Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-2}{-3}\right)-\left(\frac{5}{3}\right)\)
2. \(+\left(\frac{6}{-11}\right)-\left(\frac{5}{-13}\right)\)
3. \(+\left(\frac{-14}{-3}\right)-\left(\frac{-11}{2}\right)\)
4. \(-\left(\frac{2}{9}\right)-\left(\frac{4}{7}\right)\)
5. \(+\left(\frac{-3}{4}\right)+\left(\frac{-12}{-11}\right)\)
6. \(+\left(\frac{15}{-13}\right)+\left(\frac{13}{12}\right)\)
7. \(-\left(\frac{12}{13}\right)-\left(\frac{10}{3}\right)\)
8. \(-\left(\frac{9}{-13}\right)-\left(\frac{3}{-8}\right)\)
9. \(-\left(\frac{2}{-9}\right)+\left(\frac{7}{-10}\right)\)
10. \(+\left(\frac{8}{13}\right)+\left(\frac{-5}{-3}\right)\)
11. \(-\left(\frac{2}{3}\right)-\left(\frac{4}{-5}\right)\)
12. \(+\left(\frac{6}{5}\right)-\left(\frac{-6}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-2}{-3}\right)-\left(\frac{5}{3}\right)\\= \frac{2}{3}-\frac{5}{3}\\=\frac{2-5}{3}\\=\frac{-3}{3}\\=\frac{-1}{1}\)
2. \(+\left(\frac{6}{-11}\right)-\left(\frac{5}{-13}\right)\\= \frac{-6}{11}+\frac{5}{13}\\=\frac{-78}{143}+\frac{55}{143}\\=\frac{-78+55}{143}\\=\frac{-23}{143}\)
3. \(+\left(\frac{-14}{-3}\right)-\left(\frac{-11}{2}\right)\\= \frac{14}{3}+\frac{11}{2}\\=\frac{28}{6}+\frac{33}{6}\\=\frac{28+33}{6}\\=\frac{61}{6}\)
4. \(-\left(\frac{2}{9}\right)-\left(\frac{4}{7}\right)\\= \frac{-2}{9}-\frac{4}{7}\\=\frac{-14}{63}-\frac{36}{63}\\=\frac{-14-36}{63}\\=\frac{-50}{63}\)
5. \(+\left(\frac{-3}{4}\right)+\left(\frac{-12}{-11}\right)\\= \frac{-3}{4}+\frac{12}{11}\\=\frac{-33}{44}+\frac{48}{44}\\=\frac{-33+48}{44}\\=\frac{15}{44}\)
6. \(+\left(\frac{15}{-13}\right)+\left(\frac{13}{12}\right)\\= \frac{-15}{13}+\frac{13}{12}\\=\frac{-180}{156}+\frac{169}{156}\\=\frac{-180+169}{156}\\=\frac{-11}{156}\)
7. \(-\left(\frac{12}{13}\right)-\left(\frac{10}{3}\right)\\= \frac{-12}{13}-\frac{10}{3}\\=\frac{-36}{39}-\frac{130}{39}\\=\frac{-36-130}{39}\\=\frac{-166}{39}\)
8. \(-\left(\frac{9}{-13}\right)-\left(\frac{3}{-8}\right)\\= \frac{9}{13}+\frac{3}{8}\\=\frac{72}{104}+\frac{39}{104}\\=\frac{72+39}{104}\\=\frac{111}{104}\)
9. \(-\left(\frac{2}{-9}\right)+\left(\frac{7}{-10}\right)\\= \frac{2}{9}-\frac{7}{10}\\=\frac{20}{90}-\frac{63}{90}\\=\frac{20-63}{90}\\=\frac{-43}{90}\)
10. \(+\left(\frac{8}{13}\right)+\left(\frac{-5}{-3}\right)\\= \frac{8}{13}+\frac{5}{3}\\=\frac{24}{39}+\frac{65}{39}\\=\frac{24+65}{39}\\=\frac{89}{39}\)
11. \(-\left(\frac{2}{3}\right)-\left(\frac{4}{-5}\right)\\= \frac{-2}{3}+\frac{4}{5}\\=\frac{-10}{15}+\frac{12}{15}\\=\frac{-10+12}{15}\\=\frac{2}{15}\)
12. \(+\left(\frac{6}{5}\right)-\left(\frac{-6}{-13}\right)\\= \frac{6}{5}-\frac{6}{13}\\=\frac{78}{65}-\frac{30}{65}\\=\frac{78-30}{65}\\=\frac{48}{65}\)