Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{3}{4}\right)+\left(\frac{-9}{5}\right)\)
2. \(+\left(\frac{-6}{11}\right)-\left(\frac{2}{-3}\right)\)
3. \(+\left(\frac{11}{4}\right)+\left(\frac{5}{14}\right)\)
4. \(+\left(\frac{-15}{-2}\right)+\left(\frac{-5}{12}\right)\)
5. \(+\left(\frac{-15}{-8}\right)+\left(\frac{4}{7}\right)\)
6. \(+\left(\frac{4}{-11}\right)-\left(\frac{4}{7}\right)\)
7. \(+\left(\frac{10}{-13}\right)-\left(\frac{-13}{14}\right)\)
8. \(+\left(\frac{12}{13}\right)-\left(\frac{-14}{11}\right)\)
9. \(+\left(\frac{5}{-7}\right)-\left(\frac{-8}{13}\right)\)
10. \(+\left(\frac{2}{13}\right)+\left(\frac{6}{-11}\right)\)
11. \(+\left(\frac{-11}{2}\right)-\left(\frac{6}{-5}\right)\)
12. \(+\left(\frac{-2}{-3}\right)+\left(\frac{7}{8}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{3}{4}\right)+\left(\frac{-9}{5}\right)\\= \frac{-3}{4}-\frac{9}{5}\\=\frac{-15}{20}-\frac{36}{20}\\=\frac{-15-36}{20}\\=\frac{-51}{20}\)
2. \(+\left(\frac{-6}{11}\right)-\left(\frac{2}{-3}\right)\\= \frac{-6}{11}+\frac{2}{3}\\=\frac{-18}{33}+\frac{22}{33}\\=\frac{-18+22}{33}\\=\frac{4}{33}\)
3. \(+\left(\frac{11}{4}\right)+\left(\frac{5}{14}\right)\\= \frac{11}{4}+\frac{5}{14}\\=\frac{77}{28}+\frac{10}{28}\\=\frac{77+10}{28}\\=\frac{87}{28}\)
4. \(+\left(\frac{-15}{-2}\right)+\left(\frac{-5}{12}\right)\\= \frac{15}{2}-\frac{5}{12}\\=\frac{90}{12}-\frac{5}{12}\\=\frac{90-5}{12}\\=\frac{85}{12}\)
5. \(+\left(\frac{-15}{-8}\right)+\left(\frac{4}{7}\right)\\= \frac{15}{8}+\frac{4}{7}\\=\frac{105}{56}+\frac{32}{56}\\=\frac{105+32}{56}\\=\frac{137}{56}\)
6. \(+\left(\frac{4}{-11}\right)-\left(\frac{4}{7}\right)\\= \frac{-4}{11}-\frac{4}{7}\\=\frac{-28}{77}-\frac{44}{77}\\=\frac{-28-44}{77}\\=\frac{-72}{77}\)
7. \(+\left(\frac{10}{-13}\right)-\left(\frac{-13}{14}\right)\\= \frac{-10}{13}+\frac{13}{14}\\=\frac{-140}{182}+\frac{169}{182}\\=\frac{-140+169}{182}\\=\frac{29}{182}\)
8. \(+\left(\frac{12}{13}\right)-\left(\frac{-14}{11}\right)\\= \frac{12}{13}+\frac{14}{11}\\=\frac{132}{143}+\frac{182}{143}\\=\frac{132+182}{143}\\=\frac{314}{143}\)
9. \(+\left(\frac{5}{-7}\right)-\left(\frac{-8}{13}\right)\\= \frac{-5}{7}+\frac{8}{13}\\=\frac{-65}{91}+\frac{56}{91}\\=\frac{-65+56}{91}\\=\frac{-9}{91}\)
10. \(+\left(\frac{2}{13}\right)+\left(\frac{6}{-11}\right)\\= \frac{2}{13}-\frac{6}{11}\\=\frac{22}{143}-\frac{78}{143}\\=\frac{22-78}{143}\\=\frac{-56}{143}\)
11. \(+\left(\frac{-11}{2}\right)-\left(\frac{6}{-5}\right)\\= \frac{-11}{2}+\frac{6}{5}\\=\frac{-55}{10}+\frac{12}{10}\\=\frac{-55+12}{10}\\=\frac{-43}{10}\)
12. \(+\left(\frac{-2}{-3}\right)+\left(\frac{7}{8}\right)\\= \frac{2}{3}+\frac{7}{8}\\=\frac{16}{24}+\frac{21}{24}\\=\frac{16+21}{24}\\=\frac{37}{24}\)