Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-10}{7}\right)+\left(\frac{-10}{7}\right)\)
2. \(+\left(\frac{-10}{3}\right)+\left(\frac{2}{-3}\right)\)
3. \(+\left(\frac{3}{-11}\right)+\left(\frac{9}{-8}\right)\)
4. \(-\left(\frac{-15}{-7}\right)-\left(\frac{5}{3}\right)\)
5. \(+\left(\frac{-8}{-7}\right)+\left(\frac{-8}{7}\right)\)
6. \(-\left(\frac{-14}{9}\right)-\left(\frac{15}{-8}\right)\)
7. \(-\left(\frac{4}{-3}\right)+\left(\frac{11}{2}\right)\)
8. \(-\left(\frac{8}{-9}\right)+\left(\frac{13}{-11}\right)\)
9. \(-\left(\frac{6}{11}\right)+\left(\frac{6}{-5}\right)\)
10. \(-\left(\frac{6}{-11}\right)-\left(\frac{-10}{7}\right)\)
11. \(+\left(\frac{7}{9}\right)+\left(\frac{3}{14}\right)\)
12. \(+\left(\frac{-14}{-3}\right)-\left(\frac{-5}{11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-10}{7}\right)+\left(\frac{-10}{7}\right)\\= \frac{10}{7}-\frac{10}{7}\\=\frac{10-10}{7}\\=\frac{0}{7}\\=\frac{0}{1}\)
2. \(+\left(\frac{-10}{3}\right)+\left(\frac{2}{-3}\right)\\= \frac{-10}{3}-\frac{2}{3}\\=\frac{-10-2}{3}\\=\frac{-12}{3}\\=\frac{-4}{1}\)
3. \(+\left(\frac{3}{-11}\right)+\left(\frac{9}{-8}\right)\\= \frac{-3}{11}-\frac{9}{8}\\=\frac{-24}{88}-\frac{99}{88}\\=\frac{-24-99}{88}\\=\frac{-123}{88}\)
4. \(-\left(\frac{-15}{-7}\right)-\left(\frac{5}{3}\right)\\= \frac{-15}{7}-\frac{5}{3}\\=\frac{-45}{21}-\frac{35}{21}\\=\frac{-45-35}{21}\\=\frac{-80}{21}\)
5. \(+\left(\frac{-8}{-7}\right)+\left(\frac{-8}{7}\right)\\= \frac{8}{7}-\frac{8}{7}\\=\frac{8-8}{7}\\=\frac{0}{7}\\=\frac{0}{1}\)
6. \(-\left(\frac{-14}{9}\right)-\left(\frac{15}{-8}\right)\\= \frac{14}{9}+\frac{15}{8}\\=\frac{112}{72}+\frac{135}{72}\\=\frac{112+135}{72}\\=\frac{247}{72}\)
7. \(-\left(\frac{4}{-3}\right)+\left(\frac{11}{2}\right)\\= \frac{4}{3}+\frac{11}{2}\\=\frac{8}{6}+\frac{33}{6}\\=\frac{8+33}{6}\\=\frac{41}{6}\)
8. \(-\left(\frac{8}{-9}\right)+\left(\frac{13}{-11}\right)\\= \frac{8}{9}-\frac{13}{11}\\=\frac{88}{99}-\frac{117}{99}\\=\frac{88-117}{99}\\=\frac{-29}{99}\)
9. \(-\left(\frac{6}{11}\right)+\left(\frac{6}{-5}\right)\\= \frac{-6}{11}-\frac{6}{5}\\=\frac{-30}{55}-\frac{66}{55}\\=\frac{-30-66}{55}\\=\frac{-96}{55}\)
10. \(-\left(\frac{6}{-11}\right)-\left(\frac{-10}{7}\right)\\= \frac{6}{11}+\frac{10}{7}\\=\frac{42}{77}+\frac{110}{77}\\=\frac{42+110}{77}\\=\frac{152}{77}\)
11. \(+\left(\frac{7}{9}\right)+\left(\frac{3}{14}\right)\\= \frac{7}{9}+\frac{3}{14}\\=\frac{98}{126}+\frac{27}{126}\\=\frac{98+27}{126}\\=\frac{125}{126}\)
12. \(+\left(\frac{-14}{-3}\right)-\left(\frac{-5}{11}\right)\\= \frac{14}{3}+\frac{5}{11}\\=\frac{154}{33}+\frac{15}{33}\\=\frac{154+15}{33}\\=\frac{169}{33}\)