Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-9}{-13}\right)+\left(\frac{-9}{8}\right)\)
2. \(-\left(\frac{-7}{-12}\right)+\left(\frac{-14}{-9}\right)\)
3. \(+\left(\frac{-5}{-3}\right)-\left(\frac{-10}{9}\right)\)
4. \(-\left(\frac{-4}{3}\right)-\left(\frac{4}{-3}\right)\)
5. \(-\left(\frac{-10}{-13}\right)+\left(\frac{-3}{-10}\right)\)
6. \(-\left(\frac{-8}{-9}\right)-\left(\frac{8}{9}\right)\)
7. \(-\left(\frac{-15}{-2}\right)+\left(\frac{4}{-3}\right)\)
8. \(+\left(\frac{-4}{-3}\right)+\left(\frac{-6}{7}\right)\)
9. \(-\left(\frac{-11}{6}\right)+\left(\frac{-2}{3}\right)\)
10. \(-\left(\frac{12}{-5}\right)+\left(\frac{10}{-9}\right)\)
11. \(-\left(\frac{5}{3}\right)-\left(\frac{6}{-11}\right)\)
12. \(+\left(\frac{-11}{-2}\right)+\left(\frac{-10}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-9}{-13}\right)+\left(\frac{-9}{8}\right)\\= \frac{9}{13}-\frac{9}{8}\\=\frac{72}{104}-\frac{117}{104}\\=\frac{72-117}{104}\\=\frac{-45}{104}\)
2. \(-\left(\frac{-7}{-12}\right)+\left(\frac{-14}{-9}\right)\\= \frac{-7}{12}+\frac{14}{9}\\=\frac{-21}{36}+\frac{56}{36}\\=\frac{-21+56}{36}\\=\frac{35}{36}\)
3. \(+\left(\frac{-5}{-3}\right)-\left(\frac{-10}{9}\right)\\= \frac{5}{3}+\frac{10}{9}\\=\frac{15}{9}+\frac{10}{9}\\=\frac{15+10}{9}\\=\frac{25}{9}\)
4. \(-\left(\frac{-4}{3}\right)-\left(\frac{4}{-3}\right)\\= \frac{4}{3}+\frac{4}{3}\\=\frac{4+4}{3}\\=\frac{8}{3}\)
5. \(-\left(\frac{-10}{-13}\right)+\left(\frac{-3}{-10}\right)\\= \frac{-10}{13}+\frac{3}{10}\\=\frac{-100}{130}+\frac{39}{130}\\=\frac{-100+39}{130}\\=\frac{-61}{130}\)
6. \(-\left(\frac{-8}{-9}\right)-\left(\frac{8}{9}\right)\\= \frac{-8}{9}-\frac{8}{9}\\=\frac{-8-8}{9}\\=\frac{-16}{9}\)
7. \(-\left(\frac{-15}{-2}\right)+\left(\frac{4}{-3}\right)\\= \frac{-15}{2}-\frac{4}{3}\\=\frac{-45}{6}-\frac{8}{6}\\=\frac{-45-8}{6}\\=\frac{-53}{6}\)
8. \(+\left(\frac{-4}{-3}\right)+\left(\frac{-6}{7}\right)\\= \frac{4}{3}-\frac{6}{7}\\=\frac{28}{21}-\frac{18}{21}\\=\frac{28-18}{21}\\=\frac{10}{21}\)
9. \(-\left(\frac{-11}{6}\right)+\left(\frac{-2}{3}\right)\\= \frac{11}{6}-\frac{2}{3}\\=\frac{11-2}{6}\\=\frac{9}{6}\\=\frac{3}{2}\)
10. \(-\left(\frac{12}{-5}\right)+\left(\frac{10}{-9}\right)\\= \frac{12}{5}-\frac{10}{9}\\=\frac{108}{45}-\frac{50}{45}\\=\frac{108-50}{45}\\=\frac{58}{45}\)
11. \(-\left(\frac{5}{3}\right)-\left(\frac{6}{-11}\right)\\= \frac{-5}{3}+\frac{6}{11}\\=\frac{-55}{33}+\frac{18}{33}\\=\frac{-55+18}{33}\\=\frac{-37}{33}\)
12. \(+\left(\frac{-11}{-2}\right)+\left(\frac{-10}{-7}\right)\\= \frac{11}{2}+\frac{10}{7}\\=\frac{77}{14}+\frac{20}{14}\\=\frac{77+20}{14}\\=\frac{97}{14}\)