Breuken haakjesregel (reeks 1)

Bereken

\(+\left(\frac{-10}{7}\right)+\left(\frac{15}{-4}\right)\)

\(+\left(\frac{-10}{7}\right)+\left(\frac{15}{-4}\right)\\= \frac{-10}{7}-\frac{15}{4}\\=\frac{-40}{28}-\frac{105}{28}\\=\frac{-40-105}{28}\\=\frac{-145}{28}\)