Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{14}{-3}\right)+\left(\frac{-10}{-9}\right)\)
2. \(-\left(\frac{-4}{-7}\right)-\left(\frac{-14}{9}\right)\)
3. \(+\left(\frac{2}{-9}\right)+\left(\frac{12}{-11}\right)\)
4. \(-\left(\frac{-12}{13}\right)+\left(\frac{-10}{3}\right)\)
5. \(+\left(\frac{-15}{-13}\right)-\left(\frac{10}{-3}\right)\)
6. \(-\left(\frac{14}{-3}\right)+\left(\frac{10}{3}\right)\)
7. \(+\left(\frac{14}{3}\right)+\left(\frac{3}{14}\right)\)
8. \(-\left(\frac{-4}{9}\right)+\left(\frac{-11}{-13}\right)\)
9. \(-\left(\frac{9}{2}\right)+\left(\frac{11}{3}\right)\)
10. \(-\left(\frac{6}{-11}\right)-\left(\frac{-14}{-3}\right)\)
11. \(+\left(\frac{-9}{4}\right)+\left(\frac{12}{-5}\right)\)
12. \(-\left(\frac{10}{-3}\right)+\left(\frac{12}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{14}{-3}\right)+\left(\frac{-10}{-9}\right)\\= \frac{14}{3}+\frac{10}{9}\\=\frac{42}{9}+\frac{10}{9}\\=\frac{42+10}{9}\\=\frac{52}{9}\)
2. \(-\left(\frac{-4}{-7}\right)-\left(\frac{-14}{9}\right)\\= \frac{-4}{7}+\frac{14}{9}\\=\frac{-36}{63}+\frac{98}{63}\\=\frac{-36+98}{63}\\=\frac{62}{63}\)
3. \(+\left(\frac{2}{-9}\right)+\left(\frac{12}{-11}\right)\\= \frac{-2}{9}-\frac{12}{11}\\=\frac{-22}{99}-\frac{108}{99}\\=\frac{-22-108}{99}\\=\frac{-130}{99}\)
4. \(-\left(\frac{-12}{13}\right)+\left(\frac{-10}{3}\right)\\= \frac{12}{13}-\frac{10}{3}\\=\frac{36}{39}-\frac{130}{39}\\=\frac{36-130}{39}\\=\frac{-94}{39}\)
5. \(+\left(\frac{-15}{-13}\right)-\left(\frac{10}{-3}\right)\\= \frac{15}{13}+\frac{10}{3}\\=\frac{45}{39}+\frac{130}{39}\\=\frac{45+130}{39}\\=\frac{175}{39}\)
6. \(-\left(\frac{14}{-3}\right)+\left(\frac{10}{3}\right)\\= \frac{14}{3}+\frac{10}{3}\\=\frac{14+10}{3}\\=\frac{24}{3}\\=\frac{8}{1}\)
7. \(+\left(\frac{14}{3}\right)+\left(\frac{3}{14}\right)\\= \frac{14}{3}+\frac{3}{14}\\=\frac{196}{42}+\frac{9}{42}\\=\frac{196+9}{42}\\=\frac{205}{42}\)
8. \(-\left(\frac{-4}{9}\right)+\left(\frac{-11}{-13}\right)\\= \frac{4}{9}+\frac{11}{13}\\=\frac{52}{117}+\frac{99}{117}\\=\frac{52+99}{117}\\=\frac{151}{117}\)
9. \(-\left(\frac{9}{2}\right)+\left(\frac{11}{3}\right)\\= \frac{-9}{2}+\frac{11}{3}\\=\frac{-27}{6}+\frac{22}{6}\\=\frac{-27+22}{6}\\=\frac{-5}{6}\)
10. \(-\left(\frac{6}{-11}\right)-\left(\frac{-14}{-3}\right)\\= \frac{6}{11}-\frac{14}{3}\\=\frac{18}{33}-\frac{154}{33}\\=\frac{18-154}{33}\\=\frac{-136}{33}\)
11. \(+\left(\frac{-9}{4}\right)+\left(\frac{12}{-5}\right)\\= \frac{-9}{4}-\frac{12}{5}\\=\frac{-45}{20}-\frac{48}{20}\\=\frac{-45-48}{20}\\=\frac{-93}{20}\)
12. \(-\left(\frac{10}{-3}\right)+\left(\frac{12}{-5}\right)\\= \frac{10}{3}-\frac{12}{5}\\=\frac{50}{15}-\frac{36}{15}\\=\frac{50-36}{15}\\=\frac{14}{15}\)