Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{10}{3}\right)-\left(\frac{-4}{-13}\right)\)
2. \(-\left(\frac{-14}{3}\right)-\left(\frac{-10}{-7}\right)\)
3. \(+\left(\frac{-4}{5}\right)-\left(\frac{-9}{5}\right)\)
4. \(+\left(\frac{12}{5}\right)-\left(\frac{10}{-11}\right)\)
5. \(+\left(\frac{-15}{7}\right)-\left(\frac{10}{11}\right)\)
6. \(+\left(\frac{15}{14}\right)-\left(\frac{-10}{-13}\right)\)
7. \(+\left(\frac{-14}{3}\right)+\left(\frac{4}{7}\right)\)
8. \(-\left(\frac{3}{10}\right)-\left(\frac{-6}{13}\right)\)
9. \(-\left(\frac{5}{8}\right)+\left(\frac{-4}{7}\right)\)
10. \(-\left(\frac{-7}{4}\right)+\left(\frac{-11}{14}\right)\)
11. \(+\left(\frac{-10}{3}\right)+\left(\frac{-2}{11}\right)\)
12. \(+\left(\frac{9}{13}\right)+\left(\frac{7}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{10}{3}\right)-\left(\frac{-4}{-13}\right)\\= \frac{-10}{3}-\frac{4}{13}\\=\frac{-130}{39}-\frac{12}{39}\\=\frac{-130-12}{39}\\=\frac{-142}{39}\)
2. \(-\left(\frac{-14}{3}\right)-\left(\frac{-10}{-7}\right)\\= \frac{14}{3}-\frac{10}{7}\\=\frac{98}{21}-\frac{30}{21}\\=\frac{98-30}{21}\\=\frac{68}{21}\)
3. \(+\left(\frac{-4}{5}\right)-\left(\frac{-9}{5}\right)\\= \frac{-4}{5}+\frac{9}{5}\\=\frac{-4+9}{5}\\=\frac{5}{5}\\=\frac{1}{1}\)
4. \(+\left(\frac{12}{5}\right)-\left(\frac{10}{-11}\right)\\= \frac{12}{5}+\frac{10}{11}\\=\frac{132}{55}+\frac{50}{55}\\=\frac{132+50}{55}\\=\frac{182}{55}\)
5. \(+\left(\frac{-15}{7}\right)-\left(\frac{10}{11}\right)\\= \frac{-15}{7}-\frac{10}{11}\\=\frac{-165}{77}-\frac{70}{77}\\=\frac{-165-70}{77}\\=\frac{-235}{77}\)
6. \(+\left(\frac{15}{14}\right)-\left(\frac{-10}{-13}\right)\\= \frac{15}{14}-\frac{10}{13}\\=\frac{195}{182}-\frac{140}{182}\\=\frac{195-140}{182}\\=\frac{55}{182}\)
7. \(+\left(\frac{-14}{3}\right)+\left(\frac{4}{7}\right)\\= \frac{-14}{3}+\frac{4}{7}\\=\frac{-98}{21}+\frac{12}{21}\\=\frac{-98+12}{21}\\=\frac{-86}{21}\)
8. \(-\left(\frac{3}{10}\right)-\left(\frac{-6}{13}\right)\\= \frac{-3}{10}+\frac{6}{13}\\=\frac{-39}{130}+\frac{60}{130}\\=\frac{-39+60}{130}\\=\frac{21}{130}\)
9. \(-\left(\frac{5}{8}\right)+\left(\frac{-4}{7}\right)\\= \frac{-5}{8}-\frac{4}{7}\\=\frac{-35}{56}-\frac{32}{56}\\=\frac{-35-32}{56}\\=\frac{-67}{56}\)
10. \(-\left(\frac{-7}{4}\right)+\left(\frac{-11}{14}\right)\\= \frac{7}{4}-\frac{11}{14}\\=\frac{49}{28}-\frac{22}{28}\\=\frac{49-22}{28}\\=\frac{27}{28}\)
11. \(+\left(\frac{-10}{3}\right)+\left(\frac{-2}{11}\right)\\= \frac{-10}{3}-\frac{2}{11}\\=\frac{-110}{33}-\frac{6}{33}\\=\frac{-110-6}{33}\\=\frac{-116}{33}\)
12. \(+\left(\frac{9}{13}\right)+\left(\frac{7}{-3}\right)\\= \frac{9}{13}-\frac{7}{3}\\=\frac{27}{39}-\frac{91}{39}\\=\frac{27-91}{39}\\=\frac{-64}{39}\)