Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-4}{-5}\right)+\left(\frac{-11}{9}\right)\)
2. \(-\left(\frac{13}{12}\right)-\left(\frac{6}{13}\right)\)
3. \(-\left(\frac{5}{2}\right)+\left(\frac{4}{9}\right)\)
4. \(-\left(\frac{-9}{14}\right)+\left(\frac{-14}{9}\right)\)
5. \(+\left(\frac{-8}{-9}\right)-\left(\frac{-3}{13}\right)\)
6. \(-\left(\frac{-11}{-12}\right)+\left(\frac{4}{3}\right)\)
7. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-5}{2}\right)\)
8. \(-\left(\frac{-11}{5}\right)-\left(\frac{4}{3}\right)\)
9. \(-\left(\frac{13}{14}\right)-\left(\frac{-13}{2}\right)\)
10. \(+\left(\frac{-4}{-11}\right)+\left(\frac{8}{-11}\right)\)
11. \(-\left(\frac{-11}{-2}\right)+\left(\frac{6}{5}\right)\)
12. \(-\left(\frac{-4}{9}\right)+\left(\frac{7}{6}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{-4}{-5}\right)+\left(\frac{-11}{9}\right)\\= \frac{-4}{5}-\frac{11}{9}\\=\frac{-36}{45}-\frac{55}{45}\\=\frac{-36-55}{45}\\=\frac{-91}{45}\)
2. \(-\left(\frac{13}{12}\right)-\left(\frac{6}{13}\right)\\= \frac{-13}{12}-\frac{6}{13}\\=\frac{-169}{156}-\frac{72}{156}\\=\frac{-169-72}{156}\\=\frac{-241}{156}\)
3. \(-\left(\frac{5}{2}\right)+\left(\frac{4}{9}\right)\\= \frac{-5}{2}+\frac{4}{9}\\=\frac{-45}{18}+\frac{8}{18}\\=\frac{-45+8}{18}\\=\frac{-37}{18}\)
4. \(-\left(\frac{-9}{14}\right)+\left(\frac{-14}{9}\right)\\= \frac{9}{14}-\frac{14}{9}\\=\frac{81}{126}-\frac{196}{126}\\=\frac{81-196}{126}\\=\frac{-115}{126}\)
5. \(+\left(\frac{-8}{-9}\right)-\left(\frac{-3}{13}\right)\\= \frac{8}{9}+\frac{3}{13}\\=\frac{104}{117}+\frac{27}{117}\\=\frac{104+27}{117}\\=\frac{131}{117}\)
6. \(-\left(\frac{-11}{-12}\right)+\left(\frac{4}{3}\right)\\= \frac{-11}{12}+\frac{4}{3}\\=\frac{-11+4}{12}\\=\frac{-7}{12}\)
7. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-5}{2}\right)\\= \frac{12}{5}-\frac{5}{2}\\=\frac{24}{10}-\frac{25}{10}\\=\frac{24-25}{10}\\=\frac{-1}{10}\)
8. \(-\left(\frac{-11}{5}\right)-\left(\frac{4}{3}\right)\\= \frac{11}{5}-\frac{4}{3}\\=\frac{33}{15}-\frac{20}{15}\\=\frac{33-20}{15}\\=\frac{13}{15}\)
9. \(-\left(\frac{13}{14}\right)-\left(\frac{-13}{2}\right)\\= \frac{-13}{14}+\frac{13}{2}\\=\frac{-13+13}{14}\\=\frac{0}{14}\\=\frac{0}{1}\)
10. \(+\left(\frac{-4}{-11}\right)+\left(\frac{8}{-11}\right)\\= \frac{4}{11}-\frac{8}{11}\\=\frac{4-8}{11}\\=\frac{-4}{11}\)
11. \(-\left(\frac{-11}{-2}\right)+\left(\frac{6}{5}\right)\\= \frac{-11}{2}+\frac{6}{5}\\=\frac{-55}{10}+\frac{12}{10}\\=\frac{-55+12}{10}\\=\frac{-43}{10}\)
12. \(-\left(\frac{-4}{9}\right)+\left(\frac{7}{6}\right)\\= \frac{4}{9}+\frac{7}{6}\\=\frac{8}{18}+\frac{21}{18}\\=\frac{8+21}{18}\\=\frac{29}{18}\)