Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{6}{5}\right)+\left(\frac{-7}{-10}\right)\)
2. \(-\left(\frac{-13}{2}\right)+\left(\frac{-11}{8}\right)\)
3. \(+\left(\frac{-10}{-13}\right)-\left(\frac{-2}{-5}\right)\)
4. \(-\left(\frac{13}{-5}\right)+\left(\frac{-7}{-2}\right)\)
5. \(-\left(\frac{-9}{2}\right)-\left(\frac{-2}{-11}\right)\)
6. \(+\left(\frac{-14}{-9}\right)-\left(\frac{15}{14}\right)\)
7. \(-\left(\frac{10}{-3}\right)-\left(\frac{5}{-7}\right)\)
8. \(-\left(\frac{-6}{11}\right)-\left(\frac{-12}{-7}\right)\)
9. \(-\left(\frac{-11}{-8}\right)+\left(\frac{-7}{-8}\right)\)
10. \(+\left(\frac{-5}{-8}\right)+\left(\frac{13}{3}\right)\)
11. \(-\left(\frac{6}{-11}\right)-\left(\frac{13}{4}\right)\)
12. \(+\left(\frac{11}{-7}\right)-\left(\frac{13}{-2}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{6}{5}\right)+\left(\frac{-7}{-10}\right)\\= \frac{6}{5}+\frac{7}{10}\\=\frac{12}{10}+\frac{7}{10}\\=\frac{12+7}{10}\\=\frac{19}{10}\)
2. \(-\left(\frac{-13}{2}\right)+\left(\frac{-11}{8}\right)\\= \frac{13}{2}-\frac{11}{8}\\=\frac{52}{8}-\frac{11}{8}\\=\frac{52-11}{8}\\=\frac{41}{8}\)
3. \(+\left(\frac{-10}{-13}\right)-\left(\frac{-2}{-5}\right)\\= \frac{10}{13}-\frac{2}{5}\\=\frac{50}{65}-\frac{26}{65}\\=\frac{50-26}{65}\\=\frac{24}{65}\)
4. \(-\left(\frac{13}{-5}\right)+\left(\frac{-7}{-2}\right)\\= \frac{13}{5}+\frac{7}{2}\\=\frac{26}{10}+\frac{35}{10}\\=\frac{26+35}{10}\\=\frac{61}{10}\)
5. \(-\left(\frac{-9}{2}\right)-\left(\frac{-2}{-11}\right)\\= \frac{9}{2}-\frac{2}{11}\\=\frac{99}{22}-\frac{4}{22}\\=\frac{99-4}{22}\\=\frac{95}{22}\)
6. \(+\left(\frac{-14}{-9}\right)-\left(\frac{15}{14}\right)\\= \frac{14}{9}-\frac{15}{14}\\=\frac{196}{126}-\frac{135}{126}\\=\frac{196-135}{126}\\=\frac{61}{126}\)
7. \(-\left(\frac{10}{-3}\right)-\left(\frac{5}{-7}\right)\\= \frac{10}{3}+\frac{5}{7}\\=\frac{70}{21}+\frac{15}{21}\\=\frac{70+15}{21}\\=\frac{85}{21}\)
8. \(-\left(\frac{-6}{11}\right)-\left(\frac{-12}{-7}\right)\\= \frac{6}{11}-\frac{12}{7}\\=\frac{42}{77}-\frac{132}{77}\\=\frac{42-132}{77}\\=\frac{-90}{77}\)
9. \(-\left(\frac{-11}{-8}\right)+\left(\frac{-7}{-8}\right)\\= \frac{-11}{8}+\frac{7}{8}\\=\frac{-11+7}{8}\\=\frac{-4}{8}\\=\frac{-1}{2}\)
10. \(+\left(\frac{-5}{-8}\right)+\left(\frac{13}{3}\right)\\= \frac{5}{8}+\frac{13}{3}\\=\frac{15}{24}+\frac{104}{24}\\=\frac{15+104}{24}\\=\frac{119}{24}\)
11. \(-\left(\frac{6}{-11}\right)-\left(\frac{13}{4}\right)\\= \frac{6}{11}-\frac{13}{4}\\=\frac{24}{44}-\frac{143}{44}\\=\frac{24-143}{44}\\=\frac{-119}{44}\)
12. \(+\left(\frac{11}{-7}\right)-\left(\frac{13}{-2}\right)\\= \frac{-11}{7}+\frac{13}{2}\\=\frac{-22}{14}+\frac{91}{14}\\=\frac{-22+91}{14}\\=\frac{69}{14}\)