Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{7}{5}\right) -\left(\frac{-4}{-8}\right) +\left(\frac{2}{-8}\right)\)
2. \(+\left(\frac{-9}{-7}\right) +\left(\frac{4}{-2}\right) -\left(\frac{-9}{4}\right)\)
3. \(+\left(\frac{5}{6}\right) +\left(\frac{-9}{-4}\right) -\left(\frac{-10}{2}\right)\)
4. \(+\left(\frac{7}{8}\right) -\left(\frac{9}{-10}\right) +\left(\frac{2}{6}\right)\)
5. \(+\left(\frac{7}{6}\right) +\left(\frac{3}{5}\right) -\left(\frac{12}{12}\right)\)
6. \(+\left(\frac{-8}{7}\right) +\left(\frac{8}{4}\right) -\left(\frac{-7}{9}\right)\)
7. \(-\left(\frac{-10}{-7}\right) -\left(\frac{3}{-7}\right) +\left(\frac{10}{-2}\right)\)
8. \(-\left(\frac{8}{-5}\right) -\left(\frac{-4}{-10}\right) -\left(\frac{8}{5}\right)\)
9. \(-\left(\frac{-9}{4}\right) +\left(\frac{3}{-7}\right) +\left(\frac{10}{-10}\right)\)
10. \(+\left(\frac{10}{7}\right) -\left(\frac{-9}{-9}\right) +\left(\frac{-8}{-5}\right)\)
11. \(+\left(\frac{-7}{9}\right) -\left(\frac{4}{-2}\right) +\left(\frac{10}{-2}\right)\)
12. \(+\left(\frac{4}{3}\right) -\left(\frac{-5}{-3}\right) -\left(\frac{4}{-12}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{7}{5}\right) -\left(\frac{-4}{-8}\right) +\left(\frac{2}{-8}\right)\\= \frac{7}{5}- \frac{4}{8}-\frac{2}{8}\\=\frac{7}{5}-\frac{1}{2}-\frac{1}{4}\\=\frac{28}{20}-\frac{10}{20}-\frac{5}{20}\\=\frac{28-10-5}{20}\\=\frac{13}{20}\)
2. \(+\left(\frac{-9}{-7}\right) +\left(\frac{4}{-2}\right) -\left(\frac{-9}{4}\right)\\= \frac{9}{7}- \frac{4}{2}+\frac{9}{4}\\=\frac{9}{7}-\frac{2}{1}+\frac{9}{4}\\=\frac{36}{28}-\frac{56}{28}+\frac{63}{28}\\=\frac{36-56+63}{28}\\=\frac{43}{28}\)
3. \(+\left(\frac{5}{6}\right) +\left(\frac{-9}{-4}\right) -\left(\frac{-10}{2}\right)\\= \frac{5}{6}+ \frac{9}{4}+\frac{10}{2}\\=\frac{5}{6}+\frac{9}{4}+\frac{5}{1}\\=\frac{10}{12}+\frac{27}{12}+\frac{60}{12}\\=\frac{10+27+60}{12}\\=\frac{97}{12}\)
4. \(+\left(\frac{7}{8}\right) -\left(\frac{9}{-10}\right) +\left(\frac{2}{6}\right)\\= \frac{7}{8}+ \frac{9}{10}+\frac{2}{6}\\=\frac{7}{8}+\frac{9}{10}+\frac{1}{3}\\=\frac{105}{120}+\frac{108}{120}+\frac{40}{120}\\=\frac{105+108+40}{120}\\=\frac{253}{120}\)
5. \(+\left(\frac{7}{6}\right) +\left(\frac{3}{5}\right) -\left(\frac{12}{12}\right)\\= \frac{7}{6}+ \frac{3}{5}-\frac{12}{12}\\=\frac{7}{6}+\frac{3}{5}-\frac{1}{1}\\=\frac{35}{30}+\frac{18}{30}-\frac{30}{30}\\=\frac{35+18-30}{30}\\=\frac{23}{30}\)
6. \(+\left(\frac{-8}{7}\right) +\left(\frac{8}{4}\right) -\left(\frac{-7}{9}\right)\\= \frac{-8}{7}+ \frac{8}{4}+\frac{7}{9}\\=\frac{-8}{7}+\frac{2}{1}+\frac{7}{9}\\=\frac{-72}{63}+\frac{126}{63}+\frac{49}{63}\\=\frac{-72+126+49}{63}\\=\frac{103}{63}\)
7. \(-\left(\frac{-10}{-7}\right) -\left(\frac{3}{-7}\right) +\left(\frac{10}{-2}\right)\\= \frac{-10}{7}+ \frac{3}{7}-\frac{10}{2}\\=\frac{-10}{7}+\frac{3}{7}-\frac{5}{1}\\=\frac{-10+3-5}{7}\\=\frac{-12}{7}\)
8. \(-\left(\frac{8}{-5}\right) -\left(\frac{-4}{-10}\right) -\left(\frac{8}{5}\right)\\= \frac{8}{5}- \frac{4}{10}-\frac{8}{5}\\=\frac{8}{5}-\frac{2}{5}-\frac{8}{5}\\=\frac{8-2-8}{5}\\=\frac{-2}{5}\)
9. \(-\left(\frac{-9}{4}\right) +\left(\frac{3}{-7}\right) +\left(\frac{10}{-10}\right)\\= \frac{9}{4}- \frac{3}{7}-\frac{10}{10}\\=\frac{9}{4}-\frac{3}{7}-\frac{1}{1}\\=\frac{63}{28}-\frac{12}{28}-\frac{28}{28}\\=\frac{63-12-28}{28}\\=\frac{23}{28}\)
10. \(+\left(\frac{10}{7}\right) -\left(\frac{-9}{-9}\right) +\left(\frac{-8}{-5}\right)\\= \frac{10}{7}- \frac{9}{9}+\frac{8}{5}\\=\frac{10}{7}-\frac{1}{1}+\frac{8}{5}\\=\frac{50}{35}-\frac{35}{35}+\frac{56}{35}\\=\frac{50-35+56}{35}\\=\frac{71}{35}\)
11. \(+\left(\frac{-7}{9}\right) -\left(\frac{4}{-2}\right) +\left(\frac{10}{-2}\right)\\= \frac{-7}{9}+ \frac{4}{2}-\frac{10}{2}\\=\frac{-7}{9}+\frac{2}{1}-\frac{5}{1}\\=\frac{-7+2-5}{9}\\=\frac{-10}{9}\)
12. \(+\left(\frac{4}{3}\right) -\left(\frac{-5}{-3}\right) -\left(\frac{4}{-12}\right)\\= \frac{4}{3}- \frac{5}{3}+\frac{4}{12}\\=\frac{4}{3}-\frac{5}{3}+\frac{1}{3}\\=\frac{4-5+1}{3}\\=\frac{0}{3}\\=\frac{0}{1}\)