Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{9}{13}\right)-\left(\frac{10}{-7}\right)\)
2. \(-\left(\frac{-13}{14}\right)-\left(\frac{6}{-5}\right)\)
3. \(-\left(\frac{15}{-8}\right)-\left(\frac{-12}{11}\right)\)
4. \(+\left(\frac{11}{-4}\right)+\left(\frac{-15}{13}\right)\)
5. \(+\left(\frac{15}{4}\right)+\left(\frac{2}{-7}\right)\)
6. \(+\left(\frac{-4}{-3}\right)+\left(\frac{5}{-6}\right)\)
7. \(-\left(\frac{-13}{-2}\right)-\left(\frac{-12}{-11}\right)\)
8. \(-\left(\frac{-15}{14}\right)-\left(\frac{-10}{3}\right)\)
9. \(-\left(\frac{-2}{-3}\right)+\left(\frac{6}{5}\right)\)
10. \(-\left(\frac{-2}{-3}\right)-\left(\frac{12}{-11}\right)\)
11. \(+\left(\frac{7}{-5}\right)-\left(\frac{-2}{9}\right)\)
12. \(+\left(\frac{-14}{-5}\right)+\left(\frac{-2}{5}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{9}{13}\right)-\left(\frac{10}{-7}\right)\\= \frac{-9}{13}+\frac{10}{7}\\=\frac{-63}{91}+\frac{130}{91}\\=\frac{-63+130}{91}\\=\frac{67}{91}\)
2. \(-\left(\frac{-13}{14}\right)-\left(\frac{6}{-5}\right)\\= \frac{13}{14}+\frac{6}{5}\\=\frac{65}{70}+\frac{84}{70}\\=\frac{65+84}{70}\\=\frac{149}{70}\)
3. \(-\left(\frac{15}{-8}\right)-\left(\frac{-12}{11}\right)\\= \frac{15}{8}+\frac{12}{11}\\=\frac{165}{88}+\frac{96}{88}\\=\frac{165+96}{88}\\=\frac{261}{88}\)
4. \(+\left(\frac{11}{-4}\right)+\left(\frac{-15}{13}\right)\\= \frac{-11}{4}-\frac{15}{13}\\=\frac{-143}{52}-\frac{60}{52}\\=\frac{-143-60}{52}\\=\frac{-203}{52}\)
5. \(+\left(\frac{15}{4}\right)+\left(\frac{2}{-7}\right)\\= \frac{15}{4}-\frac{2}{7}\\=\frac{105}{28}-\frac{8}{28}\\=\frac{105-8}{28}\\=\frac{97}{28}\)
6. \(+\left(\frac{-4}{-3}\right)+\left(\frac{5}{-6}\right)\\= \frac{4}{3}-\frac{5}{6}\\=\frac{8}{6}-\frac{5}{6}\\=\frac{8-5}{6}\\=\frac{3}{6}\\=\frac{1}{2}\)
7. \(-\left(\frac{-13}{-2}\right)-\left(\frac{-12}{-11}\right)\\= \frac{-13}{2}-\frac{12}{11}\\=\frac{-143}{22}-\frac{24}{22}\\=\frac{-143-24}{22}\\=\frac{-167}{22}\)
8. \(-\left(\frac{-15}{14}\right)-\left(\frac{-10}{3}\right)\\= \frac{15}{14}+\frac{10}{3}\\=\frac{45}{42}+\frac{140}{42}\\=\frac{45+140}{42}\\=\frac{185}{42}\)
9. \(-\left(\frac{-2}{-3}\right)+\left(\frac{6}{5}\right)\\= \frac{-2}{3}+\frac{6}{5}\\=\frac{-10}{15}+\frac{18}{15}\\=\frac{-10+18}{15}\\=\frac{8}{15}\)
10. \(-\left(\frac{-2}{-3}\right)-\left(\frac{12}{-11}\right)\\= \frac{-2}{3}+\frac{12}{11}\\=\frac{-22}{33}+\frac{36}{33}\\=\frac{-22+36}{33}\\=\frac{14}{33}\)
11. \(+\left(\frac{7}{-5}\right)-\left(\frac{-2}{9}\right)\\= \frac{-7}{5}+\frac{2}{9}\\=\frac{-63}{45}+\frac{10}{45}\\=\frac{-63+10}{45}\\=\frac{-53}{45}\)
12. \(+\left(\frac{-14}{-5}\right)+\left(\frac{-2}{5}\right)\\= \frac{14}{5}-\frac{2}{5}\\=\frac{14-2}{5}\\=\frac{12}{5}\)