Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-3}{-10}\right)-\left(\frac{14}{9}\right)\)
2. \(-\left(\frac{-13}{9}\right)+\left(\frac{-11}{2}\right)\)
3. \(+\left(\frac{-3}{8}\right)+\left(\frac{6}{-5}\right)\)
4. \(-\left(\frac{-13}{-2}\right)+\left(\frac{8}{5}\right)\)
5. \(+\left(\frac{-10}{-7}\right)+\left(\frac{-13}{-3}\right)\)
6. \(+\left(\frac{5}{-14}\right)-\left(\frac{-8}{-3}\right)\)
7. \(-\left(\frac{6}{7}\right)-\left(\frac{10}{11}\right)\)
8. \(+\left(\frac{10}{-3}\right)+\left(\frac{10}{3}\right)\)
9. \(+\left(\frac{3}{-4}\right)-\left(\frac{4}{7}\right)\)
10. \(-\left(\frac{-14}{3}\right)-\left(\frac{14}{-3}\right)\)
11. \(+\left(\frac{6}{7}\right)-\left(\frac{6}{11}\right)\)
12. \(+\left(\frac{-10}{-11}\right)+\left(\frac{-11}{5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-3}{-10}\right)-\left(\frac{14}{9}\right)\\= \frac{3}{10}-\frac{14}{9}\\=\frac{27}{90}-\frac{140}{90}\\=\frac{27-140}{90}\\=\frac{-113}{90}\)
2. \(-\left(\frac{-13}{9}\right)+\left(\frac{-11}{2}\right)\\= \frac{13}{9}-\frac{11}{2}\\=\frac{26}{18}-\frac{99}{18}\\=\frac{26-99}{18}\\=\frac{-73}{18}\)
3. \(+\left(\frac{-3}{8}\right)+\left(\frac{6}{-5}\right)\\= \frac{-3}{8}-\frac{6}{5}\\=\frac{-15}{40}-\frac{48}{40}\\=\frac{-15-48}{40}\\=\frac{-63}{40}\)
4. \(-\left(\frac{-13}{-2}\right)+\left(\frac{8}{5}\right)\\= \frac{-13}{2}+\frac{8}{5}\\=\frac{-65}{10}+\frac{16}{10}\\=\frac{-65+16}{10}\\=\frac{-49}{10}\)
5. \(+\left(\frac{-10}{-7}\right)+\left(\frac{-13}{-3}\right)\\= \frac{10}{7}+\frac{13}{3}\\=\frac{30}{21}+\frac{91}{21}\\=\frac{30+91}{21}\\=\frac{121}{21}\)
6. \(+\left(\frac{5}{-14}\right)-\left(\frac{-8}{-3}\right)\\= \frac{-5}{14}-\frac{8}{3}\\=\frac{-15}{42}-\frac{112}{42}\\=\frac{-15-112}{42}\\=\frac{-127}{42}\)
7. \(-\left(\frac{6}{7}\right)-\left(\frac{10}{11}\right)\\= \frac{-6}{7}-\frac{10}{11}\\=\frac{-66}{77}-\frac{70}{77}\\=\frac{-66-70}{77}\\=\frac{-136}{77}\)
8. \(+\left(\frac{10}{-3}\right)+\left(\frac{10}{3}\right)\\= \frac{-10}{3}+\frac{10}{3}\\=\frac{-10+10}{3}\\=\frac{0}{3}\\=\frac{0}{1}\)
9. \(+\left(\frac{3}{-4}\right)-\left(\frac{4}{7}\right)\\= \frac{-3}{4}-\frac{4}{7}\\=\frac{-21}{28}-\frac{16}{28}\\=\frac{-21-16}{28}\\=\frac{-37}{28}\)
10. \(-\left(\frac{-14}{3}\right)-\left(\frac{14}{-3}\right)\\= \frac{14}{3}+\frac{14}{3}\\=\frac{14+14}{3}\\=\frac{28}{3}\)
11. \(+\left(\frac{6}{7}\right)-\left(\frac{6}{11}\right)\\= \frac{6}{7}-\frac{6}{11}\\=\frac{66}{77}-\frac{42}{77}\\=\frac{66-42}{77}\\=\frac{24}{77}\)
12. \(+\left(\frac{-10}{-11}\right)+\left(\frac{-11}{5}\right)\\= \frac{10}{11}-\frac{11}{5}\\=\frac{50}{55}-\frac{121}{55}\\=\frac{50-121}{55}\\=\frac{-71}{55}\)