Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-7}{3}\right)+\left(\frac{-4}{7}\right)\)
2. \(-\left(\frac{-8}{-3}\right)-\left(\frac{2}{-7}\right)\)
3. \(+\left(\frac{-4}{9}\right)+\left(\frac{7}{-4}\right)\)
4. \(-\left(\frac{-5}{-14}\right)+\left(\frac{-9}{13}\right)\)
5. \(-\left(\frac{-13}{-10}\right)-\left(\frac{-6}{7}\right)\)
6. \(+\left(\frac{-3}{-4}\right)-\left(\frac{10}{9}\right)\)
7. \(+\left(\frac{-13}{2}\right)-\left(\frac{-14}{-3}\right)\)
8. \(-\left(\frac{-10}{3}\right)+\left(\frac{-11}{-13}\right)\)
9. \(+\left(\frac{-10}{-7}\right)+\left(\frac{-9}{-11}\right)\)
10. \(+\left(\frac{3}{-7}\right)-\left(\frac{12}{-11}\right)\)
11. \(+\left(\frac{-4}{7}\right)-\left(\frac{10}{-9}\right)\)
12. \(+\left(\frac{8}{-13}\right)+\left(\frac{5}{4}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-7}{3}\right)+\left(\frac{-4}{7}\right)\\= \frac{-7}{3}-\frac{4}{7}\\=\frac{-49}{21}-\frac{12}{21}\\=\frac{-49-12}{21}\\=\frac{-61}{21}\)
2. \(-\left(\frac{-8}{-3}\right)-\left(\frac{2}{-7}\right)\\= \frac{-8}{3}+\frac{2}{7}\\=\frac{-56}{21}+\frac{6}{21}\\=\frac{-56+6}{21}\\=\frac{-50}{21}\)
3. \(+\left(\frac{-4}{9}\right)+\left(\frac{7}{-4}\right)\\= \frac{-4}{9}-\frac{7}{4}\\=\frac{-16}{36}-\frac{63}{36}\\=\frac{-16-63}{36}\\=\frac{-79}{36}\)
4. \(-\left(\frac{-5}{-14}\right)+\left(\frac{-9}{13}\right)\\= \frac{-5}{14}-\frac{9}{13}\\=\frac{-65}{182}-\frac{126}{182}\\=\frac{-65-126}{182}\\=\frac{-191}{182}\)
5. \(-\left(\frac{-13}{-10}\right)-\left(\frac{-6}{7}\right)\\= \frac{-13}{10}+\frac{6}{7}\\=\frac{-91}{70}+\frac{60}{70}\\=\frac{-91+60}{70}\\=\frac{-31}{70}\)
6. \(+\left(\frac{-3}{-4}\right)-\left(\frac{10}{9}\right)\\= \frac{3}{4}-\frac{10}{9}\\=\frac{27}{36}-\frac{40}{36}\\=\frac{27-40}{36}\\=\frac{-13}{36}\)
7. \(+\left(\frac{-13}{2}\right)-\left(\frac{-14}{-3}\right)\\= \frac{-13}{2}-\frac{14}{3}\\=\frac{-39}{6}-\frac{28}{6}\\=\frac{-39-28}{6}\\=\frac{-67}{6}\)
8. \(-\left(\frac{-10}{3}\right)+\left(\frac{-11}{-13}\right)\\= \frac{10}{3}+\frac{11}{13}\\=\frac{130}{39}+\frac{33}{39}\\=\frac{130+33}{39}\\=\frac{163}{39}\)
9. \(+\left(\frac{-10}{-7}\right)+\left(\frac{-9}{-11}\right)\\= \frac{10}{7}+\frac{9}{11}\\=\frac{110}{77}+\frac{63}{77}\\=\frac{110+63}{77}\\=\frac{173}{77}\)
10. \(+\left(\frac{3}{-7}\right)-\left(\frac{12}{-11}\right)\\= \frac{-3}{7}+\frac{12}{11}\\=\frac{-33}{77}+\frac{84}{77}\\=\frac{-33+84}{77}\\=\frac{51}{77}\)
11. \(+\left(\frac{-4}{7}\right)-\left(\frac{10}{-9}\right)\\= \frac{-4}{7}+\frac{10}{9}\\=\frac{-36}{63}+\frac{70}{63}\\=\frac{-36+70}{63}\\=\frac{34}{63}\)
12. \(+\left(\frac{8}{-13}\right)+\left(\frac{5}{4}\right)\\= \frac{-8}{13}+\frac{5}{4}\\=\frac{-32}{52}+\frac{65}{52}\\=\frac{-32+65}{52}\\=\frac{33}{52}\)