Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{15}{14}\right)-\left(\frac{-10}{3}\right)\)
2. \(-\left(\frac{-9}{7}\right)+\left(\frac{-5}{-8}\right)\)
3. \(+\left(\frac{8}{-5}\right)+\left(\frac{-12}{-13}\right)\)
4. \(+\left(\frac{13}{-9}\right)+\left(\frac{11}{12}\right)\)
5. \(-\left(\frac{-14}{3}\right)-\left(\frac{-6}{-5}\right)\)
6. \(-\left(\frac{-4}{13}\right)+\left(\frac{-10}{-11}\right)\)
7. \(+\left(\frac{14}{-5}\right)-\left(\frac{-7}{-3}\right)\)
8. \(-\left(\frac{-5}{-7}\right)-\left(\frac{-10}{13}\right)\)
9. \(+\left(\frac{6}{5}\right)-\left(\frac{-2}{7}\right)\)
10. \(+\left(\frac{-10}{-9}\right)+\left(\frac{-3}{4}\right)\)
11. \(-\left(\frac{4}{7}\right)-\left(\frac{-12}{11}\right)\)
12. \(-\left(\frac{15}{-11}\right)-\left(\frac{15}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{15}{14}\right)-\left(\frac{-10}{3}\right)\\= \frac{15}{14}+\frac{10}{3}\\=\frac{45}{42}+\frac{140}{42}\\=\frac{45+140}{42}\\=\frac{185}{42}\)
2. \(-\left(\frac{-9}{7}\right)+\left(\frac{-5}{-8}\right)\\= \frac{9}{7}+\frac{5}{8}\\=\frac{72}{56}+\frac{35}{56}\\=\frac{72+35}{56}\\=\frac{107}{56}\)
3. \(+\left(\frac{8}{-5}\right)+\left(\frac{-12}{-13}\right)\\= \frac{-8}{5}+\frac{12}{13}\\=\frac{-104}{65}+\frac{60}{65}\\=\frac{-104+60}{65}\\=\frac{-44}{65}\)
4. \(+\left(\frac{13}{-9}\right)+\left(\frac{11}{12}\right)\\= \frac{-13}{9}+\frac{11}{12}\\=\frac{-52}{36}+\frac{33}{36}\\=\frac{-52+33}{36}\\=\frac{-19}{36}\)
5. \(-\left(\frac{-14}{3}\right)-\left(\frac{-6}{-5}\right)\\= \frac{14}{3}-\frac{6}{5}\\=\frac{70}{15}-\frac{18}{15}\\=\frac{70-18}{15}\\=\frac{52}{15}\)
6. \(-\left(\frac{-4}{13}\right)+\left(\frac{-10}{-11}\right)\\= \frac{4}{13}+\frac{10}{11}\\=\frac{44}{143}+\frac{130}{143}\\=\frac{44+130}{143}\\=\frac{174}{143}\)
7. \(+\left(\frac{14}{-5}\right)-\left(\frac{-7}{-3}\right)\\= \frac{-14}{5}-\frac{7}{3}\\=\frac{-42}{15}-\frac{35}{15}\\=\frac{-42-35}{15}\\=\frac{-77}{15}\)
8. \(-\left(\frac{-5}{-7}\right)-\left(\frac{-10}{13}\right)\\= \frac{-5}{7}+\frac{10}{13}\\=\frac{-65}{91}+\frac{70}{91}\\=\frac{-65+70}{91}\\=\frac{5}{91}\)
9. \(+\left(\frac{6}{5}\right)-\left(\frac{-2}{7}\right)\\= \frac{6}{5}+\frac{2}{7}\\=\frac{42}{35}+\frac{10}{35}\\=\frac{42+10}{35}\\=\frac{52}{35}\)
10. \(+\left(\frac{-10}{-9}\right)+\left(\frac{-3}{4}\right)\\= \frac{10}{9}-\frac{3}{4}\\=\frac{40}{36}-\frac{27}{36}\\=\frac{40-27}{36}\\=\frac{13}{36}\)
11. \(-\left(\frac{4}{7}\right)-\left(\frac{-12}{11}\right)\\= \frac{-4}{7}+\frac{12}{11}\\=\frac{-44}{77}+\frac{84}{77}\\=\frac{-44+84}{77}\\=\frac{40}{77}\)
12. \(-\left(\frac{15}{-11}\right)-\left(\frac{15}{-11}\right)\\= \frac{15}{11}+\frac{15}{11}\\=\frac{15+15}{11}\\=\frac{30}{11}\)