Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-5}{6}\right)-\left(\frac{-13}{14}\right)\)
2. \(+\left(\frac{-11}{-5}\right)-\left(\frac{15}{7}\right)\)
3. \(+\left(\frac{-10}{11}\right)-\left(\frac{7}{-2}\right)\)
4. \(+\left(\frac{-2}{11}\right)+\left(\frac{-7}{-4}\right)\)
5. \(+\left(\frac{-12}{11}\right)-\left(\frac{4}{-3}\right)\)
6. \(-\left(\frac{13}{9}\right)+\left(\frac{11}{-12}\right)\)
7. \(+\left(\frac{13}{2}\right)-\left(\frac{9}{-2}\right)\)
8. \(-\left(\frac{-7}{-2}\right)+\left(\frac{-9}{5}\right)\)
9. \(-\left(\frac{-12}{-5}\right)-\left(\frac{-7}{8}\right)\)
10. \(-\left(\frac{-8}{-3}\right)-\left(\frac{-9}{-2}\right)\)
11. \(-\left(\frac{-9}{-7}\right)+\left(\frac{-11}{-6}\right)\)
12. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-13}{-14}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-5}{6}\right)-\left(\frac{-13}{14}\right)\\= \frac{5}{6}+\frac{13}{14}\\=\frac{35}{42}+\frac{39}{42}\\=\frac{35+39}{42}\\=\frac{74}{42}\\=\frac{37}{21}\)
2. \(+\left(\frac{-11}{-5}\right)-\left(\frac{15}{7}\right)\\= \frac{11}{5}-\frac{15}{7}\\=\frac{77}{35}-\frac{75}{35}\\=\frac{77-75}{35}\\=\frac{2}{35}\)
3. \(+\left(\frac{-10}{11}\right)-\left(\frac{7}{-2}\right)\\= \frac{-10}{11}+\frac{7}{2}\\=\frac{-20}{22}+\frac{77}{22}\\=\frac{-20+77}{22}\\=\frac{57}{22}\)
4. \(+\left(\frac{-2}{11}\right)+\left(\frac{-7}{-4}\right)\\= \frac{-2}{11}+\frac{7}{4}\\=\frac{-8}{44}+\frac{77}{44}\\=\frac{-8+77}{44}\\=\frac{69}{44}\)
5. \(+\left(\frac{-12}{11}\right)-\left(\frac{4}{-3}\right)\\= \frac{-12}{11}+\frac{4}{3}\\=\frac{-36}{33}+\frac{44}{33}\\=\frac{-36+44}{33}\\=\frac{8}{33}\)
6. \(-\left(\frac{13}{9}\right)+\left(\frac{11}{-12}\right)\\= \frac{-13}{9}-\frac{11}{12}\\=\frac{-52}{36}-\frac{33}{36}\\=\frac{-52-33}{36}\\=\frac{-85}{36}\)
7. \(+\left(\frac{13}{2}\right)-\left(\frac{9}{-2}\right)\\= \frac{13}{2}+\frac{9}{2}\\=\frac{13+9}{2}\\=\frac{22}{2}\\=\frac{11}{1}\)
8. \(-\left(\frac{-7}{-2}\right)+\left(\frac{-9}{5}\right)\\= \frac{-7}{2}-\frac{9}{5}\\=\frac{-35}{10}-\frac{18}{10}\\=\frac{-35-18}{10}\\=\frac{-53}{10}\)
9. \(-\left(\frac{-12}{-5}\right)-\left(\frac{-7}{8}\right)\\= \frac{-12}{5}+\frac{7}{8}\\=\frac{-96}{40}+\frac{35}{40}\\=\frac{-96+35}{40}\\=\frac{-61}{40}\)
10. \(-\left(\frac{-8}{-3}\right)-\left(\frac{-9}{-2}\right)\\= \frac{-8}{3}-\frac{9}{2}\\=\frac{-16}{6}-\frac{27}{6}\\=\frac{-16-27}{6}\\=\frac{-43}{6}\)
11. \(-\left(\frac{-9}{-7}\right)+\left(\frac{-11}{-6}\right)\\= \frac{-9}{7}+\frac{11}{6}\\=\frac{-54}{42}+\frac{77}{42}\\=\frac{-54+77}{42}\\=\frac{23}{42}\)
12. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-13}{-14}\right)\\= \frac{4}{3}-\frac{13}{14}\\=\frac{56}{42}-\frac{39}{42}\\=\frac{56-39}{42}\\=\frac{17}{42}\)