Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{3}{13}\right)-\left(\frac{-11}{-12}\right)\)
2. \(+\left(\frac{14}{3}\right)+\left(\frac{-10}{-3}\right)\)
3. \(+\left(\frac{12}{-11}\right)+\left(\frac{-10}{-13}\right)\)
4. \(+\left(\frac{-5}{3}\right)-\left(\frac{12}{-5}\right)\)
5. \(+\left(\frac{-9}{10}\right)+\left(\frac{-6}{-11}\right)\)
6. \(-\left(\frac{8}{-3}\right)+\left(\frac{9}{-4}\right)\)
7. \(+\left(\frac{13}{-14}\right)+\left(\frac{8}{5}\right)\)
8. \(-\left(\frac{-5}{-9}\right)-\left(\frac{15}{-13}\right)\)
9. \(-\left(\frac{-10}{3}\right)-\left(\frac{10}{-7}\right)\)
10. \(-\left(\frac{15}{-8}\right)-\left(\frac{-2}{5}\right)\)
11. \(+\left(\frac{12}{-5}\right)+\left(\frac{-14}{3}\right)\)
12. \(+\left(\frac{4}{-3}\right)-\left(\frac{3}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{3}{13}\right)-\left(\frac{-11}{-12}\right)\\= \frac{-3}{13}-\frac{11}{12}\\=\frac{-36}{156}-\frac{143}{156}\\=\frac{-36-143}{156}\\=\frac{-179}{156}\)
2. \(+\left(\frac{14}{3}\right)+\left(\frac{-10}{-3}\right)\\= \frac{14}{3}+\frac{10}{3}\\=\frac{14+10}{3}\\=\frac{24}{3}\\=\frac{8}{1}\)
3. \(+\left(\frac{12}{-11}\right)+\left(\frac{-10}{-13}\right)\\= \frac{-12}{11}+\frac{10}{13}\\=\frac{-156}{143}+\frac{110}{143}\\=\frac{-156+110}{143}\\=\frac{-46}{143}\)
4. \(+\left(\frac{-5}{3}\right)-\left(\frac{12}{-5}\right)\\= \frac{-5}{3}+\frac{12}{5}\\=\frac{-25}{15}+\frac{36}{15}\\=\frac{-25+36}{15}\\=\frac{11}{15}\)
5. \(+\left(\frac{-9}{10}\right)+\left(\frac{-6}{-11}\right)\\= \frac{-9}{10}+\frac{6}{11}\\=\frac{-99}{110}+\frac{60}{110}\\=\frac{-99+60}{110}\\=\frac{-39}{110}\)
6. \(-\left(\frac{8}{-3}\right)+\left(\frac{9}{-4}\right)\\= \frac{8}{3}-\frac{9}{4}\\=\frac{32}{12}-\frac{27}{12}\\=\frac{32-27}{12}\\=\frac{5}{12}\)
7. \(+\left(\frac{13}{-14}\right)+\left(\frac{8}{5}\right)\\= \frac{-13}{14}+\frac{8}{5}\\=\frac{-65}{70}+\frac{112}{70}\\=\frac{-65+112}{70}\\=\frac{47}{70}\)
8. \(-\left(\frac{-5}{-9}\right)-\left(\frac{15}{-13}\right)\\= \frac{-5}{9}+\frac{15}{13}\\=\frac{-65}{117}+\frac{135}{117}\\=\frac{-65+135}{117}\\=\frac{70}{117}\)
9. \(-\left(\frac{-10}{3}\right)-\left(\frac{10}{-7}\right)\\= \frac{10}{3}+\frac{10}{7}\\=\frac{70}{21}+\frac{30}{21}\\=\frac{70+30}{21}\\=\frac{100}{21}\)
10. \(-\left(\frac{15}{-8}\right)-\left(\frac{-2}{5}\right)\\= \frac{15}{8}+\frac{2}{5}\\=\frac{75}{40}+\frac{16}{40}\\=\frac{75+16}{40}\\=\frac{91}{40}\)
11. \(+\left(\frac{12}{-5}\right)+\left(\frac{-14}{3}\right)\\= \frac{-12}{5}-\frac{14}{3}\\=\frac{-36}{15}-\frac{70}{15}\\=\frac{-36-70}{15}\\=\frac{-106}{15}\)
12. \(+\left(\frac{4}{-3}\right)-\left(\frac{3}{-13}\right)\\= \frac{-4}{3}+\frac{3}{13}\\=\frac{-52}{39}+\frac{9}{39}\\=\frac{-52+9}{39}\\=\frac{-43}{39}\)