Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{3}{-7}\right)+\left(\frac{-10}{-13}\right)\)
2. \(+\left(\frac{-14}{5}\right)-\left(\frac{11}{-10}\right)\)
3. \(-\left(\frac{3}{-10}\right)+\left(\frac{9}{4}\right)\)
4. \(-\left(\frac{-2}{3}\right)-\left(\frac{8}{11}\right)\)
5. \(+\left(\frac{-15}{-2}\right)+\left(\frac{6}{-5}\right)\)
6. \(+\left(\frac{5}{-11}\right)+\left(\frac{-8}{-3}\right)\)
7. \(-\left(\frac{-14}{9}\right)+\left(\frac{-11}{-2}\right)\)
8. \(-\left(\frac{12}{5}\right)+\left(\frac{-3}{-13}\right)\)
9. \(+\left(\frac{3}{14}\right)-\left(\frac{10}{3}\right)\)
10. \(+\left(\frac{-9}{5}\right)+\left(\frac{8}{-7}\right)\)
11. \(+\left(\frac{13}{-2}\right)+\left(\frac{-10}{11}\right)\)
12. \(+\left(\frac{-4}{-5}\right)+\left(\frac{5}{3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{3}{-7}\right)+\left(\frac{-10}{-13}\right)\\= \frac{3}{7}+\frac{10}{13}\\=\frac{39}{91}+\frac{70}{91}\\=\frac{39+70}{91}\\=\frac{109}{91}\)
2. \(+\left(\frac{-14}{5}\right)-\left(\frac{11}{-10}\right)\\= \frac{-14}{5}+\frac{11}{10}\\=\frac{-28}{10}+\frac{11}{10}\\=\frac{-28+11}{10}\\=\frac{-17}{10}\)
3. \(-\left(\frac{3}{-10}\right)+\left(\frac{9}{4}\right)\\= \frac{3}{10}+\frac{9}{4}\\=\frac{6}{20}+\frac{45}{20}\\=\frac{6+45}{20}\\=\frac{51}{20}\)
4. \(-\left(\frac{-2}{3}\right)-\left(\frac{8}{11}\right)\\= \frac{2}{3}-\frac{8}{11}\\=\frac{22}{33}-\frac{24}{33}\\=\frac{22-24}{33}\\=\frac{-2}{33}\)
5. \(+\left(\frac{-15}{-2}\right)+\left(\frac{6}{-5}\right)\\= \frac{15}{2}-\frac{6}{5}\\=\frac{75}{10}-\frac{12}{10}\\=\frac{75-12}{10}\\=\frac{63}{10}\)
6. \(+\left(\frac{5}{-11}\right)+\left(\frac{-8}{-3}\right)\\= \frac{-5}{11}+\frac{8}{3}\\=\frac{-15}{33}+\frac{88}{33}\\=\frac{-15+88}{33}\\=\frac{73}{33}\)
7. \(-\left(\frac{-14}{9}\right)+\left(\frac{-11}{-2}\right)\\= \frac{14}{9}+\frac{11}{2}\\=\frac{28}{18}+\frac{99}{18}\\=\frac{28+99}{18}\\=\frac{127}{18}\)
8. \(-\left(\frac{12}{5}\right)+\left(\frac{-3}{-13}\right)\\= \frac{-12}{5}+\frac{3}{13}\\=\frac{-156}{65}+\frac{15}{65}\\=\frac{-156+15}{65}\\=\frac{-141}{65}\)
9. \(+\left(\frac{3}{14}\right)-\left(\frac{10}{3}\right)\\= \frac{3}{14}-\frac{10}{3}\\=\frac{9}{42}-\frac{140}{42}\\=\frac{9-140}{42}\\=\frac{-131}{42}\)
10. \(+\left(\frac{-9}{5}\right)+\left(\frac{8}{-7}\right)\\= \frac{-9}{5}-\frac{8}{7}\\=\frac{-63}{35}-\frac{40}{35}\\=\frac{-63-40}{35}\\=\frac{-103}{35}\)
11. \(+\left(\frac{13}{-2}\right)+\left(\frac{-10}{11}\right)\\= \frac{-13}{2}-\frac{10}{11}\\=\frac{-143}{22}-\frac{20}{22}\\=\frac{-143-20}{22}\\=\frac{-163}{22}\)
12. \(+\left(\frac{-4}{-5}\right)+\left(\frac{5}{3}\right)\\= \frac{4}{5}+\frac{5}{3}\\=\frac{12}{15}+\frac{25}{15}\\=\frac{12+25}{15}\\=\frac{37}{15}\)