Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-3}{2}\right)-\left(\frac{-10}{-13}\right)\)
2. \(+\left(\frac{14}{11}\right)-\left(\frac{14}{3}\right)\)
3. \(-\left(\frac{8}{-7}\right)+\left(\frac{-12}{13}\right)\)
4. \(+\left(\frac{12}{-7}\right)-\left(\frac{-10}{13}\right)\)
5. \(-\left(\frac{-9}{-13}\right)+\left(\frac{-6}{5}\right)\)
6. \(-\left(\frac{-9}{11}\right)-\left(\frac{-13}{-10}\right)\)
7. \(-\left(\frac{-5}{13}\right)-\left(\frac{-3}{11}\right)\)
8. \(+\left(\frac{5}{11}\right)+\left(\frac{6}{11}\right)\)
9. \(+\left(\frac{-7}{-12}\right)+\left(\frac{-11}{-13}\right)\)
10. \(+\left(\frac{5}{-11}\right)+\left(\frac{-4}{-7}\right)\)
11. \(+\left(\frac{11}{10}\right)+\left(\frac{14}{9}\right)\)
12. \(+\left(\frac{-4}{13}\right)-\left(\frac{-8}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-3}{2}\right)-\left(\frac{-10}{-13}\right)\\= \frac{-3}{2}-\frac{10}{13}\\=\frac{-39}{26}-\frac{20}{26}\\=\frac{-39-20}{26}\\=\frac{-59}{26}\)
2. \(+\left(\frac{14}{11}\right)-\left(\frac{14}{3}\right)\\= \frac{14}{11}-\frac{14}{3}\\=\frac{42}{33}-\frac{154}{33}\\=\frac{42-154}{33}\\=\frac{-112}{33}\)
3. \(-\left(\frac{8}{-7}\right)+\left(\frac{-12}{13}\right)\\= \frac{8}{7}-\frac{12}{13}\\=\frac{104}{91}-\frac{84}{91}\\=\frac{104-84}{91}\\=\frac{20}{91}\)
4. \(+\left(\frac{12}{-7}\right)-\left(\frac{-10}{13}\right)\\= \frac{-12}{7}+\frac{10}{13}\\=\frac{-156}{91}+\frac{70}{91}\\=\frac{-156+70}{91}\\=\frac{-86}{91}\)
5. \(-\left(\frac{-9}{-13}\right)+\left(\frac{-6}{5}\right)\\= \frac{-9}{13}-\frac{6}{5}\\=\frac{-45}{65}-\frac{78}{65}\\=\frac{-45-78}{65}\\=\frac{-123}{65}\)
6. \(-\left(\frac{-9}{11}\right)-\left(\frac{-13}{-10}\right)\\= \frac{9}{11}-\frac{13}{10}\\=\frac{90}{110}-\frac{143}{110}\\=\frac{90-143}{110}\\=\frac{-53}{110}\)
7. \(-\left(\frac{-5}{13}\right)-\left(\frac{-3}{11}\right)\\= \frac{5}{13}+\frac{3}{11}\\=\frac{55}{143}+\frac{39}{143}\\=\frac{55+39}{143}\\=\frac{94}{143}\)
8. \(+\left(\frac{5}{11}\right)+\left(\frac{6}{11}\right)\\= \frac{5}{11}+\frac{6}{11}\\=\frac{5+6}{11}\\=\frac{11}{11}\\=\frac{1}{1}\)
9. \(+\left(\frac{-7}{-12}\right)+\left(\frac{-11}{-13}\right)\\= \frac{7}{12}+\frac{11}{13}\\=\frac{91}{156}+\frac{132}{156}\\=\frac{91+132}{156}\\=\frac{223}{156}\)
10. \(+\left(\frac{5}{-11}\right)+\left(\frac{-4}{-7}\right)\\= \frac{-5}{11}+\frac{4}{7}\\=\frac{-35}{77}+\frac{44}{77}\\=\frac{-35+44}{77}\\=\frac{9}{77}\)
11. \(+\left(\frac{11}{10}\right)+\left(\frac{14}{9}\right)\\= \frac{11}{10}+\frac{14}{9}\\=\frac{99}{90}+\frac{140}{90}\\=\frac{99+140}{90}\\=\frac{239}{90}\)
12. \(+\left(\frac{-4}{13}\right)-\left(\frac{-8}{-5}\right)\\= \frac{-4}{13}-\frac{8}{5}\\=\frac{-20}{65}-\frac{104}{65}\\=\frac{-20-104}{65}\\=\frac{-124}{65}\)