Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(+\left(\frac{13}{-10}\right)-\left(\frac{3}{8}\right)\)
  2. \(-\left(\frac{7}{3}\right)-\left(\frac{10}{9}\right)\)
  3. \(-\left(\frac{-7}{5}\right)-\left(\frac{-3}{-13}\right)\)
  4. \(+\left(\frac{7}{-2}\right)-\left(\frac{-15}{13}\right)\)
  5. \(+\left(\frac{15}{-4}\right)+\left(\frac{-7}{2}\right)\)
  6. \(-\left(\frac{10}{13}\right)+\left(\frac{15}{-4}\right)\)
  7. \(+\left(\frac{10}{3}\right)+\left(\frac{-10}{-3}\right)\)
  8. \(+\left(\frac{-11}{13}\right)-\left(\frac{15}{13}\right)\)
  9. \(-\left(\frac{-2}{3}\right)-\left(\frac{15}{-14}\right)\)
  10. \(+\left(\frac{-14}{3}\right)-\left(\frac{7}{-2}\right)\)
  11. \(+\left(\frac{15}{11}\right)-\left(\frac{8}{-13}\right)\)
  12. \(+\left(\frac{3}{-5}\right)+\left(\frac{-6}{5}\right)\)

Bereken

Verbetersleutel

  1. \(+\left(\frac{13}{-10}\right)-\left(\frac{3}{8}\right)\\= \frac{-13}{10}-\frac{3}{8}\\=\frac{-52}{40}-\frac{15}{40}\\=\frac{-52-15}{40}\\=\frac{-67}{40}\)
  2. \(-\left(\frac{7}{3}\right)-\left(\frac{10}{9}\right)\\= \frac{-7}{3}-\frac{10}{9}\\=\frac{-21}{9}-\frac{10}{9}\\=\frac{-21-10}{9}\\=\frac{-31}{9}\)
  3. \(-\left(\frac{-7}{5}\right)-\left(\frac{-3}{-13}\right)\\= \frac{7}{5}-\frac{3}{13}\\=\frac{91}{65}-\frac{15}{65}\\=\frac{91-15}{65}\\=\frac{76}{65}\)
  4. \(+\left(\frac{7}{-2}\right)-\left(\frac{-15}{13}\right)\\= \frac{-7}{2}+\frac{15}{13}\\=\frac{-91}{26}+\frac{30}{26}\\=\frac{-91+30}{26}\\=\frac{-61}{26}\)
  5. \(+\left(\frac{15}{-4}\right)+\left(\frac{-7}{2}\right)\\= \frac{-15}{4}-\frac{7}{2}\\=\frac{-15-7}{4}\\=\frac{-22}{4}\\=\frac{-11}{2}\)
  6. \(-\left(\frac{10}{13}\right)+\left(\frac{15}{-4}\right)\\= \frac{-10}{13}-\frac{15}{4}\\=\frac{-40}{52}-\frac{195}{52}\\=\frac{-40-195}{52}\\=\frac{-235}{52}\)
  7. \(+\left(\frac{10}{3}\right)+\left(\frac{-10}{-3}\right)\\= \frac{10}{3}+\frac{10}{3}\\=\frac{10+10}{3}\\=\frac{20}{3}\)
  8. \(+\left(\frac{-11}{13}\right)-\left(\frac{15}{13}\right)\\= \frac{-11}{13}-\frac{15}{13}\\=\frac{-11-15}{13}\\=\frac{-26}{13}\\=\frac{-2}{1}\)
  9. \(-\left(\frac{-2}{3}\right)-\left(\frac{15}{-14}\right)\\= \frac{2}{3}+\frac{15}{14}\\=\frac{28}{42}+\frac{45}{42}\\=\frac{28+45}{42}\\=\frac{73}{42}\)
  10. \(+\left(\frac{-14}{3}\right)-\left(\frac{7}{-2}\right)\\= \frac{-14}{3}+\frac{7}{2}\\=\frac{-28}{6}+\frac{21}{6}\\=\frac{-28+21}{6}\\=\frac{-7}{6}\)
  11. \(+\left(\frac{15}{11}\right)-\left(\frac{8}{-13}\right)\\= \frac{15}{11}+\frac{8}{13}\\=\frac{195}{143}+\frac{88}{143}\\=\frac{195+88}{143}\\=\frac{283}{143}\)
  12. \(+\left(\frac{3}{-5}\right)+\left(\frac{-6}{5}\right)\\= \frac{-3}{5}-\frac{6}{5}\\=\frac{-3-6}{5}\\=\frac{-9}{5}\)
Oefeningengenerator wiskundeoefeningen.be 2025-11-27 08:40:13
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