Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{3}{-4}\right)-\left(\frac{-10}{7}\right)\)
2. \(-\left(\frac{3}{-4}\right)+\left(\frac{-2}{-9}\right)\)
3. \(+\left(\frac{8}{11}\right)-\left(\frac{-5}{2}\right)\)
4. \(+\left(\frac{-7}{8}\right)-\left(\frac{11}{2}\right)\)
5. \(-\left(\frac{8}{-5}\right)+\left(\frac{-10}{-11}\right)\)
6. \(-\left(\frac{-4}{-3}\right)+\left(\frac{-6}{5}\right)\)
7. \(-\left(\frac{3}{-13}\right)-\left(\frac{10}{-11}\right)\)
8. \(+\left(\frac{15}{-2}\right)+\left(\frac{8}{-3}\right)\)
9. \(+\left(\frac{7}{-10}\right)-\left(\frac{-15}{-8}\right)\)
10. \(-\left(\frac{-4}{5}\right)+\left(\frac{-6}{-5}\right)\)
11. \(-\left(\frac{12}{11}\right)+\left(\frac{-2}{-5}\right)\)
12. \(-\left(\frac{-12}{-13}\right)-\left(\frac{5}{8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{3}{-4}\right)-\left(\frac{-10}{7}\right)\\= \frac{-3}{4}+\frac{10}{7}\\=\frac{-21}{28}+\frac{40}{28}\\=\frac{-21+40}{28}\\=\frac{19}{28}\)
2. \(-\left(\frac{3}{-4}\right)+\left(\frac{-2}{-9}\right)\\= \frac{3}{4}+\frac{2}{9}\\=\frac{27}{36}+\frac{8}{36}\\=\frac{27+8}{36}\\=\frac{35}{36}\)
3. \(+\left(\frac{8}{11}\right)-\left(\frac{-5}{2}\right)\\= \frac{8}{11}+\frac{5}{2}\\=\frac{16}{22}+\frac{55}{22}\\=\frac{16+55}{22}\\=\frac{71}{22}\)
4. \(+\left(\frac{-7}{8}\right)-\left(\frac{11}{2}\right)\\= \frac{-7}{8}-\frac{11}{2}\\=\frac{-7-11}{8}\\=\frac{-18}{8}\\=\frac{-9}{4}\)
5. \(-\left(\frac{8}{-5}\right)+\left(\frac{-10}{-11}\right)\\= \frac{8}{5}+\frac{10}{11}\\=\frac{88}{55}+\frac{50}{55}\\=\frac{88+50}{55}\\=\frac{138}{55}\)
6. \(-\left(\frac{-4}{-3}\right)+\left(\frac{-6}{5}\right)\\= \frac{-4}{3}-\frac{6}{5}\\=\frac{-20}{15}-\frac{18}{15}\\=\frac{-20-18}{15}\\=\frac{-38}{15}\)
7. \(-\left(\frac{3}{-13}\right)-\left(\frac{10}{-11}\right)\\= \frac{3}{13}+\frac{10}{11}\\=\frac{33}{143}+\frac{130}{143}\\=\frac{33+130}{143}\\=\frac{163}{143}\)
8. \(+\left(\frac{15}{-2}\right)+\left(\frac{8}{-3}\right)\\= \frac{-15}{2}-\frac{8}{3}\\=\frac{-45}{6}-\frac{16}{6}\\=\frac{-45-16}{6}\\=\frac{-61}{6}\)
9. \(+\left(\frac{7}{-10}\right)-\left(\frac{-15}{-8}\right)\\= \frac{-7}{10}-\frac{15}{8}\\=\frac{-28}{40}-\frac{75}{40}\\=\frac{-28-75}{40}\\=\frac{-103}{40}\)
10. \(-\left(\frac{-4}{5}\right)+\left(\frac{-6}{-5}\right)\\= \frac{4}{5}+\frac{6}{5}\\=\frac{4+6}{5}\\=\frac{10}{5}\\=\frac{2}{1}\)
11. \(-\left(\frac{12}{11}\right)+\left(\frac{-2}{-5}\right)\\= \frac{-12}{11}+\frac{2}{5}\\=\frac{-60}{55}+\frac{22}{55}\\=\frac{-60+22}{55}\\=\frac{-38}{55}\)
12. \(-\left(\frac{-12}{-13}\right)-\left(\frac{5}{8}\right)\\= \frac{-12}{13}-\frac{5}{8}\\=\frac{-96}{104}-\frac{65}{104}\\=\frac{-96-65}{104}\\=\frac{-161}{104}\)