Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{5}{-6}\right)-\left(\frac{12}{-11}\right)\)
2. \(+\left(\frac{-11}{2}\right)-\left(\frac{-10}{3}\right)\)
3. \(+\left(\frac{-6}{5}\right)+\left(\frac{-13}{8}\right)\)
4. \(+\left(\frac{-8}{13}\right)-\left(\frac{-3}{7}\right)\)
5. \(+\left(\frac{-5}{13}\right)-\left(\frac{-8}{3}\right)\)
6. \(-\left(\frac{14}{-3}\right)+\left(\frac{-8}{-5}\right)\)
7. \(+\left(\frac{14}{3}\right)+\left(\frac{4}{-7}\right)\)
8. \(-\left(\frac{-4}{-13}\right)-\left(\frac{-9}{-10}\right)\)
9. \(-\left(\frac{8}{9}\right)-\left(\frac{14}{5}\right)\)
10. \(-\left(\frac{-8}{-3}\right)-\left(\frac{-8}{5}\right)\)
11. \(-\left(\frac{14}{-13}\right)-\left(\frac{5}{-7}\right)\)
12. \(+\left(\frac{-8}{3}\right)-\left(\frac{7}{8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{5}{-6}\right)-\left(\frac{12}{-11}\right)\\= \frac{-5}{6}+\frac{12}{11}\\=\frac{-55}{66}+\frac{72}{66}\\=\frac{-55+72}{66}\\=\frac{17}{66}\)
2. \(+\left(\frac{-11}{2}\right)-\left(\frac{-10}{3}\right)\\= \frac{-11}{2}+\frac{10}{3}\\=\frac{-33}{6}+\frac{20}{6}\\=\frac{-33+20}{6}\\=\frac{-13}{6}\)
3. \(+\left(\frac{-6}{5}\right)+\left(\frac{-13}{8}\right)\\= \frac{-6}{5}-\frac{13}{8}\\=\frac{-48}{40}-\frac{65}{40}\\=\frac{-48-65}{40}\\=\frac{-113}{40}\)
4. \(+\left(\frac{-8}{13}\right)-\left(\frac{-3}{7}\right)\\= \frac{-8}{13}+\frac{3}{7}\\=\frac{-56}{91}+\frac{39}{91}\\=\frac{-56+39}{91}\\=\frac{-17}{91}\)
5. \(+\left(\frac{-5}{13}\right)-\left(\frac{-8}{3}\right)\\= \frac{-5}{13}+\frac{8}{3}\\=\frac{-15}{39}+\frac{104}{39}\\=\frac{-15+104}{39}\\=\frac{89}{39}\)
6. \(-\left(\frac{14}{-3}\right)+\left(\frac{-8}{-5}\right)\\= \frac{14}{3}+\frac{8}{5}\\=\frac{70}{15}+\frac{24}{15}\\=\frac{70+24}{15}\\=\frac{94}{15}\)
7. \(+\left(\frac{14}{3}\right)+\left(\frac{4}{-7}\right)\\= \frac{14}{3}-\frac{4}{7}\\=\frac{98}{21}-\frac{12}{21}\\=\frac{98-12}{21}\\=\frac{86}{21}\)
8. \(-\left(\frac{-4}{-13}\right)-\left(\frac{-9}{-10}\right)\\= \frac{-4}{13}-\frac{9}{10}\\=\frac{-40}{130}-\frac{117}{130}\\=\frac{-40-117}{130}\\=\frac{-157}{130}\)
9. \(-\left(\frac{8}{9}\right)-\left(\frac{14}{5}\right)\\= \frac{-8}{9}-\frac{14}{5}\\=\frac{-40}{45}-\frac{126}{45}\\=\frac{-40-126}{45}\\=\frac{-166}{45}\)
10. \(-\left(\frac{-8}{-3}\right)-\left(\frac{-8}{5}\right)\\= \frac{-8}{3}+\frac{8}{5}\\=\frac{-40}{15}+\frac{24}{15}\\=\frac{-40+24}{15}\\=\frac{-16}{15}\)
11. \(-\left(\frac{14}{-13}\right)-\left(\frac{5}{-7}\right)\\= \frac{14}{13}+\frac{5}{7}\\=\frac{98}{91}+\frac{65}{91}\\=\frac{98+65}{91}\\=\frac{163}{91}\)
12. \(+\left(\frac{-8}{3}\right)-\left(\frac{7}{8}\right)\\= \frac{-8}{3}-\frac{7}{8}\\=\frac{-64}{24}-\frac{21}{24}\\=\frac{-64-21}{24}\\=\frac{-85}{24}\)