Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-10}{9}\right)-\left(\frac{11}{3}\right)\)
2. \(-\left(\frac{3}{-14}\right)-\left(\frac{-2}{-3}\right)\)
3. \(+\left(\frac{-12}{5}\right)-\left(\frac{12}{11}\right)\)
4. \(-\left(\frac{13}{-2}\right)+\left(\frac{14}{9}\right)\)
5. \(-\left(\frac{-7}{2}\right)-\left(\frac{12}{5}\right)\)
6. \(-\left(\frac{12}{-5}\right)+\left(\frac{-4}{9}\right)\)
7. \(-\left(\frac{-15}{2}\right)+\left(\frac{7}{-12}\right)\)
8. \(-\left(\frac{-13}{7}\right)-\left(\frac{-11}{-4}\right)\)
9. \(+\left(\frac{7}{10}\right)+\left(\frac{4}{13}\right)\)
10. \(-\left(\frac{-14}{-3}\right)-\left(\frac{-6}{-11}\right)\)
11. \(+\left(\frac{9}{7}\right)-\left(\frac{-6}{13}\right)\)
12. \(-\left(\frac{10}{-7}\right)-\left(\frac{2}{3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-10}{9}\right)-\left(\frac{11}{3}\right)\\= \frac{-10}{9}-\frac{11}{3}\\=\frac{-10-11}{9}\\=\frac{-21}{9}\\=\frac{-7}{3}\)
2. \(-\left(\frac{3}{-14}\right)-\left(\frac{-2}{-3}\right)\\= \frac{3}{14}-\frac{2}{3}\\=\frac{9}{42}-\frac{28}{42}\\=\frac{9-28}{42}\\=\frac{-19}{42}\)
3. \(+\left(\frac{-12}{5}\right)-\left(\frac{12}{11}\right)\\= \frac{-12}{5}-\frac{12}{11}\\=\frac{-132}{55}-\frac{60}{55}\\=\frac{-132-60}{55}\\=\frac{-192}{55}\)
4. \(-\left(\frac{13}{-2}\right)+\left(\frac{14}{9}\right)\\= \frac{13}{2}+\frac{14}{9}\\=\frac{117}{18}+\frac{28}{18}\\=\frac{117+28}{18}\\=\frac{145}{18}\)
5. \(-\left(\frac{-7}{2}\right)-\left(\frac{12}{5}\right)\\= \frac{7}{2}-\frac{12}{5}\\=\frac{35}{10}-\frac{24}{10}\\=\frac{35-24}{10}\\=\frac{11}{10}\)
6. \(-\left(\frac{12}{-5}\right)+\left(\frac{-4}{9}\right)\\= \frac{12}{5}-\frac{4}{9}\\=\frac{108}{45}-\frac{20}{45}\\=\frac{108-20}{45}\\=\frac{88}{45}\)
7. \(-\left(\frac{-15}{2}\right)+\left(\frac{7}{-12}\right)\\= \frac{15}{2}-\frac{7}{12}\\=\frac{90}{12}-\frac{7}{12}\\=\frac{90-7}{12}\\=\frac{83}{12}\)
8. \(-\left(\frac{-13}{7}\right)-\left(\frac{-11}{-4}\right)\\= \frac{13}{7}-\frac{11}{4}\\=\frac{52}{28}-\frac{77}{28}\\=\frac{52-77}{28}\\=\frac{-25}{28}\)
9. \(+\left(\frac{7}{10}\right)+\left(\frac{4}{13}\right)\\= \frac{7}{10}+\frac{4}{13}\\=\frac{91}{130}+\frac{40}{130}\\=\frac{91+40}{130}\\=\frac{131}{130}\)
10. \(-\left(\frac{-14}{-3}\right)-\left(\frac{-6}{-11}\right)\\= \frac{-14}{3}-\frac{6}{11}\\=\frac{-154}{33}-\frac{18}{33}\\=\frac{-154-18}{33}\\=\frac{-172}{33}\)
11. \(+\left(\frac{9}{7}\right)-\left(\frac{-6}{13}\right)\\= \frac{9}{7}+\frac{6}{13}\\=\frac{117}{91}+\frac{42}{91}\\=\frac{117+42}{91}\\=\frac{159}{91}\)
12. \(-\left(\frac{10}{-7}\right)-\left(\frac{2}{3}\right)\\= \frac{10}{7}-\frac{2}{3}\\=\frac{30}{21}-\frac{14}{21}\\=\frac{30-14}{21}\\=\frac{16}{21}\)