Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{11}{8}\right)+\left(\frac{5}{3}\right)\)
2. \(+\left(\frac{8}{13}\right)-\left(\frac{-15}{8}\right)\)
3. \(-\left(\frac{-2}{-9}\right)-\left(\frac{-10}{-3}\right)\)
4. \(+\left(\frac{10}{7}\right)-\left(\frac{9}{-10}\right)\)
5. \(-\left(\frac{-6}{-13}\right)+\left(\frac{13}{4}\right)\)
6. \(-\left(\frac{-2}{-5}\right)+\left(\frac{-12}{-11}\right)\)
7. \(+\left(\frac{-14}{-9}\right)+\left(\frac{2}{-3}\right)\)
8. \(+\left(\frac{14}{9}\right)-\left(\frac{6}{-7}\right)\)
9. \(+\left(\frac{-9}{-13}\right)-\left(\frac{8}{3}\right)\)
10. \(-\left(\frac{-4}{-9}\right)-\left(\frac{-13}{6}\right)\)
11. \(+\left(\frac{5}{-11}\right)-\left(\frac{3}{-14}\right)\)
12. \(+\left(\frac{5}{9}\right)+\left(\frac{7}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{11}{8}\right)+\left(\frac{5}{3}\right)\\= \frac{-11}{8}+\frac{5}{3}\\=\frac{-33}{24}+\frac{40}{24}\\=\frac{-33+40}{24}\\=\frac{7}{24}\)
2. \(+\left(\frac{8}{13}\right)-\left(\frac{-15}{8}\right)\\= \frac{8}{13}+\frac{15}{8}\\=\frac{64}{104}+\frac{195}{104}\\=\frac{64+195}{104}\\=\frac{259}{104}\)
3. \(-\left(\frac{-2}{-9}\right)-\left(\frac{-10}{-3}\right)\\= \frac{-2}{9}-\frac{10}{3}\\=\frac{-2-10}{9}\\=\frac{-12}{9}\\=\frac{-4}{3}\)
4. \(+\left(\frac{10}{7}\right)-\left(\frac{9}{-10}\right)\\= \frac{10}{7}+\frac{9}{10}\\=\frac{100}{70}+\frac{63}{70}\\=\frac{100+63}{70}\\=\frac{163}{70}\)
5. \(-\left(\frac{-6}{-13}\right)+\left(\frac{13}{4}\right)\\= \frac{-6}{13}+\frac{13}{4}\\=\frac{-24}{52}+\frac{169}{52}\\=\frac{-24+169}{52}\\=\frac{145}{52}\)
6. \(-\left(\frac{-2}{-5}\right)+\left(\frac{-12}{-11}\right)\\= \frac{-2}{5}+\frac{12}{11}\\=\frac{-22}{55}+\frac{60}{55}\\=\frac{-22+60}{55}\\=\frac{38}{55}\)
7. \(+\left(\frac{-14}{-9}\right)+\left(\frac{2}{-3}\right)\\= \frac{14}{9}-\frac{2}{3}\\=\frac{14-2}{9}\\=\frac{12}{9}\\=\frac{4}{3}\)
8. \(+\left(\frac{14}{9}\right)-\left(\frac{6}{-7}\right)\\= \frac{14}{9}+\frac{6}{7}\\=\frac{98}{63}+\frac{54}{63}\\=\frac{98+54}{63}\\=\frac{152}{63}\)
9. \(+\left(\frac{-9}{-13}\right)-\left(\frac{8}{3}\right)\\= \frac{9}{13}-\frac{8}{3}\\=\frac{27}{39}-\frac{104}{39}\\=\frac{27-104}{39}\\=\frac{-77}{39}\)
10. \(-\left(\frac{-4}{-9}\right)-\left(\frac{-13}{6}\right)\\= \frac{-4}{9}+\frac{13}{6}\\=\frac{-8}{18}+\frac{39}{18}\\=\frac{-8+39}{18}\\=\frac{31}{18}\)
11. \(+\left(\frac{5}{-11}\right)-\left(\frac{3}{-14}\right)\\= \frac{-5}{11}+\frac{3}{14}\\=\frac{-70}{154}+\frac{33}{154}\\=\frac{-70+33}{154}\\=\frac{-37}{154}\)
12. \(+\left(\frac{5}{9}\right)+\left(\frac{7}{-13}\right)\\= \frac{5}{9}-\frac{7}{13}\\=\frac{65}{117}-\frac{63}{117}\\=\frac{65-63}{117}\\=\frac{2}{117}\)