Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-7}{5}\right) -\left(\frac{8}{-2}\right) +\left(\frac{-12}{3}\right)\)
2. \(+\left(\frac{-5}{6}\right) -\left(\frac{5}{-6}\right) -\left(\frac{9}{9}\right)\)
3. \(+\left(\frac{8}{-7}\right) -\left(\frac{-4}{2}\right) +\left(\frac{2}{-7}\right)\)
4. \(-\left(\frac{-3}{2}\right) -\left(\frac{2}{9}\right) -\left(\frac{-3}{7}\right)\)
5. \(-\left(\frac{2}{7}\right) -\left(\frac{8}{-8}\right) +\left(\frac{-7}{5}\right)\)
6. \(-\left(\frac{8}{-3}\right) +\left(\frac{-5}{8}\right) -\left(\frac{-4}{4}\right)\)
7. \(-\left(\frac{3}{4}\right) -\left(\frac{5}{-6}\right) +\left(\frac{-2}{10}\right)\)
8. \(-\left(\frac{7}{4}\right) -\left(\frac{2}{7}\right) -\left(\frac{-7}{-9}\right)\)
9. \(+\left(\frac{-5}{3}\right) +\left(\frac{7}{-7}\right) +\left(\frac{-12}{-5}\right)\)
10. \(+\left(\frac{2}{5}\right) +\left(\frac{-4}{-8}\right) +\left(\frac{-4}{-10}\right)\)
11. \(-\left(\frac{10}{-9}\right) -\left(\frac{10}{2}\right) -\left(\frac{6}{11}\right)\)
12. \(+\left(\frac{-3}{-7}\right) -\left(\frac{4}{-8}\right) +\left(\frac{8}{11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-7}{5}\right) -\left(\frac{8}{-2}\right) +\left(\frac{-12}{3}\right)\\= \frac{7}{5}+ \frac{8}{2}-\frac{12}{3}\\=\frac{7}{5}+\frac{4}{1}-\frac{4}{1}\\=\frac{7+4-4}{5}\\=\frac{7}{5}\)
2. \(+\left(\frac{-5}{6}\right) -\left(\frac{5}{-6}\right) -\left(\frac{9}{9}\right)\\= \frac{-5}{6}+ \frac{5}{6}-\frac{9}{9}\\=\frac{-5}{6}+\frac{5}{6}-\frac{1}{1}\\=\frac{-5+5-1}{6}\\=\frac{-1}{6}\)
3. \(+\left(\frac{8}{-7}\right) -\left(\frac{-4}{2}\right) +\left(\frac{2}{-7}\right)\\= \frac{-8}{7}+ \frac{4}{2}-\frac{2}{7}\\=\frac{-8}{7}+\frac{2}{1}-\frac{2}{7}\\=\frac{-8+2-2}{7}\\=\frac{-8}{7}\)
4. \(-\left(\frac{-3}{2}\right) -\left(\frac{2}{9}\right) -\left(\frac{-3}{7}\right)\\= \frac{3}{2}- \frac{2}{9}+\frac{3}{7}\\=\frac{189}{126}-\frac{28}{126}+\frac{54}{126}\\=\frac{189-28+54}{126}\\=\frac{215}{126}\)
5. \(-\left(\frac{2}{7}\right) -\left(\frac{8}{-8}\right) +\left(\frac{-7}{5}\right)\\= \frac{-2}{7}+ \frac{8}{8}-\frac{7}{5}\\=\frac{-2}{7}+\frac{1}{1}-\frac{7}{5}\\=\frac{-10}{35}+\frac{35}{35}-\frac{49}{35}\\=\frac{-10+35-49}{35}\\=\frac{-24}{35}\)
6. \(-\left(\frac{8}{-3}\right) +\left(\frac{-5}{8}\right) -\left(\frac{-4}{4}\right)\\= \frac{8}{3}- \frac{5}{8}+\frac{4}{4}\\=\frac{8}{3}-\frac{5}{8}+\frac{1}{1}\\=\frac{64}{24}-\frac{15}{24}+\frac{24}{24}\\=\frac{64-15+24}{24}\\=\frac{73}{24}\)
7. \(-\left(\frac{3}{4}\right) -\left(\frac{5}{-6}\right) +\left(\frac{-2}{10}\right)\\= \frac{-3}{4}+ \frac{5}{6}-\frac{2}{10}\\=\frac{-3}{4}+\frac{5}{6}-\frac{1}{5}\\=\frac{-45}{60}+\frac{50}{60}-\frac{12}{60}\\=\frac{-45+50-12}{60}\\=\frac{-7}{60}\)
8. \(-\left(\frac{7}{4}\right) -\left(\frac{2}{7}\right) -\left(\frac{-7}{-9}\right)\\= \frac{-7}{4}- \frac{2}{7}-\frac{7}{9}\\=\frac{-441}{252}-\frac{72}{252}-\frac{196}{252}\\=\frac{-441-72-196}{252}\\=\frac{-709}{252}\)
9. \(+\left(\frac{-5}{3}\right) +\left(\frac{7}{-7}\right) +\left(\frac{-12}{-5}\right)\\= \frac{-5}{3}- \frac{7}{7}+\frac{12}{5}\\=\frac{-5}{3}-\frac{1}{1}+\frac{12}{5}\\=\frac{-25}{15}-\frac{15}{15}+\frac{36}{15}\\=\frac{-25-15+36}{15}\\=\frac{-4}{15}\)
10. \(+\left(\frac{2}{5}\right) +\left(\frac{-4}{-8}\right) +\left(\frac{-4}{-10}\right)\\= \frac{2}{5}+ \frac{4}{8}+\frac{4}{10}\\=\frac{2}{5}+\frac{1}{2}+\frac{2}{5}\\=\frac{4}{10}+\frac{5}{10}+\frac{4}{10}\\=\frac{4+5+4}{10}\\=\frac{13}{10}\)
11. \(-\left(\frac{10}{-9}\right) -\left(\frac{10}{2}\right) -\left(\frac{6}{11}\right)\\= \frac{10}{9}- \frac{10}{2}-\frac{6}{11}\\=\frac{10}{9}-\frac{5}{1}-\frac{6}{11}\\=\frac{110}{99}-\frac{495}{99}-\frac{54}{99}\\=\frac{110-495-54}{99}\\=\frac{-439}{99}\)
12. \(+\left(\frac{-3}{-7}\right) -\left(\frac{4}{-8}\right) +\left(\frac{8}{11}\right)\\= \frac{3}{7}+ \frac{4}{8}+\frac{8}{11}\\=\frac{3}{7}+\frac{1}{2}+\frac{8}{11}\\=\frac{66}{154}+\frac{77}{154}+\frac{112}{154}\\=\frac{66+77+112}{154}\\=\frac{255}{154}\)