Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{4}{7}\right)-\left(\frac{-2}{-13}\right)\)
2. \(-\left(\frac{6}{5}\right)-\left(\frac{7}{-9}\right)\)
3. \(-\left(\frac{4}{7}\right)-\left(\frac{-4}{-7}\right)\)
4. \(-\left(\frac{6}{5}\right)+\left(\frac{6}{7}\right)\)
5. \(+\left(\frac{4}{9}\right)+\left(\frac{14}{5}\right)\)
6. \(+\left(\frac{13}{-3}\right)-\left(\frac{-6}{11}\right)\)
7. \(+\left(\frac{4}{9}\right)-\left(\frac{4}{3}\right)\)
8. \(+\left(\frac{-9}{2}\right)-\left(\frac{15}{11}\right)\)
9. \(+\left(\frac{11}{-10}\right)-\left(\frac{5}{6}\right)\)
10. \(+\left(\frac{-5}{-13}\right)+\left(\frac{11}{-12}\right)\)
11. \(+\left(\frac{15}{11}\right)-\left(\frac{5}{3}\right)\)
12. \(-\left(\frac{-7}{-2}\right)-\left(\frac{-15}{7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{4}{7}\right)-\left(\frac{-2}{-13}\right)\\= \frac{-4}{7}-\frac{2}{13}\\=\frac{-52}{91}-\frac{14}{91}\\=\frac{-52-14}{91}\\=\frac{-66}{91}\)
2. \(-\left(\frac{6}{5}\right)-\left(\frac{7}{-9}\right)\\= \frac{-6}{5}+\frac{7}{9}\\=\frac{-54}{45}+\frac{35}{45}\\=\frac{-54+35}{45}\\=\frac{-19}{45}\)
3. \(-\left(\frac{4}{7}\right)-\left(\frac{-4}{-7}\right)\\= \frac{-4}{7}-\frac{4}{7}\\=\frac{-4-4}{7}\\=\frac{-8}{7}\)
4. \(-\left(\frac{6}{5}\right)+\left(\frac{6}{7}\right)\\= \frac{-6}{5}+\frac{6}{7}\\=\frac{-42}{35}+\frac{30}{35}\\=\frac{-42+30}{35}\\=\frac{-12}{35}\)
5. \(+\left(\frac{4}{9}\right)+\left(\frac{14}{5}\right)\\= \frac{4}{9}+\frac{14}{5}\\=\frac{20}{45}+\frac{126}{45}\\=\frac{20+126}{45}\\=\frac{146}{45}\)
6. \(+\left(\frac{13}{-3}\right)-\left(\frac{-6}{11}\right)\\= \frac{-13}{3}+\frac{6}{11}\\=\frac{-143}{33}+\frac{18}{33}\\=\frac{-143+18}{33}\\=\frac{-125}{33}\)
7. \(+\left(\frac{4}{9}\right)-\left(\frac{4}{3}\right)\\= \frac{4}{9}-\frac{4}{3}\\=\frac{4-4}{9}\\=\frac{0}{9}\\=\frac{0}{1}\)
8. \(+\left(\frac{-9}{2}\right)-\left(\frac{15}{11}\right)\\= \frac{-9}{2}-\frac{15}{11}\\=\frac{-99}{22}-\frac{30}{22}\\=\frac{-99-30}{22}\\=\frac{-129}{22}\)
9. \(+\left(\frac{11}{-10}\right)-\left(\frac{5}{6}\right)\\= \frac{-11}{10}-\frac{5}{6}\\=\frac{-33}{30}-\frac{25}{30}\\=\frac{-33-25}{30}\\=\frac{-58}{30}\\=\frac{-29}{15}\)
10. \(+\left(\frac{-5}{-13}\right)+\left(\frac{11}{-12}\right)\\= \frac{5}{13}-\frac{11}{12}\\=\frac{60}{156}-\frac{143}{156}\\=\frac{60-143}{156}\\=\frac{-83}{156}\)
11. \(+\left(\frac{15}{11}\right)-\left(\frac{5}{3}\right)\\= \frac{15}{11}-\frac{5}{3}\\=\frac{45}{33}-\frac{55}{33}\\=\frac{45-55}{33}\\=\frac{-10}{33}\)
12. \(-\left(\frac{-7}{-2}\right)-\left(\frac{-15}{7}\right)\\= \frac{-7}{2}+\frac{15}{7}\\=\frac{-49}{14}+\frac{30}{14}\\=\frac{-49+30}{14}\\=\frac{-19}{14}\)