Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-4}{-13}\right)+\left(\frac{-11}{10}\right)\)
2. \(+\left(\frac{5}{13}\right)-\left(\frac{-13}{-9}\right)\)
3. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-4}{9}\right)\)
4. \(+\left(\frac{-11}{6}\right)+\left(\frac{13}{-8}\right)\)
5. \(+\left(\frac{-5}{-11}\right)+\left(\frac{6}{-5}\right)\)
6. \(-\left(\frac{-7}{8}\right)-\left(\frac{9}{10}\right)\)
7. \(-\left(\frac{5}{4}\right)+\left(\frac{-10}{-7}\right)\)
8. \(+\left(\frac{14}{5}\right)-\left(\frac{6}{-13}\right)\)
9. \(-\left(\frac{-14}{-9}\right)+\left(\frac{15}{11}\right)\)
10. \(-\left(\frac{15}{-14}\right)+\left(\frac{8}{-13}\right)\)
11. \(-\left(\frac{-7}{9}\right)+\left(\frac{-5}{3}\right)\)
12. \(-\left(\frac{-11}{-10}\right)-\left(\frac{-4}{7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-4}{-13}\right)+\left(\frac{-11}{10}\right)\\= \frac{4}{13}-\frac{11}{10}\\=\frac{40}{130}-\frac{143}{130}\\=\frac{40-143}{130}\\=\frac{-103}{130}\)
2. \(+\left(\frac{5}{13}\right)-\left(\frac{-13}{-9}\right)\\= \frac{5}{13}-\frac{13}{9}\\=\frac{45}{117}-\frac{169}{117}\\=\frac{45-169}{117}\\=\frac{-124}{117}\)
3. \(+\left(\frac{-4}{-3}\right)-\left(\frac{-4}{9}\right)\\= \frac{4}{3}+\frac{4}{9}\\=\frac{12}{9}+\frac{4}{9}\\=\frac{12+4}{9}\\=\frac{16}{9}\)
4. \(+\left(\frac{-11}{6}\right)+\left(\frac{13}{-8}\right)\\= \frac{-11}{6}-\frac{13}{8}\\=\frac{-44}{24}-\frac{39}{24}\\=\frac{-44-39}{24}\\=\frac{-83}{24}\)
5. \(+\left(\frac{-5}{-11}\right)+\left(\frac{6}{-5}\right)\\= \frac{5}{11}-\frac{6}{5}\\=\frac{25}{55}-\frac{66}{55}\\=\frac{25-66}{55}\\=\frac{-41}{55}\)
6. \(-\left(\frac{-7}{8}\right)-\left(\frac{9}{10}\right)\\= \frac{7}{8}-\frac{9}{10}\\=\frac{35}{40}-\frac{36}{40}\\=\frac{35-36}{40}\\=\frac{-1}{40}\)
7. \(-\left(\frac{5}{4}\right)+\left(\frac{-10}{-7}\right)\\= \frac{-5}{4}+\frac{10}{7}\\=\frac{-35}{28}+\frac{40}{28}\\=\frac{-35+40}{28}\\=\frac{5}{28}\)
8. \(+\left(\frac{14}{5}\right)-\left(\frac{6}{-13}\right)\\= \frac{14}{5}+\frac{6}{13}\\=\frac{182}{65}+\frac{30}{65}\\=\frac{182+30}{65}\\=\frac{212}{65}\)
9. \(-\left(\frac{-14}{-9}\right)+\left(\frac{15}{11}\right)\\= \frac{-14}{9}+\frac{15}{11}\\=\frac{-154}{99}+\frac{135}{99}\\=\frac{-154+135}{99}\\=\frac{-19}{99}\)
10. \(-\left(\frac{15}{-14}\right)+\left(\frac{8}{-13}\right)\\= \frac{15}{14}-\frac{8}{13}\\=\frac{195}{182}-\frac{112}{182}\\=\frac{195-112}{182}\\=\frac{83}{182}\)
11. \(-\left(\frac{-7}{9}\right)+\left(\frac{-5}{3}\right)\\= \frac{7}{9}-\frac{5}{3}\\=\frac{7-5}{9}\\=\frac{2}{9}\)
12. \(-\left(\frac{-11}{-10}\right)-\left(\frac{-4}{7}\right)\\= \frac{-11}{10}+\frac{4}{7}\\=\frac{-77}{70}+\frac{40}{70}\\=\frac{-77+40}{70}\\=\frac{-37}{70}\)