Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-13}{6}\right)+\left(\frac{7}{3}\right)\)
2. \(+\left(\frac{12}{-11}\right)-\left(\frac{9}{-4}\right)\)
3. \(-\left(\frac{-4}{7}\right)-\left(\frac{-3}{10}\right)\)
4. \(+\left(\frac{8}{-3}\right)+\left(\frac{-8}{13}\right)\)
5. \(+\left(\frac{-9}{-8}\right)+\left(\frac{-5}{8}\right)\)
6. \(+\left(\frac{-5}{-2}\right)-\left(\frac{6}{-5}\right)\)
7. \(-\left(\frac{7}{-2}\right)-\left(\frac{-13}{-6}\right)\)
8. \(+\left(\frac{-4}{7}\right)-\left(\frac{9}{11}\right)\)
9. \(+\left(\frac{11}{-12}\right)-\left(\frac{13}{-6}\right)\)
10. \(+\left(\frac{8}{11}\right)-\left(\frac{5}{-4}\right)\)
11. \(+\left(\frac{15}{-7}\right)+\left(\frac{11}{3}\right)\)
12. \(+\left(\frac{-2}{-5}\right)-\left(\frac{-3}{4}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-13}{6}\right)+\left(\frac{7}{3}\right)\\= \frac{-13}{6}+\frac{7}{3}\\=\frac{-13+7}{6}\\=\frac{-6}{6}\\=\frac{-1}{1}\)
2. \(+\left(\frac{12}{-11}\right)-\left(\frac{9}{-4}\right)\\= \frac{-12}{11}+\frac{9}{4}\\=\frac{-48}{44}+\frac{99}{44}\\=\frac{-48+99}{44}\\=\frac{51}{44}\)
3. \(-\left(\frac{-4}{7}\right)-\left(\frac{-3}{10}\right)\\= \frac{4}{7}+\frac{3}{10}\\=\frac{40}{70}+\frac{21}{70}\\=\frac{40+21}{70}\\=\frac{61}{70}\)
4. \(+\left(\frac{8}{-3}\right)+\left(\frac{-8}{13}\right)\\= \frac{-8}{3}-\frac{8}{13}\\=\frac{-104}{39}-\frac{24}{39}\\=\frac{-104-24}{39}\\=\frac{-128}{39}\)
5. \(+\left(\frac{-9}{-8}\right)+\left(\frac{-5}{8}\right)\\= \frac{9}{8}-\frac{5}{8}\\=\frac{9-5}{8}\\=\frac{4}{8}\\=\frac{1}{2}\)
6. \(+\left(\frac{-5}{-2}\right)-\left(\frac{6}{-5}\right)\\= \frac{5}{2}+\frac{6}{5}\\=\frac{25}{10}+\frac{12}{10}\\=\frac{25+12}{10}\\=\frac{37}{10}\)
7. \(-\left(\frac{7}{-2}\right)-\left(\frac{-13}{-6}\right)\\= \frac{7}{2}-\frac{13}{6}\\=\frac{21}{6}-\frac{13}{6}\\=\frac{21-13}{6}\\=\frac{8}{6}\\=\frac{4}{3}\)
8. \(+\left(\frac{-4}{7}\right)-\left(\frac{9}{11}\right)\\= \frac{-4}{7}-\frac{9}{11}\\=\frac{-44}{77}-\frac{63}{77}\\=\frac{-44-63}{77}\\=\frac{-107}{77}\)
9. \(+\left(\frac{11}{-12}\right)-\left(\frac{13}{-6}\right)\\= \frac{-11}{12}+\frac{13}{6}\\=\frac{-11+13}{12}\\=\frac{2}{12}\\=\frac{1}{6}\)
10. \(+\left(\frac{8}{11}\right)-\left(\frac{5}{-4}\right)\\= \frac{8}{11}+\frac{5}{4}\\=\frac{32}{44}+\frac{55}{44}\\=\frac{32+55}{44}\\=\frac{87}{44}\)
11. \(+\left(\frac{15}{-7}\right)+\left(\frac{11}{3}\right)\\= \frac{-15}{7}+\frac{11}{3}\\=\frac{-45}{21}+\frac{77}{21}\\=\frac{-45+77}{21}\\=\frac{32}{21}\)
12. \(+\left(\frac{-2}{-5}\right)-\left(\frac{-3}{4}\right)\\= \frac{2}{5}+\frac{3}{4}\\=\frac{8}{20}+\frac{15}{20}\\=\frac{8+15}{20}\\=\frac{23}{20}\)