Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{3}\right)+\left(\frac{-15}{7}\right)\)
2. \(+\left(\frac{6}{-11}\right)-\left(\frac{-9}{14}\right)\)
3. \(-\left(\frac{-3}{10}\right)-\left(\frac{-13}{6}\right)\)
4. \(+\left(\frac{10}{-7}\right)+\left(\frac{6}{11}\right)\)
5. \(-\left(\frac{-3}{-13}\right)-\left(\frac{-12}{7}\right)\)
6. \(-\left(\frac{-2}{-9}\right)-\left(\frac{10}{13}\right)\)
7. \(+\left(\frac{-2}{-13}\right)+\left(\frac{12}{5}\right)\)
8. \(-\left(\frac{-2}{9}\right)+\left(\frac{-2}{-11}\right)\)
9. \(-\left(\frac{-7}{-8}\right)-\left(\frac{-2}{-5}\right)\)
10. \(-\left(\frac{-3}{-13}\right)-\left(\frac{-11}{-7}\right)\)
11. \(-\left(\frac{10}{11}\right)-\left(\frac{6}{5}\right)\)
12. \(+\left(\frac{-12}{13}\right)-\left(\frac{12}{11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{10}{3}\right)+\left(\frac{-15}{7}\right)\\= \frac{10}{3}-\frac{15}{7}\\=\frac{70}{21}-\frac{45}{21}\\=\frac{70-45}{21}\\=\frac{25}{21}\)
2. \(+\left(\frac{6}{-11}\right)-\left(\frac{-9}{14}\right)\\= \frac{-6}{11}+\frac{9}{14}\\=\frac{-84}{154}+\frac{99}{154}\\=\frac{-84+99}{154}\\=\frac{15}{154}\)
3. \(-\left(\frac{-3}{10}\right)-\left(\frac{-13}{6}\right)\\= \frac{3}{10}+\frac{13}{6}\\=\frac{9}{30}+\frac{65}{30}\\=\frac{9+65}{30}\\=\frac{74}{30}\\=\frac{37}{15}\)
4. \(+\left(\frac{10}{-7}\right)+\left(\frac{6}{11}\right)\\= \frac{-10}{7}+\frac{6}{11}\\=\frac{-110}{77}+\frac{42}{77}\\=\frac{-110+42}{77}\\=\frac{-68}{77}\)
5. \(-\left(\frac{-3}{-13}\right)-\left(\frac{-12}{7}\right)\\= \frac{-3}{13}+\frac{12}{7}\\=\frac{-21}{91}+\frac{156}{91}\\=\frac{-21+156}{91}\\=\frac{135}{91}\)
6. \(-\left(\frac{-2}{-9}\right)-\left(\frac{10}{13}\right)\\= \frac{-2}{9}-\frac{10}{13}\\=\frac{-26}{117}-\frac{90}{117}\\=\frac{-26-90}{117}\\=\frac{-116}{117}\)
7. \(+\left(\frac{-2}{-13}\right)+\left(\frac{12}{5}\right)\\= \frac{2}{13}+\frac{12}{5}\\=\frac{10}{65}+\frac{156}{65}\\=\frac{10+156}{65}\\=\frac{166}{65}\)
8. \(-\left(\frac{-2}{9}\right)+\left(\frac{-2}{-11}\right)\\= \frac{2}{9}+\frac{2}{11}\\=\frac{22}{99}+\frac{18}{99}\\=\frac{22+18}{99}\\=\frac{40}{99}\)
9. \(-\left(\frac{-7}{-8}\right)-\left(\frac{-2}{-5}\right)\\= \frac{-7}{8}-\frac{2}{5}\\=\frac{-35}{40}-\frac{16}{40}\\=\frac{-35-16}{40}\\=\frac{-51}{40}\)
10. \(-\left(\frac{-3}{-13}\right)-\left(\frac{-11}{-7}\right)\\= \frac{-3}{13}-\frac{11}{7}\\=\frac{-21}{91}-\frac{143}{91}\\=\frac{-21-143}{91}\\=\frac{-164}{91}\)
11. \(-\left(\frac{10}{11}\right)-\left(\frac{6}{5}\right)\\= \frac{-10}{11}-\frac{6}{5}\\=\frac{-50}{55}-\frac{66}{55}\\=\frac{-50-66}{55}\\=\frac{-116}{55}\)
12. \(+\left(\frac{-12}{13}\right)-\left(\frac{12}{11}\right)\\= \frac{-12}{13}-\frac{12}{11}\\=\frac{-132}{143}-\frac{156}{143}\\=\frac{-132-156}{143}\\=\frac{-288}{143}\)