Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-2}{-3}\right)-\left(\frac{-3}{8}\right)\)
2. \(-\left(\frac{-8}{-11}\right)+\left(\frac{-9}{-10}\right)\)
3. \(-\left(\frac{11}{-10}\right)-\left(\frac{-7}{10}\right)\)
4. \(-\left(\frac{6}{-11}\right)-\left(\frac{-13}{-3}\right)\)
5. \(+\left(\frac{-11}{-2}\right)+\left(\frac{13}{11}\right)\)
6. \(-\left(\frac{-4}{11}\right)+\left(\frac{-9}{-13}\right)\)
7. \(-\left(\frac{-14}{-9}\right)-\left(\frac{15}{-8}\right)\)
8. \(-\left(\frac{13}{-11}\right)-\left(\frac{13}{-9}\right)\)
9. \(-\left(\frac{4}{-5}\right)+\left(\frac{8}{5}\right)\)
10. \(-\left(\frac{6}{-5}\right)+\left(\frac{2}{7}\right)\)
11. \(-\left(\frac{-11}{8}\right)+\left(\frac{15}{-7}\right)\)
12. \(-\left(\frac{-13}{-11}\right)+\left(\frac{2}{-9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-2}{-3}\right)-\left(\frac{-3}{8}\right)\\= \frac{2}{3}+\frac{3}{8}\\=\frac{16}{24}+\frac{9}{24}\\=\frac{16+9}{24}\\=\frac{25}{24}\)
2. \(-\left(\frac{-8}{-11}\right)+\left(\frac{-9}{-10}\right)\\= \frac{-8}{11}+\frac{9}{10}\\=\frac{-80}{110}+\frac{99}{110}\\=\frac{-80+99}{110}\\=\frac{19}{110}\)
3. \(-\left(\frac{11}{-10}\right)-\left(\frac{-7}{10}\right)\\= \frac{11}{10}+\frac{7}{10}\\=\frac{11+7}{10}\\=\frac{18}{10}\\=\frac{9}{5}\)
4. \(-\left(\frac{6}{-11}\right)-\left(\frac{-13}{-3}\right)\\= \frac{6}{11}-\frac{13}{3}\\=\frac{18}{33}-\frac{143}{33}\\=\frac{18-143}{33}\\=\frac{-125}{33}\)
5. \(+\left(\frac{-11}{-2}\right)+\left(\frac{13}{11}\right)\\= \frac{11}{2}+\frac{13}{11}\\=\frac{121}{22}+\frac{26}{22}\\=\frac{121+26}{22}\\=\frac{147}{22}\)
6. \(-\left(\frac{-4}{11}\right)+\left(\frac{-9}{-13}\right)\\= \frac{4}{11}+\frac{9}{13}\\=\frac{52}{143}+\frac{99}{143}\\=\frac{52+99}{143}\\=\frac{151}{143}\)
7. \(-\left(\frac{-14}{-9}\right)-\left(\frac{15}{-8}\right)\\= \frac{-14}{9}+\frac{15}{8}\\=\frac{-112}{72}+\frac{135}{72}\\=\frac{-112+135}{72}\\=\frac{23}{72}\)
8. \(-\left(\frac{13}{-11}\right)-\left(\frac{13}{-9}\right)\\= \frac{13}{11}+\frac{13}{9}\\=\frac{117}{99}+\frac{143}{99}\\=\frac{117+143}{99}\\=\frac{260}{99}\)
9. \(-\left(\frac{4}{-5}\right)+\left(\frac{8}{5}\right)\\= \frac{4}{5}+\frac{8}{5}\\=\frac{4+8}{5}\\=\frac{12}{5}\)
10. \(-\left(\frac{6}{-5}\right)+\left(\frac{2}{7}\right)\\= \frac{6}{5}+\frac{2}{7}\\=\frac{42}{35}+\frac{10}{35}\\=\frac{42+10}{35}\\=\frac{52}{35}\)
11. \(-\left(\frac{-11}{8}\right)+\left(\frac{15}{-7}\right)\\= \frac{11}{8}-\frac{15}{7}\\=\frac{77}{56}-\frac{120}{56}\\=\frac{77-120}{56}\\=\frac{-43}{56}\)
12. \(-\left(\frac{-13}{-11}\right)+\left(\frac{2}{-9}\right)\\= \frac{-13}{11}-\frac{2}{9}\\=\frac{-117}{99}-\frac{22}{99}\\=\frac{-117-22}{99}\\=\frac{-139}{99}\)