Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-3}{10}\right)-\left(\frac{-11}{-13}\right)\)
2. \(-\left(\frac{9}{-14}\right)-\left(\frac{3}{-11}\right)\)
3. \(+\left(\frac{-4}{-9}\right)-\left(\frac{-9}{-13}\right)\)
4. \(-\left(\frac{10}{3}\right)-\left(\frac{13}{-10}\right)\)
5. \(-\left(\frac{5}{7}\right)-\left(\frac{-7}{-11}\right)\)
6. \(-\left(\frac{-3}{-4}\right)+\left(\frac{14}{9}\right)\)
7. \(-\left(\frac{-8}{13}\right)+\left(\frac{5}{4}\right)\)
8. \(+\left(\frac{-7}{-13}\right)-\left(\frac{-8}{9}\right)\)
9. \(+\left(\frac{-14}{11}\right)+\left(\frac{-4}{-3}\right)\)
10. \(-\left(\frac{7}{-8}\right)+\left(\frac{12}{5}\right)\)
11. \(-\left(\frac{-14}{9}\right)-\left(\frac{13}{4}\right)\)
12. \(+\left(\frac{-6}{5}\right)-\left(\frac{-2}{-5}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-3}{10}\right)-\left(\frac{-11}{-13}\right)\\= \frac{-3}{10}-\frac{11}{13}\\=\frac{-39}{130}-\frac{110}{130}\\=\frac{-39-110}{130}\\=\frac{-149}{130}\)
2. \(-\left(\frac{9}{-14}\right)-\left(\frac{3}{-11}\right)\\= \frac{9}{14}+\frac{3}{11}\\=\frac{99}{154}+\frac{42}{154}\\=\frac{99+42}{154}\\=\frac{141}{154}\)
3. \(+\left(\frac{-4}{-9}\right)-\left(\frac{-9}{-13}\right)\\= \frac{4}{9}-\frac{9}{13}\\=\frac{52}{117}-\frac{81}{117}\\=\frac{52-81}{117}\\=\frac{-29}{117}\)
4. \(-\left(\frac{10}{3}\right)-\left(\frac{13}{-10}\right)\\= \frac{-10}{3}+\frac{13}{10}\\=\frac{-100}{30}+\frac{39}{30}\\=\frac{-100+39}{30}\\=\frac{-61}{30}\)
5. \(-\left(\frac{5}{7}\right)-\left(\frac{-7}{-11}\right)\\= \frac{-5}{7}-\frac{7}{11}\\=\frac{-55}{77}-\frac{49}{77}\\=\frac{-55-49}{77}\\=\frac{-104}{77}\)
6. \(-\left(\frac{-3}{-4}\right)+\left(\frac{14}{9}\right)\\= \frac{-3}{4}+\frac{14}{9}\\=\frac{-27}{36}+\frac{56}{36}\\=\frac{-27+56}{36}\\=\frac{29}{36}\)
7. \(-\left(\frac{-8}{13}\right)+\left(\frac{5}{4}\right)\\= \frac{8}{13}+\frac{5}{4}\\=\frac{32}{52}+\frac{65}{52}\\=\frac{32+65}{52}\\=\frac{97}{52}\)
8. \(+\left(\frac{-7}{-13}\right)-\left(\frac{-8}{9}\right)\\= \frac{7}{13}+\frac{8}{9}\\=\frac{63}{117}+\frac{104}{117}\\=\frac{63+104}{117}\\=\frac{167}{117}\)
9. \(+\left(\frac{-14}{11}\right)+\left(\frac{-4}{-3}\right)\\= \frac{-14}{11}+\frac{4}{3}\\=\frac{-42}{33}+\frac{44}{33}\\=\frac{-42+44}{33}\\=\frac{2}{33}\)
10. \(-\left(\frac{7}{-8}\right)+\left(\frac{12}{5}\right)\\= \frac{7}{8}+\frac{12}{5}\\=\frac{35}{40}+\frac{96}{40}\\=\frac{35+96}{40}\\=\frac{131}{40}\)
11. \(-\left(\frac{-14}{9}\right)-\left(\frac{13}{4}\right)\\= \frac{14}{9}-\frac{13}{4}\\=\frac{56}{36}-\frac{117}{36}\\=\frac{56-117}{36}\\=\frac{-61}{36}\)
12. \(+\left(\frac{-6}{5}\right)-\left(\frac{-2}{-5}\right)\\= \frac{-6}{5}-\frac{2}{5}\\=\frac{-6-2}{5}\\=\frac{-8}{5}\)