Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-3}{10}\right)+\left(\frac{10}{3}\right)\)
2. \(+\left(\frac{6}{5}\right)-\left(\frac{-4}{-3}\right)\)
3. \(-\left(\frac{-6}{-7}\right)-\left(\frac{-7}{13}\right)\)
4. \(+\left(\frac{8}{-9}\right)-\left(\frac{-12}{5}\right)\)
5. \(+\left(\frac{7}{-13}\right)-\left(\frac{-3}{-4}\right)\)
6. \(+\left(\frac{12}{5}\right)+\left(\frac{-6}{-5}\right)\)
7. \(+\left(\frac{2}{3}\right)-\left(\frac{15}{4}\right)\)
8. \(+\left(\frac{4}{-3}\right)-\left(\frac{-9}{-13}\right)\)
9. \(+\left(\frac{14}{9}\right)+\left(\frac{-4}{7}\right)\)
10. \(-\left(\frac{-11}{-3}\right)+\left(\frac{-12}{-13}\right)\)
11. \(-\left(\frac{-2}{-3}\right)+\left(\frac{-13}{6}\right)\)
12. \(+\left(\frac{-6}{5}\right)+\left(\frac{-12}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-3}{10}\right)+\left(\frac{10}{3}\right)\\= \frac{-3}{10}+\frac{10}{3}\\=\frac{-9}{30}+\frac{100}{30}\\=\frac{-9+100}{30}\\=\frac{91}{30}\)
2. \(+\left(\frac{6}{5}\right)-\left(\frac{-4}{-3}\right)\\= \frac{6}{5}-\frac{4}{3}\\=\frac{18}{15}-\frac{20}{15}\\=\frac{18-20}{15}\\=\frac{-2}{15}\)
3. \(-\left(\frac{-6}{-7}\right)-\left(\frac{-7}{13}\right)\\= \frac{-6}{7}+\frac{7}{13}\\=\frac{-78}{91}+\frac{49}{91}\\=\frac{-78+49}{91}\\=\frac{-29}{91}\)
4. \(+\left(\frac{8}{-9}\right)-\left(\frac{-12}{5}\right)\\= \frac{-8}{9}+\frac{12}{5}\\=\frac{-40}{45}+\frac{108}{45}\\=\frac{-40+108}{45}\\=\frac{68}{45}\)
5. \(+\left(\frac{7}{-13}\right)-\left(\frac{-3}{-4}\right)\\= \frac{-7}{13}-\frac{3}{4}\\=\frac{-28}{52}-\frac{39}{52}\\=\frac{-28-39}{52}\\=\frac{-67}{52}\)
6. \(+\left(\frac{12}{5}\right)+\left(\frac{-6}{-5}\right)\\= \frac{12}{5}+\frac{6}{5}\\=\frac{12+6}{5}\\=\frac{18}{5}\)
7. \(+\left(\frac{2}{3}\right)-\left(\frac{15}{4}\right)\\= \frac{2}{3}-\frac{15}{4}\\=\frac{8}{12}-\frac{45}{12}\\=\frac{8-45}{12}\\=\frac{-37}{12}\)
8. \(+\left(\frac{4}{-3}\right)-\left(\frac{-9}{-13}\right)\\= \frac{-4}{3}-\frac{9}{13}\\=\frac{-52}{39}-\frac{27}{39}\\=\frac{-52-27}{39}\\=\frac{-79}{39}\)
9. \(+\left(\frac{14}{9}\right)+\left(\frac{-4}{7}\right)\\= \frac{14}{9}-\frac{4}{7}\\=\frac{98}{63}-\frac{36}{63}\\=\frac{98-36}{63}\\=\frac{62}{63}\)
10. \(-\left(\frac{-11}{-3}\right)+\left(\frac{-12}{-13}\right)\\= \frac{-11}{3}+\frac{12}{13}\\=\frac{-143}{39}+\frac{36}{39}\\=\frac{-143+36}{39}\\=\frac{-107}{39}\)
11. \(-\left(\frac{-2}{-3}\right)+\left(\frac{-13}{6}\right)\\= \frac{-2}{3}-\frac{13}{6}\\=\frac{-4}{6}-\frac{13}{6}\\=\frac{-4-13}{6}\\=\frac{-17}{6}\)
12. \(+\left(\frac{-6}{5}\right)+\left(\frac{-12}{-11}\right)\\= \frac{-6}{5}+\frac{12}{11}\\=\frac{-66}{55}+\frac{60}{55}\\=\frac{-66+60}{55}\\=\frac{-6}{55}\)