Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{13}{2}\right)+\left(\frac{14}{11}\right)\)
2. \(-\left(\frac{-13}{-3}\right)-\left(\frac{-5}{-6}\right)\)
3. \(+\left(\frac{12}{-5}\right)-\left(\frac{-9}{-4}\right)\)
4. \(+\left(\frac{9}{2}\right)-\left(\frac{-6}{5}\right)\)
5. \(+\left(\frac{-2}{-3}\right)+\left(\frac{6}{-7}\right)\)
6. \(-\left(\frac{-14}{-11}\right)-\left(\frac{-3}{-5}\right)\)
7. \(-\left(\frac{12}{-13}\right)+\left(\frac{-11}{9}\right)\)
8. \(-\left(\frac{3}{8}\right)-\left(\frac{-6}{11}\right)\)
9. \(-\left(\frac{-8}{-3}\right)-\left(\frac{4}{13}\right)\)
10. \(+\left(\frac{8}{5}\right)+\left(\frac{-12}{-5}\right)\)
11. \(+\left(\frac{-5}{6}\right)+\left(\frac{9}{5}\right)\)
12. \(-\left(\frac{9}{2}\right)-\left(\frac{-14}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{13}{2}\right)+\left(\frac{14}{11}\right)\\= \frac{13}{2}+\frac{14}{11}\\=\frac{143}{22}+\frac{28}{22}\\=\frac{143+28}{22}\\=\frac{171}{22}\)
2. \(-\left(\frac{-13}{-3}\right)-\left(\frac{-5}{-6}\right)\\= \frac{-13}{3}-\frac{5}{6}\\=\frac{-26}{6}-\frac{5}{6}\\=\frac{-26-5}{6}\\=\frac{-31}{6}\)
3. \(+\left(\frac{12}{-5}\right)-\left(\frac{-9}{-4}\right)\\= \frac{-12}{5}-\frac{9}{4}\\=\frac{-48}{20}-\frac{45}{20}\\=\frac{-48-45}{20}\\=\frac{-93}{20}\)
4. \(+\left(\frac{9}{2}\right)-\left(\frac{-6}{5}\right)\\= \frac{9}{2}+\frac{6}{5}\\=\frac{45}{10}+\frac{12}{10}\\=\frac{45+12}{10}\\=\frac{57}{10}\)
5. \(+\left(\frac{-2}{-3}\right)+\left(\frac{6}{-7}\right)\\= \frac{2}{3}-\frac{6}{7}\\=\frac{14}{21}-\frac{18}{21}\\=\frac{14-18}{21}\\=\frac{-4}{21}\)
6. \(-\left(\frac{-14}{-11}\right)-\left(\frac{-3}{-5}\right)\\= \frac{-14}{11}-\frac{3}{5}\\=\frac{-70}{55}-\frac{33}{55}\\=\frac{-70-33}{55}\\=\frac{-103}{55}\)
7. \(-\left(\frac{12}{-13}\right)+\left(\frac{-11}{9}\right)\\= \frac{12}{13}-\frac{11}{9}\\=\frac{108}{117}-\frac{143}{117}\\=\frac{108-143}{117}\\=\frac{-35}{117}\)
8. \(-\left(\frac{3}{8}\right)-\left(\frac{-6}{11}\right)\\= \frac{-3}{8}+\frac{6}{11}\\=\frac{-33}{88}+\frac{48}{88}\\=\frac{-33+48}{88}\\=\frac{15}{88}\)
9. \(-\left(\frac{-8}{-3}\right)-\left(\frac{4}{13}\right)\\= \frac{-8}{3}-\frac{4}{13}\\=\frac{-104}{39}-\frac{12}{39}\\=\frac{-104-12}{39}\\=\frac{-116}{39}\)
10. \(+\left(\frac{8}{5}\right)+\left(\frac{-12}{-5}\right)\\= \frac{8}{5}+\frac{12}{5}\\=\frac{8+12}{5}\\=\frac{20}{5}\\=\frac{4}{1}\)
11. \(+\left(\frac{-5}{6}\right)+\left(\frac{9}{5}\right)\\= \frac{-5}{6}+\frac{9}{5}\\=\frac{-25}{30}+\frac{54}{30}\\=\frac{-25+54}{30}\\=\frac{29}{30}\)
12. \(-\left(\frac{9}{2}\right)-\left(\frac{-14}{-3}\right)\\= \frac{-9}{2}-\frac{14}{3}\\=\frac{-27}{6}-\frac{28}{6}\\=\frac{-27-28}{6}\\=\frac{-55}{6}\)