Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{14}{-11}\right)-\left(\frac{12}{-5}\right)\)
2. \(-\left(\frac{10}{-11}\right)-\left(\frac{-8}{3}\right)\)
3. \(+\left(\frac{11}{10}\right)-\left(\frac{-7}{2}\right)\)
4. \(-\left(\frac{6}{-7}\right)+\left(\frac{-10}{-13}\right)\)
5. \(-\left(\frac{3}{-11}\right)+\left(\frac{-12}{7}\right)\)
6. \(-\left(\frac{-11}{7}\right)+\left(\frac{2}{9}\right)\)
7. \(-\left(\frac{10}{-9}\right)-\left(\frac{6}{-13}\right)\)
8. \(-\left(\frac{-6}{-5}\right)+\left(\frac{-9}{10}\right)\)
9. \(+\left(\frac{7}{-10}\right)+\left(\frac{11}{-5}\right)\)
10. \(-\left(\frac{-2}{3}\right)-\left(\frac{-9}{-4}\right)\)
11. \(+\left(\frac{-5}{-2}\right)-\left(\frac{-9}{-7}\right)\)
12. \(-\left(\frac{-10}{-7}\right)-\left(\frac{7}{-11}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{14}{-11}\right)-\left(\frac{12}{-5}\right)\\= \frac{-14}{11}+\frac{12}{5}\\=\frac{-70}{55}+\frac{132}{55}\\=\frac{-70+132}{55}\\=\frac{62}{55}\)
2. \(-\left(\frac{10}{-11}\right)-\left(\frac{-8}{3}\right)\\= \frac{10}{11}+\frac{8}{3}\\=\frac{30}{33}+\frac{88}{33}\\=\frac{30+88}{33}\\=\frac{118}{33}\)
3. \(+\left(\frac{11}{10}\right)-\left(\frac{-7}{2}\right)\\= \frac{11}{10}+\frac{7}{2}\\=\frac{11+7}{10}\\=\frac{18}{10}\\=\frac{9}{5}\)
4. \(-\left(\frac{6}{-7}\right)+\left(\frac{-10}{-13}\right)\\= \frac{6}{7}+\frac{10}{13}\\=\frac{78}{91}+\frac{70}{91}\\=\frac{78+70}{91}\\=\frac{148}{91}\)
5. \(-\left(\frac{3}{-11}\right)+\left(\frac{-12}{7}\right)\\= \frac{3}{11}-\frac{12}{7}\\=\frac{21}{77}-\frac{132}{77}\\=\frac{21-132}{77}\\=\frac{-111}{77}\)
6. \(-\left(\frac{-11}{7}\right)+\left(\frac{2}{9}\right)\\= \frac{11}{7}+\frac{2}{9}\\=\frac{99}{63}+\frac{14}{63}\\=\frac{99+14}{63}\\=\frac{113}{63}\)
7. \(-\left(\frac{10}{-9}\right)-\left(\frac{6}{-13}\right)\\= \frac{10}{9}+\frac{6}{13}\\=\frac{130}{117}+\frac{54}{117}\\=\frac{130+54}{117}\\=\frac{184}{117}\)
8. \(-\left(\frac{-6}{-5}\right)+\left(\frac{-9}{10}\right)\\= \frac{-6}{5}-\frac{9}{10}\\=\frac{-12}{10}-\frac{9}{10}\\=\frac{-12-9}{10}\\=\frac{-21}{10}\)
9. \(+\left(\frac{7}{-10}\right)+\left(\frac{11}{-5}\right)\\= \frac{-7}{10}-\frac{11}{5}\\=\frac{-7-11}{10}\\=\frac{-18}{10}\\=\frac{-9}{5}\)
10. \(-\left(\frac{-2}{3}\right)-\left(\frac{-9}{-4}\right)\\= \frac{2}{3}-\frac{9}{4}\\=\frac{8}{12}-\frac{27}{12}\\=\frac{8-27}{12}\\=\frac{-19}{12}\)
11. \(+\left(\frac{-5}{-2}\right)-\left(\frac{-9}{-7}\right)\\= \frac{5}{2}-\frac{9}{7}\\=\frac{35}{14}-\frac{18}{14}\\=\frac{35-18}{14}\\=\frac{17}{14}\)
12. \(-\left(\frac{-10}{-7}\right)-\left(\frac{7}{-11}\right)\\= \frac{-10}{7}+\frac{7}{11}\\=\frac{-110}{77}+\frac{49}{77}\\=\frac{-110+49}{77}\\=\frac{-61}{77}\)