Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-11}{-6}\right)+\left(\frac{-14}{5}\right)\)
2. \(+\left(\frac{-5}{2}\right)-\left(\frac{12}{7}\right)\)
3. \(-\left(\frac{11}{14}\right)+\left(\frac{-15}{-8}\right)\)
4. \(+\left(\frac{12}{-5}\right)-\left(\frac{-13}{-12}\right)\)
5. \(-\left(\frac{9}{8}\right)-\left(\frac{15}{7}\right)\)
6. \(+\left(\frac{13}{11}\right)-\left(\frac{-10}{13}\right)\)
7. \(+\left(\frac{-12}{-5}\right)+\left(\frac{3}{-8}\right)\)
8. \(-\left(\frac{12}{7}\right)-\left(\frac{-8}{3}\right)\)
9. \(+\left(\frac{11}{8}\right)-\left(\frac{-13}{-14}\right)\)
10. \(-\left(\frac{-8}{-9}\right)-\left(\frac{4}{7}\right)\)
11. \(-\left(\frac{10}{7}\right)-\left(\frac{-5}{-14}\right)\)
12. \(-\left(\frac{12}{-7}\right)-\left(\frac{-13}{-4}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-11}{-6}\right)+\left(\frac{-14}{5}\right)\\= \frac{-11}{6}-\frac{14}{5}\\=\frac{-55}{30}-\frac{84}{30}\\=\frac{-55-84}{30}\\=\frac{-139}{30}\)
2. \(+\left(\frac{-5}{2}\right)-\left(\frac{12}{7}\right)\\= \frac{-5}{2}-\frac{12}{7}\\=\frac{-35}{14}-\frac{24}{14}\\=\frac{-35-24}{14}\\=\frac{-59}{14}\)
3. \(-\left(\frac{11}{14}\right)+\left(\frac{-15}{-8}\right)\\= \frac{-11}{14}+\frac{15}{8}\\=\frac{-44}{56}+\frac{105}{56}\\=\frac{-44+105}{56}\\=\frac{61}{56}\)
4. \(+\left(\frac{12}{-5}\right)-\left(\frac{-13}{-12}\right)\\= \frac{-12}{5}-\frac{13}{12}\\=\frac{-144}{60}-\frac{65}{60}\\=\frac{-144-65}{60}\\=\frac{-209}{60}\)
5. \(-\left(\frac{9}{8}\right)-\left(\frac{15}{7}\right)\\= \frac{-9}{8}-\frac{15}{7}\\=\frac{-63}{56}-\frac{120}{56}\\=\frac{-63-120}{56}\\=\frac{-183}{56}\)
6. \(+\left(\frac{13}{11}\right)-\left(\frac{-10}{13}\right)\\= \frac{13}{11}+\frac{10}{13}\\=\frac{169}{143}+\frac{110}{143}\\=\frac{169+110}{143}\\=\frac{279}{143}\)
7. \(+\left(\frac{-12}{-5}\right)+\left(\frac{3}{-8}\right)\\= \frac{12}{5}-\frac{3}{8}\\=\frac{96}{40}-\frac{15}{40}\\=\frac{96-15}{40}\\=\frac{81}{40}\)
8. \(-\left(\frac{12}{7}\right)-\left(\frac{-8}{3}\right)\\= \frac{-12}{7}+\frac{8}{3}\\=\frac{-36}{21}+\frac{56}{21}\\=\frac{-36+56}{21}\\=\frac{20}{21}\)
9. \(+\left(\frac{11}{8}\right)-\left(\frac{-13}{-14}\right)\\= \frac{11}{8}-\frac{13}{14}\\=\frac{77}{56}-\frac{52}{56}\\=\frac{77-52}{56}\\=\frac{25}{56}\)
10. \(-\left(\frac{-8}{-9}\right)-\left(\frac{4}{7}\right)\\= \frac{-8}{9}-\frac{4}{7}\\=\frac{-56}{63}-\frac{36}{63}\\=\frac{-56-36}{63}\\=\frac{-92}{63}\)
11. \(-\left(\frac{10}{7}\right)-\left(\frac{-5}{-14}\right)\\= \frac{-10}{7}-\frac{5}{14}\\=\frac{-20}{14}-\frac{5}{14}\\=\frac{-20-5}{14}\\=\frac{-25}{14}\)
12. \(-\left(\frac{12}{-7}\right)-\left(\frac{-13}{-4}\right)\\= \frac{12}{7}-\frac{13}{4}\\=\frac{48}{28}-\frac{91}{28}\\=\frac{48-91}{28}\\=\frac{-43}{28}\)