Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-6}{-13}\right)+\left(\frac{-6}{11}\right)\)
2. \(-\left(\frac{-2}{3}\right)+\left(\frac{13}{8}\right)\)
3. \(+\left(\frac{-8}{9}\right)-\left(\frac{6}{-5}\right)\)
4. \(-\left(\frac{-2}{-7}\right)+\left(\frac{-9}{5}\right)\)
5. \(-\left(\frac{12}{-11}\right)-\left(\frac{8}{-3}\right)\)
6. \(+\left(\frac{-3}{-10}\right)-\left(\frac{8}{-13}\right)\)
7. \(-\left(\frac{3}{13}\right)-\left(\frac{3}{5}\right)\)
8. \(-\left(\frac{7}{-10}\right)-\left(\frac{3}{-2}\right)\)
9. \(-\left(\frac{4}{-5}\right)-\left(\frac{-5}{-8}\right)\)
10. \(+\left(\frac{8}{3}\right)+\left(\frac{10}{-11}\right)\)
11. \(+\left(\frac{10}{-11}\right)+\left(\frac{9}{-7}\right)\)
12. \(-\left(\frac{9}{2}\right)-\left(\frac{7}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-6}{-13}\right)+\left(\frac{-6}{11}\right)\\= \frac{6}{13}-\frac{6}{11}\\=\frac{66}{143}-\frac{78}{143}\\=\frac{66-78}{143}\\=\frac{-12}{143}\)
2. \(-\left(\frac{-2}{3}\right)+\left(\frac{13}{8}\right)\\= \frac{2}{3}+\frac{13}{8}\\=\frac{16}{24}+\frac{39}{24}\\=\frac{16+39}{24}\\=\frac{55}{24}\)
3. \(+\left(\frac{-8}{9}\right)-\left(\frac{6}{-5}\right)\\= \frac{-8}{9}+\frac{6}{5}\\=\frac{-40}{45}+\frac{54}{45}\\=\frac{-40+54}{45}\\=\frac{14}{45}\)
4. \(-\left(\frac{-2}{-7}\right)+\left(\frac{-9}{5}\right)\\= \frac{-2}{7}-\frac{9}{5}\\=\frac{-10}{35}-\frac{63}{35}\\=\frac{-10-63}{35}\\=\frac{-73}{35}\)
5. \(-\left(\frac{12}{-11}\right)-\left(\frac{8}{-3}\right)\\= \frac{12}{11}+\frac{8}{3}\\=\frac{36}{33}+\frac{88}{33}\\=\frac{36+88}{33}\\=\frac{124}{33}\)
6. \(+\left(\frac{-3}{-10}\right)-\left(\frac{8}{-13}\right)\\= \frac{3}{10}+\frac{8}{13}\\=\frac{39}{130}+\frac{80}{130}\\=\frac{39+80}{130}\\=\frac{119}{130}\)
7. \(-\left(\frac{3}{13}\right)-\left(\frac{3}{5}\right)\\= \frac{-3}{13}-\frac{3}{5}\\=\frac{-15}{65}-\frac{39}{65}\\=\frac{-15-39}{65}\\=\frac{-54}{65}\)
8. \(-\left(\frac{7}{-10}\right)-\left(\frac{3}{-2}\right)\\= \frac{7}{10}+\frac{3}{2}\\=\frac{7+3}{10}\\=\frac{10}{10}\\=\frac{1}{1}\)
9. \(-\left(\frac{4}{-5}\right)-\left(\frac{-5}{-8}\right)\\= \frac{4}{5}-\frac{5}{8}\\=\frac{32}{40}-\frac{25}{40}\\=\frac{32-25}{40}\\=\frac{7}{40}\)
10. \(+\left(\frac{8}{3}\right)+\left(\frac{10}{-11}\right)\\= \frac{8}{3}-\frac{10}{11}\\=\frac{88}{33}-\frac{30}{33}\\=\frac{88-30}{33}\\=\frac{58}{33}\)
11. \(+\left(\frac{10}{-11}\right)+\left(\frac{9}{-7}\right)\\= \frac{-10}{11}-\frac{9}{7}\\=\frac{-70}{77}-\frac{99}{77}\\=\frac{-70-99}{77}\\=\frac{-169}{77}\)
12. \(-\left(\frac{9}{2}\right)-\left(\frac{7}{-11}\right)\\= \frac{-9}{2}+\frac{7}{11}\\=\frac{-99}{22}+\frac{14}{22}\\=\frac{-99+14}{22}\\=\frac{-85}{22}\)