Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-2}{3}\right) -\left(\frac{-5}{6}\right) -\left(\frac{-5}{2}\right)\)
2. \(+\left(\frac{-7}{-9}\right) -\left(\frac{-3}{-2}\right) +\left(\frac{6}{11}\right)\)
3. \(+\left(\frac{-5}{6}\right) +\left(\frac{-5}{-4}\right) +\left(\frac{6}{8}\right)\)
4. \(-\left(\frac{7}{-2}\right) -\left(\frac{-3}{-8}\right) +\left(\frac{-12}{-7}\right)\)
5. \(-\left(\frac{-3}{-7}\right) -\left(\frac{-5}{-3}\right) -\left(\frac{9}{-8}\right)\)
6. \(-\left(\frac{5}{-7}\right) -\left(\frac{-2}{3}\right) +\left(\frac{10}{2}\right)\)
7. \(-\left(\frac{5}{-8}\right) -\left(\frac{-6}{4}\right) +\left(\frac{5}{7}\right)\)
8. \(-\left(\frac{-9}{-7}\right) -\left(\frac{2}{6}\right) -\left(\frac{-12}{10}\right)\)
9. \(-\left(\frac{-2}{-3}\right) -\left(\frac{-4}{-3}\right) +\left(\frac{10}{-4}\right)\)
10. \(+\left(\frac{-10}{-3}\right) -\left(\frac{3}{9}\right) -\left(\frac{-10}{8}\right)\)
11. \(-\left(\frac{2}{7}\right) +\left(\frac{10}{7}\right) +\left(\frac{3}{3}\right)\)
12. \(-\left(\frac{5}{2}\right) -\left(\frac{9}{-8}\right) +\left(\frac{10}{8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-2}{3}\right) -\left(\frac{-5}{6}\right) -\left(\frac{-5}{2}\right)\\= \frac{-2}{3}+ \frac{5}{6}+\frac{5}{2}\\=\frac{-4}{6}+\frac{5}{6}+\frac{15}{6}\\=\frac{-4+5+15}{6}\\=\frac{16}{6}\\=\frac{8}{3}\)
2. \(+\left(\frac{-7}{-9}\right) -\left(\frac{-3}{-2}\right) +\left(\frac{6}{11}\right)\\= \frac{7}{9}- \frac{3}{2}+\frac{6}{11}\\=\frac{154}{198}-\frac{297}{198}+\frac{108}{198}\\=\frac{154-297+108}{198}\\=\frac{-35}{198}\)
3. \(+\left(\frac{-5}{6}\right) +\left(\frac{-5}{-4}\right) +\left(\frac{6}{8}\right)\\= \frac{-5}{6}+ \frac{5}{4}+\frac{6}{8}\\=\frac{-5}{6}+\frac{5}{4}+\frac{3}{4}\\=\frac{-10}{12}+\frac{15}{12}+\frac{9}{12}\\=\frac{-10+15+9}{12}\\=\frac{14}{12}\\=\frac{7}{6}\)
4. \(-\left(\frac{7}{-2}\right) -\left(\frac{-3}{-8}\right) +\left(\frac{-12}{-7}\right)\\= \frac{7}{2}- \frac{3}{8}+\frac{12}{7}\\=\frac{196}{56}-\frac{21}{56}+\frac{96}{56}\\=\frac{196-21+96}{56}\\=\frac{271}{56}\)
5. \(-\left(\frac{-3}{-7}\right) -\left(\frac{-5}{-3}\right) -\left(\frac{9}{-8}\right)\\= \frac{-3}{7}- \frac{5}{3}+\frac{9}{8}\\=\frac{-72}{168}-\frac{280}{168}+\frac{189}{168}\\=\frac{-72-280+189}{168}\\=\frac{-163}{168}\)
6. \(-\left(\frac{5}{-7}\right) -\left(\frac{-2}{3}\right) +\left(\frac{10}{2}\right)\\= \frac{5}{7}+ \frac{2}{3}+\frac{10}{2}\\=\frac{5}{7}+\frac{2}{3}+\frac{5}{1}\\=\frac{15}{21}+\frac{14}{21}+\frac{105}{21}\\=\frac{15+14+105}{21}\\=\frac{134}{21}\)
7. \(-\left(\frac{5}{-8}\right) -\left(\frac{-6}{4}\right) +\left(\frac{5}{7}\right)\\= \frac{5}{8}+ \frac{6}{4}+\frac{5}{7}\\=\frac{5}{8}+\frac{3}{2}+\frac{5}{7}\\=\frac{35}{56}+\frac{84}{56}+\frac{40}{56}\\=\frac{35+84+40}{56}\\=\frac{159}{56}\)
8. \(-\left(\frac{-9}{-7}\right) -\left(\frac{2}{6}\right) -\left(\frac{-12}{10}\right)\\= \frac{-9}{7}- \frac{2}{6}+\frac{12}{10}\\=\frac{-9}{7}-\frac{1}{3}+\frac{6}{5}\\=\frac{-135}{105}-\frac{35}{105}+\frac{126}{105}\\=\frac{-135-35+126}{105}\\=\frac{-44}{105}\)
9. \(-\left(\frac{-2}{-3}\right) -\left(\frac{-4}{-3}\right) +\left(\frac{10}{-4}\right)\\= \frac{-2}{3}- \frac{4}{3}-\frac{10}{4}\\=\frac{-2}{3}-\frac{4}{3}-\frac{5}{2}\\=\frac{-4}{6}-\frac{8}{6}-\frac{15}{6}\\=\frac{-4-8-15}{6}\\=\frac{-27}{6}\\=\frac{-9}{2}\)
10. \(+\left(\frac{-10}{-3}\right) -\left(\frac{3}{9}\right) -\left(\frac{-10}{8}\right)\\= \frac{10}{3}- \frac{3}{9}+\frac{10}{8}\\=\frac{10}{3}-\frac{1}{3}+\frac{5}{4}\\=\frac{40}{12}-\frac{4}{12}+\frac{15}{12}\\=\frac{40-4+15}{12}\\=\frac{51}{12}\\=\frac{17}{4}\)
11. \(-\left(\frac{2}{7}\right) +\left(\frac{10}{7}\right) +\left(\frac{3}{3}\right)\\= \frac{-2}{7}+ \frac{10}{7}+\frac{3}{3}\\=\frac{-2}{7}+\frac{10}{7}+\frac{1}{1}\\=\frac{-2+10+1}{7}\\=\frac{9}{7}\)
12. \(-\left(\frac{5}{2}\right) -\left(\frac{9}{-8}\right) +\left(\frac{10}{8}\right)\\= \frac{-5}{2}+ \frac{9}{8}+\frac{10}{8}\\=\frac{-5}{2}+\frac{9}{8}+\frac{5}{4}\\=\frac{-20}{8}+\frac{9}{8}+\frac{10}{8}\\=\frac{-20+9+10}{8}\\=\frac{-1}{8}\)