Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-9}{-8}\right)-\left(\frac{13}{-5}\right)\)
2. \(-\left(\frac{-15}{7}\right)+\left(\frac{-4}{-3}\right)\)
3. \(-\left(\frac{-8}{3}\right)+\left(\frac{14}{-3}\right)\)
4. \(+\left(\frac{-2}{-13}\right)-\left(\frac{-5}{11}\right)\)
5. \(-\left(\frac{6}{5}\right)+\left(\frac{-13}{-4}\right)\)
6. \(-\left(\frac{2}{-3}\right)-\left(\frac{-11}{3}\right)\)
7. \(-\left(\frac{11}{-5}\right)+\left(\frac{-15}{4}\right)\)
8. \(+\left(\frac{15}{7}\right)-\left(\frac{-2}{3}\right)\)
9. \(+\left(\frac{13}{-8}\right)-\left(\frac{-13}{-7}\right)\)
10. \(-\left(\frac{-9}{10}\right)+\left(\frac{-9}{13}\right)\)
11. \(+\left(\frac{-8}{-13}\right)-\left(\frac{7}{-5}\right)\)
12. \(-\left(\frac{-14}{9}\right)+\left(\frac{-2}{-13}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-9}{-8}\right)-\left(\frac{13}{-5}\right)\\= \frac{-9}{8}+\frac{13}{5}\\=\frac{-45}{40}+\frac{104}{40}\\=\frac{-45+104}{40}\\=\frac{59}{40}\)
2. \(-\left(\frac{-15}{7}\right)+\left(\frac{-4}{-3}\right)\\= \frac{15}{7}+\frac{4}{3}\\=\frac{45}{21}+\frac{28}{21}\\=\frac{45+28}{21}\\=\frac{73}{21}\)
3. \(-\left(\frac{-8}{3}\right)+\left(\frac{14}{-3}\right)\\= \frac{8}{3}-\frac{14}{3}\\=\frac{8-14}{3}\\=\frac{-6}{3}\\=\frac{-2}{1}\)
4. \(+\left(\frac{-2}{-13}\right)-\left(\frac{-5}{11}\right)\\= \frac{2}{13}+\frac{5}{11}\\=\frac{22}{143}+\frac{65}{143}\\=\frac{22+65}{143}\\=\frac{87}{143}\)
5. \(-\left(\frac{6}{5}\right)+\left(\frac{-13}{-4}\right)\\= \frac{-6}{5}+\frac{13}{4}\\=\frac{-24}{20}+\frac{65}{20}\\=\frac{-24+65}{20}\\=\frac{41}{20}\)
6. \(-\left(\frac{2}{-3}\right)-\left(\frac{-11}{3}\right)\\= \frac{2}{3}+\frac{11}{3}\\=\frac{2+11}{3}\\=\frac{13}{3}\)
7. \(-\left(\frac{11}{-5}\right)+\left(\frac{-15}{4}\right)\\= \frac{11}{5}-\frac{15}{4}\\=\frac{44}{20}-\frac{75}{20}\\=\frac{44-75}{20}\\=\frac{-31}{20}\)
8. \(+\left(\frac{15}{7}\right)-\left(\frac{-2}{3}\right)\\= \frac{15}{7}+\frac{2}{3}\\=\frac{45}{21}+\frac{14}{21}\\=\frac{45+14}{21}\\=\frac{59}{21}\)
9. \(+\left(\frac{13}{-8}\right)-\left(\frac{-13}{-7}\right)\\= \frac{-13}{8}-\frac{13}{7}\\=\frac{-91}{56}-\frac{104}{56}\\=\frac{-91-104}{56}\\=\frac{-195}{56}\)
10. \(-\left(\frac{-9}{10}\right)+\left(\frac{-9}{13}\right)\\= \frac{9}{10}-\frac{9}{13}\\=\frac{117}{130}-\frac{90}{130}\\=\frac{117-90}{130}\\=\frac{27}{130}\)
11. \(+\left(\frac{-8}{-13}\right)-\left(\frac{7}{-5}\right)\\= \frac{8}{13}+\frac{7}{5}\\=\frac{40}{65}+\frac{91}{65}\\=\frac{40+91}{65}\\=\frac{131}{65}\)
12. \(-\left(\frac{-14}{9}\right)+\left(\frac{-2}{-13}\right)\\= \frac{14}{9}+\frac{2}{13}\\=\frac{182}{117}+\frac{18}{117}\\=\frac{182+18}{117}\\=\frac{200}{117}\)