Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-3}{10}\right)+\left(\frac{-6}{-13}\right)\)
2. \(-\left(\frac{10}{-7}\right)+\left(\frac{-7}{5}\right)\)
3. \(-\left(\frac{9}{13}\right)+\left(\frac{-9}{8}\right)\)
4. \(+\left(\frac{9}{2}\right)-\left(\frac{4}{5}\right)\)
5. \(-\left(\frac{14}{9}\right)-\left(\frac{12}{-5}\right)\)
6. \(-\left(\frac{-14}{5}\right)+\left(\frac{3}{4}\right)\)
7. \(-\left(\frac{-14}{-3}\right)-\left(\frac{13}{-8}\right)\)
8. \(-\left(\frac{4}{9}\right)-\left(\frac{12}{5}\right)\)
9. \(+\left(\frac{-10}{13}\right)-\left(\frac{-15}{-14}\right)\)
10. \(-\left(\frac{-15}{13}\right)-\left(\frac{-8}{7}\right)\)
11. \(-\left(\frac{-4}{11}\right)+\left(\frac{6}{11}\right)\)
12. \(+\left(\frac{13}{7}\right)+\left(\frac{-13}{14}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-3}{10}\right)+\left(\frac{-6}{-13}\right)\\= \frac{-3}{10}+\frac{6}{13}\\=\frac{-39}{130}+\frac{60}{130}\\=\frac{-39+60}{130}\\=\frac{21}{130}\)
2. \(-\left(\frac{10}{-7}\right)+\left(\frac{-7}{5}\right)\\= \frac{10}{7}-\frac{7}{5}\\=\frac{50}{35}-\frac{49}{35}\\=\frac{50-49}{35}\\=\frac{1}{35}\)
3. \(-\left(\frac{9}{13}\right)+\left(\frac{-9}{8}\right)\\= \frac{-9}{13}-\frac{9}{8}\\=\frac{-72}{104}-\frac{117}{104}\\=\frac{-72-117}{104}\\=\frac{-189}{104}\)
4. \(+\left(\frac{9}{2}\right)-\left(\frac{4}{5}\right)\\= \frac{9}{2}-\frac{4}{5}\\=\frac{45}{10}-\frac{8}{10}\\=\frac{45-8}{10}\\=\frac{37}{10}\)
5. \(-\left(\frac{14}{9}\right)-\left(\frac{12}{-5}\right)\\= \frac{-14}{9}+\frac{12}{5}\\=\frac{-70}{45}+\frac{108}{45}\\=\frac{-70+108}{45}\\=\frac{38}{45}\)
6. \(-\left(\frac{-14}{5}\right)+\left(\frac{3}{4}\right)\\= \frac{14}{5}+\frac{3}{4}\\=\frac{56}{20}+\frac{15}{20}\\=\frac{56+15}{20}\\=\frac{71}{20}\)
7. \(-\left(\frac{-14}{-3}\right)-\left(\frac{13}{-8}\right)\\= \frac{-14}{3}+\frac{13}{8}\\=\frac{-112}{24}+\frac{39}{24}\\=\frac{-112+39}{24}\\=\frac{-73}{24}\)
8. \(-\left(\frac{4}{9}\right)-\left(\frac{12}{5}\right)\\= \frac{-4}{9}-\frac{12}{5}\\=\frac{-20}{45}-\frac{108}{45}\\=\frac{-20-108}{45}\\=\frac{-128}{45}\)
9. \(+\left(\frac{-10}{13}\right)-\left(\frac{-15}{-14}\right)\\= \frac{-10}{13}-\frac{15}{14}\\=\frac{-140}{182}-\frac{195}{182}\\=\frac{-140-195}{182}\\=\frac{-335}{182}\)
10. \(-\left(\frac{-15}{13}\right)-\left(\frac{-8}{7}\right)\\= \frac{15}{13}+\frac{8}{7}\\=\frac{105}{91}+\frac{104}{91}\\=\frac{105+104}{91}\\=\frac{209}{91}\)
11. \(-\left(\frac{-4}{11}\right)+\left(\frac{6}{11}\right)\\= \frac{4}{11}+\frac{6}{11}\\=\frac{4+6}{11}\\=\frac{10}{11}\)
12. \(+\left(\frac{13}{7}\right)+\left(\frac{-13}{14}\right)\\= \frac{13}{7}-\frac{13}{14}\\=\frac{26}{14}-\frac{13}{14}\\=\frac{26-13}{14}\\=\frac{13}{14}\)