Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-8}{9}\right)-\left(\frac{-8}{5}\right)\)
2. \(-\left(\frac{2}{11}\right)+\left(\frac{-3}{-4}\right)\)
3. \(+\left(\frac{8}{5}\right)-\left(\frac{3}{-5}\right)\)
4. \(-\left(\frac{12}{5}\right)-\left(\frac{7}{-8}\right)\)
5. \(-\left(\frac{10}{-13}\right)+\left(\frac{-15}{-7}\right)\)
6. \(-\left(\frac{-6}{5}\right)+\left(\frac{9}{7}\right)\)
7. \(-\left(\frac{-8}{13}\right)-\left(\frac{-3}{7}\right)\)
8. \(+\left(\frac{-4}{3}\right)-\left(\frac{-9}{2}\right)\)
9. \(+\left(\frac{-12}{5}\right)+\left(\frac{5}{-14}\right)\)
10. \(-\left(\frac{11}{-14}\right)+\left(\frac{2}{-11}\right)\)
11. \(+\left(\frac{-3}{-2}\right)+\left(\frac{-7}{-10}\right)\)
12. \(-\left(\frac{-14}{13}\right)+\left(\frac{7}{11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-8}{9}\right)-\left(\frac{-8}{5}\right)\\= \frac{8}{9}+\frac{8}{5}\\=\frac{40}{45}+\frac{72}{45}\\=\frac{40+72}{45}\\=\frac{112}{45}\)
2. \(-\left(\frac{2}{11}\right)+\left(\frac{-3}{-4}\right)\\= \frac{-2}{11}+\frac{3}{4}\\=\frac{-8}{44}+\frac{33}{44}\\=\frac{-8+33}{44}\\=\frac{25}{44}\)
3. \(+\left(\frac{8}{5}\right)-\left(\frac{3}{-5}\right)\\= \frac{8}{5}+\frac{3}{5}\\=\frac{8+3}{5}\\=\frac{11}{5}\)
4. \(-\left(\frac{12}{5}\right)-\left(\frac{7}{-8}\right)\\= \frac{-12}{5}+\frac{7}{8}\\=\frac{-96}{40}+\frac{35}{40}\\=\frac{-96+35}{40}\\=\frac{-61}{40}\)
5. \(-\left(\frac{10}{-13}\right)+\left(\frac{-15}{-7}\right)\\= \frac{10}{13}+\frac{15}{7}\\=\frac{70}{91}+\frac{195}{91}\\=\frac{70+195}{91}\\=\frac{265}{91}\)
6. \(-\left(\frac{-6}{5}\right)+\left(\frac{9}{7}\right)\\= \frac{6}{5}+\frac{9}{7}\\=\frac{42}{35}+\frac{45}{35}\\=\frac{42+45}{35}\\=\frac{87}{35}\)
7. \(-\left(\frac{-8}{13}\right)-\left(\frac{-3}{7}\right)\\= \frac{8}{13}+\frac{3}{7}\\=\frac{56}{91}+\frac{39}{91}\\=\frac{56+39}{91}\\=\frac{95}{91}\)
8. \(+\left(\frac{-4}{3}\right)-\left(\frac{-9}{2}\right)\\= \frac{-4}{3}+\frac{9}{2}\\=\frac{-8}{6}+\frac{27}{6}\\=\frac{-8+27}{6}\\=\frac{19}{6}\)
9. \(+\left(\frac{-12}{5}\right)+\left(\frac{5}{-14}\right)\\= \frac{-12}{5}-\frac{5}{14}\\=\frac{-168}{70}-\frac{25}{70}\\=\frac{-168-25}{70}\\=\frac{-193}{70}\)
10. \(-\left(\frac{11}{-14}\right)+\left(\frac{2}{-11}\right)\\= \frac{11}{14}-\frac{2}{11}\\=\frac{121}{154}-\frac{28}{154}\\=\frac{121-28}{154}\\=\frac{93}{154}\)
11. \(+\left(\frac{-3}{-2}\right)+\left(\frac{-7}{-10}\right)\\= \frac{3}{2}+\frac{7}{10}\\=\frac{15}{10}+\frac{7}{10}\\=\frac{15+7}{10}\\=\frac{22}{10}\\=\frac{11}{5}\)
12. \(-\left(\frac{-14}{13}\right)+\left(\frac{7}{11}\right)\\= \frac{14}{13}+\frac{7}{11}\\=\frac{154}{143}+\frac{91}{143}\\=\frac{154+91}{143}\\=\frac{245}{143}\)