Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{12}{5}\right)+\left(\frac{3}{10}\right)\)
2. \(-\left(\frac{-14}{-9}\right)+\left(\frac{-15}{-7}\right)\)
3. \(-\left(\frac{-8}{7}\right)-\left(\frac{2}{7}\right)\)
4. \(-\left(\frac{-3}{4}\right)-\left(\frac{-5}{-2}\right)\)
5. \(+\left(\frac{10}{-7}\right)-\left(\frac{13}{5}\right)\)
6. \(-\left(\frac{5}{3}\right)+\left(\frac{15}{2}\right)\)
7. \(-\left(\frac{-3}{-13}\right)-\left(\frac{5}{6}\right)\)
8. \(+\left(\frac{-4}{3}\right)-\left(\frac{9}{-2}\right)\)
9. \(+\left(\frac{12}{-11}\right)+\left(\frac{-11}{-10}\right)\)
10. \(+\left(\frac{-13}{2}\right)-\left(\frac{-12}{5}\right)\)
11. \(+\left(\frac{4}{9}\right)-\left(\frac{-12}{-5}\right)\)
12. \(+\left(\frac{11}{-12}\right)+\left(\frac{-11}{6}\right)\)

---

Bereken

Verbetersleutel

1. \(-\left(\frac{12}{5}\right)+\left(\frac{3}{10}\right)\\= \frac{-12}{5}+\frac{3}{10}\\=\frac{-24}{10}+\frac{3}{10}\\=\frac{-24+3}{10}\\=\frac{-21}{10}\)
2. \(-\left(\frac{-14}{-9}\right)+\left(\frac{-15}{-7}\right)\\= \frac{-14}{9}+\frac{15}{7}\\=\frac{-98}{63}+\frac{135}{63}\\=\frac{-98+135}{63}\\=\frac{37}{63}\)
3. \(-\left(\frac{-8}{7}\right)-\left(\frac{2}{7}\right)\\= \frac{8}{7}-\frac{2}{7}\\=\frac{8-2}{7}\\=\frac{6}{7}\)
4. \(-\left(\frac{-3}{4}\right)-\left(\frac{-5}{-2}\right)\\= \frac{3}{4}-\frac{5}{2}\\=\frac{3-5}{4}\\=\frac{-2}{4}\\=\frac{-1}{2}\)
5. \(+\left(\frac{10}{-7}\right)-\left(\frac{13}{5}\right)\\= \frac{-10}{7}-\frac{13}{5}\\=\frac{-50}{35}-\frac{91}{35}\\=\frac{-50-91}{35}\\=\frac{-141}{35}\)
6. \(-\left(\frac{5}{3}\right)+\left(\frac{15}{2}\right)\\= \frac{-5}{3}+\frac{15}{2}\\=\frac{-10}{6}+\frac{45}{6}\\=\frac{-10+45}{6}\\=\frac{35}{6}\)
7. \(-\left(\frac{-3}{-13}\right)-\left(\frac{5}{6}\right)\\= \frac{-3}{13}-\frac{5}{6}\\=\frac{-18}{78}-\frac{65}{78}\\=\frac{-18-65}{78}\\=\frac{-83}{78}\)
8. \(+\left(\frac{-4}{3}\right)-\left(\frac{9}{-2}\right)\\= \frac{-4}{3}+\frac{9}{2}\\=\frac{-8}{6}+\frac{27}{6}\\=\frac{-8+27}{6}\\=\frac{19}{6}\)
9. \(+\left(\frac{12}{-11}\right)+\left(\frac{-11}{-10}\right)\\= \frac{-12}{11}+\frac{11}{10}\\=\frac{-120}{110}+\frac{121}{110}\\=\frac{-120+121}{110}\\=\frac{1}{110}\)
10. \(+\left(\frac{-13}{2}\right)-\left(\frac{-12}{5}\right)\\= \frac{-13}{2}+\frac{12}{5}\\=\frac{-65}{10}+\frac{24}{10}\\=\frac{-65+24}{10}\\=\frac{-41}{10}\)
11. \(+\left(\frac{4}{9}\right)-\left(\frac{-12}{-5}\right)\\= \frac{4}{9}-\frac{12}{5}\\=\frac{20}{45}-\frac{108}{45}\\=\frac{20-108}{45}\\=\frac{-88}{45}\)
12. \(+\left(\frac{11}{-12}\right)+\left(\frac{-11}{6}\right)\\= \frac{-11}{12}-\frac{11}{6}\\=\frac{-11-11}{12}\\=\frac{-22}{12}\\=\frac{-11}{6}\)