Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-11}{2}\right)+\left(\frac{-4}{3}\right)\)
2. \(-\left(\frac{-4}{9}\right)+\left(\frac{14}{3}\right)\)
3. \(-\left(\frac{9}{-7}\right)+\left(\frac{3}{4}\right)\)
4. \(-\left(\frac{-4}{-3}\right)-\left(\frac{10}{-13}\right)\)
5. \(-\left(\frac{3}{8}\right)+\left(\frac{-6}{7}\right)\)
6. \(-\left(\frac{-15}{-13}\right)+\left(\frac{-15}{2}\right)\)
7. \(+\left(\frac{-2}{-9}\right)+\left(\frac{2}{-3}\right)\)
8. \(+\left(\frac{5}{6}\right)-\left(\frac{7}{3}\right)\)
9. \(+\left(\frac{-5}{-4}\right)+\left(\frac{2}{3}\right)\)
10. \(+\left(\frac{-12}{11}\right)-\left(\frac{-10}{3}\right)\)
11. \(-\left(\frac{-2}{3}\right)+\left(\frac{-2}{-13}\right)\)
12. \(+\left(\frac{15}{14}\right)-\left(\frac{-6}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-11}{2}\right)+\left(\frac{-4}{3}\right)\\= \frac{-11}{2}-\frac{4}{3}\\=\frac{-33}{6}-\frac{8}{6}\\=\frac{-33-8}{6}\\=\frac{-41}{6}\)
2. \(-\left(\frac{-4}{9}\right)+\left(\frac{14}{3}\right)\\= \frac{4}{9}+\frac{14}{3}\\=\frac{4+14}{9}\\=\frac{18}{9}\\=\frac{2}{1}\)
3. \(-\left(\frac{9}{-7}\right)+\left(\frac{3}{4}\right)\\= \frac{9}{7}+\frac{3}{4}\\=\frac{36}{28}+\frac{21}{28}\\=\frac{36+21}{28}\\=\frac{57}{28}\)
4. \(-\left(\frac{-4}{-3}\right)-\left(\frac{10}{-13}\right)\\= \frac{-4}{3}+\frac{10}{13}\\=\frac{-52}{39}+\frac{30}{39}\\=\frac{-52+30}{39}\\=\frac{-22}{39}\)
5. \(-\left(\frac{3}{8}\right)+\left(\frac{-6}{7}\right)\\= \frac{-3}{8}-\frac{6}{7}\\=\frac{-21}{56}-\frac{48}{56}\\=\frac{-21-48}{56}\\=\frac{-69}{56}\)
6. \(-\left(\frac{-15}{-13}\right)+\left(\frac{-15}{2}\right)\\= \frac{-15}{13}-\frac{15}{2}\\=\frac{-30}{26}-\frac{195}{26}\\=\frac{-30-195}{26}\\=\frac{-225}{26}\)
7. \(+\left(\frac{-2}{-9}\right)+\left(\frac{2}{-3}\right)\\= \frac{2}{9}-\frac{2}{3}\\=\frac{2-2}{9}\\=\frac{0}{9}\\=\frac{0}{1}\)
8. \(+\left(\frac{5}{6}\right)-\left(\frac{7}{3}\right)\\= \frac{5}{6}-\frac{7}{3}\\=\frac{5-7}{6}\\=\frac{-2}{6}\\=\frac{-1}{3}\)
9. \(+\left(\frac{-5}{-4}\right)+\left(\frac{2}{3}\right)\\= \frac{5}{4}+\frac{2}{3}\\=\frac{15}{12}+\frac{8}{12}\\=\frac{15+8}{12}\\=\frac{23}{12}\)
10. \(+\left(\frac{-12}{11}\right)-\left(\frac{-10}{3}\right)\\= \frac{-12}{11}+\frac{10}{3}\\=\frac{-36}{33}+\frac{110}{33}\\=\frac{-36+110}{33}\\=\frac{74}{33}\)
11. \(-\left(\frac{-2}{3}\right)+\left(\frac{-2}{-13}\right)\\= \frac{2}{3}+\frac{2}{13}\\=\frac{26}{39}+\frac{6}{39}\\=\frac{26+6}{39}\\=\frac{32}{39}\)
12. \(+\left(\frac{15}{14}\right)-\left(\frac{-6}{-5}\right)\\= \frac{15}{14}-\frac{6}{5}\\=\frac{75}{70}-\frac{84}{70}\\=\frac{75-84}{70}\\=\frac{-9}{70}\)