Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer 

Bereken

  1. \(+\left(\frac{2}{-13}\right)-\left(\frac{-3}{2}\right)\)
  2. \(-\left(\frac{4}{-11}\right)+\left(\frac{3}{4}\right)\)
  3. \(-\left(\frac{6}{5}\right)-\left(\frac{-2}{-13}\right)\)
  4. \(+\left(\frac{-2}{9}\right)+\left(\frac{-10}{-7}\right)\)
  5. \(+\left(\frac{-6}{11}\right)+\left(\frac{-13}{-3}\right)\)
  6. \(-\left(\frac{-11}{14}\right)+\left(\frac{8}{-3}\right)\)
  7. \(-\left(\frac{9}{-10}\right)-\left(\frac{5}{-7}\right)\)
  8. \(+\left(\frac{-10}{-3}\right)-\left(\frac{-7}{8}\right)\)
  9. \(+\left(\frac{8}{7}\right)+\left(\frac{11}{12}\right)\)
  10. \(+\left(\frac{-13}{14}\right)-\left(\frac{-7}{4}\right)\)
  11. \(+\left(\frac{-10}{-9}\right)+\left(\frac{-2}{-3}\right)\)
  12. \(+\left(\frac{-13}{-8}\right)+\left(\frac{-11}{10}\right)\)

Bereken

Verbetersleutel

  1. \(+\left(\frac{2}{-13}\right)-\left(\frac{-3}{2}\right)\\= \frac{-2}{13}+\frac{3}{2}\\=\frac{-4}{26}+\frac{39}{26}\\=\frac{-4+39}{26}\\=\frac{35}{26}\)
  2. \(-\left(\frac{4}{-11}\right)+\left(\frac{3}{4}\right)\\= \frac{4}{11}+\frac{3}{4}\\=\frac{16}{44}+\frac{33}{44}\\=\frac{16+33}{44}\\=\frac{49}{44}\)
  3. \(-\left(\frac{6}{5}\right)-\left(\frac{-2}{-13}\right)\\= \frac{-6}{5}-\frac{2}{13}\\=\frac{-78}{65}-\frac{10}{65}\\=\frac{-78-10}{65}\\=\frac{-88}{65}\)
  4. \(+\left(\frac{-2}{9}\right)+\left(\frac{-10}{-7}\right)\\= \frac{-2}{9}+\frac{10}{7}\\=\frac{-14}{63}+\frac{90}{63}\\=\frac{-14+90}{63}\\=\frac{76}{63}\)
  5. \(+\left(\frac{-6}{11}\right)+\left(\frac{-13}{-3}\right)\\= \frac{-6}{11}+\frac{13}{3}\\=\frac{-18}{33}+\frac{143}{33}\\=\frac{-18+143}{33}\\=\frac{125}{33}\)
  6. \(-\left(\frac{-11}{14}\right)+\left(\frac{8}{-3}\right)\\= \frac{11}{14}-\frac{8}{3}\\=\frac{33}{42}-\frac{112}{42}\\=\frac{33-112}{42}\\=\frac{-79}{42}\)
  7. \(-\left(\frac{9}{-10}\right)-\left(\frac{5}{-7}\right)\\= \frac{9}{10}+\frac{5}{7}\\=\frac{63}{70}+\frac{50}{70}\\=\frac{63+50}{70}\\=\frac{113}{70}\)
  8. \(+\left(\frac{-10}{-3}\right)-\left(\frac{-7}{8}\right)\\= \frac{10}{3}+\frac{7}{8}\\=\frac{80}{24}+\frac{21}{24}\\=\frac{80+21}{24}\\=\frac{101}{24}\)
  9. \(+\left(\frac{8}{7}\right)+\left(\frac{11}{12}\right)\\= \frac{8}{7}+\frac{11}{12}\\=\frac{96}{84}+\frac{77}{84}\\=\frac{96+77}{84}\\=\frac{173}{84}\)
  10. \(+\left(\frac{-13}{14}\right)-\left(\frac{-7}{4}\right)\\= \frac{-13}{14}+\frac{7}{4}\\=\frac{-26}{28}+\frac{49}{28}\\=\frac{-26+49}{28}\\=\frac{23}{28}\)
  11. \(+\left(\frac{-10}{-9}\right)+\left(\frac{-2}{-3}\right)\\= \frac{10}{9}+\frac{2}{3}\\=\frac{10+2}{9}\\=\frac{12}{9}\\=\frac{4}{3}\)
  12. \(+\left(\frac{-13}{-8}\right)+\left(\frac{-11}{10}\right)\\= \frac{13}{8}-\frac{11}{10}\\=\frac{65}{40}-\frac{44}{40}\\=\frac{65-44}{40}\\=\frac{21}{40}\)
Oefeningengenerator wiskundeoefeningen.be 2026-08-25 04:37:18
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