Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-12}{-5}\right)+\left(\frac{4}{13}\right)\)
2. \(+\left(\frac{14}{3}\right)-\left(\frac{-9}{4}\right)\)
3. \(+\left(\frac{3}{-10}\right)-\left(\frac{-11}{12}\right)\)
4. \(+\left(\frac{-12}{13}\right)-\left(\frac{-9}{-13}\right)\)
5. \(+\left(\frac{6}{13}\right)-\left(\frac{-11}{-2}\right)\)
6. \(+\left(\frac{8}{-5}\right)+\left(\frac{-6}{13}\right)\)
7. \(-\left(\frac{15}{-13}\right)+\left(\frac{-10}{7}\right)\)
8. \(-\left(\frac{-5}{2}\right)+\left(\frac{12}{-5}\right)\)
9. \(-\left(\frac{12}{11}\right)-\left(\frac{9}{13}\right)\)
10. \(+\left(\frac{10}{9}\right)-\left(\frac{2}{-7}\right)\)
11. \(+\left(\frac{2}{11}\right)-\left(\frac{-3}{-2}\right)\)
12. \(-\left(\frac{12}{-13}\right)-\left(\frac{14}{3}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-12}{-5}\right)+\left(\frac{4}{13}\right)\\= \frac{12}{5}+\frac{4}{13}\\=\frac{156}{65}+\frac{20}{65}\\=\frac{156+20}{65}\\=\frac{176}{65}\)
2. \(+\left(\frac{14}{3}\right)-\left(\frac{-9}{4}\right)\\= \frac{14}{3}+\frac{9}{4}\\=\frac{56}{12}+\frac{27}{12}\\=\frac{56+27}{12}\\=\frac{83}{12}\)
3. \(+\left(\frac{3}{-10}\right)-\left(\frac{-11}{12}\right)\\= \frac{-3}{10}+\frac{11}{12}\\=\frac{-18}{60}+\frac{55}{60}\\=\frac{-18+55}{60}\\=\frac{37}{60}\)
4. \(+\left(\frac{-12}{13}\right)-\left(\frac{-9}{-13}\right)\\= \frac{-12}{13}-\frac{9}{13}\\=\frac{-12-9}{13}\\=\frac{-21}{13}\)
5. \(+\left(\frac{6}{13}\right)-\left(\frac{-11}{-2}\right)\\= \frac{6}{13}-\frac{11}{2}\\=\frac{12}{26}-\frac{143}{26}\\=\frac{12-143}{26}\\=\frac{-131}{26}\)
6. \(+\left(\frac{8}{-5}\right)+\left(\frac{-6}{13}\right)\\= \frac{-8}{5}-\frac{6}{13}\\=\frac{-104}{65}-\frac{30}{65}\\=\frac{-104-30}{65}\\=\frac{-134}{65}\)
7. \(-\left(\frac{15}{-13}\right)+\left(\frac{-10}{7}\right)\\= \frac{15}{13}-\frac{10}{7}\\=\frac{105}{91}-\frac{130}{91}\\=\frac{105-130}{91}\\=\frac{-25}{91}\)
8. \(-\left(\frac{-5}{2}\right)+\left(\frac{12}{-5}\right)\\= \frac{5}{2}-\frac{12}{5}\\=\frac{25}{10}-\frac{24}{10}\\=\frac{25-24}{10}\\=\frac{1}{10}\)
9. \(-\left(\frac{12}{11}\right)-\left(\frac{9}{13}\right)\\= \frac{-12}{11}-\frac{9}{13}\\=\frac{-156}{143}-\frac{99}{143}\\=\frac{-156-99}{143}\\=\frac{-255}{143}\)
10. \(+\left(\frac{10}{9}\right)-\left(\frac{2}{-7}\right)\\= \frac{10}{9}+\frac{2}{7}\\=\frac{70}{63}+\frac{18}{63}\\=\frac{70+18}{63}\\=\frac{88}{63}\)
11. \(+\left(\frac{2}{11}\right)-\left(\frac{-3}{-2}\right)\\= \frac{2}{11}-\frac{3}{2}\\=\frac{4}{22}-\frac{33}{22}\\=\frac{4-33}{22}\\=\frac{-29}{22}\)
12. \(-\left(\frac{12}{-13}\right)-\left(\frac{14}{3}\right)\\= \frac{12}{13}-\frac{14}{3}\\=\frac{36}{39}-\frac{182}{39}\\=\frac{36-182}{39}\\=\frac{-146}{39}\)