Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{5}{-9}\right)+\left(\frac{13}{4}\right)\)
2. \(-\left(\frac{-3}{10}\right)-\left(\frac{13}{-5}\right)\)
3. \(-\left(\frac{4}{3}\right)-\left(\frac{5}{-11}\right)\)
4. \(-\left(\frac{-11}{2}\right)+\left(\frac{6}{-13}\right)\)
5. \(-\left(\frac{6}{-11}\right)-\left(\frac{-15}{-11}\right)\)
6. \(-\left(\frac{3}{4}\right)+\left(\frac{13}{11}\right)\)
7. \(-\left(\frac{-8}{3}\right)+\left(\frac{-2}{5}\right)\)
8. \(-\left(\frac{4}{-3}\right)-\left(\frac{5}{-9}\right)\)
9. \(+\left(\frac{8}{-3}\right)+\left(\frac{-13}{8}\right)\)
10. \(+\left(\frac{-13}{-14}\right)-\left(\frac{10}{11}\right)\)
11. \(-\left(\frac{13}{10}\right)+\left(\frac{-12}{11}\right)\)
12. \(+\left(\frac{4}{-3}\right)+\left(\frac{-15}{7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{5}{-9}\right)+\left(\frac{13}{4}\right)\\= \frac{-5}{9}+\frac{13}{4}\\=\frac{-20}{36}+\frac{117}{36}\\=\frac{-20+117}{36}\\=\frac{97}{36}\)
2. \(-\left(\frac{-3}{10}\right)-\left(\frac{13}{-5}\right)\\= \frac{3}{10}+\frac{13}{5}\\=\frac{3+13}{10}\\=\frac{16}{10}\\=\frac{8}{5}\)
3. \(-\left(\frac{4}{3}\right)-\left(\frac{5}{-11}\right)\\= \frac{-4}{3}+\frac{5}{11}\\=\frac{-44}{33}+\frac{15}{33}\\=\frac{-44+15}{33}\\=\frac{-29}{33}\)
4. \(-\left(\frac{-11}{2}\right)+\left(\frac{6}{-13}\right)\\= \frac{11}{2}-\frac{6}{13}\\=\frac{143}{26}-\frac{12}{26}\\=\frac{143-12}{26}\\=\frac{131}{26}\)
5. \(-\left(\frac{6}{-11}\right)-\left(\frac{-15}{-11}\right)\\= \frac{6}{11}-\frac{15}{11}\\=\frac{6-15}{11}\\=\frac{-9}{11}\)
6. \(-\left(\frac{3}{4}\right)+\left(\frac{13}{11}\right)\\= \frac{-3}{4}+\frac{13}{11}\\=\frac{-33}{44}+\frac{52}{44}\\=\frac{-33+52}{44}\\=\frac{19}{44}\)
7. \(-\left(\frac{-8}{3}\right)+\left(\frac{-2}{5}\right)\\= \frac{8}{3}-\frac{2}{5}\\=\frac{40}{15}-\frac{6}{15}\\=\frac{40-6}{15}\\=\frac{34}{15}\)
8. \(-\left(\frac{4}{-3}\right)-\left(\frac{5}{-9}\right)\\= \frac{4}{3}+\frac{5}{9}\\=\frac{12}{9}+\frac{5}{9}\\=\frac{12+5}{9}\\=\frac{17}{9}\)
9. \(+\left(\frac{8}{-3}\right)+\left(\frac{-13}{8}\right)\\= \frac{-8}{3}-\frac{13}{8}\\=\frac{-64}{24}-\frac{39}{24}\\=\frac{-64-39}{24}\\=\frac{-103}{24}\)
10. \(+\left(\frac{-13}{-14}\right)-\left(\frac{10}{11}\right)\\= \frac{13}{14}-\frac{10}{11}\\=\frac{143}{154}-\frac{140}{154}\\=\frac{143-140}{154}\\=\frac{3}{154}\)
11. \(-\left(\frac{13}{10}\right)+\left(\frac{-12}{11}\right)\\= \frac{-13}{10}-\frac{12}{11}\\=\frac{-143}{110}-\frac{120}{110}\\=\frac{-143-120}{110}\\=\frac{-263}{110}\)
12. \(+\left(\frac{4}{-3}\right)+\left(\frac{-15}{7}\right)\\= \frac{-4}{3}-\frac{15}{7}\\=\frac{-28}{21}-\frac{45}{21}\\=\frac{-28-45}{21}\\=\frac{-73}{21}\)