Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{15}{-14}\right)-\left(\frac{11}{13}\right)\)
2. \(-\left(\frac{-9}{5}\right)-\left(\frac{14}{3}\right)\)
3. \(+\left(\frac{-7}{-8}\right)-\left(\frac{-15}{11}\right)\)
4. \(+\left(\frac{2}{-3}\right)+\left(\frac{-14}{-13}\right)\)
5. \(+\left(\frac{-8}{-3}\right)+\left(\frac{-4}{-11}\right)\)
6. \(-\left(\frac{-13}{-11}\right)-\left(\frac{13}{10}\right)\)
7. \(+\left(\frac{-11}{-6}\right)+\left(\frac{-5}{-7}\right)\)
8. \(+\left(\frac{-15}{7}\right)-\left(\frac{2}{5}\right)\)
9. \(+\left(\frac{10}{3}\right)-\left(\frac{14}{5}\right)\)
10. \(+\left(\frac{6}{-11}\right)+\left(\frac{8}{-5}\right)\)
11. \(+\left(\frac{-7}{5}\right)+\left(\frac{-15}{11}\right)\)
12. \(-\left(\frac{-5}{3}\right)-\left(\frac{3}{-10}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{15}{-14}\right)-\left(\frac{11}{13}\right)\\= \frac{-15}{14}-\frac{11}{13}\\=\frac{-195}{182}-\frac{154}{182}\\=\frac{-195-154}{182}\\=\frac{-349}{182}\)
2. \(-\left(\frac{-9}{5}\right)-\left(\frac{14}{3}\right)\\= \frac{9}{5}-\frac{14}{3}\\=\frac{27}{15}-\frac{70}{15}\\=\frac{27-70}{15}\\=\frac{-43}{15}\)
3. \(+\left(\frac{-7}{-8}\right)-\left(\frac{-15}{11}\right)\\= \frac{7}{8}+\frac{15}{11}\\=\frac{77}{88}+\frac{120}{88}\\=\frac{77+120}{88}\\=\frac{197}{88}\)
4. \(+\left(\frac{2}{-3}\right)+\left(\frac{-14}{-13}\right)\\= \frac{-2}{3}+\frac{14}{13}\\=\frac{-26}{39}+\frac{42}{39}\\=\frac{-26+42}{39}\\=\frac{16}{39}\)
5. \(+\left(\frac{-8}{-3}\right)+\left(\frac{-4}{-11}\right)\\= \frac{8}{3}+\frac{4}{11}\\=\frac{88}{33}+\frac{12}{33}\\=\frac{88+12}{33}\\=\frac{100}{33}\)
6. \(-\left(\frac{-13}{-11}\right)-\left(\frac{13}{10}\right)\\= \frac{-13}{11}-\frac{13}{10}\\=\frac{-130}{110}-\frac{143}{110}\\=\frac{-130-143}{110}\\=\frac{-273}{110}\)
7. \(+\left(\frac{-11}{-6}\right)+\left(\frac{-5}{-7}\right)\\= \frac{11}{6}+\frac{5}{7}\\=\frac{77}{42}+\frac{30}{42}\\=\frac{77+30}{42}\\=\frac{107}{42}\)
8. \(+\left(\frac{-15}{7}\right)-\left(\frac{2}{5}\right)\\= \frac{-15}{7}-\frac{2}{5}\\=\frac{-75}{35}-\frac{14}{35}\\=\frac{-75-14}{35}\\=\frac{-89}{35}\)
9. \(+\left(\frac{10}{3}\right)-\left(\frac{14}{5}\right)\\= \frac{10}{3}-\frac{14}{5}\\=\frac{50}{15}-\frac{42}{15}\\=\frac{50-42}{15}\\=\frac{8}{15}\)
10. \(+\left(\frac{6}{-11}\right)+\left(\frac{8}{-5}\right)\\= \frac{-6}{11}-\frac{8}{5}\\=\frac{-30}{55}-\frac{88}{55}\\=\frac{-30-88}{55}\\=\frac{-118}{55}\)
11. \(+\left(\frac{-7}{5}\right)+\left(\frac{-15}{11}\right)\\= \frac{-7}{5}-\frac{15}{11}\\=\frac{-77}{55}-\frac{75}{55}\\=\frac{-77-75}{55}\\=\frac{-152}{55}\)
12. \(-\left(\frac{-5}{3}\right)-\left(\frac{3}{-10}\right)\\= \frac{5}{3}+\frac{3}{10}\\=\frac{50}{30}+\frac{9}{30}\\=\frac{50+9}{30}\\=\frac{59}{30}\)