Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-14}{3}\right)-\left(\frac{13}{14}\right)\)
2. \(-\left(\frac{6}{-5}\right)+\left(\frac{-13}{5}\right)\)
3. \(-\left(\frac{-4}{3}\right)+\left(\frac{-11}{7}\right)\)
4. \(-\left(\frac{12}{5}\right)+\left(\frac{14}{-11}\right)\)
5. \(-\left(\frac{-11}{3}\right)-\left(\frac{10}{3}\right)\)
6. \(-\left(\frac{2}{7}\right)-\left(\frac{-4}{-11}\right)\)
7. \(-\left(\frac{-10}{9}\right)+\left(\frac{-15}{-13}\right)\)
8. \(-\left(\frac{-11}{6}\right)-\left(\frac{10}{9}\right)\)
9. \(+\left(\frac{10}{-11}\right)-\left(\frac{-7}{-3}\right)\)
10. \(+\left(\frac{9}{-7}\right)+\left(\frac{-15}{-4}\right)\)
11. \(-\left(\frac{3}{5}\right)-\left(\frac{-10}{-7}\right)\)
12. \(+\left(\frac{-4}{-3}\right)+\left(\frac{-2}{9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-14}{3}\right)-\left(\frac{13}{14}\right)\\= \frac{-14}{3}-\frac{13}{14}\\=\frac{-196}{42}-\frac{39}{42}\\=\frac{-196-39}{42}\\=\frac{-235}{42}\)
2. \(-\left(\frac{6}{-5}\right)+\left(\frac{-13}{5}\right)\\= \frac{6}{5}-\frac{13}{5}\\=\frac{6-13}{5}\\=\frac{-7}{5}\)
3. \(-\left(\frac{-4}{3}\right)+\left(\frac{-11}{7}\right)\\= \frac{4}{3}-\frac{11}{7}\\=\frac{28}{21}-\frac{33}{21}\\=\frac{28-33}{21}\\=\frac{-5}{21}\)
4. \(-\left(\frac{12}{5}\right)+\left(\frac{14}{-11}\right)\\= \frac{-12}{5}-\frac{14}{11}\\=\frac{-132}{55}-\frac{70}{55}\\=\frac{-132-70}{55}\\=\frac{-202}{55}\)
5. \(-\left(\frac{-11}{3}\right)-\left(\frac{10}{3}\right)\\= \frac{11}{3}-\frac{10}{3}\\=\frac{11-10}{3}\\=\frac{1}{3}\)
6. \(-\left(\frac{2}{7}\right)-\left(\frac{-4}{-11}\right)\\= \frac{-2}{7}-\frac{4}{11}\\=\frac{-22}{77}-\frac{28}{77}\\=\frac{-22-28}{77}\\=\frac{-50}{77}\)
7. \(-\left(\frac{-10}{9}\right)+\left(\frac{-15}{-13}\right)\\= \frac{10}{9}+\frac{15}{13}\\=\frac{130}{117}+\frac{135}{117}\\=\frac{130+135}{117}\\=\frac{265}{117}\)
8. \(-\left(\frac{-11}{6}\right)-\left(\frac{10}{9}\right)\\= \frac{11}{6}-\frac{10}{9}\\=\frac{33}{18}-\frac{20}{18}\\=\frac{33-20}{18}\\=\frac{13}{18}\)
9. \(+\left(\frac{10}{-11}\right)-\left(\frac{-7}{-3}\right)\\= \frac{-10}{11}-\frac{7}{3}\\=\frac{-30}{33}-\frac{77}{33}\\=\frac{-30-77}{33}\\=\frac{-107}{33}\)
10. \(+\left(\frac{9}{-7}\right)+\left(\frac{-15}{-4}\right)\\= \frac{-9}{7}+\frac{15}{4}\\=\frac{-36}{28}+\frac{105}{28}\\=\frac{-36+105}{28}\\=\frac{69}{28}\)
11. \(-\left(\frac{3}{5}\right)-\left(\frac{-10}{-7}\right)\\= \frac{-3}{5}-\frac{10}{7}\\=\frac{-21}{35}-\frac{50}{35}\\=\frac{-21-50}{35}\\=\frac{-71}{35}\)
12. \(+\left(\frac{-4}{-3}\right)+\left(\frac{-2}{9}\right)\\= \frac{4}{3}-\frac{2}{9}\\=\frac{12}{9}-\frac{2}{9}\\=\frac{12-2}{9}\\=\frac{10}{9}\)