Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-3}{-11}\right)+\left(\frac{8}{3}\right)\)
2. \(-\left(\frac{13}{10}\right)-\left(\frac{-13}{-2}\right)\)
3. \(-\left(\frac{3}{-14}\right)-\left(\frac{4}{11}\right)\)
4. \(+\left(\frac{2}{5}\right)-\left(\frac{12}{11}\right)\)
5. \(-\left(\frac{13}{14}\right)+\left(\frac{9}{13}\right)\)
6. \(+\left(\frac{12}{-5}\right)+\left(\frac{10}{-3}\right)\)
7. \(-\left(\frac{15}{11}\right)+\left(\frac{13}{3}\right)\)
8. \(+\left(\frac{-11}{5}\right)+\left(\frac{-5}{-14}\right)\)
9. \(+\left(\frac{9}{5}\right)-\left(\frac{9}{14}\right)\)
10. \(-\left(\frac{9}{4}\right)-\left(\frac{-10}{-7}\right)\)
11. \(+\left(\frac{13}{4}\right)+\left(\frac{9}{-7}\right)\)
12. \(+\left(\frac{-10}{-3}\right)-\left(\frac{6}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-3}{-11}\right)+\left(\frac{8}{3}\right)\\= \frac{-3}{11}+\frac{8}{3}\\=\frac{-9}{33}+\frac{88}{33}\\=\frac{-9+88}{33}\\=\frac{79}{33}\)
2. \(-\left(\frac{13}{10}\right)-\left(\frac{-13}{-2}\right)\\= \frac{-13}{10}-\frac{13}{2}\\=\frac{-13-13}{10}\\=\frac{-26}{10}\\=\frac{-13}{5}\)
3. \(-\left(\frac{3}{-14}\right)-\left(\frac{4}{11}\right)\\= \frac{3}{14}-\frac{4}{11}\\=\frac{33}{154}-\frac{56}{154}\\=\frac{33-56}{154}\\=\frac{-23}{154}\)
4. \(+\left(\frac{2}{5}\right)-\left(\frac{12}{11}\right)\\= \frac{2}{5}-\frac{12}{11}\\=\frac{22}{55}-\frac{60}{55}\\=\frac{22-60}{55}\\=\frac{-38}{55}\)
5. \(-\left(\frac{13}{14}\right)+\left(\frac{9}{13}\right)\\= \frac{-13}{14}+\frac{9}{13}\\=\frac{-169}{182}+\frac{126}{182}\\=\frac{-169+126}{182}\\=\frac{-43}{182}\)
6. \(+\left(\frac{12}{-5}\right)+\left(\frac{10}{-3}\right)\\= \frac{-12}{5}-\frac{10}{3}\\=\frac{-36}{15}-\frac{50}{15}\\=\frac{-36-50}{15}\\=\frac{-86}{15}\)
7. \(-\left(\frac{15}{11}\right)+\left(\frac{13}{3}\right)\\= \frac{-15}{11}+\frac{13}{3}\\=\frac{-45}{33}+\frac{143}{33}\\=\frac{-45+143}{33}\\=\frac{98}{33}\)
8. \(+\left(\frac{-11}{5}\right)+\left(\frac{-5}{-14}\right)\\= \frac{-11}{5}+\frac{5}{14}\\=\frac{-154}{70}+\frac{25}{70}\\=\frac{-154+25}{70}\\=\frac{-129}{70}\)
9. \(+\left(\frac{9}{5}\right)-\left(\frac{9}{14}\right)\\= \frac{9}{5}-\frac{9}{14}\\=\frac{126}{70}-\frac{45}{70}\\=\frac{126-45}{70}\\=\frac{81}{70}\)
10. \(-\left(\frac{9}{4}\right)-\left(\frac{-10}{-7}\right)\\= \frac{-9}{4}-\frac{10}{7}\\=\frac{-63}{28}-\frac{40}{28}\\=\frac{-63-40}{28}\\=\frac{-103}{28}\)
11. \(+\left(\frac{13}{4}\right)+\left(\frac{9}{-7}\right)\\= \frac{13}{4}-\frac{9}{7}\\=\frac{91}{28}-\frac{36}{28}\\=\frac{91-36}{28}\\=\frac{55}{28}\)
12. \(+\left(\frac{-10}{-3}\right)-\left(\frac{6}{-5}\right)\\= \frac{10}{3}+\frac{6}{5}\\=\frac{50}{15}+\frac{18}{15}\\=\frac{50+18}{15}\\=\frac{68}{15}\)