Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{2}{11}\right)-\left(\frac{11}{-7}\right)\)
2. \(-\left(\frac{-7}{-4}\right)+\left(\frac{-12}{11}\right)\)
3. \(+\left(\frac{15}{13}\right)-\left(\frac{-15}{2}\right)\)
4. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-14}{11}\right)\)
5. \(+\left(\frac{3}{11}\right)+\left(\frac{-12}{7}\right)\)
6. \(+\left(\frac{8}{-7}\right)+\left(\frac{6}{5}\right)\)
7. \(-\left(\frac{15}{14}\right)+\left(\frac{10}{-11}\right)\)
8. \(-\left(\frac{-2}{7}\right)+\left(\frac{-15}{-4}\right)\)
9. \(-\left(\frac{9}{11}\right)+\left(\frac{7}{5}\right)\)
10. \(+\left(\frac{9}{-4}\right)+\left(\frac{-8}{-3}\right)\)
11. \(+\left(\frac{7}{12}\right)+\left(\frac{-14}{3}\right)\)
12. \(+\left(\frac{-9}{-10}\right)-\left(\frac{-12}{5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{2}{11}\right)-\left(\frac{11}{-7}\right)\\= \frac{2}{11}+\frac{11}{7}\\=\frac{14}{77}+\frac{121}{77}\\=\frac{14+121}{77}\\=\frac{135}{77}\)
2. \(-\left(\frac{-7}{-4}\right)+\left(\frac{-12}{11}\right)\\= \frac{-7}{4}-\frac{12}{11}\\=\frac{-77}{44}-\frac{48}{44}\\=\frac{-77-48}{44}\\=\frac{-125}{44}\)
3. \(+\left(\frac{15}{13}\right)-\left(\frac{-15}{2}\right)\\= \frac{15}{13}+\frac{15}{2}\\=\frac{30}{26}+\frac{195}{26}\\=\frac{30+195}{26}\\=\frac{225}{26}\)
4. \(+\left(\frac{-12}{-5}\right)+\left(\frac{-14}{11}\right)\\= \frac{12}{5}-\frac{14}{11}\\=\frac{132}{55}-\frac{70}{55}\\=\frac{132-70}{55}\\=\frac{62}{55}\)
5. \(+\left(\frac{3}{11}\right)+\left(\frac{-12}{7}\right)\\= \frac{3}{11}-\frac{12}{7}\\=\frac{21}{77}-\frac{132}{77}\\=\frac{21-132}{77}\\=\frac{-111}{77}\)
6. \(+\left(\frac{8}{-7}\right)+\left(\frac{6}{5}\right)\\= \frac{-8}{7}+\frac{6}{5}\\=\frac{-40}{35}+\frac{42}{35}\\=\frac{-40+42}{35}\\=\frac{2}{35}\)
7. \(-\left(\frac{15}{14}\right)+\left(\frac{10}{-11}\right)\\= \frac{-15}{14}-\frac{10}{11}\\=\frac{-165}{154}-\frac{140}{154}\\=\frac{-165-140}{154}\\=\frac{-305}{154}\)
8. \(-\left(\frac{-2}{7}\right)+\left(\frac{-15}{-4}\right)\\= \frac{2}{7}+\frac{15}{4}\\=\frac{8}{28}+\frac{105}{28}\\=\frac{8+105}{28}\\=\frac{113}{28}\)
9. \(-\left(\frac{9}{11}\right)+\left(\frac{7}{5}\right)\\= \frac{-9}{11}+\frac{7}{5}\\=\frac{-45}{55}+\frac{77}{55}\\=\frac{-45+77}{55}\\=\frac{32}{55}\)
10. \(+\left(\frac{9}{-4}\right)+\left(\frac{-8}{-3}\right)\\= \frac{-9}{4}+\frac{8}{3}\\=\frac{-27}{12}+\frac{32}{12}\\=\frac{-27+32}{12}\\=\frac{5}{12}\)
11. \(+\left(\frac{7}{12}\right)+\left(\frac{-14}{3}\right)\\= \frac{7}{12}-\frac{14}{3}\\=\frac{7-14}{12}\\=\frac{-7}{12}\)
12. \(+\left(\frac{-9}{-10}\right)-\left(\frac{-12}{5}\right)\\= \frac{9}{10}+\frac{12}{5}\\=\frac{9+12}{10}\\=\frac{21}{10}\)