Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{7}\right)+\left(\frac{-7}{5}\right)\)
2. \(-\left(\frac{-15}{-4}\right)+\left(\frac{-9}{10}\right)\)
3. \(+\left(\frac{5}{6}\right)+\left(\frac{3}{4}\right)\)
4. \(-\left(\frac{10}{3}\right)-\left(\frac{2}{-7}\right)\)
5. \(+\left(\frac{-10}{9}\right)-\left(\frac{-8}{3}\right)\)
6. \(+\left(\frac{10}{11}\right)-\left(\frac{-9}{7}\right)\)
7. \(+\left(\frac{4}{-5}\right)-\left(\frac{-12}{5}\right)\)
8. \(+\left(\frac{14}{-11}\right)-\left(\frac{-4}{-11}\right)\)
9. \(+\left(\frac{11}{10}\right)-\left(\frac{-2}{5}\right)\)
10. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-6}{11}\right)\)
11. \(-\left(\frac{-9}{14}\right)+\left(\frac{5}{13}\right)\)
12. \(+\left(\frac{-13}{-4}\right)+\left(\frac{-4}{11}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{10}{7}\right)+\left(\frac{-7}{5}\right)\\= \frac{10}{7}-\frac{7}{5}\\=\frac{50}{35}-\frac{49}{35}\\=\frac{50-49}{35}\\=\frac{1}{35}\)
2. \(-\left(\frac{-15}{-4}\right)+\left(\frac{-9}{10}\right)\\= \frac{-15}{4}-\frac{9}{10}\\=\frac{-75}{20}-\frac{18}{20}\\=\frac{-75-18}{20}\\=\frac{-93}{20}\)
3. \(+\left(\frac{5}{6}\right)+\left(\frac{3}{4}\right)\\= \frac{5}{6}+\frac{3}{4}\\=\frac{10}{12}+\frac{9}{12}\\=\frac{10+9}{12}\\=\frac{19}{12}\)
4. \(-\left(\frac{10}{3}\right)-\left(\frac{2}{-7}\right)\\= \frac{-10}{3}+\frac{2}{7}\\=\frac{-70}{21}+\frac{6}{21}\\=\frac{-70+6}{21}\\=\frac{-64}{21}\)
5. \(+\left(\frac{-10}{9}\right)-\left(\frac{-8}{3}\right)\\= \frac{-10}{9}+\frac{8}{3}\\=\frac{-10+8}{9}\\=\frac{-2}{9}\)
6. \(+\left(\frac{10}{11}\right)-\left(\frac{-9}{7}\right)\\= \frac{10}{11}+\frac{9}{7}\\=\frac{70}{77}+\frac{99}{77}\\=\frac{70+99}{77}\\=\frac{169}{77}\)
7. \(+\left(\frac{4}{-5}\right)-\left(\frac{-12}{5}\right)\\= \frac{-4}{5}+\frac{12}{5}\\=\frac{-4+12}{5}\\=\frac{8}{5}\)
8. \(+\left(\frac{14}{-11}\right)-\left(\frac{-4}{-11}\right)\\= \frac{-14}{11}-\frac{4}{11}\\=\frac{-14-4}{11}\\=\frac{-18}{11}\)
9. \(+\left(\frac{11}{10}\right)-\left(\frac{-2}{5}\right)\\= \frac{11}{10}+\frac{2}{5}\\=\frac{11+2}{10}\\=\frac{13}{10}\)
10. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-6}{11}\right)\\= \frac{-6}{11}+\frac{6}{11}\\=\frac{-6+6}{11}\\=\frac{0}{11}\\=\frac{0}{1}\)
11. \(-\left(\frac{-9}{14}\right)+\left(\frac{5}{13}\right)\\= \frac{9}{14}+\frac{5}{13}\\=\frac{117}{182}+\frac{70}{182}\\=\frac{117+70}{182}\\=\frac{187}{182}\)
12. \(+\left(\frac{-13}{-4}\right)+\left(\frac{-4}{11}\right)\\= \frac{13}{4}-\frac{4}{11}\\=\frac{143}{44}-\frac{16}{44}\\=\frac{143-16}{44}\\=\frac{127}{44}\)