Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-10}{-11}\right)-\left(\frac{-12}{-5}\right)\)
2. \(-\left(\frac{-11}{-8}\right)-\left(\frac{-5}{-13}\right)\)
3. \(+\left(\frac{-6}{-11}\right)+\left(\frac{10}{9}\right)\)
4. \(-\left(\frac{5}{-6}\right)+\left(\frac{-7}{3}\right)\)
5. \(-\left(\frac{-9}{-5}\right)-\left(\frac{-15}{-2}\right)\)
6. \(-\left(\frac{-11}{-2}\right)+\left(\frac{-8}{3}\right)\)
7. \(-\left(\frac{-3}{13}\right)-\left(\frac{-5}{-8}\right)\)
8. \(-\left(\frac{10}{-9}\right)-\left(\frac{-12}{-13}\right)\)
9. \(-\left(\frac{14}{-9}\right)+\left(\frac{-13}{10}\right)\)
10. \(+\left(\frac{15}{-14}\right)+\left(\frac{12}{5}\right)\)
11. \(+\left(\frac{4}{5}\right)+\left(\frac{-5}{6}\right)\)
12. \(-\left(\frac{-10}{11}\right)+\left(\frac{-3}{7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-10}{-11}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-10}{11}-\frac{12}{5}\\=\frac{-50}{55}-\frac{132}{55}\\=\frac{-50-132}{55}\\=\frac{-182}{55}\)
2. \(-\left(\frac{-11}{-8}\right)-\left(\frac{-5}{-13}\right)\\= \frac{-11}{8}-\frac{5}{13}\\=\frac{-143}{104}-\frac{40}{104}\\=\frac{-143-40}{104}\\=\frac{-183}{104}\)
3. \(+\left(\frac{-6}{-11}\right)+\left(\frac{10}{9}\right)\\= \frac{6}{11}+\frac{10}{9}\\=\frac{54}{99}+\frac{110}{99}\\=\frac{54+110}{99}\\=\frac{164}{99}\)
4. \(-\left(\frac{5}{-6}\right)+\left(\frac{-7}{3}\right)\\= \frac{5}{6}-\frac{7}{3}\\=\frac{5-7}{6}\\=\frac{-2}{6}\\=\frac{-1}{3}\)
5. \(-\left(\frac{-9}{-5}\right)-\left(\frac{-15}{-2}\right)\\= \frac{-9}{5}-\frac{15}{2}\\=\frac{-18}{10}-\frac{75}{10}\\=\frac{-18-75}{10}\\=\frac{-93}{10}\)
6. \(-\left(\frac{-11}{-2}\right)+\left(\frac{-8}{3}\right)\\= \frac{-11}{2}-\frac{8}{3}\\=\frac{-33}{6}-\frac{16}{6}\\=\frac{-33-16}{6}\\=\frac{-49}{6}\)
7. \(-\left(\frac{-3}{13}\right)-\left(\frac{-5}{-8}\right)\\= \frac{3}{13}-\frac{5}{8}\\=\frac{24}{104}-\frac{65}{104}\\=\frac{24-65}{104}\\=\frac{-41}{104}\)
8. \(-\left(\frac{10}{-9}\right)-\left(\frac{-12}{-13}\right)\\= \frac{10}{9}-\frac{12}{13}\\=\frac{130}{117}-\frac{108}{117}\\=\frac{130-108}{117}\\=\frac{22}{117}\)
9. \(-\left(\frac{14}{-9}\right)+\left(\frac{-13}{10}\right)\\= \frac{14}{9}-\frac{13}{10}\\=\frac{140}{90}-\frac{117}{90}\\=\frac{140-117}{90}\\=\frac{23}{90}\)
10. \(+\left(\frac{15}{-14}\right)+\left(\frac{12}{5}\right)\\= \frac{-15}{14}+\frac{12}{5}\\=\frac{-75}{70}+\frac{168}{70}\\=\frac{-75+168}{70}\\=\frac{93}{70}\)
11. \(+\left(\frac{4}{5}\right)+\left(\frac{-5}{6}\right)\\= \frac{4}{5}-\frac{5}{6}\\=\frac{24}{30}-\frac{25}{30}\\=\frac{24-25}{30}\\=\frac{-1}{30}\)
12. \(-\left(\frac{-10}{11}\right)+\left(\frac{-3}{7}\right)\\= \frac{10}{11}-\frac{3}{7}\\=\frac{70}{77}-\frac{33}{77}\\=\frac{70-33}{77}\\=\frac{37}{77}\)