac{21}{24}\\=\frac{-26-21}{24}\\=\frac{-47}{24}\)
12. \(-\left(\frac{-11}{-8}\right)+\left(\frac{-10}{13}\right)\\= \frac{-11}{8}-\frac{10}{13}\\=\frac{-143}{104}-\frac{80}{104}\\=\frac{-143-80}{104}\\=\frac{-223}{104}\)