Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-6}{-5}\right)+\left(\frac{10}{3}\right)\)
2. \(+\left(\frac{-13}{-10}\right)+\left(\frac{9}{7}\right)\)
3. \(-\left(\frac{2}{-11}\right)-\left(\frac{-6}{5}\right)\)
4. \(+\left(\frac{5}{-6}\right)+\left(\frac{12}{7}\right)\)
5. \(-\left(\frac{-6}{13}\right)+\left(\frac{-14}{-9}\right)\)
6. \(+\left(\frac{-6}{-13}\right)+\left(\frac{14}{3}\right)\)
7. \(-\left(\frac{-9}{11}\right)+\left(\frac{-4}{3}\right)\)
8. \(-\left(\frac{15}{-13}\right)+\left(\frac{-12}{11}\right)\)
9. \(+\left(\frac{9}{-2}\right)+\left(\frac{-13}{-2}\right)\)
10. \(+\left(\frac{-4}{13}\right)+\left(\frac{-12}{-11}\right)\)
11. \(-\left(\frac{-5}{-7}\right)+\left(\frac{4}{-3}\right)\)
12. \(-\left(\frac{-2}{-3}\right)+\left(\frac{-14}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-6}{-5}\right)+\left(\frac{10}{3}\right)\\= \frac{-6}{5}+\frac{10}{3}\\=\frac{-18}{15}+\frac{50}{15}\\=\frac{-18+50}{15}\\=\frac{32}{15}\)
2. \(+\left(\frac{-13}{-10}\right)+\left(\frac{9}{7}\right)\\= \frac{13}{10}+\frac{9}{7}\\=\frac{91}{70}+\frac{90}{70}\\=\frac{91+90}{70}\\=\frac{181}{70}\)
3. \(-\left(\frac{2}{-11}\right)-\left(\frac{-6}{5}\right)\\= \frac{2}{11}+\frac{6}{5}\\=\frac{10}{55}+\frac{66}{55}\\=\frac{10+66}{55}\\=\frac{76}{55}\)
4. \(+\left(\frac{5}{-6}\right)+\left(\frac{12}{7}\right)\\= \frac{-5}{6}+\frac{12}{7}\\=\frac{-35}{42}+\frac{72}{42}\\=\frac{-35+72}{42}\\=\frac{37}{42}\)
5. \(-\left(\frac{-6}{13}\right)+\left(\frac{-14}{-9}\right)\\= \frac{6}{13}+\frac{14}{9}\\=\frac{54}{117}+\frac{182}{117}\\=\frac{54+182}{117}\\=\frac{236}{117}\)
6. \(+\left(\frac{-6}{-13}\right)+\left(\frac{14}{3}\right)\\= \frac{6}{13}+\frac{14}{3}\\=\frac{18}{39}+\frac{182}{39}\\=\frac{18+182}{39}\\=\frac{200}{39}\)
7. \(-\left(\frac{-9}{11}\right)+\left(\frac{-4}{3}\right)\\= \frac{9}{11}-\frac{4}{3}\\=\frac{27}{33}-\frac{44}{33}\\=\frac{27-44}{33}\\=\frac{-17}{33}\)
8. \(-\left(\frac{15}{-13}\right)+\left(\frac{-12}{11}\right)\\= \frac{15}{13}-\frac{12}{11}\\=\frac{165}{143}-\frac{156}{143}\\=\frac{165-156}{143}\\=\frac{9}{143}\)
9. \(+\left(\frac{9}{-2}\right)+\left(\frac{-13}{-2}\right)\\= \frac{-9}{2}+\frac{13}{2}\\=\frac{-9+13}{2}\\=\frac{4}{2}\\=\frac{2}{1}\)
10. \(+\left(\frac{-4}{13}\right)+\left(\frac{-12}{-11}\right)\\= \frac{-4}{13}+\frac{12}{11}\\=\frac{-44}{143}+\frac{156}{143}\\=\frac{-44+156}{143}\\=\frac{112}{143}\)
11. \(-\left(\frac{-5}{-7}\right)+\left(\frac{4}{-3}\right)\\= \frac{-5}{7}-\frac{4}{3}\\=\frac{-15}{21}-\frac{28}{21}\\=\frac{-15-28}{21}\\=\frac{-43}{21}\)
12. \(-\left(\frac{-2}{-3}\right)+\left(\frac{-14}{-5}\right)\\= \frac{-2}{3}+\frac{14}{5}\\=\frac{-10}{15}+\frac{42}{15}\\=\frac{-10+42}{15}\\=\frac{32}{15}\)