Breuken haakjesregel (reeks 1)

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Bereken

1. \(-\left(\frac{-4}{7}\right)+\left(\frac{-10}{-9}\right)\)
2. \(-\left(\frac{13}{-12}\right)+\left(\frac{4}{-7}\right)\)
3. \(-\left(\frac{13}{11}\right)+\left(\frac{-7}{2}\right)\)
4. \(+\left(\frac{-10}{-3}\right)-\left(\frac{2}{7}\right)\)
5. \(-\left(\frac{15}{-8}\right)+\left(\frac{9}{-5}\right)\)
6. \(-\left(\frac{-3}{4}\right)-\left(\frac{-7}{-2}\right)\)
7. \(-\left(\frac{-7}{6}\right)+\left(\frac{-15}{-11}\right)\)
8. \(-\left(\frac{-6}{5}\right)-\left(\frac{-13}{-6}\right)\)
9. \(-\left(\frac{7}{-3}\right)-\left(\frac{-10}{-7}\right)\)
10. \(+\left(\frac{2}{-5}\right)-\left(\frac{-10}{-3}\right)\)
11. \(-\left(\frac{10}{3}\right)-\left(\frac{6}{-5}\right)\)
12. \(+\left(\frac{3}{7}\right)-\left(\frac{10}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-4}{7}\right)+\left(\frac{-10}{-9}\right)\\= \frac{4}{7}+\frac{10}{9}\\=\frac{36}{63}+\frac{70}{63}\\=\frac{36+70}{63}\\=\frac{106}{63}\)
2. \(-\left(\frac{13}{-12}\right)+\left(\frac{4}{-7}\right)\\= \frac{13}{12}-\frac{4}{7}\\=\frac{91}{84}-\frac{48}{84}\\=\frac{91-48}{84}\\=\frac{43}{84}\)
3. \(-\left(\frac{13}{11}\right)+\left(\frac{-7}{2}\right)\\= \frac{-13}{11}-\frac{7}{2}\\=\frac{-26}{22}-\frac{77}{22}\\=\frac{-26-77}{22}\\=\frac{-103}{22}\)
4. \(+\left(\frac{-10}{-3}\right)-\left(\frac{2}{7}\right)\\= \frac{10}{3}-\frac{2}{7}\\=\frac{70}{21}-\frac{6}{21}\\=\frac{70-6}{21}\\=\frac{64}{21}\)
5. \(-\left(\frac{15}{-8}\right)+\left(\frac{9}{-5}\right)\\= \frac{15}{8}-\frac{9}{5}\\=\frac{75}{40}-\frac{72}{40}\\=\frac{75-72}{40}\\=\frac{3}{40}\)
6. \(-\left(\frac{-3}{4}\right)-\left(\frac{-7}{-2}\right)\\= \frac{3}{4}-\frac{7}{2}\\=\frac{3-7}{4}\\=\frac{-4}{4}\\=\frac{-1}{1}\)
7. \(-\left(\frac{-7}{6}\right)+\left(\frac{-15}{-11}\right)\\= \frac{7}{6}+\frac{15}{11}\\=\frac{77}{66}+\frac{90}{66}\\=\frac{77+90}{66}\\=\frac{167}{66}\)
8. \(-\left(\frac{-6}{5}\right)-\left(\frac{-13}{-6}\right)\\= \frac{6}{5}-\frac{13}{6}\\=\frac{36}{30}-\frac{65}{30}\\=\frac{36-65}{30}\\=\frac{-29}{30}\)
9. \(-\left(\frac{7}{-3}\right)-\left(\frac{-10}{-7}\right)\\= \frac{7}{3}-\frac{10}{7}\\=\frac{49}{21}-\frac{30}{21}\\=\frac{49-30}{21}\\=\frac{19}{21}\)
10. \(+\left(\frac{2}{-5}\right)-\left(\frac{-10}{-3}\right)\\= \frac{-2}{5}-\frac{10}{3}\\=\frac{-6}{15}-\frac{50}{15}\\=\frac{-6-50}{15}\\=\frac{-56}{15}\)
11. \(-\left(\frac{10}{3}\right)-\left(\frac{6}{-5}\right)\\= \frac{-10}{3}+\frac{6}{5}\\=\frac{-50}{15}+\frac{18}{15}\\=\frac{-50+18}{15}\\=\frac{-32}{15}\)
12. \(+\left(\frac{3}{7}\right)-\left(\frac{10}{-7}\right)\\= \frac{3}{7}+\frac{10}{7}\\=\frac{3+10}{7}\\=\frac{13}{7}\)