Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{5}{-2}\right)-\left(\frac{-3}{-5}\right)\)
2. \(-\left(\frac{3}{11}\right)-\left(\frac{-3}{2}\right)\)
3. \(-\left(\frac{-10}{-11}\right)+\left(\frac{8}{5}\right)\)
4. \(+\left(\frac{-13}{-2}\right)+\left(\frac{11}{-2}\right)\)
5. \(+\left(\frac{12}{-5}\right)+\left(\frac{-15}{-13}\right)\)
6. \(-\left(\frac{-3}{10}\right)+\left(\frac{13}{-9}\right)\)
7. \(-\left(\frac{-2}{-3}\right)+\left(\frac{14}{-9}\right)\)
8. \(-\left(\frac{-12}{-5}\right)-\left(\frac{-6}{11}\right)\)
9. \(+\left(\frac{7}{-5}\right)-\left(\frac{8}{3}\right)\)
10. \(-\left(\frac{9}{-10}\right)-\left(\frac{2}{3}\right)\)
11. \(-\left(\frac{6}{-5}\right)+\left(\frac{-8}{-3}\right)\)
12. \(-\left(\frac{13}{11}\right)+\left(\frac{-13}{-10}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{5}{-2}\right)-\left(\frac{-3}{-5}\right)\\= \frac{-5}{2}-\frac{3}{5}\\=\frac{-25}{10}-\frac{6}{10}\\=\frac{-25-6}{10}\\=\frac{-31}{10}\)
2. \(-\left(\frac{3}{11}\right)-\left(\frac{-3}{2}\right)\\= \frac{-3}{11}+\frac{3}{2}\\=\frac{-6}{22}+\frac{33}{22}\\=\frac{-6+33}{22}\\=\frac{27}{22}\)
3. \(-\left(\frac{-10}{-11}\right)+\left(\frac{8}{5}\right)\\= \frac{-10}{11}+\frac{8}{5}\\=\frac{-50}{55}+\frac{88}{55}\\=\frac{-50+88}{55}\\=\frac{38}{55}\)
4. \(+\left(\frac{-13}{-2}\right)+\left(\frac{11}{-2}\right)\\= \frac{13}{2}-\frac{11}{2}\\=\frac{13-11}{2}\\=\frac{2}{2}\\=\frac{1}{1}\)
5. \(+\left(\frac{12}{-5}\right)+\left(\frac{-15}{-13}\right)\\= \frac{-12}{5}+\frac{15}{13}\\=\frac{-156}{65}+\frac{75}{65}\\=\frac{-156+75}{65}\\=\frac{-81}{65}\)
6. \(-\left(\frac{-3}{10}\right)+\left(\frac{13}{-9}\right)\\= \frac{3}{10}-\frac{13}{9}\\=\frac{27}{90}-\frac{130}{90}\\=\frac{27-130}{90}\\=\frac{-103}{90}\)
7. \(-\left(\frac{-2}{-3}\right)+\left(\frac{14}{-9}\right)\\= \frac{-2}{3}-\frac{14}{9}\\=\frac{-6}{9}-\frac{14}{9}\\=\frac{-6-14}{9}\\=\frac{-20}{9}\)
8. \(-\left(\frac{-12}{-5}\right)-\left(\frac{-6}{11}\right)\\= \frac{-12}{5}+\frac{6}{11}\\=\frac{-132}{55}+\frac{30}{55}\\=\frac{-132+30}{55}\\=\frac{-102}{55}\)
9. \(+\left(\frac{7}{-5}\right)-\left(\frac{8}{3}\right)\\= \frac{-7}{5}-\frac{8}{3}\\=\frac{-21}{15}-\frac{40}{15}\\=\frac{-21-40}{15}\\=\frac{-61}{15}\)
10. \(-\left(\frac{9}{-10}\right)-\left(\frac{2}{3}\right)\\= \frac{9}{10}-\frac{2}{3}\\=\frac{27}{30}-\frac{20}{30}\\=\frac{27-20}{30}\\=\frac{7}{30}\)
11. \(-\left(\frac{6}{-5}\right)+\left(\frac{-8}{-3}\right)\\= \frac{6}{5}+\frac{8}{3}\\=\frac{18}{15}+\frac{40}{15}\\=\frac{18+40}{15}\\=\frac{58}{15}\)
12. \(-\left(\frac{13}{11}\right)+\left(\frac{-13}{-10}\right)\\= \frac{-13}{11}+\frac{13}{10}\\=\frac{-130}{110}+\frac{143}{110}\\=\frac{-130+143}{110}\\=\frac{13}{110}\)