Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{9}{-7}\right)-\left(\frac{-5}{6}\right)\)
2. \(+\left(\frac{6}{-5}\right)-\left(\frac{-12}{5}\right)\)
3. \(+\left(\frac{2}{-3}\right)-\left(\frac{7}{-10}\right)\)
4. \(+\left(\frac{-14}{-3}\right)+\left(\frac{2}{-3}\right)\)
5. \(+\left(\frac{-15}{-11}\right)+\left(\frac{14}{-5}\right)\)
6. \(-\left(\frac{-8}{-5}\right)-\left(\frac{9}{-7}\right)\)
7. \(+\left(\frac{12}{5}\right)-\left(\frac{14}{3}\right)\)
8. \(+\left(\frac{6}{5}\right)+\left(\frac{-8}{-9}\right)\)
9. \(-\left(\frac{-14}{-5}\right)+\left(\frac{10}{3}\right)\)
10. \(+\left(\frac{-11}{12}\right)-\left(\frac{-8}{13}\right)\)
11. \(+\left(\frac{-8}{-13}\right)+\left(\frac{11}{12}\right)\)
12. \(+\left(\frac{13}{5}\right)-\left(\frac{5}{6}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{9}{-7}\right)-\left(\frac{-5}{6}\right)\\= \frac{9}{7}+\frac{5}{6}\\=\frac{54}{42}+\frac{35}{42}\\=\frac{54+35}{42}\\=\frac{89}{42}\)
2. \(+\left(\frac{6}{-5}\right)-\left(\frac{-12}{5}\right)\\= \frac{-6}{5}+\frac{12}{5}\\=\frac{-6+12}{5}\\=\frac{6}{5}\)
3. \(+\left(\frac{2}{-3}\right)-\left(\frac{7}{-10}\right)\\= \frac{-2}{3}+\frac{7}{10}\\=\frac{-20}{30}+\frac{21}{30}\\=\frac{-20+21}{30}\\=\frac{1}{30}\)
4. \(+\left(\frac{-14}{-3}\right)+\left(\frac{2}{-3}\right)\\= \frac{14}{3}-\frac{2}{3}\\=\frac{14-2}{3}\\=\frac{12}{3}\\=\frac{4}{1}\)
5. \(+\left(\frac{-15}{-11}\right)+\left(\frac{14}{-5}\right)\\= \frac{15}{11}-\frac{14}{5}\\=\frac{75}{55}-\frac{154}{55}\\=\frac{75-154}{55}\\=\frac{-79}{55}\)
6. \(-\left(\frac{-8}{-5}\right)-\left(\frac{9}{-7}\right)\\= \frac{-8}{5}+\frac{9}{7}\\=\frac{-56}{35}+\frac{45}{35}\\=\frac{-56+45}{35}\\=\frac{-11}{35}\)
7. \(+\left(\frac{12}{5}\right)-\left(\frac{14}{3}\right)\\= \frac{12}{5}-\frac{14}{3}\\=\frac{36}{15}-\frac{70}{15}\\=\frac{36-70}{15}\\=\frac{-34}{15}\)
8. \(+\left(\frac{6}{5}\right)+\left(\frac{-8}{-9}\right)\\= \frac{6}{5}+\frac{8}{9}\\=\frac{54}{45}+\frac{40}{45}\\=\frac{54+40}{45}\\=\frac{94}{45}\)
9. \(-\left(\frac{-14}{-5}\right)+\left(\frac{10}{3}\right)\\= \frac{-14}{5}+\frac{10}{3}\\=\frac{-42}{15}+\frac{50}{15}\\=\frac{-42+50}{15}\\=\frac{8}{15}\)
10. \(+\left(\frac{-11}{12}\right)-\left(\frac{-8}{13}\right)\\= \frac{-11}{12}+\frac{8}{13}\\=\frac{-143}{156}+\frac{96}{156}\\=\frac{-143+96}{156}\\=\frac{-47}{156}\)
11. \(+\left(\frac{-8}{-13}\right)+\left(\frac{11}{12}\right)\\= \frac{8}{13}+\frac{11}{12}\\=\frac{96}{156}+\frac{143}{156}\\=\frac{96+143}{156}\\=\frac{239}{156}\)
12. \(+\left(\frac{13}{5}\right)-\left(\frac{5}{6}\right)\\= \frac{13}{5}-\frac{5}{6}\\=\frac{78}{30}-\frac{25}{30}\\=\frac{78-25}{30}\\=\frac{53}{30}\)