Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{7}\right)-\left(\frac{-6}{5}\right)\)
2. \(-\left(\frac{13}{-10}\right)+\left(\frac{-13}{-9}\right)\)
3. \(-\left(\frac{3}{8}\right)+\left(\frac{14}{-3}\right)\)
4. \(+\left(\frac{-7}{-6}\right)-\left(\frac{7}{8}\right)\)
5. \(+\left(\frac{10}{-13}\right)+\left(\frac{-5}{9}\right)\)
6. \(-\left(\frac{-14}{-13}\right)-\left(\frac{-7}{-2}\right)\)
7. \(+\left(\frac{7}{-13}\right)+\left(\frac{-6}{-11}\right)\)
8. \(-\left(\frac{6}{-5}\right)-\left(\frac{10}{7}\right)\)
9. \(+\left(\frac{-4}{3}\right)-\left(\frac{15}{7}\right)\)
10. \(+\left(\frac{8}{-3}\right)-\left(\frac{-9}{13}\right)\)
11. \(-\left(\frac{-14}{5}\right)+\left(\frac{-10}{13}\right)\)
12. \(-\left(\frac{-10}{-9}\right)-\left(\frac{-13}{7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{10}{7}\right)-\left(\frac{-6}{5}\right)\\= \frac{10}{7}+\frac{6}{5}\\=\frac{50}{35}+\frac{42}{35}\\=\frac{50+42}{35}\\=\frac{92}{35}\)
2. \(-\left(\frac{13}{-10}\right)+\left(\frac{-13}{-9}\right)\\= \frac{13}{10}+\frac{13}{9}\\=\frac{117}{90}+\frac{130}{90}\\=\frac{117+130}{90}\\=\frac{247}{90}\)
3. \(-\left(\frac{3}{8}\right)+\left(\frac{14}{-3}\right)\\= \frac{-3}{8}-\frac{14}{3}\\=\frac{-9}{24}-\frac{112}{24}\\=\frac{-9-112}{24}\\=\frac{-121}{24}\)
4. \(+\left(\frac{-7}{-6}\right)-\left(\frac{7}{8}\right)\\= \frac{7}{6}-\frac{7}{8}\\=\frac{28}{24}-\frac{21}{24}\\=\frac{28-21}{24}\\=\frac{7}{24}\)
5. \(+\left(\frac{10}{-13}\right)+\left(\frac{-5}{9}\right)\\= \frac{-10}{13}-\frac{5}{9}\\=\frac{-90}{117}-\frac{65}{117}\\=\frac{-90-65}{117}\\=\frac{-155}{117}\)
6. \(-\left(\frac{-14}{-13}\right)-\left(\frac{-7}{-2}\right)\\= \frac{-14}{13}-\frac{7}{2}\\=\frac{-28}{26}-\frac{91}{26}\\=\frac{-28-91}{26}\\=\frac{-119}{26}\)
7. \(+\left(\frac{7}{-13}\right)+\left(\frac{-6}{-11}\right)\\= \frac{-7}{13}+\frac{6}{11}\\=\frac{-77}{143}+\frac{78}{143}\\=\frac{-77+78}{143}\\=\frac{1}{143}\)
8. \(-\left(\frac{6}{-5}\right)-\left(\frac{10}{7}\right)\\= \frac{6}{5}-\frac{10}{7}\\=\frac{42}{35}-\frac{50}{35}\\=\frac{42-50}{35}\\=\frac{-8}{35}\)
9. \(+\left(\frac{-4}{3}\right)-\left(\frac{15}{7}\right)\\= \frac{-4}{3}-\frac{15}{7}\\=\frac{-28}{21}-\frac{45}{21}\\=\frac{-28-45}{21}\\=\frac{-73}{21}\)
10. \(+\left(\frac{8}{-3}\right)-\left(\frac{-9}{13}\right)\\= \frac{-8}{3}+\frac{9}{13}\\=\frac{-104}{39}+\frac{27}{39}\\=\frac{-104+27}{39}\\=\frac{-77}{39}\)
11. \(-\left(\frac{-14}{5}\right)+\left(\frac{-10}{13}\right)\\= \frac{14}{5}-\frac{10}{13}\\=\frac{182}{65}-\frac{50}{65}\\=\frac{182-50}{65}\\=\frac{132}{65}\)
12. \(-\left(\frac{-10}{-9}\right)-\left(\frac{-13}{7}\right)\\= \frac{-10}{9}+\frac{13}{7}\\=\frac{-70}{63}+\frac{117}{63}\\=\frac{-70+117}{63}\\=\frac{47}{63}\)