Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-11}{12}\right)-\left(\frac{15}{-11}\right)\)
2. \(-\left(\frac{14}{-13}\right)-\left(\frac{-10}{-3}\right)\)
3. \(-\left(\frac{-12}{-11}\right)-\left(\frac{-8}{-13}\right)\)
4. \(+\left(\frac{9}{7}\right)+\left(\frac{5}{2}\right)\)
5. \(+\left(\frac{-15}{-8}\right)-\left(\frac{13}{11}\right)\)
6. \(-\left(\frac{-8}{5}\right)+\left(\frac{-13}{8}\right)\)
7. \(-\left(\frac{-2}{13}\right)+\left(\frac{-15}{-2}\right)\)
8. \(-\left(\frac{-11}{12}\right)-\left(\frac{14}{-9}\right)\)
9. \(+\left(\frac{-3}{4}\right)+\left(\frac{-5}{-6}\right)\)
10. \(-\left(\frac{5}{2}\right)+\left(\frac{12}{7}\right)\)
11. \(-\left(\frac{-9}{4}\right)+\left(\frac{3}{8}\right)\)
12. \(+\left(\frac{8}{3}\right)+\left(\frac{-6}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-11}{12}\right)-\left(\frac{15}{-11}\right)\\= \frac{11}{12}+\frac{15}{11}\\=\frac{121}{132}+\frac{180}{132}\\=\frac{121+180}{132}\\=\frac{301}{132}\)
2. \(-\left(\frac{14}{-13}\right)-\left(\frac{-10}{-3}\right)\\= \frac{14}{13}-\frac{10}{3}\\=\frac{42}{39}-\frac{130}{39}\\=\frac{42-130}{39}\\=\frac{-88}{39}\)
3. \(-\left(\frac{-12}{-11}\right)-\left(\frac{-8}{-13}\right)\\= \frac{-12}{11}-\frac{8}{13}\\=\frac{-156}{143}-\frac{88}{143}\\=\frac{-156-88}{143}\\=\frac{-244}{143}\)
4. \(+\left(\frac{9}{7}\right)+\left(\frac{5}{2}\right)\\= \frac{9}{7}+\frac{5}{2}\\=\frac{18}{14}+\frac{35}{14}\\=\frac{18+35}{14}\\=\frac{53}{14}\)
5. \(+\left(\frac{-15}{-8}\right)-\left(\frac{13}{11}\right)\\= \frac{15}{8}-\frac{13}{11}\\=\frac{165}{88}-\frac{104}{88}\\=\frac{165-104}{88}\\=\frac{61}{88}\)
6. \(-\left(\frac{-8}{5}\right)+\left(\frac{-13}{8}\right)\\= \frac{8}{5}-\frac{13}{8}\\=\frac{64}{40}-\frac{65}{40}\\=\frac{64-65}{40}\\=\frac{-1}{40}\)
7. \(-\left(\frac{-2}{13}\right)+\left(\frac{-15}{-2}\right)\\= \frac{2}{13}+\frac{15}{2}\\=\frac{4}{26}+\frac{195}{26}\\=\frac{4+195}{26}\\=\frac{199}{26}\)
8. \(-\left(\frac{-11}{12}\right)-\left(\frac{14}{-9}\right)\\= \frac{11}{12}+\frac{14}{9}\\=\frac{33}{36}+\frac{56}{36}\\=\frac{33+56}{36}\\=\frac{89}{36}\)
9. \(+\left(\frac{-3}{4}\right)+\left(\frac{-5}{-6}\right)\\= \frac{-3}{4}+\frac{5}{6}\\=\frac{-9}{12}+\frac{10}{12}\\=\frac{-9+10}{12}\\=\frac{1}{12}\)
10. \(-\left(\frac{5}{2}\right)+\left(\frac{12}{7}\right)\\= \frac{-5}{2}+\frac{12}{7}\\=\frac{-35}{14}+\frac{24}{14}\\=\frac{-35+24}{14}\\=\frac{-11}{14}\)
11. \(-\left(\frac{-9}{4}\right)+\left(\frac{3}{8}\right)\\= \frac{9}{4}+\frac{3}{8}\\=\frac{18}{8}+\frac{3}{8}\\=\frac{18+3}{8}\\=\frac{21}{8}\)
12. \(+\left(\frac{8}{3}\right)+\left(\frac{-6}{-5}\right)\\= \frac{8}{3}+\frac{6}{5}\\=\frac{40}{15}+\frac{18}{15}\\=\frac{40+18}{15}\\=\frac{58}{15}\)