Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-14}{-3}\right)+\left(\frac{-3}{2}\right)\)
2. \(+\left(\frac{-14}{-3}\right)-\left(\frac{3}{7}\right)\)
3. \(+\left(\frac{-8}{-3}\right)+\left(\frac{15}{4}\right)\)
4. \(+\left(\frac{-13}{8}\right)+\left(\frac{15}{-7}\right)\)
5. \(+\left(\frac{2}{7}\right)-\left(\frac{-9}{-13}\right)\)
6. \(+\left(\frac{7}{9}\right)-\left(\frac{9}{-5}\right)\)
7. \(-\left(\frac{-2}{-9}\right)-\left(\frac{10}{-3}\right)\)
8. \(+\left(\frac{15}{-14}\right)+\left(\frac{2}{-9}\right)\)
9. \(+\left(\frac{6}{5}\right)+\left(\frac{13}{8}\right)\)
10. \(+\left(\frac{10}{-13}\right)+\left(\frac{11}{-12}\right)\)
11. \(+\left(\frac{-9}{-8}\right)+\left(\frac{3}{11}\right)\)
12. \(-\left(\frac{-9}{-14}\right)-\left(\frac{-8}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-14}{-3}\right)+\left(\frac{-3}{2}\right)\\= \frac{14}{3}-\frac{3}{2}\\=\frac{28}{6}-\frac{9}{6}\\=\frac{28-9}{6}\\=\frac{19}{6}\)
2. \(+\left(\frac{-14}{-3}\right)-\left(\frac{3}{7}\right)\\= \frac{14}{3}-\frac{3}{7}\\=\frac{98}{21}-\frac{9}{21}\\=\frac{98-9}{21}\\=\frac{89}{21}\)
3. \(+\left(\frac{-8}{-3}\right)+\left(\frac{15}{4}\right)\\= \frac{8}{3}+\frac{15}{4}\\=\frac{32}{12}+\frac{45}{12}\\=\frac{32+45}{12}\\=\frac{77}{12}\)
4. \(+\left(\frac{-13}{8}\right)+\left(\frac{15}{-7}\right)\\= \frac{-13}{8}-\frac{15}{7}\\=\frac{-91}{56}-\frac{120}{56}\\=\frac{-91-120}{56}\\=\frac{-211}{56}\)
5. \(+\left(\frac{2}{7}\right)-\left(\frac{-9}{-13}\right)\\= \frac{2}{7}-\frac{9}{13}\\=\frac{26}{91}-\frac{63}{91}\\=\frac{26-63}{91}\\=\frac{-37}{91}\)
6. \(+\left(\frac{7}{9}\right)-\left(\frac{9}{-5}\right)\\= \frac{7}{9}+\frac{9}{5}\\=\frac{35}{45}+\frac{81}{45}\\=\frac{35+81}{45}\\=\frac{116}{45}\)
7. \(-\left(\frac{-2}{-9}\right)-\left(\frac{10}{-3}\right)\\= \frac{-2}{9}+\frac{10}{3}\\=\frac{-2+10}{9}\\=\frac{8}{9}\)
8. \(+\left(\frac{15}{-14}\right)+\left(\frac{2}{-9}\right)\\= \frac{-15}{14}-\frac{2}{9}\\=\frac{-135}{126}-\frac{28}{126}\\=\frac{-135-28}{126}\\=\frac{-163}{126}\)
9. \(+\left(\frac{6}{5}\right)+\left(\frac{13}{8}\right)\\= \frac{6}{5}+\frac{13}{8}\\=\frac{48}{40}+\frac{65}{40}\\=\frac{48+65}{40}\\=\frac{113}{40}\)
10. \(+\left(\frac{10}{-13}\right)+\left(\frac{11}{-12}\right)\\= \frac{-10}{13}-\frac{11}{12}\\=\frac{-120}{156}-\frac{143}{156}\\=\frac{-120-143}{156}\\=\frac{-263}{156}\)
11. \(+\left(\frac{-9}{-8}\right)+\left(\frac{3}{11}\right)\\= \frac{9}{8}+\frac{3}{11}\\=\frac{99}{88}+\frac{24}{88}\\=\frac{99+24}{88}\\=\frac{123}{88}\)
12. \(-\left(\frac{-9}{-14}\right)-\left(\frac{-8}{-3}\right)\\= \frac{-9}{14}-\frac{8}{3}\\=\frac{-27}{42}-\frac{112}{42}\\=\frac{-27-112}{42}\\=\frac{-139}{42}\)