Breuken haakjesregel (reeks 1)

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Bereken

1. \(+\left(\frac{-9}{4}\right)-\left(\frac{-12}{-5}\right)\)
2. \(+\left(\frac{9}{13}\right)+\left(\frac{6}{-11}\right)\)
3. \(+\left(\frac{10}{3}\right)-\left(\frac{3}{5}\right)\)
4. \(-\left(\frac{8}{-3}\right)+\left(\frac{8}{5}\right)\)
5. \(-\left(\frac{-7}{-2}\right)+\left(\frac{-13}{8}\right)\)
6. \(+\left(\frac{2}{-3}\right)-\left(\frac{6}{5}\right)\)
7. \(+\left(\frac{11}{-14}\right)-\left(\frac{-3}{-7}\right)\)
8. \(-\left(\frac{4}{-9}\right)-\left(\frac{-5}{2}\right)\)
9. \(+\left(\frac{9}{13}\right)-\left(\frac{-15}{-7}\right)\)
10. \(-\left(\frac{2}{13}\right)+\left(\frac{-6}{-5}\right)\)
11. \(-\left(\frac{-11}{-8}\right)-\left(\frac{-10}{-3}\right)\)
12. \(+\left(\frac{2}{13}\right)-\left(\frac{-3}{-10}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-9}{4}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-9}{4}-\frac{12}{5}\\=\frac{-45}{20}-\frac{48}{20}\\=\frac{-45-48}{20}\\=\frac{-93}{20}\)
2. \(+\left(\frac{9}{13}\right)+\left(\frac{6}{-11}\right)\\= \frac{9}{13}-\frac{6}{11}\\=\frac{99}{143}-\frac{78}{143}\\=\frac{99-78}{143}\\=\frac{21}{143}\)
3. \(+\left(\frac{10}{3}\right)-\left(\frac{3}{5}\right)\\= \frac{10}{3}-\frac{3}{5}\\=\frac{50}{15}-\frac{9}{15}\\=\frac{50-9}{15}\\=\frac{41}{15}\)
4. \(-\left(\frac{8}{-3}\right)+\left(\frac{8}{5}\right)\\= \frac{8}{3}+\frac{8}{5}\\=\frac{40}{15}+\frac{24}{15}\\=\frac{40+24}{15}\\=\frac{64}{15}\)
5. \(-\left(\frac{-7}{-2}\right)+\left(\frac{-13}{8}\right)\\= \frac{-7}{2}-\frac{13}{8}\\=\frac{-28}{8}-\frac{13}{8}\\=\frac{-28-13}{8}\\=\frac{-41}{8}\)
6. \(+\left(\frac{2}{-3}\right)-\left(\frac{6}{5}\right)\\= \frac{-2}{3}-\frac{6}{5}\\=\frac{-10}{15}-\frac{18}{15}\\=\frac{-10-18}{15}\\=\frac{-28}{15}\)
7. \(+\left(\frac{11}{-14}\right)-\left(\frac{-3}{-7}\right)\\= \frac{-11}{14}-\frac{3}{7}\\=\frac{-11-3}{14}\\=\frac{-14}{14}\\=\frac{-1}{1}\)
8. \(-\left(\frac{4}{-9}\right)-\left(\frac{-5}{2}\right)\\= \frac{4}{9}+\frac{5}{2}\\=\frac{8}{18}+\frac{45}{18}\\=\frac{8+45}{18}\\=\frac{53}{18}\)
9. \(+\left(\frac{9}{13}\right)-\left(\frac{-15}{-7}\right)\\= \frac{9}{13}-\frac{15}{7}\\=\frac{63}{91}-\frac{195}{91}\\=\frac{63-195}{91}\\=\frac{-132}{91}\)
10. \(-\left(\frac{2}{13}\right)+\left(\frac{-6}{-5}\right)\\= \frac{-2}{13}+\frac{6}{5}\\=\frac{-10}{65}+\frac{78}{65}\\=\frac{-10+78}{65}\\=\frac{68}{65}\)
11. \(-\left(\frac{-11}{-8}\right)-\left(\frac{-10}{-3}\right)\\= \frac{-11}{8}-\frac{10}{3}\\=\frac{-33}{24}-\frac{80}{24}\\=\frac{-33-80}{24}\\=\frac{-113}{24}\)
12. \(+\left(\frac{2}{13}\right)-\left(\frac{-3}{-10}\right)\\= \frac{2}{13}-\frac{3}{10}\\=\frac{20}{130}-\frac{39}{130}\\=\frac{20-39}{130}\\=\frac{-19}{130}\)