Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{-7}\right)-\left(\frac{-6}{-11}\right)\)
2. \(+\left(\frac{-3}{-2}\right)-\left(\frac{-4}{5}\right)\)
3. \(-\left(\frac{7}{13}\right)+\left(\frac{7}{-8}\right)\)
4. \(-\left(\frac{14}{-11}\right)-\left(\frac{-5}{-9}\right)\)
5. \(-\left(\frac{15}{-4}\right)-\left(\frac{-10}{13}\right)\)
6. \(-\left(\frac{-11}{-13}\right)-\left(\frac{7}{-2}\right)\)
7. \(-\left(\frac{3}{10}\right)+\left(\frac{-7}{-2}\right)\)
8. \(+\left(\frac{-13}{2}\right)+\left(\frac{-7}{-8}\right)\)
9. \(-\left(\frac{10}{-11}\right)-\left(\frac{8}{5}\right)\)
10. \(+\left(\frac{-15}{-7}\right)-\left(\frac{-12}{-5}\right)\)
11. \(-\left(\frac{-12}{-11}\right)+\left(\frac{-12}{-7}\right)\)
12. \(+\left(\frac{-4}{-9}\right)-\left(\frac{15}{-8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{10}{-7}\right)-\left(\frac{-6}{-11}\right)\\= \frac{-10}{7}-\frac{6}{11}\\=\frac{-110}{77}-\frac{42}{77}\\=\frac{-110-42}{77}\\=\frac{-152}{77}\)
2. \(+\left(\frac{-3}{-2}\right)-\left(\frac{-4}{5}\right)\\= \frac{3}{2}+\frac{4}{5}\\=\frac{15}{10}+\frac{8}{10}\\=\frac{15+8}{10}\\=\frac{23}{10}\)
3. \(-\left(\frac{7}{13}\right)+\left(\frac{7}{-8}\right)\\= \frac{-7}{13}-\frac{7}{8}\\=\frac{-56}{104}-\frac{91}{104}\\=\frac{-56-91}{104}\\=\frac{-147}{104}\)
4. \(-\left(\frac{14}{-11}\right)-\left(\frac{-5}{-9}\right)\\= \frac{14}{11}-\frac{5}{9}\\=\frac{126}{99}-\frac{55}{99}\\=\frac{126-55}{99}\\=\frac{71}{99}\)
5. \(-\left(\frac{15}{-4}\right)-\left(\frac{-10}{13}\right)\\= \frac{15}{4}+\frac{10}{13}\\=\frac{195}{52}+\frac{40}{52}\\=\frac{195+40}{52}\\=\frac{235}{52}\)
6. \(-\left(\frac{-11}{-13}\right)-\left(\frac{7}{-2}\right)\\= \frac{-11}{13}+\frac{7}{2}\\=\frac{-22}{26}+\frac{91}{26}\\=\frac{-22+91}{26}\\=\frac{69}{26}\)
7. \(-\left(\frac{3}{10}\right)+\left(\frac{-7}{-2}\right)\\= \frac{-3}{10}+\frac{7}{2}\\=\frac{-3+7}{10}\\=\frac{4}{10}\\=\frac{2}{5}\)
8. \(+\left(\frac{-13}{2}\right)+\left(\frac{-7}{-8}\right)\\= \frac{-13}{2}+\frac{7}{8}\\=\frac{-52}{8}+\frac{7}{8}\\=\frac{-52+7}{8}\\=\frac{-45}{8}\)
9. \(-\left(\frac{10}{-11}\right)-\left(\frac{8}{5}\right)\\= \frac{10}{11}-\frac{8}{5}\\=\frac{50}{55}-\frac{88}{55}\\=\frac{50-88}{55}\\=\frac{-38}{55}\)
10. \(+\left(\frac{-15}{-7}\right)-\left(\frac{-12}{-5}\right)\\= \frac{15}{7}-\frac{12}{5}\\=\frac{75}{35}-\frac{84}{35}\\=\frac{75-84}{35}\\=\frac{-9}{35}\)
11. \(-\left(\frac{-12}{-11}\right)+\left(\frac{-12}{-7}\right)\\= \frac{-12}{11}+\frac{12}{7}\\=\frac{-84}{77}+\frac{132}{77}\\=\frac{-84+132}{77}\\=\frac{48}{77}\)
12. \(+\left(\frac{-4}{-9}\right)-\left(\frac{15}{-8}\right)\\= \frac{4}{9}+\frac{15}{8}\\=\frac{32}{72}+\frac{135}{72}\\=\frac{32+135}{72}\\=\frac{167}{72}\)