Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-12}{5}\right)+\left(\frac{-12}{-11}\right)\)
2. \(-\left(\frac{10}{7}\right)+\left(\frac{-4}{7}\right)\)
3. \(+\left(\frac{-7}{-9}\right)+\left(\frac{-13}{-14}\right)\)
4. \(-\left(\frac{12}{5}\right)-\left(\frac{15}{11}\right)\)
5. \(+\left(\frac{-10}{-11}\right)-\left(\frac{-8}{-13}\right)\)
6. \(-\left(\frac{-4}{-7}\right)+\left(\frac{-6}{-5}\right)\)
7. \(-\left(\frac{-6}{-13}\right)-\left(\frac{12}{-11}\right)\)
8. \(+\left(\frac{-11}{9}\right)+\left(\frac{5}{-8}\right)\)
9. \(+\left(\frac{9}{-8}\right)+\left(\frac{-3}{14}\right)\)
10. \(-\left(\frac{-5}{11}\right)+\left(\frac{10}{-3}\right)\)
11. \(-\left(\frac{-7}{13}\right)-\left(\frac{11}{10}\right)\)
12. \(+\left(\frac{13}{6}\right)+\left(\frac{4}{7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-12}{5}\right)+\left(\frac{-12}{-11}\right)\\= \frac{-12}{5}+\frac{12}{11}\\=\frac{-132}{55}+\frac{60}{55}\\=\frac{-132+60}{55}\\=\frac{-72}{55}\)
2. \(-\left(\frac{10}{7}\right)+\left(\frac{-4}{7}\right)\\= \frac{-10}{7}-\frac{4}{7}\\=\frac{-10-4}{7}\\=\frac{-14}{7}\\=\frac{-2}{1}\)
3. \(+\left(\frac{-7}{-9}\right)+\left(\frac{-13}{-14}\right)\\= \frac{7}{9}+\frac{13}{14}\\=\frac{98}{126}+\frac{117}{126}\\=\frac{98+117}{126}\\=\frac{215}{126}\)
4. \(-\left(\frac{12}{5}\right)-\left(\frac{15}{11}\right)\\= \frac{-12}{5}-\frac{15}{11}\\=\frac{-132}{55}-\frac{75}{55}\\=\frac{-132-75}{55}\\=\frac{-207}{55}\)
5. \(+\left(\frac{-10}{-11}\right)-\left(\frac{-8}{-13}\right)\\= \frac{10}{11}-\frac{8}{13}\\=\frac{130}{143}-\frac{88}{143}\\=\frac{130-88}{143}\\=\frac{42}{143}\)
6. \(-\left(\frac{-4}{-7}\right)+\left(\frac{-6}{-5}\right)\\= \frac{-4}{7}+\frac{6}{5}\\=\frac{-20}{35}+\frac{42}{35}\\=\frac{-20+42}{35}\\=\frac{22}{35}\)
7. \(-\left(\frac{-6}{-13}\right)-\left(\frac{12}{-11}\right)\\= \frac{-6}{13}+\frac{12}{11}\\=\frac{-66}{143}+\frac{156}{143}\\=\frac{-66+156}{143}\\=\frac{90}{143}\)
8. \(+\left(\frac{-11}{9}\right)+\left(\frac{5}{-8}\right)\\= \frac{-11}{9}-\frac{5}{8}\\=\frac{-88}{72}-\frac{45}{72}\\=\frac{-88-45}{72}\\=\frac{-133}{72}\)
9. \(+\left(\frac{9}{-8}\right)+\left(\frac{-3}{14}\right)\\= \frac{-9}{8}-\frac{3}{14}\\=\frac{-63}{56}-\frac{12}{56}\\=\frac{-63-12}{56}\\=\frac{-75}{56}\)
10. \(-\left(\frac{-5}{11}\right)+\left(\frac{10}{-3}\right)\\= \frac{5}{11}-\frac{10}{3}\\=\frac{15}{33}-\frac{110}{33}\\=\frac{15-110}{33}\\=\frac{-95}{33}\)
11. \(-\left(\frac{-7}{13}\right)-\left(\frac{11}{10}\right)\\= \frac{7}{13}-\frac{11}{10}\\=\frac{70}{130}-\frac{143}{130}\\=\frac{70-143}{130}\\=\frac{-73}{130}\)
12. \(+\left(\frac{13}{6}\right)+\left(\frac{4}{7}\right)\\= \frac{13}{6}+\frac{4}{7}\\=\frac{91}{42}+\frac{24}{42}\\=\frac{91+24}{42}\\=\frac{115}{42}\)