Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-12}{-5}\right)-\left(\frac{3}{-4}\right)\)
2. \(-\left(\frac{4}{7}\right)+\left(\frac{13}{12}\right)\)
3. \(-\left(\frac{8}{13}\right)-\left(\frac{-11}{2}\right)\)
4. \(+\left(\frac{-10}{-11}\right)-\left(\frac{-5}{-6}\right)\)
5. \(-\left(\frac{-8}{7}\right)+\left(\frac{14}{3}\right)\)
6. \(+\left(\frac{-2}{-3}\right)+\left(\frac{-4}{9}\right)\)
7. \(-\left(\frac{6}{5}\right)+\left(\frac{8}{-3}\right)\)
8. \(+\left(\frac{2}{-11}\right)+\left(\frac{5}{-11}\right)\)
9. \(+\left(\frac{-15}{4}\right)-\left(\frac{-8}{-3}\right)\)
10. \(-\left(\frac{-2}{11}\right)-\left(\frac{3}{10}\right)\)
11. \(+\left(\frac{-15}{11}\right)+\left(\frac{-7}{-12}\right)\)
12. \(-\left(\frac{4}{3}\right)-\left(\frac{14}{3}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-12}{-5}\right)-\left(\frac{3}{-4}\right)\\= \frac{12}{5}+\frac{3}{4}\\=\frac{48}{20}+\frac{15}{20}\\=\frac{48+15}{20}\\=\frac{63}{20}\)
2. \(-\left(\frac{4}{7}\right)+\left(\frac{13}{12}\right)\\= \frac{-4}{7}+\frac{13}{12}\\=\frac{-48}{84}+\frac{91}{84}\\=\frac{-48+91}{84}\\=\frac{43}{84}\)
3. \(-\left(\frac{8}{13}\right)-\left(\frac{-11}{2}\right)\\= \frac{-8}{13}+\frac{11}{2}\\=\frac{-16}{26}+\frac{143}{26}\\=\frac{-16+143}{26}\\=\frac{127}{26}\)
4. \(+\left(\frac{-10}{-11}\right)-\left(\frac{-5}{-6}\right)\\= \frac{10}{11}-\frac{5}{6}\\=\frac{60}{66}-\frac{55}{66}\\=\frac{60-55}{66}\\=\frac{5}{66}\)
5. \(-\left(\frac{-8}{7}\right)+\left(\frac{14}{3}\right)\\= \frac{8}{7}+\frac{14}{3}\\=\frac{24}{21}+\frac{98}{21}\\=\frac{24+98}{21}\\=\frac{122}{21}\)
6. \(+\left(\frac{-2}{-3}\right)+\left(\frac{-4}{9}\right)\\= \frac{2}{3}-\frac{4}{9}\\=\frac{6}{9}-\frac{4}{9}\\=\frac{6-4}{9}\\=\frac{2}{9}\)
7. \(-\left(\frac{6}{5}\right)+\left(\frac{8}{-3}\right)\\= \frac{-6}{5}-\frac{8}{3}\\=\frac{-18}{15}-\frac{40}{15}\\=\frac{-18-40}{15}\\=\frac{-58}{15}\)
8. \(+\left(\frac{2}{-11}\right)+\left(\frac{5}{-11}\right)\\= \frac{-2}{11}-\frac{5}{11}\\=\frac{-2-5}{11}\\=\frac{-7}{11}\)
9. \(+\left(\frac{-15}{4}\right)-\left(\frac{-8}{-3}\right)\\= \frac{-15}{4}-\frac{8}{3}\\=\frac{-45}{12}-\frac{32}{12}\\=\frac{-45-32}{12}\\=\frac{-77}{12}\)
10. \(-\left(\frac{-2}{11}\right)-\left(\frac{3}{10}\right)\\= \frac{2}{11}-\frac{3}{10}\\=\frac{20}{110}-\frac{33}{110}\\=\frac{20-33}{110}\\=\frac{-13}{110}\)
11. \(+\left(\frac{-15}{11}\right)+\left(\frac{-7}{-12}\right)\\= \frac{-15}{11}+\frac{7}{12}\\=\frac{-180}{132}+\frac{77}{132}\\=\frac{-180+77}{132}\\=\frac{-103}{132}\)
12. \(-\left(\frac{4}{3}\right)-\left(\frac{14}{3}\right)\\= \frac{-4}{3}-\frac{14}{3}\\=\frac{-4-14}{3}\\=\frac{-18}{3}\\=\frac{-6}{1}\)