Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-7}{-6}\right)-\left(\frac{3}{5}\right)\)
2. \(-\left(\frac{-12}{-7}\right)-\left(\frac{-11}{-10}\right)\)
3. \(-\left(\frac{7}{-6}\right)-\left(\frac{-6}{13}\right)\)
4. \(-\left(\frac{13}{-2}\right)+\left(\frac{4}{9}\right)\)
5. \(-\left(\frac{-8}{-5}\right)+\left(\frac{-11}{12}\right)\)
6. \(-\left(\frac{-7}{12}\right)+\left(\frac{-10}{3}\right)\)
7. \(+\left(\frac{10}{-7}\right)+\left(\frac{11}{12}\right)\)
8. \(+\left(\frac{-15}{13}\right)-\left(\frac{2}{13}\right)\)
9. \(-\left(\frac{-3}{-4}\right)-\left(\frac{4}{-3}\right)\)
10. \(-\left(\frac{14}{-3}\right)-\left(\frac{-7}{8}\right)\)
11. \(-\left(\frac{15}{-7}\right)-\left(\frac{-3}{-11}\right)\)
12. \(+\left(\frac{11}{-2}\right)+\left(\frac{14}{11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-7}{-6}\right)-\left(\frac{3}{5}\right)\\= \frac{7}{6}-\frac{3}{5}\\=\frac{35}{30}-\frac{18}{30}\\=\frac{35-18}{30}\\=\frac{17}{30}\)
2. \(-\left(\frac{-12}{-7}\right)-\left(\frac{-11}{-10}\right)\\= \frac{-12}{7}-\frac{11}{10}\\=\frac{-120}{70}-\frac{77}{70}\\=\frac{-120-77}{70}\\=\frac{-197}{70}\)
3. \(-\left(\frac{7}{-6}\right)-\left(\frac{-6}{13}\right)\\= \frac{7}{6}+\frac{6}{13}\\=\frac{91}{78}+\frac{36}{78}\\=\frac{91+36}{78}\\=\frac{127}{78}\)
4. \(-\left(\frac{13}{-2}\right)+\left(\frac{4}{9}\right)\\= \frac{13}{2}+\frac{4}{9}\\=\frac{117}{18}+\frac{8}{18}\\=\frac{117+8}{18}\\=\frac{125}{18}\)
5. \(-\left(\frac{-8}{-5}\right)+\left(\frac{-11}{12}\right)\\= \frac{-8}{5}-\frac{11}{12}\\=\frac{-96}{60}-\frac{55}{60}\\=\frac{-96-55}{60}\\=\frac{-151}{60}\)
6. \(-\left(\frac{-7}{12}\right)+\left(\frac{-10}{3}\right)\\= \frac{7}{12}-\frac{10}{3}\\=\frac{7-10}{12}\\=\frac{-3}{12}\\=\frac{-1}{4}\)
7. \(+\left(\frac{10}{-7}\right)+\left(\frac{11}{12}\right)\\= \frac{-10}{7}+\frac{11}{12}\\=\frac{-120}{84}+\frac{77}{84}\\=\frac{-120+77}{84}\\=\frac{-43}{84}\)
8. \(+\left(\frac{-15}{13}\right)-\left(\frac{2}{13}\right)\\= \frac{-15}{13}-\frac{2}{13}\\=\frac{-15-2}{13}\\=\frac{-17}{13}\)
9. \(-\left(\frac{-3}{-4}\right)-\left(\frac{4}{-3}\right)\\= \frac{-3}{4}+\frac{4}{3}\\=\frac{-9}{12}+\frac{16}{12}\\=\frac{-9+16}{12}\\=\frac{7}{12}\)
10. \(-\left(\frac{14}{-3}\right)-\left(\frac{-7}{8}\right)\\= \frac{14}{3}+\frac{7}{8}\\=\frac{112}{24}+\frac{21}{24}\\=\frac{112+21}{24}\\=\frac{133}{24}\)
11. \(-\left(\frac{15}{-7}\right)-\left(\frac{-3}{-11}\right)\\= \frac{15}{7}-\frac{3}{11}\\=\frac{165}{77}-\frac{21}{77}\\=\frac{165-21}{77}\\=\frac{144}{77}\)
12. \(+\left(\frac{11}{-2}\right)+\left(\frac{14}{11}\right)\\= \frac{-11}{2}+\frac{14}{11}\\=\frac{-121}{22}+\frac{28}{22}\\=\frac{-121+28}{22}\\=\frac{-93}{22}\)