Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-8}{-13}\right)\)
2. \(+\left(\frac{-6}{-7}\right)+\left(\frac{9}{-7}\right)\)
3. \(+\left(\frac{8}{-3}\right)+\left(\frac{-13}{-12}\right)\)
4. \(-\left(\frac{-5}{-3}\right)+\left(\frac{14}{3}\right)\)
5. \(+\left(\frac{11}{8}\right)-\left(\frac{-11}{2}\right)\)
6. \(-\left(\frac{-6}{5}\right)-\left(\frac{-2}{3}\right)\)
7. \(-\left(\frac{10}{7}\right)+\left(\frac{14}{-11}\right)\)
8. \(-\left(\frac{14}{13}\right)-\left(\frac{11}{-7}\right)\)
9. \(-\left(\frac{-12}{11}\right)-\left(\frac{-4}{-13}\right)\)
10. \(-\left(\frac{8}{-11}\right)-\left(\frac{11}{-3}\right)\)
11. \(-\left(\frac{11}{-13}\right)+\left(\frac{2}{-7}\right)\)
12. \(+\left(\frac{6}{-11}\right)+\left(\frac{-4}{-9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-8}{-13}\right)\\= \frac{4}{3}-\frac{8}{13}\\=\frac{52}{39}-\frac{24}{39}\\=\frac{52-24}{39}\\=\frac{28}{39}\)
2. \(+\left(\frac{-6}{-7}\right)+\left(\frac{9}{-7}\right)\\= \frac{6}{7}-\frac{9}{7}\\=\frac{6-9}{7}\\=\frac{-3}{7}\)
3. \(+\left(\frac{8}{-3}\right)+\left(\frac{-13}{-12}\right)\\= \frac{-8}{3}+\frac{13}{12}\\=\frac{-32}{12}+\frac{13}{12}\\=\frac{-32+13}{12}\\=\frac{-19}{12}\)
4. \(-\left(\frac{-5}{-3}\right)+\left(\frac{14}{3}\right)\\= \frac{-5}{3}+\frac{14}{3}\\=\frac{-5+14}{3}\\=\frac{9}{3}\\=\frac{3}{1}\)
5. \(+\left(\frac{11}{8}\right)-\left(\frac{-11}{2}\right)\\= \frac{11}{8}+\frac{11}{2}\\=\frac{11+11}{8}\\=\frac{22}{8}\\=\frac{11}{4}\)
6. \(-\left(\frac{-6}{5}\right)-\left(\frac{-2}{3}\right)\\= \frac{6}{5}+\frac{2}{3}\\=\frac{18}{15}+\frac{10}{15}\\=\frac{18+10}{15}\\=\frac{28}{15}\)
7. \(-\left(\frac{10}{7}\right)+\left(\frac{14}{-11}\right)\\= \frac{-10}{7}-\frac{14}{11}\\=\frac{-110}{77}-\frac{98}{77}\\=\frac{-110-98}{77}\\=\frac{-208}{77}\)
8. \(-\left(\frac{14}{13}\right)-\left(\frac{11}{-7}\right)\\= \frac{-14}{13}+\frac{11}{7}\\=\frac{-98}{91}+\frac{143}{91}\\=\frac{-98+143}{91}\\=\frac{45}{91}\)
9. \(-\left(\frac{-12}{11}\right)-\left(\frac{-4}{-13}\right)\\= \frac{12}{11}-\frac{4}{13}\\=\frac{156}{143}-\frac{44}{143}\\=\frac{156-44}{143}\\=\frac{112}{143}\)
10. \(-\left(\frac{8}{-11}\right)-\left(\frac{11}{-3}\right)\\= \frac{8}{11}+\frac{11}{3}\\=\frac{24}{33}+\frac{121}{33}\\=\frac{24+121}{33}\\=\frac{145}{33}\)
11. \(-\left(\frac{11}{-13}\right)+\left(\frac{2}{-7}\right)\\= \frac{11}{13}-\frac{2}{7}\\=\frac{77}{91}-\frac{26}{91}\\=\frac{77-26}{91}\\=\frac{51}{91}\)
12. \(+\left(\frac{6}{-11}\right)+\left(\frac{-4}{-9}\right)\\= \frac{-6}{11}+\frac{4}{9}\\=\frac{-54}{99}+\frac{44}{99}\\=\frac{-54+44}{99}\\=\frac{-10}{99}\)