Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{9}{4}\right)-\left(\frac{-7}{-5}\right)\)
2. \(-\left(\frac{11}{9}\right)+\left(\frac{11}{13}\right)\)
3. \(-\left(\frac{11}{14}\right)-\left(\frac{-3}{-2}\right)\)
4. \(+\left(\frac{-9}{11}\right)-\left(\frac{-6}{-13}\right)\)
5. \(-\left(\frac{10}{-11}\right)-\left(\frac{-5}{12}\right)\)
6. \(-\left(\frac{9}{-4}\right)+\left(\frac{15}{-7}\right)\)
7. \(+\left(\frac{11}{14}\right)-\left(\frac{-6}{7}\right)\)
8. \(+\left(\frac{15}{-2}\right)+\left(\frac{-10}{7}\right)\)
9. \(-\left(\frac{3}{13}\right)+\left(\frac{-2}{3}\right)\)
10. \(+\left(\frac{-3}{-10}\right)+\left(\frac{11}{10}\right)\)
11. \(-\left(\frac{-10}{-7}\right)-\left(\frac{-13}{12}\right)\)
12. \(-\left(\frac{-4}{-13}\right)-\left(\frac{10}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{9}{4}\right)-\left(\frac{-7}{-5}\right)\\= \frac{-9}{4}-\frac{7}{5}\\=\frac{-45}{20}-\frac{28}{20}\\=\frac{-45-28}{20}\\=\frac{-73}{20}\)
2. \(-\left(\frac{11}{9}\right)+\left(\frac{11}{13}\right)\\= \frac{-11}{9}+\frac{11}{13}\\=\frac{-143}{117}+\frac{99}{117}\\=\frac{-143+99}{117}\\=\frac{-44}{117}\)
3. \(-\left(\frac{11}{14}\right)-\left(\frac{-3}{-2}\right)\\= \frac{-11}{14}-\frac{3}{2}\\=\frac{-11-3}{14}\\=\frac{-14}{14}\\=\frac{-1}{1}\)
4. \(+\left(\frac{-9}{11}\right)-\left(\frac{-6}{-13}\right)\\= \frac{-9}{11}-\frac{6}{13}\\=\frac{-117}{143}-\frac{66}{143}\\=\frac{-117-66}{143}\\=\frac{-183}{143}\)
5. \(-\left(\frac{10}{-11}\right)-\left(\frac{-5}{12}\right)\\= \frac{10}{11}+\frac{5}{12}\\=\frac{120}{132}+\frac{55}{132}\\=\frac{120+55}{132}\\=\frac{175}{132}\)
6. \(-\left(\frac{9}{-4}\right)+\left(\frac{15}{-7}\right)\\= \frac{9}{4}-\frac{15}{7}\\=\frac{63}{28}-\frac{60}{28}\\=\frac{63-60}{28}\\=\frac{3}{28}\)
7. \(+\left(\frac{11}{14}\right)-\left(\frac{-6}{7}\right)\\= \frac{11}{14}+\frac{6}{7}\\=\frac{11+6}{14}\\=\frac{17}{14}\)
8. \(+\left(\frac{15}{-2}\right)+\left(\frac{-10}{7}\right)\\= \frac{-15}{2}-\frac{10}{7}\\=\frac{-105}{14}-\frac{20}{14}\\=\frac{-105-20}{14}\\=\frac{-125}{14}\)
9. \(-\left(\frac{3}{13}\right)+\left(\frac{-2}{3}\right)\\= \frac{-3}{13}-\frac{2}{3}\\=\frac{-9}{39}-\frac{26}{39}\\=\frac{-9-26}{39}\\=\frac{-35}{39}\)
10. \(+\left(\frac{-3}{-10}\right)+\left(\frac{11}{10}\right)\\= \frac{3}{10}+\frac{11}{10}\\=\frac{3+11}{10}\\=\frac{14}{10}\\=\frac{7}{5}\)
11. \(-\left(\frac{-10}{-7}\right)-\left(\frac{-13}{12}\right)\\= \frac{-10}{7}+\frac{13}{12}\\=\frac{-120}{84}+\frac{91}{84}\\=\frac{-120+91}{84}\\=\frac{-29}{84}\)
12. \(-\left(\frac{-4}{-13}\right)-\left(\frac{10}{-3}\right)\\= \frac{-4}{13}+\frac{10}{3}\\=\frac{-12}{39}+\frac{130}{39}\\=\frac{-12+130}{39}\\=\frac{118}{39}\)