Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-5}{9}\right)+\left(\frac{10}{-11}\right)\)
2. \(-\left(\frac{-6}{-13}\right)-\left(\frac{10}{-3}\right)\)
3. \(+\left(\frac{7}{-10}\right)-\left(\frac{14}{-9}\right)\)
4. \(-\left(\frac{2}{-3}\right)-\left(\frac{4}{5}\right)\)
5. \(+\left(\frac{12}{-5}\right)-\left(\frac{3}{5}\right)\)
6. \(+\left(\frac{4}{-5}\right)+\left(\frac{-4}{7}\right)\)
7. \(+\left(\frac{5}{-13}\right)-\left(\frac{-4}{11}\right)\)
8. \(+\left(\frac{-2}{11}\right)+\left(\frac{10}{-9}\right)\)
9. \(+\left(\frac{5}{12}\right)-\left(\frac{-12}{5}\right)\)
10. \(-\left(\frac{-11}{-2}\right)-\left(\frac{7}{3}\right)\)
11. \(-\left(\frac{-14}{3}\right)+\left(\frac{4}{-3}\right)\)
12. \(-\left(\frac{-15}{-4}\right)-\left(\frac{11}{8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-5}{9}\right)+\left(\frac{10}{-11}\right)\\= \frac{-5}{9}-\frac{10}{11}\\=\frac{-55}{99}-\frac{90}{99}\\=\frac{-55-90}{99}\\=\frac{-145}{99}\)
2. \(-\left(\frac{-6}{-13}\right)-\left(\frac{10}{-3}\right)\\= \frac{-6}{13}+\frac{10}{3}\\=\frac{-18}{39}+\frac{130}{39}\\=\frac{-18+130}{39}\\=\frac{112}{39}\)
3. \(+\left(\frac{7}{-10}\right)-\left(\frac{14}{-9}\right)\\= \frac{-7}{10}+\frac{14}{9}\\=\frac{-63}{90}+\frac{140}{90}\\=\frac{-63+140}{90}\\=\frac{77}{90}\)
4. \(-\left(\frac{2}{-3}\right)-\left(\frac{4}{5}\right)\\= \frac{2}{3}-\frac{4}{5}\\=\frac{10}{15}-\frac{12}{15}\\=\frac{10-12}{15}\\=\frac{-2}{15}\)
5. \(+\left(\frac{12}{-5}\right)-\left(\frac{3}{5}\right)\\= \frac{-12}{5}-\frac{3}{5}\\=\frac{-12-3}{5}\\=\frac{-15}{5}\\=\frac{-3}{1}\)
6. \(+\left(\frac{4}{-5}\right)+\left(\frac{-4}{7}\right)\\= \frac{-4}{5}-\frac{4}{7}\\=\frac{-28}{35}-\frac{20}{35}\\=\frac{-28-20}{35}\\=\frac{-48}{35}\)
7. \(+\left(\frac{5}{-13}\right)-\left(\frac{-4}{11}\right)\\= \frac{-5}{13}+\frac{4}{11}\\=\frac{-55}{143}+\frac{52}{143}\\=\frac{-55+52}{143}\\=\frac{-3}{143}\)
8. \(+\left(\frac{-2}{11}\right)+\left(\frac{10}{-9}\right)\\= \frac{-2}{11}-\frac{10}{9}\\=\frac{-18}{99}-\frac{110}{99}\\=\frac{-18-110}{99}\\=\frac{-128}{99}\)
9. \(+\left(\frac{5}{12}\right)-\left(\frac{-12}{5}\right)\\= \frac{5}{12}+\frac{12}{5}\\=\frac{25}{60}+\frac{144}{60}\\=\frac{25+144}{60}\\=\frac{169}{60}\)
10. \(-\left(\frac{-11}{-2}\right)-\left(\frac{7}{3}\right)\\= \frac{-11}{2}-\frac{7}{3}\\=\frac{-33}{6}-\frac{14}{6}\\=\frac{-33-14}{6}\\=\frac{-47}{6}\)
11. \(-\left(\frac{-14}{3}\right)+\left(\frac{4}{-3}\right)\\= \frac{14}{3}-\frac{4}{3}\\=\frac{14-4}{3}\\=\frac{10}{3}\)
12. \(-\left(\frac{-15}{-4}\right)-\left(\frac{11}{8}\right)\\= \frac{-15}{4}-\frac{11}{8}\\=\frac{-30}{8}-\frac{11}{8}\\=\frac{-30-11}{8}\\=\frac{-41}{8}\)