Bereken
- \(+\left(\frac{-10}{11}\right)-\left(\frac{3}{10}\right)\)
- \(+\left(\frac{14}{5}\right)-\left(\frac{3}{4}\right)\)
- \(+\left(\frac{12}{5}\right)+\left(\frac{-5}{-11}\right)\)
- \(+\left(\frac{-13}{-3}\right)+\left(\frac{-10}{9}\right)\)
- \(-\left(\frac{-2}{7}\right)+\left(\frac{-14}{-3}\right)\)
- \(-\left(\frac{-11}{9}\right)-\left(\frac{-5}{11}\right)\)
- \(-\left(\frac{8}{11}\right)+\left(\frac{-4}{7}\right)\)
- \(-\left(\frac{4}{-7}\right)+\left(\frac{4}{-9}\right)\)
- \(-\left(\frac{-13}{-7}\right)+\left(\frac{11}{3}\right)\)
- \(-\left(\frac{-14}{-9}\right)-\left(\frac{-3}{13}\right)\)
- \(-\left(\frac{-5}{-14}\right)+\left(\frac{-13}{-3}\right)\)
- \(-\left(\frac{6}{13}\right)+\left(\frac{14}{-9}\right)\)
Bereken
Verbetersleutel
- \(+\left(\frac{-10}{11}\right)-\left(\frac{3}{10}\right)\\= \frac{-10}{11}-\frac{3}{10}\\=\frac{-100}{110}-\frac{33}{110}\\=\frac{-100-33}{110}\\=\frac{-133}{110}\)
- \(+\left(\frac{14}{5}\right)-\left(\frac{3}{4}\right)\\= \frac{14}{5}-\frac{3}{4}\\=\frac{56}{20}-\frac{15}{20}\\=\frac{56-15}{20}\\=\frac{41}{20}\)
- \(+\left(\frac{12}{5}\right)+\left(\frac{-5}{-11}\right)\\= \frac{12}{5}+\frac{5}{11}\\=\frac{132}{55}+\frac{25}{55}\\=\frac{132+25}{55}\\=\frac{157}{55}\)
- \(+\left(\frac{-13}{-3}\right)+\left(\frac{-10}{9}\right)\\= \frac{13}{3}-\frac{10}{9}\\=\frac{39}{9}-\frac{10}{9}\\=\frac{39-10}{9}\\=\frac{29}{9}\)
- \(-\left(\frac{-2}{7}\right)+\left(\frac{-14}{-3}\right)\\= \frac{2}{7}+\frac{14}{3}\\=\frac{6}{21}+\frac{98}{21}\\=\frac{6+98}{21}\\=\frac{104}{21}\)
- \(-\left(\frac{-11}{9}\right)-\left(\frac{-5}{11}\right)\\= \frac{11}{9}+\frac{5}{11}\\=\frac{121}{99}+\frac{45}{99}\\=\frac{121+45}{99}\\=\frac{166}{99}\)
- \(-\left(\frac{8}{11}\right)+\left(\frac{-4}{7}\right)\\= \frac{-8}{11}-\frac{4}{7}\\=\frac{-56}{77}-\frac{44}{77}\\=\frac{-56-44}{77}\\=\frac{-100}{77}\)
- \(-\left(\frac{4}{-7}\right)+\left(\frac{4}{-9}\right)\\= \frac{4}{7}-\frac{4}{9}\\=\frac{36}{63}-\frac{28}{63}\\=\frac{36-28}{63}\\=\frac{8}{63}\)
- \(-\left(\frac{-13}{-7}\right)+\left(\frac{11}{3}\right)\\= \frac{-13}{7}+\frac{11}{3}\\=\frac{-39}{21}+\frac{77}{21}\\=\frac{-39+77}{21}\\=\frac{38}{21}\)
- \(-\left(\frac{-14}{-9}\right)-\left(\frac{-3}{13}\right)\\= \frac{-14}{9}+\frac{3}{13}\\=\frac{-182}{117}+\frac{27}{117}\\=\frac{-182+27}{117}\\=\frac{-155}{117}\)
- \(-\left(\frac{-5}{-14}\right)+\left(\frac{-13}{-3}\right)\\= \frac{-5}{14}+\frac{13}{3}\\=\frac{-15}{42}+\frac{182}{42}\\=\frac{-15+182}{42}\\=\frac{167}{42}\)
- \(-\left(\frac{6}{13}\right)+\left(\frac{14}{-9}\right)\\= \frac{-6}{13}-\frac{14}{9}\\=\frac{-54}{117}-\frac{182}{117}\\=\frac{-54-182}{117}\\=\frac{-236}{117}\)