Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-5}{-2}\right) +\left(\frac{-9}{9}\right) -\left(\frac{5}{-2}\right)\)
2. \(-\left(\frac{-6}{7}\right) +\left(\frac{3}{3}\right) +\left(\frac{7}{6}\right)\)
3. \(-\left(\frac{-6}{5}\right) +\left(\frac{8}{-9}\right) +\left(\frac{-11}{-8}\right)\)
4. \(+\left(\frac{7}{-9}\right) +\left(\frac{3}{6}\right) -\left(\frac{-9}{6}\right)\)
5. \(+\left(\frac{2}{9}\right) -\left(\frac{-3}{4}\right) -\left(\frac{5}{-6}\right)\)
6. \(-\left(\frac{5}{-4}\right) -\left(\frac{3}{9}\right) -\left(\frac{6}{3}\right)\)
7. \(-\left(\frac{5}{8}\right) +\left(\frac{10}{-4}\right) -\left(\frac{4}{-5}\right)\)
8. \(+\left(\frac{-9}{2}\right) -\left(\frac{3}{4}\right) +\left(\frac{-2}{-2}\right)\)
9. \(-\left(\frac{7}{9}\right) +\left(\frac{-2}{9}\right) +\left(\frac{6}{-6}\right)\)
10. \(+\left(\frac{7}{-2}\right) -\left(\frac{-8}{-2}\right) -\left(\frac{3}{2}\right)\)
11. \(-\left(\frac{10}{-3}\right) +\left(\frac{3}{-3}\right) -\left(\frac{11}{11}\right)\)
12. \(+\left(\frac{-9}{2}\right) +\left(\frac{4}{3}\right) -\left(\frac{-3}{7}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-5}{-2}\right) +\left(\frac{-9}{9}\right) -\left(\frac{5}{-2}\right)\\= \frac{-5}{2}- \frac{9}{9}+\frac{5}{2}\\=\frac{-5}{2}-\frac{1}{1}+\frac{5}{2}\\=\frac{-5-1+5}{2}\\=\frac{-1}{2}\)
2. \(-\left(\frac{-6}{7}\right) +\left(\frac{3}{3}\right) +\left(\frac{7}{6}\right)\\= \frac{6}{7}+ \frac{3}{3}+\frac{7}{6}\\=\frac{6}{7}+\frac{1}{1}+\frac{7}{6}\\=\frac{36}{42}+\frac{42}{42}+\frac{49}{42}\\=\frac{36+42+49}{42}\\=\frac{127}{42}\)
3. \(-\left(\frac{-6}{5}\right) +\left(\frac{8}{-9}\right) +\left(\frac{-11}{-8}\right)\\= \frac{6}{5}- \frac{8}{9}+\frac{11}{8}\\=\frac{432}{360}-\frac{320}{360}+\frac{495}{360}\\=\frac{432-320+495}{360}\\=\frac{607}{360}\)
4. \(+\left(\frac{7}{-9}\right) +\left(\frac{3}{6}\right) -\left(\frac{-9}{6}\right)\\= \frac{-7}{9}+ \frac{3}{6}+\frac{9}{6}\\=\frac{-7}{9}+\frac{1}{2}+\frac{3}{2}\\=\frac{-14}{18}+\frac{9}{18}+\frac{27}{18}\\=\frac{-14+9+27}{18}\\=\frac{22}{18}\\=\frac{11}{9}\)
5. \(+\left(\frac{2}{9}\right) -\left(\frac{-3}{4}\right) -\left(\frac{5}{-6}\right)\\= \frac{2}{9}+ \frac{3}{4}+\frac{5}{6}\\=\frac{8}{36}+\frac{27}{36}+\frac{30}{36}\\=\frac{8+27+30}{36}\\=\frac{65}{36}\)
6. \(-\left(\frac{5}{-4}\right) -\left(\frac{3}{9}\right) -\left(\frac{6}{3}\right)\\= \frac{5}{4}- \frac{3}{9}-\frac{6}{3}\\=\frac{5}{4}-\frac{1}{3}-\frac{2}{1}\\=\frac{15}{12}-\frac{4}{12}-\frac{24}{12}\\=\frac{15-4-24}{12}\\=\frac{-13}{12}\)
7. \(-\left(\frac{5}{8}\right) +\left(\frac{10}{-4}\right) -\left(\frac{4}{-5}\right)\\= \frac{-5}{8}- \frac{10}{4}+\frac{4}{5}\\=\frac{-5}{8}-\frac{5}{2}+\frac{4}{5}\\=\frac{-25}{40}-\frac{100}{40}+\frac{32}{40}\\=\frac{-25-100+32}{40}\\=\frac{-93}{40}\)
8. \(+\left(\frac{-9}{2}\right) -\left(\frac{3}{4}\right) +\left(\frac{-2}{-2}\right)\\= \frac{-9}{2}- \frac{3}{4}+\frac{2}{2}\\=\frac{-9}{2}-\frac{3}{4}+\frac{1}{1}\\=\frac{-18}{4}-\frac{3}{4}+\frac{4}{4}\\=\frac{-18-3+4}{4}\\=\frac{-17}{4}\)
9. \(-\left(\frac{7}{9}\right) +\left(\frac{-2}{9}\right) +\left(\frac{6}{-6}\right)\\= \frac{-7}{9}- \frac{2}{9}-\frac{6}{6}\\=\frac{-7}{9}-\frac{2}{9}-\frac{1}{1}\\=\frac{-7-2-1}{9}\\=\frac{-10}{9}\)
10. \(+\left(\frac{7}{-2}\right) -\left(\frac{-8}{-2}\right) -\left(\frac{3}{2}\right)\\= \frac{-7}{2}- \frac{8}{2}-\frac{3}{2}\\=\frac{-7}{2}-\frac{4}{1}-\frac{3}{2}\\=\frac{-7-4-3}{2}\\=\frac{-14}{2}\\=\frac{-7}{1}\)
11. \(-\left(\frac{10}{-3}\right) +\left(\frac{3}{-3}\right) -\left(\frac{11}{11}\right)\\= \frac{10}{3}- \frac{3}{3}-\frac{11}{11}\\=\frac{10}{3}-\frac{1}{1}-\frac{1}{1}\\=\frac{10-1-1}{3}\\=\frac{8}{3}\)
12. \(+\left(\frac{-9}{2}\right) +\left(\frac{4}{3}\right) -\left(\frac{-3}{7}\right)\\= \frac{-9}{2}+ \frac{4}{3}+\frac{3}{7}\\=\frac{-189}{42}+\frac{56}{42}+\frac{18}{42}\\=\frac{-189+56+18}{42}\\=\frac{-115}{42}\)