Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-5}{2}\right)+\left(\frac{-3}{-10}\right)\)
2. \(-\left(\frac{7}{5}\right)+\left(\frac{-13}{8}\right)\)
3. \(-\left(\frac{3}{13}\right)+\left(\frac{-10}{7}\right)\)
4. \(-\left(\frac{-9}{7}\right)+\left(\frac{-14}{-5}\right)\)
5. \(-\left(\frac{14}{13}\right)-\left(\frac{2}{-3}\right)\)
6. \(-\left(\frac{-13}{-4}\right)+\left(\frac{15}{-13}\right)\)
7. \(+\left(\frac{-9}{-5}\right)-\left(\frac{10}{3}\right)\)
8. \(-\left(\frac{-15}{-14}\right)-\left(\frac{11}{14}\right)\)
9. \(-\left(\frac{11}{2}\right)-\left(\frac{-8}{-5}\right)\)
10. \(+\left(\frac{-6}{7}\right)+\left(\frac{-14}{-3}\right)\)
11. \(-\left(\frac{13}{-14}\right)-\left(\frac{11}{8}\right)\)
12. \(+\left(\frac{2}{-3}\right)+\left(\frac{8}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-5}{2}\right)+\left(\frac{-3}{-10}\right)\\= \frac{5}{2}+\frac{3}{10}\\=\frac{25}{10}+\frac{3}{10}\\=\frac{25+3}{10}\\=\frac{28}{10}\\=\frac{14}{5}\)
2. \(-\left(\frac{7}{5}\right)+\left(\frac{-13}{8}\right)\\= \frac{-7}{5}-\frac{13}{8}\\=\frac{-56}{40}-\frac{65}{40}\\=\frac{-56-65}{40}\\=\frac{-121}{40}\)
3. \(-\left(\frac{3}{13}\right)+\left(\frac{-10}{7}\right)\\= \frac{-3}{13}-\frac{10}{7}\\=\frac{-21}{91}-\frac{130}{91}\\=\frac{-21-130}{91}\\=\frac{-151}{91}\)
4. \(-\left(\frac{-9}{7}\right)+\left(\frac{-14}{-5}\right)\\= \frac{9}{7}+\frac{14}{5}\\=\frac{45}{35}+\frac{98}{35}\\=\frac{45+98}{35}\\=\frac{143}{35}\)
5. \(-\left(\frac{14}{13}\right)-\left(\frac{2}{-3}\right)\\= \frac{-14}{13}+\frac{2}{3}\\=\frac{-42}{39}+\frac{26}{39}\\=\frac{-42+26}{39}\\=\frac{-16}{39}\)
6. \(-\left(\frac{-13}{-4}\right)+\left(\frac{15}{-13}\right)\\= \frac{-13}{4}-\frac{15}{13}\\=\frac{-169}{52}-\frac{60}{52}\\=\frac{-169-60}{52}\\=\frac{-229}{52}\)
7. \(+\left(\frac{-9}{-5}\right)-\left(\frac{10}{3}\right)\\= \frac{9}{5}-\frac{10}{3}\\=\frac{27}{15}-\frac{50}{15}\\=\frac{27-50}{15}\\=\frac{-23}{15}\)
8. \(-\left(\frac{-15}{-14}\right)-\left(\frac{11}{14}\right)\\= \frac{-15}{14}-\frac{11}{14}\\=\frac{-15-11}{14}\\=\frac{-26}{14}\\=\frac{-13}{7}\)
9. \(-\left(\frac{11}{2}\right)-\left(\frac{-8}{-5}\right)\\= \frac{-11}{2}-\frac{8}{5}\\=\frac{-55}{10}-\frac{16}{10}\\=\frac{-55-16}{10}\\=\frac{-71}{10}\)
10. \(+\left(\frac{-6}{7}\right)+\left(\frac{-14}{-3}\right)\\= \frac{-6}{7}+\frac{14}{3}\\=\frac{-18}{21}+\frac{98}{21}\\=\frac{-18+98}{21}\\=\frac{80}{21}\)
11. \(-\left(\frac{13}{-14}\right)-\left(\frac{11}{8}\right)\\= \frac{13}{14}-\frac{11}{8}\\=\frac{52}{56}-\frac{77}{56}\\=\frac{52-77}{56}\\=\frac{-25}{56}\)
12. \(+\left(\frac{2}{-3}\right)+\left(\frac{8}{-3}\right)\\= \frac{-2}{3}-\frac{8}{3}\\=\frac{-2-8}{3}\\=\frac{-10}{3}\)