Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{10}{-7}\right)+\left(\frac{6}{13}\right)\)
2. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-4}{-3}\right)\)
3. \(-\left(\frac{-5}{11}\right)-\left(\frac{-4}{-9}\right)\)
4. \(+\left(\frac{-9}{-13}\right)+\left(\frac{3}{-10}\right)\)
5. \(-\left(\frac{-3}{-13}\right)+\left(\frac{10}{3}\right)\)
6. \(+\left(\frac{12}{5}\right)+\left(\frac{-13}{-10}\right)\)
7. \(-\left(\frac{7}{-8}\right)+\left(\frac{-7}{10}\right)\)
8. \(+\left(\frac{6}{5}\right)-\left(\frac{4}{-9}\right)\)
9. \(-\left(\frac{10}{3}\right)+\left(\frac{-9}{2}\right)\)
10. \(+\left(\frac{-8}{-5}\right)-\left(\frac{-3}{2}\right)\)
11. \(-\left(\frac{8}{3}\right)+\left(\frac{5}{-3}\right)\)
12. \(+\left(\frac{-14}{-3}\right)-\left(\frac{-13}{-11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{10}{-7}\right)+\left(\frac{6}{13}\right)\\= \frac{10}{7}+\frac{6}{13}\\=\frac{130}{91}+\frac{42}{91}\\=\frac{130+42}{91}\\=\frac{172}{91}\)
2. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-4}{-3}\right)\\= \frac{-6}{11}-\frac{4}{3}\\=\frac{-18}{33}-\frac{44}{33}\\=\frac{-18-44}{33}\\=\frac{-62}{33}\)
3. \(-\left(\frac{-5}{11}\right)-\left(\frac{-4}{-9}\right)\\= \frac{5}{11}-\frac{4}{9}\\=\frac{45}{99}-\frac{44}{99}\\=\frac{45-44}{99}\\=\frac{1}{99}\)
4. \(+\left(\frac{-9}{-13}\right)+\left(\frac{3}{-10}\right)\\= \frac{9}{13}-\frac{3}{10}\\=\frac{90}{130}-\frac{39}{130}\\=\frac{90-39}{130}\\=\frac{51}{130}\)
5. \(-\left(\frac{-3}{-13}\right)+\left(\frac{10}{3}\right)\\= \frac{-3}{13}+\frac{10}{3}\\=\frac{-9}{39}+\frac{130}{39}\\=\frac{-9+130}{39}\\=\frac{121}{39}\)
6. \(+\left(\frac{12}{5}\right)+\left(\frac{-13}{-10}\right)\\= \frac{12}{5}+\frac{13}{10}\\=\frac{24}{10}+\frac{13}{10}\\=\frac{24+13}{10}\\=\frac{37}{10}\)
7. \(-\left(\frac{7}{-8}\right)+\left(\frac{-7}{10}\right)\\= \frac{7}{8}-\frac{7}{10}\\=\frac{35}{40}-\frac{28}{40}\\=\frac{35-28}{40}\\=\frac{7}{40}\)
8. \(+\left(\frac{6}{5}\right)-\left(\frac{4}{-9}\right)\\= \frac{6}{5}+\frac{4}{9}\\=\frac{54}{45}+\frac{20}{45}\\=\frac{54+20}{45}\\=\frac{74}{45}\)
9. \(-\left(\frac{10}{3}\right)+\left(\frac{-9}{2}\right)\\= \frac{-10}{3}-\frac{9}{2}\\=\frac{-20}{6}-\frac{27}{6}\\=\frac{-20-27}{6}\\=\frac{-47}{6}\)
10. \(+\left(\frac{-8}{-5}\right)-\left(\frac{-3}{2}\right)\\= \frac{8}{5}+\frac{3}{2}\\=\frac{16}{10}+\frac{15}{10}\\=\frac{16+15}{10}\\=\frac{31}{10}\)
11. \(-\left(\frac{8}{3}\right)+\left(\frac{5}{-3}\right)\\= \frac{-8}{3}-\frac{5}{3}\\=\frac{-8-5}{3}\\=\frac{-13}{3}\)
12. \(+\left(\frac{-14}{-3}\right)-\left(\frac{-13}{-11}\right)\\= \frac{14}{3}-\frac{13}{11}\\=\frac{154}{33}-\frac{39}{33}\\=\frac{154-39}{33}\\=\frac{115}{33}\)