Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{7}{3}\right)-\left(\frac{15}{8}\right)\)
2. \(-\left(\frac{-14}{-5}\right)-\left(\frac{15}{-11}\right)\)
3. \(+\left(\frac{-2}{-9}\right)+\left(\frac{2}{3}\right)\)
4. \(-\left(\frac{9}{2}\right)+\left(\frac{15}{13}\right)\)
5. \(+\left(\frac{-9}{8}\right)-\left(\frac{5}{6}\right)\)
6. \(-\left(\frac{-14}{-9}\right)+\left(\frac{-15}{-2}\right)\)
7. \(-\left(\frac{-10}{-7}\right)+\left(\frac{-13}{4}\right)\)
8. \(+\left(\frac{-7}{13}\right)+\left(\frac{15}{11}\right)\)
9. \(+\left(\frac{11}{8}\right)-\left(\frac{-14}{9}\right)\)
10. \(-\left(\frac{7}{4}\right)-\left(\frac{-10}{-9}\right)\)
11. \(+\left(\frac{12}{-7}\right)-\left(\frac{4}{11}\right)\)
12. \(+\left(\frac{-14}{-5}\right)+\left(\frac{11}{10}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{7}{3}\right)-\left(\frac{15}{8}\right)\\= \frac{-7}{3}-\frac{15}{8}\\=\frac{-56}{24}-\frac{45}{24}\\=\frac{-56-45}{24}\\=\frac{-101}{24}\)
2. \(-\left(\frac{-14}{-5}\right)-\left(\frac{15}{-11}\right)\\= \frac{-14}{5}+\frac{15}{11}\\=\frac{-154}{55}+\frac{75}{55}\\=\frac{-154+75}{55}\\=\frac{-79}{55}\)
3. \(+\left(\frac{-2}{-9}\right)+\left(\frac{2}{3}\right)\\= \frac{2}{9}+\frac{2}{3}\\=\frac{2+2}{9}\\=\frac{4}{9}\)
4. \(-\left(\frac{9}{2}\right)+\left(\frac{15}{13}\right)\\= \frac{-9}{2}+\frac{15}{13}\\=\frac{-117}{26}+\frac{30}{26}\\=\frac{-117+30}{26}\\=\frac{-87}{26}\)
5. \(+\left(\frac{-9}{8}\right)-\left(\frac{5}{6}\right)\\= \frac{-9}{8}-\frac{5}{6}\\=\frac{-27}{24}-\frac{20}{24}\\=\frac{-27-20}{24}\\=\frac{-47}{24}\)
6. \(-\left(\frac{-14}{-9}\right)+\left(\frac{-15}{-2}\right)\\= \frac{-14}{9}+\frac{15}{2}\\=\frac{-28}{18}+\frac{135}{18}\\=\frac{-28+135}{18}\\=\frac{107}{18}\)
7. \(-\left(\frac{-10}{-7}\right)+\left(\frac{-13}{4}\right)\\= \frac{-10}{7}-\frac{13}{4}\\=\frac{-40}{28}-\frac{91}{28}\\=\frac{-40-91}{28}\\=\frac{-131}{28}\)
8. \(+\left(\frac{-7}{13}\right)+\left(\frac{15}{11}\right)\\= \frac{-7}{13}+\frac{15}{11}\\=\frac{-77}{143}+\frac{195}{143}\\=\frac{-77+195}{143}\\=\frac{118}{143}\)
9. \(+\left(\frac{11}{8}\right)-\left(\frac{-14}{9}\right)\\= \frac{11}{8}+\frac{14}{9}\\=\frac{99}{72}+\frac{112}{72}\\=\frac{99+112}{72}\\=\frac{211}{72}\)
10. \(-\left(\frac{7}{4}\right)-\left(\frac{-10}{-9}\right)\\= \frac{-7}{4}-\frac{10}{9}\\=\frac{-63}{36}-\frac{40}{36}\\=\frac{-63-40}{36}\\=\frac{-103}{36}\)
11. \(+\left(\frac{12}{-7}\right)-\left(\frac{4}{11}\right)\\= \frac{-12}{7}-\frac{4}{11}\\=\frac{-132}{77}-\frac{28}{77}\\=\frac{-132-28}{77}\\=\frac{-160}{77}\)
12. \(+\left(\frac{-14}{-5}\right)+\left(\frac{11}{10}\right)\\= \frac{14}{5}+\frac{11}{10}\\=\frac{28}{10}+\frac{11}{10}\\=\frac{28+11}{10}\\=\frac{39}{10}\)