Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{11}{3}\right)+\left(\frac{15}{14}\right)\)
2. \(-\left(\frac{-14}{-11}\right)-\left(\frac{14}{-3}\right)\)
3. \(+\left(\frac{8}{11}\right)-\left(\frac{14}{-11}\right)\)
4. \(+\left(\frac{14}{-3}\right)-\left(\frac{-12}{-13}\right)\)
5. \(+\left(\frac{14}{-3}\right)+\left(\frac{-11}{3}\right)\)
6. \(+\left(\frac{8}{-9}\right)-\left(\frac{3}{13}\right)\)
7. \(+\left(\frac{-3}{-7}\right)+\left(\frac{8}{5}\right)\)
8. \(+\left(\frac{-11}{-8}\right)-\left(\frac{-13}{2}\right)\)
9. \(+\left(\frac{-9}{2}\right)+\left(\frac{-6}{5}\right)\)
10. \(+\left(\frac{8}{13}\right)+\left(\frac{9}{7}\right)\)
11. \(+\left(\frac{9}{4}\right)-\left(\frac{-8}{3}\right)\)
12. \(+\left(\frac{3}{5}\right)+\left(\frac{5}{13}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{11}{3}\right)+\left(\frac{15}{14}\right)\\= \frac{11}{3}+\frac{15}{14}\\=\frac{154}{42}+\frac{45}{42}\\=\frac{154+45}{42}\\=\frac{199}{42}\)
2. \(-\left(\frac{-14}{-11}\right)-\left(\frac{14}{-3}\right)\\= \frac{-14}{11}+\frac{14}{3}\\=\frac{-42}{33}+\frac{154}{33}\\=\frac{-42+154}{33}\\=\frac{112}{33}\)
3. \(+\left(\frac{8}{11}\right)-\left(\frac{14}{-11}\right)\\= \frac{8}{11}+\frac{14}{11}\\=\frac{8+14}{11}\\=\frac{22}{11}\\=\frac{2}{1}\)
4. \(+\left(\frac{14}{-3}\right)-\left(\frac{-12}{-13}\right)\\= \frac{-14}{3}-\frac{12}{13}\\=\frac{-182}{39}-\frac{36}{39}\\=\frac{-182-36}{39}\\=\frac{-218}{39}\)
5. \(+\left(\frac{14}{-3}\right)+\left(\frac{-11}{3}\right)\\= \frac{-14}{3}-\frac{11}{3}\\=\frac{-14-11}{3}\\=\frac{-25}{3}\)
6. \(+\left(\frac{8}{-9}\right)-\left(\frac{3}{13}\right)\\= \frac{-8}{9}-\frac{3}{13}\\=\frac{-104}{117}-\frac{27}{117}\\=\frac{-104-27}{117}\\=\frac{-131}{117}\)
7. \(+\left(\frac{-3}{-7}\right)+\left(\frac{8}{5}\right)\\= \frac{3}{7}+\frac{8}{5}\\=\frac{15}{35}+\frac{56}{35}\\=\frac{15+56}{35}\\=\frac{71}{35}\)
8. \(+\left(\frac{-11}{-8}\right)-\left(\frac{-13}{2}\right)\\= \frac{11}{8}+\frac{13}{2}\\=\frac{11+13}{8}\\=\frac{24}{8}\\=\frac{3}{1}\)
9. \(+\left(\frac{-9}{2}\right)+\left(\frac{-6}{5}\right)\\= \frac{-9}{2}-\frac{6}{5}\\=\frac{-45}{10}-\frac{12}{10}\\=\frac{-45-12}{10}\\=\frac{-57}{10}\)
10. \(+\left(\frac{8}{13}\right)+\left(\frac{9}{7}\right)\\= \frac{8}{13}+\frac{9}{7}\\=\frac{56}{91}+\frac{117}{91}\\=\frac{56+117}{91}\\=\frac{173}{91}\)
11. \(+\left(\frac{9}{4}\right)-\left(\frac{-8}{3}\right)\\= \frac{9}{4}+\frac{8}{3}\\=\frac{27}{12}+\frac{32}{12}\\=\frac{27+32}{12}\\=\frac{59}{12}\)
12. \(+\left(\frac{3}{5}\right)+\left(\frac{5}{13}\right)\\= \frac{3}{5}+\frac{5}{13}\\=\frac{39}{65}+\frac{25}{65}\\=\frac{39+25}{65}\\=\frac{64}{65}\)