Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-10}{-7}\right) +\left(\frac{8}{6}\right) -\left(\frac{6}{11}\right)\)
2. \(+\left(\frac{10}{7}\right) -\left(\frac{6}{4}\right) -\left(\frac{-8}{12}\right)\)
3. \(+\left(\frac{-7}{5}\right) -\left(\frac{8}{6}\right) +\left(\frac{11}{11}\right)\)
4. \(-\left(\frac{-9}{4}\right) -\left(\frac{6}{6}\right) +\left(\frac{9}{-2}\right)\)
5. \(-\left(\frac{4}{-5}\right) -\left(\frac{7}{7}\right) -\left(\frac{-3}{-3}\right)\)
6. \(+\left(\frac{-10}{-9}\right) +\left(\frac{2}{6}\right) +\left(\frac{-3}{-11}\right)\)
7. \(-\left(\frac{-9}{7}\right) +\left(\frac{7}{-10}\right) -\left(\frac{-7}{-10}\right)\)
8. \(-\left(\frac{-2}{-3}\right) -\left(\frac{2}{3}\right) +\left(\frac{-11}{-3}\right)\)
9. \(-\left(\frac{6}{5}\right) -\left(\frac{-7}{-2}\right) -\left(\frac{4}{-4}\right)\)
10. \(-\left(\frac{8}{-3}\right) +\left(\frac{5}{4}\right) +\left(\frac{-5}{-9}\right)\)
11. \(-\left(\frac{5}{9}\right) -\left(\frac{3}{5}\right) -\left(\frac{8}{-3}\right)\)
12. \(+\left(\frac{10}{-3}\right) -\left(\frac{-2}{5}\right) -\left(\frac{-3}{-9}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-10}{-7}\right) +\left(\frac{8}{6}\right) -\left(\frac{6}{11}\right)\\= \frac{10}{7}+ \frac{8}{6}-\frac{6}{11}\\=\frac{10}{7}+\frac{4}{3}-\frac{6}{11}\\=\frac{330}{231}+\frac{308}{231}-\frac{126}{231}\\=\frac{330+308-126}{231}\\=\frac{512}{231}\)
2. \(+\left(\frac{10}{7}\right) -\left(\frac{6}{4}\right) -\left(\frac{-8}{12}\right)\\= \frac{10}{7}- \frac{6}{4}+\frac{8}{12}\\=\frac{10}{7}-\frac{3}{2}+\frac{2}{3}\\=\frac{60}{42}-\frac{63}{42}+\frac{28}{42}\\=\frac{60-63+28}{42}\\=\frac{25}{42}\)
3. \(+\left(\frac{-7}{5}\right) -\left(\frac{8}{6}\right) +\left(\frac{11}{11}\right)\\= \frac{-7}{5}- \frac{8}{6}+\frac{11}{11}\\=\frac{-7}{5}-\frac{4}{3}+\frac{1}{1}\\=\frac{-21}{15}-\frac{20}{15}+\frac{15}{15}\\=\frac{-21-20+15}{15}\\=\frac{-26}{15}\)
4. \(-\left(\frac{-9}{4}\right) -\left(\frac{6}{6}\right) +\left(\frac{9}{-2}\right)\\= \frac{9}{4}- \frac{6}{6}-\frac{9}{2}\\=\frac{9}{4}-\frac{1}{1}-\frac{9}{2}\\=\frac{9-1-9}{4}\\=\frac{-1}{4}\)
5. \(-\left(\frac{4}{-5}\right) -\left(\frac{7}{7}\right) -\left(\frac{-3}{-3}\right)\\= \frac{4}{5}- \frac{7}{7}-\frac{3}{3}\\=\frac{4}{5}-\frac{1}{1}-\frac{1}{1}\\=\frac{4-1-1}{5}\\=\frac{2}{5}\)
6. \(+\left(\frac{-10}{-9}\right) +\left(\frac{2}{6}\right) +\left(\frac{-3}{-11}\right)\\= \frac{10}{9}+ \frac{2}{6}+\frac{3}{11}\\=\frac{10}{9}+\frac{1}{3}+\frac{3}{11}\\=\frac{110}{99}+\frac{33}{99}+\frac{27}{99}\\=\frac{110+33+27}{99}\\=\frac{170}{99}\)
7. \(-\left(\frac{-9}{7}\right) +\left(\frac{7}{-10}\right) -\left(\frac{-7}{-10}\right)\\= \frac{9}{7}- \frac{7}{10}-\frac{7}{10}\\=\frac{90}{70}-\frac{49}{70}-\frac{49}{70}\\=\frac{90-49-49}{70}\\=\frac{-8}{70}\\=\frac{-4}{35}\)
8. \(-\left(\frac{-2}{-3}\right) -\left(\frac{2}{3}\right) +\left(\frac{-11}{-3}\right)\\= \frac{-2}{3}- \frac{2}{3}+\frac{11}{3}\\=\frac{-2-2+11}{3}\\=\frac{7}{3}\)
9. \(-\left(\frac{6}{5}\right) -\left(\frac{-7}{-2}\right) -\left(\frac{4}{-4}\right)\\= \frac{-6}{5}- \frac{7}{2}+\frac{4}{4}\\=\frac{-6}{5}-\frac{7}{2}+\frac{1}{1}\\=\frac{-12}{10}-\frac{35}{10}+\frac{10}{10}\\=\frac{-12-35+10}{10}\\=\frac{-37}{10}\)
10. \(-\left(\frac{8}{-3}\right) +\left(\frac{5}{4}\right) +\left(\frac{-5}{-9}\right)\\= \frac{8}{3}+ \frac{5}{4}+\frac{5}{9}\\=\frac{96}{36}+\frac{45}{36}+\frac{20}{36}\\=\frac{96+45+20}{36}\\=\frac{161}{36}\)
11. \(-\left(\frac{5}{9}\right) -\left(\frac{3}{5}\right) -\left(\frac{8}{-3}\right)\\= \frac{-5}{9}- \frac{3}{5}+\frac{8}{3}\\=\frac{-25}{45}-\frac{27}{45}+\frac{120}{45}\\=\frac{-25-27+120}{45}\\=\frac{68}{45}\)
12. \(+\left(\frac{10}{-3}\right) -\left(\frac{-2}{5}\right) -\left(\frac{-3}{-9}\right)\\= \frac{-10}{3}+ \frac{2}{5}-\frac{3}{9}\\=\frac{-10}{3}+\frac{2}{5}-\frac{1}{3}\\=\frac{-50}{15}+\frac{6}{15}-\frac{5}{15}\\=\frac{-50+6-5}{15}\\=\frac{-49}{15}\)