Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-7}{-5}\right) -\left(\frac{-7}{-10}\right) +\left(\frac{-11}{-12}\right)\)
2. \(-\left(\frac{-7}{-6}\right) -\left(\frac{-9}{-10}\right) +\left(\frac{-12}{-2}\right)\)
3. \(-\left(\frac{9}{4}\right) +\left(\frac{-8}{-7}\right) +\left(\frac{-3}{-9}\right)\)
4. \(+\left(\frac{9}{7}\right) +\left(\frac{-8}{5}\right) +\left(\frac{-11}{9}\right)\)
5. \(-\left(\frac{5}{-9}\right) +\left(\frac{5}{6}\right) -\left(\frac{11}{-11}\right)\)
6. \(+\left(\frac{-6}{5}\right) -\left(\frac{3}{2}\right) -\left(\frac{-4}{10}\right)\)
7. \(-\left(\frac{-3}{4}\right) +\left(\frac{7}{-2}\right) -\left(\frac{8}{6}\right)\)
8. \(-\left(\frac{-9}{4}\right) +\left(\frac{-10}{8}\right) -\left(\frac{-6}{4}\right)\)
9. \(-\left(\frac{-9}{-7}\right) +\left(\frac{-6}{7}\right) +\left(\frac{-8}{-6}\right)\)
10. \(-\left(\frac{-4}{3}\right) +\left(\frac{2}{-3}\right) -\left(\frac{8}{3}\right)\)
11. \(+\left(\frac{9}{-4}\right) -\left(\frac{9}{2}\right) -\left(\frac{3}{-9}\right)\)
12. \(-\left(\frac{-10}{-7}\right) +\left(\frac{8}{2}\right) +\left(\frac{11}{11}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-7}{-5}\right) -\left(\frac{-7}{-10}\right) +\left(\frac{-11}{-12}\right)\\= \frac{-7}{5}- \frac{7}{10}+\frac{11}{12}\\=\frac{-84}{60}-\frac{42}{60}+\frac{55}{60}\\=\frac{-84-42+55}{60}\\=\frac{-71}{60}\)
2. \(-\left(\frac{-7}{-6}\right) -\left(\frac{-9}{-10}\right) +\left(\frac{-12}{-2}\right)\\= \frac{-7}{6}- \frac{9}{10}+\frac{12}{2}\\=\frac{-7}{6}-\frac{9}{10}+\frac{6}{1}\\=\frac{-35}{30}-\frac{27}{30}+\frac{180}{30}\\=\frac{-35-27+180}{30}\\=\frac{118}{30}\\=\frac{59}{15}\)
3. \(-\left(\frac{9}{4}\right) +\left(\frac{-8}{-7}\right) +\left(\frac{-3}{-9}\right)\\= \frac{-9}{4}+ \frac{8}{7}+\frac{3}{9}\\=\frac{-9}{4}+\frac{8}{7}+\frac{1}{3}\\=\frac{-189}{84}+\frac{96}{84}+\frac{28}{84}\\=\frac{-189+96+28}{84}\\=\frac{-65}{84}\)
4. \(+\left(\frac{9}{7}\right) +\left(\frac{-8}{5}\right) +\left(\frac{-11}{9}\right)\\= \frac{9}{7}- \frac{8}{5}-\frac{11}{9}\\=\frac{405}{315}-\frac{504}{315}-\frac{385}{315}\\=\frac{405-504-385}{315}\\=\frac{-484}{315}\)
5. \(-\left(\frac{5}{-9}\right) +\left(\frac{5}{6}\right) -\left(\frac{11}{-11}\right)\\= \frac{5}{9}+ \frac{5}{6}+\frac{11}{11}\\=\frac{5}{9}+\frac{5}{6}+\frac{1}{1}\\=\frac{10}{18}+\frac{15}{18}+\frac{18}{18}\\=\frac{10+15+18}{18}\\=\frac{43}{18}\)
6. \(+\left(\frac{-6}{5}\right) -\left(\frac{3}{2}\right) -\left(\frac{-4}{10}\right)\\= \frac{-6}{5}- \frac{3}{2}+\frac{4}{10}\\=\frac{-6}{5}-\frac{3}{2}+\frac{2}{5}\\=\frac{-12}{10}-\frac{15}{10}+\frac{4}{10}\\=\frac{-12-15+4}{10}\\=\frac{-23}{10}\)
7. \(-\left(\frac{-3}{4}\right) +\left(\frac{7}{-2}\right) -\left(\frac{8}{6}\right)\\= \frac{3}{4}- \frac{7}{2}-\frac{8}{6}\\=\frac{3}{4}-\frac{7}{2}-\frac{4}{3}\\=\frac{9}{12}-\frac{42}{12}-\frac{16}{12}\\=\frac{9-42-16}{12}\\=\frac{-49}{12}\)
8. \(-\left(\frac{-9}{4}\right) +\left(\frac{-10}{8}\right) -\left(\frac{-6}{4}\right)\\= \frac{9}{4}- \frac{10}{8}+\frac{6}{4}\\=\frac{9}{4}-\frac{5}{4}+\frac{3}{2}\\=\frac{9-5+3}{4}\\=\frac{7}{4}\)
9. \(-\left(\frac{-9}{-7}\right) +\left(\frac{-6}{7}\right) +\left(\frac{-8}{-6}\right)\\= \frac{-9}{7}- \frac{6}{7}+\frac{8}{6}\\=\frac{-9}{7}-\frac{6}{7}+\frac{4}{3}\\=\frac{-27}{21}-\frac{18}{21}+\frac{28}{21}\\=\frac{-27-18+28}{21}\\=\frac{-17}{21}\)
10. \(-\left(\frac{-4}{3}\right) +\left(\frac{2}{-3}\right) -\left(\frac{8}{3}\right)\\= \frac{4}{3}- \frac{2}{3}-\frac{8}{3}\\=\frac{4-2-8}{3}\\=\frac{-6}{3}\\=\frac{-2}{1}\)
11. \(+\left(\frac{9}{-4}\right) -\left(\frac{9}{2}\right) -\left(\frac{3}{-9}\right)\\= \frac{-9}{4}- \frac{9}{2}+\frac{3}{9}\\=\frac{-9}{4}-\frac{9}{2}+\frac{1}{3}\\=\frac{-27}{12}-\frac{54}{12}+\frac{4}{12}\\=\frac{-27-54+4}{12}\\=\frac{-77}{12}\)
12. \(-\left(\frac{-10}{-7}\right) +\left(\frac{8}{2}\right) +\left(\frac{11}{11}\right)\\= \frac{-10}{7}+ \frac{8}{2}+\frac{11}{11}\\=\frac{-10}{7}+\frac{4}{1}+\frac{1}{1}\\=\frac{-10+4+1}{7}\\=\frac{-5}{7}\)