Bereken
- \(-\left(\frac{9}{-10}\right)-\left(\frac{-15}{-11}\right)\)
- \(+\left(\frac{10}{-3}\right)+\left(\frac{-2}{-3}\right)\)
- \(-\left(\frac{-10}{-13}\right)-\left(\frac{7}{2}\right)\)
- \(-\left(\frac{-6}{7}\right)+\left(\frac{-7}{2}\right)\)
- \(+\left(\frac{-12}{-11}\right)-\left(\frac{7}{3}\right)\)
- \(+\left(\frac{6}{5}\right)+\left(\frac{7}{9}\right)\)
- \(+\left(\frac{-6}{13}\right)+\left(\frac{-9}{-2}\right)\)
- \(+\left(\frac{2}{5}\right)+\left(\frac{13}{14}\right)\)
- \(+\left(\frac{6}{-5}\right)-\left(\frac{-8}{7}\right)\)
- \(-\left(\frac{-2}{13}\right)-\left(\frac{-4}{-7}\right)\)
- \(-\left(\frac{-14}{3}\right)+\left(\frac{-2}{-7}\right)\)
- \(-\left(\frac{-15}{2}\right)+\left(\frac{9}{5}\right)\)
Bereken
Verbetersleutel
- \(-\left(\frac{9}{-10}\right)-\left(\frac{-15}{-11}\right)\\= \frac{9}{10}-\frac{15}{11}\\=\frac{99}{110}-\frac{150}{110}\\=\frac{99-150}{110}\\=\frac{-51}{110}\)
- \(+\left(\frac{10}{-3}\right)+\left(\frac{-2}{-3}\right)\\= \frac{-10}{3}+\frac{2}{3}\\=\frac{-10+2}{3}\\=\frac{-8}{3}\)
- \(-\left(\frac{-10}{-13}\right)-\left(\frac{7}{2}\right)\\= \frac{-10}{13}-\frac{7}{2}\\=\frac{-20}{26}-\frac{91}{26}\\=\frac{-20-91}{26}\\=\frac{-111}{26}\)
- \(-\left(\frac{-6}{7}\right)+\left(\frac{-7}{2}\right)\\= \frac{6}{7}-\frac{7}{2}\\=\frac{12}{14}-\frac{49}{14}\\=\frac{12-49}{14}\\=\frac{-37}{14}\)
- \(+\left(\frac{-12}{-11}\right)-\left(\frac{7}{3}\right)\\= \frac{12}{11}-\frac{7}{3}\\=\frac{36}{33}-\frac{77}{33}\\=\frac{36-77}{33}\\=\frac{-41}{33}\)
- \(+\left(\frac{6}{5}\right)+\left(\frac{7}{9}\right)\\= \frac{6}{5}+\frac{7}{9}\\=\frac{54}{45}+\frac{35}{45}\\=\frac{54+35}{45}\\=\frac{89}{45}\)
- \(+\left(\frac{-6}{13}\right)+\left(\frac{-9}{-2}\right)\\= \frac{-6}{13}+\frac{9}{2}\\=\frac{-12}{26}+\frac{117}{26}\\=\frac{-12+117}{26}\\=\frac{105}{26}\)
- \(+\left(\frac{2}{5}\right)+\left(\frac{13}{14}\right)\\= \frac{2}{5}+\frac{13}{14}\\=\frac{28}{70}+\frac{65}{70}\\=\frac{28+65}{70}\\=\frac{93}{70}\)
- \(+\left(\frac{6}{-5}\right)-\left(\frac{-8}{7}\right)\\= \frac{-6}{5}+\frac{8}{7}\\=\frac{-42}{35}+\frac{40}{35}\\=\frac{-42+40}{35}\\=\frac{-2}{35}\)
- \(-\left(\frac{-2}{13}\right)-\left(\frac{-4}{-7}\right)\\= \frac{2}{13}-\frac{4}{7}\\=\frac{14}{91}-\frac{52}{91}\\=\frac{14-52}{91}\\=\frac{-38}{91}\)
- \(-\left(\frac{-14}{3}\right)+\left(\frac{-2}{-7}\right)\\= \frac{14}{3}+\frac{2}{7}\\=\frac{98}{21}+\frac{6}{21}\\=\frac{98+6}{21}\\=\frac{104}{21}\)
- \(-\left(\frac{-15}{2}\right)+\left(\frac{9}{5}\right)\\= \frac{15}{2}+\frac{9}{5}\\=\frac{75}{10}+\frac{18}{10}\\=\frac{75+18}{10}\\=\frac{93}{10}\)