Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{15}{-7}\right)-\left(\frac{15}{11}\right)\)
2. \(+\left(\frac{13}{8}\right)+\left(\frac{-13}{-4}\right)\)
3. \(-\left(\frac{-2}{-3}\right)-\left(\frac{-5}{-9}\right)\)
4. \(+\left(\frac{10}{11}\right)-\left(\frac{14}{-11}\right)\)
5. \(-\left(\frac{-8}{-3}\right)+\left(\frac{-10}{-11}\right)\)
6. \(-\left(\frac{8}{11}\right)+\left(\frac{9}{-13}\right)\)
7. \(-\left(\frac{-3}{-11}\right)-\left(\frac{3}{10}\right)\)
8. \(-\left(\frac{2}{9}\right)+\left(\frac{-4}{-11}\right)\)
9. \(+\left(\frac{3}{4}\right)-\left(\frac{11}{-12}\right)\)
10. \(+\left(\frac{-6}{-5}\right)+\left(\frac{-12}{-11}\right)\)
11. \(+\left(\frac{6}{11}\right)-\left(\frac{-8}{-9}\right)\)
12. \(-\left(\frac{-9}{4}\right)-\left(\frac{-2}{13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{15}{-7}\right)-\left(\frac{15}{11}\right)\\= \frac{15}{7}-\frac{15}{11}\\=\frac{165}{77}-\frac{105}{77}\\=\frac{165-105}{77}\\=\frac{60}{77}\)
2. \(+\left(\frac{13}{8}\right)+\left(\frac{-13}{-4}\right)\\= \frac{13}{8}+\frac{13}{4}\\=\frac{13+13}{8}\\=\frac{26}{8}\\=\frac{13}{4}\)
3. \(-\left(\frac{-2}{-3}\right)-\left(\frac{-5}{-9}\right)\\= \frac{-2}{3}-\frac{5}{9}\\=\frac{-6}{9}-\frac{5}{9}\\=\frac{-6-5}{9}\\=\frac{-11}{9}\)
4. \(+\left(\frac{10}{11}\right)-\left(\frac{14}{-11}\right)\\= \frac{10}{11}+\frac{14}{11}\\=\frac{10+14}{11}\\=\frac{24}{11}\)
5. \(-\left(\frac{-8}{-3}\right)+\left(\frac{-10}{-11}\right)\\= \frac{-8}{3}+\frac{10}{11}\\=\frac{-88}{33}+\frac{30}{33}\\=\frac{-88+30}{33}\\=\frac{-58}{33}\)
6. \(-\left(\frac{8}{11}\right)+\left(\frac{9}{-13}\right)\\= \frac{-8}{11}-\frac{9}{13}\\=\frac{-104}{143}-\frac{99}{143}\\=\frac{-104-99}{143}\\=\frac{-203}{143}\)
7. \(-\left(\frac{-3}{-11}\right)-\left(\frac{3}{10}\right)\\= \frac{-3}{11}-\frac{3}{10}\\=\frac{-30}{110}-\frac{33}{110}\\=\frac{-30-33}{110}\\=\frac{-63}{110}\)
8. \(-\left(\frac{2}{9}\right)+\left(\frac{-4}{-11}\right)\\= \frac{-2}{9}+\frac{4}{11}\\=\frac{-22}{99}+\frac{36}{99}\\=\frac{-22+36}{99}\\=\frac{14}{99}\)
9. \(+\left(\frac{3}{4}\right)-\left(\frac{11}{-12}\right)\\= \frac{3}{4}+\frac{11}{12}\\=\frac{9}{12}+\frac{11}{12}\\=\frac{9+11}{12}\\=\frac{20}{12}\\=\frac{5}{3}\)
10. \(+\left(\frac{-6}{-5}\right)+\left(\frac{-12}{-11}\right)\\= \frac{6}{5}+\frac{12}{11}\\=\frac{66}{55}+\frac{60}{55}\\=\frac{66+60}{55}\\=\frac{126}{55}\)
11. \(+\left(\frac{6}{11}\right)-\left(\frac{-8}{-9}\right)\\= \frac{6}{11}-\frac{8}{9}\\=\frac{54}{99}-\frac{88}{99}\\=\frac{54-88}{99}\\=\frac{-34}{99}\)
12. \(-\left(\frac{-9}{4}\right)-\left(\frac{-2}{13}\right)\\= \frac{9}{4}+\frac{2}{13}\\=\frac{117}{52}+\frac{8}{52}\\=\frac{117+8}{52}\\=\frac{125}{52}\)