Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-6}{5}\right) +\left(\frac{5}{5}\right) +\left(\frac{-6}{-2}\right)\)
2. \(-\left(\frac{-7}{2}\right) +\left(\frac{5}{10}\right) +\left(\frac{7}{-11}\right)\)
3. \(-\left(\frac{9}{5}\right) -\left(\frac{-2}{-7}\right) -\left(\frac{7}{5}\right)\)
4. \(-\left(\frac{7}{2}\right) -\left(\frac{-3}{-2}\right) -\left(\frac{12}{-12}\right)\)
5. \(-\left(\frac{-2}{3}\right) -\left(\frac{7}{3}\right) +\left(\frac{-12}{-6}\right)\)
6. \(-\left(\frac{-7}{-4}\right) +\left(\frac{-6}{3}\right) +\left(\frac{2}{5}\right)\)
7. \(-\left(\frac{-9}{-2}\right) +\left(\frac{8}{6}\right) +\left(\frac{9}{7}\right)\)
8. \(+\left(\frac{3}{2}\right) -\left(\frac{-6}{3}\right) +\left(\frac{-8}{6}\right)\)
9. \(+\left(\frac{-4}{9}\right) -\left(\frac{-5}{-3}\right) -\left(\frac{-9}{8}\right)\)
10. \(+\left(\frac{-10}{3}\right) -\left(\frac{-10}{6}\right) -\left(\frac{-3}{-4}\right)\)
11. \(-\left(\frac{-5}{9}\right) -\left(\frac{-9}{8}\right) -\left(\frac{11}{-11}\right)\)
12. \(-\left(\frac{-7}{2}\right) -\left(\frac{5}{-4}\right) +\left(\frac{-10}{7}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-6}{5}\right) +\left(\frac{5}{5}\right) +\left(\frac{-6}{-2}\right)\\= \frac{-6}{5}+ \frac{5}{5}+\frac{6}{2}\\=\frac{-6}{5}+\frac{1}{1}+\frac{3}{1}\\=\frac{-6+1+3}{5}\\=\frac{-2}{5}\)
2. \(-\left(\frac{-7}{2}\right) +\left(\frac{5}{10}\right) +\left(\frac{7}{-11}\right)\\= \frac{7}{2}+ \frac{5}{10}-\frac{7}{11}\\=\frac{7}{2}+\frac{1}{2}-\frac{7}{11}\\=\frac{77}{22}+\frac{11}{22}-\frac{14}{22}\\=\frac{77+11-14}{22}\\=\frac{74}{22}\\=\frac{37}{11}\)
3. \(-\left(\frac{9}{5}\right) -\left(\frac{-2}{-7}\right) -\left(\frac{7}{5}\right)\\= \frac{-9}{5}- \frac{2}{7}-\frac{7}{5}\\=\frac{-63}{35}-\frac{10}{35}-\frac{49}{35}\\=\frac{-63-10-49}{35}\\=\frac{-122}{35}\)
4. \(-\left(\frac{7}{2}\right) -\left(\frac{-3}{-2}\right) -\left(\frac{12}{-12}\right)\\= \frac{-7}{2}- \frac{3}{2}+\frac{12}{12}\\=\frac{-7}{2}-\frac{3}{2}+\frac{1}{1}\\=\frac{-7-3+1}{2}\\=\frac{-9}{2}\)
5. \(-\left(\frac{-2}{3}\right) -\left(\frac{7}{3}\right) +\left(\frac{-12}{-6}\right)\\= \frac{2}{3}- \frac{7}{3}+\frac{12}{6}\\=\frac{2}{3}-\frac{7}{3}+\frac{2}{1}\\=\frac{2-7+2}{3}\\=\frac{-3}{3}\\=\frac{-1}{1}\)
6. \(-\left(\frac{-7}{-4}\right) +\left(\frac{-6}{3}\right) +\left(\frac{2}{5}\right)\\= \frac{-7}{4}- \frac{6}{3}+\frac{2}{5}\\=\frac{-7}{4}-\frac{2}{1}+\frac{2}{5}\\=\frac{-35}{20}-\frac{40}{20}+\frac{8}{20}\\=\frac{-35-40+8}{20}\\=\frac{-67}{20}\)
7. \(-\left(\frac{-9}{-2}\right) +\left(\frac{8}{6}\right) +\left(\frac{9}{7}\right)\\= \frac{-9}{2}+ \frac{8}{6}+\frac{9}{7}\\=\frac{-9}{2}+\frac{4}{3}+\frac{9}{7}\\=\frac{-189}{42}+\frac{56}{42}+\frac{54}{42}\\=\frac{-189+56+54}{42}\\=\frac{-79}{42}\)
8. \(+\left(\frac{3}{2}\right) -\left(\frac{-6}{3}\right) +\left(\frac{-8}{6}\right)\\= \frac{3}{2}+ \frac{6}{3}-\frac{8}{6}\\=\frac{3}{2}+\frac{2}{1}-\frac{4}{3}\\=\frac{9}{6}+\frac{12}{6}-\frac{8}{6}\\=\frac{9+12-8}{6}\\=\frac{13}{6}\)
9. \(+\left(\frac{-4}{9}\right) -\left(\frac{-5}{-3}\right) -\left(\frac{-9}{8}\right)\\= \frac{-4}{9}- \frac{5}{3}+\frac{9}{8}\\=\frac{-32}{72}-\frac{120}{72}+\frac{81}{72}\\=\frac{-32-120+81}{72}\\=\frac{-71}{72}\)
10. \(+\left(\frac{-10}{3}\right) -\left(\frac{-10}{6}\right) -\left(\frac{-3}{-4}\right)\\= \frac{-10}{3}+ \frac{10}{6}-\frac{3}{4}\\=\frac{-10}{3}+\frac{5}{3}-\frac{3}{4}\\=\frac{-40}{12}+\frac{20}{12}-\frac{9}{12}\\=\frac{-40+20-9}{12}\\=\frac{-29}{12}\)
11. \(-\left(\frac{-5}{9}\right) -\left(\frac{-9}{8}\right) -\left(\frac{11}{-11}\right)\\= \frac{5}{9}+ \frac{9}{8}+\frac{11}{11}\\=\frac{5}{9}+\frac{9}{8}+\frac{1}{1}\\=\frac{40}{72}+\frac{81}{72}+\frac{72}{72}\\=\frac{40+81+72}{72}\\=\frac{193}{72}\)
12. \(-\left(\frac{-7}{2}\right) -\left(\frac{5}{-4}\right) +\left(\frac{-10}{7}\right)\\= \frac{7}{2}+ \frac{5}{4}-\frac{10}{7}\\=\frac{98}{28}+\frac{35}{28}-\frac{40}{28}\\=\frac{98+35-40}{28}\\=\frac{93}{28}\)