Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{12}{11}\right)-\left(\frac{10}{-3}\right)\)
2. \(+\left(\frac{-6}{-5}\right)+\left(\frac{11}{-2}\right)\)
3. \(-\left(\frac{3}{-8}\right)+\left(\frac{-14}{9}\right)\)
4. \(-\left(\frac{4}{-7}\right)-\left(\frac{6}{-11}\right)\)
5. \(-\left(\frac{-4}{-9}\right)-\left(\frac{-2}{7}\right)\)
6. \(+\left(\frac{9}{-4}\right)-\left(\frac{-12}{7}\right)\)
7. \(+\left(\frac{-11}{5}\right)-\left(\frac{-2}{3}\right)\)
8. \(-\left(\frac{8}{3}\right)-\left(\frac{8}{-3}\right)\)
9. \(+\left(\frac{-13}{7}\right)+\left(\frac{-15}{-11}\right)\)
10. \(+\left(\frac{-13}{-10}\right)-\left(\frac{11}{-5}\right)\)
11. \(-\left(\frac{14}{3}\right)-\left(\frac{-13}{14}\right)\)
12. \(-\left(\frac{-8}{3}\right)+\left(\frac{12}{13}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{12}{11}\right)-\left(\frac{10}{-3}\right)\\= \frac{12}{11}+\frac{10}{3}\\=\frac{36}{33}+\frac{110}{33}\\=\frac{36+110}{33}\\=\frac{146}{33}\)
2. \(+\left(\frac{-6}{-5}\right)+\left(\frac{11}{-2}\right)\\= \frac{6}{5}-\frac{11}{2}\\=\frac{12}{10}-\frac{55}{10}\\=\frac{12-55}{10}\\=\frac{-43}{10}\)
3. \(-\left(\frac{3}{-8}\right)+\left(\frac{-14}{9}\right)\\= \frac{3}{8}-\frac{14}{9}\\=\frac{27}{72}-\frac{112}{72}\\=\frac{27-112}{72}\\=\frac{-85}{72}\)
4. \(-\left(\frac{4}{-7}\right)-\left(\frac{6}{-11}\right)\\= \frac{4}{7}+\frac{6}{11}\\=\frac{44}{77}+\frac{42}{77}\\=\frac{44+42}{77}\\=\frac{86}{77}\)
5. \(-\left(\frac{-4}{-9}\right)-\left(\frac{-2}{7}\right)\\= \frac{-4}{9}+\frac{2}{7}\\=\frac{-28}{63}+\frac{18}{63}\\=\frac{-28+18}{63}\\=\frac{-10}{63}\)
6. \(+\left(\frac{9}{-4}\right)-\left(\frac{-12}{7}\right)\\= \frac{-9}{4}+\frac{12}{7}\\=\frac{-63}{28}+\frac{48}{28}\\=\frac{-63+48}{28}\\=\frac{-15}{28}\)
7. \(+\left(\frac{-11}{5}\right)-\left(\frac{-2}{3}\right)\\= \frac{-11}{5}+\frac{2}{3}\\=\frac{-33}{15}+\frac{10}{15}\\=\frac{-33+10}{15}\\=\frac{-23}{15}\)
8. \(-\left(\frac{8}{3}\right)-\left(\frac{8}{-3}\right)\\= \frac{-8}{3}+\frac{8}{3}\\=\frac{-8+8}{3}\\=\frac{0}{3}\\=\frac{0}{1}\)
9. \(+\left(\frac{-13}{7}\right)+\left(\frac{-15}{-11}\right)\\= \frac{-13}{7}+\frac{15}{11}\\=\frac{-143}{77}+\frac{105}{77}\\=\frac{-143+105}{77}\\=\frac{-38}{77}\)
10. \(+\left(\frac{-13}{-10}\right)-\left(\frac{11}{-5}\right)\\= \frac{13}{10}+\frac{11}{5}\\=\frac{13+11}{10}\\=\frac{24}{10}\\=\frac{12}{5}\)
11. \(-\left(\frac{14}{3}\right)-\left(\frac{-13}{14}\right)\\= \frac{-14}{3}+\frac{13}{14}\\=\frac{-196}{42}+\frac{39}{42}\\=\frac{-196+39}{42}\\=\frac{-157}{42}\)
12. \(-\left(\frac{-8}{3}\right)+\left(\frac{12}{13}\right)\\= \frac{8}{3}+\frac{12}{13}\\=\frac{104}{39}+\frac{36}{39}\\=\frac{104+36}{39}\\=\frac{140}{39}\)