Breuken haakjesregel (reeks 1)

Bereken

\(+\left(\frac{6}{-13}\right)+\left(\frac{5}{9}\right)\)

\(+\left(\frac{6}{-13}\right)+\left(\frac{5}{9}\right)\\= \frac{-6}{13}+\frac{5}{9}\\=\frac{-54}{117}+\frac{65}{117}\\=\frac{-54+65}{117}\\=\frac{11}{117}\)