Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-3}{4}\right)-\left(\frac{4}{-7}\right)\)
2. \(-\left(\frac{-14}{-3}\right)+\left(\frac{-14}{13}\right)\)
3. \(-\left(\frac{-12}{-7}\right)+\left(\frac{-11}{-12}\right)\)
4. \(-\left(\frac{12}{-5}\right)-\left(\frac{-9}{5}\right)\)
5. \(+\left(\frac{-14}{13}\right)-\left(\frac{8}{9}\right)\)
6. \(-\left(\frac{-3}{2}\right)-\left(\frac{-6}{5}\right)\)
7. \(+\left(\frac{15}{-11}\right)-\left(\frac{-2}{9}\right)\)
8. \(-\left(\frac{10}{7}\right)-\left(\frac{-11}{-14}\right)\)
9. \(-\left(\frac{15}{8}\right)-\left(\frac{5}{14}\right)\)
10. \(-\left(\frac{-15}{4}\right)-\left(\frac{6}{5}\right)\)
11. \(-\left(\frac{-2}{7}\right)+\left(\frac{-4}{11}\right)\)
12. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-4}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-3}{4}\right)-\left(\frac{4}{-7}\right)\\= \frac{3}{4}+\frac{4}{7}\\=\frac{21}{28}+\frac{16}{28}\\=\frac{21+16}{28}\\=\frac{37}{28}\)
2. \(-\left(\frac{-14}{-3}\right)+\left(\frac{-14}{13}\right)\\= \frac{-14}{3}-\frac{14}{13}\\=\frac{-182}{39}-\frac{42}{39}\\=\frac{-182-42}{39}\\=\frac{-224}{39}\)
3. \(-\left(\frac{-12}{-7}\right)+\left(\frac{-11}{-12}\right)\\= \frac{-12}{7}+\frac{11}{12}\\=\frac{-144}{84}+\frac{77}{84}\\=\frac{-144+77}{84}\\=\frac{-67}{84}\)
4. \(-\left(\frac{12}{-5}\right)-\left(\frac{-9}{5}\right)\\= \frac{12}{5}+\frac{9}{5}\\=\frac{12+9}{5}\\=\frac{21}{5}\)
5. \(+\left(\frac{-14}{13}\right)-\left(\frac{8}{9}\right)\\= \frac{-14}{13}-\frac{8}{9}\\=\frac{-126}{117}-\frac{104}{117}\\=\frac{-126-104}{117}\\=\frac{-230}{117}\)
6. \(-\left(\frac{-3}{2}\right)-\left(\frac{-6}{5}\right)\\= \frac{3}{2}+\frac{6}{5}\\=\frac{15}{10}+\frac{12}{10}\\=\frac{15+12}{10}\\=\frac{27}{10}\)
7. \(+\left(\frac{15}{-11}\right)-\left(\frac{-2}{9}\right)\\= \frac{-15}{11}+\frac{2}{9}\\=\frac{-135}{99}+\frac{22}{99}\\=\frac{-135+22}{99}\\=\frac{-113}{99}\)
8. \(-\left(\frac{10}{7}\right)-\left(\frac{-11}{-14}\right)\\= \frac{-10}{7}-\frac{11}{14}\\=\frac{-20}{14}-\frac{11}{14}\\=\frac{-20-11}{14}\\=\frac{-31}{14}\)
9. \(-\left(\frac{15}{8}\right)-\left(\frac{5}{14}\right)\\= \frac{-15}{8}-\frac{5}{14}\\=\frac{-105}{56}-\frac{20}{56}\\=\frac{-105-20}{56}\\=\frac{-125}{56}\)
10. \(-\left(\frac{-15}{4}\right)-\left(\frac{6}{5}\right)\\= \frac{15}{4}-\frac{6}{5}\\=\frac{75}{20}-\frac{24}{20}\\=\frac{75-24}{20}\\=\frac{51}{20}\)
11. \(-\left(\frac{-2}{7}\right)+\left(\frac{-4}{11}\right)\\= \frac{2}{7}-\frac{4}{11}\\=\frac{22}{77}-\frac{28}{77}\\=\frac{22-28}{77}\\=\frac{-6}{77}\)
12. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-4}{-3}\right)\\= \frac{-6}{11}-\frac{4}{3}\\=\frac{-18}{33}-\frac{44}{33}\\=\frac{-18-44}{33}\\=\frac{-62}{33}\)