Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-5}{4}\right)-\left(\frac{7}{11}\right)\)
2. \(+\left(\frac{9}{-7}\right)-\left(\frac{-7}{-6}\right)\)
3. \(+\left(\frac{9}{-11}\right)+\left(\frac{15}{2}\right)\)
4. \(-\left(\frac{-15}{11}\right)-\left(\frac{9}{-7}\right)\)
5. \(+\left(\frac{11}{-8}\right)-\left(\frac{-11}{12}\right)\)
6. \(-\left(\frac{6}{-5}\right)+\left(\frac{6}{-5}\right)\)
7. \(+\left(\frac{8}{9}\right)-\left(\frac{-11}{12}\right)\)
8. \(+\left(\frac{3}{13}\right)-\left(\frac{8}{-13}\right)\)
9. \(-\left(\frac{14}{-3}\right)-\left(\frac{7}{9}\right)\)
10. \(-\left(\frac{-9}{-8}\right)-\left(\frac{13}{9}\right)\)
11. \(-\left(\frac{8}{5}\right)-\left(\frac{-8}{-3}\right)\)
12. \(+\left(\frac{10}{-9}\right)-\left(\frac{2}{13}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-5}{4}\right)-\left(\frac{7}{11}\right)\\= \frac{-5}{4}-\frac{7}{11}\\=\frac{-55}{44}-\frac{28}{44}\\=\frac{-55-28}{44}\\=\frac{-83}{44}\)
2. \(+\left(\frac{9}{-7}\right)-\left(\frac{-7}{-6}\right)\\= \frac{-9}{7}-\frac{7}{6}\\=\frac{-54}{42}-\frac{49}{42}\\=\frac{-54-49}{42}\\=\frac{-103}{42}\)
3. \(+\left(\frac{9}{-11}\right)+\left(\frac{15}{2}\right)\\= \frac{-9}{11}+\frac{15}{2}\\=\frac{-18}{22}+\frac{165}{22}\\=\frac{-18+165}{22}\\=\frac{147}{22}\)
4. \(-\left(\frac{-15}{11}\right)-\left(\frac{9}{-7}\right)\\= \frac{15}{11}+\frac{9}{7}\\=\frac{105}{77}+\frac{99}{77}\\=\frac{105+99}{77}\\=\frac{204}{77}\)
5. \(+\left(\frac{11}{-8}\right)-\left(\frac{-11}{12}\right)\\= \frac{-11}{8}+\frac{11}{12}\\=\frac{-33}{24}+\frac{22}{24}\\=\frac{-33+22}{24}\\=\frac{-11}{24}\)
6. \(-\left(\frac{6}{-5}\right)+\left(\frac{6}{-5}\right)\\= \frac{6}{5}-\frac{6}{5}\\=\frac{6-6}{5}\\=\frac{0}{5}\\=\frac{0}{1}\)
7. \(+\left(\frac{8}{9}\right)-\left(\frac{-11}{12}\right)\\= \frac{8}{9}+\frac{11}{12}\\=\frac{32}{36}+\frac{33}{36}\\=\frac{32+33}{36}\\=\frac{65}{36}\)
8. \(+\left(\frac{3}{13}\right)-\left(\frac{8}{-13}\right)\\= \frac{3}{13}+\frac{8}{13}\\=\frac{3+8}{13}\\=\frac{11}{13}\)
9. \(-\left(\frac{14}{-3}\right)-\left(\frac{7}{9}\right)\\= \frac{14}{3}-\frac{7}{9}\\=\frac{42}{9}-\frac{7}{9}\\=\frac{42-7}{9}\\=\frac{35}{9}\)
10. \(-\left(\frac{-9}{-8}\right)-\left(\frac{13}{9}\right)\\= \frac{-9}{8}-\frac{13}{9}\\=\frac{-81}{72}-\frac{104}{72}\\=\frac{-81-104}{72}\\=\frac{-185}{72}\)
11. \(-\left(\frac{8}{5}\right)-\left(\frac{-8}{-3}\right)\\= \frac{-8}{5}-\frac{8}{3}\\=\frac{-24}{15}-\frac{40}{15}\\=\frac{-24-40}{15}\\=\frac{-64}{15}\)
12. \(+\left(\frac{10}{-9}\right)-\left(\frac{2}{13}\right)\\= \frac{-10}{9}-\frac{2}{13}\\=\frac{-130}{117}-\frac{18}{117}\\=\frac{-130-18}{117}\\=\frac{-148}{117}\)