Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-11}{-14}\right)-\left(\frac{-4}{13}\right)\)
2. \(-\left(\frac{-14}{-13}\right)-\left(\frac{-12}{-5}\right)\)
3. \(-\left(\frac{4}{-13}\right)+\left(\frac{5}{-14}\right)\)
4. \(-\left(\frac{11}{-2}\right)-\left(\frac{-13}{-6}\right)\)
5. \(+\left(\frac{13}{-6}\right)+\left(\frac{-3}{4}\right)\)
6. \(+\left(\frac{2}{-11}\right)-\left(\frac{10}{3}\right)\)
7. \(-\left(\frac{-11}{-5}\right)+\left(\frac{14}{-3}\right)\)
8. \(-\left(\frac{15}{-13}\right)-\left(\frac{-8}{3}\right)\)
9. \(-\left(\frac{-15}{13}\right)-\left(\frac{-14}{5}\right)\)
10. \(+\left(\frac{2}{-3}\right)+\left(\frac{4}{-3}\right)\)
11. \(+\left(\frac{-2}{-11}\right)+\left(\frac{14}{11}\right)\)
12. \(+\left(\frac{-10}{3}\right)-\left(\frac{8}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-11}{-14}\right)-\left(\frac{-4}{13}\right)\\= \frac{11}{14}+\frac{4}{13}\\=\frac{143}{182}+\frac{56}{182}\\=\frac{143+56}{182}\\=\frac{199}{182}\)
2. \(-\left(\frac{-14}{-13}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-14}{13}-\frac{12}{5}\\=\frac{-70}{65}-\frac{156}{65}\\=\frac{-70-156}{65}\\=\frac{-226}{65}\)
3. \(-\left(\frac{4}{-13}\right)+\left(\frac{5}{-14}\right)\\= \frac{4}{13}-\frac{5}{14}\\=\frac{56}{182}-\frac{65}{182}\\=\frac{56-65}{182}\\=\frac{-9}{182}\)
4. \(-\left(\frac{11}{-2}\right)-\left(\frac{-13}{-6}\right)\\= \frac{11}{2}-\frac{13}{6}\\=\frac{33}{6}-\frac{13}{6}\\=\frac{33-13}{6}\\=\frac{20}{6}\\=\frac{10}{3}\)
5. \(+\left(\frac{13}{-6}\right)+\left(\frac{-3}{4}\right)\\= \frac{-13}{6}-\frac{3}{4}\\=\frac{-26}{12}-\frac{9}{12}\\=\frac{-26-9}{12}\\=\frac{-35}{12}\)
6. \(+\left(\frac{2}{-11}\right)-\left(\frac{10}{3}\right)\\= \frac{-2}{11}-\frac{10}{3}\\=\frac{-6}{33}-\frac{110}{33}\\=\frac{-6-110}{33}\\=\frac{-116}{33}\)
7. \(-\left(\frac{-11}{-5}\right)+\left(\frac{14}{-3}\right)\\= \frac{-11}{5}-\frac{14}{3}\\=\frac{-33}{15}-\frac{70}{15}\\=\frac{-33-70}{15}\\=\frac{-103}{15}\)
8. \(-\left(\frac{15}{-13}\right)-\left(\frac{-8}{3}\right)\\= \frac{15}{13}+\frac{8}{3}\\=\frac{45}{39}+\frac{104}{39}\\=\frac{45+104}{39}\\=\frac{149}{39}\)
9. \(-\left(\frac{-15}{13}\right)-\left(\frac{-14}{5}\right)\\= \frac{15}{13}+\frac{14}{5}\\=\frac{75}{65}+\frac{182}{65}\\=\frac{75+182}{65}\\=\frac{257}{65}\)
10. \(+\left(\frac{2}{-3}\right)+\left(\frac{4}{-3}\right)\\= \frac{-2}{3}-\frac{4}{3}\\=\frac{-2-4}{3}\\=\frac{-6}{3}\\=\frac{-2}{1}\)
11. \(+\left(\frac{-2}{-11}\right)+\left(\frac{14}{11}\right)\\= \frac{2}{11}+\frac{14}{11}\\=\frac{2+14}{11}\\=\frac{16}{11}\)
12. \(+\left(\frac{-10}{3}\right)-\left(\frac{8}{-5}\right)\\= \frac{-10}{3}+\frac{8}{5}\\=\frac{-50}{15}+\frac{24}{15}\\=\frac{-50+24}{15}\\=\frac{-26}{15}\)