Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{14}{-13}\right)-\left(\frac{-4}{13}\right)\)
2. \(+\left(\frac{9}{-8}\right)+\left(\frac{11}{12}\right)\)
3. \(-\left(\frac{5}{6}\right)-\left(\frac{6}{11}\right)\)
4. \(-\left(\frac{-15}{-11}\right)+\left(\frac{-2}{7}\right)\)
5. \(-\left(\frac{-6}{13}\right)+\left(\frac{15}{2}\right)\)
6. \(-\left(\frac{-12}{-5}\right)+\left(\frac{2}{-11}\right)\)
7. \(-\left(\frac{8}{11}\right)+\left(\frac{-4}{3}\right)\)
8. \(+\left(\frac{12}{11}\right)-\left(\frac{12}{-5}\right)\)
9. \(-\left(\frac{-15}{-11}\right)-\left(\frac{-12}{-5}\right)\)
10. \(-\left(\frac{10}{3}\right)-\left(\frac{5}{-14}\right)\)
11. \(-\left(\frac{-7}{-10}\right)+\left(\frac{2}{-11}\right)\)
12. \(-\left(\frac{3}{10}\right)-\left(\frac{10}{-7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{14}{-13}\right)-\left(\frac{-4}{13}\right)\\= \frac{14}{13}+\frac{4}{13}\\=\frac{14+4}{13}\\=\frac{18}{13}\)
2. \(+\left(\frac{9}{-8}\right)+\left(\frac{11}{12}\right)\\= \frac{-9}{8}+\frac{11}{12}\\=\frac{-27}{24}+\frac{22}{24}\\=\frac{-27+22}{24}\\=\frac{-5}{24}\)
3. \(-\left(\frac{5}{6}\right)-\left(\frac{6}{11}\right)\\= \frac{-5}{6}-\frac{6}{11}\\=\frac{-55}{66}-\frac{36}{66}\\=\frac{-55-36}{66}\\=\frac{-91}{66}\)
4. \(-\left(\frac{-15}{-11}\right)+\left(\frac{-2}{7}\right)\\= \frac{-15}{11}-\frac{2}{7}\\=\frac{-105}{77}-\frac{22}{77}\\=\frac{-105-22}{77}\\=\frac{-127}{77}\)
5. \(-\left(\frac{-6}{13}\right)+\left(\frac{15}{2}\right)\\= \frac{6}{13}+\frac{15}{2}\\=\frac{12}{26}+\frac{195}{26}\\=\frac{12+195}{26}\\=\frac{207}{26}\)
6. \(-\left(\frac{-12}{-5}\right)+\left(\frac{2}{-11}\right)\\= \frac{-12}{5}-\frac{2}{11}\\=\frac{-132}{55}-\frac{10}{55}\\=\frac{-132-10}{55}\\=\frac{-142}{55}\)
7. \(-\left(\frac{8}{11}\right)+\left(\frac{-4}{3}\right)\\= \frac{-8}{11}-\frac{4}{3}\\=\frac{-24}{33}-\frac{44}{33}\\=\frac{-24-44}{33}\\=\frac{-68}{33}\)
8. \(+\left(\frac{12}{11}\right)-\left(\frac{12}{-5}\right)\\= \frac{12}{11}+\frac{12}{5}\\=\frac{60}{55}+\frac{132}{55}\\=\frac{60+132}{55}\\=\frac{192}{55}\)
9. \(-\left(\frac{-15}{-11}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-15}{11}-\frac{12}{5}\\=\frac{-75}{55}-\frac{132}{55}\\=\frac{-75-132}{55}\\=\frac{-207}{55}\)
10. \(-\left(\frac{10}{3}\right)-\left(\frac{5}{-14}\right)\\= \frac{-10}{3}+\frac{5}{14}\\=\frac{-140}{42}+\frac{15}{42}\\=\frac{-140+15}{42}\\=\frac{-125}{42}\)
11. \(-\left(\frac{-7}{-10}\right)+\left(\frac{2}{-11}\right)\\= \frac{-7}{10}-\frac{2}{11}\\=\frac{-77}{110}-\frac{20}{110}\\=\frac{-77-20}{110}\\=\frac{-97}{110}\)
12. \(-\left(\frac{3}{10}\right)-\left(\frac{10}{-7}\right)\\= \frac{-3}{10}+\frac{10}{7}\\=\frac{-21}{70}+\frac{100}{70}\\=\frac{-21+100}{70}\\=\frac{79}{70}\)