Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-9}{-4}\right) +\left(\frac{2}{4}\right) -\left(\frac{6}{-6}\right)\)
2. \(-\left(\frac{-5}{3}\right) -\left(\frac{-4}{-3}\right) +\left(\frac{7}{10}\right)\)
3. \(+\left(\frac{-2}{-5}\right) +\left(\frac{9}{2}\right) +\left(\frac{7}{5}\right)\)
4. \(-\left(\frac{4}{7}\right) +\left(\frac{6}{-3}\right) +\left(\frac{-3}{10}\right)\)
5. \(-\left(\frac{6}{5}\right) -\left(\frac{8}{10}\right) +\left(\frac{8}{-3}\right)\)
6. \(-\left(\frac{5}{-7}\right) -\left(\frac{10}{-2}\right) -\left(\frac{-4}{-12}\right)\)
7. \(-\left(\frac{9}{2}\right) +\left(\frac{3}{5}\right) -\left(\frac{-2}{2}\right)\)
8. \(+\left(\frac{-8}{5}\right) -\left(\frac{-6}{-7}\right) +\left(\frac{10}{4}\right)\)
9. \(-\left(\frac{-7}{2}\right) -\left(\frac{-4}{-9}\right) +\left(\frac{-5}{-11}\right)\)
10. \(-\left(\frac{-2}{7}\right) -\left(\frac{2}{-6}\right) +\left(\frac{10}{3}\right)\)
11. \(+\left(\frac{3}{7}\right) +\left(\frac{-8}{8}\right) -\left(\frac{3}{2}\right)\)
12. \(+\left(\frac{3}{2}\right) +\left(\frac{-5}{-2}\right) -\left(\frac{-9}{3}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-9}{-4}\right) +\left(\frac{2}{4}\right) -\left(\frac{6}{-6}\right)\\= \frac{-9}{4}+ \frac{2}{4}+\frac{6}{6}\\=\frac{-9}{4}+\frac{1}{2}+\frac{1}{1}\\=\frac{-9+1+1}{4}\\=\frac{-7}{4}\)
2. \(-\left(\frac{-5}{3}\right) -\left(\frac{-4}{-3}\right) +\left(\frac{7}{10}\right)\\= \frac{5}{3}- \frac{4}{3}+\frac{7}{10}\\=\frac{50}{30}-\frac{40}{30}+\frac{21}{30}\\=\frac{50-40+21}{30}\\=\frac{31}{30}\)
3. \(+\left(\frac{-2}{-5}\right) +\left(\frac{9}{2}\right) +\left(\frac{7}{5}\right)\\= \frac{2}{5}+ \frac{9}{2}+\frac{7}{5}\\=\frac{4}{10}+\frac{45}{10}+\frac{14}{10}\\=\frac{4+45+14}{10}\\=\frac{63}{10}\)
4. \(-\left(\frac{4}{7}\right) +\left(\frac{6}{-3}\right) +\left(\frac{-3}{10}\right)\\= \frac{-4}{7}- \frac{6}{3}-\frac{3}{10}\\=\frac{-4}{7}-\frac{2}{1}-\frac{3}{10}\\=\frac{-40}{70}-\frac{140}{70}-\frac{21}{70}\\=\frac{-40-140-21}{70}\\=\frac{-201}{70}\)
5. \(-\left(\frac{6}{5}\right) -\left(\frac{8}{10}\right) +\left(\frac{8}{-3}\right)\\= \frac{-6}{5}- \frac{8}{10}-\frac{8}{3}\\=\frac{-6}{5}-\frac{4}{5}-\frac{8}{3}\\=\frac{-18}{15}-\frac{12}{15}-\frac{40}{15}\\=\frac{-18-12-40}{15}\\=\frac{-70}{15}\\=\frac{-14}{3}\)
6. \(-\left(\frac{5}{-7}\right) -\left(\frac{10}{-2}\right) -\left(\frac{-4}{-12}\right)\\= \frac{5}{7}+ \frac{10}{2}-\frac{4}{12}\\=\frac{5}{7}+\frac{5}{1}-\frac{1}{3}\\=\frac{15}{21}+\frac{105}{21}-\frac{7}{21}\\=\frac{15+105-7}{21}\\=\frac{113}{21}\)
7. \(-\left(\frac{9}{2}\right) +\left(\frac{3}{5}\right) -\left(\frac{-2}{2}\right)\\= \frac{-9}{2}+ \frac{3}{5}+\frac{2}{2}\\=\frac{-9}{2}+\frac{3}{5}+\frac{1}{1}\\=\frac{-45}{10}+\frac{6}{10}+\frac{10}{10}\\=\frac{-45+6+10}{10}\\=\frac{-29}{10}\)
8. \(+\left(\frac{-8}{5}\right) -\left(\frac{-6}{-7}\right) +\left(\frac{10}{4}\right)\\= \frac{-8}{5}- \frac{6}{7}+\frac{10}{4}\\=\frac{-8}{5}-\frac{6}{7}+\frac{5}{2}\\=\frac{-112}{70}-\frac{60}{70}+\frac{175}{70}\\=\frac{-112-60+175}{70}\\=\frac{3}{70}\)
9. \(-\left(\frac{-7}{2}\right) -\left(\frac{-4}{-9}\right) +\left(\frac{-5}{-11}\right)\\= \frac{7}{2}- \frac{4}{9}+\frac{5}{11}\\=\frac{693}{198}-\frac{88}{198}+\frac{90}{198}\\=\frac{693-88+90}{198}\\=\frac{695}{198}\)
10. \(-\left(\frac{-2}{7}\right) -\left(\frac{2}{-6}\right) +\left(\frac{10}{3}\right)\\= \frac{2}{7}+ \frac{2}{6}+\frac{10}{3}\\=\frac{2}{7}+\frac{1}{3}+\frac{10}{3}\\=\frac{6}{21}+\frac{7}{21}+\frac{70}{21}\\=\frac{6+7+70}{21}\\=\frac{83}{21}\)
11. \(+\left(\frac{3}{7}\right) +\left(\frac{-8}{8}\right) -\left(\frac{3}{2}\right)\\= \frac{3}{7}- \frac{8}{8}-\frac{3}{2}\\=\frac{3}{7}-\frac{1}{1}-\frac{3}{2}\\=\frac{6}{14}-\frac{14}{14}-\frac{21}{14}\\=\frac{6-14-21}{14}\\=\frac{-29}{14}\)
12. \(+\left(\frac{3}{2}\right) +\left(\frac{-5}{-2}\right) -\left(\frac{-9}{3}\right)\\= \frac{3}{2}+ \frac{5}{2}+\frac{9}{3}\\=\frac{3}{2}+\frac{5}{2}+\frac{3}{1}\\=\frac{3+5+3}{2}\\=\frac{11}{2}\)