Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-8}{3}\right)-\left(\frac{11}{-12}\right)\)
2. \(-\left(\frac{7}{5}\right)-\left(\frac{5}{4}\right)\)
3. \(-\left(\frac{11}{10}\right)+\left(\frac{11}{-5}\right)\)
4. \(+\left(\frac{-8}{-13}\right)+\left(\frac{-12}{13}\right)\)
5. \(-\left(\frac{-10}{-7}\right)-\left(\frac{-15}{-4}\right)\)
6. \(-\left(\frac{-6}{11}\right)+\left(\frac{7}{9}\right)\)
7. \(+\left(\frac{-15}{4}\right)+\left(\frac{12}{-5}\right)\)
8. \(+\left(\frac{14}{11}\right)-\left(\frac{12}{11}\right)\)
9. \(+\left(\frac{-10}{-3}\right)+\left(\frac{4}{-5}\right)\)
10. \(-\left(\frac{-9}{14}\right)-\left(\frac{-3}{-5}\right)\)
11. \(+\left(\frac{10}{-7}\right)-\left(\frac{14}{5}\right)\)
12. \(+\left(\frac{-11}{-12}\right)-\left(\frac{7}{2}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-8}{3}\right)-\left(\frac{11}{-12}\right)\\= \frac{8}{3}+\frac{11}{12}\\=\frac{32}{12}+\frac{11}{12}\\=\frac{32+11}{12}\\=\frac{43}{12}\)
2. \(-\left(\frac{7}{5}\right)-\left(\frac{5}{4}\right)\\= \frac{-7}{5}-\frac{5}{4}\\=\frac{-28}{20}-\frac{25}{20}\\=\frac{-28-25}{20}\\=\frac{-53}{20}\)
3. \(-\left(\frac{11}{10}\right)+\left(\frac{11}{-5}\right)\\= \frac{-11}{10}-\frac{11}{5}\\=\frac{-11-11}{10}\\=\frac{-22}{10}\\=\frac{-11}{5}\)
4. \(+\left(\frac{-8}{-13}\right)+\left(\frac{-12}{13}\right)\\= \frac{8}{13}-\frac{12}{13}\\=\frac{8-12}{13}\\=\frac{-4}{13}\)
5. \(-\left(\frac{-10}{-7}\right)-\left(\frac{-15}{-4}\right)\\= \frac{-10}{7}-\frac{15}{4}\\=\frac{-40}{28}-\frac{105}{28}\\=\frac{-40-105}{28}\\=\frac{-145}{28}\)
6. \(-\left(\frac{-6}{11}\right)+\left(\frac{7}{9}\right)\\= \frac{6}{11}+\frac{7}{9}\\=\frac{54}{99}+\frac{77}{99}\\=\frac{54+77}{99}\\=\frac{131}{99}\)
7. \(+\left(\frac{-15}{4}\right)+\left(\frac{12}{-5}\right)\\= \frac{-15}{4}-\frac{12}{5}\\=\frac{-75}{20}-\frac{48}{20}\\=\frac{-75-48}{20}\\=\frac{-123}{20}\)
8. \(+\left(\frac{14}{11}\right)-\left(\frac{12}{11}\right)\\= \frac{14}{11}-\frac{12}{11}\\=\frac{14-12}{11}\\=\frac{2}{11}\)
9. \(+\left(\frac{-10}{-3}\right)+\left(\frac{4}{-5}\right)\\= \frac{10}{3}-\frac{4}{5}\\=\frac{50}{15}-\frac{12}{15}\\=\frac{50-12}{15}\\=\frac{38}{15}\)
10. \(-\left(\frac{-9}{14}\right)-\left(\frac{-3}{-5}\right)\\= \frac{9}{14}-\frac{3}{5}\\=\frac{45}{70}-\frac{42}{70}\\=\frac{45-42}{70}\\=\frac{3}{70}\)
11. \(+\left(\frac{10}{-7}\right)-\left(\frac{14}{5}\right)\\= \frac{-10}{7}-\frac{14}{5}\\=\frac{-50}{35}-\frac{98}{35}\\=\frac{-50-98}{35}\\=\frac{-148}{35}\)
12. \(+\left(\frac{-11}{-12}\right)-\left(\frac{7}{2}\right)\\= \frac{11}{12}-\frac{7}{2}\\=\frac{11-7}{12}\\=\frac{4}{12}\\=\frac{1}{3}\)