Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{12}{-5}\right)-\left(\frac{-3}{-5}\right)\)
2. \(+\left(\frac{-3}{-4}\right)+\left(\frac{7}{2}\right)\)
3. \(-\left(\frac{11}{-6}\right)+\left(\frac{12}{-11}\right)\)
4. \(-\left(\frac{-9}{-10}\right)-\left(\frac{-10}{7}\right)\)
5. \(+\left(\frac{-14}{13}\right)+\left(\frac{-14}{3}\right)\)
6. \(-\left(\frac{-8}{9}\right)+\left(\frac{7}{4}\right)\)
7. \(-\left(\frac{-2}{5}\right)-\left(\frac{-7}{3}\right)\)
8. \(-\left(\frac{-3}{2}\right)+\left(\frac{-11}{-2}\right)\)
9. \(+\left(\frac{-7}{8}\right)-\left(\frac{12}{-7}\right)\)
10. \(-\left(\frac{9}{2}\right)-\left(\frac{2}{-11}\right)\)
11. \(-\left(\frac{15}{-14}\right)+\left(\frac{-7}{3}\right)\)
12. \(-\left(\frac{4}{3}\right)+\left(\frac{11}{6}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{12}{-5}\right)-\left(\frac{-3}{-5}\right)\\= \frac{12}{5}-\frac{3}{5}\\=\frac{12-3}{5}\\=\frac{9}{5}\)
2. \(+\left(\frac{-3}{-4}\right)+\left(\frac{7}{2}\right)\\= \frac{3}{4}+\frac{7}{2}\\=\frac{3+7}{4}\\=\frac{10}{4}\\=\frac{5}{2}\)
3. \(-\left(\frac{11}{-6}\right)+\left(\frac{12}{-11}\right)\\= \frac{11}{6}-\frac{12}{11}\\=\frac{121}{66}-\frac{72}{66}\\=\frac{121-72}{66}\\=\frac{49}{66}\)
4. \(-\left(\frac{-9}{-10}\right)-\left(\frac{-10}{7}\right)\\= \frac{-9}{10}+\frac{10}{7}\\=\frac{-63}{70}+\frac{100}{70}\\=\frac{-63+100}{70}\\=\frac{37}{70}\)
5. \(+\left(\frac{-14}{13}\right)+\left(\frac{-14}{3}\right)\\= \frac{-14}{13}-\frac{14}{3}\\=\frac{-42}{39}-\frac{182}{39}\\=\frac{-42-182}{39}\\=\frac{-224}{39}\)
6. \(-\left(\frac{-8}{9}\right)+\left(\frac{7}{4}\right)\\= \frac{8}{9}+\frac{7}{4}\\=\frac{32}{36}+\frac{63}{36}\\=\frac{32+63}{36}\\=\frac{95}{36}\)
7. \(-\left(\frac{-2}{5}\right)-\left(\frac{-7}{3}\right)\\= \frac{2}{5}+\frac{7}{3}\\=\frac{6}{15}+\frac{35}{15}\\=\frac{6+35}{15}\\=\frac{41}{15}\)
8. \(-\left(\frac{-3}{2}\right)+\left(\frac{-11}{-2}\right)\\= \frac{3}{2}+\frac{11}{2}\\=\frac{3+11}{2}\\=\frac{14}{2}\\=\frac{7}{1}\)
9. \(+\left(\frac{-7}{8}\right)-\left(\frac{12}{-7}\right)\\= \frac{-7}{8}+\frac{12}{7}\\=\frac{-49}{56}+\frac{96}{56}\\=\frac{-49+96}{56}\\=\frac{47}{56}\)
10. \(-\left(\frac{9}{2}\right)-\left(\frac{2}{-11}\right)\\= \frac{-9}{2}+\frac{2}{11}\\=\frac{-99}{22}+\frac{4}{22}\\=\frac{-99+4}{22}\\=\frac{-95}{22}\)
11. \(-\left(\frac{15}{-14}\right)+\left(\frac{-7}{3}\right)\\= \frac{15}{14}-\frac{7}{3}\\=\frac{45}{42}-\frac{98}{42}\\=\frac{45-98}{42}\\=\frac{-53}{42}\)
12. \(-\left(\frac{4}{3}\right)+\left(\frac{11}{6}\right)\\= \frac{-4}{3}+\frac{11}{6}\\=\frac{-8}{6}+\frac{11}{6}\\=\frac{-8+11}{6}\\=\frac{3}{6}\\=\frac{1}{2}\)