Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{6}{5}\right)+\left(\frac{4}{-3}\right)\)
2. \(+\left(\frac{15}{-2}\right)+\left(\frac{10}{3}\right)\)
3. \(-\left(\frac{-5}{-2}\right)-\left(\frac{-9}{-2}\right)\)
4. \(+\left(\frac{9}{7}\right)-\left(\frac{-11}{-2}\right)\)
5. \(+\left(\frac{-10}{13}\right)+\left(\frac{5}{-8}\right)\)
6. \(-\left(\frac{-11}{-10}\right)-\left(\frac{-14}{13}\right)\)
7. \(-\left(\frac{-7}{13}\right)+\left(\frac{7}{3}\right)\)
8. \(-\left(\frac{-4}{-3}\right)-\left(\frac{-13}{-6}\right)\)
9. \(-\left(\frac{-13}{9}\right)-\left(\frac{-7}{6}\right)\)
10. \(-\left(\frac{4}{9}\right)+\left(\frac{-8}{11}\right)\)
11. \(-\left(\frac{-14}{9}\right)+\left(\frac{12}{-13}\right)\)
12. \(+\left(\frac{-5}{2}\right)-\left(\frac{-10}{3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{6}{5}\right)+\left(\frac{4}{-3}\right)\\= \frac{-6}{5}-\frac{4}{3}\\=\frac{-18}{15}-\frac{20}{15}\\=\frac{-18-20}{15}\\=\frac{-38}{15}\)
2. \(+\left(\frac{15}{-2}\right)+\left(\frac{10}{3}\right)\\= \frac{-15}{2}+\frac{10}{3}\\=\frac{-45}{6}+\frac{20}{6}\\=\frac{-45+20}{6}\\=\frac{-25}{6}\)
3. \(-\left(\frac{-5}{-2}\right)-\left(\frac{-9}{-2}\right)\\= \frac{-5}{2}-\frac{9}{2}\\=\frac{-5-9}{2}\\=\frac{-14}{2}\\=\frac{-7}{1}\)
4. \(+\left(\frac{9}{7}\right)-\left(\frac{-11}{-2}\right)\\= \frac{9}{7}-\frac{11}{2}\\=\frac{18}{14}-\frac{77}{14}\\=\frac{18-77}{14}\\=\frac{-59}{14}\)
5. \(+\left(\frac{-10}{13}\right)+\left(\frac{5}{-8}\right)\\= \frac{-10}{13}-\frac{5}{8}\\=\frac{-80}{104}-\frac{65}{104}\\=\frac{-80-65}{104}\\=\frac{-145}{104}\)
6. \(-\left(\frac{-11}{-10}\right)-\left(\frac{-14}{13}\right)\\= \frac{-11}{10}+\frac{14}{13}\\=\frac{-143}{130}+\frac{140}{130}\\=\frac{-143+140}{130}\\=\frac{-3}{130}\)
7. \(-\left(\frac{-7}{13}\right)+\left(\frac{7}{3}\right)\\= \frac{7}{13}+\frac{7}{3}\\=\frac{21}{39}+\frac{91}{39}\\=\frac{21+91}{39}\\=\frac{112}{39}\)
8. \(-\left(\frac{-4}{-3}\right)-\left(\frac{-13}{-6}\right)\\= \frac{-4}{3}-\frac{13}{6}\\=\frac{-8}{6}-\frac{13}{6}\\=\frac{-8-13}{6}\\=\frac{-21}{6}\\=\frac{-7}{2}\)
9. \(-\left(\frac{-13}{9}\right)-\left(\frac{-7}{6}\right)\\= \frac{13}{9}+\frac{7}{6}\\=\frac{26}{18}+\frac{21}{18}\\=\frac{26+21}{18}\\=\frac{47}{18}\)
10. \(-\left(\frac{4}{9}\right)+\left(\frac{-8}{11}\right)\\= \frac{-4}{9}-\frac{8}{11}\\=\frac{-44}{99}-\frac{72}{99}\\=\frac{-44-72}{99}\\=\frac{-116}{99}\)
11. \(-\left(\frac{-14}{9}\right)+\left(\frac{12}{-13}\right)\\= \frac{14}{9}-\frac{12}{13}\\=\frac{182}{117}-\frac{108}{117}\\=\frac{182-108}{117}\\=\frac{74}{117}\)
12. \(+\left(\frac{-5}{2}\right)-\left(\frac{-10}{3}\right)\\= \frac{-5}{2}+\frac{10}{3}\\=\frac{-15}{6}+\frac{20}{6}\\=\frac{-15+20}{6}\\=\frac{5}{6}\)