Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{15}{13}\right)+\left(\frac{-11}{12}\right)\)
2. \(-\left(\frac{14}{3}\right)+\left(\frac{-9}{-4}\right)\)
3. \(+\left(\frac{-5}{11}\right)-\left(\frac{13}{10}\right)\)
4. \(-\left(\frac{-7}{-10}\right)-\left(\frac{2}{7}\right)\)
5. \(-\left(\frac{-5}{2}\right)+\left(\frac{-7}{4}\right)\)
6. \(-\left(\frac{-7}{10}\right)+\left(\frac{-8}{-13}\right)\)
7. \(+\left(\frac{-11}{-3}\right)+\left(\frac{-12}{13}\right)\)
8. \(-\left(\frac{12}{11}\right)-\left(\frac{-11}{5}\right)\)
9. \(+\left(\frac{12}{-5}\right)-\left(\frac{4}{3}\right)\)
10. \(-\left(\frac{-9}{10}\right)+\left(\frac{-12}{11}\right)\)
11. \(-\left(\frac{-8}{11}\right)+\left(\frac{4}{-11}\right)\)
12. \(-\left(\frac{-12}{5}\right)-\left(\frac{14}{9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{15}{13}\right)+\left(\frac{-11}{12}\right)\\= \frac{15}{13}-\frac{11}{12}\\=\frac{180}{156}-\frac{143}{156}\\=\frac{180-143}{156}\\=\frac{37}{156}\)
2. \(-\left(\frac{14}{3}\right)+\left(\frac{-9}{-4}\right)\\= \frac{-14}{3}+\frac{9}{4}\\=\frac{-56}{12}+\frac{27}{12}\\=\frac{-56+27}{12}\\=\frac{-29}{12}\)
3. \(+\left(\frac{-5}{11}\right)-\left(\frac{13}{10}\right)\\= \frac{-5}{11}-\frac{13}{10}\\=\frac{-50}{110}-\frac{143}{110}\\=\frac{-50-143}{110}\\=\frac{-193}{110}\)
4. \(-\left(\frac{-7}{-10}\right)-\left(\frac{2}{7}\right)\\= \frac{-7}{10}-\frac{2}{7}\\=\frac{-49}{70}-\frac{20}{70}\\=\frac{-49-20}{70}\\=\frac{-69}{70}\)
5. \(-\left(\frac{-5}{2}\right)+\left(\frac{-7}{4}\right)\\= \frac{5}{2}-\frac{7}{4}\\=\frac{10}{4}-\frac{7}{4}\\=\frac{10-7}{4}\\=\frac{3}{4}\)
6. \(-\left(\frac{-7}{10}\right)+\left(\frac{-8}{-13}\right)\\= \frac{7}{10}+\frac{8}{13}\\=\frac{91}{130}+\frac{80}{130}\\=\frac{91+80}{130}\\=\frac{171}{130}\)
7. \(+\left(\frac{-11}{-3}\right)+\left(\frac{-12}{13}\right)\\= \frac{11}{3}-\frac{12}{13}\\=\frac{143}{39}-\frac{36}{39}\\=\frac{143-36}{39}\\=\frac{107}{39}\)
8. \(-\left(\frac{12}{11}\right)-\left(\frac{-11}{5}\right)\\= \frac{-12}{11}+\frac{11}{5}\\=\frac{-60}{55}+\frac{121}{55}\\=\frac{-60+121}{55}\\=\frac{61}{55}\)
9. \(+\left(\frac{12}{-5}\right)-\left(\frac{4}{3}\right)\\= \frac{-12}{5}-\frac{4}{3}\\=\frac{-36}{15}-\frac{20}{15}\\=\frac{-36-20}{15}\\=\frac{-56}{15}\)
10. \(-\left(\frac{-9}{10}\right)+\left(\frac{-12}{11}\right)\\= \frac{9}{10}-\frac{12}{11}\\=\frac{99}{110}-\frac{120}{110}\\=\frac{99-120}{110}\\=\frac{-21}{110}\)
11. \(-\left(\frac{-8}{11}\right)+\left(\frac{4}{-11}\right)\\= \frac{8}{11}-\frac{4}{11}\\=\frac{8-4}{11}\\=\frac{4}{11}\)
12. \(-\left(\frac{-12}{5}\right)-\left(\frac{14}{9}\right)\\= \frac{12}{5}-\frac{14}{9}\\=\frac{108}{45}-\frac{70}{45}\\=\frac{108-70}{45}\\=\frac{38}{45}\)