Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{9}{-11}\right)-\left(\frac{10}{-3}\right)\)
2. \(-\left(\frac{3}{5}\right)+\left(\frac{15}{4}\right)\)
3. \(+\left(\frac{4}{3}\right)-\left(\frac{-10}{-3}\right)\)
4. \(-\left(\frac{-12}{13}\right)-\left(\frac{4}{11}\right)\)
5. \(-\left(\frac{-5}{-6}\right)-\left(\frac{7}{-8}\right)\)
6. \(-\left(\frac{-15}{7}\right)+\left(\frac{-12}{11}\right)\)
7. \(+\left(\frac{-15}{-7}\right)-\left(\frac{9}{2}\right)\)
8. \(-\left(\frac{-10}{-7}\right)+\left(\frac{-8}{5}\right)\)
9. \(-\left(\frac{-4}{7}\right)+\left(\frac{-9}{14}\right)\)
10. \(-\left(\frac{4}{9}\right)+\left(\frac{9}{-14}\right)\)
11. \(-\left(\frac{9}{-8}\right)-\left(\frac{10}{-3}\right)\)
12. \(-\left(\frac{-2}{-3}\right)+\left(\frac{15}{4}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{9}{-11}\right)-\left(\frac{10}{-3}\right)\\= \frac{9}{11}+\frac{10}{3}\\=\frac{27}{33}+\frac{110}{33}\\=\frac{27+110}{33}\\=\frac{137}{33}\)
2. \(-\left(\frac{3}{5}\right)+\left(\frac{15}{4}\right)\\= \frac{-3}{5}+\frac{15}{4}\\=\frac{-12}{20}+\frac{75}{20}\\=\frac{-12+75}{20}\\=\frac{63}{20}\)
3. \(+\left(\frac{4}{3}\right)-\left(\frac{-10}{-3}\right)\\= \frac{4}{3}-\frac{10}{3}\\=\frac{4-10}{3}\\=\frac{-6}{3}\\=\frac{-2}{1}\)
4. \(-\left(\frac{-12}{13}\right)-\left(\frac{4}{11}\right)\\= \frac{12}{13}-\frac{4}{11}\\=\frac{132}{143}-\frac{52}{143}\\=\frac{132-52}{143}\\=\frac{80}{143}\)
5. \(-\left(\frac{-5}{-6}\right)-\left(\frac{7}{-8}\right)\\= \frac{-5}{6}+\frac{7}{8}\\=\frac{-20}{24}+\frac{21}{24}\\=\frac{-20+21}{24}\\=\frac{1}{24}\)
6. \(-\left(\frac{-15}{7}\right)+\left(\frac{-12}{11}\right)\\= \frac{15}{7}-\frac{12}{11}\\=\frac{165}{77}-\frac{84}{77}\\=\frac{165-84}{77}\\=\frac{81}{77}\)
7. \(+\left(\frac{-15}{-7}\right)-\left(\frac{9}{2}\right)\\= \frac{15}{7}-\frac{9}{2}\\=\frac{30}{14}-\frac{63}{14}\\=\frac{30-63}{14}\\=\frac{-33}{14}\)
8. \(-\left(\frac{-10}{-7}\right)+\left(\frac{-8}{5}\right)\\= \frac{-10}{7}-\frac{8}{5}\\=\frac{-50}{35}-\frac{56}{35}\\=\frac{-50-56}{35}\\=\frac{-106}{35}\)
9. \(-\left(\frac{-4}{7}\right)+\left(\frac{-9}{14}\right)\\= \frac{4}{7}-\frac{9}{14}\\=\frac{8}{14}-\frac{9}{14}\\=\frac{8-9}{14}\\=\frac{-1}{14}\)
10. \(-\left(\frac{4}{9}\right)+\left(\frac{9}{-14}\right)\\= \frac{-4}{9}-\frac{9}{14}\\=\frac{-56}{126}-\frac{81}{126}\\=\frac{-56-81}{126}\\=\frac{-137}{126}\)
11. \(-\left(\frac{9}{-8}\right)-\left(\frac{10}{-3}\right)\\= \frac{9}{8}+\frac{10}{3}\\=\frac{27}{24}+\frac{80}{24}\\=\frac{27+80}{24}\\=\frac{107}{24}\)
12. \(-\left(\frac{-2}{-3}\right)+\left(\frac{15}{4}\right)\\= \frac{-2}{3}+\frac{15}{4}\\=\frac{-8}{12}+\frac{45}{12}\\=\frac{-8+45}{12}\\=\frac{37}{12}\)