Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{5}{-11}\right)-\left(\frac{-12}{-5}\right)\)
2. \(+\left(\frac{-3}{2}\right)-\left(\frac{6}{-5}\right)\)
3. \(+\left(\frac{-3}{10}\right)-\left(\frac{12}{11}\right)\)
4. \(-\left(\frac{-10}{-3}\right)+\left(\frac{-4}{5}\right)\)
5. \(-\left(\frac{-13}{-8}\right)-\left(\frac{-9}{-7}\right)\)
6. \(+\left(\frac{-13}{-11}\right)+\left(\frac{-2}{3}\right)\)
7. \(-\left(\frac{5}{-9}\right)-\left(\frac{-5}{6}\right)\)
8. \(+\left(\frac{14}{-3}\right)+\left(\frac{6}{-5}\right)\)
9. \(+\left(\frac{-2}{5}\right)-\left(\frac{-5}{14}\right)\)
10. \(+\left(\frac{-6}{5}\right)+\left(\frac{15}{14}\right)\)
11. \(+\left(\frac{12}{5}\right)+\left(\frac{3}{-8}\right)\)
12. \(-\left(\frac{-6}{-13}\right)+\left(\frac{10}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{5}{-11}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-5}{11}-\frac{12}{5}\\=\frac{-25}{55}-\frac{132}{55}\\=\frac{-25-132}{55}\\=\frac{-157}{55}\)
2. \(+\left(\frac{-3}{2}\right)-\left(\frac{6}{-5}\right)\\= \frac{-3}{2}+\frac{6}{5}\\=\frac{-15}{10}+\frac{12}{10}\\=\frac{-15+12}{10}\\=\frac{-3}{10}\)
3. \(+\left(\frac{-3}{10}\right)-\left(\frac{12}{11}\right)\\= \frac{-3}{10}-\frac{12}{11}\\=\frac{-33}{110}-\frac{120}{110}\\=\frac{-33-120}{110}\\=\frac{-153}{110}\)
4. \(-\left(\frac{-10}{-3}\right)+\left(\frac{-4}{5}\right)\\= \frac{-10}{3}-\frac{4}{5}\\=\frac{-50}{15}-\frac{12}{15}\\=\frac{-50-12}{15}\\=\frac{-62}{15}\)
5. \(-\left(\frac{-13}{-8}\right)-\left(\frac{-9}{-7}\right)\\= \frac{-13}{8}-\frac{9}{7}\\=\frac{-91}{56}-\frac{72}{56}\\=\frac{-91-72}{56}\\=\frac{-163}{56}\)
6. \(+\left(\frac{-13}{-11}\right)+\left(\frac{-2}{3}\right)\\= \frac{13}{11}-\frac{2}{3}\\=\frac{39}{33}-\frac{22}{33}\\=\frac{39-22}{33}\\=\frac{17}{33}\)
7. \(-\left(\frac{5}{-9}\right)-\left(\frac{-5}{6}\right)\\= \frac{5}{9}+\frac{5}{6}\\=\frac{10}{18}+\frac{15}{18}\\=\frac{10+15}{18}\\=\frac{25}{18}\)
8. \(+\left(\frac{14}{-3}\right)+\left(\frac{6}{-5}\right)\\= \frac{-14}{3}-\frac{6}{5}\\=\frac{-70}{15}-\frac{18}{15}\\=\frac{-70-18}{15}\\=\frac{-88}{15}\)
9. \(+\left(\frac{-2}{5}\right)-\left(\frac{-5}{14}\right)\\= \frac{-2}{5}+\frac{5}{14}\\=\frac{-28}{70}+\frac{25}{70}\\=\frac{-28+25}{70}\\=\frac{-3}{70}\)
10. \(+\left(\frac{-6}{5}\right)+\left(\frac{15}{14}\right)\\= \frac{-6}{5}+\frac{15}{14}\\=\frac{-84}{70}+\frac{75}{70}\\=\frac{-84+75}{70}\\=\frac{-9}{70}\)
11. \(+\left(\frac{12}{5}\right)+\left(\frac{3}{-8}\right)\\= \frac{12}{5}-\frac{3}{8}\\=\frac{96}{40}-\frac{15}{40}\\=\frac{96-15}{40}\\=\frac{81}{40}\)
12. \(-\left(\frac{-6}{-13}\right)+\left(\frac{10}{-7}\right)\\= \frac{-6}{13}-\frac{10}{7}\\=\frac{-42}{91}-\frac{130}{91}\\=\frac{-42-130}{91}\\=\frac{-172}{91}\)