Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{11}{-8}\right)-\left(\frac{6}{-11}\right)\)
2. \(-\left(\frac{7}{13}\right)-\left(\frac{8}{-11}\right)\)
3. \(+\left(\frac{15}{-7}\right)-\left(\frac{6}{7}\right)\)
4. \(+\left(\frac{8}{3}\right)-\left(\frac{10}{9}\right)\)
5. \(-\left(\frac{-7}{-6}\right)-\left(\frac{-15}{-4}\right)\)
6. \(+\left(\frac{-2}{-3}\right)+\left(\frac{4}{9}\right)\)
7. \(-\left(\frac{11}{-12}\right)-\left(\frac{-10}{-3}\right)\)
8. \(-\left(\frac{-7}{8}\right)+\left(\frac{2}{7}\right)\)
9. \(-\left(\frac{-11}{-7}\right)-\left(\frac{11}{10}\right)\)
10. \(+\left(\frac{6}{-11}\right)+\left(\frac{-13}{2}\right)\)
11. \(-\left(\frac{13}{7}\right)+\left(\frac{-2}{13}\right)\)
12. \(-\left(\frac{-8}{-3}\right)-\left(\frac{-10}{9}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{11}{-8}\right)-\left(\frac{6}{-11}\right)\\= \frac{11}{8}+\frac{6}{11}\\=\frac{121}{88}+\frac{48}{88}\\=\frac{121+48}{88}\\=\frac{169}{88}\)
2. \(-\left(\frac{7}{13}\right)-\left(\frac{8}{-11}\right)\\= \frac{-7}{13}+\frac{8}{11}\\=\frac{-77}{143}+\frac{104}{143}\\=\frac{-77+104}{143}\\=\frac{27}{143}\)
3. \(+\left(\frac{15}{-7}\right)-\left(\frac{6}{7}\right)\\= \frac{-15}{7}-\frac{6}{7}\\=\frac{-15-6}{7}\\=\frac{-21}{7}\\=\frac{-3}{1}\)
4. \(+\left(\frac{8}{3}\right)-\left(\frac{10}{9}\right)\\= \frac{8}{3}-\frac{10}{9}\\=\frac{24}{9}-\frac{10}{9}\\=\frac{24-10}{9}\\=\frac{14}{9}\)
5. \(-\left(\frac{-7}{-6}\right)-\left(\frac{-15}{-4}\right)\\= \frac{-7}{6}-\frac{15}{4}\\=\frac{-14}{12}-\frac{45}{12}\\=\frac{-14-45}{12}\\=\frac{-59}{12}\)
6. \(+\left(\frac{-2}{-3}\right)+\left(\frac{4}{9}\right)\\= \frac{2}{3}+\frac{4}{9}\\=\frac{6}{9}+\frac{4}{9}\\=\frac{6+4}{9}\\=\frac{10}{9}\)
7. \(-\left(\frac{11}{-12}\right)-\left(\frac{-10}{-3}\right)\\= \frac{11}{12}-\frac{10}{3}\\=\frac{11-10}{12}\\=\frac{1}{12}\)
8. \(-\left(\frac{-7}{8}\right)+\left(\frac{2}{7}\right)\\= \frac{7}{8}+\frac{2}{7}\\=\frac{49}{56}+\frac{16}{56}\\=\frac{49+16}{56}\\=\frac{65}{56}\)
9. \(-\left(\frac{-11}{-7}\right)-\left(\frac{11}{10}\right)\\= \frac{-11}{7}-\frac{11}{10}\\=\frac{-110}{70}-\frac{77}{70}\\=\frac{-110-77}{70}\\=\frac{-187}{70}\)
10. \(+\left(\frac{6}{-11}\right)+\left(\frac{-13}{2}\right)\\= \frac{-6}{11}-\frac{13}{2}\\=\frac{-12}{22}-\frac{143}{22}\\=\frac{-12-143}{22}\\=\frac{-155}{22}\)
11. \(-\left(\frac{13}{7}\right)+\left(\frac{-2}{13}\right)\\= \frac{-13}{7}-\frac{2}{13}\\=\frac{-169}{91}-\frac{14}{91}\\=\frac{-169-14}{91}\\=\frac{-183}{91}\)
12. \(-\left(\frac{-8}{-3}\right)-\left(\frac{-10}{9}\right)\\= \frac{-8}{3}+\frac{10}{9}\\=\frac{-24}{9}+\frac{10}{9}\\=\frac{-24+10}{9}\\=\frac{-14}{9}\)