Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{7}{8}\right)+\left(\frac{-2}{3}\right)\)
2. \(+\left(\frac{9}{-10}\right)+\left(\frac{12}{-5}\right)\)
3. \(-\left(\frac{4}{3}\right)-\left(\frac{13}{5}\right)\)
4. \(-\left(\frac{-12}{-5}\right)-\left(\frac{8}{13}\right)\)
5. \(-\left(\frac{12}{-13}\right)+\left(\frac{-6}{-7}\right)\)
6. \(-\left(\frac{4}{13}\right)-\left(\frac{13}{3}\right)\)
7. \(+\left(\frac{-14}{-9}\right)-\left(\frac{3}{-13}\right)\)
8. \(-\left(\frac{-10}{9}\right)+\left(\frac{-10}{-3}\right)\)
9. \(-\left(\frac{-8}{3}\right)+\left(\frac{-10}{13}\right)\)
10. \(-\left(\frac{-11}{-4}\right)+\left(\frac{11}{10}\right)\)
11. \(+\left(\frac{9}{-14}\right)+\left(\frac{-10}{9}\right)\)
12. \(+\left(\frac{-8}{3}\right)-\left(\frac{-14}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{7}{8}\right)+\left(\frac{-2}{3}\right)\\= \frac{7}{8}-\frac{2}{3}\\=\frac{21}{24}-\frac{16}{24}\\=\frac{21-16}{24}\\=\frac{5}{24}\)
2. \(+\left(\frac{9}{-10}\right)+\left(\frac{12}{-5}\right)\\= \frac{-9}{10}-\frac{12}{5}\\=\frac{-9-12}{10}\\=\frac{-21}{10}\)
3. \(-\left(\frac{4}{3}\right)-\left(\frac{13}{5}\right)\\= \frac{-4}{3}-\frac{13}{5}\\=\frac{-20}{15}-\frac{39}{15}\\=\frac{-20-39}{15}\\=\frac{-59}{15}\)
4. \(-\left(\frac{-12}{-5}\right)-\left(\frac{8}{13}\right)\\= \frac{-12}{5}-\frac{8}{13}\\=\frac{-156}{65}-\frac{40}{65}\\=\frac{-156-40}{65}\\=\frac{-196}{65}\)
5. \(-\left(\frac{12}{-13}\right)+\left(\frac{-6}{-7}\right)\\= \frac{12}{13}+\frac{6}{7}\\=\frac{84}{91}+\frac{78}{91}\\=\frac{84+78}{91}\\=\frac{162}{91}\)
6. \(-\left(\frac{4}{13}\right)-\left(\frac{13}{3}\right)\\= \frac{-4}{13}-\frac{13}{3}\\=\frac{-12}{39}-\frac{169}{39}\\=\frac{-12-169}{39}\\=\frac{-181}{39}\)
7. \(+\left(\frac{-14}{-9}\right)-\left(\frac{3}{-13}\right)\\= \frac{14}{9}+\frac{3}{13}\\=\frac{182}{117}+\frac{27}{117}\\=\frac{182+27}{117}\\=\frac{209}{117}\)
8. \(-\left(\frac{-10}{9}\right)+\left(\frac{-10}{-3}\right)\\= \frac{10}{9}+\frac{10}{3}\\=\frac{10+10}{9}\\=\frac{20}{9}\)
9. \(-\left(\frac{-8}{3}\right)+\left(\frac{-10}{13}\right)\\= \frac{8}{3}-\frac{10}{13}\\=\frac{104}{39}-\frac{30}{39}\\=\frac{104-30}{39}\\=\frac{74}{39}\)
10. \(-\left(\frac{-11}{-4}\right)+\left(\frac{11}{10}\right)\\= \frac{-11}{4}+\frac{11}{10}\\=\frac{-55}{20}+\frac{22}{20}\\=\frac{-55+22}{20}\\=\frac{-33}{20}\)
11. \(+\left(\frac{9}{-14}\right)+\left(\frac{-10}{9}\right)\\= \frac{-9}{14}-\frac{10}{9}\\=\frac{-81}{126}-\frac{140}{126}\\=\frac{-81-140}{126}\\=\frac{-221}{126}\)
12. \(+\left(\frac{-8}{3}\right)-\left(\frac{-14}{-5}\right)\\= \frac{-8}{3}-\frac{14}{5}\\=\frac{-40}{15}-\frac{42}{15}\\=\frac{-40-42}{15}\\=\frac{-82}{15}\)