Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-4}{7}\right) +\left(\frac{-5}{5}\right) +\left(\frac{11}{-4}\right)\)
2. \(+\left(\frac{6}{-5}\right) -\left(\frac{-3}{3}\right) +\left(\frac{-4}{4}\right)\)
3. \(-\left(\frac{-9}{2}\right) +\left(\frac{-10}{-5}\right) +\left(\frac{-10}{8}\right)\)
4. \(-\left(\frac{-7}{-4}\right) -\left(\frac{-5}{3}\right) -\left(\frac{-9}{4}\right)\)
5. \(-\left(\frac{3}{-7}\right) +\left(\frac{9}{-5}\right) -\left(\frac{-7}{10}\right)\)
6. \(-\left(\frac{-6}{5}\right) +\left(\frac{6}{10}\right) +\left(\frac{6}{-8}\right)\)
7. \(+\left(\frac{-6}{5}\right) -\left(\frac{6}{-2}\right) +\left(\frac{7}{-12}\right)\)
8. \(-\left(\frac{-4}{-3}\right) -\left(\frac{-10}{6}\right) +\left(\frac{4}{4}\right)\)
9. \(+\left(\frac{-2}{-3}\right) +\left(\frac{8}{-2}\right) +\left(\frac{-11}{-3}\right)\)
10. \(+\left(\frac{-5}{3}\right) +\left(\frac{4}{9}\right) +\left(\frac{-4}{-10}\right)\)
11. \(+\left(\frac{-4}{-9}\right) -\left(\frac{4}{9}\right) +\left(\frac{6}{2}\right)\)
12. \(-\left(\frac{-7}{-2}\right) -\left(\frac{-10}{-6}\right) +\left(\frac{-2}{-5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-4}{7}\right) +\left(\frac{-5}{5}\right) +\left(\frac{11}{-4}\right)\\= \frac{-4}{7}- \frac{5}{5}-\frac{11}{4}\\=\frac{-4}{7}-\frac{1}{1}-\frac{11}{4}\\=\frac{-16}{28}-\frac{28}{28}-\frac{77}{28}\\=\frac{-16-28-77}{28}\\=\frac{-121}{28}\)
2. \(+\left(\frac{6}{-5}\right) -\left(\frac{-3}{3}\right) +\left(\frac{-4}{4}\right)\\= \frac{-6}{5}+ \frac{3}{3}-\frac{4}{4}\\=\frac{-6}{5}+\frac{1}{1}-\frac{1}{1}\\=\frac{-6+1-1}{5}\\=\frac{-6}{5}\)
3. \(-\left(\frac{-9}{2}\right) +\left(\frac{-10}{-5}\right) +\left(\frac{-10}{8}\right)\\= \frac{9}{2}+ \frac{10}{5}-\frac{10}{8}\\=\frac{9}{2}+\frac{2}{1}-\frac{5}{4}\\=\frac{18}{4}+\frac{8}{4}-\frac{5}{4}\\=\frac{18+8-5}{4}\\=\frac{21}{4}\)
4. \(-\left(\frac{-7}{-4}\right) -\left(\frac{-5}{3}\right) -\left(\frac{-9}{4}\right)\\= \frac{-7}{4}+ \frac{5}{3}+\frac{9}{4}\\=\frac{-21}{12}+\frac{20}{12}+\frac{27}{12}\\=\frac{-21+20+27}{12}\\=\frac{26}{12}\\=\frac{13}{6}\)
5. \(-\left(\frac{3}{-7}\right) +\left(\frac{9}{-5}\right) -\left(\frac{-7}{10}\right)\\= \frac{3}{7}- \frac{9}{5}+\frac{7}{10}\\=\frac{30}{70}-\frac{126}{70}+\frac{49}{70}\\=\frac{30-126+49}{70}\\=\frac{-47}{70}\)
6. \(-\left(\frac{-6}{5}\right) +\left(\frac{6}{10}\right) +\left(\frac{6}{-8}\right)\\= \frac{6}{5}+ \frac{6}{10}-\frac{6}{8}\\=\frac{6}{5}+\frac{3}{5}-\frac{3}{4}\\=\frac{24}{20}+\frac{12}{20}-\frac{15}{20}\\=\frac{24+12-15}{20}\\=\frac{21}{20}\)
7. \(+\left(\frac{-6}{5}\right) -\left(\frac{6}{-2}\right) +\left(\frac{7}{-12}\right)\\= \frac{-6}{5}+ \frac{6}{2}-\frac{7}{12}\\=\frac{-6}{5}+\frac{3}{1}-\frac{7}{12}\\=\frac{-72}{60}+\frac{180}{60}-\frac{35}{60}\\=\frac{-72+180-35}{60}\\=\frac{73}{60}\)
8. \(-\left(\frac{-4}{-3}\right) -\left(\frac{-10}{6}\right) +\left(\frac{4}{4}\right)\\= \frac{-4}{3}+ \frac{10}{6}+\frac{4}{4}\\=\frac{-4}{3}+\frac{5}{3}+\frac{1}{1}\\=\frac{-4+5+1}{3}\\=\frac{2}{3}\)
9. \(+\left(\frac{-2}{-3}\right) +\left(\frac{8}{-2}\right) +\left(\frac{-11}{-3}\right)\\= \frac{2}{3}- \frac{8}{2}+\frac{11}{3}\\=\frac{2}{3}-\frac{4}{1}+\frac{11}{3}\\=\frac{2-4+11}{3}\\=\frac{9}{3}\\=\frac{3}{1}\)
10. \(+\left(\frac{-5}{3}\right) +\left(\frac{4}{9}\right) +\left(\frac{-4}{-10}\right)\\= \frac{-5}{3}+ \frac{4}{9}+\frac{4}{10}\\=\frac{-5}{3}+\frac{4}{9}+\frac{2}{5}\\=\frac{-75}{45}+\frac{20}{45}+\frac{18}{45}\\=\frac{-75+20+18}{45}\\=\frac{-37}{45}\)
11. \(+\left(\frac{-4}{-9}\right) -\left(\frac{4}{9}\right) +\left(\frac{6}{2}\right)\\= \frac{4}{9}- \frac{4}{9}+\frac{6}{2}\\=\frac{4}{9}-\frac{4}{9}+\frac{3}{1}\\=\frac{4-4+3}{9}\\=\frac{3}{9}\\=\frac{1}{3}\)
12. \(-\left(\frac{-7}{-2}\right) -\left(\frac{-10}{-6}\right) +\left(\frac{-2}{-5}\right)\\= \frac{-7}{2}- \frac{10}{6}+\frac{2}{5}\\=\frac{-7}{2}-\frac{5}{3}+\frac{2}{5}\\=\frac{-105}{30}-\frac{50}{30}+\frac{12}{30}\\=\frac{-105-50+12}{30}\\=\frac{-143}{30}\)