Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-3}{7}\right) -\left(\frac{4}{2}\right) -\left(\frac{8}{10}\right)\)
2. \(-\left(\frac{9}{5}\right) -\left(\frac{-8}{-2}\right) +\left(\frac{12}{-4}\right)\)
3. \(+\left(\frac{-10}{-3}\right) -\left(\frac{8}{6}\right) +\left(\frac{-11}{5}\right)\)
4. \(-\left(\frac{7}{-3}\right) -\left(\frac{4}{9}\right) -\left(\frac{4}{11}\right)\)
5. \(-\left(\frac{6}{-5}\right) +\left(\frac{-8}{9}\right) +\left(\frac{6}{-4}\right)\)
6. \(+\left(\frac{-8}{9}\right) -\left(\frac{7}{-9}\right) +\left(\frac{-5}{-3}\right)\)
7. \(-\left(\frac{7}{-3}\right) -\left(\frac{-9}{-2}\right) +\left(\frac{-11}{8}\right)\)
8. \(-\left(\frac{-10}{-7}\right) -\left(\frac{7}{-8}\right) -\left(\frac{6}{3}\right)\)
9. \(+\left(\frac{-9}{-2}\right) -\left(\frac{10}{-9}\right) +\left(\frac{12}{12}\right)\)
10. \(-\left(\frac{9}{-8}\right) +\left(\frac{9}{9}\right) -\left(\frac{6}{8}\right)\)
11. \(+\left(\frac{-2}{7}\right) +\left(\frac{9}{-8}\right) -\left(\frac{-9}{10}\right)\)
12. \(-\left(\frac{4}{-5}\right) +\left(\frac{-6}{-6}\right) +\left(\frac{11}{8}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-3}{7}\right) -\left(\frac{4}{2}\right) -\left(\frac{8}{10}\right)\\= \frac{3}{7}- \frac{4}{2}-\frac{8}{10}\\=\frac{3}{7}-\frac{2}{1}-\frac{4}{5}\\=\frac{15}{35}-\frac{70}{35}-\frac{28}{35}\\=\frac{15-70-28}{35}\\=\frac{-83}{35}\)
2. \(-\left(\frac{9}{5}\right) -\left(\frac{-8}{-2}\right) +\left(\frac{12}{-4}\right)\\= \frac{-9}{5}- \frac{8}{2}-\frac{12}{4}\\=\frac{-9}{5}-\frac{4}{1}-\frac{3}{1}\\=\frac{-9-4-3}{5}\\=\frac{-16}{5}\)
3. \(+\left(\frac{-10}{-3}\right) -\left(\frac{8}{6}\right) +\left(\frac{-11}{5}\right)\\= \frac{10}{3}- \frac{8}{6}-\frac{11}{5}\\=\frac{10}{3}-\frac{4}{3}-\frac{11}{5}\\=\frac{50}{15}-\frac{20}{15}-\frac{33}{15}\\=\frac{50-20-33}{15}\\=\frac{-3}{15}\\=\frac{-1}{5}\)
4. \(-\left(\frac{7}{-3}\right) -\left(\frac{4}{9}\right) -\left(\frac{4}{11}\right)\\= \frac{7}{3}- \frac{4}{9}-\frac{4}{11}\\=\frac{231}{99}-\frac{44}{99}-\frac{36}{99}\\=\frac{231-44-36}{99}\\=\frac{151}{99}\)
5. \(-\left(\frac{6}{-5}\right) +\left(\frac{-8}{9}\right) +\left(\frac{6}{-4}\right)\\= \frac{6}{5}- \frac{8}{9}-\frac{6}{4}\\=\frac{6}{5}-\frac{8}{9}-\frac{3}{2}\\=\frac{108}{90}-\frac{80}{90}-\frac{135}{90}\\=\frac{108-80-135}{90}\\=\frac{-107}{90}\)
6. \(+\left(\frac{-8}{9}\right) -\left(\frac{7}{-9}\right) +\left(\frac{-5}{-3}\right)\\= \frac{-8}{9}+ \frac{7}{9}+\frac{5}{3}\\=\frac{-8+7+5}{9}\\=\frac{4}{9}\)
7. \(-\left(\frac{7}{-3}\right) -\left(\frac{-9}{-2}\right) +\left(\frac{-11}{8}\right)\\= \frac{7}{3}- \frac{9}{2}-\frac{11}{8}\\=\frac{56}{24}-\frac{108}{24}-\frac{33}{24}\\=\frac{56-108-33}{24}\\=\frac{-85}{24}\)
8. \(-\left(\frac{-10}{-7}\right) -\left(\frac{7}{-8}\right) -\left(\frac{6}{3}\right)\\= \frac{-10}{7}+ \frac{7}{8}-\frac{6}{3}\\=\frac{-10}{7}+\frac{7}{8}-\frac{2}{1}\\=\frac{-80}{56}+\frac{49}{56}-\frac{112}{56}\\=\frac{-80+49-112}{56}\\=\frac{-143}{56}\)
9. \(+\left(\frac{-9}{-2}\right) -\left(\frac{10}{-9}\right) +\left(\frac{12}{12}\right)\\= \frac{9}{2}+ \frac{10}{9}+\frac{12}{12}\\=\frac{9}{2}+\frac{10}{9}+\frac{1}{1}\\=\frac{81}{18}+\frac{20}{18}+\frac{18}{18}\\=\frac{81+20+18}{18}\\=\frac{119}{18}\)
10. \(-\left(\frac{9}{-8}\right) +\left(\frac{9}{9}\right) -\left(\frac{6}{8}\right)\\= \frac{9}{8}+ \frac{9}{9}-\frac{6}{8}\\=\frac{9}{8}+\frac{1}{1}-\frac{3}{4}\\=\frac{9+1-3}{8}\\=\frac{7}{8}\)
11. \(+\left(\frac{-2}{7}\right) +\left(\frac{9}{-8}\right) -\left(\frac{-9}{10}\right)\\= \frac{-2}{7}- \frac{9}{8}+\frac{9}{10}\\=\frac{-80}{280}-\frac{315}{280}+\frac{252}{280}\\=\frac{-80-315+252}{280}\\=\frac{-143}{280}\)
12. \(-\left(\frac{4}{-5}\right) +\left(\frac{-6}{-6}\right) +\left(\frac{11}{8}\right)\\= \frac{4}{5}+ \frac{6}{6}+\frac{11}{8}\\=\frac{4}{5}+\frac{1}{1}+\frac{11}{8}\\=\frac{32}{40}+\frac{40}{40}+\frac{55}{40}\\=\frac{32+40+55}{40}\\=\frac{127}{40}\)