Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-2}{13}\right)+\left(\frac{8}{-11}\right)\)
2. \(-\left(\frac{-5}{-7}\right)+\left(\frac{-7}{-9}\right)\)
3. \(+\left(\frac{-8}{-13}\right)+\left(\frac{-5}{8}\right)\)
4. \(-\left(\frac{7}{12}\right)+\left(\frac{-9}{-7}\right)\)
5. \(+\left(\frac{2}{3}\right)-\left(\frac{-7}{-12}\right)\)
6. \(-\left(\frac{-15}{-11}\right)+\left(\frac{7}{-5}\right)\)
7. \(-\left(\frac{-9}{14}\right)+\left(\frac{-15}{-13}\right)\)
8. \(+\left(\frac{2}{3}\right)-\left(\frac{8}{-13}\right)\)
9. \(+\left(\frac{5}{-6}\right)-\left(\frac{-7}{5}\right)\)
10. \(-\left(\frac{-10}{-11}\right)-\left(\frac{-15}{-13}\right)\)
11. \(-\left(\frac{-6}{-5}\right)-\left(\frac{-14}{-9}\right)\)
12. \(+\left(\frac{-11}{-12}\right)+\left(\frac{-14}{3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-2}{13}\right)+\left(\frac{8}{-11}\right)\\= \frac{-2}{13}-\frac{8}{11}\\=\frac{-22}{143}-\frac{104}{143}\\=\frac{-22-104}{143}\\=\frac{-126}{143}\)
2. \(-\left(\frac{-5}{-7}\right)+\left(\frac{-7}{-9}\right)\\= \frac{-5}{7}+\frac{7}{9}\\=\frac{-45}{63}+\frac{49}{63}\\=\frac{-45+49}{63}\\=\frac{4}{63}\)
3. \(+\left(\frac{-8}{-13}\right)+\left(\frac{-5}{8}\right)\\= \frac{8}{13}-\frac{5}{8}\\=\frac{64}{104}-\frac{65}{104}\\=\frac{64-65}{104}\\=\frac{-1}{104}\)
4. \(-\left(\frac{7}{12}\right)+\left(\frac{-9}{-7}\right)\\= \frac{-7}{12}+\frac{9}{7}\\=\frac{-49}{84}+\frac{108}{84}\\=\frac{-49+108}{84}\\=\frac{59}{84}\)
5. \(+\left(\frac{2}{3}\right)-\left(\frac{-7}{-12}\right)\\= \frac{2}{3}-\frac{7}{12}\\=\frac{8}{12}-\frac{7}{12}\\=\frac{8-7}{12}\\=\frac{1}{12}\)
6. \(-\left(\frac{-15}{-11}\right)+\left(\frac{7}{-5}\right)\\= \frac{-15}{11}-\frac{7}{5}\\=\frac{-75}{55}-\frac{77}{55}\\=\frac{-75-77}{55}\\=\frac{-152}{55}\)
7. \(-\left(\frac{-9}{14}\right)+\left(\frac{-15}{-13}\right)\\= \frac{9}{14}+\frac{15}{13}\\=\frac{117}{182}+\frac{210}{182}\\=\frac{117+210}{182}\\=\frac{327}{182}\)
8. \(+\left(\frac{2}{3}\right)-\left(\frac{8}{-13}\right)\\= \frac{2}{3}+\frac{8}{13}\\=\frac{26}{39}+\frac{24}{39}\\=\frac{26+24}{39}\\=\frac{50}{39}\)
9. \(+\left(\frac{5}{-6}\right)-\left(\frac{-7}{5}\right)\\= \frac{-5}{6}+\frac{7}{5}\\=\frac{-25}{30}+\frac{42}{30}\\=\frac{-25+42}{30}\\=\frac{17}{30}\)
10. \(-\left(\frac{-10}{-11}\right)-\left(\frac{-15}{-13}\right)\\= \frac{-10}{11}-\frac{15}{13}\\=\frac{-130}{143}-\frac{165}{143}\\=\frac{-130-165}{143}\\=\frac{-295}{143}\)
11. \(-\left(\frac{-6}{-5}\right)-\left(\frac{-14}{-9}\right)\\= \frac{-6}{5}-\frac{14}{9}\\=\frac{-54}{45}-\frac{70}{45}\\=\frac{-54-70}{45}\\=\frac{-124}{45}\)
12. \(+\left(\frac{-11}{-12}\right)+\left(\frac{-14}{3}\right)\\= \frac{11}{12}-\frac{14}{3}\\=\frac{11-14}{12}\\=\frac{-3}{12}\\=\frac{-1}{4}\)