Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-3}{-14}\right)+\left(\frac{-15}{-11}\right)\)
2. \(-\left(\frac{9}{7}\right)+\left(\frac{-10}{-9}\right)\)
3. \(+\left(\frac{-7}{-10}\right)+\left(\frac{6}{-11}\right)\)
4. \(+\left(\frac{13}{10}\right)+\left(\frac{-7}{-9}\right)\)
5. \(-\left(\frac{-3}{-8}\right)-\left(\frac{-8}{-11}\right)\)
6. \(+\left(\frac{4}{9}\right)+\left(\frac{15}{-13}\right)\)
7. \(-\left(\frac{10}{-11}\right)-\left(\frac{3}{-13}\right)\)
8. \(-\left(\frac{-9}{-10}\right)-\left(\frac{9}{8}\right)\)
9. \(+\left(\frac{-12}{5}\right)-\left(\frac{13}{14}\right)\)
10. \(+\left(\frac{-11}{-8}\right)+\left(\frac{-15}{13}\right)\)
11. \(-\left(\frac{4}{-3}\right)-\left(\frac{13}{12}\right)\)
12. \(+\left(\frac{-13}{-7}\right)+\left(\frac{11}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-3}{-14}\right)+\left(\frac{-15}{-11}\right)\\= \frac{3}{14}+\frac{15}{11}\\=\frac{33}{154}+\frac{210}{154}\\=\frac{33+210}{154}\\=\frac{243}{154}\)
2. \(-\left(\frac{9}{7}\right)+\left(\frac{-10}{-9}\right)\\= \frac{-9}{7}+\frac{10}{9}\\=\frac{-81}{63}+\frac{70}{63}\\=\frac{-81+70}{63}\\=\frac{-11}{63}\)
3. \(+\left(\frac{-7}{-10}\right)+\left(\frac{6}{-11}\right)\\= \frac{7}{10}-\frac{6}{11}\\=\frac{77}{110}-\frac{60}{110}\\=\frac{77-60}{110}\\=\frac{17}{110}\)
4. \(+\left(\frac{13}{10}\right)+\left(\frac{-7}{-9}\right)\\= \frac{13}{10}+\frac{7}{9}\\=\frac{117}{90}+\frac{70}{90}\\=\frac{117+70}{90}\\=\frac{187}{90}\)
5. \(-\left(\frac{-3}{-8}\right)-\left(\frac{-8}{-11}\right)\\= \frac{-3}{8}-\frac{8}{11}\\=\frac{-33}{88}-\frac{64}{88}\\=\frac{-33-64}{88}\\=\frac{-97}{88}\)
6. \(+\left(\frac{4}{9}\right)+\left(\frac{15}{-13}\right)\\= \frac{4}{9}-\frac{15}{13}\\=\frac{52}{117}-\frac{135}{117}\\=\frac{52-135}{117}\\=\frac{-83}{117}\)
7. \(-\left(\frac{10}{-11}\right)-\left(\frac{3}{-13}\right)\\= \frac{10}{11}+\frac{3}{13}\\=\frac{130}{143}+\frac{33}{143}\\=\frac{130+33}{143}\\=\frac{163}{143}\)
8. \(-\left(\frac{-9}{-10}\right)-\left(\frac{9}{8}\right)\\= \frac{-9}{10}-\frac{9}{8}\\=\frac{-36}{40}-\frac{45}{40}\\=\frac{-36-45}{40}\\=\frac{-81}{40}\)
9. \(+\left(\frac{-12}{5}\right)-\left(\frac{13}{14}\right)\\= \frac{-12}{5}-\frac{13}{14}\\=\frac{-168}{70}-\frac{65}{70}\\=\frac{-168-65}{70}\\=\frac{-233}{70}\)
10. \(+\left(\frac{-11}{-8}\right)+\left(\frac{-15}{13}\right)\\= \frac{11}{8}-\frac{15}{13}\\=\frac{143}{104}-\frac{120}{104}\\=\frac{143-120}{104}\\=\frac{23}{104}\)
11. \(-\left(\frac{4}{-3}\right)-\left(\frac{13}{12}\right)\\= \frac{4}{3}-\frac{13}{12}\\=\frac{16}{12}-\frac{13}{12}\\=\frac{16-13}{12}\\=\frac{3}{12}\\=\frac{1}{4}\)
12. \(+\left(\frac{-13}{-7}\right)+\left(\frac{11}{-7}\right)\\= \frac{13}{7}-\frac{11}{7}\\=\frac{13-11}{7}\\=\frac{2}{7}\)