Breuken haakjesregel (reeks 1)

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Bereken

1. \(-\left(\frac{-2}{3}\right)+\left(\frac{12}{-5}\right)\)
2. \(+\left(\frac{-2}{-3}\right)-\left(\frac{-2}{3}\right)\)
3. \(-\left(\frac{-2}{7}\right)+\left(\frac{-4}{-9}\right)\)
4. \(-\left(\frac{12}{-5}\right)+\left(\frac{-5}{-7}\right)\)
5. \(-\left(\frac{-2}{-11}\right)+\left(\frac{5}{6}\right)\)
6. \(-\left(\frac{-8}{13}\right)-\left(\frac{-9}{10}\right)\)
7. \(-\left(\frac{-7}{-2}\right)-\left(\frac{11}{13}\right)\)
8. \(+\left(\frac{-2}{11}\right)+\left(\frac{-10}{-7}\right)\)
9. \(+\left(\frac{7}{-10}\right)-\left(\frac{-14}{-5}\right)\)
10. \(+\left(\frac{-6}{5}\right)+\left(\frac{-8}{5}\right)\)
11. \(-\left(\frac{14}{-3}\right)+\left(\frac{-8}{-13}\right)\)
12. \(-\left(\frac{-6}{-7}\right)+\left(\frac{-8}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-2}{3}\right)+\left(\frac{12}{-5}\right)\\= \frac{2}{3}-\frac{12}{5}\\=\frac{10}{15}-\frac{36}{15}\\=\frac{10-36}{15}\\=\frac{-26}{15}\)
2. \(+\left(\frac{-2}{-3}\right)-\left(\frac{-2}{3}\right)\\= \frac{2}{3}+\frac{2}{3}\\=\frac{2+2}{3}\\=\frac{4}{3}\)
3. \(-\left(\frac{-2}{7}\right)+\left(\frac{-4}{-9}\right)\\= \frac{2}{7}+\frac{4}{9}\\=\frac{18}{63}+\frac{28}{63}\\=\frac{18+28}{63}\\=\frac{46}{63}\)
4. \(-\left(\frac{12}{-5}\right)+\left(\frac{-5}{-7}\right)\\= \frac{12}{5}+\frac{5}{7}\\=\frac{84}{35}+\frac{25}{35}\\=\frac{84+25}{35}\\=\frac{109}{35}\)
5. \(-\left(\frac{-2}{-11}\right)+\left(\frac{5}{6}\right)\\= \frac{-2}{11}+\frac{5}{6}\\=\frac{-12}{66}+\frac{55}{66}\\=\frac{-12+55}{66}\\=\frac{43}{66}\)
6. \(-\left(\frac{-8}{13}\right)-\left(\frac{-9}{10}\right)\\= \frac{8}{13}+\frac{9}{10}\\=\frac{80}{130}+\frac{117}{130}\\=\frac{80+117}{130}\\=\frac{197}{130}\)
7. \(-\left(\frac{-7}{-2}\right)-\left(\frac{11}{13}\right)\\= \frac{-7}{2}-\frac{11}{13}\\=\frac{-91}{26}-\frac{22}{26}\\=\frac{-91-22}{26}\\=\frac{-113}{26}\)
8. \(+\left(\frac{-2}{11}\right)+\left(\frac{-10}{-7}\right)\\= \frac{-2}{11}+\frac{10}{7}\\=\frac{-14}{77}+\frac{110}{77}\\=\frac{-14+110}{77}\\=\frac{96}{77}\)
9. \(+\left(\frac{7}{-10}\right)-\left(\frac{-14}{-5}\right)\\= \frac{-7}{10}-\frac{14}{5}\\=\frac{-7-14}{10}\\=\frac{-21}{10}\)
10. \(+\left(\frac{-6}{5}\right)+\left(\frac{-8}{5}\right)\\= \frac{-6}{5}-\frac{8}{5}\\=\frac{-6-8}{5}\\=\frac{-14}{5}\)
11. \(-\left(\frac{14}{-3}\right)+\left(\frac{-8}{-13}\right)\\= \frac{14}{3}+\frac{8}{13}\\=\frac{182}{39}+\frac{24}{39}\\=\frac{182+24}{39}\\=\frac{206}{39}\)
12. \(-\left(\frac{-6}{-7}\right)+\left(\frac{-8}{-13}\right)\\= \frac{-6}{7}+\frac{8}{13}\\=\frac{-78}{91}+\frac{56}{91}\\=\frac{-78+56}{91}\\=\frac{-22}{91}\)