Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{13}{-11}\right)+\left(\frac{-11}{9}\right)\)
2. \(+\left(\frac{-8}{3}\right)+\left(\frac{7}{9}\right)\)
3. \(+\left(\frac{15}{14}\right)-\left(\frac{8}{13}\right)\)
4. \(-\left(\frac{3}{8}\right)+\left(\frac{2}{-3}\right)\)
5. \(-\left(\frac{-6}{5}\right)+\left(\frac{-5}{9}\right)\)
6. \(-\left(\frac{10}{11}\right)-\left(\frac{2}{3}\right)\)
7. \(+\left(\frac{-6}{13}\right)-\left(\frac{9}{4}\right)\)
8. \(-\left(\frac{14}{11}\right)-\left(\frac{-8}{-3}\right)\)
9. \(-\left(\frac{-2}{-13}\right)-\left(\frac{-11}{5}\right)\)
10. \(+\left(\frac{6}{-13}\right)+\left(\frac{-2}{-5}\right)\)
11. \(-\left(\frac{11}{-5}\right)+\left(\frac{-12}{11}\right)\)
12. \(+\left(\frac{15}{-11}\right)+\left(\frac{5}{-6}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{13}{-11}\right)+\left(\frac{-11}{9}\right)\\= \frac{-13}{11}-\frac{11}{9}\\=\frac{-117}{99}-\frac{121}{99}\\=\frac{-117-121}{99}\\=\frac{-238}{99}\)
2. \(+\left(\frac{-8}{3}\right)+\left(\frac{7}{9}\right)\\= \frac{-8}{3}+\frac{7}{9}\\=\frac{-24}{9}+\frac{7}{9}\\=\frac{-24+7}{9}\\=\frac{-17}{9}\)
3. \(+\left(\frac{15}{14}\right)-\left(\frac{8}{13}\right)\\= \frac{15}{14}-\frac{8}{13}\\=\frac{195}{182}-\frac{112}{182}\\=\frac{195-112}{182}\\=\frac{83}{182}\)
4. \(-\left(\frac{3}{8}\right)+\left(\frac{2}{-3}\right)\\= \frac{-3}{8}-\frac{2}{3}\\=\frac{-9}{24}-\frac{16}{24}\\=\frac{-9-16}{24}\\=\frac{-25}{24}\)
5. \(-\left(\frac{-6}{5}\right)+\left(\frac{-5}{9}\right)\\= \frac{6}{5}-\frac{5}{9}\\=\frac{54}{45}-\frac{25}{45}\\=\frac{54-25}{45}\\=\frac{29}{45}\)
6. \(-\left(\frac{10}{11}\right)-\left(\frac{2}{3}\right)\\= \frac{-10}{11}-\frac{2}{3}\\=\frac{-30}{33}-\frac{22}{33}\\=\frac{-30-22}{33}\\=\frac{-52}{33}\)
7. \(+\left(\frac{-6}{13}\right)-\left(\frac{9}{4}\right)\\= \frac{-6}{13}-\frac{9}{4}\\=\frac{-24}{52}-\frac{117}{52}\\=\frac{-24-117}{52}\\=\frac{-141}{52}\)
8. \(-\left(\frac{14}{11}\right)-\left(\frac{-8}{-3}\right)\\= \frac{-14}{11}-\frac{8}{3}\\=\frac{-42}{33}-\frac{88}{33}\\=\frac{-42-88}{33}\\=\frac{-130}{33}\)
9. \(-\left(\frac{-2}{-13}\right)-\left(\frac{-11}{5}\right)\\= \frac{-2}{13}+\frac{11}{5}\\=\frac{-10}{65}+\frac{143}{65}\\=\frac{-10+143}{65}\\=\frac{133}{65}\)
10. \(+\left(\frac{6}{-13}\right)+\left(\frac{-2}{-5}\right)\\= \frac{-6}{13}+\frac{2}{5}\\=\frac{-30}{65}+\frac{26}{65}\\=\frac{-30+26}{65}\\=\frac{-4}{65}\)
11. \(-\left(\frac{11}{-5}\right)+\left(\frac{-12}{11}\right)\\= \frac{11}{5}-\frac{12}{11}\\=\frac{121}{55}-\frac{60}{55}\\=\frac{121-60}{55}\\=\frac{61}{55}\)
12. \(+\left(\frac{15}{-11}\right)+\left(\frac{5}{-6}\right)\\= \frac{-15}{11}-\frac{5}{6}\\=\frac{-90}{66}-\frac{55}{66}\\=\frac{-90-55}{66}\\=\frac{-145}{66}\)