Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{13}{8}\right)+\left(\frac{2}{-3}\right)\)
2. \(-\left(\frac{-14}{-9}\right)-\left(\frac{-8}{-3}\right)\)
3. \(-\left(\frac{5}{6}\right)-\left(\frac{-9}{7}\right)\)
4. \(-\left(\frac{-9}{-13}\right)+\left(\frac{3}{7}\right)\)
5. \(+\left(\frac{-2}{5}\right)+\left(\frac{8}{5}\right)\)
6. \(+\left(\frac{6}{5}\right)+\left(\frac{3}{-13}\right)\)
7. \(+\left(\frac{12}{-5}\right)-\left(\frac{-8}{-5}\right)\)
8. \(-\left(\frac{15}{-8}\right)+\left(\frac{9}{4}\right)\)
9. \(+\left(\frac{8}{-3}\right)-\left(\frac{-12}{-13}\right)\)
10. \(+\left(\frac{9}{-8}\right)+\left(\frac{-3}{-10}\right)\)
11. \(-\left(\frac{-4}{-3}\right)+\left(\frac{-15}{2}\right)\)
12. \(+\left(\frac{-8}{13}\right)+\left(\frac{10}{7}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{13}{8}\right)+\left(\frac{2}{-3}\right)\\= \frac{13}{8}-\frac{2}{3}\\=\frac{39}{24}-\frac{16}{24}\\=\frac{39-16}{24}\\=\frac{23}{24}\)
2. \(-\left(\frac{-14}{-9}\right)-\left(\frac{-8}{-3}\right)\\= \frac{-14}{9}-\frac{8}{3}\\=\frac{-14-8}{9}\\=\frac{-22}{9}\)
3. \(-\left(\frac{5}{6}\right)-\left(\frac{-9}{7}\right)\\= \frac{-5}{6}+\frac{9}{7}\\=\frac{-35}{42}+\frac{54}{42}\\=\frac{-35+54}{42}\\=\frac{19}{42}\)
4. \(-\left(\frac{-9}{-13}\right)+\left(\frac{3}{7}\right)\\= \frac{-9}{13}+\frac{3}{7}\\=\frac{-63}{91}+\frac{39}{91}\\=\frac{-63+39}{91}\\=\frac{-24}{91}\)
5. \(+\left(\frac{-2}{5}\right)+\left(\frac{8}{5}\right)\\= \frac{-2}{5}+\frac{8}{5}\\=\frac{-2+8}{5}\\=\frac{6}{5}\)
6. \(+\left(\frac{6}{5}\right)+\left(\frac{3}{-13}\right)\\= \frac{6}{5}-\frac{3}{13}\\=\frac{78}{65}-\frac{15}{65}\\=\frac{78-15}{65}\\=\frac{63}{65}\)
7. \(+\left(\frac{12}{-5}\right)-\left(\frac{-8}{-5}\right)\\= \frac{-12}{5}-\frac{8}{5}\\=\frac{-12-8}{5}\\=\frac{-20}{5}\\=\frac{-4}{1}\)
8. \(-\left(\frac{15}{-8}\right)+\left(\frac{9}{4}\right)\\= \frac{15}{8}+\frac{9}{4}\\=\frac{15+9}{8}\\=\frac{24}{8}\\=\frac{3}{1}\)
9. \(+\left(\frac{8}{-3}\right)-\left(\frac{-12}{-13}\right)\\= \frac{-8}{3}-\frac{12}{13}\\=\frac{-104}{39}-\frac{36}{39}\\=\frac{-104-36}{39}\\=\frac{-140}{39}\)
10. \(+\left(\frac{9}{-8}\right)+\left(\frac{-3}{-10}\right)\\= \frac{-9}{8}+\frac{3}{10}\\=\frac{-45}{40}+\frac{12}{40}\\=\frac{-45+12}{40}\\=\frac{-33}{40}\)
11. \(-\left(\frac{-4}{-3}\right)+\left(\frac{-15}{2}\right)\\= \frac{-4}{3}-\frac{15}{2}\\=\frac{-8}{6}-\frac{45}{6}\\=\frac{-8-45}{6}\\=\frac{-53}{6}\)
12. \(+\left(\frac{-8}{13}\right)+\left(\frac{10}{7}\right)\\= \frac{-8}{13}+\frac{10}{7}\\=\frac{-56}{91}+\frac{130}{91}\\=\frac{-56+130}{91}\\=\frac{74}{91}\)