Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(-\left(\frac{-11}{13}\right)-\left(\frac{13}{12}\right)\)
  2. \(+\left(\frac{7}{-2}\right)+\left(\frac{4}{13}\right)\)
  3. \(-\left(\frac{7}{8}\right)-\left(\frac{-12}{11}\right)\)
  4. \(+\left(\frac{-14}{3}\right)+\left(\frac{-10}{-9}\right)\)
  5. \(+\left(\frac{-12}{5}\right)-\left(\frac{15}{4}\right)\)
  6. \(+\left(\frac{-5}{-6}\right)+\left(\frac{-13}{-8}\right)\)
  7. \(-\left(\frac{-11}{2}\right)+\left(\frac{-8}{-11}\right)\)
  8. \(-\left(\frac{7}{-10}\right)+\left(\frac{9}{-10}\right)\)
  9. \(+\left(\frac{15}{4}\right)-\left(\frac{7}{12}\right)\)
  10. \(-\left(\frac{8}{-3}\right)+\left(\frac{-13}{12}\right)\)
  11. \(+\left(\frac{-3}{-2}\right)-\left(\frac{3}{-13}\right)\)
  12. \(-\left(\frac{-8}{-9}\right)+\left(\frac{9}{4}\right)\)

Bereken

Verbetersleutel

  1. \(-\left(\frac{-11}{13}\right)-\left(\frac{13}{12}\right)\\= \frac{11}{13}-\frac{13}{12}\\=\frac{132}{156}-\frac{169}{156}\\=\frac{132-169}{156}\\=\frac{-37}{156}\)
  2. \(+\left(\frac{7}{-2}\right)+\left(\frac{4}{13}\right)\\= \frac{-7}{2}+\frac{4}{13}\\=\frac{-91}{26}+\frac{8}{26}\\=\frac{-91+8}{26}\\=\frac{-83}{26}\)
  3. \(-\left(\frac{7}{8}\right)-\left(\frac{-12}{11}\right)\\= \frac{-7}{8}+\frac{12}{11}\\=\frac{-77}{88}+\frac{96}{88}\\=\frac{-77+96}{88}\\=\frac{19}{88}\)
  4. \(+\left(\frac{-14}{3}\right)+\left(\frac{-10}{-9}\right)\\= \frac{-14}{3}+\frac{10}{9}\\=\frac{-42}{9}+\frac{10}{9}\\=\frac{-42+10}{9}\\=\frac{-32}{9}\)
  5. \(+\left(\frac{-12}{5}\right)-\left(\frac{15}{4}\right)\\= \frac{-12}{5}-\frac{15}{4}\\=\frac{-48}{20}-\frac{75}{20}\\=\frac{-48-75}{20}\\=\frac{-123}{20}\)
  6. \(+\left(\frac{-5}{-6}\right)+\left(\frac{-13}{-8}\right)\\= \frac{5}{6}+\frac{13}{8}\\=\frac{20}{24}+\frac{39}{24}\\=\frac{20+39}{24}\\=\frac{59}{24}\)
  7. \(-\left(\frac{-11}{2}\right)+\left(\frac{-8}{-11}\right)\\= \frac{11}{2}+\frac{8}{11}\\=\frac{121}{22}+\frac{16}{22}\\=\frac{121+16}{22}\\=\frac{137}{22}\)
  8. \(-\left(\frac{7}{-10}\right)+\left(\frac{9}{-10}\right)\\= \frac{7}{10}-\frac{9}{10}\\=\frac{7-9}{10}\\=\frac{-2}{10}\\=\frac{-1}{5}\)
  9. \(+\left(\frac{15}{4}\right)-\left(\frac{7}{12}\right)\\= \frac{15}{4}-\frac{7}{12}\\=\frac{45}{12}-\frac{7}{12}\\=\frac{45-7}{12}\\=\frac{38}{12}\\=\frac{19}{6}\)
  10. \(-\left(\frac{8}{-3}\right)+\left(\frac{-13}{12}\right)\\= \frac{8}{3}-\frac{13}{12}\\=\frac{32}{12}-\frac{13}{12}\\=\frac{32-13}{12}\\=\frac{19}{12}\)
  11. \(+\left(\frac{-3}{-2}\right)-\left(\frac{3}{-13}\right)\\= \frac{3}{2}+\frac{3}{13}\\=\frac{39}{26}+\frac{6}{26}\\=\frac{39+6}{26}\\=\frac{45}{26}\)
  12. \(-\left(\frac{-8}{-9}\right)+\left(\frac{9}{4}\right)\\= \frac{-8}{9}+\frac{9}{4}\\=\frac{-32}{36}+\frac{81}{36}\\=\frac{-32+81}{36}\\=\frac{49}{36}\)
Oefeningengenerator wiskundeoefeningen.be 2026-11-07 05:28:23
Een site van Busleyden Atheneum Mechelen