Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{5}{-9}\right)+\left(\frac{7}{-8}\right)\)
2. \(+\left(\frac{12}{11}\right)+\left(\frac{-3}{-2}\right)\)
3. \(+\left(\frac{-6}{11}\right)+\left(\frac{-10}{-7}\right)\)
4. \(+\left(\frac{-8}{7}\right)-\left(\frac{-15}{7}\right)\)
5. \(-\left(\frac{3}{-10}\right)+\left(\frac{-2}{-3}\right)\)
6. \(-\left(\frac{5}{-13}\right)+\left(\frac{10}{-3}\right)\)
7. \(+\left(\frac{15}{11}\right)-\left(\frac{-13}{-3}\right)\)
8. \(-\left(\frac{-3}{11}\right)+\left(\frac{11}{10}\right)\)
9. \(+\left(\frac{-12}{5}\right)+\left(\frac{13}{14}\right)\)
10. \(+\left(\frac{-13}{-14}\right)-\left(\frac{12}{-11}\right)\)
11. \(+\left(\frac{-10}{7}\right)+\left(\frac{12}{-5}\right)\)
12. \(+\left(\frac{-2}{-9}\right)+\left(\frac{-13}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{5}{-9}\right)+\left(\frac{7}{-8}\right)\\= \frac{-5}{9}-\frac{7}{8}\\=\frac{-40}{72}-\frac{63}{72}\\=\frac{-40-63}{72}\\=\frac{-103}{72}\)
2. \(+\left(\frac{12}{11}\right)+\left(\frac{-3}{-2}\right)\\= \frac{12}{11}+\frac{3}{2}\\=\frac{24}{22}+\frac{33}{22}\\=\frac{24+33}{22}\\=\frac{57}{22}\)
3. \(+\left(\frac{-6}{11}\right)+\left(\frac{-10}{-7}\right)\\= \frac{-6}{11}+\frac{10}{7}\\=\frac{-42}{77}+\frac{110}{77}\\=\frac{-42+110}{77}\\=\frac{68}{77}\)
4. \(+\left(\frac{-8}{7}\right)-\left(\frac{-15}{7}\right)\\= \frac{-8}{7}+\frac{15}{7}\\=\frac{-8+15}{7}\\=\frac{7}{7}\\=\frac{1}{1}\)
5. \(-\left(\frac{3}{-10}\right)+\left(\frac{-2}{-3}\right)\\= \frac{3}{10}+\frac{2}{3}\\=\frac{9}{30}+\frac{20}{30}\\=\frac{9+20}{30}\\=\frac{29}{30}\)
6. \(-\left(\frac{5}{-13}\right)+\left(\frac{10}{-3}\right)\\= \frac{5}{13}-\frac{10}{3}\\=\frac{15}{39}-\frac{130}{39}\\=\frac{15-130}{39}\\=\frac{-115}{39}\)
7. \(+\left(\frac{15}{11}\right)-\left(\frac{-13}{-3}\right)\\= \frac{15}{11}-\frac{13}{3}\\=\frac{45}{33}-\frac{143}{33}\\=\frac{45-143}{33}\\=\frac{-98}{33}\)
8. \(-\left(\frac{-3}{11}\right)+\left(\frac{11}{10}\right)\\= \frac{3}{11}+\frac{11}{10}\\=\frac{30}{110}+\frac{121}{110}\\=\frac{30+121}{110}\\=\frac{151}{110}\)
9. \(+\left(\frac{-12}{5}\right)+\left(\frac{13}{14}\right)\\= \frac{-12}{5}+\frac{13}{14}\\=\frac{-168}{70}+\frac{65}{70}\\=\frac{-168+65}{70}\\=\frac{-103}{70}\)
10. \(+\left(\frac{-13}{-14}\right)-\left(\frac{12}{-11}\right)\\= \frac{13}{14}+\frac{12}{11}\\=\frac{143}{154}+\frac{168}{154}\\=\frac{143+168}{154}\\=\frac{311}{154}\)
11. \(+\left(\frac{-10}{7}\right)+\left(\frac{12}{-5}\right)\\= \frac{-10}{7}-\frac{12}{5}\\=\frac{-50}{35}-\frac{84}{35}\\=\frac{-50-84}{35}\\=\frac{-134}{35}\)
12. \(+\left(\frac{-2}{-9}\right)+\left(\frac{-13}{-7}\right)\\= \frac{2}{9}+\frac{13}{7}\\=\frac{14}{63}+\frac{117}{63}\\=\frac{14+117}{63}\\=\frac{131}{63}\)