Breuken haakjesregel (reeks 1)

Bereken

\(-\left(\frac{-10}{3}\right)+\left(\frac{-12}{-11}\right)\)

\(-\left(\frac{-10}{3}\right)+\left(\frac{-12}{-11}\right)\\= \frac{10}{3}+\frac{12}{11}\\=\frac{110}{33}+\frac{36}{33}\\=\frac{110+36}{33}\\=\frac{146}{33}\)