Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-10}{-3}\right)-\left(\frac{-8}{5}\right)\)
2. \(+\left(\frac{-12}{13}\right)-\left(\frac{10}{-7}\right)\)
3. \(+\left(\frac{-14}{-13}\right)-\left(\frac{-8}{-3}\right)\)
4. \(-\left(\frac{-2}{3}\right)-\left(\frac{12}{5}\right)\)
5. \(-\left(\frac{-2}{9}\right)+\left(\frac{5}{4}\right)\)
6. \(-\left(\frac{15}{-11}\right)-\left(\frac{15}{13}\right)\)
7. \(-\left(\frac{15}{13}\right)+\left(\frac{9}{-2}\right)\)
8. \(+\left(\frac{11}{-2}\right)-\left(\frac{-3}{-13}\right)\)
9. \(+\left(\frac{9}{-2}\right)+\left(\frac{6}{-11}\right)\)
10. \(+\left(\frac{-10}{3}\right)-\left(\frac{13}{-2}\right)\)
11. \(-\left(\frac{-13}{14}\right)+\left(\frac{-3}{8}\right)\)
12. \(-\left(\frac{-14}{5}\right)-\left(\frac{10}{-3}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-10}{-3}\right)-\left(\frac{-8}{5}\right)\\= \frac{10}{3}+\frac{8}{5}\\=\frac{50}{15}+\frac{24}{15}\\=\frac{50+24}{15}\\=\frac{74}{15}\)
2. \(+\left(\frac{-12}{13}\right)-\left(\frac{10}{-7}\right)\\= \frac{-12}{13}+\frac{10}{7}\\=\frac{-84}{91}+\frac{130}{91}\\=\frac{-84+130}{91}\\=\frac{46}{91}\)
3. \(+\left(\frac{-14}{-13}\right)-\left(\frac{-8}{-3}\right)\\= \frac{14}{13}-\frac{8}{3}\\=\frac{42}{39}-\frac{104}{39}\\=\frac{42-104}{39}\\=\frac{-62}{39}\)
4. \(-\left(\frac{-2}{3}\right)-\left(\frac{12}{5}\right)\\= \frac{2}{3}-\frac{12}{5}\\=\frac{10}{15}-\frac{36}{15}\\=\frac{10-36}{15}\\=\frac{-26}{15}\)
5. \(-\left(\frac{-2}{9}\right)+\left(\frac{5}{4}\right)\\= \frac{2}{9}+\frac{5}{4}\\=\frac{8}{36}+\frac{45}{36}\\=\frac{8+45}{36}\\=\frac{53}{36}\)
6. \(-\left(\frac{15}{-11}\right)-\left(\frac{15}{13}\right)\\= \frac{15}{11}-\frac{15}{13}\\=\frac{195}{143}-\frac{165}{143}\\=\frac{195-165}{143}\\=\frac{30}{143}\)
7. \(-\left(\frac{15}{13}\right)+\left(\frac{9}{-2}\right)\\= \frac{-15}{13}-\frac{9}{2}\\=\frac{-30}{26}-\frac{117}{26}\\=\frac{-30-117}{26}\\=\frac{-147}{26}\)
8. \(+\left(\frac{11}{-2}\right)-\left(\frac{-3}{-13}\right)\\= \frac{-11}{2}-\frac{3}{13}\\=\frac{-143}{26}-\frac{6}{26}\\=\frac{-143-6}{26}\\=\frac{-149}{26}\)
9. \(+\left(\frac{9}{-2}\right)+\left(\frac{6}{-11}\right)\\= \frac{-9}{2}-\frac{6}{11}\\=\frac{-99}{22}-\frac{12}{22}\\=\frac{-99-12}{22}\\=\frac{-111}{22}\)
10. \(+\left(\frac{-10}{3}\right)-\left(\frac{13}{-2}\right)\\= \frac{-10}{3}+\frac{13}{2}\\=\frac{-20}{6}+\frac{39}{6}\\=\frac{-20+39}{6}\\=\frac{19}{6}\)
11. \(-\left(\frac{-13}{14}\right)+\left(\frac{-3}{8}\right)\\= \frac{13}{14}-\frac{3}{8}\\=\frac{52}{56}-\frac{21}{56}\\=\frac{52-21}{56}\\=\frac{31}{56}\)
12. \(-\left(\frac{-14}{5}\right)-\left(\frac{10}{-3}\right)\\= \frac{14}{5}+\frac{10}{3}\\=\frac{42}{15}+\frac{50}{15}\\=\frac{42+50}{15}\\=\frac{92}{15}\)