Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{2}{11}\right)+\left(\frac{-6}{-5}\right)\)
2. \(-\left(\frac{4}{-5}\right)+\left(\frac{12}{-7}\right)\)
3. \(+\left(\frac{-10}{-9}\right)-\left(\frac{-15}{2}\right)\)
4. \(-\left(\frac{-15}{7}\right)+\left(\frac{-9}{2}\right)\)
5. \(+\left(\frac{13}{11}\right)+\left(\frac{-5}{6}\right)\)
6. \(+\left(\frac{-5}{12}\right)-\left(\frac{3}{-11}\right)\)
7. \(-\left(\frac{3}{13}\right)+\left(\frac{-2}{-11}\right)\)
8. \(+\left(\frac{14}{-9}\right)+\left(\frac{10}{-3}\right)\)
9. \(-\left(\frac{4}{3}\right)-\left(\frac{-15}{13}\right)\)
10. \(+\left(\frac{-7}{-3}\right)+\left(\frac{-3}{2}\right)\)
11. \(-\left(\frac{14}{-9}\right)+\left(\frac{5}{6}\right)\)
12. \(-\left(\frac{-9}{5}\right)-\left(\frac{-8}{3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{2}{11}\right)+\left(\frac{-6}{-5}\right)\\= \frac{2}{11}+\frac{6}{5}\\=\frac{10}{55}+\frac{66}{55}\\=\frac{10+66}{55}\\=\frac{76}{55}\)
2. \(-\left(\frac{4}{-5}\right)+\left(\frac{12}{-7}\right)\\= \frac{4}{5}-\frac{12}{7}\\=\frac{28}{35}-\frac{60}{35}\\=\frac{28-60}{35}\\=\frac{-32}{35}\)
3. \(+\left(\frac{-10}{-9}\right)-\left(\frac{-15}{2}\right)\\= \frac{10}{9}+\frac{15}{2}\\=\frac{20}{18}+\frac{135}{18}\\=\frac{20+135}{18}\\=\frac{155}{18}\)
4. \(-\left(\frac{-15}{7}\right)+\left(\frac{-9}{2}\right)\\= \frac{15}{7}-\frac{9}{2}\\=\frac{30}{14}-\frac{63}{14}\\=\frac{30-63}{14}\\=\frac{-33}{14}\)
5. \(+\left(\frac{13}{11}\right)+\left(\frac{-5}{6}\right)\\= \frac{13}{11}-\frac{5}{6}\\=\frac{78}{66}-\frac{55}{66}\\=\frac{78-55}{66}\\=\frac{23}{66}\)
6. \(+\left(\frac{-5}{12}\right)-\left(\frac{3}{-11}\right)\\= \frac{-5}{12}+\frac{3}{11}\\=\frac{-55}{132}+\frac{36}{132}\\=\frac{-55+36}{132}\\=\frac{-19}{132}\)
7. \(-\left(\frac{3}{13}\right)+\left(\frac{-2}{-11}\right)\\= \frac{-3}{13}+\frac{2}{11}\\=\frac{-33}{143}+\frac{26}{143}\\=\frac{-33+26}{143}\\=\frac{-7}{143}\)
8. \(+\left(\frac{14}{-9}\right)+\left(\frac{10}{-3}\right)\\= \frac{-14}{9}-\frac{10}{3}\\=\frac{-14-10}{9}\\=\frac{-24}{9}\\=\frac{-8}{3}\)
9. \(-\left(\frac{4}{3}\right)-\left(\frac{-15}{13}\right)\\= \frac{-4}{3}+\frac{15}{13}\\=\frac{-52}{39}+\frac{45}{39}\\=\frac{-52+45}{39}\\=\frac{-7}{39}\)
10. \(+\left(\frac{-7}{-3}\right)+\left(\frac{-3}{2}\right)\\= \frac{7}{3}-\frac{3}{2}\\=\frac{14}{6}-\frac{9}{6}\\=\frac{14-9}{6}\\=\frac{5}{6}\)
11. \(-\left(\frac{14}{-9}\right)+\left(\frac{5}{6}\right)\\= \frac{14}{9}+\frac{5}{6}\\=\frac{28}{18}+\frac{15}{18}\\=\frac{28+15}{18}\\=\frac{43}{18}\)
12. \(-\left(\frac{-9}{5}\right)-\left(\frac{-8}{3}\right)\\= \frac{9}{5}+\frac{8}{3}\\=\frac{27}{15}+\frac{40}{15}\\=\frac{27+40}{15}\\=\frac{67}{15}\)