Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{3}{-13}\right)+\left(\frac{3}{13}\right)\)
2. \(-\left(\frac{-10}{3}\right)+\left(\frac{-5}{-11}\right)\)
3. \(+\left(\frac{-11}{2}\right)-\left(\frac{-8}{3}\right)\)
4. \(-\left(\frac{15}{11}\right)-\left(\frac{-7}{-9}\right)\)
5. \(-\left(\frac{2}{3}\right)-\left(\frac{5}{-14}\right)\)
6. \(+\left(\frac{-6}{11}\right)+\left(\frac{10}{7}\right)\)
7. \(-\left(\frac{-8}{-3}\right)+\left(\frac{-7}{-6}\right)\)
8. \(-\left(\frac{5}{-12}\right)-\left(\frac{9}{8}\right)\)
9. \(-\left(\frac{8}{7}\right)-\left(\frac{-12}{13}\right)\)
10. \(-\left(\frac{-6}{5}\right)-\left(\frac{-14}{9}\right)\)
11. \(-\left(\frac{-14}{11}\right)+\left(\frac{4}{3}\right)\)
12. \(+\left(\frac{4}{11}\right)-\left(\frac{-7}{-4}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{3}{-13}\right)+\left(\frac{3}{13}\right)\\= \frac{3}{13}+\frac{3}{13}\\=\frac{3+3}{13}\\=\frac{6}{13}\)
2. \(-\left(\frac{-10}{3}\right)+\left(\frac{-5}{-11}\right)\\= \frac{10}{3}+\frac{5}{11}\\=\frac{110}{33}+\frac{15}{33}\\=\frac{110+15}{33}\\=\frac{125}{33}\)
3. \(+\left(\frac{-11}{2}\right)-\left(\frac{-8}{3}\right)\\= \frac{-11}{2}+\frac{8}{3}\\=\frac{-33}{6}+\frac{16}{6}\\=\frac{-33+16}{6}\\=\frac{-17}{6}\)
4. \(-\left(\frac{15}{11}\right)-\left(\frac{-7}{-9}\right)\\= \frac{-15}{11}-\frac{7}{9}\\=\frac{-135}{99}-\frac{77}{99}\\=\frac{-135-77}{99}\\=\frac{-212}{99}\)
5. \(-\left(\frac{2}{3}\right)-\left(\frac{5}{-14}\right)\\= \frac{-2}{3}+\frac{5}{14}\\=\frac{-28}{42}+\frac{15}{42}\\=\frac{-28+15}{42}\\=\frac{-13}{42}\)
6. \(+\left(\frac{-6}{11}\right)+\left(\frac{10}{7}\right)\\= \frac{-6}{11}+\frac{10}{7}\\=\frac{-42}{77}+\frac{110}{77}\\=\frac{-42+110}{77}\\=\frac{68}{77}\)
7. \(-\left(\frac{-8}{-3}\right)+\left(\frac{-7}{-6}\right)\\= \frac{-8}{3}+\frac{7}{6}\\=\frac{-16}{6}+\frac{7}{6}\\=\frac{-16+7}{6}\\=\frac{-9}{6}\\=\frac{-3}{2}\)
8. \(-\left(\frac{5}{-12}\right)-\left(\frac{9}{8}\right)\\= \frac{5}{12}-\frac{9}{8}\\=\frac{10}{24}-\frac{27}{24}\\=\frac{10-27}{24}\\=\frac{-17}{24}\)
9. \(-\left(\frac{8}{7}\right)-\left(\frac{-12}{13}\right)\\= \frac{-8}{7}+\frac{12}{13}\\=\frac{-104}{91}+\frac{84}{91}\\=\frac{-104+84}{91}\\=\frac{-20}{91}\)
10. \(-\left(\frac{-6}{5}\right)-\left(\frac{-14}{9}\right)\\= \frac{6}{5}+\frac{14}{9}\\=\frac{54}{45}+\frac{70}{45}\\=\frac{54+70}{45}\\=\frac{124}{45}\)
11. \(-\left(\frac{-14}{11}\right)+\left(\frac{4}{3}\right)\\= \frac{14}{11}+\frac{4}{3}\\=\frac{42}{33}+\frac{44}{33}\\=\frac{42+44}{33}\\=\frac{86}{33}\)
12. \(+\left(\frac{4}{11}\right)-\left(\frac{-7}{-4}\right)\\= \frac{4}{11}-\frac{7}{4}\\=\frac{16}{44}-\frac{77}{44}\\=\frac{16-77}{44}\\=\frac{-61}{44}\)