Breuken haakjesregel (reeks 1)

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Bereken

1. \(-\left(\frac{12}{-7}\right)+\left(\frac{8}{9}\right)\)
2. \(-\left(\frac{11}{5}\right)+\left(\frac{-3}{13}\right)\)
3. \(-\left(\frac{-6}{-5}\right)+\left(\frac{7}{-4}\right)\)
4. \(-\left(\frac{-10}{3}\right)-\left(\frac{14}{-9}\right)\)
5. \(+\left(\frac{5}{6}\right)-\left(\frac{-10}{7}\right)\)
6. \(+\left(\frac{11}{13}\right)+\left(\frac{14}{-3}\right)\)
7. \(+\left(\frac{-8}{-13}\right)-\left(\frac{14}{13}\right)\)
8. \(-\left(\frac{3}{-11}\right)+\left(\frac{14}{11}\right)\)
9. \(-\left(\frac{-13}{-2}\right)+\left(\frac{-10}{7}\right)\)
10. \(+\left(\frac{-4}{-13}\right)+\left(\frac{3}{7}\right)\)
11. \(-\left(\frac{-5}{9}\right)+\left(\frac{3}{2}\right)\)
12. \(+\left(\frac{-7}{-3}\right)-\left(\frac{-5}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{12}{-7}\right)+\left(\frac{8}{9}\right)\\= \frac{12}{7}+\frac{8}{9}\\=\frac{108}{63}+\frac{56}{63}\\=\frac{108+56}{63}\\=\frac{164}{63}\)
2. \(-\left(\frac{11}{5}\right)+\left(\frac{-3}{13}\right)\\= \frac{-11}{5}-\frac{3}{13}\\=\frac{-143}{65}-\frac{15}{65}\\=\frac{-143-15}{65}\\=\frac{-158}{65}\)
3. \(-\left(\frac{-6}{-5}\right)+\left(\frac{7}{-4}\right)\\= \frac{-6}{5}-\frac{7}{4}\\=\frac{-24}{20}-\frac{35}{20}\\=\frac{-24-35}{20}\\=\frac{-59}{20}\)
4. \(-\left(\frac{-10}{3}\right)-\left(\frac{14}{-9}\right)\\= \frac{10}{3}+\frac{14}{9}\\=\frac{30}{9}+\frac{14}{9}\\=\frac{30+14}{9}\\=\frac{44}{9}\)
5. \(+\left(\frac{5}{6}\right)-\left(\frac{-10}{7}\right)\\= \frac{5}{6}+\frac{10}{7}\\=\frac{35}{42}+\frac{60}{42}\\=\frac{35+60}{42}\\=\frac{95}{42}\)
6. \(+\left(\frac{11}{13}\right)+\left(\frac{14}{-3}\right)\\= \frac{11}{13}-\frac{14}{3}\\=\frac{33}{39}-\frac{182}{39}\\=\frac{33-182}{39}\\=\frac{-149}{39}\)
7. \(+\left(\frac{-8}{-13}\right)-\left(\frac{14}{13}\right)\\= \frac{8}{13}-\frac{14}{13}\\=\frac{8-14}{13}\\=\frac{-6}{13}\)
8. \(-\left(\frac{3}{-11}\right)+\left(\frac{14}{11}\right)\\= \frac{3}{11}+\frac{14}{11}\\=\frac{3+14}{11}\\=\frac{17}{11}\)
9. \(-\left(\frac{-13}{-2}\right)+\left(\frac{-10}{7}\right)\\= \frac{-13}{2}-\frac{10}{7}\\=\frac{-91}{14}-\frac{20}{14}\\=\frac{-91-20}{14}\\=\frac{-111}{14}\)
10. \(+\left(\frac{-4}{-13}\right)+\left(\frac{3}{7}\right)\\= \frac{4}{13}+\frac{3}{7}\\=\frac{28}{91}+\frac{39}{91}\\=\frac{28+39}{91}\\=\frac{67}{91}\)
11. \(-\left(\frac{-5}{9}\right)+\left(\frac{3}{2}\right)\\= \frac{5}{9}+\frac{3}{2}\\=\frac{10}{18}+\frac{27}{18}\\=\frac{10+27}{18}\\=\frac{37}{18}\)
12. \(+\left(\frac{-7}{-3}\right)-\left(\frac{-5}{-3}\right)\\= \frac{7}{3}-\frac{5}{3}\\=\frac{7-5}{3}\\=\frac{2}{3}\)