Breuken haakjesregel (reeks 1)

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Bereken

1. \(+\left(\frac{-13}{3}\right)+\left(\frac{5}{-11}\right)\)
2. \(+\left(\frac{2}{11}\right)+\left(\frac{-15}{11}\right)\)
3. \(-\left(\frac{10}{-11}\right)+\left(\frac{-14}{3}\right)\)
4. \(-\left(\frac{14}{-3}\right)+\left(\frac{4}{-9}\right)\)
5. \(+\left(\frac{-11}{10}\right)-\left(\frac{7}{12}\right)\)
6. \(-\left(\frac{3}{2}\right)-\left(\frac{-3}{10}\right)\)
7. \(+\left(\frac{9}{2}\right)+\left(\frac{15}{2}\right)\)
8. \(+\left(\frac{-5}{-9}\right)+\left(\frac{6}{5}\right)\)
9. \(-\left(\frac{15}{11}\right)+\left(\frac{10}{-3}\right)\)
10. \(-\left(\frac{12}{-7}\right)-\left(\frac{11}{14}\right)\)
11. \(-\left(\frac{-10}{13}\right)-\left(\frac{4}{-7}\right)\)
12. \(-\left(\frac{15}{-13}\right)+\left(\frac{-2}{3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-13}{3}\right)+\left(\frac{5}{-11}\right)\\= \frac{-13}{3}-\frac{5}{11}\\=\frac{-143}{33}-\frac{15}{33}\\=\frac{-143-15}{33}\\=\frac{-158}{33}\)
2. \(+\left(\frac{2}{11}\right)+\left(\frac{-15}{11}\right)\\= \frac{2}{11}-\frac{15}{11}\\=\frac{2-15}{11}\\=\frac{-13}{11}\)
3. \(-\left(\frac{10}{-11}\right)+\left(\frac{-14}{3}\right)\\= \frac{10}{11}-\frac{14}{3}\\=\frac{30}{33}-\frac{154}{33}\\=\frac{30-154}{33}\\=\frac{-124}{33}\)
4. \(-\left(\frac{14}{-3}\right)+\left(\frac{4}{-9}\right)\\= \frac{14}{3}-\frac{4}{9}\\=\frac{42}{9}-\frac{4}{9}\\=\frac{42-4}{9}\\=\frac{38}{9}\)
5. \(+\left(\frac{-11}{10}\right)-\left(\frac{7}{12}\right)\\= \frac{-11}{10}-\frac{7}{12}\\=\frac{-66}{60}-\frac{35}{60}\\=\frac{-66-35}{60}\\=\frac{-101}{60}\)
6. \(-\left(\frac{3}{2}\right)-\left(\frac{-3}{10}\right)\\= \frac{-3}{2}+\frac{3}{10}\\=\frac{-15}{10}+\frac{3}{10}\\=\frac{-15+3}{10}\\=\frac{-12}{10}\\=\frac{-6}{5}\)
7. \(+\left(\frac{9}{2}\right)+\left(\frac{15}{2}\right)\\= \frac{9}{2}+\frac{15}{2}\\=\frac{9+15}{2}\\=\frac{24}{2}\\=\frac{12}{1}\)
8. \(+\left(\frac{-5}{-9}\right)+\left(\frac{6}{5}\right)\\= \frac{5}{9}+\frac{6}{5}\\=\frac{25}{45}+\frac{54}{45}\\=\frac{25+54}{45}\\=\frac{79}{45}\)
9. \(-\left(\frac{15}{11}\right)+\left(\frac{10}{-3}\right)\\= \frac{-15}{11}-\frac{10}{3}\\=\frac{-45}{33}-\frac{110}{33}\\=\frac{-45-110}{33}\\=\frac{-155}{33}\)
10. \(-\left(\frac{12}{-7}\right)-\left(\frac{11}{14}\right)\\= \frac{12}{7}-\frac{11}{14}\\=\frac{24}{14}-\frac{11}{14}\\=\frac{24-11}{14}\\=\frac{13}{14}\)
11. \(-\left(\frac{-10}{13}\right)-\left(\frac{4}{-7}\right)\\= \frac{10}{13}+\frac{4}{7}\\=\frac{70}{91}+\frac{52}{91}\\=\frac{70+52}{91}\\=\frac{122}{91}\)
12. \(-\left(\frac{15}{-13}\right)+\left(\frac{-2}{3}\right)\\= \frac{15}{13}-\frac{2}{3}\\=\frac{45}{39}-\frac{26}{39}\\=\frac{45-26}{39}\\=\frac{19}{39}\)