Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-10}{-3}\right)+\left(\frac{-10}{7}\right)\)
2. \(-\left(\frac{-3}{-2}\right)+\left(\frac{10}{3}\right)\)
3. \(+\left(\frac{5}{4}\right)+\left(\frac{7}{3}\right)\)
4. \(+\left(\frac{-7}{-11}\right)-\left(\frac{7}{8}\right)\)
5. \(+\left(\frac{-15}{2}\right)-\left(\frac{-12}{-5}\right)\)
6. \(-\left(\frac{-3}{4}\right)+\left(\frac{2}{-5}\right)\)
7. \(+\left(\frac{5}{6}\right)+\left(\frac{-6}{-5}\right)\)
8. \(+\left(\frac{-10}{13}\right)+\left(\frac{5}{12}\right)\)
9. \(-\left(\frac{5}{-8}\right)-\left(\frac{-5}{-8}\right)\)
10. \(-\left(\frac{11}{5}\right)-\left(\frac{2}{3}\right)\)
11. \(-\left(\frac{13}{4}\right)-\left(\frac{-2}{3}\right)\)
12. \(+\left(\frac{-7}{-2}\right)+\left(\frac{13}{2}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-10}{-3}\right)+\left(\frac{-10}{7}\right)\\= \frac{10}{3}-\frac{10}{7}\\=\frac{70}{21}-\frac{30}{21}\\=\frac{70-30}{21}\\=\frac{40}{21}\)
2. \(-\left(\frac{-3}{-2}\right)+\left(\frac{10}{3}\right)\\= \frac{-3}{2}+\frac{10}{3}\\=\frac{-9}{6}+\frac{20}{6}\\=\frac{-9+20}{6}\\=\frac{11}{6}\)
3. \(+\left(\frac{5}{4}\right)+\left(\frac{7}{3}\right)\\= \frac{5}{4}+\frac{7}{3}\\=\frac{15}{12}+\frac{28}{12}\\=\frac{15+28}{12}\\=\frac{43}{12}\)
4. \(+\left(\frac{-7}{-11}\right)-\left(\frac{7}{8}\right)\\= \frac{7}{11}-\frac{7}{8}\\=\frac{56}{88}-\frac{77}{88}\\=\frac{56-77}{88}\\=\frac{-21}{88}\)
5. \(+\left(\frac{-15}{2}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-15}{2}-\frac{12}{5}\\=\frac{-75}{10}-\frac{24}{10}\\=\frac{-75-24}{10}\\=\frac{-99}{10}\)
6. \(-\left(\frac{-3}{4}\right)+\left(\frac{2}{-5}\right)\\= \frac{3}{4}-\frac{2}{5}\\=\frac{15}{20}-\frac{8}{20}\\=\frac{15-8}{20}\\=\frac{7}{20}\)
7. \(+\left(\frac{5}{6}\right)+\left(\frac{-6}{-5}\right)\\= \frac{5}{6}+\frac{6}{5}\\=\frac{25}{30}+\frac{36}{30}\\=\frac{25+36}{30}\\=\frac{61}{30}\)
8. \(+\left(\frac{-10}{13}\right)+\left(\frac{5}{12}\right)\\= \frac{-10}{13}+\frac{5}{12}\\=\frac{-120}{156}+\frac{65}{156}\\=\frac{-120+65}{156}\\=\frac{-55}{156}\)
9. \(-\left(\frac{5}{-8}\right)-\left(\frac{-5}{-8}\right)\\= \frac{5}{8}-\frac{5}{8}\\=\frac{5-5}{8}\\=\frac{0}{8}\\=\frac{0}{1}\)
10. \(-\left(\frac{11}{5}\right)-\left(\frac{2}{3}\right)\\= \frac{-11}{5}-\frac{2}{3}\\=\frac{-33}{15}-\frac{10}{15}\\=\frac{-33-10}{15}\\=\frac{-43}{15}\)
11. \(-\left(\frac{13}{4}\right)-\left(\frac{-2}{3}\right)\\= \frac{-13}{4}+\frac{2}{3}\\=\frac{-39}{12}+\frac{8}{12}\\=\frac{-39+8}{12}\\=\frac{-31}{12}\)
12. \(+\left(\frac{-7}{-2}\right)+\left(\frac{13}{2}\right)\\= \frac{7}{2}+\frac{13}{2}\\=\frac{7+13}{2}\\=\frac{20}{2}\\=\frac{10}{1}\)