Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{-7}\right)-\left(\frac{6}{13}\right)\)
2. \(-\left(\frac{-14}{11}\right)+\left(\frac{-4}{5}\right)\)
3. \(-\left(\frac{-3}{7}\right)+\left(\frac{10}{-9}\right)\)
4. \(-\left(\frac{-12}{-11}\right)+\left(\frac{14}{3}\right)\)
5. \(-\left(\frac{-10}{13}\right)+\left(\frac{8}{-3}\right)\)
6. \(-\left(\frac{4}{3}\right)+\left(\frac{-10}{-13}\right)\)
7. \(+\left(\frac{11}{7}\right)-\left(\frac{-9}{2}\right)\)
8. \(+\left(\frac{14}{5}\right)+\left(\frac{-8}{3}\right)\)
9. \(-\left(\frac{-13}{-7}\right)+\left(\frac{12}{7}\right)\)
10. \(-\left(\frac{10}{13}\right)-\left(\frac{14}{-9}\right)\)
11. \(+\left(\frac{-3}{7}\right)+\left(\frac{-13}{10}\right)\)
12. \(-\left(\frac{8}{-13}\right)-\left(\frac{-8}{3}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{10}{-7}\right)-\left(\frac{6}{13}\right)\\= \frac{-10}{7}-\frac{6}{13}\\=\frac{-130}{91}-\frac{42}{91}\\=\frac{-130-42}{91}\\=\frac{-172}{91}\)
2. \(-\left(\frac{-14}{11}\right)+\left(\frac{-4}{5}\right)\\= \frac{14}{11}-\frac{4}{5}\\=\frac{70}{55}-\frac{44}{55}\\=\frac{70-44}{55}\\=\frac{26}{55}\)
3. \(-\left(\frac{-3}{7}\right)+\left(\frac{10}{-9}\right)\\= \frac{3}{7}-\frac{10}{9}\\=\frac{27}{63}-\frac{70}{63}\\=\frac{27-70}{63}\\=\frac{-43}{63}\)
4. \(-\left(\frac{-12}{-11}\right)+\left(\frac{14}{3}\right)\\= \frac{-12}{11}+\frac{14}{3}\\=\frac{-36}{33}+\frac{154}{33}\\=\frac{-36+154}{33}\\=\frac{118}{33}\)
5. \(-\left(\frac{-10}{13}\right)+\left(\frac{8}{-3}\right)\\= \frac{10}{13}-\frac{8}{3}\\=\frac{30}{39}-\frac{104}{39}\\=\frac{30-104}{39}\\=\frac{-74}{39}\)
6. \(-\left(\frac{4}{3}\right)+\left(\frac{-10}{-13}\right)\\= \frac{-4}{3}+\frac{10}{13}\\=\frac{-52}{39}+\frac{30}{39}\\=\frac{-52+30}{39}\\=\frac{-22}{39}\)
7. \(+\left(\frac{11}{7}\right)-\left(\frac{-9}{2}\right)\\= \frac{11}{7}+\frac{9}{2}\\=\frac{22}{14}+\frac{63}{14}\\=\frac{22+63}{14}\\=\frac{85}{14}\)
8. \(+\left(\frac{14}{5}\right)+\left(\frac{-8}{3}\right)\\= \frac{14}{5}-\frac{8}{3}\\=\frac{42}{15}-\frac{40}{15}\\=\frac{42-40}{15}\\=\frac{2}{15}\)
9. \(-\left(\frac{-13}{-7}\right)+\left(\frac{12}{7}\right)\\= \frac{-13}{7}+\frac{12}{7}\\=\frac{-13+12}{7}\\=\frac{-1}{7}\)
10. \(-\left(\frac{10}{13}\right)-\left(\frac{14}{-9}\right)\\= \frac{-10}{13}+\frac{14}{9}\\=\frac{-90}{117}+\frac{182}{117}\\=\frac{-90+182}{117}\\=\frac{92}{117}\)
11. \(+\left(\frac{-3}{7}\right)+\left(\frac{-13}{10}\right)\\= \frac{-3}{7}-\frac{13}{10}\\=\frac{-30}{70}-\frac{91}{70}\\=\frac{-30-91}{70}\\=\frac{-121}{70}\)
12. \(-\left(\frac{8}{-13}\right)-\left(\frac{-8}{3}\right)\\= \frac{8}{13}+\frac{8}{3}\\=\frac{24}{39}+\frac{104}{39}\\=\frac{24+104}{39}\\=\frac{128}{39}\)