Breuken haakjesregel (reeks 1)

Bereken

\(+\left(\frac{-13}{-2}\right)+\left(\frac{7}{-3}\right)\)

\(+\left(\frac{-13}{-2}\right)+\left(\frac{7}{-3}\right)\\= \frac{13}{2}-\frac{7}{3}\\=\frac{39}{6}-\frac{14}{6}\\=\frac{39-14}{6}\\=\frac{25}{6}\)