Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{10}{9}\right)-\left(\frac{-2}{13}\right)\)
2. \(+\left(\frac{-12}{13}\right)-\left(\frac{-7}{8}\right)\)
3. \(-\left(\frac{-14}{5}\right)+\left(\frac{-7}{-11}\right)\)
4. \(-\left(\frac{8}{13}\right)-\left(\frac{-6}{7}\right)\)
5. \(+\left(\frac{10}{7}\right)-\left(\frac{-3}{4}\right)\)
6. \(+\left(\frac{11}{3}\right)+\left(\frac{-4}{-9}\right)\)
7. \(+\left(\frac{10}{-3}\right)+\left(\frac{14}{9}\right)\)
8. \(-\left(\frac{-8}{-13}\right)-\left(\frac{4}{-3}\right)\)
9. \(-\left(\frac{5}{-11}\right)+\left(\frac{-3}{11}\right)\)
10. \(+\left(\frac{7}{-4}\right)-\left(\frac{15}{-2}\right)\)
11. \(+\left(\frac{-13}{-7}\right)+\left(\frac{-10}{-9}\right)\)
12. \(-\left(\frac{-2}{9}\right)+\left(\frac{11}{8}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{10}{9}\right)-\left(\frac{-2}{13}\right)\\= \frac{-10}{9}+\frac{2}{13}\\=\frac{-130}{117}+\frac{18}{117}\\=\frac{-130+18}{117}\\=\frac{-112}{117}\)
2. \(+\left(\frac{-12}{13}\right)-\left(\frac{-7}{8}\right)\\= \frac{-12}{13}+\frac{7}{8}\\=\frac{-96}{104}+\frac{91}{104}\\=\frac{-96+91}{104}\\=\frac{-5}{104}\)
3. \(-\left(\frac{-14}{5}\right)+\left(\frac{-7}{-11}\right)\\= \frac{14}{5}+\frac{7}{11}\\=\frac{154}{55}+\frac{35}{55}\\=\frac{154+35}{55}\\=\frac{189}{55}\)
4. \(-\left(\frac{8}{13}\right)-\left(\frac{-6}{7}\right)\\= \frac{-8}{13}+\frac{6}{7}\\=\frac{-56}{91}+\frac{78}{91}\\=\frac{-56+78}{91}\\=\frac{22}{91}\)
5. \(+\left(\frac{10}{7}\right)-\left(\frac{-3}{4}\right)\\= \frac{10}{7}+\frac{3}{4}\\=\frac{40}{28}+\frac{21}{28}\\=\frac{40+21}{28}\\=\frac{61}{28}\)
6. \(+\left(\frac{11}{3}\right)+\left(\frac{-4}{-9}\right)\\= \frac{11}{3}+\frac{4}{9}\\=\frac{33}{9}+\frac{4}{9}\\=\frac{33+4}{9}\\=\frac{37}{9}\)
7. \(+\left(\frac{10}{-3}\right)+\left(\frac{14}{9}\right)\\= \frac{-10}{3}+\frac{14}{9}\\=\frac{-30}{9}+\frac{14}{9}\\=\frac{-30+14}{9}\\=\frac{-16}{9}\)
8. \(-\left(\frac{-8}{-13}\right)-\left(\frac{4}{-3}\right)\\= \frac{-8}{13}+\frac{4}{3}\\=\frac{-24}{39}+\frac{52}{39}\\=\frac{-24+52}{39}\\=\frac{28}{39}\)
9. \(-\left(\frac{5}{-11}\right)+\left(\frac{-3}{11}\right)\\= \frac{5}{11}-\frac{3}{11}\\=\frac{5-3}{11}\\=\frac{2}{11}\)
10. \(+\left(\frac{7}{-4}\right)-\left(\frac{15}{-2}\right)\\= \frac{-7}{4}+\frac{15}{2}\\=\frac{-7+15}{4}\\=\frac{8}{4}\\=\frac{2}{1}\)
11. \(+\left(\frac{-13}{-7}\right)+\left(\frac{-10}{-9}\right)\\= \frac{13}{7}+\frac{10}{9}\\=\frac{117}{63}+\frac{70}{63}\\=\frac{117+70}{63}\\=\frac{187}{63}\)
12. \(-\left(\frac{-2}{9}\right)+\left(\frac{11}{8}\right)\\= \frac{2}{9}+\frac{11}{8}\\=\frac{16}{72}+\frac{99}{72}\\=\frac{16+99}{72}\\=\frac{115}{72}\)