Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-11}{3}\right)-\left(\frac{-8}{11}\right)\)
2. \(-\left(\frac{12}{13}\right)-\left(\frac{-3}{5}\right)\)
3. \(-\left(\frac{11}{-5}\right)+\left(\frac{-10}{7}\right)\)
4. \(-\left(\frac{-12}{11}\right)-\left(\frac{2}{-5}\right)\)
5. \(+\left(\frac{3}{-7}\right)-\left(\frac{-13}{10}\right)\)
6. \(-\left(\frac{-12}{5}\right)+\left(\frac{15}{-13}\right)\)
7. \(-\left(\frac{-13}{6}\right)-\left(\frac{15}{-4}\right)\)
8. \(-\left(\frac{-13}{-10}\right)+\left(\frac{-3}{-13}\right)\)
9. \(+\left(\frac{-7}{-2}\right)+\left(\frac{-6}{13}\right)\)
10. \(+\left(\frac{-6}{-11}\right)+\left(\frac{-6}{-11}\right)\)
11. \(-\left(\frac{9}{10}\right)-\left(\frac{2}{-7}\right)\)
12. \(+\left(\frac{-11}{-13}\right)-\left(\frac{10}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-11}{3}\right)-\left(\frac{-8}{11}\right)\\= \frac{-11}{3}+\frac{8}{11}\\=\frac{-121}{33}+\frac{24}{33}\\=\frac{-121+24}{33}\\=\frac{-97}{33}\)
2. \(-\left(\frac{12}{13}\right)-\left(\frac{-3}{5}\right)\\= \frac{-12}{13}+\frac{3}{5}\\=\frac{-60}{65}+\frac{39}{65}\\=\frac{-60+39}{65}\\=\frac{-21}{65}\)
3. \(-\left(\frac{11}{-5}\right)+\left(\frac{-10}{7}\right)\\= \frac{11}{5}-\frac{10}{7}\\=\frac{77}{35}-\frac{50}{35}\\=\frac{77-50}{35}\\=\frac{27}{35}\)
4. \(-\left(\frac{-12}{11}\right)-\left(\frac{2}{-5}\right)\\= \frac{12}{11}+\frac{2}{5}\\=\frac{60}{55}+\frac{22}{55}\\=\frac{60+22}{55}\\=\frac{82}{55}\)
5. \(+\left(\frac{3}{-7}\right)-\left(\frac{-13}{10}\right)\\= \frac{-3}{7}+\frac{13}{10}\\=\frac{-30}{70}+\frac{91}{70}\\=\frac{-30+91}{70}\\=\frac{61}{70}\)
6. \(-\left(\frac{-12}{5}\right)+\left(\frac{15}{-13}\right)\\= \frac{12}{5}-\frac{15}{13}\\=\frac{156}{65}-\frac{75}{65}\\=\frac{156-75}{65}\\=\frac{81}{65}\)
7. \(-\left(\frac{-13}{6}\right)-\left(\frac{15}{-4}\right)\\= \frac{13}{6}+\frac{15}{4}\\=\frac{26}{12}+\frac{45}{12}\\=\frac{26+45}{12}\\=\frac{71}{12}\)
8. \(-\left(\frac{-13}{-10}\right)+\left(\frac{-3}{-13}\right)\\= \frac{-13}{10}+\frac{3}{13}\\=\frac{-169}{130}+\frac{30}{130}\\=\frac{-169+30}{130}\\=\frac{-139}{130}\)
9. \(+\left(\frac{-7}{-2}\right)+\left(\frac{-6}{13}\right)\\= \frac{7}{2}-\frac{6}{13}\\=\frac{91}{26}-\frac{12}{26}\\=\frac{91-12}{26}\\=\frac{79}{26}\)
10. \(+\left(\frac{-6}{-11}\right)+\left(\frac{-6}{-11}\right)\\= \frac{6}{11}+\frac{6}{11}\\=\frac{6+6}{11}\\=\frac{12}{11}\)
11. \(-\left(\frac{9}{10}\right)-\left(\frac{2}{-7}\right)\\= \frac{-9}{10}+\frac{2}{7}\\=\frac{-63}{70}+\frac{20}{70}\\=\frac{-63+20}{70}\\=\frac{-43}{70}\)
12. \(+\left(\frac{-11}{-13}\right)-\left(\frac{10}{-7}\right)\\= \frac{11}{13}+\frac{10}{7}\\=\frac{77}{91}+\frac{130}{91}\\=\frac{77+130}{91}\\=\frac{207}{91}\)