Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-7}{-13}\right)-\left(\frac{3}{7}\right)\)
2. \(+\left(\frac{7}{-5}\right)-\left(\frac{5}{-6}\right)\)
3. \(+\left(\frac{-3}{-4}\right)+\left(\frac{5}{-6}\right)\)
4. \(+\left(\frac{10}{-7}\right)+\left(\frac{15}{-2}\right)\)
5. \(+\left(\frac{-10}{9}\right)+\left(\frac{-9}{-10}\right)\)
6. \(+\left(\frac{-10}{-3}\right)+\left(\frac{3}{-4}\right)\)
7. \(-\left(\frac{-11}{6}\right)-\left(\frac{-7}{3}\right)\)
8. \(+\left(\frac{15}{-2}\right)-\left(\frac{-10}{-3}\right)\)
9. \(-\left(\frac{-15}{4}\right)-\left(\frac{-11}{-2}\right)\)
10. \(+\left(\frac{-14}{9}\right)+\left(\frac{-13}{4}\right)\)
11. \(+\left(\frac{-8}{-9}\right)+\left(\frac{-13}{6}\right)\)
12. \(+\left(\frac{-10}{-3}\right)-\left(\frac{4}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-7}{-13}\right)-\left(\frac{3}{7}\right)\\= \frac{7}{13}-\frac{3}{7}\\=\frac{49}{91}-\frac{39}{91}\\=\frac{49-39}{91}\\=\frac{10}{91}\)
2. \(+\left(\frac{7}{-5}\right)-\left(\frac{5}{-6}\right)\\= \frac{-7}{5}+\frac{5}{6}\\=\frac{-42}{30}+\frac{25}{30}\\=\frac{-42+25}{30}\\=\frac{-17}{30}\)
3. \(+\left(\frac{-3}{-4}\right)+\left(\frac{5}{-6}\right)\\= \frac{3}{4}-\frac{5}{6}\\=\frac{9}{12}-\frac{10}{12}\\=\frac{9-10}{12}\\=\frac{-1}{12}\)
4. \(+\left(\frac{10}{-7}\right)+\left(\frac{15}{-2}\right)\\= \frac{-10}{7}-\frac{15}{2}\\=\frac{-20}{14}-\frac{105}{14}\\=\frac{-20-105}{14}\\=\frac{-125}{14}\)
5. \(+\left(\frac{-10}{9}\right)+\left(\frac{-9}{-10}\right)\\= \frac{-10}{9}+\frac{9}{10}\\=\frac{-100}{90}+\frac{81}{90}\\=\frac{-100+81}{90}\\=\frac{-19}{90}\)
6. \(+\left(\frac{-10}{-3}\right)+\left(\frac{3}{-4}\right)\\= \frac{10}{3}-\frac{3}{4}\\=\frac{40}{12}-\frac{9}{12}\\=\frac{40-9}{12}\\=\frac{31}{12}\)
7. \(-\left(\frac{-11}{6}\right)-\left(\frac{-7}{3}\right)\\= \frac{11}{6}+\frac{7}{3}\\=\frac{11+7}{6}\\=\frac{18}{6}\\=\frac{3}{1}\)
8. \(+\left(\frac{15}{-2}\right)-\left(\frac{-10}{-3}\right)\\= \frac{-15}{2}-\frac{10}{3}\\=\frac{-45}{6}-\frac{20}{6}\\=\frac{-45-20}{6}\\=\frac{-65}{6}\)
9. \(-\left(\frac{-15}{4}\right)-\left(\frac{-11}{-2}\right)\\= \frac{15}{4}-\frac{11}{2}\\=\frac{15-11}{4}\\=\frac{4}{4}\\=\frac{1}{1}\)
10. \(+\left(\frac{-14}{9}\right)+\left(\frac{-13}{4}\right)\\= \frac{-14}{9}-\frac{13}{4}\\=\frac{-56}{36}-\frac{117}{36}\\=\frac{-56-117}{36}\\=\frac{-173}{36}\)
11. \(+\left(\frac{-8}{-9}\right)+\left(\frac{-13}{6}\right)\\= \frac{8}{9}-\frac{13}{6}\\=\frac{16}{18}-\frac{39}{18}\\=\frac{16-39}{18}\\=\frac{-23}{18}\)
12. \(+\left(\frac{-10}{-3}\right)-\left(\frac{4}{-7}\right)\\= \frac{10}{3}+\frac{4}{7}\\=\frac{70}{21}+\frac{12}{21}\\=\frac{70+12}{21}\\=\frac{82}{21}\)