Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-7}{9}\right)+\left(\frac{-9}{-10}\right)\)
2. \(-\left(\frac{-13}{-2}\right)-\left(\frac{5}{-3}\right)\)
3. \(-\left(\frac{-9}{8}\right)-\left(\frac{-2}{-7}\right)\)
4. \(+\left(\frac{10}{-3}\right)+\left(\frac{10}{3}\right)\)
5. \(+\left(\frac{15}{11}\right)+\left(\frac{14}{-3}\right)\)
6. \(-\left(\frac{-7}{4}\right)+\left(\frac{10}{9}\right)\)
7. \(-\left(\frac{8}{-7}\right)+\left(\frac{10}{-11}\right)\)
8. \(+\left(\frac{15}{-13}\right)-\left(\frac{-3}{10}\right)\)
9. \(-\left(\frac{3}{2}\right)-\left(\frac{6}{-5}\right)\)
10. \(-\left(\frac{-13}{14}\right)-\left(\frac{-2}{-3}\right)\)
11. \(-\left(\frac{15}{-11}\right)+\left(\frac{-10}{9}\right)\)
12. \(-\left(\frac{7}{5}\right)+\left(\frac{-11}{-14}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-7}{9}\right)+\left(\frac{-9}{-10}\right)\\= \frac{-7}{9}+\frac{9}{10}\\=\frac{-70}{90}+\frac{81}{90}\\=\frac{-70+81}{90}\\=\frac{11}{90}\)
2. \(-\left(\frac{-13}{-2}\right)-\left(\frac{5}{-3}\right)\\= \frac{-13}{2}+\frac{5}{3}\\=\frac{-39}{6}+\frac{10}{6}\\=\frac{-39+10}{6}\\=\frac{-29}{6}\)
3. \(-\left(\frac{-9}{8}\right)-\left(\frac{-2}{-7}\right)\\= \frac{9}{8}-\frac{2}{7}\\=\frac{63}{56}-\frac{16}{56}\\=\frac{63-16}{56}\\=\frac{47}{56}\)
4. \(+\left(\frac{10}{-3}\right)+\left(\frac{10}{3}\right)\\= \frac{-10}{3}+\frac{10}{3}\\=\frac{-10+10}{3}\\=\frac{0}{3}\\=\frac{0}{1}\)
5. \(+\left(\frac{15}{11}\right)+\left(\frac{14}{-3}\right)\\= \frac{15}{11}-\frac{14}{3}\\=\frac{45}{33}-\frac{154}{33}\\=\frac{45-154}{33}\\=\frac{-109}{33}\)
6. \(-\left(\frac{-7}{4}\right)+\left(\frac{10}{9}\right)\\= \frac{7}{4}+\frac{10}{9}\\=\frac{63}{36}+\frac{40}{36}\\=\frac{63+40}{36}\\=\frac{103}{36}\)
7. \(-\left(\frac{8}{-7}\right)+\left(\frac{10}{-11}\right)\\= \frac{8}{7}-\frac{10}{11}\\=\frac{88}{77}-\frac{70}{77}\\=\frac{88-70}{77}\\=\frac{18}{77}\)
8. \(+\left(\frac{15}{-13}\right)-\left(\frac{-3}{10}\right)\\= \frac{-15}{13}+\frac{3}{10}\\=\frac{-150}{130}+\frac{39}{130}\\=\frac{-150+39}{130}\\=\frac{-111}{130}\)
9. \(-\left(\frac{3}{2}\right)-\left(\frac{6}{-5}\right)\\= \frac{-3}{2}+\frac{6}{5}\\=\frac{-15}{10}+\frac{12}{10}\\=\frac{-15+12}{10}\\=\frac{-3}{10}\)
10. \(-\left(\frac{-13}{14}\right)-\left(\frac{-2}{-3}\right)\\= \frac{13}{14}-\frac{2}{3}\\=\frac{39}{42}-\frac{28}{42}\\=\frac{39-28}{42}\\=\frac{11}{42}\)
11. \(-\left(\frac{15}{-11}\right)+\left(\frac{-10}{9}\right)\\= \frac{15}{11}-\frac{10}{9}\\=\frac{135}{99}-\frac{110}{99}\\=\frac{135-110}{99}\\=\frac{25}{99}\)
12. \(-\left(\frac{7}{5}\right)+\left(\frac{-11}{-14}\right)\\= \frac{-7}{5}+\frac{11}{14}\\=\frac{-98}{70}+\frac{55}{70}\\=\frac{-98+55}{70}\\=\frac{-43}{70}\)