Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{8}{-7}\right)-\left(\frac{-14}{5}\right)\)
2. \(-\left(\frac{3}{-5}\right)+\left(\frac{-10}{-11}\right)\)
3. \(+\left(\frac{-9}{-14}\right)-\left(\frac{3}{7}\right)\)
4. \(-\left(\frac{-7}{-11}\right)+\left(\frac{5}{-6}\right)\)
5. \(+\left(\frac{-15}{-4}\right)-\left(\frac{10}{-9}\right)\)
6. \(-\left(\frac{3}{10}\right)-\left(\frac{5}{-12}\right)\)
7. \(+\left(\frac{8}{-11}\right)+\left(\frac{-6}{5}\right)\)
8. \(+\left(\frac{14}{13}\right)-\left(\frac{-5}{-11}\right)\)
9. \(-\left(\frac{-5}{-12}\right)+\left(\frac{-14}{-9}\right)\)
10. \(+\left(\frac{-12}{13}\right)-\left(\frac{-12}{11}\right)\)
11. \(-\left(\frac{-5}{-12}\right)-\left(\frac{5}{14}\right)\)
12. \(-\left(\frac{-11}{-8}\right)+\left(\frac{7}{-3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{8}{-7}\right)-\left(\frac{-14}{5}\right)\\= \frac{8}{7}+\frac{14}{5}\\=\frac{40}{35}+\frac{98}{35}\\=\frac{40+98}{35}\\=\frac{138}{35}\)
2. \(-\left(\frac{3}{-5}\right)+\left(\frac{-10}{-11}\right)\\= \frac{3}{5}+\frac{10}{11}\\=\frac{33}{55}+\frac{50}{55}\\=\frac{33+50}{55}\\=\frac{83}{55}\)
3. \(+\left(\frac{-9}{-14}\right)-\left(\frac{3}{7}\right)\\= \frac{9}{14}-\frac{3}{7}\\=\frac{9-3}{14}\\=\frac{6}{14}\\=\frac{3}{7}\)
4. \(-\left(\frac{-7}{-11}\right)+\left(\frac{5}{-6}\right)\\= \frac{-7}{11}-\frac{5}{6}\\=\frac{-42}{66}-\frac{55}{66}\\=\frac{-42-55}{66}\\=\frac{-97}{66}\)
5. \(+\left(\frac{-15}{-4}\right)-\left(\frac{10}{-9}\right)\\= \frac{15}{4}+\frac{10}{9}\\=\frac{135}{36}+\frac{40}{36}\\=\frac{135+40}{36}\\=\frac{175}{36}\)
6. \(-\left(\frac{3}{10}\right)-\left(\frac{5}{-12}\right)\\= \frac{-3}{10}+\frac{5}{12}\\=\frac{-18}{60}+\frac{25}{60}\\=\frac{-18+25}{60}\\=\frac{7}{60}\)
7. \(+\left(\frac{8}{-11}\right)+\left(\frac{-6}{5}\right)\\= \frac{-8}{11}-\frac{6}{5}\\=\frac{-40}{55}-\frac{66}{55}\\=\frac{-40-66}{55}\\=\frac{-106}{55}\)
8. \(+\left(\frac{14}{13}\right)-\left(\frac{-5}{-11}\right)\\= \frac{14}{13}-\frac{5}{11}\\=\frac{154}{143}-\frac{65}{143}\\=\frac{154-65}{143}\\=\frac{89}{143}\)
9. \(-\left(\frac{-5}{-12}\right)+\left(\frac{-14}{-9}\right)\\= \frac{-5}{12}+\frac{14}{9}\\=\frac{-15}{36}+\frac{56}{36}\\=\frac{-15+56}{36}\\=\frac{41}{36}\)
10. \(+\left(\frac{-12}{13}\right)-\left(\frac{-12}{11}\right)\\= \frac{-12}{13}+\frac{12}{11}\\=\frac{-132}{143}+\frac{156}{143}\\=\frac{-132+156}{143}\\=\frac{24}{143}\)
11. \(-\left(\frac{-5}{-12}\right)-\left(\frac{5}{14}\right)\\= \frac{-5}{12}-\frac{5}{14}\\=\frac{-35}{84}-\frac{30}{84}\\=\frac{-35-30}{84}\\=\frac{-65}{84}\)
12. \(-\left(\frac{-11}{-8}\right)+\left(\frac{7}{-3}\right)\\= \frac{-11}{8}-\frac{7}{3}\\=\frac{-33}{24}-\frac{56}{24}\\=\frac{-33-56}{24}\\=\frac{-89}{24}\)