Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-4}{3}\right)-\left(\frac{3}{14}\right)\)
2. \(-\left(\frac{-5}{-7}\right)-\left(\frac{-9}{-4}\right)\)
3. \(-\left(\frac{-13}{-5}\right)-\left(\frac{12}{11}\right)\)
4. \(-\left(\frac{-3}{-8}\right)-\left(\frac{11}{13}\right)\)
5. \(-\left(\frac{-4}{-3}\right)+\left(\frac{6}{5}\right)\)
6. \(+\left(\frac{-3}{8}\right)+\left(\frac{-3}{-4}\right)\)
7. \(-\left(\frac{11}{-14}\right)-\left(\frac{6}{-5}\right)\)
8. \(+\left(\frac{-6}{-5}\right)+\left(\frac{-14}{13}\right)\)
9. \(+\left(\frac{15}{13}\right)+\left(\frac{15}{4}\right)\)
10. \(+\left(\frac{9}{5}\right)-\left(\frac{-10}{-7}\right)\)
11. \(-\left(\frac{-5}{11}\right)+\left(\frac{10}{-7}\right)\)
12. \(+\left(\frac{15}{11}\right)-\left(\frac{-10}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-4}{3}\right)-\left(\frac{3}{14}\right)\\= \frac{-4}{3}-\frac{3}{14}\\=\frac{-56}{42}-\frac{9}{42}\\=\frac{-56-9}{42}\\=\frac{-65}{42}\)
2. \(-\left(\frac{-5}{-7}\right)-\left(\frac{-9}{-4}\right)\\= \frac{-5}{7}-\frac{9}{4}\\=\frac{-20}{28}-\frac{63}{28}\\=\frac{-20-63}{28}\\=\frac{-83}{28}\)
3. \(-\left(\frac{-13}{-5}\right)-\left(\frac{12}{11}\right)\\= \frac{-13}{5}-\frac{12}{11}\\=\frac{-143}{55}-\frac{60}{55}\\=\frac{-143-60}{55}\\=\frac{-203}{55}\)
4. \(-\left(\frac{-3}{-8}\right)-\left(\frac{11}{13}\right)\\= \frac{-3}{8}-\frac{11}{13}\\=\frac{-39}{104}-\frac{88}{104}\\=\frac{-39-88}{104}\\=\frac{-127}{104}\)
5. \(-\left(\frac{-4}{-3}\right)+\left(\frac{6}{5}\right)\\= \frac{-4}{3}+\frac{6}{5}\\=\frac{-20}{15}+\frac{18}{15}\\=\frac{-20+18}{15}\\=\frac{-2}{15}\)
6. \(+\left(\frac{-3}{8}\right)+\left(\frac{-3}{-4}\right)\\= \frac{-3}{8}+\frac{3}{4}\\=\frac{-3+3}{8}\\=\frac{0}{8}\\=\frac{0}{1}\)
7. \(-\left(\frac{11}{-14}\right)-\left(\frac{6}{-5}\right)\\= \frac{11}{14}+\frac{6}{5}\\=\frac{55}{70}+\frac{84}{70}\\=\frac{55+84}{70}\\=\frac{139}{70}\)
8. \(+\left(\frac{-6}{-5}\right)+\left(\frac{-14}{13}\right)\\= \frac{6}{5}-\frac{14}{13}\\=\frac{78}{65}-\frac{70}{65}\\=\frac{78-70}{65}\\=\frac{8}{65}\)
9. \(+\left(\frac{15}{13}\right)+\left(\frac{15}{4}\right)\\= \frac{15}{13}+\frac{15}{4}\\=\frac{60}{52}+\frac{195}{52}\\=\frac{60+195}{52}\\=\frac{255}{52}\)
10. \(+\left(\frac{9}{5}\right)-\left(\frac{-10}{-7}\right)\\= \frac{9}{5}-\frac{10}{7}\\=\frac{63}{35}-\frac{50}{35}\\=\frac{63-50}{35}\\=\frac{13}{35}\)
11. \(-\left(\frac{-5}{11}\right)+\left(\frac{10}{-7}\right)\\= \frac{5}{11}-\frac{10}{7}\\=\frac{35}{77}-\frac{110}{77}\\=\frac{35-110}{77}\\=\frac{-75}{77}\)
12. \(+\left(\frac{15}{11}\right)-\left(\frac{-10}{-11}\right)\\= \frac{15}{11}-\frac{10}{11}\\=\frac{15-10}{11}\\=\frac{5}{11}\)