Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-9}{8}\right) +\left(\frac{5}{-4}\right) +\left(\frac{7}{-11}\right)\)
2. \(+\left(\frac{-4}{7}\right) -\left(\frac{8}{-10}\right) -\left(\frac{-3}{-11}\right)\)
3. \(+\left(\frac{-8}{-7}\right) -\left(\frac{-9}{-7}\right) +\left(\frac{4}{-12}\right)\)
4. \(-\left(\frac{-6}{-5}\right) +\left(\frac{7}{-10}\right) +\left(\frac{3}{-2}\right)\)
5. \(+\left(\frac{2}{3}\right) -\left(\frac{-3}{8}\right) -\left(\frac{6}{3}\right)\)
6. \(+\left(\frac{10}{-9}\right) -\left(\frac{-4}{-5}\right) +\left(\frac{-9}{3}\right)\)
7. \(+\left(\frac{4}{-7}\right) +\left(\frac{-7}{10}\right) +\left(\frac{-7}{5}\right)\)
8. \(-\left(\frac{-6}{5}\right) -\left(\frac{4}{7}\right) -\left(\frac{2}{-8}\right)\)
9. \(-\left(\frac{-2}{9}\right) +\left(\frac{10}{2}\right) -\left(\frac{10}{11}\right)\)
10. \(+\left(\frac{2}{3}\right) -\left(\frac{-8}{5}\right) +\left(\frac{-8}{-4}\right)\)
11. \(+\left(\frac{3}{2}\right) +\left(\frac{4}{6}\right) +\left(\frac{-2}{11}\right)\)
12. \(+\left(\frac{3}{8}\right) +\left(\frac{7}{10}\right) +\left(\frac{-4}{2}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-9}{8}\right) +\left(\frac{5}{-4}\right) +\left(\frac{7}{-11}\right)\\= \frac{9}{8}- \frac{5}{4}-\frac{7}{11}\\=\frac{99}{88}-\frac{110}{88}-\frac{56}{88}\\=\frac{99-110-56}{88}\\=\frac{-67}{88}\)
2. \(+\left(\frac{-4}{7}\right) -\left(\frac{8}{-10}\right) -\left(\frac{-3}{-11}\right)\\= \frac{-4}{7}+ \frac{8}{10}-\frac{3}{11}\\=\frac{-4}{7}+\frac{4}{5}-\frac{3}{11}\\=\frac{-220}{385}+\frac{308}{385}-\frac{105}{385}\\=\frac{-220+308-105}{385}\\=\frac{-17}{385}\)
3. \(+\left(\frac{-8}{-7}\right) -\left(\frac{-9}{-7}\right) +\left(\frac{4}{-12}\right)\\= \frac{8}{7}- \frac{9}{7}-\frac{4}{12}\\=\frac{8}{7}-\frac{9}{7}-\frac{1}{3}\\=\frac{24}{21}-\frac{27}{21}-\frac{7}{21}\\=\frac{24-27-7}{21}\\=\frac{-10}{21}\)
4. \(-\left(\frac{-6}{-5}\right) +\left(\frac{7}{-10}\right) +\left(\frac{3}{-2}\right)\\= \frac{-6}{5}- \frac{7}{10}-\frac{3}{2}\\=\frac{-12}{10}-\frac{7}{10}-\frac{15}{10}\\=\frac{-12-7-15}{10}\\=\frac{-34}{10}\\=\frac{-17}{5}\)
5. \(+\left(\frac{2}{3}\right) -\left(\frac{-3}{8}\right) -\left(\frac{6}{3}\right)\\= \frac{2}{3}+ \frac{3}{8}-\frac{6}{3}\\=\frac{2}{3}+\frac{3}{8}-\frac{2}{1}\\=\frac{16}{24}+\frac{9}{24}-\frac{48}{24}\\=\frac{16+9-48}{24}\\=\frac{-23}{24}\)
6. \(+\left(\frac{10}{-9}\right) -\left(\frac{-4}{-5}\right) +\left(\frac{-9}{3}\right)\\= \frac{-10}{9}- \frac{4}{5}-\frac{9}{3}\\=\frac{-10}{9}-\frac{4}{5}-\frac{3}{1}\\=\frac{-50}{45}-\frac{36}{45}-\frac{135}{45}\\=\frac{-50-36-135}{45}\\=\frac{-221}{45}\)
7. \(+\left(\frac{4}{-7}\right) +\left(\frac{-7}{10}\right) +\left(\frac{-7}{5}\right)\\= \frac{-4}{7}- \frac{7}{10}-\frac{7}{5}\\=\frac{-40}{70}-\frac{49}{70}-\frac{98}{70}\\=\frac{-40-49-98}{70}\\=\frac{-187}{70}\)
8. \(-\left(\frac{-6}{5}\right) -\left(\frac{4}{7}\right) -\left(\frac{2}{-8}\right)\\= \frac{6}{5}- \frac{4}{7}+\frac{2}{8}\\=\frac{6}{5}-\frac{4}{7}+\frac{1}{4}\\=\frac{168}{140}-\frac{80}{140}+\frac{35}{140}\\=\frac{168-80+35}{140}\\=\frac{123}{140}\)
9. \(-\left(\frac{-2}{9}\right) +\left(\frac{10}{2}\right) -\left(\frac{10}{11}\right)\\= \frac{2}{9}+ \frac{10}{2}-\frac{10}{11}\\=\frac{2}{9}+\frac{5}{1}-\frac{10}{11}\\=\frac{22}{99}+\frac{495}{99}-\frac{90}{99}\\=\frac{22+495-90}{99}\\=\frac{427}{99}\)
10. \(+\left(\frac{2}{3}\right) -\left(\frac{-8}{5}\right) +\left(\frac{-8}{-4}\right)\\= \frac{2}{3}+ \frac{8}{5}+\frac{8}{4}\\=\frac{2}{3}+\frac{8}{5}+\frac{2}{1}\\=\frac{10}{15}+\frac{24}{15}+\frac{30}{15}\\=\frac{10+24+30}{15}\\=\frac{64}{15}\)
11. \(+\left(\frac{3}{2}\right) +\left(\frac{4}{6}\right) +\left(\frac{-2}{11}\right)\\= \frac{3}{2}+ \frac{4}{6}-\frac{2}{11}\\=\frac{3}{2}+\frac{2}{3}-\frac{2}{11}\\=\frac{99}{66}+\frac{44}{66}-\frac{12}{66}\\=\frac{99+44-12}{66}\\=\frac{131}{66}\)
12. \(+\left(\frac{3}{8}\right) +\left(\frac{7}{10}\right) +\left(\frac{-4}{2}\right)\\= \frac{3}{8}+ \frac{7}{10}-\frac{4}{2}\\=\frac{3}{8}+\frac{7}{10}-\frac{2}{1}\\=\frac{15}{40}+\frac{28}{40}-\frac{80}{40}\\=\frac{15+28-80}{40}\\=\frac{-37}{40}\)