Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-15}{2}\right)-\left(\frac{12}{-5}\right)\)
2. \(-\left(\frac{-10}{-3}\right)-\left(\frac{-3}{-8}\right)\)
3. \(-\left(\frac{-15}{-4}\right)+\left(\frac{-6}{-5}\right)\)
4. \(-\left(\frac{-9}{5}\right)+\left(\frac{7}{-8}\right)\)
5. \(-\left(\frac{12}{5}\right)-\left(\frac{-11}{-8}\right)\)
6. \(-\left(\frac{4}{13}\right)+\left(\frac{12}{-5}\right)\)
7. \(+\left(\frac{-11}{-4}\right)-\left(\frac{3}{-13}\right)\)
8. \(+\left(\frac{11}{10}\right)+\left(\frac{7}{8}\right)\)
9. \(-\left(\frac{10}{7}\right)-\left(\frac{-6}{13}\right)\)
10. \(+\left(\frac{10}{11}\right)+\left(\frac{-2}{-7}\right)\)
11. \(+\left(\frac{-13}{-6}\right)+\left(\frac{-7}{2}\right)\)
12. \(-\left(\frac{6}{-5}\right)-\left(\frac{5}{2}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-15}{2}\right)-\left(\frac{12}{-5}\right)\\= \frac{-15}{2}+\frac{12}{5}\\=\frac{-75}{10}+\frac{24}{10}\\=\frac{-75+24}{10}\\=\frac{-51}{10}\)
2. \(-\left(\frac{-10}{-3}\right)-\left(\frac{-3}{-8}\right)\\= \frac{-10}{3}-\frac{3}{8}\\=\frac{-80}{24}-\frac{9}{24}\\=\frac{-80-9}{24}\\=\frac{-89}{24}\)
3. \(-\left(\frac{-15}{-4}\right)+\left(\frac{-6}{-5}\right)\\= \frac{-15}{4}+\frac{6}{5}\\=\frac{-75}{20}+\frac{24}{20}\\=\frac{-75+24}{20}\\=\frac{-51}{20}\)
4. \(-\left(\frac{-9}{5}\right)+\left(\frac{7}{-8}\right)\\= \frac{9}{5}-\frac{7}{8}\\=\frac{72}{40}-\frac{35}{40}\\=\frac{72-35}{40}\\=\frac{37}{40}\)
5. \(-\left(\frac{12}{5}\right)-\left(\frac{-11}{-8}\right)\\= \frac{-12}{5}-\frac{11}{8}\\=\frac{-96}{40}-\frac{55}{40}\\=\frac{-96-55}{40}\\=\frac{-151}{40}\)
6. \(-\left(\frac{4}{13}\right)+\left(\frac{12}{-5}\right)\\= \frac{-4}{13}-\frac{12}{5}\\=\frac{-20}{65}-\frac{156}{65}\\=\frac{-20-156}{65}\\=\frac{-176}{65}\)
7. \(+\left(\frac{-11}{-4}\right)-\left(\frac{3}{-13}\right)\\= \frac{11}{4}+\frac{3}{13}\\=\frac{143}{52}+\frac{12}{52}\\=\frac{143+12}{52}\\=\frac{155}{52}\)
8. \(+\left(\frac{11}{10}\right)+\left(\frac{7}{8}\right)\\= \frac{11}{10}+\frac{7}{8}\\=\frac{44}{40}+\frac{35}{40}\\=\frac{44+35}{40}\\=\frac{79}{40}\)
9. \(-\left(\frac{10}{7}\right)-\left(\frac{-6}{13}\right)\\= \frac{-10}{7}+\frac{6}{13}\\=\frac{-130}{91}+\frac{42}{91}\\=\frac{-130+42}{91}\\=\frac{-88}{91}\)
10. \(+\left(\frac{10}{11}\right)+\left(\frac{-2}{-7}\right)\\= \frac{10}{11}+\frac{2}{7}\\=\frac{70}{77}+\frac{22}{77}\\=\frac{70+22}{77}\\=\frac{92}{77}\)
11. \(+\left(\frac{-13}{-6}\right)+\left(\frac{-7}{2}\right)\\= \frac{13}{6}-\frac{7}{2}\\=\frac{13-7}{6}\\=\frac{6}{6}\\=\frac{1}{1}\)
12. \(-\left(\frac{6}{-5}\right)-\left(\frac{5}{2}\right)\\= \frac{6}{5}-\frac{5}{2}\\=\frac{12}{10}-\frac{25}{10}\\=\frac{12-25}{10}\\=\frac{-13}{10}\)