Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-7}{-12}\right)-\left(\frac{3}{4}\right)\)
2. \(+\left(\frac{-11}{-12}\right)-\left(\frac{6}{5}\right)\)
3. \(-\left(\frac{-8}{-7}\right)-\left(\frac{-11}{-5}\right)\)
4. \(+\left(\frac{-7}{-13}\right)-\left(\frac{-12}{-5}\right)\)
5. \(+\left(\frac{3}{-7}\right)-\left(\frac{-5}{-13}\right)\)
6. \(-\left(\frac{5}{-14}\right)-\left(\frac{15}{13}\right)\)
7. \(+\left(\frac{-8}{7}\right)+\left(\frac{2}{-3}\right)\)
8. \(-\left(\frac{-11}{13}\right)-\left(\frac{-15}{2}\right)\)
9. \(+\left(\frac{13}{-11}\right)-\left(\frac{-12}{-7}\right)\)
10. \(-\left(\frac{10}{-11}\right)-\left(\frac{-4}{5}\right)\)
11. \(-\left(\frac{2}{3}\right)+\left(\frac{-5}{-2}\right)\)
12. \(-\left(\frac{12}{5}\right)-\left(\frac{2}{3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-7}{-12}\right)-\left(\frac{3}{4}\right)\\= \frac{-7}{12}-\frac{3}{4}\\=\frac{-7-3}{12}\\=\frac{-10}{12}\\=\frac{-5}{6}\)
2. \(+\left(\frac{-11}{-12}\right)-\left(\frac{6}{5}\right)\\= \frac{11}{12}-\frac{6}{5}\\=\frac{55}{60}-\frac{72}{60}\\=\frac{55-72}{60}\\=\frac{-17}{60}\)
3. \(-\left(\frac{-8}{-7}\right)-\left(\frac{-11}{-5}\right)\\= \frac{-8}{7}-\frac{11}{5}\\=\frac{-40}{35}-\frac{77}{35}\\=\frac{-40-77}{35}\\=\frac{-117}{35}\)
4. \(+\left(\frac{-7}{-13}\right)-\left(\frac{-12}{-5}\right)\\= \frac{7}{13}-\frac{12}{5}\\=\frac{35}{65}-\frac{156}{65}\\=\frac{35-156}{65}\\=\frac{-121}{65}\)
5. \(+\left(\frac{3}{-7}\right)-\left(\frac{-5}{-13}\right)\\= \frac{-3}{7}-\frac{5}{13}\\=\frac{-39}{91}-\frac{35}{91}\\=\frac{-39-35}{91}\\=\frac{-74}{91}\)
6. \(-\left(\frac{5}{-14}\right)-\left(\frac{15}{13}\right)\\= \frac{5}{14}-\frac{15}{13}\\=\frac{65}{182}-\frac{210}{182}\\=\frac{65-210}{182}\\=\frac{-145}{182}\)
7. \(+\left(\frac{-8}{7}\right)+\left(\frac{2}{-3}\right)\\= \frac{-8}{7}-\frac{2}{3}\\=\frac{-24}{21}-\frac{14}{21}\\=\frac{-24-14}{21}\\=\frac{-38}{21}\)
8. \(-\left(\frac{-11}{13}\right)-\left(\frac{-15}{2}\right)\\= \frac{11}{13}+\frac{15}{2}\\=\frac{22}{26}+\frac{195}{26}\\=\frac{22+195}{26}\\=\frac{217}{26}\)
9. \(+\left(\frac{13}{-11}\right)-\left(\frac{-12}{-7}\right)\\= \frac{-13}{11}-\frac{12}{7}\\=\frac{-91}{77}-\frac{132}{77}\\=\frac{-91-132}{77}\\=\frac{-223}{77}\)
10. \(-\left(\frac{10}{-11}\right)-\left(\frac{-4}{5}\right)\\= \frac{10}{11}+\frac{4}{5}\\=\frac{50}{55}+\frac{44}{55}\\=\frac{50+44}{55}\\=\frac{94}{55}\)
11. \(-\left(\frac{2}{3}\right)+\left(\frac{-5}{-2}\right)\\= \frac{-2}{3}+\frac{5}{2}\\=\frac{-4}{6}+\frac{15}{6}\\=\frac{-4+15}{6}\\=\frac{11}{6}\)
12. \(-\left(\frac{12}{5}\right)-\left(\frac{2}{3}\right)\\= \frac{-12}{5}-\frac{2}{3}\\=\frac{-36}{15}-\frac{10}{15}\\=\frac{-36-10}{15}\\=\frac{-46}{15}\)