Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{8}{13}\right)-\left(\frac{-11}{-8}\right)\)
2. \(+\left(\frac{4}{3}\right)+\left(\frac{13}{14}\right)\)
3. \(+\left(\frac{5}{-2}\right)-\left(\frac{14}{3}\right)\)
4. \(-\left(\frac{4}{-3}\right)-\left(\frac{7}{-2}\right)\)
5. \(-\left(\frac{6}{-7}\right)-\left(\frac{10}{13}\right)\)
6. \(-\left(\frac{13}{-4}\right)+\left(\frac{10}{-3}\right)\)
7. \(+\left(\frac{7}{-8}\right)-\left(\frac{3}{-2}\right)\)
8. \(-\left(\frac{3}{8}\right)-\left(\frac{-15}{-2}\right)\)
9. \(-\left(\frac{6}{-5}\right)+\left(\frac{-9}{2}\right)\)
10. \(+\left(\frac{-9}{8}\right)-\left(\frac{-6}{5}\right)\)
11. \(+\left(\frac{3}{-11}\right)-\left(\frac{-2}{-3}\right)\)
12. \(+\left(\frac{5}{6}\right)+\left(\frac{10}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{8}{13}\right)-\left(\frac{-11}{-8}\right)\\= \frac{8}{13}-\frac{11}{8}\\=\frac{64}{104}-\frac{143}{104}\\=\frac{64-143}{104}\\=\frac{-79}{104}\)
2. \(+\left(\frac{4}{3}\right)+\left(\frac{13}{14}\right)\\= \frac{4}{3}+\frac{13}{14}\\=\frac{56}{42}+\frac{39}{42}\\=\frac{56+39}{42}\\=\frac{95}{42}\)
3. \(+\left(\frac{5}{-2}\right)-\left(\frac{14}{3}\right)\\= \frac{-5}{2}-\frac{14}{3}\\=\frac{-15}{6}-\frac{28}{6}\\=\frac{-15-28}{6}\\=\frac{-43}{6}\)
4. \(-\left(\frac{4}{-3}\right)-\left(\frac{7}{-2}\right)\\= \frac{4}{3}+\frac{7}{2}\\=\frac{8}{6}+\frac{21}{6}\\=\frac{8+21}{6}\\=\frac{29}{6}\)
5. \(-\left(\frac{6}{-7}\right)-\left(\frac{10}{13}\right)\\= \frac{6}{7}-\frac{10}{13}\\=\frac{78}{91}-\frac{70}{91}\\=\frac{78-70}{91}\\=\frac{8}{91}\)
6. \(-\left(\frac{13}{-4}\right)+\left(\frac{10}{-3}\right)\\= \frac{13}{4}-\frac{10}{3}\\=\frac{39}{12}-\frac{40}{12}\\=\frac{39-40}{12}\\=\frac{-1}{12}\)
7. \(+\left(\frac{7}{-8}\right)-\left(\frac{3}{-2}\right)\\= \frac{-7}{8}+\frac{3}{2}\\=\frac{-7+3}{8}\\=\frac{-4}{8}\\=\frac{-1}{2}\)
8. \(-\left(\frac{3}{8}\right)-\left(\frac{-15}{-2}\right)\\= \frac{-3}{8}-\frac{15}{2}\\=\frac{-3-15}{8}\\=\frac{-18}{8}\\=\frac{-9}{4}\)
9. \(-\left(\frac{6}{-5}\right)+\left(\frac{-9}{2}\right)\\= \frac{6}{5}-\frac{9}{2}\\=\frac{12}{10}-\frac{45}{10}\\=\frac{12-45}{10}\\=\frac{-33}{10}\)
10. \(+\left(\frac{-9}{8}\right)-\left(\frac{-6}{5}\right)\\= \frac{-9}{8}+\frac{6}{5}\\=\frac{-45}{40}+\frac{48}{40}\\=\frac{-45+48}{40}\\=\frac{3}{40}\)
11. \(+\left(\frac{3}{-11}\right)-\left(\frac{-2}{-3}\right)\\= \frac{-3}{11}-\frac{2}{3}\\=\frac{-9}{33}-\frac{22}{33}\\=\frac{-9-22}{33}\\=\frac{-31}{33}\)
12. \(+\left(\frac{5}{6}\right)+\left(\frac{10}{-7}\right)\\= \frac{5}{6}-\frac{10}{7}\\=\frac{35}{42}-\frac{60}{42}\\=\frac{35-60}{42}\\=\frac{-25}{42}\)