Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-4}{3}\right)+\left(\frac{-11}{12}\right)\)
2. \(+\left(\frac{3}{-7}\right)+\left(\frac{9}{10}\right)\)
3. \(-\left(\frac{14}{9}\right)-\left(\frac{-10}{3}\right)\)
4. \(-\left(\frac{12}{11}\right)-\left(\frac{9}{13}\right)\)
5. \(-\left(\frac{-8}{7}\right)-\left(\frac{-6}{13}\right)\)
6. \(-\left(\frac{11}{-12}\right)+\left(\frac{-13}{-3}\right)\)
7. \(+\left(\frac{15}{-13}\right)+\left(\frac{-12}{13}\right)\)
8. \(-\left(\frac{9}{4}\right)+\left(\frac{9}{-4}\right)\)
9. \(-\left(\frac{14}{-9}\right)+\left(\frac{-8}{7}\right)\)
10. \(-\left(\frac{14}{-3}\right)+\left(\frac{-6}{13}\right)\)
11. \(+\left(\frac{-11}{13}\right)+\left(\frac{-10}{-7}\right)\)
12. \(-\left(\frac{-15}{-8}\right)+\left(\frac{12}{5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-4}{3}\right)+\left(\frac{-11}{12}\right)\\= \frac{-4}{3}-\frac{11}{12}\\=\frac{-16}{12}-\frac{11}{12}\\=\frac{-16-11}{12}\\=\frac{-27}{12}\\=\frac{-9}{4}\)
2. \(+\left(\frac{3}{-7}\right)+\left(\frac{9}{10}\right)\\= \frac{-3}{7}+\frac{9}{10}\\=\frac{-30}{70}+\frac{63}{70}\\=\frac{-30+63}{70}\\=\frac{33}{70}\)
3. \(-\left(\frac{14}{9}\right)-\left(\frac{-10}{3}\right)\\= \frac{-14}{9}+\frac{10}{3}\\=\frac{-14+10}{9}\\=\frac{-4}{9}\)
4. \(-\left(\frac{12}{11}\right)-\left(\frac{9}{13}\right)\\= \frac{-12}{11}-\frac{9}{13}\\=\frac{-156}{143}-\frac{99}{143}\\=\frac{-156-99}{143}\\=\frac{-255}{143}\)
5. \(-\left(\frac{-8}{7}\right)-\left(\frac{-6}{13}\right)\\= \frac{8}{7}+\frac{6}{13}\\=\frac{104}{91}+\frac{42}{91}\\=\frac{104+42}{91}\\=\frac{146}{91}\)
6. \(-\left(\frac{11}{-12}\right)+\left(\frac{-13}{-3}\right)\\= \frac{11}{12}+\frac{13}{3}\\=\frac{11+13}{12}\\=\frac{24}{12}\\=\frac{2}{1}\)
7. \(+\left(\frac{15}{-13}\right)+\left(\frac{-12}{13}\right)\\= \frac{-15}{13}-\frac{12}{13}\\=\frac{-15-12}{13}\\=\frac{-27}{13}\)
8. \(-\left(\frac{9}{4}\right)+\left(\frac{9}{-4}\right)\\= \frac{-9}{4}-\frac{9}{4}\\=\frac{-9-9}{4}\\=\frac{-18}{4}\\=\frac{-9}{2}\)
9. \(-\left(\frac{14}{-9}\right)+\left(\frac{-8}{7}\right)\\= \frac{14}{9}-\frac{8}{7}\\=\frac{98}{63}-\frac{72}{63}\\=\frac{98-72}{63}\\=\frac{26}{63}\)
10. \(-\left(\frac{14}{-3}\right)+\left(\frac{-6}{13}\right)\\= \frac{14}{3}-\frac{6}{13}\\=\frac{182}{39}-\frac{18}{39}\\=\frac{182-18}{39}\\=\frac{164}{39}\)
11. \(+\left(\frac{-11}{13}\right)+\left(\frac{-10}{-7}\right)\\= \frac{-11}{13}+\frac{10}{7}\\=\frac{-77}{91}+\frac{130}{91}\\=\frac{-77+130}{91}\\=\frac{53}{91}\)
12. \(-\left(\frac{-15}{-8}\right)+\left(\frac{12}{5}\right)\\= \frac{-15}{8}+\frac{12}{5}\\=\frac{-75}{40}+\frac{96}{40}\\=\frac{-75+96}{40}\\=\frac{21}{40}\)