Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-15}{4}\right)+\left(\frac{-4}{5}\right)\)
2. \(+\left(\frac{2}{-13}\right)-\left(\frac{7}{-10}\right)\)
3. \(+\left(\frac{5}{-13}\right)-\left(\frac{-8}{-11}\right)\)
4. \(-\left(\frac{-10}{3}\right)+\left(\frac{-2}{-9}\right)\)
5. \(-\left(\frac{9}{-4}\right)+\left(\frac{-15}{4}\right)\)
6. \(-\left(\frac{-2}{3}\right)+\left(\frac{-11}{-9}\right)\)
7. \(-\left(\frac{2}{11}\right)+\left(\frac{-13}{2}\right)\)
8. \(-\left(\frac{9}{-7}\right)+\left(\frac{15}{-2}\right)\)
9. \(+\left(\frac{-14}{13}\right)-\left(\frac{-8}{9}\right)\)
10. \(+\left(\frac{-4}{-3}\right)+\left(\frac{6}{11}\right)\)
11. \(-\left(\frac{8}{11}\right)+\left(\frac{8}{3}\right)\)
12. \(+\left(\frac{10}{-13}\right)-\left(\frac{12}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-15}{4}\right)+\left(\frac{-4}{5}\right)\\= \frac{-15}{4}-\frac{4}{5}\\=\frac{-75}{20}-\frac{16}{20}\\=\frac{-75-16}{20}\\=\frac{-91}{20}\)
2. \(+\left(\frac{2}{-13}\right)-\left(\frac{7}{-10}\right)\\= \frac{-2}{13}+\frac{7}{10}\\=\frac{-20}{130}+\frac{91}{130}\\=\frac{-20+91}{130}\\=\frac{71}{130}\)
3. \(+\left(\frac{5}{-13}\right)-\left(\frac{-8}{-11}\right)\\= \frac{-5}{13}-\frac{8}{11}\\=\frac{-55}{143}-\frac{104}{143}\\=\frac{-55-104}{143}\\=\frac{-159}{143}\)
4. \(-\left(\frac{-10}{3}\right)+\left(\frac{-2}{-9}\right)\\= \frac{10}{3}+\frac{2}{9}\\=\frac{30}{9}+\frac{2}{9}\\=\frac{30+2}{9}\\=\frac{32}{9}\)
5. \(-\left(\frac{9}{-4}\right)+\left(\frac{-15}{4}\right)\\= \frac{9}{4}-\frac{15}{4}\\=\frac{9-15}{4}\\=\frac{-6}{4}\\=\frac{-3}{2}\)
6. \(-\left(\frac{-2}{3}\right)+\left(\frac{-11}{-9}\right)\\= \frac{2}{3}+\frac{11}{9}\\=\frac{6}{9}+\frac{11}{9}\\=\frac{6+11}{9}\\=\frac{17}{9}\)
7. \(-\left(\frac{2}{11}\right)+\left(\frac{-13}{2}\right)\\= \frac{-2}{11}-\frac{13}{2}\\=\frac{-4}{22}-\frac{143}{22}\\=\frac{-4-143}{22}\\=\frac{-147}{22}\)
8. \(-\left(\frac{9}{-7}\right)+\left(\frac{15}{-2}\right)\\= \frac{9}{7}-\frac{15}{2}\\=\frac{18}{14}-\frac{105}{14}\\=\frac{18-105}{14}\\=\frac{-87}{14}\)
9. \(+\left(\frac{-14}{13}\right)-\left(\frac{-8}{9}\right)\\= \frac{-14}{13}+\frac{8}{9}\\=\frac{-126}{117}+\frac{104}{117}\\=\frac{-126+104}{117}\\=\frac{-22}{117}\)
10. \(+\left(\frac{-4}{-3}\right)+\left(\frac{6}{11}\right)\\= \frac{4}{3}+\frac{6}{11}\\=\frac{44}{33}+\frac{18}{33}\\=\frac{44+18}{33}\\=\frac{62}{33}\)
11. \(-\left(\frac{8}{11}\right)+\left(\frac{8}{3}\right)\\= \frac{-8}{11}+\frac{8}{3}\\=\frac{-24}{33}+\frac{88}{33}\\=\frac{-24+88}{33}\\=\frac{64}{33}\)
12. \(+\left(\frac{10}{-13}\right)-\left(\frac{12}{-11}\right)\\= \frac{-10}{13}+\frac{12}{11}\\=\frac{-110}{143}+\frac{156}{143}\\=\frac{-110+156}{143}\\=\frac{46}{143}\)