Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-5}{-11}\right)+\left(\frac{8}{-5}\right)\)
2. \(+\left(\frac{-10}{11}\right)+\left(\frac{10}{7}\right)\)
3. \(-\left(\frac{2}{7}\right)+\left(\frac{15}{11}\right)\)
4. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-3}{-8}\right)\)
5. \(+\left(\frac{-7}{-4}\right)+\left(\frac{-11}{5}\right)\)
6. \(+\left(\frac{-6}{11}\right)-\left(\frac{-4}{7}\right)\)
7. \(-\left(\frac{13}{6}\right)+\left(\frac{-6}{13}\right)\)
8. \(-\left(\frac{15}{-4}\right)-\left(\frac{-7}{12}\right)\)
9. \(+\left(\frac{-15}{7}\right)+\left(\frac{10}{-3}\right)\)
10. \(+\left(\frac{2}{11}\right)+\left(\frac{15}{-11}\right)\)
11. \(-\left(\frac{7}{5}\right)+\left(\frac{-13}{-9}\right)\)
12. \(+\left(\frac{6}{7}\right)+\left(\frac{4}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-5}{-11}\right)+\left(\frac{8}{-5}\right)\\= \frac{-5}{11}-\frac{8}{5}\\=\frac{-25}{55}-\frac{88}{55}\\=\frac{-25-88}{55}\\=\frac{-113}{55}\)
2. \(+\left(\frac{-10}{11}\right)+\left(\frac{10}{7}\right)\\= \frac{-10}{11}+\frac{10}{7}\\=\frac{-70}{77}+\frac{110}{77}\\=\frac{-70+110}{77}\\=\frac{40}{77}\)
3. \(-\left(\frac{2}{7}\right)+\left(\frac{15}{11}\right)\\= \frac{-2}{7}+\frac{15}{11}\\=\frac{-22}{77}+\frac{105}{77}\\=\frac{-22+105}{77}\\=\frac{83}{77}\)
4. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-3}{-8}\right)\\= \frac{12}{5}+\frac{3}{8}\\=\frac{96}{40}+\frac{15}{40}\\=\frac{96+15}{40}\\=\frac{111}{40}\)
5. \(+\left(\frac{-7}{-4}\right)+\left(\frac{-11}{5}\right)\\= \frac{7}{4}-\frac{11}{5}\\=\frac{35}{20}-\frac{44}{20}\\=\frac{35-44}{20}\\=\frac{-9}{20}\)
6. \(+\left(\frac{-6}{11}\right)-\left(\frac{-4}{7}\right)\\= \frac{-6}{11}+\frac{4}{7}\\=\frac{-42}{77}+\frac{44}{77}\\=\frac{-42+44}{77}\\=\frac{2}{77}\)
7. \(-\left(\frac{13}{6}\right)+\left(\frac{-6}{13}\right)\\= \frac{-13}{6}-\frac{6}{13}\\=\frac{-169}{78}-\frac{36}{78}\\=\frac{-169-36}{78}\\=\frac{-205}{78}\)
8. \(-\left(\frac{15}{-4}\right)-\left(\frac{-7}{12}\right)\\= \frac{15}{4}+\frac{7}{12}\\=\frac{45}{12}+\frac{7}{12}\\=\frac{45+7}{12}\\=\frac{52}{12}\\=\frac{13}{3}\)
9. \(+\left(\frac{-15}{7}\right)+\left(\frac{10}{-3}\right)\\= \frac{-15}{7}-\frac{10}{3}\\=\frac{-45}{21}-\frac{70}{21}\\=\frac{-45-70}{21}\\=\frac{-115}{21}\)
10. \(+\left(\frac{2}{11}\right)+\left(\frac{15}{-11}\right)\\= \frac{2}{11}-\frac{15}{11}\\=\frac{2-15}{11}\\=\frac{-13}{11}\)
11. \(-\left(\frac{7}{5}\right)+\left(\frac{-13}{-9}\right)\\= \frac{-7}{5}+\frac{13}{9}\\=\frac{-63}{45}+\frac{65}{45}\\=\frac{-63+65}{45}\\=\frac{2}{45}\)
12. \(+\left(\frac{6}{7}\right)+\left(\frac{4}{-13}\right)\\= \frac{6}{7}-\frac{4}{13}\\=\frac{78}{91}-\frac{28}{91}\\=\frac{78-28}{91}\\=\frac{50}{91}\)