Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-13}{-11}\right)+\left(\frac{15}{-4}\right)\)
2. \(-\left(\frac{-11}{12}\right)-\left(\frac{10}{-7}\right)\)
3. \(-\left(\frac{-2}{-3}\right)+\left(\frac{-14}{3}\right)\)
4. \(+\left(\frac{-12}{5}\right)-\left(\frac{2}{7}\right)\)
5. \(-\left(\frac{-5}{7}\right)+\left(\frac{-8}{3}\right)\)
6. \(+\left(\frac{5}{6}\right)+\left(\frac{5}{6}\right)\)
7. \(+\left(\frac{-2}{5}\right)-\left(\frac{9}{-2}\right)\)
8. \(-\left(\frac{-5}{-6}\right)+\left(\frac{-6}{5}\right)\)
9. \(+\left(\frac{11}{4}\right)-\left(\frac{5}{3}\right)\)
10. \(+\left(\frac{-6}{-7}\right)+\left(\frac{4}{-3}\right)\)
11. \(-\left(\frac{10}{-13}\right)+\left(\frac{-11}{14}\right)\)
12. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-8}{3}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-13}{-11}\right)+\left(\frac{15}{-4}\right)\\= \frac{13}{11}-\frac{15}{4}\\=\frac{52}{44}-\frac{165}{44}\\=\frac{52-165}{44}\\=\frac{-113}{44}\)
2. \(-\left(\frac{-11}{12}\right)-\left(\frac{10}{-7}\right)\\= \frac{11}{12}+\frac{10}{7}\\=\frac{77}{84}+\frac{120}{84}\\=\frac{77+120}{84}\\=\frac{197}{84}\)
3. \(-\left(\frac{-2}{-3}\right)+\left(\frac{-14}{3}\right)\\= \frac{-2}{3}-\frac{14}{3}\\=\frac{-2-14}{3}\\=\frac{-16}{3}\)
4. \(+\left(\frac{-12}{5}\right)-\left(\frac{2}{7}\right)\\= \frac{-12}{5}-\frac{2}{7}\\=\frac{-84}{35}-\frac{10}{35}\\=\frac{-84-10}{35}\\=\frac{-94}{35}\)
5. \(-\left(\frac{-5}{7}\right)+\left(\frac{-8}{3}\right)\\= \frac{5}{7}-\frac{8}{3}\\=\frac{15}{21}-\frac{56}{21}\\=\frac{15-56}{21}\\=\frac{-41}{21}\)
6. \(+\left(\frac{5}{6}\right)+\left(\frac{5}{6}\right)\\= \frac{5}{6}+\frac{5}{6}\\=\frac{5+5}{6}\\=\frac{10}{6}\\=\frac{5}{3}\)
7. \(+\left(\frac{-2}{5}\right)-\left(\frac{9}{-2}\right)\\= \frac{-2}{5}+\frac{9}{2}\\=\frac{-4}{10}+\frac{45}{10}\\=\frac{-4+45}{10}\\=\frac{41}{10}\)
8. \(-\left(\frac{-5}{-6}\right)+\left(\frac{-6}{5}\right)\\= \frac{-5}{6}-\frac{6}{5}\\=\frac{-25}{30}-\frac{36}{30}\\=\frac{-25-36}{30}\\=\frac{-61}{30}\)
9. \(+\left(\frac{11}{4}\right)-\left(\frac{5}{3}\right)\\= \frac{11}{4}-\frac{5}{3}\\=\frac{33}{12}-\frac{20}{12}\\=\frac{33-20}{12}\\=\frac{13}{12}\)
10. \(+\left(\frac{-6}{-7}\right)+\left(\frac{4}{-3}\right)\\= \frac{6}{7}-\frac{4}{3}\\=\frac{18}{21}-\frac{28}{21}\\=\frac{18-28}{21}\\=\frac{-10}{21}\)
11. \(-\left(\frac{10}{-13}\right)+\left(\frac{-11}{14}\right)\\= \frac{10}{13}-\frac{11}{14}\\=\frac{140}{182}-\frac{143}{182}\\=\frac{140-143}{182}\\=\frac{-3}{182}\)
12. \(-\left(\frac{-6}{-11}\right)-\left(\frac{-8}{3}\right)\\= \frac{-6}{11}+\frac{8}{3}\\=\frac{-18}{33}+\frac{88}{33}\\=\frac{-18+88}{33}\\=\frac{70}{33}\)