Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{10}{3}\right)+\left(\frac{-13}{6}\right)\)
2. \(-\left(\frac{-14}{-3}\right)-\left(\frac{4}{13}\right)\)
3. \(+\left(\frac{-4}{-3}\right)-\left(\frac{9}{-7}\right)\)
4. \(+\left(\frac{8}{-11}\right)-\left(\frac{-10}{3}\right)\)
5. \(+\left(\frac{4}{-5}\right)+\left(\frac{10}{-7}\right)\)
6. \(-\left(\frac{14}{-11}\right)-\left(\frac{9}{13}\right)\)
7. \(-\left(\frac{11}{5}\right)+\left(\frac{-8}{-3}\right)\)
8. \(+\left(\frac{3}{4}\right)-\left(\frac{12}{-11}\right)\)
9. \(-\left(\frac{-6}{-7}\right)-\left(\frac{12}{13}\right)\)
10. \(-\left(\frac{2}{11}\right)+\left(\frac{12}{11}\right)\)
11. \(-\left(\frac{-11}{-4}\right)-\left(\frac{-13}{12}\right)\)
12. \(-\left(\frac{-11}{-8}\right)-\left(\frac{12}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{10}{3}\right)+\left(\frac{-13}{6}\right)\\= \frac{-10}{3}-\frac{13}{6}\\=\frac{-20}{6}-\frac{13}{6}\\=\frac{-20-13}{6}\\=\frac{-33}{6}\\=\frac{-11}{2}\)
2. \(-\left(\frac{-14}{-3}\right)-\left(\frac{4}{13}\right)\\= \frac{-14}{3}-\frac{4}{13}\\=\frac{-182}{39}-\frac{12}{39}\\=\frac{-182-12}{39}\\=\frac{-194}{39}\)
3. \(+\left(\frac{-4}{-3}\right)-\left(\frac{9}{-7}\right)\\= \frac{4}{3}+\frac{9}{7}\\=\frac{28}{21}+\frac{27}{21}\\=\frac{28+27}{21}\\=\frac{55}{21}\)
4. \(+\left(\frac{8}{-11}\right)-\left(\frac{-10}{3}\right)\\= \frac{-8}{11}+\frac{10}{3}\\=\frac{-24}{33}+\frac{110}{33}\\=\frac{-24+110}{33}\\=\frac{86}{33}\)
5. \(+\left(\frac{4}{-5}\right)+\left(\frac{10}{-7}\right)\\= \frac{-4}{5}-\frac{10}{7}\\=\frac{-28}{35}-\frac{50}{35}\\=\frac{-28-50}{35}\\=\frac{-78}{35}\)
6. \(-\left(\frac{14}{-11}\right)-\left(\frac{9}{13}\right)\\= \frac{14}{11}-\frac{9}{13}\\=\frac{182}{143}-\frac{99}{143}\\=\frac{182-99}{143}\\=\frac{83}{143}\)
7. \(-\left(\frac{11}{5}\right)+\left(\frac{-8}{-3}\right)\\= \frac{-11}{5}+\frac{8}{3}\\=\frac{-33}{15}+\frac{40}{15}\\=\frac{-33+40}{15}\\=\frac{7}{15}\)
8. \(+\left(\frac{3}{4}\right)-\left(\frac{12}{-11}\right)\\= \frac{3}{4}+\frac{12}{11}\\=\frac{33}{44}+\frac{48}{44}\\=\frac{33+48}{44}\\=\frac{81}{44}\)
9. \(-\left(\frac{-6}{-7}\right)-\left(\frac{12}{13}\right)\\= \frac{-6}{7}-\frac{12}{13}\\=\frac{-78}{91}-\frac{84}{91}\\=\frac{-78-84}{91}\\=\frac{-162}{91}\)
10. \(-\left(\frac{2}{11}\right)+\left(\frac{12}{11}\right)\\= \frac{-2}{11}+\frac{12}{11}\\=\frac{-2+12}{11}\\=\frac{10}{11}\)
11. \(-\left(\frac{-11}{-4}\right)-\left(\frac{-13}{12}\right)\\= \frac{-11}{4}+\frac{13}{12}\\=\frac{-33}{12}+\frac{13}{12}\\=\frac{-33+13}{12}\\=\frac{-20}{12}\\=\frac{-5}{3}\)
12. \(-\left(\frac{-11}{-8}\right)-\left(\frac{12}{-11}\right)\\= \frac{-11}{8}+\frac{12}{11}\\=\frac{-121}{88}+\frac{96}{88}\\=\frac{-121+96}{88}\\=\frac{-25}{88}\)