Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-10}{9}\right)+\left(\frac{-3}{-10}\right)\)
2. \(-\left(\frac{-8}{3}\right)-\left(\frac{14}{9}\right)\)
3. \(-\left(\frac{15}{-8}\right)+\left(\frac{-7}{-8}\right)\)
4. \(+\left(\frac{9}{4}\right)+\left(\frac{-12}{7}\right)\)
5. \(+\left(\frac{-10}{-3}\right)+\left(\frac{-2}{11}\right)\)
6. \(+\left(\frac{-9}{7}\right)+\left(\frac{-9}{-13}\right)\)
7. \(-\left(\frac{13}{-10}\right)+\left(\frac{9}{-13}\right)\)
8. \(-\left(\frac{3}{-10}\right)-\left(\frac{9}{-5}\right)\)
9. \(-\left(\frac{2}{11}\right)-\left(\frac{13}{-10}\right)\)
10. \(-\left(\frac{-8}{-9}\right)+\left(\frac{-11}{-2}\right)\)
11. \(+\left(\frac{-6}{11}\right)+\left(\frac{-8}{-7}\right)\)
12. \(-\left(\frac{10}{11}\right)-\left(\frac{-11}{8}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-10}{9}\right)+\left(\frac{-3}{-10}\right)\\= \frac{-10}{9}+\frac{3}{10}\\=\frac{-100}{90}+\frac{27}{90}\\=\frac{-100+27}{90}\\=\frac{-73}{90}\)
2. \(-\left(\frac{-8}{3}\right)-\left(\frac{14}{9}\right)\\= \frac{8}{3}-\frac{14}{9}\\=\frac{24}{9}-\frac{14}{9}\\=\frac{24-14}{9}\\=\frac{10}{9}\)
3. \(-\left(\frac{15}{-8}\right)+\left(\frac{-7}{-8}\right)\\= \frac{15}{8}+\frac{7}{8}\\=\frac{15+7}{8}\\=\frac{22}{8}\\=\frac{11}{4}\)
4. \(+\left(\frac{9}{4}\right)+\left(\frac{-12}{7}\right)\\= \frac{9}{4}-\frac{12}{7}\\=\frac{63}{28}-\frac{48}{28}\\=\frac{63-48}{28}\\=\frac{15}{28}\)
5. \(+\left(\frac{-10}{-3}\right)+\left(\frac{-2}{11}\right)\\= \frac{10}{3}-\frac{2}{11}\\=\frac{110}{33}-\frac{6}{33}\\=\frac{110-6}{33}\\=\frac{104}{33}\)
6. \(+\left(\frac{-9}{7}\right)+\left(\frac{-9}{-13}\right)\\= \frac{-9}{7}+\frac{9}{13}\\=\frac{-117}{91}+\frac{63}{91}\\=\frac{-117+63}{91}\\=\frac{-54}{91}\)
7. \(-\left(\frac{13}{-10}\right)+\left(\frac{9}{-13}\right)\\= \frac{13}{10}-\frac{9}{13}\\=\frac{169}{130}-\frac{90}{130}\\=\frac{169-90}{130}\\=\frac{79}{130}\)
8. \(-\left(\frac{3}{-10}\right)-\left(\frac{9}{-5}\right)\\= \frac{3}{10}+\frac{9}{5}\\=\frac{3+9}{10}\\=\frac{12}{10}\\=\frac{6}{5}\)
9. \(-\left(\frac{2}{11}\right)-\left(\frac{13}{-10}\right)\\= \frac{-2}{11}+\frac{13}{10}\\=\frac{-20}{110}+\frac{143}{110}\\=\frac{-20+143}{110}\\=\frac{123}{110}\)
10. \(-\left(\frac{-8}{-9}\right)+\left(\frac{-11}{-2}\right)\\= \frac{-8}{9}+\frac{11}{2}\\=\frac{-16}{18}+\frac{99}{18}\\=\frac{-16+99}{18}\\=\frac{83}{18}\)
11. \(+\left(\frac{-6}{11}\right)+\left(\frac{-8}{-7}\right)\\= \frac{-6}{11}+\frac{8}{7}\\=\frac{-42}{77}+\frac{88}{77}\\=\frac{-42+88}{77}\\=\frac{46}{77}\)
12. \(-\left(\frac{10}{11}\right)-\left(\frac{-11}{8}\right)\\= \frac{-10}{11}+\frac{11}{8}\\=\frac{-80}{88}+\frac{121}{88}\\=\frac{-80+121}{88}\\=\frac{41}{88}\)