Breuken haakjesregel (reeks 1)

Bereken

\(+\left(\frac{-15}{13}\right)+\left(\frac{6}{-5}\right)\)

\(+\left(\frac{-15}{13}\right)+\left(\frac{6}{-5}\right)\\= \frac{-15}{13}-\frac{6}{5}\\=\frac{-75}{65}-\frac{78}{65}\\=\frac{-75-78}{65}\\=\frac{-153}{65}\)