Breuken haakjesregel (reeks 1)

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Bereken

1. \(+\left(\frac{-15}{4}\right)+\left(\frac{-5}{6}\right)\)
2. \(+\left(\frac{-2}{5}\right)-\left(\frac{6}{-5}\right)\)
3. \(-\left(\frac{-7}{12}\right)-\left(\frac{4}{-13}\right)\)
4. \(+\left(\frac{-7}{-10}\right)-\left(\frac{10}{7}\right)\)
5. \(+\left(\frac{-4}{3}\right)-\left(\frac{13}{3}\right)\)
6. \(+\left(\frac{-13}{-2}\right)-\left(\frac{11}{13}\right)\)
7. \(-\left(\frac{-12}{-5}\right)+\left(\frac{-5}{-2}\right)\)
8. \(+\left(\frac{11}{-9}\right)-\left(\frac{13}{2}\right)\)
9. \(-\left(\frac{5}{-13}\right)-\left(\frac{-15}{4}\right)\)
10. \(-\left(\frac{14}{13}\right)+\left(\frac{-15}{-7}\right)\)
11. \(-\left(\frac{7}{10}\right)-\left(\frac{4}{9}\right)\)
12. \(+\left(\frac{-15}{7}\right)+\left(\frac{-10}{7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-15}{4}\right)+\left(\frac{-5}{6}\right)\\= \frac{-15}{4}-\frac{5}{6}\\=\frac{-45}{12}-\frac{10}{12}\\=\frac{-45-10}{12}\\=\frac{-55}{12}\)
2. \(+\left(\frac{-2}{5}\right)-\left(\frac{6}{-5}\right)\\= \frac{-2}{5}+\frac{6}{5}\\=\frac{-2+6}{5}\\=\frac{4}{5}\)
3. \(-\left(\frac{-7}{12}\right)-\left(\frac{4}{-13}\right)\\= \frac{7}{12}+\frac{4}{13}\\=\frac{91}{156}+\frac{48}{156}\\=\frac{91+48}{156}\\=\frac{139}{156}\)
4. \(+\left(\frac{-7}{-10}\right)-\left(\frac{10}{7}\right)\\= \frac{7}{10}-\frac{10}{7}\\=\frac{49}{70}-\frac{100}{70}\\=\frac{49-100}{70}\\=\frac{-51}{70}\)
5. \(+\left(\frac{-4}{3}\right)-\left(\frac{13}{3}\right)\\= \frac{-4}{3}-\frac{13}{3}\\=\frac{-4-13}{3}\\=\frac{-17}{3}\)
6. \(+\left(\frac{-13}{-2}\right)-\left(\frac{11}{13}\right)\\= \frac{13}{2}-\frac{11}{13}\\=\frac{169}{26}-\frac{22}{26}\\=\frac{169-22}{26}\\=\frac{147}{26}\)
7. \(-\left(\frac{-12}{-5}\right)+\left(\frac{-5}{-2}\right)\\= \frac{-12}{5}+\frac{5}{2}\\=\frac{-24}{10}+\frac{25}{10}\\=\frac{-24+25}{10}\\=\frac{1}{10}\)
8. \(+\left(\frac{11}{-9}\right)-\left(\frac{13}{2}\right)\\= \frac{-11}{9}-\frac{13}{2}\\=\frac{-22}{18}-\frac{117}{18}\\=\frac{-22-117}{18}\\=\frac{-139}{18}\)
9. \(-\left(\frac{5}{-13}\right)-\left(\frac{-15}{4}\right)\\= \frac{5}{13}+\frac{15}{4}\\=\frac{20}{52}+\frac{195}{52}\\=\frac{20+195}{52}\\=\frac{215}{52}\)
10. \(-\left(\frac{14}{13}\right)+\left(\frac{-15}{-7}\right)\\= \frac{-14}{13}+\frac{15}{7}\\=\frac{-98}{91}+\frac{195}{91}\\=\frac{-98+195}{91}\\=\frac{97}{91}\)
11. \(-\left(\frac{7}{10}\right)-\left(\frac{4}{9}\right)\\= \frac{-7}{10}-\frac{4}{9}\\=\frac{-63}{90}-\frac{40}{90}\\=\frac{-63-40}{90}\\=\frac{-103}{90}\)
12. \(+\left(\frac{-15}{7}\right)+\left(\frac{-10}{7}\right)\\= \frac{-15}{7}-\frac{10}{7}\\=\frac{-15-10}{7}\\=\frac{-25}{7}\)