Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{7}{2}\right)-\left(\frac{9}{-11}\right)\)
2. \(-\left(\frac{-9}{-2}\right)-\left(\frac{-6}{-11}\right)\)
3. \(-\left(\frac{-5}{-7}\right)-\left(\frac{-2}{5}\right)\)
4. \(-\left(\frac{-3}{-14}\right)-\left(\frac{-14}{9}\right)\)
5. \(-\left(\frac{-7}{5}\right)-\left(\frac{12}{13}\right)\)
6. \(+\left(\frac{-15}{-8}\right)-\left(\frac{-3}{13}\right)\)
7. \(+\left(\frac{3}{-10}\right)+\left(\frac{9}{-11}\right)\)
8. \(+\left(\frac{13}{14}\right)-\left(\frac{-5}{-4}\right)\)
9. \(+\left(\frac{-10}{-13}\right)+\left(\frac{9}{-11}\right)\)
10. \(+\left(\frac{10}{-9}\right)-\left(\frac{12}{-7}\right)\)
11. \(+\left(\frac{-5}{-12}\right)+\left(\frac{10}{13}\right)\)
12. \(-\left(\frac{-13}{-4}\right)-\left(\frac{-9}{7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{7}{2}\right)-\left(\frac{9}{-11}\right)\\= \frac{-7}{2}+\frac{9}{11}\\=\frac{-77}{22}+\frac{18}{22}\\=\frac{-77+18}{22}\\=\frac{-59}{22}\)
2. \(-\left(\frac{-9}{-2}\right)-\left(\frac{-6}{-11}\right)\\= \frac{-9}{2}-\frac{6}{11}\\=\frac{-99}{22}-\frac{12}{22}\\=\frac{-99-12}{22}\\=\frac{-111}{22}\)
3. \(-\left(\frac{-5}{-7}\right)-\left(\frac{-2}{5}\right)\\= \frac{-5}{7}+\frac{2}{5}\\=\frac{-25}{35}+\frac{14}{35}\\=\frac{-25+14}{35}\\=\frac{-11}{35}\)
4. \(-\left(\frac{-3}{-14}\right)-\left(\frac{-14}{9}\right)\\= \frac{-3}{14}+\frac{14}{9}\\=\frac{-27}{126}+\frac{196}{126}\\=\frac{-27+196}{126}\\=\frac{169}{126}\)
5. \(-\left(\frac{-7}{5}\right)-\left(\frac{12}{13}\right)\\= \frac{7}{5}-\frac{12}{13}\\=\frac{91}{65}-\frac{60}{65}\\=\frac{91-60}{65}\\=\frac{31}{65}\)
6. \(+\left(\frac{-15}{-8}\right)-\left(\frac{-3}{13}\right)\\= \frac{15}{8}+\frac{3}{13}\\=\frac{195}{104}+\frac{24}{104}\\=\frac{195+24}{104}\\=\frac{219}{104}\)
7. \(+\left(\frac{3}{-10}\right)+\left(\frac{9}{-11}\right)\\= \frac{-3}{10}-\frac{9}{11}\\=\frac{-33}{110}-\frac{90}{110}\\=\frac{-33-90}{110}\\=\frac{-123}{110}\)
8. \(+\left(\frac{13}{14}\right)-\left(\frac{-5}{-4}\right)\\= \frac{13}{14}-\frac{5}{4}\\=\frac{26}{28}-\frac{35}{28}\\=\frac{26-35}{28}\\=\frac{-9}{28}\)
9. \(+\left(\frac{-10}{-13}\right)+\left(\frac{9}{-11}\right)\\= \frac{10}{13}-\frac{9}{11}\\=\frac{110}{143}-\frac{117}{143}\\=\frac{110-117}{143}\\=\frac{-7}{143}\)
10. \(+\left(\frac{10}{-9}\right)-\left(\frac{12}{-7}\right)\\= \frac{-10}{9}+\frac{12}{7}\\=\frac{-70}{63}+\frac{108}{63}\\=\frac{-70+108}{63}\\=\frac{38}{63}\)
11. \(+\left(\frac{-5}{-12}\right)+\left(\frac{10}{13}\right)\\= \frac{5}{12}+\frac{10}{13}\\=\frac{65}{156}+\frac{120}{156}\\=\frac{65+120}{156}\\=\frac{185}{156}\)
12. \(-\left(\frac{-13}{-4}\right)-\left(\frac{-9}{7}\right)\\= \frac{-13}{4}+\frac{9}{7}\\=\frac{-91}{28}+\frac{36}{28}\\=\frac{-91+36}{28}\\=\frac{-55}{28}\)