Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(-\left(\frac{-10}{3}\right) +\left(\frac{5}{4}\right) -\left(\frac{10}{-10}\right)\)
2. \(-\left(\frac{-9}{-2}\right) -\left(\frac{3}{-6}\right) +\left(\frac{-4}{-10}\right)\)
3. \(-\left(\frac{-3}{4}\right) -\left(\frac{-7}{-9}\right) +\left(\frac{4}{-7}\right)\)
4. \(+\left(\frac{10}{3}\right) +\left(\frac{3}{6}\right) -\left(\frac{9}{4}\right)\)
5. \(-\left(\frac{-7}{-2}\right) +\left(\frac{-4}{2}\right) -\left(\frac{5}{-2}\right)\)
6. \(+\left(\frac{5}{6}\right) +\left(\frac{4}{8}\right) -\left(\frac{-10}{10}\right)\)
7. \(-\left(\frac{8}{-3}\right) +\left(\frac{-4}{3}\right) +\left(\frac{-4}{3}\right)\)
8. \(+\left(\frac{5}{-2}\right) +\left(\frac{-9}{2}\right) -\left(\frac{-8}{8}\right)\)
9. \(+\left(\frac{7}{-5}\right) +\left(\frac{7}{6}\right) -\left(\frac{3}{6}\right)\)
10. \(+\left(\frac{10}{-9}\right) -\left(\frac{9}{3}\right) +\left(\frac{-6}{8}\right)\)
11. \(+\left(\frac{2}{7}\right) -\left(\frac{2}{5}\right) -\left(\frac{2}{-8}\right)\)
12. \(+\left(\frac{-4}{3}\right) +\left(\frac{8}{-3}\right) -\left(\frac{4}{-6}\right)\)

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Bereken

Verbetersleutel

1. \(-\left(\frac{-10}{3}\right) +\left(\frac{5}{4}\right) -\left(\frac{10}{-10}\right)\\= \frac{10}{3}+ \frac{5}{4}+\frac{10}{10}\\=\frac{10}{3}+\frac{5}{4}+\frac{1}{1}\\=\frac{40}{12}+\frac{15}{12}+\frac{12}{12}\\=\frac{40+15+12}{12}\\=\frac{67}{12}\)
2. \(-\left(\frac{-9}{-2}\right) -\left(\frac{3}{-6}\right) +\left(\frac{-4}{-10}\right)\\= \frac{-9}{2}+ \frac{3}{6}+\frac{4}{10}\\=\frac{-9}{2}+\frac{1}{2}+\frac{2}{5}\\=\frac{-45}{10}+\frac{5}{10}+\frac{4}{10}\\=\frac{-45+5+4}{10}\\=\frac{-36}{10}\\=\frac{-18}{5}\)
3. \(-\left(\frac{-3}{4}\right) -\left(\frac{-7}{-9}\right) +\left(\frac{4}{-7}\right)\\= \frac{3}{4}- \frac{7}{9}-\frac{4}{7}\\=\frac{189}{252}-\frac{196}{252}-\frac{144}{252}\\=\frac{189-196-144}{252}\\=\frac{-151}{252}\)
4. \(+\left(\frac{10}{3}\right) +\left(\frac{3}{6}\right) -\left(\frac{9}{4}\right)\\= \frac{10}{3}+ \frac{3}{6}-\frac{9}{4}\\=\frac{10}{3}+\frac{1}{2}-\frac{9}{4}\\=\frac{40}{12}+\frac{6}{12}-\frac{27}{12}\\=\frac{40+6-27}{12}\\=\frac{19}{12}\)
5. \(-\left(\frac{-7}{-2}\right) +\left(\frac{-4}{2}\right) -\left(\frac{5}{-2}\right)\\= \frac{-7}{2}- \frac{4}{2}+\frac{5}{2}\\=\frac{-7}{2}-\frac{2}{1}+\frac{5}{2}\\=\frac{-7-2+5}{2}\\=\frac{-4}{2}\\=\frac{-2}{1}\)
6. \(+\left(\frac{5}{6}\right) +\left(\frac{4}{8}\right) -\left(\frac{-10}{10}\right)\\= \frac{5}{6}+ \frac{4}{8}+\frac{10}{10}\\=\frac{5}{6}+\frac{1}{2}+\frac{1}{1}\\=\frac{5+1+1}{6}\\=\frac{7}{6}\)
7. \(-\left(\frac{8}{-3}\right) +\left(\frac{-4}{3}\right) +\left(\frac{-4}{3}\right)\\= \frac{8}{3}- \frac{4}{3}-\frac{4}{3}\\=\frac{8-4-4}{3}\\=\frac{0}{3}\\=\frac{0}{1}\)
8. \(+\left(\frac{5}{-2}\right) +\left(\frac{-9}{2}\right) -\left(\frac{-8}{8}\right)\\= \frac{-5}{2}- \frac{9}{2}+\frac{8}{8}\\=\frac{-5}{2}-\frac{9}{2}+\frac{1}{1}\\=\frac{-5-9+1}{2}\\=\frac{-13}{2}\)
9. \(+\left(\frac{7}{-5}\right) +\left(\frac{7}{6}\right) -\left(\frac{3}{6}\right)\\= \frac{-7}{5}+ \frac{7}{6}-\frac{3}{6}\\=\frac{-7}{5}+\frac{7}{6}-\frac{1}{2}\\=\frac{-42}{30}+\frac{35}{30}-\frac{15}{30}\\=\frac{-42+35-15}{30}\\=\frac{-22}{30}\\=\frac{-11}{15}\)
10. \(+\left(\frac{10}{-9}\right) -\left(\frac{9}{3}\right) +\left(\frac{-6}{8}\right)\\= \frac{-10}{9}- \frac{9}{3}-\frac{6}{8}\\=\frac{-10}{9}-\frac{3}{1}-\frac{3}{4}\\=\frac{-40}{36}-\frac{108}{36}-\frac{27}{36}\\=\frac{-40-108-27}{36}\\=\frac{-175}{36}\)
11. \(+\left(\frac{2}{7}\right) -\left(\frac{2}{5}\right) -\left(\frac{2}{-8}\right)\\= \frac{2}{7}- \frac{2}{5}+\frac{2}{8}\\=\frac{2}{7}-\frac{2}{5}+\frac{1}{4}\\=\frac{40}{140}-\frac{56}{140}+\frac{35}{140}\\=\frac{40-56+35}{140}\\=\frac{19}{140}\)
12. \(+\left(\frac{-4}{3}\right) +\left(\frac{8}{-3}\right) -\left(\frac{4}{-6}\right)\\= \frac{-4}{3}- \frac{8}{3}+\frac{4}{6}\\=\frac{-4}{3}-\frac{8}{3}+\frac{2}{3}\\=\frac{-4-8+2}{3}\\=\frac{-10}{3}\)