Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-8}{3}\right)-\left(\frac{11}{3}\right)\)
2. \(+\left(\frac{6}{13}\right)-\left(\frac{15}{4}\right)\)
3. \(-\left(\frac{12}{-11}\right)+\left(\frac{-11}{6}\right)\)
4. \(-\left(\frac{10}{3}\right)-\left(\frac{13}{-5}\right)\)
5. \(-\left(\frac{10}{11}\right)-\left(\frac{-10}{-7}\right)\)
6. \(+\left(\frac{11}{-5}\right)+\left(\frac{5}{-11}\right)\)
7. \(-\left(\frac{10}{-13}\right)-\left(\frac{4}{11}\right)\)
8. \(+\left(\frac{2}{7}\right)+\left(\frac{15}{-13}\right)\)
9. \(-\left(\frac{-8}{9}\right)+\left(\frac{7}{-13}\right)\)
10. \(+\left(\frac{4}{-3}\right)-\left(\frac{14}{9}\right)\)
11. \(-\left(\frac{-12}{5}\right)-\left(\frac{15}{7}\right)\)
12. \(+\left(\frac{11}{-6}\right)-\left(\frac{-11}{6}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-8}{3}\right)-\left(\frac{11}{3}\right)\\= \frac{-8}{3}-\frac{11}{3}\\=\frac{-8-11}{3}\\=\frac{-19}{3}\)
2. \(+\left(\frac{6}{13}\right)-\left(\frac{15}{4}\right)\\= \frac{6}{13}-\frac{15}{4}\\=\frac{24}{52}-\frac{195}{52}\\=\frac{24-195}{52}\\=\frac{-171}{52}\)
3. \(-\left(\frac{12}{-11}\right)+\left(\frac{-11}{6}\right)\\= \frac{12}{11}-\frac{11}{6}\\=\frac{72}{66}-\frac{121}{66}\\=\frac{72-121}{66}\\=\frac{-49}{66}\)
4. \(-\left(\frac{10}{3}\right)-\left(\frac{13}{-5}\right)\\= \frac{-10}{3}+\frac{13}{5}\\=\frac{-50}{15}+\frac{39}{15}\\=\frac{-50+39}{15}\\=\frac{-11}{15}\)
5. \(-\left(\frac{10}{11}\right)-\left(\frac{-10}{-7}\right)\\= \frac{-10}{11}-\frac{10}{7}\\=\frac{-70}{77}-\frac{110}{77}\\=\frac{-70-110}{77}\\=\frac{-180}{77}\)
6. \(+\left(\frac{11}{-5}\right)+\left(\frac{5}{-11}\right)\\= \frac{-11}{5}-\frac{5}{11}\\=\frac{-121}{55}-\frac{25}{55}\\=\frac{-121-25}{55}\\=\frac{-146}{55}\)
7. \(-\left(\frac{10}{-13}\right)-\left(\frac{4}{11}\right)\\= \frac{10}{13}-\frac{4}{11}\\=\frac{110}{143}-\frac{52}{143}\\=\frac{110-52}{143}\\=\frac{58}{143}\)
8. \(+\left(\frac{2}{7}\right)+\left(\frac{15}{-13}\right)\\= \frac{2}{7}-\frac{15}{13}\\=\frac{26}{91}-\frac{105}{91}\\=\frac{26-105}{91}\\=\frac{-79}{91}\)
9. \(-\left(\frac{-8}{9}\right)+\left(\frac{7}{-13}\right)\\= \frac{8}{9}-\frac{7}{13}\\=\frac{104}{117}-\frac{63}{117}\\=\frac{104-63}{117}\\=\frac{41}{117}\)
10. \(+\left(\frac{4}{-3}\right)-\left(\frac{14}{9}\right)\\= \frac{-4}{3}-\frac{14}{9}\\=\frac{-12}{9}-\frac{14}{9}\\=\frac{-12-14}{9}\\=\frac{-26}{9}\)
11. \(-\left(\frac{-12}{5}\right)-\left(\frac{15}{7}\right)\\= \frac{12}{5}-\frac{15}{7}\\=\frac{84}{35}-\frac{75}{35}\\=\frac{84-75}{35}\\=\frac{9}{35}\)
12. \(+\left(\frac{11}{-6}\right)-\left(\frac{-11}{6}\right)\\= \frac{-11}{6}+\frac{11}{6}\\=\frac{-11+11}{6}\\=\frac{0}{6}\\=\frac{0}{1}\)