Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{4}{3}\right)-\left(\frac{-8}{-3}\right)\)
2. \(+\left(\frac{-8}{3}\right)-\left(\frac{11}{2}\right)\)
3. \(+\left(\frac{-2}{-11}\right)-\left(\frac{10}{7}\right)\)
4. \(+\left(\frac{9}{10}\right)+\left(\frac{7}{-3}\right)\)
5. \(+\left(\frac{-9}{-4}\right)-\left(\frac{-4}{-7}\right)\)
6. \(-\left(\frac{5}{-9}\right)+\left(\frac{8}{-3}\right)\)
7. \(-\left(\frac{6}{-5}\right)-\left(\frac{-14}{5}\right)\)
8. \(-\left(\frac{15}{-8}\right)+\left(\frac{15}{-4}\right)\)
9. \(-\left(\frac{-14}{3}\right)+\left(\frac{-8}{13}\right)\)
10. \(+\left(\frac{-11}{-12}\right)+\left(\frac{-3}{-10}\right)\)
11. \(+\left(\frac{-9}{-14}\right)-\left(\frac{15}{-14}\right)\)
12. \(-\left(\frac{15}{11}\right)+\left(\frac{10}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{4}{3}\right)-\left(\frac{-8}{-3}\right)\\= \frac{-4}{3}-\frac{8}{3}\\=\frac{-4-8}{3}\\=\frac{-12}{3}\\=\frac{-4}{1}\)
2. \(+\left(\frac{-8}{3}\right)-\left(\frac{11}{2}\right)\\= \frac{-8}{3}-\frac{11}{2}\\=\frac{-16}{6}-\frac{33}{6}\\=\frac{-16-33}{6}\\=\frac{-49}{6}\)
3. \(+\left(\frac{-2}{-11}\right)-\left(\frac{10}{7}\right)\\= \frac{2}{11}-\frac{10}{7}\\=\frac{14}{77}-\frac{110}{77}\\=\frac{14-110}{77}\\=\frac{-96}{77}\)
4. \(+\left(\frac{9}{10}\right)+\left(\frac{7}{-3}\right)\\= \frac{9}{10}-\frac{7}{3}\\=\frac{27}{30}-\frac{70}{30}\\=\frac{27-70}{30}\\=\frac{-43}{30}\)
5. \(+\left(\frac{-9}{-4}\right)-\left(\frac{-4}{-7}\right)\\= \frac{9}{4}-\frac{4}{7}\\=\frac{63}{28}-\frac{16}{28}\\=\frac{63-16}{28}\\=\frac{47}{28}\)
6. \(-\left(\frac{5}{-9}\right)+\left(\frac{8}{-3}\right)\\= \frac{5}{9}-\frac{8}{3}\\=\frac{5-8}{9}\\=\frac{-3}{9}\\=\frac{-1}{3}\)
7. \(-\left(\frac{6}{-5}\right)-\left(\frac{-14}{5}\right)\\= \frac{6}{5}+\frac{14}{5}\\=\frac{6+14}{5}\\=\frac{20}{5}\\=\frac{4}{1}\)
8. \(-\left(\frac{15}{-8}\right)+\left(\frac{15}{-4}\right)\\= \frac{15}{8}-\frac{15}{4}\\=\frac{15-15}{8}\\=\frac{0}{8}\\=\frac{0}{1}\)
9. \(-\left(\frac{-14}{3}\right)+\left(\frac{-8}{13}\right)\\= \frac{14}{3}-\frac{8}{13}\\=\frac{182}{39}-\frac{24}{39}\\=\frac{182-24}{39}\\=\frac{158}{39}\)
10. \(+\left(\frac{-11}{-12}\right)+\left(\frac{-3}{-10}\right)\\= \frac{11}{12}+\frac{3}{10}\\=\frac{55}{60}+\frac{18}{60}\\=\frac{55+18}{60}\\=\frac{73}{60}\)
11. \(+\left(\frac{-9}{-14}\right)-\left(\frac{15}{-14}\right)\\= \frac{9}{14}+\frac{15}{14}\\=\frac{9+15}{14}\\=\frac{24}{14}\\=\frac{12}{7}\)
12. \(-\left(\frac{15}{11}\right)+\left(\frac{10}{-13}\right)\\= \frac{-15}{11}-\frac{10}{13}\\=\frac{-195}{143}-\frac{110}{143}\\=\frac{-195-110}{143}\\=\frac{-305}{143}\)