Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-3}{-4}\right)-\left(\frac{6}{-13}\right)\)
2. \(-\left(\frac{15}{-14}\right)-\left(\frac{15}{8}\right)\)
3. \(-\left(\frac{11}{-8}\right)-\left(\frac{-8}{11}\right)\)
4. \(+\left(\frac{2}{-11}\right)-\left(\frac{-5}{14}\right)\)
5. \(+\left(\frac{-14}{3}\right)-\left(\frac{-13}{-2}\right)\)
6. \(+\left(\frac{12}{7}\right)-\left(\frac{4}{-9}\right)\)
7. \(-\left(\frac{-10}{3}\right)-\left(\frac{-9}{2}\right)\)
8. \(+\left(\frac{13}{-10}\right)+\left(\frac{-2}{-3}\right)\)
9. \(-\left(\frac{14}{-9}\right)+\left(\frac{8}{-13}\right)\)
10. \(-\left(\frac{15}{-11}\right)-\left(\frac{-11}{-9}\right)\)
11. \(-\left(\frac{12}{13}\right)-\left(\frac{-4}{-9}\right)\)
12. \(+\left(\frac{-14}{-9}\right)-\left(\frac{10}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-3}{-4}\right)-\left(\frac{6}{-13}\right)\\= \frac{-3}{4}+\frac{6}{13}\\=\frac{-39}{52}+\frac{24}{52}\\=\frac{-39+24}{52}\\=\frac{-15}{52}\)
2. \(-\left(\frac{15}{-14}\right)-\left(\frac{15}{8}\right)\\= \frac{15}{14}-\frac{15}{8}\\=\frac{60}{56}-\frac{105}{56}\\=\frac{60-105}{56}\\=\frac{-45}{56}\)
3. \(-\left(\frac{11}{-8}\right)-\left(\frac{-8}{11}\right)\\= \frac{11}{8}+\frac{8}{11}\\=\frac{121}{88}+\frac{64}{88}\\=\frac{121+64}{88}\\=\frac{185}{88}\)
4. \(+\left(\frac{2}{-11}\right)-\left(\frac{-5}{14}\right)\\= \frac{-2}{11}+\frac{5}{14}\\=\frac{-28}{154}+\frac{55}{154}\\=\frac{-28+55}{154}\\=\frac{27}{154}\)
5. \(+\left(\frac{-14}{3}\right)-\left(\frac{-13}{-2}\right)\\= \frac{-14}{3}-\frac{13}{2}\\=\frac{-28}{6}-\frac{39}{6}\\=\frac{-28-39}{6}\\=\frac{-67}{6}\)
6. \(+\left(\frac{12}{7}\right)-\left(\frac{4}{-9}\right)\\= \frac{12}{7}+\frac{4}{9}\\=\frac{108}{63}+\frac{28}{63}\\=\frac{108+28}{63}\\=\frac{136}{63}\)
7. \(-\left(\frac{-10}{3}\right)-\left(\frac{-9}{2}\right)\\= \frac{10}{3}+\frac{9}{2}\\=\frac{20}{6}+\frac{27}{6}\\=\frac{20+27}{6}\\=\frac{47}{6}\)
8. \(+\left(\frac{13}{-10}\right)+\left(\frac{-2}{-3}\right)\\= \frac{-13}{10}+\frac{2}{3}\\=\frac{-39}{30}+\frac{20}{30}\\=\frac{-39+20}{30}\\=\frac{-19}{30}\)
9. \(-\left(\frac{14}{-9}\right)+\left(\frac{8}{-13}\right)\\= \frac{14}{9}-\frac{8}{13}\\=\frac{182}{117}-\frac{72}{117}\\=\frac{182-72}{117}\\=\frac{110}{117}\)
10. \(-\left(\frac{15}{-11}\right)-\left(\frac{-11}{-9}\right)\\= \frac{15}{11}-\frac{11}{9}\\=\frac{135}{99}-\frac{121}{99}\\=\frac{135-121}{99}\\=\frac{14}{99}\)
11. \(-\left(\frac{12}{13}\right)-\left(\frac{-4}{-9}\right)\\= \frac{-12}{13}-\frac{4}{9}\\=\frac{-108}{117}-\frac{52}{117}\\=\frac{-108-52}{117}\\=\frac{-160}{117}\)
12. \(+\left(\frac{-14}{-9}\right)-\left(\frac{10}{-13}\right)\\= \frac{14}{9}+\frac{10}{13}\\=\frac{182}{117}+\frac{90}{117}\\=\frac{182+90}{117}\\=\frac{272}{117}\)