Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-12}{-7}\right)+\left(\frac{7}{3}\right)\)
2. \(-\left(\frac{8}{11}\right)-\left(\frac{-15}{-2}\right)\)
3. \(+\left(\frac{-2}{-9}\right)+\left(\frac{-12}{-11}\right)\)
4. \(+\left(\frac{7}{9}\right)-\left(\frac{4}{-13}\right)\)
5. \(+\left(\frac{-13}{-2}\right)-\left(\frac{-7}{-9}\right)\)
6. \(+\left(\frac{-3}{2}\right)+\left(\frac{-6}{5}\right)\)
7. \(+\left(\frac{-6}{-11}\right)+\left(\frac{15}{13}\right)\)
8. \(+\left(\frac{-10}{7}\right)-\left(\frac{-12}{-7}\right)\)
9. \(+\left(\frac{-2}{-7}\right)-\left(\frac{15}{-11}\right)\)
10. \(+\left(\frac{-15}{2}\right)+\left(\frac{10}{3}\right)\)
11. \(-\left(\frac{-4}{3}\right)-\left(\frac{-15}{8}\right)\)
12. \(-\left(\frac{7}{2}\right)-\left(\frac{7}{8}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{-12}{-7}\right)+\left(\frac{7}{3}\right)\\= \frac{-12}{7}+\frac{7}{3}\\=\frac{-36}{21}+\frac{49}{21}\\=\frac{-36+49}{21}\\=\frac{13}{21}\)
2. \(-\left(\frac{8}{11}\right)-\left(\frac{-15}{-2}\right)\\= \frac{-8}{11}-\frac{15}{2}\\=\frac{-16}{22}-\frac{165}{22}\\=\frac{-16-165}{22}\\=\frac{-181}{22}\)
3. \(+\left(\frac{-2}{-9}\right)+\left(\frac{-12}{-11}\right)\\= \frac{2}{9}+\frac{12}{11}\\=\frac{22}{99}+\frac{108}{99}\\=\frac{22+108}{99}\\=\frac{130}{99}\)
4. \(+\left(\frac{7}{9}\right)-\left(\frac{4}{-13}\right)\\= \frac{7}{9}+\frac{4}{13}\\=\frac{91}{117}+\frac{36}{117}\\=\frac{91+36}{117}\\=\frac{127}{117}\)
5. \(+\left(\frac{-13}{-2}\right)-\left(\frac{-7}{-9}\right)\\= \frac{13}{2}-\frac{7}{9}\\=\frac{117}{18}-\frac{14}{18}\\=\frac{117-14}{18}\\=\frac{103}{18}\)
6. \(+\left(\frac{-3}{2}\right)+\left(\frac{-6}{5}\right)\\= \frac{-3}{2}-\frac{6}{5}\\=\frac{-15}{10}-\frac{12}{10}\\=\frac{-15-12}{10}\\=\frac{-27}{10}\)
7. \(+\left(\frac{-6}{-11}\right)+\left(\frac{15}{13}\right)\\= \frac{6}{11}+\frac{15}{13}\\=\frac{78}{143}+\frac{165}{143}\\=\frac{78+165}{143}\\=\frac{243}{143}\)
8. \(+\left(\frac{-10}{7}\right)-\left(\frac{-12}{-7}\right)\\= \frac{-10}{7}-\frac{12}{7}\\=\frac{-10-12}{7}\\=\frac{-22}{7}\)
9. \(+\left(\frac{-2}{-7}\right)-\left(\frac{15}{-11}\right)\\= \frac{2}{7}+\frac{15}{11}\\=\frac{22}{77}+\frac{105}{77}\\=\frac{22+105}{77}\\=\frac{127}{77}\)
10. \(+\left(\frac{-15}{2}\right)+\left(\frac{10}{3}\right)\\= \frac{-15}{2}+\frac{10}{3}\\=\frac{-45}{6}+\frac{20}{6}\\=\frac{-45+20}{6}\\=\frac{-25}{6}\)
11. \(-\left(\frac{-4}{3}\right)-\left(\frac{-15}{8}\right)\\= \frac{4}{3}+\frac{15}{8}\\=\frac{32}{24}+\frac{45}{24}\\=\frac{32+45}{24}\\=\frac{77}{24}\)
12. \(-\left(\frac{7}{2}\right)-\left(\frac{7}{8}\right)\\= \frac{-7}{2}-\frac{7}{8}\\=\frac{-28}{8}-\frac{7}{8}\\=\frac{-28-7}{8}\\=\frac{-35}{8}\)