Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-2}{13}\right)-\left(\frac{-4}{-5}\right)\)
2. \(-\left(\frac{9}{-2}\right)+\left(\frac{-15}{-14}\right)\)
3. \(-\left(\frac{11}{-2}\right)-\left(\frac{9}{-13}\right)\)
4. \(-\left(\frac{-10}{-9}\right)+\left(\frac{-8}{-3}\right)\)
5. \(+\left(\frac{-7}{-8}\right)-\left(\frac{5}{-3}\right)\)
6. \(-\left(\frac{3}{5}\right)-\left(\frac{-8}{-13}\right)\)
7. \(-\left(\frac{6}{11}\right)+\left(\frac{-10}{-11}\right)\)
8. \(-\left(\frac{4}{-3}\right)+\left(\frac{-10}{3}\right)\)
9. \(-\left(\frac{8}{-3}\right)-\left(\frac{5}{13}\right)\)
10. \(-\left(\frac{-8}{-7}\right)-\left(\frac{-9}{-7}\right)\)
11. \(-\left(\frac{14}{-3}\right)+\left(\frac{14}{-11}\right)\)
12. \(-\left(\frac{-7}{-5}\right)+\left(\frac{9}{-8}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-2}{13}\right)-\left(\frac{-4}{-5}\right)\\= \frac{-2}{13}-\frac{4}{5}\\=\frac{-10}{65}-\frac{52}{65}\\=\frac{-10-52}{65}\\=\frac{-62}{65}\)
2. \(-\left(\frac{9}{-2}\right)+\left(\frac{-15}{-14}\right)\\= \frac{9}{2}+\frac{15}{14}\\=\frac{63}{14}+\frac{15}{14}\\=\frac{63+15}{14}\\=\frac{78}{14}\\=\frac{39}{7}\)
3. \(-\left(\frac{11}{-2}\right)-\left(\frac{9}{-13}\right)\\= \frac{11}{2}+\frac{9}{13}\\=\frac{143}{26}+\frac{18}{26}\\=\frac{143+18}{26}\\=\frac{161}{26}\)
4. \(-\left(\frac{-10}{-9}\right)+\left(\frac{-8}{-3}\right)\\= \frac{-10}{9}+\frac{8}{3}\\=\frac{-10+8}{9}\\=\frac{-2}{9}\)
5. \(+\left(\frac{-7}{-8}\right)-\left(\frac{5}{-3}\right)\\= \frac{7}{8}+\frac{5}{3}\\=\frac{21}{24}+\frac{40}{24}\\=\frac{21+40}{24}\\=\frac{61}{24}\)
6. \(-\left(\frac{3}{5}\right)-\left(\frac{-8}{-13}\right)\\= \frac{-3}{5}-\frac{8}{13}\\=\frac{-39}{65}-\frac{40}{65}\\=\frac{-39-40}{65}\\=\frac{-79}{65}\)
7. \(-\left(\frac{6}{11}\right)+\left(\frac{-10}{-11}\right)\\= \frac{-6}{11}+\frac{10}{11}\\=\frac{-6+10}{11}\\=\frac{4}{11}\)
8. \(-\left(\frac{4}{-3}\right)+\left(\frac{-10}{3}\right)\\= \frac{4}{3}-\frac{10}{3}\\=\frac{4-10}{3}\\=\frac{-6}{3}\\=\frac{-2}{1}\)
9. \(-\left(\frac{8}{-3}\right)-\left(\frac{5}{13}\right)\\= \frac{8}{3}-\frac{5}{13}\\=\frac{104}{39}-\frac{15}{39}\\=\frac{104-15}{39}\\=\frac{89}{39}\)
10. \(-\left(\frac{-8}{-7}\right)-\left(\frac{-9}{-7}\right)\\= \frac{-8}{7}-\frac{9}{7}\\=\frac{-8-9}{7}\\=\frac{-17}{7}\)
11. \(-\left(\frac{14}{-3}\right)+\left(\frac{14}{-11}\right)\\= \frac{14}{3}-\frac{14}{11}\\=\frac{154}{33}-\frac{42}{33}\\=\frac{154-42}{33}\\=\frac{112}{33}\)
12. \(-\left(\frac{-7}{-5}\right)+\left(\frac{9}{-8}\right)\\= \frac{-7}{5}-\frac{9}{8}\\=\frac{-56}{40}-\frac{45}{40}\\=\frac{-56-45}{40}\\=\frac{-101}{40}\)