Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{13}{-5}\right)+\left(\frac{12}{5}\right)\)
2. \(-\left(\frac{6}{11}\right)+\left(\frac{4}{-13}\right)\)
3. \(+\left(\frac{15}{7}\right)+\left(\frac{-7}{10}\right)\)
4. \(+\left(\frac{3}{-4}\right)-\left(\frac{15}{-7}\right)\)
5. \(+\left(\frac{3}{10}\right)-\left(\frac{9}{14}\right)\)
6. \(+\left(\frac{9}{4}\right)+\left(\frac{8}{-5}\right)\)
7. \(-\left(\frac{-2}{-5}\right)+\left(\frac{-6}{5}\right)\)
8. \(+\left(\frac{3}{7}\right)+\left(\frac{-6}{5}\right)\)
9. \(+\left(\frac{12}{7}\right)-\left(\frac{4}{-5}\right)\)
10. \(-\left(\frac{-5}{-6}\right)-\left(\frac{-10}{-7}\right)\)
11. \(-\left(\frac{8}{-3}\right)+\left(\frac{4}{3}\right)\)
12. \(+\left(\frac{3}{8}\right)-\left(\frac{-12}{5}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{13}{-5}\right)+\left(\frac{12}{5}\right)\\= \frac{-13}{5}+\frac{12}{5}\\=\frac{-13+12}{5}\\=\frac{-1}{5}\)
2. \(-\left(\frac{6}{11}\right)+\left(\frac{4}{-13}\right)\\= \frac{-6}{11}-\frac{4}{13}\\=\frac{-78}{143}-\frac{44}{143}\\=\frac{-78-44}{143}\\=\frac{-122}{143}\)
3. \(+\left(\frac{15}{7}\right)+\left(\frac{-7}{10}\right)\\= \frac{15}{7}-\frac{7}{10}\\=\frac{150}{70}-\frac{49}{70}\\=\frac{150-49}{70}\\=\frac{101}{70}\)
4. \(+\left(\frac{3}{-4}\right)-\left(\frac{15}{-7}\right)\\= \frac{-3}{4}+\frac{15}{7}\\=\frac{-21}{28}+\frac{60}{28}\\=\frac{-21+60}{28}\\=\frac{39}{28}\)
5. \(+\left(\frac{3}{10}\right)-\left(\frac{9}{14}\right)\\= \frac{3}{10}-\frac{9}{14}\\=\frac{21}{70}-\frac{45}{70}\\=\frac{21-45}{70}\\=\frac{-24}{70}\\=\frac{-12}{35}\)
6. \(+\left(\frac{9}{4}\right)+\left(\frac{8}{-5}\right)\\= \frac{9}{4}-\frac{8}{5}\\=\frac{45}{20}-\frac{32}{20}\\=\frac{45-32}{20}\\=\frac{13}{20}\)
7. \(-\left(\frac{-2}{-5}\right)+\left(\frac{-6}{5}\right)\\= \frac{-2}{5}-\frac{6}{5}\\=\frac{-2-6}{5}\\=\frac{-8}{5}\)
8. \(+\left(\frac{3}{7}\right)+\left(\frac{-6}{5}\right)\\= \frac{3}{7}-\frac{6}{5}\\=\frac{15}{35}-\frac{42}{35}\\=\frac{15-42}{35}\\=\frac{-27}{35}\)
9. \(+\left(\frac{12}{7}\right)-\left(\frac{4}{-5}\right)\\= \frac{12}{7}+\frac{4}{5}\\=\frac{60}{35}+\frac{28}{35}\\=\frac{60+28}{35}\\=\frac{88}{35}\)
10. \(-\left(\frac{-5}{-6}\right)-\left(\frac{-10}{-7}\right)\\= \frac{-5}{6}-\frac{10}{7}\\=\frac{-35}{42}-\frac{60}{42}\\=\frac{-35-60}{42}\\=\frac{-95}{42}\)
11. \(-\left(\frac{8}{-3}\right)+\left(\frac{4}{3}\right)\\= \frac{8}{3}+\frac{4}{3}\\=\frac{8+4}{3}\\=\frac{12}{3}\\=\frac{4}{1}\)
12. \(+\left(\frac{3}{8}\right)-\left(\frac{-12}{5}\right)\\= \frac{3}{8}+\frac{12}{5}\\=\frac{15}{40}+\frac{96}{40}\\=\frac{15+96}{40}\\=\frac{111}{40}\)