Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{7}{9}\right)-\left(\frac{-8}{-13}\right)\)
2. \(-\left(\frac{-8}{9}\right)+\left(\frac{-13}{5}\right)\)
3. \(-\left(\frac{12}{-5}\right)-\left(\frac{-5}{-4}\right)\)
4. \(+\left(\frac{4}{-9}\right)-\left(\frac{-15}{7}\right)\)
5. \(+\left(\frac{-2}{3}\right)-\left(\frac{-14}{-13}\right)\)
6. \(+\left(\frac{-2}{-3}\right)+\left(\frac{5}{14}\right)\)
7. \(-\left(\frac{-10}{-3}\right)+\left(\frac{8}{-3}\right)\)
8. \(-\left(\frac{15}{13}\right)-\left(\frac{-13}{14}\right)\)
9. \(-\left(\frac{3}{10}\right)-\left(\frac{3}{13}\right)\)
10. \(-\left(\frac{-15}{11}\right)+\left(\frac{-10}{13}\right)\)
11. \(+\left(\frac{7}{13}\right)-\left(\frac{12}{-7}\right)\)
12. \(-\left(\frac{2}{-3}\right)-\left(\frac{8}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{7}{9}\right)-\left(\frac{-8}{-13}\right)\\= \frac{-7}{9}-\frac{8}{13}\\=\frac{-91}{117}-\frac{72}{117}\\=\frac{-91-72}{117}\\=\frac{-163}{117}\)
2. \(-\left(\frac{-8}{9}\right)+\left(\frac{-13}{5}\right)\\= \frac{8}{9}-\frac{13}{5}\\=\frac{40}{45}-\frac{117}{45}\\=\frac{40-117}{45}\\=\frac{-77}{45}\)
3. \(-\left(\frac{12}{-5}\right)-\left(\frac{-5}{-4}\right)\\= \frac{12}{5}-\frac{5}{4}\\=\frac{48}{20}-\frac{25}{20}\\=\frac{48-25}{20}\\=\frac{23}{20}\)
4. \(+\left(\frac{4}{-9}\right)-\left(\frac{-15}{7}\right)\\= \frac{-4}{9}+\frac{15}{7}\\=\frac{-28}{63}+\frac{135}{63}\\=\frac{-28+135}{63}\\=\frac{107}{63}\)
5. \(+\left(\frac{-2}{3}\right)-\left(\frac{-14}{-13}\right)\\= \frac{-2}{3}-\frac{14}{13}\\=\frac{-26}{39}-\frac{42}{39}\\=\frac{-26-42}{39}\\=\frac{-68}{39}\)
6. \(+\left(\frac{-2}{-3}\right)+\left(\frac{5}{14}\right)\\= \frac{2}{3}+\frac{5}{14}\\=\frac{28}{42}+\frac{15}{42}\\=\frac{28+15}{42}\\=\frac{43}{42}\)
7. \(-\left(\frac{-10}{-3}\right)+\left(\frac{8}{-3}\right)\\= \frac{-10}{3}-\frac{8}{3}\\=\frac{-10-8}{3}\\=\frac{-18}{3}\\=\frac{-6}{1}\)
8. \(-\left(\frac{15}{13}\right)-\left(\frac{-13}{14}\right)\\= \frac{-15}{13}+\frac{13}{14}\\=\frac{-210}{182}+\frac{169}{182}\\=\frac{-210+169}{182}\\=\frac{-41}{182}\)
9. \(-\left(\frac{3}{10}\right)-\left(\frac{3}{13}\right)\\= \frac{-3}{10}-\frac{3}{13}\\=\frac{-39}{130}-\frac{30}{130}\\=\frac{-39-30}{130}\\=\frac{-69}{130}\)
10. \(-\left(\frac{-15}{11}\right)+\left(\frac{-10}{13}\right)\\= \frac{15}{11}-\frac{10}{13}\\=\frac{195}{143}-\frac{110}{143}\\=\frac{195-110}{143}\\=\frac{85}{143}\)
11. \(+\left(\frac{7}{13}\right)-\left(\frac{12}{-7}\right)\\= \frac{7}{13}+\frac{12}{7}\\=\frac{49}{91}+\frac{156}{91}\\=\frac{49+156}{91}\\=\frac{205}{91}\)
12. \(-\left(\frac{2}{-3}\right)-\left(\frac{8}{-11}\right)\\= \frac{2}{3}+\frac{8}{11}\\=\frac{22}{33}+\frac{24}{33}\\=\frac{22+24}{33}\\=\frac{46}{33}\)