Bereken
- \(+\left(\frac{-3}{-2}\right)-\left(\frac{-13}{3}\right)\)
- \(+\left(\frac{-10}{-3}\right)-\left(\frac{10}{-7}\right)\)
- \(+\left(\frac{13}{3}\right)-\left(\frac{14}{9}\right)\)
- \(-\left(\frac{11}{12}\right)+\left(\frac{-12}{7}\right)\)
- \(-\left(\frac{-3}{-2}\right)-\left(\frac{-12}{-5}\right)\)
- \(+\left(\frac{-8}{7}\right)+\left(\frac{-6}{5}\right)\)
- \(-\left(\frac{4}{-9}\right)+\left(\frac{5}{-6}\right)\)
- \(+\left(\frac{-13}{2}\right)+\left(\frac{3}{8}\right)\)
- \(+\left(\frac{14}{5}\right)-\left(\frac{2}{-3}\right)\)
- \(+\left(\frac{-15}{13}\right)-\left(\frac{-14}{3}\right)\)
- \(+\left(\frac{4}{3}\right)-\left(\frac{-14}{5}\right)\)
- \(+\left(\frac{-3}{10}\right)+\left(\frac{-3}{-2}\right)\)
Bereken
Verbetersleutel
- \(+\left(\frac{-3}{-2}\right)-\left(\frac{-13}{3}\right)\\= \frac{3}{2}+\frac{13}{3}\\=\frac{9}{6}+\frac{26}{6}\\=\frac{9+26}{6}\\=\frac{35}{6}\)
- \(+\left(\frac{-10}{-3}\right)-\left(\frac{10}{-7}\right)\\= \frac{10}{3}+\frac{10}{7}\\=\frac{70}{21}+\frac{30}{21}\\=\frac{70+30}{21}\\=\frac{100}{21}\)
- \(+\left(\frac{13}{3}\right)-\left(\frac{14}{9}\right)\\= \frac{13}{3}-\frac{14}{9}\\=\frac{39}{9}-\frac{14}{9}\\=\frac{39-14}{9}\\=\frac{25}{9}\)
- \(-\left(\frac{11}{12}\right)+\left(\frac{-12}{7}\right)\\= \frac{-11}{12}-\frac{12}{7}\\=\frac{-77}{84}-\frac{144}{84}\\=\frac{-77-144}{84}\\=\frac{-221}{84}\)
- \(-\left(\frac{-3}{-2}\right)-\left(\frac{-12}{-5}\right)\\= \frac{-3}{2}-\frac{12}{5}\\=\frac{-15}{10}-\frac{24}{10}\\=\frac{-15-24}{10}\\=\frac{-39}{10}\)
- \(+\left(\frac{-8}{7}\right)+\left(\frac{-6}{5}\right)\\= \frac{-8}{7}-\frac{6}{5}\\=\frac{-40}{35}-\frac{42}{35}\\=\frac{-40-42}{35}\\=\frac{-82}{35}\)
- \(-\left(\frac{4}{-9}\right)+\left(\frac{5}{-6}\right)\\= \frac{4}{9}-\frac{5}{6}\\=\frac{8}{18}-\frac{15}{18}\\=\frac{8-15}{18}\\=\frac{-7}{18}\)
- \(+\left(\frac{-13}{2}\right)+\left(\frac{3}{8}\right)\\= \frac{-13}{2}+\frac{3}{8}\\=\frac{-52}{8}+\frac{3}{8}\\=\frac{-52+3}{8}\\=\frac{-49}{8}\)
- \(+\left(\frac{14}{5}\right)-\left(\frac{2}{-3}\right)\\= \frac{14}{5}+\frac{2}{3}\\=\frac{42}{15}+\frac{10}{15}\\=\frac{42+10}{15}\\=\frac{52}{15}\)
- \(+\left(\frac{-15}{13}\right)-\left(\frac{-14}{3}\right)\\= \frac{-15}{13}+\frac{14}{3}\\=\frac{-45}{39}+\frac{182}{39}\\=\frac{-45+182}{39}\\=\frac{137}{39}\)
- \(+\left(\frac{4}{3}\right)-\left(\frac{-14}{5}\right)\\= \frac{4}{3}+\frac{14}{5}\\=\frac{20}{15}+\frac{42}{15}\\=\frac{20+42}{15}\\=\frac{62}{15}\)
- \(+\left(\frac{-3}{10}\right)+\left(\frac{-3}{-2}\right)\\= \frac{-3}{10}+\frac{3}{2}\\=\frac{-3+3}{10}\\=\frac{0}{10}\\=\frac{0}{1}\)