Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-8}{-3}\right) +\left(\frac{-9}{7}\right) -\left(\frac{-9}{6}\right)\)
2. \(-\left(\frac{-6}{-5}\right) -\left(\frac{2}{5}\right) +\left(\frac{4}{5}\right)\)
3. \(-\left(\frac{3}{-4}\right) +\left(\frac{4}{8}\right) +\left(\frac{-11}{-5}\right)\)
4. \(+\left(\frac{-6}{-5}\right) +\left(\frac{10}{9}\right) -\left(\frac{-7}{-5}\right)\)
5. \(-\left(\frac{-3}{4}\right) +\left(\frac{-5}{-5}\right) -\left(\frac{2}{-2}\right)\)
6. \(-\left(\frac{4}{-3}\right) -\left(\frac{-8}{-3}\right) -\left(\frac{11}{-8}\right)\)
7. \(-\left(\frac{-5}{-6}\right) -\left(\frac{-2}{5}\right) -\left(\frac{10}{-11}\right)\)
8. \(-\left(\frac{10}{-3}\right) -\left(\frac{-6}{-2}\right) -\left(\frac{6}{-5}\right)\)
9. \(+\left(\frac{5}{-3}\right) +\left(\frac{-3}{-3}\right) -\left(\frac{12}{-11}\right)\)
10. \(+\left(\frac{7}{-8}\right) -\left(\frac{-3}{5}\right) -\left(\frac{-5}{9}\right)\)
11. \(-\left(\frac{-6}{-5}\right) -\left(\frac{9}{10}\right) +\left(\frac{5}{-7}\right)\)
12. \(+\left(\frac{-4}{9}\right) +\left(\frac{-2}{7}\right) -\left(\frac{-11}{-8}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-8}{-3}\right) +\left(\frac{-9}{7}\right) -\left(\frac{-9}{6}\right)\\= \frac{-8}{3}- \frac{9}{7}+\frac{9}{6}\\=\frac{-8}{3}-\frac{9}{7}+\frac{3}{2}\\=\frac{-112}{42}-\frac{54}{42}+\frac{63}{42}\\=\frac{-112-54+63}{42}\\=\frac{-103}{42}\)
2. \(-\left(\frac{-6}{-5}\right) -\left(\frac{2}{5}\right) +\left(\frac{4}{5}\right)\\= \frac{-6}{5}- \frac{2}{5}+\frac{4}{5}\\=\frac{-6-2+4}{5}\\=\frac{-4}{5}\)
3. \(-\left(\frac{3}{-4}\right) +\left(\frac{4}{8}\right) +\left(\frac{-11}{-5}\right)\\= \frac{3}{4}+ \frac{4}{8}+\frac{11}{5}\\=\frac{3}{4}+\frac{1}{2}+\frac{11}{5}\\=\frac{15}{20}+\frac{10}{20}+\frac{44}{20}\\=\frac{15+10+44}{20}\\=\frac{69}{20}\)
4. \(+\left(\frac{-6}{-5}\right) +\left(\frac{10}{9}\right) -\left(\frac{-7}{-5}\right)\\= \frac{6}{5}+ \frac{10}{9}-\frac{7}{5}\\=\frac{54}{45}+\frac{50}{45}-\frac{63}{45}\\=\frac{54+50-63}{45}\\=\frac{41}{45}\)
5. \(-\left(\frac{-3}{4}\right) +\left(\frac{-5}{-5}\right) -\left(\frac{2}{-2}\right)\\= \frac{3}{4}+ \frac{5}{5}+\frac{2}{2}\\=\frac{3}{4}+\frac{1}{1}+\frac{1}{1}\\=\frac{3+1+1}{4}\\=\frac{5}{4}\)
6. \(-\left(\frac{4}{-3}\right) -\left(\frac{-8}{-3}\right) -\left(\frac{11}{-8}\right)\\= \frac{4}{3}- \frac{8}{3}+\frac{11}{8}\\=\frac{32}{24}-\frac{64}{24}+\frac{33}{24}\\=\frac{32-64+33}{24}\\=\frac{1}{24}\)
7. \(-\left(\frac{-5}{-6}\right) -\left(\frac{-2}{5}\right) -\left(\frac{10}{-11}\right)\\= \frac{-5}{6}+ \frac{2}{5}+\frac{10}{11}\\=\frac{-275}{330}+\frac{132}{330}+\frac{300}{330}\\=\frac{-275+132+300}{330}\\=\frac{157}{330}\)
8. \(-\left(\frac{10}{-3}\right) -\left(\frac{-6}{-2}\right) -\left(\frac{6}{-5}\right)\\= \frac{10}{3}- \frac{6}{2}+\frac{6}{5}\\=\frac{10}{3}-\frac{3}{1}+\frac{6}{5}\\=\frac{50}{15}-\frac{45}{15}+\frac{18}{15}\\=\frac{50-45+18}{15}\\=\frac{23}{15}\)
9. \(+\left(\frac{5}{-3}\right) +\left(\frac{-3}{-3}\right) -\left(\frac{12}{-11}\right)\\= \frac{-5}{3}+ \frac{3}{3}+\frac{12}{11}\\=\frac{-5}{3}+\frac{1}{1}+\frac{12}{11}\\=\frac{-55}{33}+\frac{33}{33}+\frac{36}{33}\\=\frac{-55+33+36}{33}\\=\frac{14}{33}\)
10. \(+\left(\frac{7}{-8}\right) -\left(\frac{-3}{5}\right) -\left(\frac{-5}{9}\right)\\= \frac{-7}{8}+ \frac{3}{5}+\frac{5}{9}\\=\frac{-315}{360}+\frac{216}{360}+\frac{200}{360}\\=\frac{-315+216+200}{360}\\=\frac{101}{360}\)
11. \(-\left(\frac{-6}{-5}\right) -\left(\frac{9}{10}\right) +\left(\frac{5}{-7}\right)\\= \frac{-6}{5}- \frac{9}{10}-\frac{5}{7}\\=\frac{-84}{70}-\frac{63}{70}-\frac{50}{70}\\=\frac{-84-63-50}{70}\\=\frac{-197}{70}\)
12. \(+\left(\frac{-4}{9}\right) +\left(\frac{-2}{7}\right) -\left(\frac{-11}{-8}\right)\\= \frac{-4}{9}- \frac{2}{7}-\frac{11}{8}\\=\frac{-224}{504}-\frac{144}{504}-\frac{693}{504}\\=\frac{-224-144-693}{504}\\=\frac{-1061}{504}\)