Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{7}{-2}\right)+\left(\frac{-5}{8}\right)\)
2. \(-\left(\frac{-8}{-11}\right)-\left(\frac{-10}{3}\right)\)
3. \(-\left(\frac{8}{3}\right)-\left(\frac{5}{-9}\right)\)
4. \(-\left(\frac{-14}{-5}\right)-\left(\frac{-11}{2}\right)\)
5. \(+\left(\frac{-6}{5}\right)-\left(\frac{-2}{-13}\right)\)
6. \(+\left(\frac{-14}{-9}\right)+\left(\frac{5}{-8}\right)\)
7. \(+\left(\frac{-11}{-4}\right)+\left(\frac{-2}{-3}\right)\)
8. \(-\left(\frac{8}{-13}\right)+\left(\frac{-4}{5}\right)\)
9. \(+\left(\frac{-9}{4}\right)-\left(\frac{4}{-13}\right)\)
10. \(-\left(\frac{-4}{3}\right)+\left(\frac{13}{-14}\right)\)
11. \(-\left(\frac{3}{-10}\right)-\left(\frac{-5}{3}\right)\)
12. \(-\left(\frac{-6}{13}\right)+\left(\frac{4}{3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{7}{-2}\right)+\left(\frac{-5}{8}\right)\\= \frac{7}{2}-\frac{5}{8}\\=\frac{28}{8}-\frac{5}{8}\\=\frac{28-5}{8}\\=\frac{23}{8}\)
2. \(-\left(\frac{-8}{-11}\right)-\left(\frac{-10}{3}\right)\\= \frac{-8}{11}+\frac{10}{3}\\=\frac{-24}{33}+\frac{110}{33}\\=\frac{-24+110}{33}\\=\frac{86}{33}\)
3. \(-\left(\frac{8}{3}\right)-\left(\frac{5}{-9}\right)\\= \frac{-8}{3}+\frac{5}{9}\\=\frac{-24}{9}+\frac{5}{9}\\=\frac{-24+5}{9}\\=\frac{-19}{9}\)
4. \(-\left(\frac{-14}{-5}\right)-\left(\frac{-11}{2}\right)\\= \frac{-14}{5}+\frac{11}{2}\\=\frac{-28}{10}+\frac{55}{10}\\=\frac{-28+55}{10}\\=\frac{27}{10}\)
5. \(+\left(\frac{-6}{5}\right)-\left(\frac{-2}{-13}\right)\\= \frac{-6}{5}-\frac{2}{13}\\=\frac{-78}{65}-\frac{10}{65}\\=\frac{-78-10}{65}\\=\frac{-88}{65}\)
6. \(+\left(\frac{-14}{-9}\right)+\left(\frac{5}{-8}\right)\\= \frac{14}{9}-\frac{5}{8}\\=\frac{112}{72}-\frac{45}{72}\\=\frac{112-45}{72}\\=\frac{67}{72}\)
7. \(+\left(\frac{-11}{-4}\right)+\left(\frac{-2}{-3}\right)\\= \frac{11}{4}+\frac{2}{3}\\=\frac{33}{12}+\frac{8}{12}\\=\frac{33+8}{12}\\=\frac{41}{12}\)
8. \(-\left(\frac{8}{-13}\right)+\left(\frac{-4}{5}\right)\\= \frac{8}{13}-\frac{4}{5}\\=\frac{40}{65}-\frac{52}{65}\\=\frac{40-52}{65}\\=\frac{-12}{65}\)
9. \(+\left(\frac{-9}{4}\right)-\left(\frac{4}{-13}\right)\\= \frac{-9}{4}+\frac{4}{13}\\=\frac{-117}{52}+\frac{16}{52}\\=\frac{-117+16}{52}\\=\frac{-101}{52}\)
10. \(-\left(\frac{-4}{3}\right)+\left(\frac{13}{-14}\right)\\= \frac{4}{3}-\frac{13}{14}\\=\frac{56}{42}-\frac{39}{42}\\=\frac{56-39}{42}\\=\frac{17}{42}\)
11. \(-\left(\frac{3}{-10}\right)-\left(\frac{-5}{3}\right)\\= \frac{3}{10}+\frac{5}{3}\\=\frac{9}{30}+\frac{50}{30}\\=\frac{9+50}{30}\\=\frac{59}{30}\)
12. \(-\left(\frac{-6}{13}\right)+\left(\frac{4}{3}\right)\\= \frac{6}{13}+\frac{4}{3}\\=\frac{18}{39}+\frac{52}{39}\\=\frac{18+52}{39}\\=\frac{70}{39}\)