Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{3}{-2}\right)+\left(\frac{2}{-11}\right)\)
2. \(-\left(\frac{14}{-9}\right)-\left(\frac{8}{-7}\right)\)
3. \(+\left(\frac{-4}{5}\right)-\left(\frac{-2}{-11}\right)\)
4. \(+\left(\frac{-7}{-5}\right)+\left(\frac{10}{-7}\right)\)
5. \(+\left(\frac{-9}{-14}\right)+\left(\frac{7}{-11}\right)\)
6. \(-\left(\frac{15}{-7}\right)-\left(\frac{-10}{11}\right)\)
7. \(+\left(\frac{14}{-13}\right)+\left(\frac{9}{-10}\right)\)
8. \(+\left(\frac{15}{4}\right)+\left(\frac{-5}{-9}\right)\)
9. \(-\left(\frac{-4}{5}\right)-\left(\frac{4}{13}\right)\)
10. \(-\left(\frac{4}{7}\right)-\left(\frac{-2}{3}\right)\)
11. \(-\left(\frac{-13}{12}\right)+\left(\frac{-8}{9}\right)\)
12. \(-\left(\frac{-6}{-5}\right)-\left(\frac{9}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{3}{-2}\right)+\left(\frac{2}{-11}\right)\\= \frac{-3}{2}-\frac{2}{11}\\=\frac{-33}{22}-\frac{4}{22}\\=\frac{-33-4}{22}\\=\frac{-37}{22}\)
2. \(-\left(\frac{14}{-9}\right)-\left(\frac{8}{-7}\right)\\= \frac{14}{9}+\frac{8}{7}\\=\frac{98}{63}+\frac{72}{63}\\=\frac{98+72}{63}\\=\frac{170}{63}\)
3. \(+\left(\frac{-4}{5}\right)-\left(\frac{-2}{-11}\right)\\= \frac{-4}{5}-\frac{2}{11}\\=\frac{-44}{55}-\frac{10}{55}\\=\frac{-44-10}{55}\\=\frac{-54}{55}\)
4. \(+\left(\frac{-7}{-5}\right)+\left(\frac{10}{-7}\right)\\= \frac{7}{5}-\frac{10}{7}\\=\frac{49}{35}-\frac{50}{35}\\=\frac{49-50}{35}\\=\frac{-1}{35}\)
5. \(+\left(\frac{-9}{-14}\right)+\left(\frac{7}{-11}\right)\\= \frac{9}{14}-\frac{7}{11}\\=\frac{99}{154}-\frac{98}{154}\\=\frac{99-98}{154}\\=\frac{1}{154}\)
6. \(-\left(\frac{15}{-7}\right)-\left(\frac{-10}{11}\right)\\= \frac{15}{7}+\frac{10}{11}\\=\frac{165}{77}+\frac{70}{77}\\=\frac{165+70}{77}\\=\frac{235}{77}\)
7. \(+\left(\frac{14}{-13}\right)+\left(\frac{9}{-10}\right)\\= \frac{-14}{13}-\frac{9}{10}\\=\frac{-140}{130}-\frac{117}{130}\\=\frac{-140-117}{130}\\=\frac{-257}{130}\)
8. \(+\left(\frac{15}{4}\right)+\left(\frac{-5}{-9}\right)\\= \frac{15}{4}+\frac{5}{9}\\=\frac{135}{36}+\frac{20}{36}\\=\frac{135+20}{36}\\=\frac{155}{36}\)
9. \(-\left(\frac{-4}{5}\right)-\left(\frac{4}{13}\right)\\= \frac{4}{5}-\frac{4}{13}\\=\frac{52}{65}-\frac{20}{65}\\=\frac{52-20}{65}\\=\frac{32}{65}\)
10. \(-\left(\frac{4}{7}\right)-\left(\frac{-2}{3}\right)\\= \frac{-4}{7}+\frac{2}{3}\\=\frac{-12}{21}+\frac{14}{21}\\=\frac{-12+14}{21}\\=\frac{2}{21}\)
11. \(-\left(\frac{-13}{12}\right)+\left(\frac{-8}{9}\right)\\= \frac{13}{12}-\frac{8}{9}\\=\frac{39}{36}-\frac{32}{36}\\=\frac{39-32}{36}\\=\frac{7}{36}\)
12. \(-\left(\frac{-6}{-5}\right)-\left(\frac{9}{-7}\right)\\= \frac{-6}{5}+\frac{9}{7}\\=\frac{-42}{35}+\frac{45}{35}\\=\frac{-42+45}{35}\\=\frac{3}{35}\)