Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{3}{-2}\right) -\left(\frac{8}{4}\right) -\left(\frac{3}{4}\right)\)
2. \(-\left(\frac{4}{-9}\right) -\left(\frac{10}{5}\right) -\left(\frac{-10}{2}\right)\)
3. \(-\left(\frac{-3}{-2}\right) -\left(\frac{10}{4}\right) -\left(\frac{9}{6}\right)\)
4. \(+\left(\frac{-3}{-7}\right) +\left(\frac{10}{9}\right) +\left(\frac{-4}{-5}\right)\)
5. \(-\left(\frac{7}{8}\right) -\left(\frac{-9}{8}\right) +\left(\frac{-11}{2}\right)\)
6. \(+\left(\frac{6}{-5}\right) +\left(\frac{6}{-10}\right) +\left(\frac{-3}{8}\right)\)
7. \(+\left(\frac{-6}{5}\right) +\left(\frac{-10}{2}\right) -\left(\frac{-7}{-2}\right)\)
8. \(+\left(\frac{-8}{-5}\right) +\left(\frac{10}{-6}\right) +\left(\frac{-12}{-11}\right)\)
9. \(-\left(\frac{2}{-9}\right) -\left(\frac{-6}{-5}\right) -\left(\frac{-8}{4}\right)\)
10. \(-\left(\frac{-8}{-3}\right) -\left(\frac{-8}{4}\right) -\left(\frac{-11}{-10}\right)\)
11. \(-\left(\frac{-4}{3}\right) -\left(\frac{-4}{-5}\right) -\left(\frac{-4}{4}\right)\)
12. \(+\left(\frac{-6}{7}\right) +\left(\frac{-6}{-8}\right) -\left(\frac{-3}{-2}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{3}{-2}\right) -\left(\frac{8}{4}\right) -\left(\frac{3}{4}\right)\\= \frac{-3}{2}- \frac{8}{4}-\frac{3}{4}\\=\frac{-3}{2}-\frac{2}{1}-\frac{3}{4}\\=\frac{-6}{4}-\frac{8}{4}-\frac{3}{4}\\=\frac{-6-8-3}{4}\\=\frac{-17}{4}\)
2. \(-\left(\frac{4}{-9}\right) -\left(\frac{10}{5}\right) -\left(\frac{-10}{2}\right)\\= \frac{4}{9}- \frac{10}{5}+\frac{10}{2}\\=\frac{4}{9}-\frac{2}{1}+\frac{5}{1}\\=\frac{4-2+5}{9}\\=\frac{7}{9}\)
3. \(-\left(\frac{-3}{-2}\right) -\left(\frac{10}{4}\right) -\left(\frac{9}{6}\right)\\= \frac{-3}{2}- \frac{10}{4}-\frac{9}{6}\\=\frac{-3}{2}-\frac{5}{2}-\frac{3}{2}\\=\frac{-3-5-3}{2}\\=\frac{-11}{2}\)
4. \(+\left(\frac{-3}{-7}\right) +\left(\frac{10}{9}\right) +\left(\frac{-4}{-5}\right)\\= \frac{3}{7}+ \frac{10}{9}+\frac{4}{5}\\=\frac{135}{315}+\frac{350}{315}+\frac{252}{315}\\=\frac{135+350+252}{315}\\=\frac{737}{315}\)
5. \(-\left(\frac{7}{8}\right) -\left(\frac{-9}{8}\right) +\left(\frac{-11}{2}\right)\\= \frac{-7}{8}+ \frac{9}{8}-\frac{11}{2}\\=\frac{-7+9-11}{8}\\=\frac{-9}{8}\)
6. \(+\left(\frac{6}{-5}\right) +\left(\frac{6}{-10}\right) +\left(\frac{-3}{8}\right)\\= \frac{-6}{5}- \frac{6}{10}-\frac{3}{8}\\=\frac{-6}{5}-\frac{3}{5}-\frac{3}{8}\\=\frac{-48}{40}-\frac{24}{40}-\frac{15}{40}\\=\frac{-48-24-15}{40}\\=\frac{-87}{40}\)
7. \(+\left(\frac{-6}{5}\right) +\left(\frac{-10}{2}\right) -\left(\frac{-7}{-2}\right)\\= \frac{-6}{5}- \frac{10}{2}-\frac{7}{2}\\=\frac{-6}{5}-\frac{5}{1}-\frac{7}{2}\\=\frac{-12}{10}-\frac{50}{10}-\frac{35}{10}\\=\frac{-12-50-35}{10}\\=\frac{-97}{10}\)
8. \(+\left(\frac{-8}{-5}\right) +\left(\frac{10}{-6}\right) +\left(\frac{-12}{-11}\right)\\= \frac{8}{5}- \frac{10}{6}+\frac{12}{11}\\=\frac{8}{5}-\frac{5}{3}+\frac{12}{11}\\=\frac{264}{165}-\frac{275}{165}+\frac{180}{165}\\=\frac{264-275+180}{165}\\=\frac{169}{165}\)
9. \(-\left(\frac{2}{-9}\right) -\left(\frac{-6}{-5}\right) -\left(\frac{-8}{4}\right)\\= \frac{2}{9}- \frac{6}{5}+\frac{8}{4}\\=\frac{2}{9}-\frac{6}{5}+\frac{2}{1}\\=\frac{10}{45}-\frac{54}{45}+\frac{90}{45}\\=\frac{10-54+90}{45}\\=\frac{46}{45}\)
10. \(-\left(\frac{-8}{-3}\right) -\left(\frac{-8}{4}\right) -\left(\frac{-11}{-10}\right)\\= \frac{-8}{3}+ \frac{8}{4}-\frac{11}{10}\\=\frac{-8}{3}+\frac{2}{1}-\frac{11}{10}\\=\frac{-80}{30}+\frac{60}{30}-\frac{33}{30}\\=\frac{-80+60-33}{30}\\=\frac{-53}{30}\)
11. \(-\left(\frac{-4}{3}\right) -\left(\frac{-4}{-5}\right) -\left(\frac{-4}{4}\right)\\= \frac{4}{3}- \frac{4}{5}+\frac{4}{4}\\=\frac{4}{3}-\frac{4}{5}+\frac{1}{1}\\=\frac{20}{15}-\frac{12}{15}+\frac{15}{15}\\=\frac{20-12+15}{15}\\=\frac{23}{15}\)
12. \(+\left(\frac{-6}{7}\right) +\left(\frac{-6}{-8}\right) -\left(\frac{-3}{-2}\right)\\= \frac{-6}{7}+ \frac{6}{8}-\frac{3}{2}\\=\frac{-6}{7}+\frac{3}{4}-\frac{3}{2}\\=\frac{-24}{28}+\frac{21}{28}-\frac{42}{28}\\=\frac{-24+21-42}{28}\\=\frac{-45}{28}\)