Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{9}{-10}\right)+\left(\frac{10}{11}\right)\)
2. \(+\left(\frac{12}{-11}\right)-\left(\frac{-7}{-3}\right)\)
3. \(+\left(\frac{-9}{-7}\right)-\left(\frac{15}{-11}\right)\)
4. \(-\left(\frac{-9}{-2}\right)-\left(\frac{2}{-11}\right)\)
5. \(-\left(\frac{-9}{5}\right)+\left(\frac{-6}{-11}\right)\)
6. \(-\left(\frac{13}{-9}\right)+\left(\frac{-7}{8}\right)\)
7. \(-\left(\frac{-9}{-2}\right)+\left(\frac{-7}{-6}\right)\)
8. \(+\left(\frac{6}{13}\right)-\left(\frac{3}{13}\right)\)
9. \(-\left(\frac{7}{-2}\right)-\left(\frac{2}{3}\right)\)
10. \(-\left(\frac{-15}{11}\right)+\left(\frac{-7}{-3}\right)\)
11. \(+\left(\frac{7}{-13}\right)-\left(\frac{-8}{-3}\right)\)
12. \(-\left(\frac{-9}{-4}\right)-\left(\frac{13}{-11}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{9}{-10}\right)+\left(\frac{10}{11}\right)\\= \frac{9}{10}+\frac{10}{11}\\=\frac{99}{110}+\frac{100}{110}\\=\frac{99+100}{110}\\=\frac{199}{110}\)
2. \(+\left(\frac{12}{-11}\right)-\left(\frac{-7}{-3}\right)\\= \frac{-12}{11}-\frac{7}{3}\\=\frac{-36}{33}-\frac{77}{33}\\=\frac{-36-77}{33}\\=\frac{-113}{33}\)
3. \(+\left(\frac{-9}{-7}\right)-\left(\frac{15}{-11}\right)\\= \frac{9}{7}+\frac{15}{11}\\=\frac{99}{77}+\frac{105}{77}\\=\frac{99+105}{77}\\=\frac{204}{77}\)
4. \(-\left(\frac{-9}{-2}\right)-\left(\frac{2}{-11}\right)\\= \frac{-9}{2}+\frac{2}{11}\\=\frac{-99}{22}+\frac{4}{22}\\=\frac{-99+4}{22}\\=\frac{-95}{22}\)
5. \(-\left(\frac{-9}{5}\right)+\left(\frac{-6}{-11}\right)\\= \frac{9}{5}+\frac{6}{11}\\=\frac{99}{55}+\frac{30}{55}\\=\frac{99+30}{55}\\=\frac{129}{55}\)
6. \(-\left(\frac{13}{-9}\right)+\left(\frac{-7}{8}\right)\\= \frac{13}{9}-\frac{7}{8}\\=\frac{104}{72}-\frac{63}{72}\\=\frac{104-63}{72}\\=\frac{41}{72}\)
7. \(-\left(\frac{-9}{-2}\right)+\left(\frac{-7}{-6}\right)\\= \frac{-9}{2}+\frac{7}{6}\\=\frac{-27}{6}+\frac{7}{6}\\=\frac{-27+7}{6}\\=\frac{-20}{6}\\=\frac{-10}{3}\)
8. \(+\left(\frac{6}{13}\right)-\left(\frac{3}{13}\right)\\= \frac{6}{13}-\frac{3}{13}\\=\frac{6-3}{13}\\=\frac{3}{13}\)
9. \(-\left(\frac{7}{-2}\right)-\left(\frac{2}{3}\right)\\= \frac{7}{2}-\frac{2}{3}\\=\frac{21}{6}-\frac{4}{6}\\=\frac{21-4}{6}\\=\frac{17}{6}\)
10. \(-\left(\frac{-15}{11}\right)+\left(\frac{-7}{-3}\right)\\= \frac{15}{11}+\frac{7}{3}\\=\frac{45}{33}+\frac{77}{33}\\=\frac{45+77}{33}\\=\frac{122}{33}\)
11. \(+\left(\frac{7}{-13}\right)-\left(\frac{-8}{-3}\right)\\= \frac{-7}{13}-\frac{8}{3}\\=\frac{-21}{39}-\frac{104}{39}\\=\frac{-21-104}{39}\\=\frac{-125}{39}\)
12. \(-\left(\frac{-9}{-4}\right)-\left(\frac{13}{-11}\right)\\= \frac{-9}{4}+\frac{13}{11}\\=\frac{-99}{44}+\frac{52}{44}\\=\frac{-99+52}{44}\\=\frac{-47}{44}\)