Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{2}{-7}\right) -\left(\frac{8}{-8}\right) -\left(\frac{10}{-3}\right)\)
2. \(+\left(\frac{3}{-7}\right) +\left(\frac{-4}{2}\right) -\left(\frac{-12}{-12}\right)\)
3. \(-\left(\frac{4}{-5}\right) -\left(\frac{4}{-6}\right) -\left(\frac{-8}{-3}\right)\)
4. \(-\left(\frac{2}{7}\right) +\left(\frac{10}{-6}\right) -\left(\frac{-12}{-12}\right)\)
5. \(-\left(\frac{8}{-9}\right) +\left(\frac{-5}{-2}\right) +\left(\frac{12}{4}\right)\)
6. \(-\left(\frac{3}{2}\right) +\left(\frac{7}{-5}\right) +\left(\frac{10}{7}\right)\)
7. \(+\left(\frac{-4}{-3}\right) -\left(\frac{-7}{-6}\right) +\left(\frac{6}{-4}\right)\)
8. \(-\left(\frac{4}{-3}\right) +\left(\frac{6}{-8}\right) +\left(\frac{-10}{12}\right)\)
9. \(-\left(\frac{-8}{-5}\right) +\left(\frac{7}{-3}\right) -\left(\frac{-2}{7}\right)\)
10. \(+\left(\frac{-2}{-7}\right) +\left(\frac{5}{10}\right) +\left(\frac{-5}{-3}\right)\)
11. \(-\left(\frac{-3}{2}\right) +\left(\frac{-8}{10}\right) -\left(\frac{3}{8}\right)\)
12. \(-\left(\frac{10}{7}\right) -\left(\frac{-4}{-7}\right) +\left(\frac{11}{12}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{2}{-7}\right) -\left(\frac{8}{-8}\right) -\left(\frac{10}{-3}\right)\\= \frac{2}{7}+ \frac{8}{8}+\frac{10}{3}\\=\frac{2}{7}+\frac{1}{1}+\frac{10}{3}\\=\frac{6}{21}+\frac{21}{21}+\frac{70}{21}\\=\frac{6+21+70}{21}\\=\frac{97}{21}\)
2. \(+\left(\frac{3}{-7}\right) +\left(\frac{-4}{2}\right) -\left(\frac{-12}{-12}\right)\\= \frac{-3}{7}- \frac{4}{2}-\frac{12}{12}\\=\frac{-3}{7}-\frac{2}{1}-\frac{1}{1}\\=\frac{-3-2-1}{7}\\=\frac{-6}{7}\)
3. \(-\left(\frac{4}{-5}\right) -\left(\frac{4}{-6}\right) -\left(\frac{-8}{-3}\right)\\= \frac{4}{5}+ \frac{4}{6}-\frac{8}{3}\\=\frac{4}{5}+\frac{2}{3}-\frac{8}{3}\\=\frac{12}{15}+\frac{10}{15}-\frac{40}{15}\\=\frac{12+10-40}{15}\\=\frac{-18}{15}\\=\frac{-6}{5}\)
4. \(-\left(\frac{2}{7}\right) +\left(\frac{10}{-6}\right) -\left(\frac{-12}{-12}\right)\\= \frac{-2}{7}- \frac{10}{6}-\frac{12}{12}\\=\frac{-2}{7}-\frac{5}{3}-\frac{1}{1}\\=\frac{-6}{21}-\frac{35}{21}-\frac{21}{21}\\=\frac{-6-35-21}{21}\\=\frac{-62}{21}\)
5. \(-\left(\frac{8}{-9}\right) +\left(\frac{-5}{-2}\right) +\left(\frac{12}{4}\right)\\= \frac{8}{9}+ \frac{5}{2}+\frac{12}{4}\\=\frac{8}{9}+\frac{5}{2}+\frac{3}{1}\\=\frac{16}{18}+\frac{45}{18}+\frac{54}{18}\\=\frac{16+45+54}{18}\\=\frac{115}{18}\)
6. \(-\left(\frac{3}{2}\right) +\left(\frac{7}{-5}\right) +\left(\frac{10}{7}\right)\\= \frac{-3}{2}- \frac{7}{5}+\frac{10}{7}\\=\frac{-105}{70}-\frac{98}{70}+\frac{100}{70}\\=\frac{-105-98+100}{70}\\=\frac{-103}{70}\)
7. \(+\left(\frac{-4}{-3}\right) -\left(\frac{-7}{-6}\right) +\left(\frac{6}{-4}\right)\\= \frac{4}{3}- \frac{7}{6}-\frac{6}{4}\\=\frac{4}{3}-\frac{7}{6}-\frac{3}{2}\\=\frac{8}{6}-\frac{7}{6}-\frac{9}{6}\\=\frac{8-7-9}{6}\\=\frac{-8}{6}\\=\frac{-4}{3}\)
8. \(-\left(\frac{4}{-3}\right) +\left(\frac{6}{-8}\right) +\left(\frac{-10}{12}\right)\\= \frac{4}{3}- \frac{6}{8}-\frac{10}{12}\\=\frac{4}{3}-\frac{3}{4}-\frac{5}{6}\\=\frac{16}{12}-\frac{9}{12}-\frac{10}{12}\\=\frac{16-9-10}{12}\\=\frac{-3}{12}\\=\frac{-1}{4}\)
9. \(-\left(\frac{-8}{-5}\right) +\left(\frac{7}{-3}\right) -\left(\frac{-2}{7}\right)\\= \frac{-8}{5}- \frac{7}{3}+\frac{2}{7}\\=\frac{-168}{105}-\frac{245}{105}+\frac{30}{105}\\=\frac{-168-245+30}{105}\\=\frac{-383}{105}\)
10. \(+\left(\frac{-2}{-7}\right) +\left(\frac{5}{10}\right) +\left(\frac{-5}{-3}\right)\\= \frac{2}{7}+ \frac{5}{10}+\frac{5}{3}\\=\frac{2}{7}+\frac{1}{2}+\frac{5}{3}\\=\frac{12}{42}+\frac{21}{42}+\frac{70}{42}\\=\frac{12+21+70}{42}\\=\frac{103}{42}\)
11. \(-\left(\frac{-3}{2}\right) +\left(\frac{-8}{10}\right) -\left(\frac{3}{8}\right)\\= \frac{3}{2}- \frac{8}{10}-\frac{3}{8}\\=\frac{3}{2}-\frac{4}{5}-\frac{3}{8}\\=\frac{60}{40}-\frac{32}{40}-\frac{15}{40}\\=\frac{60-32-15}{40}\\=\frac{13}{40}\)
12. \(-\left(\frac{10}{7}\right) -\left(\frac{-4}{-7}\right) +\left(\frac{11}{12}\right)\\= \frac{-10}{7}- \frac{4}{7}+\frac{11}{12}\\=\frac{-120}{84}-\frac{48}{84}+\frac{77}{84}\\=\frac{-120-48+77}{84}\\=\frac{-91}{84}\\=\frac{-13}{12}\)