Breuken haakjesregel (reeks 1)

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Bereken

1. \(-\left(\frac{-2}{9}\right)+\left(\frac{-13}{14}\right)\)
2. \(+\left(\frac{-6}{11}\right)-\left(\frac{-11}{-8}\right)\)
3. \(+\left(\frac{5}{13}\right)+\left(\frac{11}{3}\right)\)
4. \(-\left(\frac{7}{2}\right)-\left(\frac{-7}{-10}\right)\)
5. \(+\left(\frac{-13}{-2}\right)+\left(\frac{14}{-9}\right)\)
6. \(-\left(\frac{7}{12}\right)-\left(\frac{-10}{-3}\right)\)
7. \(+\left(\frac{7}{11}\right)-\left(\frac{-13}{11}\right)\)
8. \(-\left(\frac{-13}{6}\right)+\left(\frac{-7}{-6}\right)\)
9. \(-\left(\frac{6}{5}\right)-\left(\frac{-9}{-4}\right)\)
10. \(+\left(\frac{2}{3}\right)+\left(\frac{14}{-3}\right)\)
11. \(+\left(\frac{-8}{7}\right)+\left(\frac{-14}{3}\right)\)
12. \(-\left(\frac{7}{2}\right)+\left(\frac{-6}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-2}{9}\right)+\left(\frac{-13}{14}\right)\\= \frac{2}{9}-\frac{13}{14}\\=\frac{28}{126}-\frac{117}{126}\\=\frac{28-117}{126}\\=\frac{-89}{126}\)
2. \(+\left(\frac{-6}{11}\right)-\left(\frac{-11}{-8}\right)\\= \frac{-6}{11}-\frac{11}{8}\\=\frac{-48}{88}-\frac{121}{88}\\=\frac{-48-121}{88}\\=\frac{-169}{88}\)
3. \(+\left(\frac{5}{13}\right)+\left(\frac{11}{3}\right)\\= \frac{5}{13}+\frac{11}{3}\\=\frac{15}{39}+\frac{143}{39}\\=\frac{15+143}{39}\\=\frac{158}{39}\)
4. \(-\left(\frac{7}{2}\right)-\left(\frac{-7}{-10}\right)\\= \frac{-7}{2}-\frac{7}{10}\\=\frac{-35}{10}-\frac{7}{10}\\=\frac{-35-7}{10}\\=\frac{-42}{10}\\=\frac{-21}{5}\)
5. \(+\left(\frac{-13}{-2}\right)+\left(\frac{14}{-9}\right)\\= \frac{13}{2}-\frac{14}{9}\\=\frac{117}{18}-\frac{28}{18}\\=\frac{117-28}{18}\\=\frac{89}{18}\)
6. \(-\left(\frac{7}{12}\right)-\left(\frac{-10}{-3}\right)\\= \frac{-7}{12}-\frac{10}{3}\\=\frac{-7-10}{12}\\=\frac{-17}{12}\)
7. \(+\left(\frac{7}{11}\right)-\left(\frac{-13}{11}\right)\\= \frac{7}{11}+\frac{13}{11}\\=\frac{7+13}{11}\\=\frac{20}{11}\)
8. \(-\left(\frac{-13}{6}\right)+\left(\frac{-7}{-6}\right)\\= \frac{13}{6}+\frac{7}{6}\\=\frac{13+7}{6}\\=\frac{20}{6}\\=\frac{10}{3}\)
9. \(-\left(\frac{6}{5}\right)-\left(\frac{-9}{-4}\right)\\= \frac{-6}{5}-\frac{9}{4}\\=\frac{-24}{20}-\frac{45}{20}\\=\frac{-24-45}{20}\\=\frac{-69}{20}\)
10. \(+\left(\frac{2}{3}\right)+\left(\frac{14}{-3}\right)\\= \frac{2}{3}-\frac{14}{3}\\=\frac{2-14}{3}\\=\frac{-12}{3}\\=\frac{-4}{1}\)
11. \(+\left(\frac{-8}{7}\right)+\left(\frac{-14}{3}\right)\\= \frac{-8}{7}-\frac{14}{3}\\=\frac{-24}{21}-\frac{98}{21}\\=\frac{-24-98}{21}\\=\frac{-122}{21}\)
12. \(-\left(\frac{7}{2}\right)+\left(\frac{-6}{-5}\right)\\= \frac{-7}{2}+\frac{6}{5}\\=\frac{-35}{10}+\frac{12}{10}\\=\frac{-35+12}{10}\\=\frac{-23}{10}\)