Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{9}{5}\right)-\left(\frac{10}{3}\right)\)
2. \(-\left(\frac{-4}{5}\right)+\left(\frac{-6}{-5}\right)\)
3. \(+\left(\frac{-13}{-4}\right)-\left(\frac{-8}{11}\right)\)
4. \(-\left(\frac{-4}{5}\right)+\left(\frac{-7}{8}\right)\)
5. \(+\left(\frac{11}{12}\right)+\left(\frac{-5}{-6}\right)\)
6. \(-\left(\frac{14}{9}\right)+\left(\frac{9}{2}\right)\)
7. \(-\left(\frac{-5}{-11}\right)-\left(\frac{5}{7}\right)\)
8. \(+\left(\frac{-8}{9}\right)-\left(\frac{5}{4}\right)\)
9. \(+\left(\frac{9}{14}\right)-\left(\frac{-3}{-2}\right)\)
10. \(-\left(\frac{13}{-4}\right)+\left(\frac{-3}{7}\right)\)
11. \(+\left(\frac{-7}{-2}\right)-\left(\frac{-5}{3}\right)\)
12. \(+\left(\frac{-14}{-9}\right)-\left(\frac{10}{13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{9}{5}\right)-\left(\frac{10}{3}\right)\\= \frac{-9}{5}-\frac{10}{3}\\=\frac{-27}{15}-\frac{50}{15}\\=\frac{-27-50}{15}\\=\frac{-77}{15}\)
2. \(-\left(\frac{-4}{5}\right)+\left(\frac{-6}{-5}\right)\\= \frac{4}{5}+\frac{6}{5}\\=\frac{4+6}{5}\\=\frac{10}{5}\\=\frac{2}{1}\)
3. \(+\left(\frac{-13}{-4}\right)-\left(\frac{-8}{11}\right)\\= \frac{13}{4}+\frac{8}{11}\\=\frac{143}{44}+\frac{32}{44}\\=\frac{143+32}{44}\\=\frac{175}{44}\)
4. \(-\left(\frac{-4}{5}\right)+\left(\frac{-7}{8}\right)\\= \frac{4}{5}-\frac{7}{8}\\=\frac{32}{40}-\frac{35}{40}\\=\frac{32-35}{40}\\=\frac{-3}{40}\)
5. \(+\left(\frac{11}{12}\right)+\left(\frac{-5}{-6}\right)\\= \frac{11}{12}+\frac{5}{6}\\=\frac{11+5}{12}\\=\frac{16}{12}\\=\frac{4}{3}\)
6. \(-\left(\frac{14}{9}\right)+\left(\frac{9}{2}\right)\\= \frac{-14}{9}+\frac{9}{2}\\=\frac{-28}{18}+\frac{81}{18}\\=\frac{-28+81}{18}\\=\frac{53}{18}\)
7. \(-\left(\frac{-5}{-11}\right)-\left(\frac{5}{7}\right)\\= \frac{-5}{11}-\frac{5}{7}\\=\frac{-35}{77}-\frac{55}{77}\\=\frac{-35-55}{77}\\=\frac{-90}{77}\)
8. \(+\left(\frac{-8}{9}\right)-\left(\frac{5}{4}\right)\\= \frac{-8}{9}-\frac{5}{4}\\=\frac{-32}{36}-\frac{45}{36}\\=\frac{-32-45}{36}\\=\frac{-77}{36}\)
9. \(+\left(\frac{9}{14}\right)-\left(\frac{-3}{-2}\right)\\= \frac{9}{14}-\frac{3}{2}\\=\frac{9-3}{14}\\=\frac{6}{14}\\=\frac{3}{7}\)
10. \(-\left(\frac{13}{-4}\right)+\left(\frac{-3}{7}\right)\\= \frac{13}{4}-\frac{3}{7}\\=\frac{91}{28}-\frac{12}{28}\\=\frac{91-12}{28}\\=\frac{79}{28}\)
11. \(+\left(\frac{-7}{-2}\right)-\left(\frac{-5}{3}\right)\\= \frac{7}{2}+\frac{5}{3}\\=\frac{21}{6}+\frac{10}{6}\\=\frac{21+10}{6}\\=\frac{31}{6}\)
12. \(+\left(\frac{-14}{-9}\right)-\left(\frac{10}{13}\right)\\= \frac{14}{9}-\frac{10}{13}\\=\frac{182}{117}-\frac{90}{117}\\=\frac{182-90}{117}\\=\frac{92}{117}\)