Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-4}{-5}\right) +\left(\frac{8}{-3}\right) -\left(\frac{9}{-11}\right)\)
2. \(-\left(\frac{7}{8}\right) +\left(\frac{5}{-3}\right) -\left(\frac{10}{-11}\right)\)
3. \(-\left(\frac{-3}{7}\right) +\left(\frac{-10}{6}\right) -\left(\frac{3}{7}\right)\)
4. \(-\left(\frac{4}{-5}\right) -\left(\frac{4}{-3}\right) +\left(\frac{7}{-4}\right)\)
5. \(-\left(\frac{6}{5}\right) -\left(\frac{-4}{2}\right) -\left(\frac{-8}{2}\right)\)
6. \(+\left(\frac{10}{-3}\right) +\left(\frac{-6}{-2}\right) -\left(\frac{-12}{4}\right)\)
7. \(-\left(\frac{10}{7}\right) -\left(\frac{10}{8}\right) +\left(\frac{11}{11}\right)\)
8. \(-\left(\frac{-4}{-9}\right) +\left(\frac{-3}{-6}\right) +\left(\frac{-3}{7}\right)\)
9. \(+\left(\frac{5}{9}\right) -\left(\frac{3}{6}\right) -\left(\frac{-10}{-7}\right)\)
10. \(-\left(\frac{5}{8}\right) -\left(\frac{-4}{-7}\right) -\left(\frac{2}{8}\right)\)
11. \(-\left(\frac{8}{5}\right) +\left(\frac{-6}{4}\right) -\left(\frac{-5}{5}\right)\)
12. \(+\left(\frac{2}{-7}\right) -\left(\frac{9}{8}\right) -\left(\frac{-9}{5}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-4}{-5}\right) +\left(\frac{8}{-3}\right) -\left(\frac{9}{-11}\right)\\= \frac{4}{5}- \frac{8}{3}+\frac{9}{11}\\=\frac{132}{165}-\frac{440}{165}+\frac{135}{165}\\=\frac{132-440+135}{165}\\=\frac{-173}{165}\)
2. \(-\left(\frac{7}{8}\right) +\left(\frac{5}{-3}\right) -\left(\frac{10}{-11}\right)\\= \frac{-7}{8}- \frac{5}{3}+\frac{10}{11}\\=\frac{-231}{264}-\frac{440}{264}+\frac{240}{264}\\=\frac{-231-440+240}{264}\\=\frac{-431}{264}\)
3. \(-\left(\frac{-3}{7}\right) +\left(\frac{-10}{6}\right) -\left(\frac{3}{7}\right)\\= \frac{3}{7}- \frac{10}{6}-\frac{3}{7}\\=\frac{3}{7}-\frac{5}{3}-\frac{3}{7}\\=\frac{9}{21}-\frac{35}{21}-\frac{9}{21}\\=\frac{9-35-9}{21}\\=\frac{-35}{21}\\=\frac{-5}{3}\)
4. \(-\left(\frac{4}{-5}\right) -\left(\frac{4}{-3}\right) +\left(\frac{7}{-4}\right)\\= \frac{4}{5}+ \frac{4}{3}-\frac{7}{4}\\=\frac{48}{60}+\frac{80}{60}-\frac{105}{60}\\=\frac{48+80-105}{60}\\=\frac{23}{60}\)
5. \(-\left(\frac{6}{5}\right) -\left(\frac{-4}{2}\right) -\left(\frac{-8}{2}\right)\\= \frac{-6}{5}+ \frac{4}{2}+\frac{8}{2}\\=\frac{-6}{5}+\frac{2}{1}+\frac{4}{1}\\=\frac{-6+2+4}{5}\\=\frac{0}{5}\\=\frac{0}{1}\)
6. \(+\left(\frac{10}{-3}\right) +\left(\frac{-6}{-2}\right) -\left(\frac{-12}{4}\right)\\= \frac{-10}{3}+ \frac{6}{2}+\frac{12}{4}\\=\frac{-10}{3}+\frac{3}{1}+\frac{3}{1}\\=\frac{-10+3+3}{3}\\=\frac{-4}{3}\)
7. \(-\left(\frac{10}{7}\right) -\left(\frac{10}{8}\right) +\left(\frac{11}{11}\right)\\= \frac{-10}{7}- \frac{10}{8}+\frac{11}{11}\\=\frac{-10}{7}-\frac{5}{4}+\frac{1}{1}\\=\frac{-40}{28}-\frac{35}{28}+\frac{28}{28}\\=\frac{-40-35+28}{28}\\=\frac{-47}{28}\)
8. \(-\left(\frac{-4}{-9}\right) +\left(\frac{-3}{-6}\right) +\left(\frac{-3}{7}\right)\\= \frac{-4}{9}+ \frac{3}{6}-\frac{3}{7}\\=\frac{-4}{9}+\frac{1}{2}-\frac{3}{7}\\=\frac{-56}{126}+\frac{63}{126}-\frac{54}{126}\\=\frac{-56+63-54}{126}\\=\frac{-47}{126}\)
9. \(+\left(\frac{5}{9}\right) -\left(\frac{3}{6}\right) -\left(\frac{-10}{-7}\right)\\= \frac{5}{9}- \frac{3}{6}-\frac{10}{7}\\=\frac{5}{9}-\frac{1}{2}-\frac{10}{7}\\=\frac{70}{126}-\frac{63}{126}-\frac{180}{126}\\=\frac{70-63-180}{126}\\=\frac{-173}{126}\)
10. \(-\left(\frac{5}{8}\right) -\left(\frac{-4}{-7}\right) -\left(\frac{2}{8}\right)\\= \frac{-5}{8}- \frac{4}{7}-\frac{2}{8}\\=\frac{-5}{8}-\frac{4}{7}-\frac{1}{4}\\=\frac{-35}{56}-\frac{32}{56}-\frac{14}{56}\\=\frac{-35-32-14}{56}\\=\frac{-81}{56}\)
11. \(-\left(\frac{8}{5}\right) +\left(\frac{-6}{4}\right) -\left(\frac{-5}{5}\right)\\= \frac{-8}{5}- \frac{6}{4}+\frac{5}{5}\\=\frac{-8}{5}-\frac{3}{2}+\frac{1}{1}\\=\frac{-16}{10}-\frac{15}{10}+\frac{10}{10}\\=\frac{-16-15+10}{10}\\=\frac{-21}{10}\)
12. \(+\left(\frac{2}{-7}\right) -\left(\frac{9}{8}\right) -\left(\frac{-9}{5}\right)\\= \frac{-2}{7}- \frac{9}{8}+\frac{9}{5}\\=\frac{-80}{280}-\frac{315}{280}+\frac{504}{280}\\=\frac{-80-315+504}{280}\\=\frac{109}{280}\)