Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-5}{-7}\right)+\left(\frac{-13}{-2}\right)\)
2. \(+\left(\frac{-4}{9}\right)+\left(\frac{4}{-11}\right)\)
3. \(-\left(\frac{13}{-10}\right)-\left(\frac{-14}{-11}\right)\)
4. \(-\left(\frac{7}{10}\right)-\left(\frac{12}{11}\right)\)
5. \(-\left(\frac{-14}{11}\right)+\left(\frac{-6}{-13}\right)\)
6. \(+\left(\frac{8}{3}\right)+\left(\frac{-3}{8}\right)\)
7. \(+\left(\frac{-9}{-14}\right)+\left(\frac{14}{3}\right)\)
8. \(-\left(\frac{-8}{-3}\right)-\left(\frac{-10}{13}\right)\)
9. \(-\left(\frac{-5}{6}\right)+\left(\frac{9}{2}\right)\)
10. \(-\left(\frac{13}{-12}\right)-\left(\frac{-6}{5}\right)\)
11. \(+\left(\frac{-12}{-5}\right)-\left(\frac{8}{-13}\right)\)
12. \(-\left(\frac{-10}{7}\right)-\left(\frac{9}{10}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-5}{-7}\right)+\left(\frac{-13}{-2}\right)\\= \frac{5}{7}+\frac{13}{2}\\=\frac{10}{14}+\frac{91}{14}\\=\frac{10+91}{14}\\=\frac{101}{14}\)
2. \(+\left(\frac{-4}{9}\right)+\left(\frac{4}{-11}\right)\\= \frac{-4}{9}-\frac{4}{11}\\=\frac{-44}{99}-\frac{36}{99}\\=\frac{-44-36}{99}\\=\frac{-80}{99}\)
3. \(-\left(\frac{13}{-10}\right)-\left(\frac{-14}{-11}\right)\\= \frac{13}{10}-\frac{14}{11}\\=\frac{143}{110}-\frac{140}{110}\\=\frac{143-140}{110}\\=\frac{3}{110}\)
4. \(-\left(\frac{7}{10}\right)-\left(\frac{12}{11}\right)\\= \frac{-7}{10}-\frac{12}{11}\\=\frac{-77}{110}-\frac{120}{110}\\=\frac{-77-120}{110}\\=\frac{-197}{110}\)
5. \(-\left(\frac{-14}{11}\right)+\left(\frac{-6}{-13}\right)\\= \frac{14}{11}+\frac{6}{13}\\=\frac{182}{143}+\frac{66}{143}\\=\frac{182+66}{143}\\=\frac{248}{143}\)
6. \(+\left(\frac{8}{3}\right)+\left(\frac{-3}{8}\right)\\= \frac{8}{3}-\frac{3}{8}\\=\frac{64}{24}-\frac{9}{24}\\=\frac{64-9}{24}\\=\frac{55}{24}\)
7. \(+\left(\frac{-9}{-14}\right)+\left(\frac{14}{3}\right)\\= \frac{9}{14}+\frac{14}{3}\\=\frac{27}{42}+\frac{196}{42}\\=\frac{27+196}{42}\\=\frac{223}{42}\)
8. \(-\left(\frac{-8}{-3}\right)-\left(\frac{-10}{13}\right)\\= \frac{-8}{3}+\frac{10}{13}\\=\frac{-104}{39}+\frac{30}{39}\\=\frac{-104+30}{39}\\=\frac{-74}{39}\)
9. \(-\left(\frac{-5}{6}\right)+\left(\frac{9}{2}\right)\\= \frac{5}{6}+\frac{9}{2}\\=\frac{5+9}{6}\\=\frac{14}{6}\\=\frac{7}{3}\)
10. \(-\left(\frac{13}{-12}\right)-\left(\frac{-6}{5}\right)\\= \frac{13}{12}+\frac{6}{5}\\=\frac{65}{60}+\frac{72}{60}\\=\frac{65+72}{60}\\=\frac{137}{60}\)
11. \(+\left(\frac{-12}{-5}\right)-\left(\frac{8}{-13}\right)\\= \frac{12}{5}+\frac{8}{13}\\=\frac{156}{65}+\frac{40}{65}\\=\frac{156+40}{65}\\=\frac{196}{65}\)
12. \(-\left(\frac{-10}{7}\right)-\left(\frac{9}{10}\right)\\= \frac{10}{7}-\frac{9}{10}\\=\frac{100}{70}-\frac{63}{70}\\=\frac{100-63}{70}\\=\frac{37}{70}\)