Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-10}{-3}\right)-\left(\frac{-10}{3}\right)\)
2. \(-\left(\frac{-4}{13}\right)-\left(\frac{7}{2}\right)\)
3. \(-\left(\frac{-13}{4}\right)-\left(\frac{9}{-11}\right)\)
4. \(+\left(\frac{-14}{9}\right)+\left(\frac{-13}{2}\right)\)
5. \(-\left(\frac{-2}{7}\right)-\left(\frac{14}{-3}\right)\)
6. \(-\left(\frac{15}{-11}\right)+\left(\frac{-7}{10}\right)\)
7. \(-\left(\frac{13}{11}\right)+\left(\frac{-3}{13}\right)\)
8. \(-\left(\frac{-4}{3}\right)-\left(\frac{9}{13}\right)\)
9. \(+\left(\frac{-10}{-7}\right)-\left(\frac{-14}{-13}\right)\)
10. \(-\left(\frac{3}{-10}\right)+\left(\frac{-2}{9}\right)\)
11. \(+\left(\frac{11}{-4}\right)-\left(\frac{15}{-11}\right)\)
12. \(-\left(\frac{3}{13}\right)-\left(\frac{-2}{11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-10}{-3}\right)-\left(\frac{-10}{3}\right)\\= \frac{-10}{3}+\frac{10}{3}\\=\frac{-10+10}{3}\\=\frac{0}{3}\\=\frac{0}{1}\)
2. \(-\left(\frac{-4}{13}\right)-\left(\frac{7}{2}\right)\\= \frac{4}{13}-\frac{7}{2}\\=\frac{8}{26}-\frac{91}{26}\\=\frac{8-91}{26}\\=\frac{-83}{26}\)
3. \(-\left(\frac{-13}{4}\right)-\left(\frac{9}{-11}\right)\\= \frac{13}{4}+\frac{9}{11}\\=\frac{143}{44}+\frac{36}{44}\\=\frac{143+36}{44}\\=\frac{179}{44}\)
4. \(+\left(\frac{-14}{9}\right)+\left(\frac{-13}{2}\right)\\= \frac{-14}{9}-\frac{13}{2}\\=\frac{-28}{18}-\frac{117}{18}\\=\frac{-28-117}{18}\\=\frac{-145}{18}\)
5. \(-\left(\frac{-2}{7}\right)-\left(\frac{14}{-3}\right)\\= \frac{2}{7}+\frac{14}{3}\\=\frac{6}{21}+\frac{98}{21}\\=\frac{6+98}{21}\\=\frac{104}{21}\)
6. \(-\left(\frac{15}{-11}\right)+\left(\frac{-7}{10}\right)\\= \frac{15}{11}-\frac{7}{10}\\=\frac{150}{110}-\frac{77}{110}\\=\frac{150-77}{110}\\=\frac{73}{110}\)
7. \(-\left(\frac{13}{11}\right)+\left(\frac{-3}{13}\right)\\= \frac{-13}{11}-\frac{3}{13}\\=\frac{-169}{143}-\frac{33}{143}\\=\frac{-169-33}{143}\\=\frac{-202}{143}\)
8. \(-\left(\frac{-4}{3}\right)-\left(\frac{9}{13}\right)\\= \frac{4}{3}-\frac{9}{13}\\=\frac{52}{39}-\frac{27}{39}\\=\frac{52-27}{39}\\=\frac{25}{39}\)
9. \(+\left(\frac{-10}{-7}\right)-\left(\frac{-14}{-13}\right)\\= \frac{10}{7}-\frac{14}{13}\\=\frac{130}{91}-\frac{98}{91}\\=\frac{130-98}{91}\\=\frac{32}{91}\)
10. \(-\left(\frac{3}{-10}\right)+\left(\frac{-2}{9}\right)\\= \frac{3}{10}-\frac{2}{9}\\=\frac{27}{90}-\frac{20}{90}\\=\frac{27-20}{90}\\=\frac{7}{90}\)
11. \(+\left(\frac{11}{-4}\right)-\left(\frac{15}{-11}\right)\\= \frac{-11}{4}+\frac{15}{11}\\=\frac{-121}{44}+\frac{60}{44}\\=\frac{-121+60}{44}\\=\frac{-61}{44}\)
12. \(-\left(\frac{3}{13}\right)-\left(\frac{-2}{11}\right)\\= \frac{-3}{13}+\frac{2}{11}\\=\frac{-33}{143}+\frac{26}{143}\\=\frac{-33+26}{143}\\=\frac{-7}{143}\)