Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-10}{9}\right)-\left(\frac{14}{3}\right)\)
2. \(+\left(\frac{8}{9}\right)+\left(\frac{12}{7}\right)\)
3. \(+\left(\frac{14}{-5}\right)+\left(\frac{-3}{2}\right)\)
4. \(+\left(\frac{-13}{-14}\right)+\left(\frac{5}{4}\right)\)
5. \(+\left(\frac{-2}{-3}\right)+\left(\frac{5}{7}\right)\)
6. \(-\left(\frac{3}{-11}\right)-\left(\frac{-10}{-3}\right)\)
7. \(-\left(\frac{8}{3}\right)+\left(\frac{15}{-4}\right)\)
8. \(-\left(\frac{-7}{-2}\right)-\left(\frac{-7}{11}\right)\)
9. \(-\left(\frac{8}{5}\right)-\left(\frac{-14}{3}\right)\)
10. \(-\left(\frac{15}{-2}\right)-\left(\frac{-8}{5}\right)\)
11. \(+\left(\frac{-7}{-8}\right)+\left(\frac{-13}{5}\right)\)
12. \(+\left(\frac{-13}{2}\right)+\left(\frac{-15}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-10}{9}\right)-\left(\frac{14}{3}\right)\\= \frac{-10}{9}-\frac{14}{3}\\=\frac{-10-14}{9}\\=\frac{-24}{9}\\=\frac{-8}{3}\)
2. \(+\left(\frac{8}{9}\right)+\left(\frac{12}{7}\right)\\= \frac{8}{9}+\frac{12}{7}\\=\frac{56}{63}+\frac{108}{63}\\=\frac{56+108}{63}\\=\frac{164}{63}\)
3. \(+\left(\frac{14}{-5}\right)+\left(\frac{-3}{2}\right)\\= \frac{-14}{5}-\frac{3}{2}\\=\frac{-28}{10}-\frac{15}{10}\\=\frac{-28-15}{10}\\=\frac{-43}{10}\)
4. \(+\left(\frac{-13}{-14}\right)+\left(\frac{5}{4}\right)\\= \frac{13}{14}+\frac{5}{4}\\=\frac{26}{28}+\frac{35}{28}\\=\frac{26+35}{28}\\=\frac{61}{28}\)
5. \(+\left(\frac{-2}{-3}\right)+\left(\frac{5}{7}\right)\\= \frac{2}{3}+\frac{5}{7}\\=\frac{14}{21}+\frac{15}{21}\\=\frac{14+15}{21}\\=\frac{29}{21}\)
6. \(-\left(\frac{3}{-11}\right)-\left(\frac{-10}{-3}\right)\\= \frac{3}{11}-\frac{10}{3}\\=\frac{9}{33}-\frac{110}{33}\\=\frac{9-110}{33}\\=\frac{-101}{33}\)
7. \(-\left(\frac{8}{3}\right)+\left(\frac{15}{-4}\right)\\= \frac{-8}{3}-\frac{15}{4}\\=\frac{-32}{12}-\frac{45}{12}\\=\frac{-32-45}{12}\\=\frac{-77}{12}\)
8. \(-\left(\frac{-7}{-2}\right)-\left(\frac{-7}{11}\right)\\= \frac{-7}{2}+\frac{7}{11}\\=\frac{-77}{22}+\frac{14}{22}\\=\frac{-77+14}{22}\\=\frac{-63}{22}\)
9. \(-\left(\frac{8}{5}\right)-\left(\frac{-14}{3}\right)\\= \frac{-8}{5}+\frac{14}{3}\\=\frac{-24}{15}+\frac{70}{15}\\=\frac{-24+70}{15}\\=\frac{46}{15}\)
10. \(-\left(\frac{15}{-2}\right)-\left(\frac{-8}{5}\right)\\= \frac{15}{2}+\frac{8}{5}\\=\frac{75}{10}+\frac{16}{10}\\=\frac{75+16}{10}\\=\frac{91}{10}\)
11. \(+\left(\frac{-7}{-8}\right)+\left(\frac{-13}{5}\right)\\= \frac{7}{8}-\frac{13}{5}\\=\frac{35}{40}-\frac{104}{40}\\=\frac{35-104}{40}\\=\frac{-69}{40}\)
12. \(+\left(\frac{-13}{2}\right)+\left(\frac{-15}{-11}\right)\\= \frac{-13}{2}+\frac{15}{11}\\=\frac{-143}{22}+\frac{30}{22}\\=\frac{-143+30}{22}\\=\frac{-113}{22}\)