Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{-3}\right)-\left(\frac{6}{-11}\right)\)
2. \(-\left(\frac{8}{5}\right)+\left(\frac{12}{-7}\right)\)
3. \(-\left(\frac{11}{-9}\right)-\left(\frac{3}{13}\right)\)
4. \(+\left(\frac{-3}{-8}\right)-\left(\frac{-11}{-12}\right)\)
5. \(+\left(\frac{-10}{3}\right)-\left(\frac{-4}{-7}\right)\)
6. \(+\left(\frac{-6}{7}\right)-\left(\frac{-4}{-11}\right)\)
7. \(+\left(\frac{-14}{3}\right)+\left(\frac{-11}{7}\right)\)
8. \(+\left(\frac{-2}{-11}\right)+\left(\frac{10}{-11}\right)\)
9. \(+\left(\frac{13}{14}\right)-\left(\frac{-14}{-13}\right)\)
10. \(-\left(\frac{9}{7}\right)+\left(\frac{7}{-9}\right)\)
11. \(+\left(\frac{-6}{-13}\right)+\left(\frac{-3}{-8}\right)\)
12. \(-\left(\frac{8}{-7}\right)-\left(\frac{-3}{10}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{10}{-3}\right)-\left(\frac{6}{-11}\right)\\= \frac{-10}{3}+\frac{6}{11}\\=\frac{-110}{33}+\frac{18}{33}\\=\frac{-110+18}{33}\\=\frac{-92}{33}\)
2. \(-\left(\frac{8}{5}\right)+\left(\frac{12}{-7}\right)\\= \frac{-8}{5}-\frac{12}{7}\\=\frac{-56}{35}-\frac{60}{35}\\=\frac{-56-60}{35}\\=\frac{-116}{35}\)
3. \(-\left(\frac{11}{-9}\right)-\left(\frac{3}{13}\right)\\= \frac{11}{9}-\frac{3}{13}\\=\frac{143}{117}-\frac{27}{117}\\=\frac{143-27}{117}\\=\frac{116}{117}\)
4. \(+\left(\frac{-3}{-8}\right)-\left(\frac{-11}{-12}\right)\\= \frac{3}{8}-\frac{11}{12}\\=\frac{9}{24}-\frac{22}{24}\\=\frac{9-22}{24}\\=\frac{-13}{24}\)
5. \(+\left(\frac{-10}{3}\right)-\left(\frac{-4}{-7}\right)\\= \frac{-10}{3}-\frac{4}{7}\\=\frac{-70}{21}-\frac{12}{21}\\=\frac{-70-12}{21}\\=\frac{-82}{21}\)
6. \(+\left(\frac{-6}{7}\right)-\left(\frac{-4}{-11}\right)\\= \frac{-6}{7}-\frac{4}{11}\\=\frac{-66}{77}-\frac{28}{77}\\=\frac{-66-28}{77}\\=\frac{-94}{77}\)
7. \(+\left(\frac{-14}{3}\right)+\left(\frac{-11}{7}\right)\\= \frac{-14}{3}-\frac{11}{7}\\=\frac{-98}{21}-\frac{33}{21}\\=\frac{-98-33}{21}\\=\frac{-131}{21}\)
8. \(+\left(\frac{-2}{-11}\right)+\left(\frac{10}{-11}\right)\\= \frac{2}{11}-\frac{10}{11}\\=\frac{2-10}{11}\\=\frac{-8}{11}\)
9. \(+\left(\frac{13}{14}\right)-\left(\frac{-14}{-13}\right)\\= \frac{13}{14}-\frac{14}{13}\\=\frac{169}{182}-\frac{196}{182}\\=\frac{169-196}{182}\\=\frac{-27}{182}\)
10. \(-\left(\frac{9}{7}\right)+\left(\frac{7}{-9}\right)\\= \frac{-9}{7}-\frac{7}{9}\\=\frac{-81}{63}-\frac{49}{63}\\=\frac{-81-49}{63}\\=\frac{-130}{63}\)
11. \(+\left(\frac{-6}{-13}\right)+\left(\frac{-3}{-8}\right)\\= \frac{6}{13}+\frac{3}{8}\\=\frac{48}{104}+\frac{39}{104}\\=\frac{48+39}{104}\\=\frac{87}{104}\)
12. \(-\left(\frac{8}{-7}\right)-\left(\frac{-3}{10}\right)\\= \frac{8}{7}+\frac{3}{10}\\=\frac{80}{70}+\frac{21}{70}\\=\frac{80+21}{70}\\=\frac{101}{70}\)