Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{4}{7}\right) -\left(\frac{-6}{-6}\right) +\left(\frac{12}{6}\right)\)
2. \(+\left(\frac{-2}{-7}\right) -\left(\frac{-6}{-8}\right) +\left(\frac{-3}{-6}\right)\)
3. \(-\left(\frac{9}{-2}\right) -\left(\frac{2}{-4}\right) -\left(\frac{-5}{-4}\right)\)
4. \(-\left(\frac{2}{-5}\right) -\left(\frac{-6}{-4}\right) +\left(\frac{10}{-6}\right)\)
5. \(+\left(\frac{10}{3}\right) +\left(\frac{9}{-2}\right) +\left(\frac{9}{8}\right)\)
6. \(-\left(\frac{-10}{-9}\right) -\left(\frac{-3}{-3}\right) +\left(\frac{-9}{10}\right)\)
7. \(+\left(\frac{4}{-3}\right) -\left(\frac{-3}{4}\right) +\left(\frac{-12}{7}\right)\)
8. \(-\left(\frac{-9}{-2}\right) -\left(\frac{3}{-3}\right) -\left(\frac{12}{10}\right)\)
9. \(+\left(\frac{-5}{-6}\right) -\left(\frac{-8}{-5}\right) -\left(\frac{2}{12}\right)\)
10. \(-\left(\frac{-8}{7}\right) -\left(\frac{2}{-5}\right) +\left(\frac{4}{-3}\right)\)
11. \(+\left(\frac{-7}{-2}\right) +\left(\frac{3}{-5}\right) -\left(\frac{-10}{9}\right)\)
12. \(+\left(\frac{-10}{-3}\right) -\left(\frac{-10}{-9}\right) -\left(\frac{-3}{10}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{4}{7}\right) -\left(\frac{-6}{-6}\right) +\left(\frac{12}{6}\right)\\= \frac{-4}{7}- \frac{6}{6}+\frac{12}{6}\\=\frac{-4}{7}-\frac{1}{1}+\frac{2}{1}\\=\frac{-4-1+2}{7}\\=\frac{-3}{7}\)
2. \(+\left(\frac{-2}{-7}\right) -\left(\frac{-6}{-8}\right) +\left(\frac{-3}{-6}\right)\\= \frac{2}{7}- \frac{6}{8}+\frac{3}{6}\\=\frac{2}{7}-\frac{3}{4}+\frac{1}{2}\\=\frac{8}{28}-\frac{21}{28}+\frac{14}{28}\\=\frac{8-21+14}{28}\\=\frac{1}{28}\)
3. \(-\left(\frac{9}{-2}\right) -\left(\frac{2}{-4}\right) -\left(\frac{-5}{-4}\right)\\= \frac{9}{2}+ \frac{2}{4}-\frac{5}{4}\\=\frac{9}{2}+\frac{1}{2}-\frac{5}{4}\\=\frac{18}{4}+\frac{2}{4}-\frac{5}{4}\\=\frac{18+2-5}{4}\\=\frac{15}{4}\)
4. \(-\left(\frac{2}{-5}\right) -\left(\frac{-6}{-4}\right) +\left(\frac{10}{-6}\right)\\= \frac{2}{5}- \frac{6}{4}-\frac{10}{6}\\=\frac{2}{5}-\frac{3}{2}-\frac{5}{3}\\=\frac{12}{30}-\frac{45}{30}-\frac{50}{30}\\=\frac{12-45-50}{30}\\=\frac{-83}{30}\)
5. \(+\left(\frac{10}{3}\right) +\left(\frac{9}{-2}\right) +\left(\frac{9}{8}\right)\\= \frac{10}{3}- \frac{9}{2}+\frac{9}{8}\\=\frac{80}{24}-\frac{108}{24}+\frac{27}{24}\\=\frac{80-108+27}{24}\\=\frac{-1}{24}\)
6. \(-\left(\frac{-10}{-9}\right) -\left(\frac{-3}{-3}\right) +\left(\frac{-9}{10}\right)\\= \frac{-10}{9}- \frac{3}{3}-\frac{9}{10}\\=\frac{-10}{9}-\frac{1}{1}-\frac{9}{10}\\=\frac{-100}{90}-\frac{90}{90}-\frac{81}{90}\\=\frac{-100-90-81}{90}\\=\frac{-271}{90}\)
7. \(+\left(\frac{4}{-3}\right) -\left(\frac{-3}{4}\right) +\left(\frac{-12}{7}\right)\\= \frac{-4}{3}+ \frac{3}{4}-\frac{12}{7}\\=\frac{-112}{84}+\frac{63}{84}-\frac{144}{84}\\=\frac{-112+63-144}{84}\\=\frac{-193}{84}\)
8. \(-\left(\frac{-9}{-2}\right) -\left(\frac{3}{-3}\right) -\left(\frac{12}{10}\right)\\= \frac{-9}{2}+ \frac{3}{3}-\frac{12}{10}\\=\frac{-9}{2}+\frac{1}{1}-\frac{6}{5}\\=\frac{-45}{10}+\frac{10}{10}-\frac{12}{10}\\=\frac{-45+10-12}{10}\\=\frac{-47}{10}\)
9. \(+\left(\frac{-5}{-6}\right) -\left(\frac{-8}{-5}\right) -\left(\frac{2}{12}\right)\\= \frac{5}{6}- \frac{8}{5}-\frac{2}{12}\\=\frac{5}{6}-\frac{8}{5}-\frac{1}{6}\\=\frac{25}{30}-\frac{48}{30}-\frac{5}{30}\\=\frac{25-48-5}{30}\\=\frac{-28}{30}\\=\frac{-14}{15}\)
10. \(-\left(\frac{-8}{7}\right) -\left(\frac{2}{-5}\right) +\left(\frac{4}{-3}\right)\\= \frac{8}{7}+ \frac{2}{5}-\frac{4}{3}\\=\frac{120}{105}+\frac{42}{105}-\frac{140}{105}\\=\frac{120+42-140}{105}\\=\frac{22}{105}\)
11. \(+\left(\frac{-7}{-2}\right) +\left(\frac{3}{-5}\right) -\left(\frac{-10}{9}\right)\\= \frac{7}{2}- \frac{3}{5}+\frac{10}{9}\\=\frac{315}{90}-\frac{54}{90}+\frac{100}{90}\\=\frac{315-54+100}{90}\\=\frac{361}{90}\)
12. \(+\left(\frac{-10}{-3}\right) -\left(\frac{-10}{-9}\right) -\left(\frac{-3}{10}\right)\\= \frac{10}{3}- \frac{10}{9}+\frac{3}{10}\\=\frac{300}{90}-\frac{100}{90}+\frac{27}{90}\\=\frac{300-100+27}{90}\\=\frac{227}{90}\)