Breuken haakjesregel (reeks 2)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{-8}{7}\right) +\left(\frac{7}{-9}\right) -\left(\frac{-5}{-8}\right)\)
2. \(+\left(\frac{4}{-3}\right) +\left(\frac{-6}{3}\right) +\left(\frac{3}{8}\right)\)
3. \(+\left(\frac{10}{3}\right) -\left(\frac{-9}{-5}\right) +\left(\frac{3}{7}\right)\)
4. \(+\left(\frac{-9}{-2}\right) +\left(\frac{-2}{2}\right) -\left(\frac{10}{-3}\right)\)
5. \(+\left(\frac{-9}{8}\right) -\left(\frac{10}{-6}\right) +\left(\frac{7}{6}\right)\)
6. \(-\left(\frac{8}{3}\right) -\left(\frac{-4}{-4}\right) +\left(\frac{-11}{-6}\right)\)
7. \(+\left(\frac{5}{-7}\right) +\left(\frac{-2}{3}\right) -\left(\frac{10}{-11}\right)\)
8. \(-\left(\frac{4}{-3}\right) +\left(\frac{-9}{-7}\right) -\left(\frac{5}{9}\right)\)
9. \(+\left(\frac{7}{-9}\right) -\left(\frac{-2}{-3}\right) +\left(\frac{-4}{12}\right)\)
10. \(+\left(\frac{2}{-3}\right) -\left(\frac{-8}{-2}\right) -\left(\frac{4}{2}\right)\)
11. \(+\left(\frac{7}{-5}\right) -\left(\frac{-4}{10}\right) +\left(\frac{-5}{5}\right)\)
12. \(+\left(\frac{-5}{2}\right) +\left(\frac{-6}{-5}\right) -\left(\frac{-11}{-2}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{-8}{7}\right) +\left(\frac{7}{-9}\right) -\left(\frac{-5}{-8}\right)\\= \frac{-8}{7}- \frac{7}{9}-\frac{5}{8}\\=\frac{-576}{504}-\frac{392}{504}-\frac{315}{504}\\=\frac{-576-392-315}{504}\\=\frac{-1283}{504}\)
2. \(+\left(\frac{4}{-3}\right) +\left(\frac{-6}{3}\right) +\left(\frac{3}{8}\right)\\= \frac{-4}{3}- \frac{6}{3}+\frac{3}{8}\\=\frac{-4}{3}-\frac{2}{1}+\frac{3}{8}\\=\frac{-32}{24}-\frac{48}{24}+\frac{9}{24}\\=\frac{-32-48+9}{24}\\=\frac{-71}{24}\)
3. \(+\left(\frac{10}{3}\right) -\left(\frac{-9}{-5}\right) +\left(\frac{3}{7}\right)\\= \frac{10}{3}- \frac{9}{5}+\frac{3}{7}\\=\frac{350}{105}-\frac{189}{105}+\frac{45}{105}\\=\frac{350-189+45}{105}\\=\frac{206}{105}\)
4. \(+\left(\frac{-9}{-2}\right) +\left(\frac{-2}{2}\right) -\left(\frac{10}{-3}\right)\\= \frac{9}{2}- \frac{2}{2}+\frac{10}{3}\\=\frac{9}{2}-\frac{1}{1}+\frac{10}{3}\\=\frac{27}{6}-\frac{6}{6}+\frac{20}{6}\\=\frac{27-6+20}{6}\\=\frac{41}{6}\)
5. \(+\left(\frac{-9}{8}\right) -\left(\frac{10}{-6}\right) +\left(\frac{7}{6}\right)\\= \frac{-9}{8}+ \frac{10}{6}+\frac{7}{6}\\=\frac{-9}{8}+\frac{5}{3}+\frac{7}{6}\\=\frac{-27}{24}+\frac{40}{24}+\frac{28}{24}\\=\frac{-27+40+28}{24}\\=\frac{41}{24}\)
6. \(-\left(\frac{8}{3}\right) -\left(\frac{-4}{-4}\right) +\left(\frac{-11}{-6}\right)\\= \frac{-8}{3}- \frac{4}{4}+\frac{11}{6}\\=\frac{-8}{3}-\frac{1}{1}+\frac{11}{6}\\=\frac{-16}{6}-\frac{6}{6}+\frac{11}{6}\\=\frac{-16-6+11}{6}\\=\frac{-11}{6}\)
7. \(+\left(\frac{5}{-7}\right) +\left(\frac{-2}{3}\right) -\left(\frac{10}{-11}\right)\\= \frac{-5}{7}- \frac{2}{3}+\frac{10}{11}\\=\frac{-165}{231}-\frac{154}{231}+\frac{210}{231}\\=\frac{-165-154+210}{231}\\=\frac{-109}{231}\)
8. \(-\left(\frac{4}{-3}\right) +\left(\frac{-9}{-7}\right) -\left(\frac{5}{9}\right)\\= \frac{4}{3}+ \frac{9}{7}-\frac{5}{9}\\=\frac{84}{63}+\frac{81}{63}-\frac{35}{63}\\=\frac{84+81-35}{63}\\=\frac{130}{63}\)
9. \(+\left(\frac{7}{-9}\right) -\left(\frac{-2}{-3}\right) +\left(\frac{-4}{12}\right)\\= \frac{-7}{9}- \frac{2}{3}-\frac{4}{12}\\=\frac{-7}{9}-\frac{2}{3}-\frac{1}{3}\\=\frac{-7-2-1}{9}\\=\frac{-10}{9}\)
10. \(+\left(\frac{2}{-3}\right) -\left(\frac{-8}{-2}\right) -\left(\frac{4}{2}\right)\\= \frac{-2}{3}- \frac{8}{2}-\frac{4}{2}\\=\frac{-2}{3}-\frac{4}{1}-\frac{2}{1}\\=\frac{-2-4-2}{3}\\=\frac{-8}{3}\)
11. \(+\left(\frac{7}{-5}\right) -\left(\frac{-4}{10}\right) +\left(\frac{-5}{5}\right)\\= \frac{-7}{5}+ \frac{4}{10}-\frac{5}{5}\\=\frac{-7}{5}+\frac{2}{5}-\frac{1}{1}\\=\frac{-7+2-1}{5}\\=\frac{-6}{5}\)
12. \(+\left(\frac{-5}{2}\right) +\left(\frac{-6}{-5}\right) -\left(\frac{-11}{-2}\right)\\= \frac{-5}{2}+ \frac{6}{5}-\frac{11}{2}\\=\frac{-25}{10}+\frac{12}{10}-\frac{55}{10}\\=\frac{-25+12-55}{10}\\=\frac{-68}{10}\\=\frac{-34}{5}\)