Breuken haakjesregel (reeks 1)

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Bereken

1. \(-\left(\frac{10}{-3}\right)-\left(\frac{6}{-5}\right)\)
2. \(-\left(\frac{10}{3}\right)+\left(\frac{8}{11}\right)\)
3. \(-\left(\frac{-10}{-9}\right)-\left(\frac{15}{-14}\right)\)
4. \(+\left(\frac{2}{7}\right)-\left(\frac{-3}{-13}\right)\)
5. \(-\left(\frac{15}{-11}\right)-\left(\frac{12}{13}\right)\)
6. \(+\left(\frac{-2}{-11}\right)-\left(\frac{-10}{-13}\right)\)
7. \(-\left(\frac{-6}{5}\right)-\left(\frac{6}{-5}\right)\)
8. \(-\left(\frac{13}{-6}\right)+\left(\frac{-7}{-2}\right)\)
9. \(-\left(\frac{-7}{-4}\right)-\left(\frac{15}{13}\right)\)
10. \(+\left(\frac{-8}{3}\right)+\left(\frac{-2}{7}\right)\)
11. \(+\left(\frac{7}{-9}\right)-\left(\frac{-2}{-9}\right)\)
12. \(+\left(\frac{7}{-4}\right)-\left(\frac{-6}{13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{10}{-3}\right)-\left(\frac{6}{-5}\right)\\= \frac{10}{3}+\frac{6}{5}\\=\frac{50}{15}+\frac{18}{15}\\=\frac{50+18}{15}\\=\frac{68}{15}\)
2. \(-\left(\frac{10}{3}\right)+\left(\frac{8}{11}\right)\\= \frac{-10}{3}+\frac{8}{11}\\=\frac{-110}{33}+\frac{24}{33}\\=\frac{-110+24}{33}\\=\frac{-86}{33}\)
3. \(-\left(\frac{-10}{-9}\right)-\left(\frac{15}{-14}\right)\\= \frac{-10}{9}+\frac{15}{14}\\=\frac{-140}{126}+\frac{135}{126}\\=\frac{-140+135}{126}\\=\frac{-5}{126}\)
4. \(+\left(\frac{2}{7}\right)-\left(\frac{-3}{-13}\right)\\= \frac{2}{7}-\frac{3}{13}\\=\frac{26}{91}-\frac{21}{91}\\=\frac{26-21}{91}\\=\frac{5}{91}\)
5. \(-\left(\frac{15}{-11}\right)-\left(\frac{12}{13}\right)\\= \frac{15}{11}-\frac{12}{13}\\=\frac{195}{143}-\frac{132}{143}\\=\frac{195-132}{143}\\=\frac{63}{143}\)
6. \(+\left(\frac{-2}{-11}\right)-\left(\frac{-10}{-13}\right)\\= \frac{2}{11}-\frac{10}{13}\\=\frac{26}{143}-\frac{110}{143}\\=\frac{26-110}{143}\\=\frac{-84}{143}\)
7. \(-\left(\frac{-6}{5}\right)-\left(\frac{6}{-5}\right)\\= \frac{6}{5}+\frac{6}{5}\\=\frac{6+6}{5}\\=\frac{12}{5}\)
8. \(-\left(\frac{13}{-6}\right)+\left(\frac{-7}{-2}\right)\\= \frac{13}{6}+\frac{7}{2}\\=\frac{13+7}{6}\\=\frac{20}{6}\\=\frac{10}{3}\)
9. \(-\left(\frac{-7}{-4}\right)-\left(\frac{15}{13}\right)\\= \frac{-7}{4}-\frac{15}{13}\\=\frac{-91}{52}-\frac{60}{52}\\=\frac{-91-60}{52}\\=\frac{-151}{52}\)
10. \(+\left(\frac{-8}{3}\right)+\left(\frac{-2}{7}\right)\\= \frac{-8}{3}-\frac{2}{7}\\=\frac{-56}{21}-\frac{6}{21}\\=\frac{-56-6}{21}\\=\frac{-62}{21}\)
11. \(+\left(\frac{7}{-9}\right)-\left(\frac{-2}{-9}\right)\\= \frac{-7}{9}-\frac{2}{9}\\=\frac{-7-2}{9}\\=\frac{-9}{9}\\=\frac{-1}{1}\)
12. \(+\left(\frac{7}{-4}\right)-\left(\frac{-6}{13}\right)\\= \frac{-7}{4}+\frac{6}{13}\\=\frac{-91}{52}+\frac{24}{52}\\=\frac{-91+24}{52}\\=\frac{-67}{52}\)