Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{3}{14}\right)-\left(\frac{5}{6}\right)\)
2. \(-\left(\frac{-11}{-3}\right)+\left(\frac{8}{9}\right)\)
3. \(+\left(\frac{-15}{-2}\right)-\left(\frac{12}{-11}\right)\)
4. \(-\left(\frac{5}{-2}\right)+\left(\frac{10}{11}\right)\)
5. \(+\left(\frac{2}{-13}\right)+\left(\frac{3}{2}\right)\)
6. \(-\left(\frac{9}{-8}\right)+\left(\frac{6}{-11}\right)\)
7. \(-\left(\frac{-9}{7}\right)-\left(\frac{7}{11}\right)\)
8. \(-\left(\frac{8}{3}\right)-\left(\frac{-14}{11}\right)\)
9. \(-\left(\frac{3}{-7}\right)+\left(\frac{3}{-10}\right)\)
10. \(+\left(\frac{5}{13}\right)+\left(\frac{-11}{-6}\right)\)
11. \(-\left(\frac{-14}{-13}\right)-\left(\frac{-5}{4}\right)\)
12. \(-\left(\frac{-3}{13}\right)-\left(\frac{-12}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{3}{14}\right)-\left(\frac{5}{6}\right)\\= \frac{-3}{14}-\frac{5}{6}\\=\frac{-9}{42}-\frac{35}{42}\\=\frac{-9-35}{42}\\=\frac{-44}{42}\\=\frac{-22}{21}\)
2. \(-\left(\frac{-11}{-3}\right)+\left(\frac{8}{9}\right)\\= \frac{-11}{3}+\frac{8}{9}\\=\frac{-33}{9}+\frac{8}{9}\\=\frac{-33+8}{9}\\=\frac{-25}{9}\)
3. \(+\left(\frac{-15}{-2}\right)-\left(\frac{12}{-11}\right)\\= \frac{15}{2}+\frac{12}{11}\\=\frac{165}{22}+\frac{24}{22}\\=\frac{165+24}{22}\\=\frac{189}{22}\)
4. \(-\left(\frac{5}{-2}\right)+\left(\frac{10}{11}\right)\\= \frac{5}{2}+\frac{10}{11}\\=\frac{55}{22}+\frac{20}{22}\\=\frac{55+20}{22}\\=\frac{75}{22}\)
5. \(+\left(\frac{2}{-13}\right)+\left(\frac{3}{2}\right)\\= \frac{-2}{13}+\frac{3}{2}\\=\frac{-4}{26}+\frac{39}{26}\\=\frac{-4+39}{26}\\=\frac{35}{26}\)
6. \(-\left(\frac{9}{-8}\right)+\left(\frac{6}{-11}\right)\\= \frac{9}{8}-\frac{6}{11}\\=\frac{99}{88}-\frac{48}{88}\\=\frac{99-48}{88}\\=\frac{51}{88}\)
7. \(-\left(\frac{-9}{7}\right)-\left(\frac{7}{11}\right)\\= \frac{9}{7}-\frac{7}{11}\\=\frac{99}{77}-\frac{49}{77}\\=\frac{99-49}{77}\\=\frac{50}{77}\)
8. \(-\left(\frac{8}{3}\right)-\left(\frac{-14}{11}\right)\\= \frac{-8}{3}+\frac{14}{11}\\=\frac{-88}{33}+\frac{42}{33}\\=\frac{-88+42}{33}\\=\frac{-46}{33}\)
9. \(-\left(\frac{3}{-7}\right)+\left(\frac{3}{-10}\right)\\= \frac{3}{7}-\frac{3}{10}\\=\frac{30}{70}-\frac{21}{70}\\=\frac{30-21}{70}\\=\frac{9}{70}\)
10. \(+\left(\frac{5}{13}\right)+\left(\frac{-11}{-6}\right)\\= \frac{5}{13}+\frac{11}{6}\\=\frac{30}{78}+\frac{143}{78}\\=\frac{30+143}{78}\\=\frac{173}{78}\)
11. \(-\left(\frac{-14}{-13}\right)-\left(\frac{-5}{4}\right)\\= \frac{-14}{13}+\frac{5}{4}\\=\frac{-56}{52}+\frac{65}{52}\\=\frac{-56+65}{52}\\=\frac{9}{52}\)
12. \(-\left(\frac{-3}{13}\right)-\left(\frac{-12}{-7}\right)\\= \frac{3}{13}-\frac{12}{7}\\=\frac{21}{91}-\frac{156}{91}\\=\frac{21-156}{91}\\=\frac{-135}{91}\)