Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-5}{2}\right)+\left(\frac{13}{-12}\right)\)
2. \(-\left(\frac{-2}{-9}\right)+\left(\frac{7}{4}\right)\)
3. \(-\left(\frac{-5}{-11}\right)+\left(\frac{8}{-3}\right)\)
4. \(-\left(\frac{-8}{-11}\right)-\left(\frac{-12}{-13}\right)\)
5. \(+\left(\frac{4}{-5}\right)+\left(\frac{4}{-9}\right)\)
6. \(-\left(\frac{12}{-13}\right)+\left(\frac{4}{11}\right)\)
7. \(-\left(\frac{-14}{-9}\right)-\left(\frac{-11}{-7}\right)\)
8. \(-\left(\frac{-15}{2}\right)+\left(\frac{-12}{5}\right)\)
9. \(-\left(\frac{-6}{-11}\right)+\left(\frac{-15}{4}\right)\)
10. \(-\left(\frac{15}{-13}\right)+\left(\frac{-2}{-5}\right)\)
11. \(+\left(\frac{-6}{7}\right)-\left(\frac{10}{11}\right)\)
12. \(-\left(\frac{7}{2}\right)-\left(\frac{8}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-5}{2}\right)+\left(\frac{13}{-12}\right)\\= \frac{-5}{2}-\frac{13}{12}\\=\frac{-30}{12}-\frac{13}{12}\\=\frac{-30-13}{12}\\=\frac{-43}{12}\)
2. \(-\left(\frac{-2}{-9}\right)+\left(\frac{7}{4}\right)\\= \frac{-2}{9}+\frac{7}{4}\\=\frac{-8}{36}+\frac{63}{36}\\=\frac{-8+63}{36}\\=\frac{55}{36}\)
3. \(-\left(\frac{-5}{-11}\right)+\left(\frac{8}{-3}\right)\\= \frac{-5}{11}-\frac{8}{3}\\=\frac{-15}{33}-\frac{88}{33}\\=\frac{-15-88}{33}\\=\frac{-103}{33}\)
4. \(-\left(\frac{-8}{-11}\right)-\left(\frac{-12}{-13}\right)\\= \frac{-8}{11}-\frac{12}{13}\\=\frac{-104}{143}-\frac{132}{143}\\=\frac{-104-132}{143}\\=\frac{-236}{143}\)
5. \(+\left(\frac{4}{-5}\right)+\left(\frac{4}{-9}\right)\\= \frac{-4}{5}-\frac{4}{9}\\=\frac{-36}{45}-\frac{20}{45}\\=\frac{-36-20}{45}\\=\frac{-56}{45}\)
6. \(-\left(\frac{12}{-13}\right)+\left(\frac{4}{11}\right)\\= \frac{12}{13}+\frac{4}{11}\\=\frac{132}{143}+\frac{52}{143}\\=\frac{132+52}{143}\\=\frac{184}{143}\)
7. \(-\left(\frac{-14}{-9}\right)-\left(\frac{-11}{-7}\right)\\= \frac{-14}{9}-\frac{11}{7}\\=\frac{-98}{63}-\frac{99}{63}\\=\frac{-98-99}{63}\\=\frac{-197}{63}\)
8. \(-\left(\frac{-15}{2}\right)+\left(\frac{-12}{5}\right)\\= \frac{15}{2}-\frac{12}{5}\\=\frac{75}{10}-\frac{24}{10}\\=\frac{75-24}{10}\\=\frac{51}{10}\)
9. \(-\left(\frac{-6}{-11}\right)+\left(\frac{-15}{4}\right)\\= \frac{-6}{11}-\frac{15}{4}\\=\frac{-24}{44}-\frac{165}{44}\\=\frac{-24-165}{44}\\=\frac{-189}{44}\)
10. \(-\left(\frac{15}{-13}\right)+\left(\frac{-2}{-5}\right)\\= \frac{15}{13}+\frac{2}{5}\\=\frac{75}{65}+\frac{26}{65}\\=\frac{75+26}{65}\\=\frac{101}{65}\)
11. \(+\left(\frac{-6}{7}\right)-\left(\frac{10}{11}\right)\\= \frac{-6}{7}-\frac{10}{11}\\=\frac{-66}{77}-\frac{70}{77}\\=\frac{-66-70}{77}\\=\frac{-136}{77}\)
12. \(-\left(\frac{7}{2}\right)-\left(\frac{8}{-7}\right)\\= \frac{-7}{2}+\frac{8}{7}\\=\frac{-49}{14}+\frac{16}{14}\\=\frac{-49+16}{14}\\=\frac{-33}{14}\)