Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-11}{-12}\right)+\left(\frac{4}{5}\right)\)
2. \(+\left(\frac{8}{13}\right)+\left(\frac{-7}{2}\right)\)
3. \(+\left(\frac{10}{3}\right)+\left(\frac{7}{3}\right)\)
4. \(-\left(\frac{6}{-13}\right)-\left(\frac{15}{-7}\right)\)
5. \(+\left(\frac{12}{-7}\right)+\left(\frac{-3}{-2}\right)\)
6. \(+\left(\frac{6}{-11}\right)+\left(\frac{-6}{5}\right)\)
7. \(+\left(\frac{-10}{3}\right)+\left(\frac{-6}{-7}\right)\)
8. \(-\left(\frac{-14}{-13}\right)+\left(\frac{2}{13}\right)\)
9. \(-\left(\frac{15}{-7}\right)-\left(\frac{2}{3}\right)\)
10. \(-\left(\frac{6}{5}\right)-\left(\frac{15}{-7}\right)\)
11. \(-\left(\frac{-8}{11}\right)-\left(\frac{-11}{-7}\right)\)
12. \(+\left(\frac{-10}{3}\right)+\left(\frac{2}{-3}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{-11}{-12}\right)+\left(\frac{4}{5}\right)\\= \frac{-11}{12}+\frac{4}{5}\\=\frac{-55}{60}+\frac{48}{60}\\=\frac{-55+48}{60}\\=\frac{-7}{60}\)
2. \(+\left(\frac{8}{13}\right)+\left(\frac{-7}{2}\right)\\= \frac{8}{13}-\frac{7}{2}\\=\frac{16}{26}-\frac{91}{26}\\=\frac{16-91}{26}\\=\frac{-75}{26}\)
3. \(+\left(\frac{10}{3}\right)+\left(\frac{7}{3}\right)\\= \frac{10}{3}+\frac{7}{3}\\=\frac{10+7}{3}\\=\frac{17}{3}\)
4. \(-\left(\frac{6}{-13}\right)-\left(\frac{15}{-7}\right)\\= \frac{6}{13}+\frac{15}{7}\\=\frac{42}{91}+\frac{195}{91}\\=\frac{42+195}{91}\\=\frac{237}{91}\)
5. \(+\left(\frac{12}{-7}\right)+\left(\frac{-3}{-2}\right)\\= \frac{-12}{7}+\frac{3}{2}\\=\frac{-24}{14}+\frac{21}{14}\\=\frac{-24+21}{14}\\=\frac{-3}{14}\)
6. \(+\left(\frac{6}{-11}\right)+\left(\frac{-6}{5}\right)\\= \frac{-6}{11}-\frac{6}{5}\\=\frac{-30}{55}-\frac{66}{55}\\=\frac{-30-66}{55}\\=\frac{-96}{55}\)
7. \(+\left(\frac{-10}{3}\right)+\left(\frac{-6}{-7}\right)\\= \frac{-10}{3}+\frac{6}{7}\\=\frac{-70}{21}+\frac{18}{21}\\=\frac{-70+18}{21}\\=\frac{-52}{21}\)
8. \(-\left(\frac{-14}{-13}\right)+\left(\frac{2}{13}\right)\\= \frac{-14}{13}+\frac{2}{13}\\=\frac{-14+2}{13}\\=\frac{-12}{13}\)
9. \(-\left(\frac{15}{-7}\right)-\left(\frac{2}{3}\right)\\= \frac{15}{7}-\frac{2}{3}\\=\frac{45}{21}-\frac{14}{21}\\=\frac{45-14}{21}\\=\frac{31}{21}\)
10. \(-\left(\frac{6}{5}\right)-\left(\frac{15}{-7}\right)\\= \frac{-6}{5}+\frac{15}{7}\\=\frac{-42}{35}+\frac{75}{35}\\=\frac{-42+75}{35}\\=\frac{33}{35}\)
11. \(-\left(\frac{-8}{11}\right)-\left(\frac{-11}{-7}\right)\\= \frac{8}{11}-\frac{11}{7}\\=\frac{56}{77}-\frac{121}{77}\\=\frac{56-121}{77}\\=\frac{-65}{77}\)
12. \(+\left(\frac{-10}{3}\right)+\left(\frac{2}{-3}\right)\\= \frac{-10}{3}-\frac{2}{3}\\=\frac{-10-2}{3}\\=\frac{-12}{3}\\=\frac{-4}{1}\)