Bereken
- \(-\left(\frac{5}{11}\right)+\left(\frac{8}{-11}\right)\)
- \(+\left(\frac{15}{7}\right)-\left(\frac{-9}{-14}\right)\)
- \(-\left(\frac{7}{-8}\right)+\left(\frac{13}{-6}\right)\)
- \(+\left(\frac{-5}{-8}\right)+\left(\frac{-4}{9}\right)\)
- \(+\left(\frac{13}{12}\right)+\left(\frac{12}{-11}\right)\)
- \(+\left(\frac{7}{6}\right)+\left(\frac{7}{3}\right)\)
- \(-\left(\frac{15}{-8}\right)-\left(\frac{-10}{-13}\right)\)
- \(+\left(\frac{10}{-3}\right)-\left(\frac{-7}{11}\right)\)
- \(-\left(\frac{9}{-11}\right)+\left(\frac{-3}{10}\right)\)
- \(+\left(\frac{-4}{-3}\right)-\left(\frac{3}{10}\right)\)
- \(+\left(\frac{8}{-3}\right)+\left(\frac{-8}{3}\right)\)
- \(-\left(\frac{-13}{4}\right)-\left(\frac{8}{-11}\right)\)
Bereken
Verbetersleutel
- \(-\left(\frac{5}{11}\right)+\left(\frac{8}{-11}\right)\\= \frac{-5}{11}-\frac{8}{11}\\=\frac{-5-8}{11}\\=\frac{-13}{11}\)
- \(+\left(\frac{15}{7}\right)-\left(\frac{-9}{-14}\right)\\= \frac{15}{7}-\frac{9}{14}\\=\frac{30}{14}-\frac{9}{14}\\=\frac{30-9}{14}\\=\frac{21}{14}\\=\frac{3}{2}\)
- \(-\left(\frac{7}{-8}\right)+\left(\frac{13}{-6}\right)\\= \frac{7}{8}-\frac{13}{6}\\=\frac{21}{24}-\frac{52}{24}\\=\frac{21-52}{24}\\=\frac{-31}{24}\)
- \(+\left(\frac{-5}{-8}\right)+\left(\frac{-4}{9}\right)\\= \frac{5}{8}-\frac{4}{9}\\=\frac{45}{72}-\frac{32}{72}\\=\frac{45-32}{72}\\=\frac{13}{72}\)
- \(+\left(\frac{13}{12}\right)+\left(\frac{12}{-11}\right)\\= \frac{13}{12}-\frac{12}{11}\\=\frac{143}{132}-\frac{144}{132}\\=\frac{143-144}{132}\\=\frac{-1}{132}\)
- \(+\left(\frac{7}{6}\right)+\left(\frac{7}{3}\right)\\= \frac{7}{6}+\frac{7}{3}\\=\frac{7+7}{6}\\=\frac{14}{6}\\=\frac{7}{3}\)
- \(-\left(\frac{15}{-8}\right)-\left(\frac{-10}{-13}\right)\\= \frac{15}{8}-\frac{10}{13}\\=\frac{195}{104}-\frac{80}{104}\\=\frac{195-80}{104}\\=\frac{115}{104}\)
- \(+\left(\frac{10}{-3}\right)-\left(\frac{-7}{11}\right)\\= \frac{-10}{3}+\frac{7}{11}\\=\frac{-110}{33}+\frac{21}{33}\\=\frac{-110+21}{33}\\=\frac{-89}{33}\)
- \(-\left(\frac{9}{-11}\right)+\left(\frac{-3}{10}\right)\\= \frac{9}{11}-\frac{3}{10}\\=\frac{90}{110}-\frac{33}{110}\\=\frac{90-33}{110}\\=\frac{57}{110}\)
- \(+\left(\frac{-4}{-3}\right)-\left(\frac{3}{10}\right)\\= \frac{4}{3}-\frac{3}{10}\\=\frac{40}{30}-\frac{9}{30}\\=\frac{40-9}{30}\\=\frac{31}{30}\)
- \(+\left(\frac{8}{-3}\right)+\left(\frac{-8}{3}\right)\\= \frac{-8}{3}-\frac{8}{3}\\=\frac{-8-8}{3}\\=\frac{-16}{3}\)
- \(-\left(\frac{-13}{4}\right)-\left(\frac{8}{-11}\right)\\= \frac{13}{4}+\frac{8}{11}\\=\frac{143}{44}+\frac{32}{44}\\=\frac{143+32}{44}\\=\frac{175}{44}\)