Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{-7}\right)-\left(\frac{-9}{13}\right)\)
2. \(-\left(\frac{14}{3}\right)+\left(\frac{10}{-3}\right)\)
3. \(+\left(\frac{4}{-5}\right)+\left(\frac{5}{-11}\right)\)
4. \(-\left(\frac{2}{3}\right)-\left(\frac{-14}{-9}\right)\)
5. \(-\left(\frac{-10}{7}\right)+\left(\frac{-12}{-13}\right)\)
6. \(-\left(\frac{-12}{5}\right)-\left(\frac{-6}{-13}\right)\)
7. \(-\left(\frac{15}{-4}\right)-\left(\frac{-4}{-7}\right)\)
8. \(-\left(\frac{-12}{13}\right)+\left(\frac{15}{-7}\right)\)
9. \(-\left(\frac{-7}{12}\right)-\left(\frac{4}{5}\right)\)
10. \(-\left(\frac{7}{9}\right)-\left(\frac{-12}{-5}\right)\)
11. \(+\left(\frac{-8}{5}\right)-\left(\frac{10}{3}\right)\)
12. \(-\left(\frac{11}{-3}\right)+\left(\frac{-11}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{10}{-7}\right)-\left(\frac{-9}{13}\right)\\= \frac{-10}{7}+\frac{9}{13}\\=\frac{-130}{91}+\frac{63}{91}\\=\frac{-130+63}{91}\\=\frac{-67}{91}\)
2. \(-\left(\frac{14}{3}\right)+\left(\frac{10}{-3}\right)\\= \frac{-14}{3}-\frac{10}{3}\\=\frac{-14-10}{3}\\=\frac{-24}{3}\\=\frac{-8}{1}\)
3. \(+\left(\frac{4}{-5}\right)+\left(\frac{5}{-11}\right)\\= \frac{-4}{5}-\frac{5}{11}\\=\frac{-44}{55}-\frac{25}{55}\\=\frac{-44-25}{55}\\=\frac{-69}{55}\)
4. \(-\left(\frac{2}{3}\right)-\left(\frac{-14}{-9}\right)\\= \frac{-2}{3}-\frac{14}{9}\\=\frac{-6}{9}-\frac{14}{9}\\=\frac{-6-14}{9}\\=\frac{-20}{9}\)
5. \(-\left(\frac{-10}{7}\right)+\left(\frac{-12}{-13}\right)\\= \frac{10}{7}+\frac{12}{13}\\=\frac{130}{91}+\frac{84}{91}\\=\frac{130+84}{91}\\=\frac{214}{91}\)
6. \(-\left(\frac{-12}{5}\right)-\left(\frac{-6}{-13}\right)\\= \frac{12}{5}-\frac{6}{13}\\=\frac{156}{65}-\frac{30}{65}\\=\frac{156-30}{65}\\=\frac{126}{65}\)
7. \(-\left(\frac{15}{-4}\right)-\left(\frac{-4}{-7}\right)\\= \frac{15}{4}-\frac{4}{7}\\=\frac{105}{28}-\frac{16}{28}\\=\frac{105-16}{28}\\=\frac{89}{28}\)
8. \(-\left(\frac{-12}{13}\right)+\left(\frac{15}{-7}\right)\\= \frac{12}{13}-\frac{15}{7}\\=\frac{84}{91}-\frac{195}{91}\\=\frac{84-195}{91}\\=\frac{-111}{91}\)
9. \(-\left(\frac{-7}{12}\right)-\left(\frac{4}{5}\right)\\= \frac{7}{12}-\frac{4}{5}\\=\frac{35}{60}-\frac{48}{60}\\=\frac{35-48}{60}\\=\frac{-13}{60}\)
10. \(-\left(\frac{7}{9}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-7}{9}-\frac{12}{5}\\=\frac{-35}{45}-\frac{108}{45}\\=\frac{-35-108}{45}\\=\frac{-143}{45}\)
11. \(+\left(\frac{-8}{5}\right)-\left(\frac{10}{3}\right)\\= \frac{-8}{5}-\frac{10}{3}\\=\frac{-24}{15}-\frac{50}{15}\\=\frac{-24-50}{15}\\=\frac{-74}{15}\)
12. \(-\left(\frac{11}{-3}\right)+\left(\frac{-11}{-3}\right)\\= \frac{11}{3}+\frac{11}{3}\\=\frac{11+11}{3}\\=\frac{22}{3}\)