Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-2}{-11}\right)-\left(\frac{-10}{3}\right)\)
2. \(-\left(\frac{-2}{-9}\right)+\left(\frac{7}{13}\right)\)
3. \(-\left(\frac{-10}{7}\right)-\left(\frac{5}{9}\right)\)
4. \(-\left(\frac{-7}{-8}\right)-\left(\frac{-3}{-11}\right)\)
5. \(+\left(\frac{14}{13}\right)-\left(\frac{14}{5}\right)\)
6. \(-\left(\frac{15}{-7}\right)-\left(\frac{4}{11}\right)\)
7. \(+\left(\frac{6}{11}\right)+\left(\frac{11}{-12}\right)\)
8. \(+\left(\frac{-9}{-11}\right)-\left(\frac{-10}{3}\right)\)
9. \(-\left(\frac{-14}{5}\right)+\left(\frac{-8}{-9}\right)\)
10. \(-\left(\frac{-6}{-5}\right)+\left(\frac{15}{11}\right)\)
11. \(+\left(\frac{-12}{13}\right)-\left(\frac{-14}{13}\right)\)
12. \(-\left(\frac{-6}{5}\right)+\left(\frac{6}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-2}{-11}\right)-\left(\frac{-10}{3}\right)\\= \frac{-2}{11}+\frac{10}{3}\\=\frac{-6}{33}+\frac{110}{33}\\=\frac{-6+110}{33}\\=\frac{104}{33}\)
2. \(-\left(\frac{-2}{-9}\right)+\left(\frac{7}{13}\right)\\= \frac{-2}{9}+\frac{7}{13}\\=\frac{-26}{117}+\frac{63}{117}\\=\frac{-26+63}{117}\\=\frac{37}{117}\)
3. \(-\left(\frac{-10}{7}\right)-\left(\frac{5}{9}\right)\\= \frac{10}{7}-\frac{5}{9}\\=\frac{90}{63}-\frac{35}{63}\\=\frac{90-35}{63}\\=\frac{55}{63}\)
4. \(-\left(\frac{-7}{-8}\right)-\left(\frac{-3}{-11}\right)\\= \frac{-7}{8}-\frac{3}{11}\\=\frac{-77}{88}-\frac{24}{88}\\=\frac{-77-24}{88}\\=\frac{-101}{88}\)
5. \(+\left(\frac{14}{13}\right)-\left(\frac{14}{5}\right)\\= \frac{14}{13}-\frac{14}{5}\\=\frac{70}{65}-\frac{182}{65}\\=\frac{70-182}{65}\\=\frac{-112}{65}\)
6. \(-\left(\frac{15}{-7}\right)-\left(\frac{4}{11}\right)\\= \frac{15}{7}-\frac{4}{11}\\=\frac{165}{77}-\frac{28}{77}\\=\frac{165-28}{77}\\=\frac{137}{77}\)
7. \(+\left(\frac{6}{11}\right)+\left(\frac{11}{-12}\right)\\= \frac{6}{11}-\frac{11}{12}\\=\frac{72}{132}-\frac{121}{132}\\=\frac{72-121}{132}\\=\frac{-49}{132}\)
8. \(+\left(\frac{-9}{-11}\right)-\left(\frac{-10}{3}\right)\\= \frac{9}{11}+\frac{10}{3}\\=\frac{27}{33}+\frac{110}{33}\\=\frac{27+110}{33}\\=\frac{137}{33}\)
9. \(-\left(\frac{-14}{5}\right)+\left(\frac{-8}{-9}\right)\\= \frac{14}{5}+\frac{8}{9}\\=\frac{126}{45}+\frac{40}{45}\\=\frac{126+40}{45}\\=\frac{166}{45}\)
10. \(-\left(\frac{-6}{-5}\right)+\left(\frac{15}{11}\right)\\= \frac{-6}{5}+\frac{15}{11}\\=\frac{-66}{55}+\frac{75}{55}\\=\frac{-66+75}{55}\\=\frac{9}{55}\)
11. \(+\left(\frac{-12}{13}\right)-\left(\frac{-14}{13}\right)\\= \frac{-12}{13}+\frac{14}{13}\\=\frac{-12+14}{13}\\=\frac{2}{13}\)
12. \(-\left(\frac{-6}{5}\right)+\left(\frac{6}{-7}\right)\\= \frac{6}{5}-\frac{6}{7}\\=\frac{42}{35}-\frac{30}{35}\\=\frac{42-30}{35}\\=\frac{12}{35}\)