Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{3}{4}\right)-\left(\frac{10}{11}\right)\)
2. \(-\left(\frac{11}{-8}\right)-\left(\frac{5}{-7}\right)\)
3. \(+\left(\frac{5}{14}\right)+\left(\frac{7}{8}\right)\)
4. \(+\left(\frac{14}{-5}\right)+\left(\frac{14}{-5}\right)\)
5. \(-\left(\frac{13}{7}\right)+\left(\frac{7}{-9}\right)\)
6. \(+\left(\frac{12}{-11}\right)+\left(\frac{-3}{8}\right)\)
7. \(+\left(\frac{-6}{-5}\right)-\left(\frac{3}{-13}\right)\)
8. \(+\left(\frac{-3}{-4}\right)-\left(\frac{-6}{11}\right)\)
9. \(+\left(\frac{-7}{-8}\right)+\left(\frac{-6}{7}\right)\)
10. \(-\left(\frac{-4}{7}\right)+\left(\frac{-9}{-13}\right)\)
11. \(-\left(\frac{14}{3}\right)-\left(\frac{4}{-3}\right)\)
12. \(+\left(\frac{-9}{13}\right)-\left(\frac{-13}{4}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{3}{4}\right)-\left(\frac{10}{11}\right)\\= \frac{-3}{4}-\frac{10}{11}\\=\frac{-33}{44}-\frac{40}{44}\\=\frac{-33-40}{44}\\=\frac{-73}{44}\)
2. \(-\left(\frac{11}{-8}\right)-\left(\frac{5}{-7}\right)\\= \frac{11}{8}+\frac{5}{7}\\=\frac{77}{56}+\frac{40}{56}\\=\frac{77+40}{56}\\=\frac{117}{56}\)
3. \(+\left(\frac{5}{14}\right)+\left(\frac{7}{8}\right)\\= \frac{5}{14}+\frac{7}{8}\\=\frac{20}{56}+\frac{49}{56}\\=\frac{20+49}{56}\\=\frac{69}{56}\)
4. \(+\left(\frac{14}{-5}\right)+\left(\frac{14}{-5}\right)\\= \frac{-14}{5}-\frac{14}{5}\\=\frac{-14-14}{5}\\=\frac{-28}{5}\)
5. \(-\left(\frac{13}{7}\right)+\left(\frac{7}{-9}\right)\\= \frac{-13}{7}-\frac{7}{9}\\=\frac{-117}{63}-\frac{49}{63}\\=\frac{-117-49}{63}\\=\frac{-166}{63}\)
6. \(+\left(\frac{12}{-11}\right)+\left(\frac{-3}{8}\right)\\= \frac{-12}{11}-\frac{3}{8}\\=\frac{-96}{88}-\frac{33}{88}\\=\frac{-96-33}{88}\\=\frac{-129}{88}\)
7. \(+\left(\frac{-6}{-5}\right)-\left(\frac{3}{-13}\right)\\= \frac{6}{5}+\frac{3}{13}\\=\frac{78}{65}+\frac{15}{65}\\=\frac{78+15}{65}\\=\frac{93}{65}\)
8. \(+\left(\frac{-3}{-4}\right)-\left(\frac{-6}{11}\right)\\= \frac{3}{4}+\frac{6}{11}\\=\frac{33}{44}+\frac{24}{44}\\=\frac{33+24}{44}\\=\frac{57}{44}\)
9. \(+\left(\frac{-7}{-8}\right)+\left(\frac{-6}{7}\right)\\= \frac{7}{8}-\frac{6}{7}\\=\frac{49}{56}-\frac{48}{56}\\=\frac{49-48}{56}\\=\frac{1}{56}\)
10. \(-\left(\frac{-4}{7}\right)+\left(\frac{-9}{-13}\right)\\= \frac{4}{7}+\frac{9}{13}\\=\frac{52}{91}+\frac{63}{91}\\=\frac{52+63}{91}\\=\frac{115}{91}\)
11. \(-\left(\frac{14}{3}\right)-\left(\frac{4}{-3}\right)\\= \frac{-14}{3}+\frac{4}{3}\\=\frac{-14+4}{3}\\=\frac{-10}{3}\)
12. \(+\left(\frac{-9}{13}\right)-\left(\frac{-13}{4}\right)\\= \frac{-9}{13}+\frac{13}{4}\\=\frac{-36}{52}+\frac{169}{52}\\=\frac{-36+169}{52}\\=\frac{133}{52}\)