Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-9}{4}\right) +\left(\frac{-8}{-6}\right) +\left(\frac{9}{-6}\right)\)
2. \(-\left(\frac{-5}{2}\right) +\left(\frac{-10}{7}\right) +\left(\frac{8}{-4}\right)\)
3. \(-\left(\frac{-10}{-7}\right) +\left(\frac{-3}{-10}\right) +\left(\frac{10}{2}\right)\)
4. \(-\left(\frac{-6}{5}\right) -\left(\frac{8}{2}\right) +\left(\frac{-7}{4}\right)\)
5. \(-\left(\frac{-5}{-2}\right) +\left(\frac{-3}{7}\right) +\left(\frac{5}{-5}\right)\)
6. \(+\left(\frac{9}{2}\right) -\left(\frac{7}{-10}\right) -\left(\frac{-3}{-12}\right)\)
7. \(+\left(\frac{5}{8}\right) +\left(\frac{-4}{10}\right) -\left(\frac{12}{4}\right)\)
8. \(+\left(\frac{7}{3}\right) -\left(\frac{5}{-7}\right) +\left(\frac{-10}{-4}\right)\)
9. \(+\left(\frac{2}{-9}\right) -\left(\frac{-3}{-10}\right) +\left(\frac{-4}{-9}\right)\)
10. \(-\left(\frac{9}{2}\right) -\left(\frac{-2}{-10}\right) -\left(\frac{-12}{-9}\right)\)
11. \(+\left(\frac{9}{8}\right) +\left(\frac{4}{8}\right) -\left(\frac{12}{-6}\right)\)
12. \(-\left(\frac{7}{-4}\right) +\left(\frac{3}{7}\right) +\left(\frac{11}{-10}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-9}{4}\right) +\left(\frac{-8}{-6}\right) +\left(\frac{9}{-6}\right)\\= \frac{9}{4}+ \frac{8}{6}-\frac{9}{6}\\=\frac{9}{4}+\frac{4}{3}-\frac{3}{2}\\=\frac{27}{12}+\frac{16}{12}-\frac{18}{12}\\=\frac{27+16-18}{12}\\=\frac{25}{12}\)
2. \(-\left(\frac{-5}{2}\right) +\left(\frac{-10}{7}\right) +\left(\frac{8}{-4}\right)\\= \frac{5}{2}- \frac{10}{7}-\frac{8}{4}\\=\frac{5}{2}-\frac{10}{7}-\frac{2}{1}\\=\frac{35}{14}-\frac{20}{14}-\frac{28}{14}\\=\frac{35-20-28}{14}\\=\frac{-13}{14}\)
3. \(-\left(\frac{-10}{-7}\right) +\left(\frac{-3}{-10}\right) +\left(\frac{10}{2}\right)\\= \frac{-10}{7}+ \frac{3}{10}+\frac{10}{2}\\=\frac{-10}{7}+\frac{3}{10}+\frac{5}{1}\\=\frac{-100}{70}+\frac{21}{70}+\frac{350}{70}\\=\frac{-100+21+350}{70}\\=\frac{271}{70}\)
4. \(-\left(\frac{-6}{5}\right) -\left(\frac{8}{2}\right) +\left(\frac{-7}{4}\right)\\= \frac{6}{5}- \frac{8}{2}-\frac{7}{4}\\=\frac{6}{5}-\frac{4}{1}-\frac{7}{4}\\=\frac{24}{20}-\frac{80}{20}-\frac{35}{20}\\=\frac{24-80-35}{20}\\=\frac{-91}{20}\)
5. \(-\left(\frac{-5}{-2}\right) +\left(\frac{-3}{7}\right) +\left(\frac{5}{-5}\right)\\= \frac{-5}{2}- \frac{3}{7}-\frac{5}{5}\\=\frac{-5}{2}-\frac{3}{7}-\frac{1}{1}\\=\frac{-35}{14}-\frac{6}{14}-\frac{14}{14}\\=\frac{-35-6-14}{14}\\=\frac{-55}{14}\)
6. \(+\left(\frac{9}{2}\right) -\left(\frac{7}{-10}\right) -\left(\frac{-3}{-12}\right)\\= \frac{9}{2}+ \frac{7}{10}-\frac{3}{12}\\=\frac{9}{2}+\frac{7}{10}-\frac{1}{4}\\=\frac{90}{20}+\frac{14}{20}-\frac{5}{20}\\=\frac{90+14-5}{20}\\=\frac{99}{20}\)
7. \(+\left(\frac{5}{8}\right) +\left(\frac{-4}{10}\right) -\left(\frac{12}{4}\right)\\= \frac{5}{8}- \frac{4}{10}-\frac{12}{4}\\=\frac{5}{8}-\frac{2}{5}-\frac{3}{1}\\=\frac{25}{40}-\frac{16}{40}-\frac{120}{40}\\=\frac{25-16-120}{40}\\=\frac{-111}{40}\)
8. \(+\left(\frac{7}{3}\right) -\left(\frac{5}{-7}\right) +\left(\frac{-10}{-4}\right)\\= \frac{7}{3}+ \frac{5}{7}+\frac{10}{4}\\=\frac{7}{3}+\frac{5}{7}+\frac{5}{2}\\=\frac{98}{42}+\frac{30}{42}+\frac{105}{42}\\=\frac{98+30+105}{42}\\=\frac{233}{42}\)
9. \(+\left(\frac{2}{-9}\right) -\left(\frac{-3}{-10}\right) +\left(\frac{-4}{-9}\right)\\= \frac{-2}{9}- \frac{3}{10}+\frac{4}{9}\\=\frac{-20}{90}-\frac{27}{90}+\frac{40}{90}\\=\frac{-20-27+40}{90}\\=\frac{-7}{90}\)
10. \(-\left(\frac{9}{2}\right) -\left(\frac{-2}{-10}\right) -\left(\frac{-12}{-9}\right)\\= \frac{-9}{2}- \frac{2}{10}-\frac{12}{9}\\=\frac{-9}{2}-\frac{1}{5}-\frac{4}{3}\\=\frac{-135}{30}-\frac{6}{30}-\frac{40}{30}\\=\frac{-135-6-40}{30}\\=\frac{-181}{30}\)
11. \(+\left(\frac{9}{8}\right) +\left(\frac{4}{8}\right) -\left(\frac{12}{-6}\right)\\= \frac{9}{8}+ \frac{4}{8}+\frac{12}{6}\\=\frac{9}{8}+\frac{1}{2}+\frac{2}{1}\\=\frac{9+1+2}{8}\\=\frac{12}{8}\\=\frac{3}{2}\)
12. \(-\left(\frac{7}{-4}\right) +\left(\frac{3}{7}\right) +\left(\frac{11}{-10}\right)\\= \frac{7}{4}+ \frac{3}{7}-\frac{11}{10}\\=\frac{245}{140}+\frac{60}{140}-\frac{154}{140}\\=\frac{245+60-154}{140}\\=\frac{151}{140}\)