Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-15}{-8}\right)+\left(\frac{-7}{12}\right)\)
2. \(-\left(\frac{6}{-7}\right)-\left(\frac{-5}{4}\right)\)
3. \(-\left(\frac{-8}{-3}\right)+\left(\frac{2}{3}\right)\)
4. \(-\left(\frac{14}{-11}\right)-\left(\frac{-13}{6}\right)\)
5. \(-\left(\frac{-12}{-7}\right)+\left(\frac{10}{-7}\right)\)
6. \(-\left(\frac{8}{13}\right)-\left(\frac{8}{-11}\right)\)
7. \(+\left(\frac{-11}{-5}\right)+\left(\frac{10}{-9}\right)\)
8. \(-\left(\frac{2}{3}\right)-\left(\frac{7}{-8}\right)\)
9. \(+\left(\frac{5}{6}\right)+\left(\frac{-11}{-3}\right)\)
10. \(-\left(\frac{4}{-13}\right)+\left(\frac{12}{-13}\right)\)
11. \(+\left(\frac{9}{11}\right)-\left(\frac{12}{11}\right)\)
12. \(+\left(\frac{-13}{-7}\right)+\left(\frac{-6}{13}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-15}{-8}\right)+\left(\frac{-7}{12}\right)\\= \frac{15}{8}-\frac{7}{12}\\=\frac{45}{24}-\frac{14}{24}\\=\frac{45-14}{24}\\=\frac{31}{24}\)
2. \(-\left(\frac{6}{-7}\right)-\left(\frac{-5}{4}\right)\\= \frac{6}{7}+\frac{5}{4}\\=\frac{24}{28}+\frac{35}{28}\\=\frac{24+35}{28}\\=\frac{59}{28}\)
3. \(-\left(\frac{-8}{-3}\right)+\left(\frac{2}{3}\right)\\= \frac{-8}{3}+\frac{2}{3}\\=\frac{-8+2}{3}\\=\frac{-6}{3}\\=\frac{-2}{1}\)
4. \(-\left(\frac{14}{-11}\right)-\left(\frac{-13}{6}\right)\\= \frac{14}{11}+\frac{13}{6}\\=\frac{84}{66}+\frac{143}{66}\\=\frac{84+143}{66}\\=\frac{227}{66}\)
5. \(-\left(\frac{-12}{-7}\right)+\left(\frac{10}{-7}\right)\\= \frac{-12}{7}-\frac{10}{7}\\=\frac{-12-10}{7}\\=\frac{-22}{7}\)
6. \(-\left(\frac{8}{13}\right)-\left(\frac{8}{-11}\right)\\= \frac{-8}{13}+\frac{8}{11}\\=\frac{-88}{143}+\frac{104}{143}\\=\frac{-88+104}{143}\\=\frac{16}{143}\)
7. \(+\left(\frac{-11}{-5}\right)+\left(\frac{10}{-9}\right)\\= \frac{11}{5}-\frac{10}{9}\\=\frac{99}{45}-\frac{50}{45}\\=\frac{99-50}{45}\\=\frac{49}{45}\)
8. \(-\left(\frac{2}{3}\right)-\left(\frac{7}{-8}\right)\\= \frac{-2}{3}+\frac{7}{8}\\=\frac{-16}{24}+\frac{21}{24}\\=\frac{-16+21}{24}\\=\frac{5}{24}\)
9. \(+\left(\frac{5}{6}\right)+\left(\frac{-11}{-3}\right)\\= \frac{5}{6}+\frac{11}{3}\\=\frac{5+11}{6}\\=\frac{16}{6}\\=\frac{8}{3}\)
10. \(-\left(\frac{4}{-13}\right)+\left(\frac{12}{-13}\right)\\= \frac{4}{13}-\frac{12}{13}\\=\frac{4-12}{13}\\=\frac{-8}{13}\)
11. \(+\left(\frac{9}{11}\right)-\left(\frac{12}{11}\right)\\= \frac{9}{11}-\frac{12}{11}\\=\frac{9-12}{11}\\=\frac{-3}{11}\)
12. \(+\left(\frac{-13}{-7}\right)+\left(\frac{-6}{13}\right)\\= \frac{13}{7}-\frac{6}{13}\\=\frac{169}{91}-\frac{42}{91}\\=\frac{169-42}{91}\\=\frac{127}{91}\)