Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-12}{-11}\right)-\left(\frac{-4}{5}\right)\)
2. \(+\left(\frac{-10}{7}\right)-\left(\frac{2}{5}\right)\)
3. \(+\left(\frac{-6}{-13}\right)+\left(\frac{-5}{7}\right)\)
4. \(+\left(\frac{8}{3}\right)-\left(\frac{-7}{-12}\right)\)
5. \(+\left(\frac{-13}{-14}\right)+\left(\frac{8}{-5}\right)\)
6. \(+\left(\frac{13}{-5}\right)-\left(\frac{15}{11}\right)\)
7. \(+\left(\frac{-12}{5}\right)-\left(\frac{11}{4}\right)\)
8. \(-\left(\frac{3}{10}\right)-\left(\frac{7}{11}\right)\)
9. \(+\left(\frac{9}{-7}\right)-\left(\frac{-5}{-3}\right)\)
10. \(+\left(\frac{13}{3}\right)-\left(\frac{15}{11}\right)\)
11. \(-\left(\frac{-5}{-2}\right)+\left(\frac{-8}{11}\right)\)
12. \(+\left(\frac{11}{12}\right)-\left(\frac{15}{7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-12}{-11}\right)-\left(\frac{-4}{5}\right)\\= \frac{12}{11}+\frac{4}{5}\\=\frac{60}{55}+\frac{44}{55}\\=\frac{60+44}{55}\\=\frac{104}{55}\)
2. \(+\left(\frac{-10}{7}\right)-\left(\frac{2}{5}\right)\\= \frac{-10}{7}-\frac{2}{5}\\=\frac{-50}{35}-\frac{14}{35}\\=\frac{-50-14}{35}\\=\frac{-64}{35}\)
3. \(+\left(\frac{-6}{-13}\right)+\left(\frac{-5}{7}\right)\\= \frac{6}{13}-\frac{5}{7}\\=\frac{42}{91}-\frac{65}{91}\\=\frac{42-65}{91}\\=\frac{-23}{91}\)
4. \(+\left(\frac{8}{3}\right)-\left(\frac{-7}{-12}\right)\\= \frac{8}{3}-\frac{7}{12}\\=\frac{32}{12}-\frac{7}{12}\\=\frac{32-7}{12}\\=\frac{25}{12}\)
5. \(+\left(\frac{-13}{-14}\right)+\left(\frac{8}{-5}\right)\\= \frac{13}{14}-\frac{8}{5}\\=\frac{65}{70}-\frac{112}{70}\\=\frac{65-112}{70}\\=\frac{-47}{70}\)
6. \(+\left(\frac{13}{-5}\right)-\left(\frac{15}{11}\right)\\= \frac{-13}{5}-\frac{15}{11}\\=\frac{-143}{55}-\frac{75}{55}\\=\frac{-143-75}{55}\\=\frac{-218}{55}\)
7. \(+\left(\frac{-12}{5}\right)-\left(\frac{11}{4}\right)\\= \frac{-12}{5}-\frac{11}{4}\\=\frac{-48}{20}-\frac{55}{20}\\=\frac{-48-55}{20}\\=\frac{-103}{20}\)
8. \(-\left(\frac{3}{10}\right)-\left(\frac{7}{11}\right)\\= \frac{-3}{10}-\frac{7}{11}\\=\frac{-33}{110}-\frac{70}{110}\\=\frac{-33-70}{110}\\=\frac{-103}{110}\)
9. \(+\left(\frac{9}{-7}\right)-\left(\frac{-5}{-3}\right)\\= \frac{-9}{7}-\frac{5}{3}\\=\frac{-27}{21}-\frac{35}{21}\\=\frac{-27-35}{21}\\=\frac{-62}{21}\)
10. \(+\left(\frac{13}{3}\right)-\left(\frac{15}{11}\right)\\= \frac{13}{3}-\frac{15}{11}\\=\frac{143}{33}-\frac{45}{33}\\=\frac{143-45}{33}\\=\frac{98}{33}\)
11. \(-\left(\frac{-5}{-2}\right)+\left(\frac{-8}{11}\right)\\= \frac{-5}{2}-\frac{8}{11}\\=\frac{-55}{22}-\frac{16}{22}\\=\frac{-55-16}{22}\\=\frac{-71}{22}\)
12. \(+\left(\frac{11}{12}\right)-\left(\frac{15}{7}\right)\\= \frac{11}{12}-\frac{15}{7}\\=\frac{77}{84}-\frac{180}{84}\\=\frac{77-180}{84}\\=\frac{-103}{84}\)