Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-2}{3}\right)-\left(\frac{-2}{-3}\right)\)
2. \(+\left(\frac{2}{-5}\right)+\left(\frac{-11}{-10}\right)\)
3. \(-\left(\frac{6}{5}\right)+\left(\frac{3}{-7}\right)\)
4. \(+\left(\frac{-11}{6}\right)+\left(\frac{10}{7}\right)\)
5. \(+\left(\frac{-3}{-8}\right)-\left(\frac{-13}{2}\right)\)
6. \(-\left(\frac{-9}{-13}\right)-\left(\frac{3}{14}\right)\)
7. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-2}{7}\right)\)
8. \(-\left(\frac{3}{-14}\right)-\left(\frac{3}{2}\right)\)
9. \(-\left(\frac{2}{9}\right)+\left(\frac{4}{3}\right)\)
10. \(-\left(\frac{2}{-3}\right)-\left(\frac{13}{8}\right)\)
11. \(-\left(\frac{3}{-13}\right)-\left(\frac{-13}{12}\right)\)
12. \(+\left(\frac{5}{-3}\right)-\left(\frac{10}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-2}{3}\right)-\left(\frac{-2}{-3}\right)\\= \frac{2}{3}-\frac{2}{3}\\=\frac{2-2}{3}\\=\frac{0}{3}\\=\frac{0}{1}\)
2. \(+\left(\frac{2}{-5}\right)+\left(\frac{-11}{-10}\right)\\= \frac{-2}{5}+\frac{11}{10}\\=\frac{-4}{10}+\frac{11}{10}\\=\frac{-4+11}{10}\\=\frac{7}{10}\)
3. \(-\left(\frac{6}{5}\right)+\left(\frac{3}{-7}\right)\\= \frac{-6}{5}-\frac{3}{7}\\=\frac{-42}{35}-\frac{15}{35}\\=\frac{-42-15}{35}\\=\frac{-57}{35}\)
4. \(+\left(\frac{-11}{6}\right)+\left(\frac{10}{7}\right)\\= \frac{-11}{6}+\frac{10}{7}\\=\frac{-77}{42}+\frac{60}{42}\\=\frac{-77+60}{42}\\=\frac{-17}{42}\)
5. \(+\left(\frac{-3}{-8}\right)-\left(\frac{-13}{2}\right)\\= \frac{3}{8}+\frac{13}{2}\\=\frac{3+13}{8}\\=\frac{16}{8}\\=\frac{2}{1}\)
6. \(-\left(\frac{-9}{-13}\right)-\left(\frac{3}{14}\right)\\= \frac{-9}{13}-\frac{3}{14}\\=\frac{-126}{182}-\frac{39}{182}\\=\frac{-126-39}{182}\\=\frac{-165}{182}\)
7. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-2}{7}\right)\\= \frac{-6}{11}+\frac{2}{7}\\=\frac{-42}{77}+\frac{22}{77}\\=\frac{-42+22}{77}\\=\frac{-20}{77}\)
8. \(-\left(\frac{3}{-14}\right)-\left(\frac{3}{2}\right)\\= \frac{3}{14}-\frac{3}{2}\\=\frac{3-3}{14}\\=\frac{0}{14}\\=\frac{0}{1}\)
9. \(-\left(\frac{2}{9}\right)+\left(\frac{4}{3}\right)\\= \frac{-2}{9}+\frac{4}{3}\\=\frac{-2+4}{9}\\=\frac{2}{9}\)
10. \(-\left(\frac{2}{-3}\right)-\left(\frac{13}{8}\right)\\= \frac{2}{3}-\frac{13}{8}\\=\frac{16}{24}-\frac{39}{24}\\=\frac{16-39}{24}\\=\frac{-23}{24}\)
11. \(-\left(\frac{3}{-13}\right)-\left(\frac{-13}{12}\right)\\= \frac{3}{13}+\frac{13}{12}\\=\frac{36}{156}+\frac{169}{156}\\=\frac{36+169}{156}\\=\frac{205}{156}\)
12. \(+\left(\frac{5}{-3}\right)-\left(\frac{10}{-13}\right)\\= \frac{-5}{3}+\frac{10}{13}\\=\frac{-65}{39}+\frac{30}{39}\\=\frac{-65+30}{39}\\=\frac{-35}{39}\)