Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-3}{-4}\right)-\left(\frac{-10}{-3}\right)\)
2. \(+\left(\frac{-7}{-4}\right)-\left(\frac{-12}{5}\right)\)
3. \(+\left(\frac{14}{3}\right)+\left(\frac{-3}{14}\right)\)
4. \(-\left(\frac{15}{-7}\right)+\left(\frac{15}{13}\right)\)
5. \(-\left(\frac{-15}{-7}\right)-\left(\frac{14}{-13}\right)\)
6. \(+\left(\frac{15}{-13}\right)-\left(\frac{-14}{-11}\right)\)
7. \(+\left(\frac{4}{7}\right)-\left(\frac{-5}{11}\right)\)
8. \(-\left(\frac{4}{-13}\right)+\left(\frac{-2}{-3}\right)\)
9. \(-\left(\frac{-14}{-11}\right)-\left(\frac{-15}{-13}\right)\)
10. \(-\left(\frac{-13}{-2}\right)-\left(\frac{5}{4}\right)\)
11. \(-\left(\frac{10}{3}\right)-\left(\frac{-14}{3}\right)\)
12. \(+\left(\frac{6}{-7}\right)+\left(\frac{-11}{-4}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-3}{-4}\right)-\left(\frac{-10}{-3}\right)\\= \frac{-3}{4}-\frac{10}{3}\\=\frac{-9}{12}-\frac{40}{12}\\=\frac{-9-40}{12}\\=\frac{-49}{12}\)
2. \(+\left(\frac{-7}{-4}\right)-\left(\frac{-12}{5}\right)\\= \frac{7}{4}+\frac{12}{5}\\=\frac{35}{20}+\frac{48}{20}\\=\frac{35+48}{20}\\=\frac{83}{20}\)
3. \(+\left(\frac{14}{3}\right)+\left(\frac{-3}{14}\right)\\= \frac{14}{3}-\frac{3}{14}\\=\frac{196}{42}-\frac{9}{42}\\=\frac{196-9}{42}\\=\frac{187}{42}\)
4. \(-\left(\frac{15}{-7}\right)+\left(\frac{15}{13}\right)\\= \frac{15}{7}+\frac{15}{13}\\=\frac{195}{91}+\frac{105}{91}\\=\frac{195+105}{91}\\=\frac{300}{91}\)
5. \(-\left(\frac{-15}{-7}\right)-\left(\frac{14}{-13}\right)\\= \frac{-15}{7}+\frac{14}{13}\\=\frac{-195}{91}+\frac{98}{91}\\=\frac{-195+98}{91}\\=\frac{-97}{91}\)
6. \(+\left(\frac{15}{-13}\right)-\left(\frac{-14}{-11}\right)\\= \frac{-15}{13}-\frac{14}{11}\\=\frac{-165}{143}-\frac{182}{143}\\=\frac{-165-182}{143}\\=\frac{-347}{143}\)
7. \(+\left(\frac{4}{7}\right)-\left(\frac{-5}{11}\right)\\= \frac{4}{7}+\frac{5}{11}\\=\frac{44}{77}+\frac{35}{77}\\=\frac{44+35}{77}\\=\frac{79}{77}\)
8. \(-\left(\frac{4}{-13}\right)+\left(\frac{-2}{-3}\right)\\= \frac{4}{13}+\frac{2}{3}\\=\frac{12}{39}+\frac{26}{39}\\=\frac{12+26}{39}\\=\frac{38}{39}\)
9. \(-\left(\frac{-14}{-11}\right)-\left(\frac{-15}{-13}\right)\\= \frac{-14}{11}-\frac{15}{13}\\=\frac{-182}{143}-\frac{165}{143}\\=\frac{-182-165}{143}\\=\frac{-347}{143}\)
10. \(-\left(\frac{-13}{-2}\right)-\left(\frac{5}{4}\right)\\= \frac{-13}{2}-\frac{5}{4}\\=\frac{-26}{4}-\frac{5}{4}\\=\frac{-26-5}{4}\\=\frac{-31}{4}\)
11. \(-\left(\frac{10}{3}\right)-\left(\frac{-14}{3}\right)\\= \frac{-10}{3}+\frac{14}{3}\\=\frac{-10+14}{3}\\=\frac{4}{3}\)
12. \(+\left(\frac{6}{-7}\right)+\left(\frac{-11}{-4}\right)\\= \frac{-6}{7}+\frac{11}{4}\\=\frac{-24}{28}+\frac{77}{28}\\=\frac{-24+77}{28}\\=\frac{53}{28}\)