Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{7}{12}\right)-\left(\frac{-9}{-2}\right)\)
2. \(-\left(\frac{-10}{-3}\right)+\left(\frac{-11}{7}\right)\)
3. \(-\left(\frac{10}{7}\right)+\left(\frac{7}{-10}\right)\)
4. \(-\left(\frac{-8}{-5}\right)+\left(\frac{9}{13}\right)\)
5. \(+\left(\frac{7}{-5}\right)+\left(\frac{8}{11}\right)\)
6. \(-\left(\frac{11}{8}\right)+\left(\frac{-6}{-11}\right)\)
7. \(-\left(\frac{9}{-13}\right)+\left(\frac{13}{-12}\right)\)
8. \(-\left(\frac{12}{5}\right)+\left(\frac{15}{-4}\right)\)
9. \(-\left(\frac{-14}{-3}\right)+\left(\frac{-5}{-7}\right)\)
10. \(-\left(\frac{5}{9}\right)+\left(\frac{-14}{3}\right)\)
11. \(+\left(\frac{2}{3}\right)-\left(\frac{-15}{11}\right)\)
12. \(-\left(\frac{-12}{-13}\right)-\left(\frac{3}{8}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{7}{12}\right)-\left(\frac{-9}{-2}\right)\\= \frac{-7}{12}-\frac{9}{2}\\=\frac{-7-9}{12}\\=\frac{-16}{12}\\=\frac{-4}{3}\)
2. \(-\left(\frac{-10}{-3}\right)+\left(\frac{-11}{7}\right)\\= \frac{-10}{3}-\frac{11}{7}\\=\frac{-70}{21}-\frac{33}{21}\\=\frac{-70-33}{21}\\=\frac{-103}{21}\)
3. \(-\left(\frac{10}{7}\right)+\left(\frac{7}{-10}\right)\\= \frac{-10}{7}-\frac{7}{10}\\=\frac{-100}{70}-\frac{49}{70}\\=\frac{-100-49}{70}\\=\frac{-149}{70}\)
4. \(-\left(\frac{-8}{-5}\right)+\left(\frac{9}{13}\right)\\= \frac{-8}{5}+\frac{9}{13}\\=\frac{-104}{65}+\frac{45}{65}\\=\frac{-104+45}{65}\\=\frac{-59}{65}\)
5. \(+\left(\frac{7}{-5}\right)+\left(\frac{8}{11}\right)\\= \frac{-7}{5}+\frac{8}{11}\\=\frac{-77}{55}+\frac{40}{55}\\=\frac{-77+40}{55}\\=\frac{-37}{55}\)
6. \(-\left(\frac{11}{8}\right)+\left(\frac{-6}{-11}\right)\\= \frac{-11}{8}+\frac{6}{11}\\=\frac{-121}{88}+\frac{48}{88}\\=\frac{-121+48}{88}\\=\frac{-73}{88}\)
7. \(-\left(\frac{9}{-13}\right)+\left(\frac{13}{-12}\right)\\= \frac{9}{13}-\frac{13}{12}\\=\frac{108}{156}-\frac{169}{156}\\=\frac{108-169}{156}\\=\frac{-61}{156}\)
8. \(-\left(\frac{12}{5}\right)+\left(\frac{15}{-4}\right)\\= \frac{-12}{5}-\frac{15}{4}\\=\frac{-48}{20}-\frac{75}{20}\\=\frac{-48-75}{20}\\=\frac{-123}{20}\)
9. \(-\left(\frac{-14}{-3}\right)+\left(\frac{-5}{-7}\right)\\= \frac{-14}{3}+\frac{5}{7}\\=\frac{-98}{21}+\frac{15}{21}\\=\frac{-98+15}{21}\\=\frac{-83}{21}\)
10. \(-\left(\frac{5}{9}\right)+\left(\frac{-14}{3}\right)\\= \frac{-5}{9}-\frac{14}{3}\\=\frac{-5-14}{9}\\=\frac{-19}{9}\)
11. \(+\left(\frac{2}{3}\right)-\left(\frac{-15}{11}\right)\\= \frac{2}{3}+\frac{15}{11}\\=\frac{22}{33}+\frac{45}{33}\\=\frac{22+45}{33}\\=\frac{67}{33}\)
12. \(-\left(\frac{-12}{-13}\right)-\left(\frac{3}{8}\right)\\= \frac{-12}{13}-\frac{3}{8}\\=\frac{-96}{104}-\frac{39}{104}\\=\frac{-96-39}{104}\\=\frac{-135}{104}\)