Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-4}{-3}\right)+\left(\frac{-4}{7}\right)\)
2. \(+\left(\frac{-8}{-11}\right)-\left(\frac{2}{-5}\right)\)
3. \(-\left(\frac{11}{-10}\right)+\left(\frac{-2}{-9}\right)\)
4. \(-\left(\frac{2}{-7}\right)-\left(\frac{-13}{-11}\right)\)
5. \(-\left(\frac{9}{5}\right)+\left(\frac{8}{-3}\right)\)
6. \(+\left(\frac{12}{5}\right)-\left(\frac{-6}{-5}\right)\)
7. \(-\left(\frac{-7}{4}\right)+\left(\frac{-4}{13}\right)\)
8. \(+\left(\frac{-15}{2}\right)+\left(\frac{-13}{8}\right)\)
9. \(-\left(\frac{8}{3}\right)-\left(\frac{-9}{5}\right)\)
10. \(-\left(\frac{-10}{9}\right)-\left(\frac{-8}{-5}\right)\)
11. \(+\left(\frac{13}{9}\right)+\left(\frac{14}{-9}\right)\)
12. \(+\left(\frac{-6}{-5}\right)+\left(\frac{4}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-4}{-3}\right)+\left(\frac{-4}{7}\right)\\= \frac{-4}{3}-\frac{4}{7}\\=\frac{-28}{21}-\frac{12}{21}\\=\frac{-28-12}{21}\\=\frac{-40}{21}\)
2. \(+\left(\frac{-8}{-11}\right)-\left(\frac{2}{-5}\right)\\= \frac{8}{11}+\frac{2}{5}\\=\frac{40}{55}+\frac{22}{55}\\=\frac{40+22}{55}\\=\frac{62}{55}\)
3. \(-\left(\frac{11}{-10}\right)+\left(\frac{-2}{-9}\right)\\= \frac{11}{10}+\frac{2}{9}\\=\frac{99}{90}+\frac{20}{90}\\=\frac{99+20}{90}\\=\frac{119}{90}\)
4. \(-\left(\frac{2}{-7}\right)-\left(\frac{-13}{-11}\right)\\= \frac{2}{7}-\frac{13}{11}\\=\frac{22}{77}-\frac{91}{77}\\=\frac{22-91}{77}\\=\frac{-69}{77}\)
5. \(-\left(\frac{9}{5}\right)+\left(\frac{8}{-3}\right)\\= \frac{-9}{5}-\frac{8}{3}\\=\frac{-27}{15}-\frac{40}{15}\\=\frac{-27-40}{15}\\=\frac{-67}{15}\)
6. \(+\left(\frac{12}{5}\right)-\left(\frac{-6}{-5}\right)\\= \frac{12}{5}-\frac{6}{5}\\=\frac{12-6}{5}\\=\frac{6}{5}\)
7. \(-\left(\frac{-7}{4}\right)+\left(\frac{-4}{13}\right)\\= \frac{7}{4}-\frac{4}{13}\\=\frac{91}{52}-\frac{16}{52}\\=\frac{91-16}{52}\\=\frac{75}{52}\)
8. \(+\left(\frac{-15}{2}\right)+\left(\frac{-13}{8}\right)\\= \frac{-15}{2}-\frac{13}{8}\\=\frac{-60}{8}-\frac{13}{8}\\=\frac{-60-13}{8}\\=\frac{-73}{8}\)
9. \(-\left(\frac{8}{3}\right)-\left(\frac{-9}{5}\right)\\= \frac{-8}{3}+\frac{9}{5}\\=\frac{-40}{15}+\frac{27}{15}\\=\frac{-40+27}{15}\\=\frac{-13}{15}\)
10. \(-\left(\frac{-10}{9}\right)-\left(\frac{-8}{-5}\right)\\= \frac{10}{9}-\frac{8}{5}\\=\frac{50}{45}-\frac{72}{45}\\=\frac{50-72}{45}\\=\frac{-22}{45}\)
11. \(+\left(\frac{13}{9}\right)+\left(\frac{14}{-9}\right)\\= \frac{13}{9}-\frac{14}{9}\\=\frac{13-14}{9}\\=\frac{-1}{9}\)
12. \(+\left(\frac{-6}{-5}\right)+\left(\frac{4}{-3}\right)\\= \frac{6}{5}-\frac{4}{3}\\=\frac{18}{15}-\frac{20}{15}\\=\frac{18-20}{15}\\=\frac{-2}{15}\)