Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{3}{-8}\right)+\left(\frac{14}{13}\right)\)
2. \(-\left(\frac{9}{2}\right)+\left(\frac{-15}{-7}\right)\)
3. \(-\left(\frac{14}{3}\right)-\left(\frac{-4}{-7}\right)\)
4. \(-\left(\frac{-4}{-13}\right)-\left(\frac{3}{-11}\right)\)
5. \(+\left(\frac{-14}{9}\right)+\left(\frac{-4}{-11}\right)\)
6. \(-\left(\frac{10}{9}\right)+\left(\frac{-9}{-14}\right)\)
7. \(+\left(\frac{-8}{-3}\right)-\left(\frac{14}{-11}\right)\)
8. \(+\left(\frac{-12}{-7}\right)-\left(\frac{2}{-13}\right)\)
9. \(-\left(\frac{13}{-8}\right)-\left(\frac{-7}{13}\right)\)
10. \(+\left(\frac{-7}{-11}\right)+\left(\frac{8}{13}\right)\)
11. \(+\left(\frac{-6}{-13}\right)-\left(\frac{2}{-5}\right)\)
12. \(+\left(\frac{-7}{-2}\right)+\left(\frac{8}{13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{3}{-8}\right)+\left(\frac{14}{13}\right)\\= \frac{3}{8}+\frac{14}{13}\\=\frac{39}{104}+\frac{112}{104}\\=\frac{39+112}{104}\\=\frac{151}{104}\)
2. \(-\left(\frac{9}{2}\right)+\left(\frac{-15}{-7}\right)\\= \frac{-9}{2}+\frac{15}{7}\\=\frac{-63}{14}+\frac{30}{14}\\=\frac{-63+30}{14}\\=\frac{-33}{14}\)
3. \(-\left(\frac{14}{3}\right)-\left(\frac{-4}{-7}\right)\\= \frac{-14}{3}-\frac{4}{7}\\=\frac{-98}{21}-\frac{12}{21}\\=\frac{-98-12}{21}\\=\frac{-110}{21}\)
4. \(-\left(\frac{-4}{-13}\right)-\left(\frac{3}{-11}\right)\\= \frac{-4}{13}+\frac{3}{11}\\=\frac{-44}{143}+\frac{39}{143}\\=\frac{-44+39}{143}\\=\frac{-5}{143}\)
5. \(+\left(\frac{-14}{9}\right)+\left(\frac{-4}{-11}\right)\\= \frac{-14}{9}+\frac{4}{11}\\=\frac{-154}{99}+\frac{36}{99}\\=\frac{-154+36}{99}\\=\frac{-118}{99}\)
6. \(-\left(\frac{10}{9}\right)+\left(\frac{-9}{-14}\right)\\= \frac{-10}{9}+\frac{9}{14}\\=\frac{-140}{126}+\frac{81}{126}\\=\frac{-140+81}{126}\\=\frac{-59}{126}\)
7. \(+\left(\frac{-8}{-3}\right)-\left(\frac{14}{-11}\right)\\= \frac{8}{3}+\frac{14}{11}\\=\frac{88}{33}+\frac{42}{33}\\=\frac{88+42}{33}\\=\frac{130}{33}\)
8. \(+\left(\frac{-12}{-7}\right)-\left(\frac{2}{-13}\right)\\= \frac{12}{7}+\frac{2}{13}\\=\frac{156}{91}+\frac{14}{91}\\=\frac{156+14}{91}\\=\frac{170}{91}\)
9. \(-\left(\frac{13}{-8}\right)-\left(\frac{-7}{13}\right)\\= \frac{13}{8}+\frac{7}{13}\\=\frac{169}{104}+\frac{56}{104}\\=\frac{169+56}{104}\\=\frac{225}{104}\)
10. \(+\left(\frac{-7}{-11}\right)+\left(\frac{8}{13}\right)\\= \frac{7}{11}+\frac{8}{13}\\=\frac{91}{143}+\frac{88}{143}\\=\frac{91+88}{143}\\=\frac{179}{143}\)
11. \(+\left(\frac{-6}{-13}\right)-\left(\frac{2}{-5}\right)\\= \frac{6}{13}+\frac{2}{5}\\=\frac{30}{65}+\frac{26}{65}\\=\frac{30+26}{65}\\=\frac{56}{65}\)
12. \(+\left(\frac{-7}{-2}\right)+\left(\frac{8}{13}\right)\\= \frac{7}{2}+\frac{8}{13}\\=\frac{91}{26}+\frac{16}{26}\\=\frac{91+16}{26}\\=\frac{107}{26}\)