Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-13}{12}\right)+\left(\frac{-9}{10}\right)\)
2. \(-\left(\frac{-7}{3}\right)+\left(\frac{-3}{-10}\right)\)
3. \(-\left(\frac{-11}{12}\right)-\left(\frac{-8}{7}\right)\)
4. \(+\left(\frac{-11}{-10}\right)+\left(\frac{-7}{-10}\right)\)
5. \(+\left(\frac{6}{-7}\right)-\left(\frac{-10}{-3}\right)\)
6. \(-\left(\frac{11}{-13}\right)-\left(\frac{14}{-9}\right)\)
7. \(-\left(\frac{-5}{8}\right)-\left(\frac{-12}{5}\right)\)
8. \(-\left(\frac{-6}{7}\right)+\left(\frac{-10}{-11}\right)\)
9. \(-\left(\frac{-14}{13}\right)-\left(\frac{-9}{-4}\right)\)
10. \(-\left(\frac{5}{7}\right)+\left(\frac{13}{-7}\right)\)
11. \(-\left(\frac{-15}{-7}\right)+\left(\frac{5}{2}\right)\)
12. \(-\left(\frac{-2}{-3}\right)+\left(\frac{14}{9}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-13}{12}\right)+\left(\frac{-9}{10}\right)\\= \frac{13}{12}-\frac{9}{10}\\=\frac{65}{60}-\frac{54}{60}\\=\frac{65-54}{60}\\=\frac{11}{60}\)
2. \(-\left(\frac{-7}{3}\right)+\left(\frac{-3}{-10}\right)\\= \frac{7}{3}+\frac{3}{10}\\=\frac{70}{30}+\frac{9}{30}\\=\frac{70+9}{30}\\=\frac{79}{30}\)
3. \(-\left(\frac{-11}{12}\right)-\left(\frac{-8}{7}\right)\\= \frac{11}{12}+\frac{8}{7}\\=\frac{77}{84}+\frac{96}{84}\\=\frac{77+96}{84}\\=\frac{173}{84}\)
4. \(+\left(\frac{-11}{-10}\right)+\left(\frac{-7}{-10}\right)\\= \frac{11}{10}+\frac{7}{10}\\=\frac{11+7}{10}\\=\frac{18}{10}\\=\frac{9}{5}\)
5. \(+\left(\frac{6}{-7}\right)-\left(\frac{-10}{-3}\right)\\= \frac{-6}{7}-\frac{10}{3}\\=\frac{-18}{21}-\frac{70}{21}\\=\frac{-18-70}{21}\\=\frac{-88}{21}\)
6. \(-\left(\frac{11}{-13}\right)-\left(\frac{14}{-9}\right)\\= \frac{11}{13}+\frac{14}{9}\\=\frac{99}{117}+\frac{182}{117}\\=\frac{99+182}{117}\\=\frac{281}{117}\)
7. \(-\left(\frac{-5}{8}\right)-\left(\frac{-12}{5}\right)\\= \frac{5}{8}+\frac{12}{5}\\=\frac{25}{40}+\frac{96}{40}\\=\frac{25+96}{40}\\=\frac{121}{40}\)
8. \(-\left(\frac{-6}{7}\right)+\left(\frac{-10}{-11}\right)\\= \frac{6}{7}+\frac{10}{11}\\=\frac{66}{77}+\frac{70}{77}\\=\frac{66+70}{77}\\=\frac{136}{77}\)
9. \(-\left(\frac{-14}{13}\right)-\left(\frac{-9}{-4}\right)\\= \frac{14}{13}-\frac{9}{4}\\=\frac{56}{52}-\frac{117}{52}\\=\frac{56-117}{52}\\=\frac{-61}{52}\)
10. \(-\left(\frac{5}{7}\right)+\left(\frac{13}{-7}\right)\\= \frac{-5}{7}-\frac{13}{7}\\=\frac{-5-13}{7}\\=\frac{-18}{7}\)
11. \(-\left(\frac{-15}{-7}\right)+\left(\frac{5}{2}\right)\\= \frac{-15}{7}+\frac{5}{2}\\=\frac{-30}{14}+\frac{35}{14}\\=\frac{-30+35}{14}\\=\frac{5}{14}\)
12. \(-\left(\frac{-2}{-3}\right)+\left(\frac{14}{9}\right)\\= \frac{-2}{3}+\frac{14}{9}\\=\frac{-6}{9}+\frac{14}{9}\\=\frac{-6+14}{9}\\=\frac{8}{9}\)