Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{5}{2}\right)+\left(\frac{-5}{3}\right)\)
2. \(-\left(\frac{15}{-7}\right)+\left(\frac{5}{2}\right)\)
3. \(-\left(\frac{8}{-3}\right)-\left(\frac{-2}{9}\right)\)
4. \(-\left(\frac{3}{13}\right)-\left(\frac{2}{7}\right)\)
5. \(-\left(\frac{11}{-13}\right)-\left(\frac{15}{8}\right)\)
6. \(+\left(\frac{-8}{-13}\right)+\left(\frac{-12}{-11}\right)\)
7. \(+\left(\frac{9}{-2}\right)+\left(\frac{-12}{13}\right)\)
8. \(-\left(\frac{2}{-5}\right)+\left(\frac{10}{-3}\right)\)
9. \(-\left(\frac{4}{-3}\right)-\left(\frac{3}{-5}\right)\)
10. \(+\left(\frac{3}{-7}\right)+\left(\frac{-13}{-2}\right)\)
11. \(-\left(\frac{-10}{3}\right)+\left(\frac{-7}{-4}\right)\)
12. \(-\left(\frac{10}{-3}\right)+\left(\frac{-13}{-3}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{5}{2}\right)+\left(\frac{-5}{3}\right)\\= \frac{-5}{2}-\frac{5}{3}\\=\frac{-15}{6}-\frac{10}{6}\\=\frac{-15-10}{6}\\=\frac{-25}{6}\)
2. \(-\left(\frac{15}{-7}\right)+\left(\frac{5}{2}\right)\\= \frac{15}{7}+\frac{5}{2}\\=\frac{30}{14}+\frac{35}{14}\\=\frac{30+35}{14}\\=\frac{65}{14}\)
3. \(-\left(\frac{8}{-3}\right)-\left(\frac{-2}{9}\right)\\= \frac{8}{3}+\frac{2}{9}\\=\frac{24}{9}+\frac{2}{9}\\=\frac{24+2}{9}\\=\frac{26}{9}\)
4. \(-\left(\frac{3}{13}\right)-\left(\frac{2}{7}\right)\\= \frac{-3}{13}-\frac{2}{7}\\=\frac{-21}{91}-\frac{26}{91}\\=\frac{-21-26}{91}\\=\frac{-47}{91}\)
5. \(-\left(\frac{11}{-13}\right)-\left(\frac{15}{8}\right)\\= \frac{11}{13}-\frac{15}{8}\\=\frac{88}{104}-\frac{195}{104}\\=\frac{88-195}{104}\\=\frac{-107}{104}\)
6. \(+\left(\frac{-8}{-13}\right)+\left(\frac{-12}{-11}\right)\\= \frac{8}{13}+\frac{12}{11}\\=\frac{88}{143}+\frac{156}{143}\\=\frac{88+156}{143}\\=\frac{244}{143}\)
7. \(+\left(\frac{9}{-2}\right)+\left(\frac{-12}{13}\right)\\= \frac{-9}{2}-\frac{12}{13}\\=\frac{-117}{26}-\frac{24}{26}\\=\frac{-117-24}{26}\\=\frac{-141}{26}\)
8. \(-\left(\frac{2}{-5}\right)+\left(\frac{10}{-3}\right)\\= \frac{2}{5}-\frac{10}{3}\\=\frac{6}{15}-\frac{50}{15}\\=\frac{6-50}{15}\\=\frac{-44}{15}\)
9. \(-\left(\frac{4}{-3}\right)-\left(\frac{3}{-5}\right)\\= \frac{4}{3}+\frac{3}{5}\\=\frac{20}{15}+\frac{9}{15}\\=\frac{20+9}{15}\\=\frac{29}{15}\)
10. \(+\left(\frac{3}{-7}\right)+\left(\frac{-13}{-2}\right)\\= \frac{-3}{7}+\frac{13}{2}\\=\frac{-6}{14}+\frac{91}{14}\\=\frac{-6+91}{14}\\=\frac{85}{14}\)
11. \(-\left(\frac{-10}{3}\right)+\left(\frac{-7}{-4}\right)\\= \frac{10}{3}+\frac{7}{4}\\=\frac{40}{12}+\frac{21}{12}\\=\frac{40+21}{12}\\=\frac{61}{12}\)
12. \(-\left(\frac{10}{-3}\right)+\left(\frac{-13}{-3}\right)\\= \frac{10}{3}+\frac{13}{3}\\=\frac{10+13}{3}\\=\frac{23}{3}\)