Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-8}{5}\right)-\left(\frac{-11}{-2}\right)\)
2. \(+\left(\frac{6}{-7}\right)+\left(\frac{-4}{9}\right)\)
3. \(+\left(\frac{9}{13}\right)-\left(\frac{-2}{11}\right)\)
4. \(+\left(\frac{-6}{-5}\right)-\left(\frac{-14}{3}\right)\)
5. \(+\left(\frac{5}{6}\right)-\left(\frac{-11}{-10}\right)\)
6. \(+\left(\frac{-2}{11}\right)-\left(\frac{5}{-6}\right)\)
7. \(+\left(\frac{10}{-3}\right)-\left(\frac{15}{14}\right)\)
8. \(-\left(\frac{-3}{-11}\right)+\left(\frac{15}{-13}\right)\)
9. \(-\left(\frac{-6}{-11}\right)+\left(\frac{11}{-14}\right)\)
10. \(-\left(\frac{8}{-3}\right)+\left(\frac{2}{3}\right)\)
11. \(-\left(\frac{15}{4}\right)+\left(\frac{7}{-8}\right)\)
12. \(-\left(\frac{4}{-3}\right)+\left(\frac{-14}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-8}{5}\right)-\left(\frac{-11}{-2}\right)\\= \frac{-8}{5}-\frac{11}{2}\\=\frac{-16}{10}-\frac{55}{10}\\=\frac{-16-55}{10}\\=\frac{-71}{10}\)
2. \(+\left(\frac{6}{-7}\right)+\left(\frac{-4}{9}\right)\\= \frac{-6}{7}-\frac{4}{9}\\=\frac{-54}{63}-\frac{28}{63}\\=\frac{-54-28}{63}\\=\frac{-82}{63}\)
3. \(+\left(\frac{9}{13}\right)-\left(\frac{-2}{11}\right)\\= \frac{9}{13}+\frac{2}{11}\\=\frac{99}{143}+\frac{26}{143}\\=\frac{99+26}{143}\\=\frac{125}{143}\)
4. \(+\left(\frac{-6}{-5}\right)-\left(\frac{-14}{3}\right)\\= \frac{6}{5}+\frac{14}{3}\\=\frac{18}{15}+\frac{70}{15}\\=\frac{18+70}{15}\\=\frac{88}{15}\)
5. \(+\left(\frac{5}{6}\right)-\left(\frac{-11}{-10}\right)\\= \frac{5}{6}-\frac{11}{10}\\=\frac{25}{30}-\frac{33}{30}\\=\frac{25-33}{30}\\=\frac{-8}{30}\\=\frac{-4}{15}\)
6. \(+\left(\frac{-2}{11}\right)-\left(\frac{5}{-6}\right)\\= \frac{-2}{11}+\frac{5}{6}\\=\frac{-12}{66}+\frac{55}{66}\\=\frac{-12+55}{66}\\=\frac{43}{66}\)
7. \(+\left(\frac{10}{-3}\right)-\left(\frac{15}{14}\right)\\= \frac{-10}{3}-\frac{15}{14}\\=\frac{-140}{42}-\frac{45}{42}\\=\frac{-140-45}{42}\\=\frac{-185}{42}\)
8. \(-\left(\frac{-3}{-11}\right)+\left(\frac{15}{-13}\right)\\= \frac{-3}{11}-\frac{15}{13}\\=\frac{-39}{143}-\frac{165}{143}\\=\frac{-39-165}{143}\\=\frac{-204}{143}\)
9. \(-\left(\frac{-6}{-11}\right)+\left(\frac{11}{-14}\right)\\= \frac{-6}{11}-\frac{11}{14}\\=\frac{-84}{154}-\frac{121}{154}\\=\frac{-84-121}{154}\\=\frac{-205}{154}\)
10. \(-\left(\frac{8}{-3}\right)+\left(\frac{2}{3}\right)\\= \frac{8}{3}+\frac{2}{3}\\=\frac{8+2}{3}\\=\frac{10}{3}\)
11. \(-\left(\frac{15}{4}\right)+\left(\frac{7}{-8}\right)\\= \frac{-15}{4}-\frac{7}{8}\\=\frac{-30}{8}-\frac{7}{8}\\=\frac{-30-7}{8}\\=\frac{-37}{8}\)
12. \(-\left(\frac{4}{-3}\right)+\left(\frac{-14}{-3}\right)\\= \frac{4}{3}+\frac{14}{3}\\=\frac{4+14}{3}\\=\frac{18}{3}\\=\frac{6}{1}\)