Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-8}{11}\right)-\left(\frac{9}{14}\right)\)
2. \(+\left(\frac{-14}{5}\right)+\left(\frac{13}{-7}\right)\)
3. \(-\left(\frac{10}{-7}\right)+\left(\frac{-10}{-3}\right)\)
4. \(+\left(\frac{-12}{11}\right)-\left(\frac{4}{11}\right)\)
5. \(-\left(\frac{-11}{12}\right)-\left(\frac{13}{11}\right)\)
6. \(+\left(\frac{2}{-7}\right)+\left(\frac{-2}{-7}\right)\)
7. \(-\left(\frac{-13}{-9}\right)+\left(\frac{-12}{-11}\right)\)
8. \(+\left(\frac{-12}{-7}\right)+\left(\frac{2}{7}\right)\)
9. \(-\left(\frac{13}{-8}\right)-\left(\frac{5}{13}\right)\)
10. \(+\left(\frac{3}{-7}\right)-\left(\frac{2}{13}\right)\)
11. \(+\left(\frac{-13}{10}\right)-\left(\frac{-8}{-11}\right)\)
12. \(+\left(\frac{-8}{-5}\right)+\left(\frac{-7}{6}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{-8}{11}\right)-\left(\frac{9}{14}\right)\\= \frac{-8}{11}-\frac{9}{14}\\=\frac{-112}{154}-\frac{99}{154}\\=\frac{-112-99}{154}\\=\frac{-211}{154}\)
2. \(+\left(\frac{-14}{5}\right)+\left(\frac{13}{-7}\right)\\= \frac{-14}{5}-\frac{13}{7}\\=\frac{-98}{35}-\frac{65}{35}\\=\frac{-98-65}{35}\\=\frac{-163}{35}\)
3. \(-\left(\frac{10}{-7}\right)+\left(\frac{-10}{-3}\right)\\= \frac{10}{7}+\frac{10}{3}\\=\frac{30}{21}+\frac{70}{21}\\=\frac{30+70}{21}\\=\frac{100}{21}\)
4. \(+\left(\frac{-12}{11}\right)-\left(\frac{4}{11}\right)\\= \frac{-12}{11}-\frac{4}{11}\\=\frac{-12-4}{11}\\=\frac{-16}{11}\)
5. \(-\left(\frac{-11}{12}\right)-\left(\frac{13}{11}\right)\\= \frac{11}{12}-\frac{13}{11}\\=\frac{121}{132}-\frac{156}{132}\\=\frac{121-156}{132}\\=\frac{-35}{132}\)
6. \(+\left(\frac{2}{-7}\right)+\left(\frac{-2}{-7}\right)\\= \frac{-2}{7}+\frac{2}{7}\\=\frac{-2+2}{7}\\=\frac{0}{7}\\=\frac{0}{1}\)
7. \(-\left(\frac{-13}{-9}\right)+\left(\frac{-12}{-11}\right)\\= \frac{-13}{9}+\frac{12}{11}\\=\frac{-143}{99}+\frac{108}{99}\\=\frac{-143+108}{99}\\=\frac{-35}{99}\)
8. \(+\left(\frac{-12}{-7}\right)+\left(\frac{2}{7}\right)\\= \frac{12}{7}+\frac{2}{7}\\=\frac{12+2}{7}\\=\frac{14}{7}\\=\frac{2}{1}\)
9. \(-\left(\frac{13}{-8}\right)-\left(\frac{5}{13}\right)\\= \frac{13}{8}-\frac{5}{13}\\=\frac{169}{104}-\frac{40}{104}\\=\frac{169-40}{104}\\=\frac{129}{104}\)
10. \(+\left(\frac{3}{-7}\right)-\left(\frac{2}{13}\right)\\= \frac{-3}{7}-\frac{2}{13}\\=\frac{-39}{91}-\frac{14}{91}\\=\frac{-39-14}{91}\\=\frac{-53}{91}\)
11. \(+\left(\frac{-13}{10}\right)-\left(\frac{-8}{-11}\right)\\= \frac{-13}{10}-\frac{8}{11}\\=\frac{-143}{110}-\frac{80}{110}\\=\frac{-143-80}{110}\\=\frac{-223}{110}\)
12. \(+\left(\frac{-8}{-5}\right)+\left(\frac{-7}{6}\right)\\= \frac{8}{5}-\frac{7}{6}\\=\frac{48}{30}-\frac{35}{30}\\=\frac{48-35}{30}\\=\frac{13}{30}\)