Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{11}{6}\right)+\left(\frac{-10}{7}\right)\)
2. \(+\left(\frac{-7}{2}\right)+\left(\frac{3}{4}\right)\)
3. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-11}{10}\right)\)
4. \(+\left(\frac{13}{-2}\right)-\left(\frac{-2}{-5}\right)\)
5. \(-\left(\frac{5}{12}\right)-\left(\frac{7}{-5}\right)\)
6. \(+\left(\frac{-12}{11}\right)-\left(\frac{5}{-13}\right)\)
7. \(-\left(\frac{12}{5}\right)-\left(\frac{-14}{-9}\right)\)
8. \(-\left(\frac{-11}{-2}\right)-\left(\frac{-6}{-13}\right)\)
9. \(-\left(\frac{-4}{-13}\right)+\left(\frac{-9}{10}\right)\)
10. \(+\left(\frac{-11}{-12}\right)+\left(\frac{14}{-11}\right)\)
11. \(+\left(\frac{13}{2}\right)+\left(\frac{-15}{-4}\right)\)
12. \(+\left(\frac{-7}{-10}\right)+\left(\frac{9}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{11}{6}\right)+\left(\frac{-10}{7}\right)\\= \frac{-11}{6}-\frac{10}{7}\\=\frac{-77}{42}-\frac{60}{42}\\=\frac{-77-60}{42}\\=\frac{-137}{42}\)
2. \(+\left(\frac{-7}{2}\right)+\left(\frac{3}{4}\right)\\= \frac{-7}{2}+\frac{3}{4}\\=\frac{-14}{4}+\frac{3}{4}\\=\frac{-14+3}{4}\\=\frac{-11}{4}\)
3. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-11}{10}\right)\\= \frac{4}{3}+\frac{11}{10}\\=\frac{40}{30}+\frac{33}{30}\\=\frac{40+33}{30}\\=\frac{73}{30}\)
4. \(+\left(\frac{13}{-2}\right)-\left(\frac{-2}{-5}\right)\\= \frac{-13}{2}-\frac{2}{5}\\=\frac{-65}{10}-\frac{4}{10}\\=\frac{-65-4}{10}\\=\frac{-69}{10}\)
5. \(-\left(\frac{5}{12}\right)-\left(\frac{7}{-5}\right)\\= \frac{-5}{12}+\frac{7}{5}\\=\frac{-25}{60}+\frac{84}{60}\\=\frac{-25+84}{60}\\=\frac{59}{60}\)
6. \(+\left(\frac{-12}{11}\right)-\left(\frac{5}{-13}\right)\\= \frac{-12}{11}+\frac{5}{13}\\=\frac{-156}{143}+\frac{55}{143}\\=\frac{-156+55}{143}\\=\frac{-101}{143}\)
7. \(-\left(\frac{12}{5}\right)-\left(\frac{-14}{-9}\right)\\= \frac{-12}{5}-\frac{14}{9}\\=\frac{-108}{45}-\frac{70}{45}\\=\frac{-108-70}{45}\\=\frac{-178}{45}\)
8. \(-\left(\frac{-11}{-2}\right)-\left(\frac{-6}{-13}\right)\\= \frac{-11}{2}-\frac{6}{13}\\=\frac{-143}{26}-\frac{12}{26}\\=\frac{-143-12}{26}\\=\frac{-155}{26}\)
9. \(-\left(\frac{-4}{-13}\right)+\left(\frac{-9}{10}\right)\\= \frac{-4}{13}-\frac{9}{10}\\=\frac{-40}{130}-\frac{117}{130}\\=\frac{-40-117}{130}\\=\frac{-157}{130}\)
10. \(+\left(\frac{-11}{-12}\right)+\left(\frac{14}{-11}\right)\\= \frac{11}{12}-\frac{14}{11}\\=\frac{121}{132}-\frac{168}{132}\\=\frac{121-168}{132}\\=\frac{-47}{132}\)
11. \(+\left(\frac{13}{2}\right)+\left(\frac{-15}{-4}\right)\\= \frac{13}{2}+\frac{15}{4}\\=\frac{26}{4}+\frac{15}{4}\\=\frac{26+15}{4}\\=\frac{41}{4}\)
12. \(+\left(\frac{-7}{-10}\right)+\left(\frac{9}{-13}\right)\\= \frac{7}{10}-\frac{9}{13}\\=\frac{91}{130}-\frac{90}{130}\\=\frac{91-90}{130}\\=\frac{1}{130}\)