Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-6}{-5}\right)-\left(\frac{-15}{-7}\right)\)
2. \(-\left(\frac{-4}{-3}\right)-\left(\frac{6}{7}\right)\)
3. \(+\left(\frac{14}{-11}\right)-\left(\frac{-7}{6}\right)\)
4. \(-\left(\frac{-12}{11}\right)-\left(\frac{-6}{-13}\right)\)
5. \(+\left(\frac{-3}{10}\right)-\left(\frac{9}{-10}\right)\)
6. \(-\left(\frac{11}{-4}\right)+\left(\frac{-8}{-3}\right)\)
7. \(-\left(\frac{-12}{-5}\right)-\left(\frac{9}{10}\right)\)
8. \(+\left(\frac{8}{-3}\right)+\left(\frac{-9}{-4}\right)\)
9. \(-\left(\frac{-4}{11}\right)+\left(\frac{-3}{-13}\right)\)
10. \(-\left(\frac{-11}{-10}\right)-\left(\frac{13}{-4}\right)\)
11. \(-\left(\frac{12}{11}\right)-\left(\frac{2}{-7}\right)\)
12. \(-\left(\frac{9}{-2}\right)+\left(\frac{-12}{5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-6}{-5}\right)-\left(\frac{-15}{-7}\right)\\= \frac{6}{5}-\frac{15}{7}\\=\frac{42}{35}-\frac{75}{35}\\=\frac{42-75}{35}\\=\frac{-33}{35}\)
2. \(-\left(\frac{-4}{-3}\right)-\left(\frac{6}{7}\right)\\= \frac{-4}{3}-\frac{6}{7}\\=\frac{-28}{21}-\frac{18}{21}\\=\frac{-28-18}{21}\\=\frac{-46}{21}\)
3. \(+\left(\frac{14}{-11}\right)-\left(\frac{-7}{6}\right)\\= \frac{-14}{11}+\frac{7}{6}\\=\frac{-84}{66}+\frac{77}{66}\\=\frac{-84+77}{66}\\=\frac{-7}{66}\)
4. \(-\left(\frac{-12}{11}\right)-\left(\frac{-6}{-13}\right)\\= \frac{12}{11}-\frac{6}{13}\\=\frac{156}{143}-\frac{66}{143}\\=\frac{156-66}{143}\\=\frac{90}{143}\)
5. \(+\left(\frac{-3}{10}\right)-\left(\frac{9}{-10}\right)\\= \frac{-3}{10}+\frac{9}{10}\\=\frac{-3+9}{10}\\=\frac{6}{10}\\=\frac{3}{5}\)
6. \(-\left(\frac{11}{-4}\right)+\left(\frac{-8}{-3}\right)\\= \frac{11}{4}+\frac{8}{3}\\=\frac{33}{12}+\frac{32}{12}\\=\frac{33+32}{12}\\=\frac{65}{12}\)
7. \(-\left(\frac{-12}{-5}\right)-\left(\frac{9}{10}\right)\\= \frac{-12}{5}-\frac{9}{10}\\=\frac{-24}{10}-\frac{9}{10}\\=\frac{-24-9}{10}\\=\frac{-33}{10}\)
8. \(+\left(\frac{8}{-3}\right)+\left(\frac{-9}{-4}\right)\\= \frac{-8}{3}+\frac{9}{4}\\=\frac{-32}{12}+\frac{27}{12}\\=\frac{-32+27}{12}\\=\frac{-5}{12}\)
9. \(-\left(\frac{-4}{11}\right)+\left(\frac{-3}{-13}\right)\\= \frac{4}{11}+\frac{3}{13}\\=\frac{52}{143}+\frac{33}{143}\\=\frac{52+33}{143}\\=\frac{85}{143}\)
10. \(-\left(\frac{-11}{-10}\right)-\left(\frac{13}{-4}\right)\\= \frac{-11}{10}+\frac{13}{4}\\=\frac{-22}{20}+\frac{65}{20}\\=\frac{-22+65}{20}\\=\frac{43}{20}\)
11. \(-\left(\frac{12}{11}\right)-\left(\frac{2}{-7}\right)\\= \frac{-12}{11}+\frac{2}{7}\\=\frac{-84}{77}+\frac{22}{77}\\=\frac{-84+22}{77}\\=\frac{-62}{77}\)
12. \(-\left(\frac{9}{-2}\right)+\left(\frac{-12}{5}\right)\\= \frac{9}{2}-\frac{12}{5}\\=\frac{45}{10}-\frac{24}{10}\\=\frac{45-24}{10}\\=\frac{21}{10}\)