Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{14}{-9}\right)-\left(\frac{-15}{11}\right)\)
2. \(+\left(\frac{-4}{7}\right)+\left(\frac{-12}{5}\right)\)
3. \(+\left(\frac{5}{-9}\right)-\left(\frac{-12}{13}\right)\)
4. \(+\left(\frac{-11}{-12}\right)+\left(\frac{7}{-8}\right)\)
5. \(+\left(\frac{8}{5}\right)-\left(\frac{7}{12}\right)\)
6. \(+\left(\frac{-11}{2}\right)+\left(\frac{-2}{5}\right)\)
7. \(+\left(\frac{5}{-2}\right)+\left(\frac{3}{-4}\right)\)
8. \(+\left(\frac{-2}{-5}\right)+\left(\frac{15}{4}\right)\)
9. \(-\left(\frac{-2}{-7}\right)+\left(\frac{8}{-13}\right)\)
10. \(-\left(\frac{-9}{-10}\right)-\left(\frac{11}{-2}\right)\)
11. \(-\left(\frac{-6}{-5}\right)-\left(\frac{13}{9}\right)\)
12. \(-\left(\frac{15}{2}\right)-\left(\frac{13}{-4}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{14}{-9}\right)-\left(\frac{-15}{11}\right)\\= \frac{-14}{9}+\frac{15}{11}\\=\frac{-154}{99}+\frac{135}{99}\\=\frac{-154+135}{99}\\=\frac{-19}{99}\)
2. \(+\left(\frac{-4}{7}\right)+\left(\frac{-12}{5}\right)\\= \frac{-4}{7}-\frac{12}{5}\\=\frac{-20}{35}-\frac{84}{35}\\=\frac{-20-84}{35}\\=\frac{-104}{35}\)
3. \(+\left(\frac{5}{-9}\right)-\left(\frac{-12}{13}\right)\\= \frac{-5}{9}+\frac{12}{13}\\=\frac{-65}{117}+\frac{108}{117}\\=\frac{-65+108}{117}\\=\frac{43}{117}\)
4. \(+\left(\frac{-11}{-12}\right)+\left(\frac{7}{-8}\right)\\= \frac{11}{12}-\frac{7}{8}\\=\frac{22}{24}-\frac{21}{24}\\=\frac{22-21}{24}\\=\frac{1}{24}\)
5. \(+\left(\frac{8}{5}\right)-\left(\frac{7}{12}\right)\\= \frac{8}{5}-\frac{7}{12}\\=\frac{96}{60}-\frac{35}{60}\\=\frac{96-35}{60}\\=\frac{61}{60}\)
6. \(+\left(\frac{-11}{2}\right)+\left(\frac{-2}{5}\right)\\= \frac{-11}{2}-\frac{2}{5}\\=\frac{-55}{10}-\frac{4}{10}\\=\frac{-55-4}{10}\\=\frac{-59}{10}\)
7. \(+\left(\frac{5}{-2}\right)+\left(\frac{3}{-4}\right)\\= \frac{-5}{2}-\frac{3}{4}\\=\frac{-10}{4}-\frac{3}{4}\\=\frac{-10-3}{4}\\=\frac{-13}{4}\)
8. \(+\left(\frac{-2}{-5}\right)+\left(\frac{15}{4}\right)\\= \frac{2}{5}+\frac{15}{4}\\=\frac{8}{20}+\frac{75}{20}\\=\frac{8+75}{20}\\=\frac{83}{20}\)
9. \(-\left(\frac{-2}{-7}\right)+\left(\frac{8}{-13}\right)\\= \frac{-2}{7}-\frac{8}{13}\\=\frac{-26}{91}-\frac{56}{91}\\=\frac{-26-56}{91}\\=\frac{-82}{91}\)
10. \(-\left(\frac{-9}{-10}\right)-\left(\frac{11}{-2}\right)\\= \frac{-9}{10}+\frac{11}{2}\\=\frac{-9+11}{10}\\=\frac{2}{10}\\=\frac{1}{5}\)
11. \(-\left(\frac{-6}{-5}\right)-\left(\frac{13}{9}\right)\\= \frac{-6}{5}-\frac{13}{9}\\=\frac{-54}{45}-\frac{65}{45}\\=\frac{-54-65}{45}\\=\frac{-119}{45}\)
12. \(-\left(\frac{15}{2}\right)-\left(\frac{13}{-4}\right)\\= \frac{-15}{2}+\frac{13}{4}\\=\frac{-30}{4}+\frac{13}{4}\\=\frac{-30+13}{4}\\=\frac{-17}{4}\)