Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{9}{-14}\right)-\left(\frac{-12}{13}\right)\)
2. \(+\left(\frac{-11}{6}\right)+\left(\frac{-12}{13}\right)\)
3. \(-\left(\frac{-13}{8}\right)-\left(\frac{6}{11}\right)\)
4. \(-\left(\frac{-14}{3}\right)-\left(\frac{12}{11}\right)\)
5. \(+\left(\frac{-10}{-3}\right)+\left(\frac{2}{13}\right)\)
6. \(-\left(\frac{-4}{5}\right)+\left(\frac{15}{11}\right)\)
7. \(-\left(\frac{15}{13}\right)-\left(\frac{12}{5}\right)\)
8. \(-\left(\frac{10}{3}\right)-\left(\frac{-9}{4}\right)\)
9. \(-\left(\frac{14}{5}\right)+\left(\frac{11}{10}\right)\)
10. \(-\left(\frac{5}{-6}\right)-\left(\frac{-15}{-11}\right)\)
11. \(-\left(\frac{14}{-11}\right)+\left(\frac{-2}{3}\right)\)
12. \(+\left(\frac{-3}{4}\right)+\left(\frac{3}{-2}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{9}{-14}\right)-\left(\frac{-12}{13}\right)\\= \frac{9}{14}+\frac{12}{13}\\=\frac{117}{182}+\frac{168}{182}\\=\frac{117+168}{182}\\=\frac{285}{182}\)
2. \(+\left(\frac{-11}{6}\right)+\left(\frac{-12}{13}\right)\\= \frac{-11}{6}-\frac{12}{13}\\=\frac{-143}{78}-\frac{72}{78}\\=\frac{-143-72}{78}\\=\frac{-215}{78}\)
3. \(-\left(\frac{-13}{8}\right)-\left(\frac{6}{11}\right)\\= \frac{13}{8}-\frac{6}{11}\\=\frac{143}{88}-\frac{48}{88}\\=\frac{143-48}{88}\\=\frac{95}{88}\)
4. \(-\left(\frac{-14}{3}\right)-\left(\frac{12}{11}\right)\\= \frac{14}{3}-\frac{12}{11}\\=\frac{154}{33}-\frac{36}{33}\\=\frac{154-36}{33}\\=\frac{118}{33}\)
5. \(+\left(\frac{-10}{-3}\right)+\left(\frac{2}{13}\right)\\= \frac{10}{3}+\frac{2}{13}\\=\frac{130}{39}+\frac{6}{39}\\=\frac{130+6}{39}\\=\frac{136}{39}\)
6. \(-\left(\frac{-4}{5}\right)+\left(\frac{15}{11}\right)\\= \frac{4}{5}+\frac{15}{11}\\=\frac{44}{55}+\frac{75}{55}\\=\frac{44+75}{55}\\=\frac{119}{55}\)
7. \(-\left(\frac{15}{13}\right)-\left(\frac{12}{5}\right)\\= \frac{-15}{13}-\frac{12}{5}\\=\frac{-75}{65}-\frac{156}{65}\\=\frac{-75-156}{65}\\=\frac{-231}{65}\)
8. \(-\left(\frac{10}{3}\right)-\left(\frac{-9}{4}\right)\\= \frac{-10}{3}+\frac{9}{4}\\=\frac{-40}{12}+\frac{27}{12}\\=\frac{-40+27}{12}\\=\frac{-13}{12}\)
9. \(-\left(\frac{14}{5}\right)+\left(\frac{11}{10}\right)\\= \frac{-14}{5}+\frac{11}{10}\\=\frac{-28}{10}+\frac{11}{10}\\=\frac{-28+11}{10}\\=\frac{-17}{10}\)
10. \(-\left(\frac{5}{-6}\right)-\left(\frac{-15}{-11}\right)\\= \frac{5}{6}-\frac{15}{11}\\=\frac{55}{66}-\frac{90}{66}\\=\frac{55-90}{66}\\=\frac{-35}{66}\)
11. \(-\left(\frac{14}{-11}\right)+\left(\frac{-2}{3}\right)\\= \frac{14}{11}-\frac{2}{3}\\=\frac{42}{33}-\frac{22}{33}\\=\frac{42-22}{33}\\=\frac{20}{33}\)
12. \(+\left(\frac{-3}{4}\right)+\left(\frac{3}{-2}\right)\\= \frac{-3}{4}-\frac{3}{2}\\=\frac{-3-3}{4}\\=\frac{-6}{4}\\=\frac{-3}{2}\)