Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{14}{9}\right)+\left(\frac{11}{-8}\right)\)
2. \(-\left(\frac{-2}{-11}\right)-\left(\frac{11}{9}\right)\)
3. \(-\left(\frac{15}{4}\right)+\left(\frac{6}{5}\right)\)
4. \(+\left(\frac{5}{11}\right)-\left(\frac{-11}{-3}\right)\)
5. \(+\left(\frac{-3}{-14}\right)-\left(\frac{-13}{-14}\right)\)
6. \(-\left(\frac{-6}{-5}\right)-\left(\frac{-11}{4}\right)\)
7. \(+\left(\frac{3}{13}\right)+\left(\frac{11}{7}\right)\)
8. \(+\left(\frac{-2}{11}\right)-\left(\frac{4}{3}\right)\)
9. \(-\left(\frac{-4}{-3}\right)+\left(\frac{-3}{2}\right)\)
10. \(+\left(\frac{12}{-5}\right)+\left(\frac{-2}{-11}\right)\)
11. \(-\left(\frac{-13}{-3}\right)-\left(\frac{15}{-11}\right)\)
12. \(-\left(\frac{-5}{3}\right)-\left(\frac{-13}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{14}{9}\right)+\left(\frac{11}{-8}\right)\\= \frac{14}{9}-\frac{11}{8}\\=\frac{112}{72}-\frac{99}{72}\\=\frac{112-99}{72}\\=\frac{13}{72}\)
2. \(-\left(\frac{-2}{-11}\right)-\left(\frac{11}{9}\right)\\= \frac{-2}{11}-\frac{11}{9}\\=\frac{-18}{99}-\frac{121}{99}\\=\frac{-18-121}{99}\\=\frac{-139}{99}\)
3. \(-\left(\frac{15}{4}\right)+\left(\frac{6}{5}\right)\\= \frac{-15}{4}+\frac{6}{5}\\=\frac{-75}{20}+\frac{24}{20}\\=\frac{-75+24}{20}\\=\frac{-51}{20}\)
4. \(+\left(\frac{5}{11}\right)-\left(\frac{-11}{-3}\right)\\= \frac{5}{11}-\frac{11}{3}\\=\frac{15}{33}-\frac{121}{33}\\=\frac{15-121}{33}\\=\frac{-106}{33}\)
5. \(+\left(\frac{-3}{-14}\right)-\left(\frac{-13}{-14}\right)\\= \frac{3}{14}-\frac{13}{14}\\=\frac{3-13}{14}\\=\frac{-10}{14}\\=\frac{-5}{7}\)
6. \(-\left(\frac{-6}{-5}\right)-\left(\frac{-11}{4}\right)\\= \frac{-6}{5}+\frac{11}{4}\\=\frac{-24}{20}+\frac{55}{20}\\=\frac{-24+55}{20}\\=\frac{31}{20}\)
7. \(+\left(\frac{3}{13}\right)+\left(\frac{11}{7}\right)\\= \frac{3}{13}+\frac{11}{7}\\=\frac{21}{91}+\frac{143}{91}\\=\frac{21+143}{91}\\=\frac{164}{91}\)
8. \(+\left(\frac{-2}{11}\right)-\left(\frac{4}{3}\right)\\= \frac{-2}{11}-\frac{4}{3}\\=\frac{-6}{33}-\frac{44}{33}\\=\frac{-6-44}{33}\\=\frac{-50}{33}\)
9. \(-\left(\frac{-4}{-3}\right)+\left(\frac{-3}{2}\right)\\= \frac{-4}{3}-\frac{3}{2}\\=\frac{-8}{6}-\frac{9}{6}\\=\frac{-8-9}{6}\\=\frac{-17}{6}\)
10. \(+\left(\frac{12}{-5}\right)+\left(\frac{-2}{-11}\right)\\= \frac{-12}{5}+\frac{2}{11}\\=\frac{-132}{55}+\frac{10}{55}\\=\frac{-132+10}{55}\\=\frac{-122}{55}\)
11. \(-\left(\frac{-13}{-3}\right)-\left(\frac{15}{-11}\right)\\= \frac{-13}{3}+\frac{15}{11}\\=\frac{-143}{33}+\frac{45}{33}\\=\frac{-143+45}{33}\\=\frac{-98}{33}\)
12. \(-\left(\frac{-5}{3}\right)-\left(\frac{-13}{-11}\right)\\= \frac{5}{3}-\frac{13}{11}\\=\frac{55}{33}-\frac{39}{33}\\=\frac{55-39}{33}\\=\frac{16}{33}\)