Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{10}{-3}\right)+\left(\frac{-11}{-8}\right)\)
2. \(+\left(\frac{-7}{-11}\right)+\left(\frac{-3}{2}\right)\)
3. \(+\left(\frac{-8}{-13}\right)-\left(\frac{-6}{-11}\right)\)
4. \(-\left(\frac{-3}{11}\right)+\left(\frac{4}{7}\right)\)
5. \(-\left(\frac{-10}{9}\right)+\left(\frac{9}{13}\right)\)
6. \(-\left(\frac{13}{-5}\right)-\left(\frac{-12}{7}\right)\)
7. \(-\left(\frac{-12}{5}\right)-\left(\frac{-9}{-7}\right)\)
8. \(+\left(\frac{-14}{13}\right)-\left(\frac{6}{-13}\right)\)
9. \(+\left(\frac{4}{-13}\right)+\left(\frac{-4}{-9}\right)\)
10. \(-\left(\frac{-3}{4}\right)+\left(\frac{12}{11}\right)\)
11. \(-\left(\frac{13}{3}\right)+\left(\frac{2}{3}\right)\)
12. \(-\left(\frac{-4}{9}\right)-\left(\frac{-13}{-10}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{10}{-3}\right)+\left(\frac{-11}{-8}\right)\\= \frac{10}{3}+\frac{11}{8}\\=\frac{80}{24}+\frac{33}{24}\\=\frac{80+33}{24}\\=\frac{113}{24}\)
2. \(+\left(\frac{-7}{-11}\right)+\left(\frac{-3}{2}\right)\\= \frac{7}{11}-\frac{3}{2}\\=\frac{14}{22}-\frac{33}{22}\\=\frac{14-33}{22}\\=\frac{-19}{22}\)
3. \(+\left(\frac{-8}{-13}\right)-\left(\frac{-6}{-11}\right)\\= \frac{8}{13}-\frac{6}{11}\\=\frac{88}{143}-\frac{78}{143}\\=\frac{88-78}{143}\\=\frac{10}{143}\)
4. \(-\left(\frac{-3}{11}\right)+\left(\frac{4}{7}\right)\\= \frac{3}{11}+\frac{4}{7}\\=\frac{21}{77}+\frac{44}{77}\\=\frac{21+44}{77}\\=\frac{65}{77}\)
5. \(-\left(\frac{-10}{9}\right)+\left(\frac{9}{13}\right)\\= \frac{10}{9}+\frac{9}{13}\\=\frac{130}{117}+\frac{81}{117}\\=\frac{130+81}{117}\\=\frac{211}{117}\)
6. \(-\left(\frac{13}{-5}\right)-\left(\frac{-12}{7}\right)\\= \frac{13}{5}+\frac{12}{7}\\=\frac{91}{35}+\frac{60}{35}\\=\frac{91+60}{35}\\=\frac{151}{35}\)
7. \(-\left(\frac{-12}{5}\right)-\left(\frac{-9}{-7}\right)\\= \frac{12}{5}-\frac{9}{7}\\=\frac{84}{35}-\frac{45}{35}\\=\frac{84-45}{35}\\=\frac{39}{35}\)
8. \(+\left(\frac{-14}{13}\right)-\left(\frac{6}{-13}\right)\\= \frac{-14}{13}+\frac{6}{13}\\=\frac{-14+6}{13}\\=\frac{-8}{13}\)
9. \(+\left(\frac{4}{-13}\right)+\left(\frac{-4}{-9}\right)\\= \frac{-4}{13}+\frac{4}{9}\\=\frac{-36}{117}+\frac{52}{117}\\=\frac{-36+52}{117}\\=\frac{16}{117}\)
10. \(-\left(\frac{-3}{4}\right)+\left(\frac{12}{11}\right)\\= \frac{3}{4}+\frac{12}{11}\\=\frac{33}{44}+\frac{48}{44}\\=\frac{33+48}{44}\\=\frac{81}{44}\)
11. \(-\left(\frac{13}{3}\right)+\left(\frac{2}{3}\right)\\= \frac{-13}{3}+\frac{2}{3}\\=\frac{-13+2}{3}\\=\frac{-11}{3}\)
12. \(-\left(\frac{-4}{9}\right)-\left(\frac{-13}{-10}\right)\\= \frac{4}{9}-\frac{13}{10}\\=\frac{40}{90}-\frac{117}{90}\\=\frac{40-117}{90}\\=\frac{-77}{90}\)