Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{3}{-10}\right)-\left(\frac{-4}{3}\right)\)
2. \(+\left(\frac{13}{-2}\right)+\left(\frac{-7}{10}\right)\)
3. \(+\left(\frac{-3}{-4}\right)+\left(\frac{-10}{7}\right)\)
4. \(+\left(\frac{-6}{5}\right)-\left(\frac{15}{-4}\right)\)
5. \(-\left(\frac{5}{8}\right)-\left(\frac{8}{11}\right)\)
6. \(-\left(\frac{-13}{5}\right)+\left(\frac{3}{10}\right)\)
7. \(+\left(\frac{-7}{3}\right)+\left(\frac{-2}{13}\right)\)
8. \(+\left(\frac{-7}{-8}\right)+\left(\frac{-12}{5}\right)\)
9. \(+\left(\frac{-9}{7}\right)+\left(\frac{-7}{2}\right)\)
10. \(-\left(\frac{-5}{-11}\right)+\left(\frac{11}{12}\right)\)
11. \(+\left(\frac{-10}{-9}\right)+\left(\frac{-5}{-6}\right)\)
12. \(+\left(\frac{-11}{-12}\right)-\left(\frac{10}{-9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{3}{-10}\right)-\left(\frac{-4}{3}\right)\\= \frac{-3}{10}+\frac{4}{3}\\=\frac{-9}{30}+\frac{40}{30}\\=\frac{-9+40}{30}\\=\frac{31}{30}\)
2. \(+\left(\frac{13}{-2}\right)+\left(\frac{-7}{10}\right)\\= \frac{-13}{2}-\frac{7}{10}\\=\frac{-65}{10}-\frac{7}{10}\\=\frac{-65-7}{10}\\=\frac{-72}{10}\\=\frac{-36}{5}\)
3. \(+\left(\frac{-3}{-4}\right)+\left(\frac{-10}{7}\right)\\= \frac{3}{4}-\frac{10}{7}\\=\frac{21}{28}-\frac{40}{28}\\=\frac{21-40}{28}\\=\frac{-19}{28}\)
4. \(+\left(\frac{-6}{5}\right)-\left(\frac{15}{-4}\right)\\= \frac{-6}{5}+\frac{15}{4}\\=\frac{-24}{20}+\frac{75}{20}\\=\frac{-24+75}{20}\\=\frac{51}{20}\)
5. \(-\left(\frac{5}{8}\right)-\left(\frac{8}{11}\right)\\= \frac{-5}{8}-\frac{8}{11}\\=\frac{-55}{88}-\frac{64}{88}\\=\frac{-55-64}{88}\\=\frac{-119}{88}\)
6. \(-\left(\frac{-13}{5}\right)+\left(\frac{3}{10}\right)\\= \frac{13}{5}+\frac{3}{10}\\=\frac{26}{10}+\frac{3}{10}\\=\frac{26+3}{10}\\=\frac{29}{10}\)
7. \(+\left(\frac{-7}{3}\right)+\left(\frac{-2}{13}\right)\\= \frac{-7}{3}-\frac{2}{13}\\=\frac{-91}{39}-\frac{6}{39}\\=\frac{-91-6}{39}\\=\frac{-97}{39}\)
8. \(+\left(\frac{-7}{-8}\right)+\left(\frac{-12}{5}\right)\\= \frac{7}{8}-\frac{12}{5}\\=\frac{35}{40}-\frac{96}{40}\\=\frac{35-96}{40}\\=\frac{-61}{40}\)
9. \(+\left(\frac{-9}{7}\right)+\left(\frac{-7}{2}\right)\\= \frac{-9}{7}-\frac{7}{2}\\=\frac{-18}{14}-\frac{49}{14}\\=\frac{-18-49}{14}\\=\frac{-67}{14}\)
10. \(-\left(\frac{-5}{-11}\right)+\left(\frac{11}{12}\right)\\= \frac{-5}{11}+\frac{11}{12}\\=\frac{-60}{132}+\frac{121}{132}\\=\frac{-60+121}{132}\\=\frac{61}{132}\)
11. \(+\left(\frac{-10}{-9}\right)+\left(\frac{-5}{-6}\right)\\= \frac{10}{9}+\frac{5}{6}\\=\frac{20}{18}+\frac{15}{18}\\=\frac{20+15}{18}\\=\frac{35}{18}\)
12. \(+\left(\frac{-11}{-12}\right)-\left(\frac{10}{-9}\right)\\= \frac{11}{12}+\frac{10}{9}\\=\frac{33}{36}+\frac{40}{36}\\=\frac{33+40}{36}\\=\frac{73}{36}\)