Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{13}{-8}\right)-\left(\frac{-3}{-5}\right)\)
2. \(+\left(\frac{-11}{12}\right)+\left(\frac{3}{7}\right)\)
3. \(-\left(\frac{10}{9}\right)-\left(\frac{15}{13}\right)\)
4. \(+\left(\frac{2}{-3}\right)+\left(\frac{10}{9}\right)\)
5. \(-\left(\frac{-8}{3}\right)+\left(\frac{8}{-11}\right)\)
6. \(-\left(\frac{5}{-6}\right)+\left(\frac{-12}{-7}\right)\)
7. \(-\left(\frac{11}{-7}\right)-\left(\frac{-14}{5}\right)\)
8. \(+\left(\frac{5}{11}\right)-\left(\frac{-3}{8}\right)\)
9. \(+\left(\frac{11}{-8}\right)-\left(\frac{15}{4}\right)\)
10. \(+\left(\frac{5}{3}\right)-\left(\frac{6}{11}\right)\)
11. \(+\left(\frac{8}{3}\right)+\left(\frac{-3}{-14}\right)\)
12. \(-\left(\frac{-7}{8}\right)-\left(\frac{-7}{-4}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{13}{-8}\right)-\left(\frac{-3}{-5}\right)\\= \frac{13}{8}-\frac{3}{5}\\=\frac{65}{40}-\frac{24}{40}\\=\frac{65-24}{40}\\=\frac{41}{40}\)
2. \(+\left(\frac{-11}{12}\right)+\left(\frac{3}{7}\right)\\= \frac{-11}{12}+\frac{3}{7}\\=\frac{-77}{84}+\frac{36}{84}\\=\frac{-77+36}{84}\\=\frac{-41}{84}\)
3. \(-\left(\frac{10}{9}\right)-\left(\frac{15}{13}\right)\\= \frac{-10}{9}-\frac{15}{13}\\=\frac{-130}{117}-\frac{135}{117}\\=\frac{-130-135}{117}\\=\frac{-265}{117}\)
4. \(+\left(\frac{2}{-3}\right)+\left(\frac{10}{9}\right)\\= \frac{-2}{3}+\frac{10}{9}\\=\frac{-6}{9}+\frac{10}{9}\\=\frac{-6+10}{9}\\=\frac{4}{9}\)
5. \(-\left(\frac{-8}{3}\right)+\left(\frac{8}{-11}\right)\\= \frac{8}{3}-\frac{8}{11}\\=\frac{88}{33}-\frac{24}{33}\\=\frac{88-24}{33}\\=\frac{64}{33}\)
6. \(-\left(\frac{5}{-6}\right)+\left(\frac{-12}{-7}\right)\\= \frac{5}{6}+\frac{12}{7}\\=\frac{35}{42}+\frac{72}{42}\\=\frac{35+72}{42}\\=\frac{107}{42}\)
7. \(-\left(\frac{11}{-7}\right)-\left(\frac{-14}{5}\right)\\= \frac{11}{7}+\frac{14}{5}\\=\frac{55}{35}+\frac{98}{35}\\=\frac{55+98}{35}\\=\frac{153}{35}\)
8. \(+\left(\frac{5}{11}\right)-\left(\frac{-3}{8}\right)\\= \frac{5}{11}+\frac{3}{8}\\=\frac{40}{88}+\frac{33}{88}\\=\frac{40+33}{88}\\=\frac{73}{88}\)
9. \(+\left(\frac{11}{-8}\right)-\left(\frac{15}{4}\right)\\= \frac{-11}{8}-\frac{15}{4}\\=\frac{-11-15}{8}\\=\frac{-26}{8}\\=\frac{-13}{4}\)
10. \(+\left(\frac{5}{3}\right)-\left(\frac{6}{11}\right)\\= \frac{5}{3}-\frac{6}{11}\\=\frac{55}{33}-\frac{18}{33}\\=\frac{55-18}{33}\\=\frac{37}{33}\)
11. \(+\left(\frac{8}{3}\right)+\left(\frac{-3}{-14}\right)\\= \frac{8}{3}+\frac{3}{14}\\=\frac{112}{42}+\frac{9}{42}\\=\frac{112+9}{42}\\=\frac{121}{42}\)
12. \(-\left(\frac{-7}{8}\right)-\left(\frac{-7}{-4}\right)\\= \frac{7}{8}-\frac{7}{4}\\=\frac{7-7}{8}\\=\frac{0}{8}\\=\frac{0}{1}\)