Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-12}{5}\right)-\left(\frac{8}{3}\right)\)
2. \(-\left(\frac{-8}{7}\right)+\left(\frac{-11}{9}\right)\)
3. \(+\left(\frac{12}{11}\right)+\left(\frac{14}{9}\right)\)
4. \(-\left(\frac{-6}{-5}\right)+\left(\frac{5}{-6}\right)\)
5. \(+\left(\frac{4}{3}\right)+\left(\frac{11}{-8}\right)\)
6. \(-\left(\frac{9}{-13}\right)-\left(\frac{5}{9}\right)\)
7. \(+\left(\frac{5}{7}\right)-\left(\frac{-15}{11}\right)\)
8. \(-\left(\frac{-8}{-3}\right)+\left(\frac{-15}{14}\right)\)
9. \(+\left(\frac{-2}{7}\right)-\left(\frac{3}{2}\right)\)
10. \(-\left(\frac{6}{7}\right)+\left(\frac{10}{-11}\right)\)
11. \(+\left(\frac{12}{11}\right)-\left(\frac{8}{-13}\right)\)
12. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-5}{6}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-12}{5}\right)-\left(\frac{8}{3}\right)\\= \frac{-12}{5}-\frac{8}{3}\\=\frac{-36}{15}-\frac{40}{15}\\=\frac{-36-40}{15}\\=\frac{-76}{15}\)
2. \(-\left(\frac{-8}{7}\right)+\left(\frac{-11}{9}\right)\\= \frac{8}{7}-\frac{11}{9}\\=\frac{72}{63}-\frac{77}{63}\\=\frac{72-77}{63}\\=\frac{-5}{63}\)
3. \(+\left(\frac{12}{11}\right)+\left(\frac{14}{9}\right)\\= \frac{12}{11}+\frac{14}{9}\\=\frac{108}{99}+\frac{154}{99}\\=\frac{108+154}{99}\\=\frac{262}{99}\)
4. \(-\left(\frac{-6}{-5}\right)+\left(\frac{5}{-6}\right)\\= \frac{-6}{5}-\frac{5}{6}\\=\frac{-36}{30}-\frac{25}{30}\\=\frac{-36-25}{30}\\=\frac{-61}{30}\)
5. \(+\left(\frac{4}{3}\right)+\left(\frac{11}{-8}\right)\\= \frac{4}{3}-\frac{11}{8}\\=\frac{32}{24}-\frac{33}{24}\\=\frac{32-33}{24}\\=\frac{-1}{24}\)
6. \(-\left(\frac{9}{-13}\right)-\left(\frac{5}{9}\right)\\= \frac{9}{13}-\frac{5}{9}\\=\frac{81}{117}-\frac{65}{117}\\=\frac{81-65}{117}\\=\frac{16}{117}\)
7. \(+\left(\frac{5}{7}\right)-\left(\frac{-15}{11}\right)\\= \frac{5}{7}+\frac{15}{11}\\=\frac{55}{77}+\frac{105}{77}\\=\frac{55+105}{77}\\=\frac{160}{77}\)
8. \(-\left(\frac{-8}{-3}\right)+\left(\frac{-15}{14}\right)\\= \frac{-8}{3}-\frac{15}{14}\\=\frac{-112}{42}-\frac{45}{42}\\=\frac{-112-45}{42}\\=\frac{-157}{42}\)
9. \(+\left(\frac{-2}{7}\right)-\left(\frac{3}{2}\right)\\= \frac{-2}{7}-\frac{3}{2}\\=\frac{-4}{14}-\frac{21}{14}\\=\frac{-4-21}{14}\\=\frac{-25}{14}\)
10. \(-\left(\frac{6}{7}\right)+\left(\frac{10}{-11}\right)\\= \frac{-6}{7}-\frac{10}{11}\\=\frac{-66}{77}-\frac{70}{77}\\=\frac{-66-70}{77}\\=\frac{-136}{77}\)
11. \(+\left(\frac{12}{11}\right)-\left(\frac{8}{-13}\right)\\= \frac{12}{11}+\frac{8}{13}\\=\frac{156}{143}+\frac{88}{143}\\=\frac{156+88}{143}\\=\frac{244}{143}\)
12. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-5}{6}\right)\\= \frac{4}{3}+\frac{5}{6}\\=\frac{8}{6}+\frac{5}{6}\\=\frac{8+5}{6}\\=\frac{13}{6}\)