Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{13}{-3}\right)+\left(\frac{-3}{10}\right)\)
2. \(-\left(\frac{3}{-4}\right)+\left(\frac{-4}{-13}\right)\)
3. \(-\left(\frac{-14}{-9}\right)-\left(\frac{13}{10}\right)\)
4. \(+\left(\frac{13}{2}\right)+\left(\frac{3}{-10}\right)\)
5. \(-\left(\frac{-13}{-9}\right)+\left(\frac{14}{-9}\right)\)
6. \(+\left(\frac{12}{-5}\right)+\left(\frac{7}{8}\right)\)
7. \(-\left(\frac{-9}{-7}\right)-\left(\frac{9}{-10}\right)\)
8. \(+\left(\frac{-15}{11}\right)-\left(\frac{-9}{-4}\right)\)
9. \(-\left(\frac{9}{-7}\right)-\left(\frac{-13}{7}\right)\)
10. \(-\left(\frac{10}{13}\right)+\left(\frac{12}{5}\right)\)
11. \(-\left(\frac{6}{5}\right)-\left(\frac{15}{11}\right)\)
12. \(-\left(\frac{10}{-13}\right)+\left(\frac{-4}{7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{13}{-3}\right)+\left(\frac{-3}{10}\right)\\= \frac{13}{3}-\frac{3}{10}\\=\frac{130}{30}-\frac{9}{30}\\=\frac{130-9}{30}\\=\frac{121}{30}\)
2. \(-\left(\frac{3}{-4}\right)+\left(\frac{-4}{-13}\right)\\= \frac{3}{4}+\frac{4}{13}\\=\frac{39}{52}+\frac{16}{52}\\=\frac{39+16}{52}\\=\frac{55}{52}\)
3. \(-\left(\frac{-14}{-9}\right)-\left(\frac{13}{10}\right)\\= \frac{-14}{9}-\frac{13}{10}\\=\frac{-140}{90}-\frac{117}{90}\\=\frac{-140-117}{90}\\=\frac{-257}{90}\)
4. \(+\left(\frac{13}{2}\right)+\left(\frac{3}{-10}\right)\\= \frac{13}{2}-\frac{3}{10}\\=\frac{65}{10}-\frac{3}{10}\\=\frac{65-3}{10}\\=\frac{62}{10}\\=\frac{31}{5}\)
5. \(-\left(\frac{-13}{-9}\right)+\left(\frac{14}{-9}\right)\\= \frac{-13}{9}-\frac{14}{9}\\=\frac{-13-14}{9}\\=\frac{-27}{9}\\=\frac{-3}{1}\)
6. \(+\left(\frac{12}{-5}\right)+\left(\frac{7}{8}\right)\\= \frac{-12}{5}+\frac{7}{8}\\=\frac{-96}{40}+\frac{35}{40}\\=\frac{-96+35}{40}\\=\frac{-61}{40}\)
7. \(-\left(\frac{-9}{-7}\right)-\left(\frac{9}{-10}\right)\\= \frac{-9}{7}+\frac{9}{10}\\=\frac{-90}{70}+\frac{63}{70}\\=\frac{-90+63}{70}\\=\frac{-27}{70}\)
8. \(+\left(\frac{-15}{11}\right)-\left(\frac{-9}{-4}\right)\\= \frac{-15}{11}-\frac{9}{4}\\=\frac{-60}{44}-\frac{99}{44}\\=\frac{-60-99}{44}\\=\frac{-159}{44}\)
9. \(-\left(\frac{9}{-7}\right)-\left(\frac{-13}{7}\right)\\= \frac{9}{7}+\frac{13}{7}\\=\frac{9+13}{7}\\=\frac{22}{7}\)
10. \(-\left(\frac{10}{13}\right)+\left(\frac{12}{5}\right)\\= \frac{-10}{13}+\frac{12}{5}\\=\frac{-50}{65}+\frac{156}{65}\\=\frac{-50+156}{65}\\=\frac{106}{65}\)
11. \(-\left(\frac{6}{5}\right)-\left(\frac{15}{11}\right)\\= \frac{-6}{5}-\frac{15}{11}\\=\frac{-66}{55}-\frac{75}{55}\\=\frac{-66-75}{55}\\=\frac{-141}{55}\)
12. \(-\left(\frac{10}{-13}\right)+\left(\frac{-4}{7}\right)\\= \frac{10}{13}-\frac{4}{7}\\=\frac{70}{91}-\frac{52}{91}\\=\frac{70-52}{91}\\=\frac{18}{91}\)