Bereken
- \(-\left(\frac{10}{-3}\right)-\left(\frac{8}{3}\right)\)
- \(-\left(\frac{11}{10}\right)+\left(\frac{-9}{11}\right)\)
- \(-\left(\frac{10}{7}\right)-\left(\frac{7}{-13}\right)\)
- \(-\left(\frac{3}{-13}\right)+\left(\frac{12}{-11}\right)\)
- \(+\left(\frac{-14}{-11}\right)-\left(\frac{-6}{13}\right)\)
- \(+\left(\frac{15}{-4}\right)-\left(\frac{-15}{-2}\right)\)
- \(-\left(\frac{4}{-3}\right)-\left(\frac{14}{-3}\right)\)
- \(+\left(\frac{-9}{14}\right)-\left(\frac{-12}{11}\right)\)
- \(+\left(\frac{7}{2}\right)+\left(\frac{-12}{5}\right)\)
- \(+\left(\frac{-10}{-13}\right)+\left(\frac{15}{-13}\right)\)
- \(+\left(\frac{5}{2}\right)-\left(\frac{-10}{-11}\right)\)
- \(+\left(\frac{-8}{3}\right)+\left(\frac{-4}{-11}\right)\)
Bereken
Verbetersleutel
- \(-\left(\frac{10}{-3}\right)-\left(\frac{8}{3}\right)\\= \frac{10}{3}-\frac{8}{3}\\=\frac{10-8}{3}\\=\frac{2}{3}\)
- \(-\left(\frac{11}{10}\right)+\left(\frac{-9}{11}\right)\\= \frac{-11}{10}-\frac{9}{11}\\=\frac{-121}{110}-\frac{90}{110}\\=\frac{-121-90}{110}\\=\frac{-211}{110}\)
- \(-\left(\frac{10}{7}\right)-\left(\frac{7}{-13}\right)\\= \frac{-10}{7}+\frac{7}{13}\\=\frac{-130}{91}+\frac{49}{91}\\=\frac{-130+49}{91}\\=\frac{-81}{91}\)
- \(-\left(\frac{3}{-13}\right)+\left(\frac{12}{-11}\right)\\= \frac{3}{13}-\frac{12}{11}\\=\frac{33}{143}-\frac{156}{143}\\=\frac{33-156}{143}\\=\frac{-123}{143}\)
- \(+\left(\frac{-14}{-11}\right)-\left(\frac{-6}{13}\right)\\= \frac{14}{11}+\frac{6}{13}\\=\frac{182}{143}+\frac{66}{143}\\=\frac{182+66}{143}\\=\frac{248}{143}\)
- \(+\left(\frac{15}{-4}\right)-\left(\frac{-15}{-2}\right)\\= \frac{-15}{4}-\frac{15}{2}\\=\frac{-15-15}{4}\\=\frac{-30}{4}\\=\frac{-15}{2}\)
- \(-\left(\frac{4}{-3}\right)-\left(\frac{14}{-3}\right)\\= \frac{4}{3}+\frac{14}{3}\\=\frac{4+14}{3}\\=\frac{18}{3}\\=\frac{6}{1}\)
- \(+\left(\frac{-9}{14}\right)-\left(\frac{-12}{11}\right)\\= \frac{-9}{14}+\frac{12}{11}\\=\frac{-99}{154}+\frac{168}{154}\\=\frac{-99+168}{154}\\=\frac{69}{154}\)
- \(+\left(\frac{7}{2}\right)+\left(\frac{-12}{5}\right)\\= \frac{7}{2}-\frac{12}{5}\\=\frac{35}{10}-\frac{24}{10}\\=\frac{35-24}{10}\\=\frac{11}{10}\)
- \(+\left(\frac{-10}{-13}\right)+\left(\frac{15}{-13}\right)\\= \frac{10}{13}-\frac{15}{13}\\=\frac{10-15}{13}\\=\frac{-5}{13}\)
- \(+\left(\frac{5}{2}\right)-\left(\frac{-10}{-11}\right)\\= \frac{5}{2}-\frac{10}{11}\\=\frac{55}{22}-\frac{20}{22}\\=\frac{55-20}{22}\\=\frac{35}{22}\)
- \(+\left(\frac{-8}{3}\right)+\left(\frac{-4}{-11}\right)\\= \frac{-8}{3}+\frac{4}{11}\\=\frac{-88}{33}+\frac{12}{33}\\=\frac{-88+12}{33}\\=\frac{-76}{33}\)