Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{5}{-11}\right)-\left(\frac{-10}{-11}\right)\)
2. \(+\left(\frac{-5}{-8}\right)+\left(\frac{-6}{-7}\right)\)
3. \(+\left(\frac{3}{-11}\right)+\left(\frac{-7}{8}\right)\)
4. \(-\left(\frac{-9}{-7}\right)+\left(\frac{-15}{-11}\right)\)
5. \(+\left(\frac{6}{7}\right)+\left(\frac{2}{-5}\right)\)
6. \(-\left(\frac{4}{-3}\right)-\left(\frac{10}{13}\right)\)
7. \(-\left(\frac{5}{11}\right)-\left(\frac{-12}{-5}\right)\)
8. \(-\left(\frac{4}{-3}\right)-\left(\frac{-15}{-7}\right)\)
9. \(-\left(\frac{-6}{-5}\right)+\left(\frac{5}{3}\right)\)
10. \(+\left(\frac{-5}{11}\right)+\left(\frac{12}{7}\right)\)
11. \(-\left(\frac{7}{3}\right)-\left(\frac{-4}{3}\right)\)
12. \(+\left(\frac{-10}{3}\right)+\left(\frac{-14}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{5}{-11}\right)-\left(\frac{-10}{-11}\right)\\= \frac{-5}{11}-\frac{10}{11}\\=\frac{-5-10}{11}\\=\frac{-15}{11}\)
2. \(+\left(\frac{-5}{-8}\right)+\left(\frac{-6}{-7}\right)\\= \frac{5}{8}+\frac{6}{7}\\=\frac{35}{56}+\frac{48}{56}\\=\frac{35+48}{56}\\=\frac{83}{56}\)
3. \(+\left(\frac{3}{-11}\right)+\left(\frac{-7}{8}\right)\\= \frac{-3}{11}-\frac{7}{8}\\=\frac{-24}{88}-\frac{77}{88}\\=\frac{-24-77}{88}\\=\frac{-101}{88}\)
4. \(-\left(\frac{-9}{-7}\right)+\left(\frac{-15}{-11}\right)\\= \frac{-9}{7}+\frac{15}{11}\\=\frac{-99}{77}+\frac{105}{77}\\=\frac{-99+105}{77}\\=\frac{6}{77}\)
5. \(+\left(\frac{6}{7}\right)+\left(\frac{2}{-5}\right)\\= \frac{6}{7}-\frac{2}{5}\\=\frac{30}{35}-\frac{14}{35}\\=\frac{30-14}{35}\\=\frac{16}{35}\)
6. \(-\left(\frac{4}{-3}\right)-\left(\frac{10}{13}\right)\\= \frac{4}{3}-\frac{10}{13}\\=\frac{52}{39}-\frac{30}{39}\\=\frac{52-30}{39}\\=\frac{22}{39}\)
7. \(-\left(\frac{5}{11}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-5}{11}-\frac{12}{5}\\=\frac{-25}{55}-\frac{132}{55}\\=\frac{-25-132}{55}\\=\frac{-157}{55}\)
8. \(-\left(\frac{4}{-3}\right)-\left(\frac{-15}{-7}\right)\\= \frac{4}{3}-\frac{15}{7}\\=\frac{28}{21}-\frac{45}{21}\\=\frac{28-45}{21}\\=\frac{-17}{21}\)
9. \(-\left(\frac{-6}{-5}\right)+\left(\frac{5}{3}\right)\\= \frac{-6}{5}+\frac{5}{3}\\=\frac{-18}{15}+\frac{25}{15}\\=\frac{-18+25}{15}\\=\frac{7}{15}\)
10. \(+\left(\frac{-5}{11}\right)+\left(\frac{12}{7}\right)\\= \frac{-5}{11}+\frac{12}{7}\\=\frac{-35}{77}+\frac{132}{77}\\=\frac{-35+132}{77}\\=\frac{97}{77}\)
11. \(-\left(\frac{7}{3}\right)-\left(\frac{-4}{3}\right)\\= \frac{-7}{3}+\frac{4}{3}\\=\frac{-7+4}{3}\\=\frac{-3}{3}\\=\frac{-1}{1}\)
12. \(+\left(\frac{-10}{3}\right)+\left(\frac{-14}{-5}\right)\\= \frac{-10}{3}+\frac{14}{5}\\=\frac{-50}{15}+\frac{42}{15}\\=\frac{-50+42}{15}\\=\frac{-8}{15}\)