Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{3}{7}\right)-\left(\frac{-7}{-2}\right)\)
2. \(-\left(\frac{-10}{3}\right)+\left(\frac{15}{14}\right)\)
3. \(-\left(\frac{8}{11}\right)+\left(\frac{4}{5}\right)\)
4. \(+\left(\frac{2}{-9}\right)-\left(\frac{-10}{11}\right)\)
5. \(+\left(\frac{11}{-7}\right)-\left(\frac{-7}{2}\right)\)
6. \(-\left(\frac{-2}{13}\right)+\left(\frac{3}{-8}\right)\)
7. \(+\left(\frac{13}{-7}\right)+\left(\frac{5}{-3}\right)\)
8. \(-\left(\frac{8}{3}\right)+\left(\frac{-2}{3}\right)\)
9. \(+\left(\frac{10}{3}\right)+\left(\frac{14}{-11}\right)\)
10. \(-\left(\frac{-6}{7}\right)-\left(\frac{-10}{11}\right)\)
11. \(+\left(\frac{-4}{3}\right)-\left(\frac{-3}{-2}\right)\)
12. \(-\left(\frac{11}{-10}\right)+\left(\frac{9}{-14}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{3}{7}\right)-\left(\frac{-7}{-2}\right)\\= \frac{3}{7}-\frac{7}{2}\\=\frac{6}{14}-\frac{49}{14}\\=\frac{6-49}{14}\\=\frac{-43}{14}\)
2. \(-\left(\frac{-10}{3}\right)+\left(\frac{15}{14}\right)\\= \frac{10}{3}+\frac{15}{14}\\=\frac{140}{42}+\frac{45}{42}\\=\frac{140+45}{42}\\=\frac{185}{42}\)
3. \(-\left(\frac{8}{11}\right)+\left(\frac{4}{5}\right)\\= \frac{-8}{11}+\frac{4}{5}\\=\frac{-40}{55}+\frac{44}{55}\\=\frac{-40+44}{55}\\=\frac{4}{55}\)
4. \(+\left(\frac{2}{-9}\right)-\left(\frac{-10}{11}\right)\\= \frac{-2}{9}+\frac{10}{11}\\=\frac{-22}{99}+\frac{90}{99}\\=\frac{-22+90}{99}\\=\frac{68}{99}\)
5. \(+\left(\frac{11}{-7}\right)-\left(\frac{-7}{2}\right)\\= \frac{-11}{7}+\frac{7}{2}\\=\frac{-22}{14}+\frac{49}{14}\\=\frac{-22+49}{14}\\=\frac{27}{14}\)
6. \(-\left(\frac{-2}{13}\right)+\left(\frac{3}{-8}\right)\\= \frac{2}{13}-\frac{3}{8}\\=\frac{16}{104}-\frac{39}{104}\\=\frac{16-39}{104}\\=\frac{-23}{104}\)
7. \(+\left(\frac{13}{-7}\right)+\left(\frac{5}{-3}\right)\\= \frac{-13}{7}-\frac{5}{3}\\=\frac{-39}{21}-\frac{35}{21}\\=\frac{-39-35}{21}\\=\frac{-74}{21}\)
8. \(-\left(\frac{8}{3}\right)+\left(\frac{-2}{3}\right)\\= \frac{-8}{3}-\frac{2}{3}\\=\frac{-8-2}{3}\\=\frac{-10}{3}\)
9. \(+\left(\frac{10}{3}\right)+\left(\frac{14}{-11}\right)\\= \frac{10}{3}-\frac{14}{11}\\=\frac{110}{33}-\frac{42}{33}\\=\frac{110-42}{33}\\=\frac{68}{33}\)
10. \(-\left(\frac{-6}{7}\right)-\left(\frac{-10}{11}\right)\\= \frac{6}{7}+\frac{10}{11}\\=\frac{66}{77}+\frac{70}{77}\\=\frac{66+70}{77}\\=\frac{136}{77}\)
11. \(+\left(\frac{-4}{3}\right)-\left(\frac{-3}{-2}\right)\\= \frac{-4}{3}-\frac{3}{2}\\=\frac{-8}{6}-\frac{9}{6}\\=\frac{-8-9}{6}\\=\frac{-17}{6}\)
12. \(-\left(\frac{11}{-10}\right)+\left(\frac{9}{-14}\right)\\= \frac{11}{10}-\frac{9}{14}\\=\frac{77}{70}-\frac{45}{70}\\=\frac{77-45}{70}\\=\frac{32}{70}\\=\frac{16}{35}\)