Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{8}{-13}\right)-\left(\frac{6}{-5}\right)\)
2. \(+\left(\frac{5}{11}\right)+\left(\frac{10}{-7}\right)\)
3. \(+\left(\frac{13}{-14}\right)-\left(\frac{12}{-13}\right)\)
4. \(-\left(\frac{-12}{-5}\right)+\left(\frac{-3}{-4}\right)\)
5. \(-\left(\frac{-10}{11}\right)-\left(\frac{-9}{-2}\right)\)
6. \(-\left(\frac{-8}{3}\right)+\left(\frac{-11}{14}\right)\)
7. \(-\left(\frac{7}{-2}\right)+\left(\frac{-8}{-13}\right)\)
8. \(+\left(\frac{-3}{-7}\right)-\left(\frac{4}{-5}\right)\)
9. \(-\left(\frac{15}{2}\right)-\left(\frac{12}{5}\right)\)
10. \(-\left(\frac{-5}{6}\right)+\left(\frac{10}{-7}\right)\)
11. \(-\left(\frac{10}{11}\right)-\left(\frac{-7}{9}\right)\)
12. \(+\left(\frac{-4}{-3}\right)+\left(\frac{-8}{9}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{8}{-13}\right)-\left(\frac{6}{-5}\right)\\= \frac{8}{13}+\frac{6}{5}\\=\frac{40}{65}+\frac{78}{65}\\=\frac{40+78}{65}\\=\frac{118}{65}\)
2. \(+\left(\frac{5}{11}\right)+\left(\frac{10}{-7}\right)\\= \frac{5}{11}-\frac{10}{7}\\=\frac{35}{77}-\frac{110}{77}\\=\frac{35-110}{77}\\=\frac{-75}{77}\)
3. \(+\left(\frac{13}{-14}\right)-\left(\frac{12}{-13}\right)\\= \frac{-13}{14}+\frac{12}{13}\\=\frac{-169}{182}+\frac{168}{182}\\=\frac{-169+168}{182}\\=\frac{-1}{182}\)
4. \(-\left(\frac{-12}{-5}\right)+\left(\frac{-3}{-4}\right)\\= \frac{-12}{5}+\frac{3}{4}\\=\frac{-48}{20}+\frac{15}{20}\\=\frac{-48+15}{20}\\=\frac{-33}{20}\)
5. \(-\left(\frac{-10}{11}\right)-\left(\frac{-9}{-2}\right)\\= \frac{10}{11}-\frac{9}{2}\\=\frac{20}{22}-\frac{99}{22}\\=\frac{20-99}{22}\\=\frac{-79}{22}\)
6. \(-\left(\frac{-8}{3}\right)+\left(\frac{-11}{14}\right)\\= \frac{8}{3}-\frac{11}{14}\\=\frac{112}{42}-\frac{33}{42}\\=\frac{112-33}{42}\\=\frac{79}{42}\)
7. \(-\left(\frac{7}{-2}\right)+\left(\frac{-8}{-13}\right)\\= \frac{7}{2}+\frac{8}{13}\\=\frac{91}{26}+\frac{16}{26}\\=\frac{91+16}{26}\\=\frac{107}{26}\)
8. \(+\left(\frac{-3}{-7}\right)-\left(\frac{4}{-5}\right)\\= \frac{3}{7}+\frac{4}{5}\\=\frac{15}{35}+\frac{28}{35}\\=\frac{15+28}{35}\\=\frac{43}{35}\)
9. \(-\left(\frac{15}{2}\right)-\left(\frac{12}{5}\right)\\= \frac{-15}{2}-\frac{12}{5}\\=\frac{-75}{10}-\frac{24}{10}\\=\frac{-75-24}{10}\\=\frac{-99}{10}\)
10. \(-\left(\frac{-5}{6}\right)+\left(\frac{10}{-7}\right)\\= \frac{5}{6}-\frac{10}{7}\\=\frac{35}{42}-\frac{60}{42}\\=\frac{35-60}{42}\\=\frac{-25}{42}\)
11. \(-\left(\frac{10}{11}\right)-\left(\frac{-7}{9}\right)\\= \frac{-10}{11}+\frac{7}{9}\\=\frac{-90}{99}+\frac{77}{99}\\=\frac{-90+77}{99}\\=\frac{-13}{99}\)
12. \(+\left(\frac{-4}{-3}\right)+\left(\frac{-8}{9}\right)\\= \frac{4}{3}-\frac{8}{9}\\=\frac{12}{9}-\frac{8}{9}\\=\frac{12-8}{9}\\=\frac{4}{9}\)