Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(+\left(\frac{10}{13}\right)+\left(\frac{7}{2}\right)\)
  2. \(-\left(\frac{5}{-2}\right)-\left(\frac{-13}{14}\right)\)
  3. \(+\left(\frac{3}{8}\right)+\left(\frac{9}{4}\right)\)
  4. \(-\left(\frac{5}{-3}\right)-\left(\frac{-8}{-5}\right)\)
  5. \(+\left(\frac{4}{-3}\right)+\left(\frac{8}{-11}\right)\)
  6. \(-\left(\frac{-5}{-2}\right)+\left(\frac{3}{-14}\right)\)
  7. \(-\left(\frac{14}{-11}\right)-\left(\frac{-2}{-7}\right)\)
  8. \(-\left(\frac{-6}{-11}\right)-\left(\frac{10}{3}\right)\)
  9. \(+\left(\frac{-6}{5}\right)-\left(\frac{-13}{5}\right)\)
  10. \(-\left(\frac{-7}{-8}\right)-\left(\frac{4}{11}\right)\)
  11. \(+\left(\frac{-10}{-7}\right)-\left(\frac{3}{4}\right)\)
  12. \(-\left(\frac{-7}{2}\right)-\left(\frac{10}{13}\right)\)

Bereken

Verbetersleutel

  1. \(+\left(\frac{10}{13}\right)+\left(\frac{7}{2}\right)\\= \frac{10}{13}+\frac{7}{2}\\=\frac{20}{26}+\frac{91}{26}\\=\frac{20+91}{26}\\=\frac{111}{26}\)
  2. \(-\left(\frac{5}{-2}\right)-\left(\frac{-13}{14}\right)\\= \frac{5}{2}+\frac{13}{14}\\=\frac{35}{14}+\frac{13}{14}\\=\frac{35+13}{14}\\=\frac{48}{14}\\=\frac{24}{7}\)
  3. \(+\left(\frac{3}{8}\right)+\left(\frac{9}{4}\right)\\= \frac{3}{8}+\frac{9}{4}\\=\frac{3+9}{8}\\=\frac{12}{8}\\=\frac{3}{2}\)
  4. \(-\left(\frac{5}{-3}\right)-\left(\frac{-8}{-5}\right)\\= \frac{5}{3}-\frac{8}{5}\\=\frac{25}{15}-\frac{24}{15}\\=\frac{25-24}{15}\\=\frac{1}{15}\)
  5. \(+\left(\frac{4}{-3}\right)+\left(\frac{8}{-11}\right)\\= \frac{-4}{3}-\frac{8}{11}\\=\frac{-44}{33}-\frac{24}{33}\\=\frac{-44-24}{33}\\=\frac{-68}{33}\)
  6. \(-\left(\frac{-5}{-2}\right)+\left(\frac{3}{-14}\right)\\= \frac{-5}{2}-\frac{3}{14}\\=\frac{-35}{14}-\frac{3}{14}\\=\frac{-35-3}{14}\\=\frac{-38}{14}\\=\frac{-19}{7}\)
  7. \(-\left(\frac{14}{-11}\right)-\left(\frac{-2}{-7}\right)\\= \frac{14}{11}-\frac{2}{7}\\=\frac{98}{77}-\frac{22}{77}\\=\frac{98-22}{77}\\=\frac{76}{77}\)
  8. \(-\left(\frac{-6}{-11}\right)-\left(\frac{10}{3}\right)\\= \frac{-6}{11}-\frac{10}{3}\\=\frac{-18}{33}-\frac{110}{33}\\=\frac{-18-110}{33}\\=\frac{-128}{33}\)
  9. \(+\left(\frac{-6}{5}\right)-\left(\frac{-13}{5}\right)\\= \frac{-6}{5}+\frac{13}{5}\\=\frac{-6+13}{5}\\=\frac{7}{5}\)
  10. \(-\left(\frac{-7}{-8}\right)-\left(\frac{4}{11}\right)\\= \frac{-7}{8}-\frac{4}{11}\\=\frac{-77}{88}-\frac{32}{88}\\=\frac{-77-32}{88}\\=\frac{-109}{88}\)
  11. \(+\left(\frac{-10}{-7}\right)-\left(\frac{3}{4}\right)\\= \frac{10}{7}-\frac{3}{4}\\=\frac{40}{28}-\frac{21}{28}\\=\frac{40-21}{28}\\=\frac{19}{28}\)
  12. \(-\left(\frac{-7}{2}\right)-\left(\frac{10}{13}\right)\\= \frac{7}{2}-\frac{10}{13}\\=\frac{91}{26}-\frac{20}{26}\\=\frac{91-20}{26}\\=\frac{71}{26}\)
Oefeningengenerator wiskundeoefeningen.be 2026-07-24 18:43:20
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