Werk uit m.b.v. de rekenregels
- \(y^{\frac{-1}{5}}.y^{-1}\)
- \(a^{1}.a^{\frac{-1}{2}}\)
- \(x^{1}.x^{-1}\)
- \(q^{\frac{-1}{6}}.q^{\frac{2}{3}}\)
- \(x^{\frac{-1}{2}}.x^{\frac{3}{4}}\)
- \(a^{\frac{3}{5}}.a^{\frac{1}{3}}\)
- \(x^{1}.x^{\frac{-5}{4}}\)
- \(q^{\frac{-1}{6}}.q^{\frac{1}{2}}\)
- \(y^{\frac{3}{4}}.y^{\frac{-3}{2}}\)
- \(q^{-1}.q^{-1}\)
- \(x^{-1}.x^{\frac{-1}{3}}\)
- \(y^{\frac{3}{2}}.y^{-2}\)
Werk uit m.b.v. de rekenregels
Verbetersleutel
- \(y^{\frac{-1}{5}}.y^{-1}\\= y^{ \frac{-1}{5} + (-1) }= y^{\frac{-6}{5}}\\=\frac{1}{\sqrt[5]{ y^{6} }}\\=\frac{1}{y.\sqrt[5]{ y }}=\frac{1}{y.\sqrt[5]{ y }}
\color{purple}{\frac{\sqrt[5]{ y^{4} }}{\sqrt[5]{ y^{4} }}} \\=\frac{\sqrt[5]{ y^{4} }}{y^{2}}\\---------------\)
- \(a^{1}.a^{\frac{-1}{2}}\\= a^{ 1 + (\frac{-1}{2}) }= a^{\frac{1}{2}}\\= \sqrt{ a } \\---------------\)
- \(x^{1}.x^{-1}\\= x^{ 1 + (-1) }= x^{0}\\=1\\---------------\)
- \(q^{\frac{-1}{6}}.q^{\frac{2}{3}}\\= q^{ \frac{-1}{6} + \frac{2}{3} }= q^{\frac{1}{2}}\\= \sqrt{ q } \\---------------\)
- \(x^{\frac{-1}{2}}.x^{\frac{3}{4}}\\= x^{ \frac{-1}{2} + \frac{3}{4} }= x^{\frac{1}{4}}\\=\sqrt[4]{ x }\\---------------\)
- \(a^{\frac{3}{5}}.a^{\frac{1}{3}}\\= a^{ \frac{3}{5} + \frac{1}{3} }= a^{\frac{14}{15}}\\=\sqrt[15]{ a^{14} }\\---------------\)
- \(x^{1}.x^{\frac{-5}{4}}\\= x^{ 1 + (\frac{-5}{4}) }= x^{\frac{-1}{4}}\\=\frac{1}{\sqrt[4]{ x }}=\frac{1}{\sqrt[4]{ x }}.
\color{purple}{\frac{\sqrt[4]{ x^{3} }}{\sqrt[4]{ x^{3} }}} \\=\frac{\sqrt[4]{ x^{3} }}{|x|}\\---------------\)
- \(q^{\frac{-1}{6}}.q^{\frac{1}{2}}\\= q^{ \frac{-1}{6} + \frac{1}{2} }= q^{\frac{1}{3}}\\=\sqrt[3]{ q }\\---------------\)
- \(y^{\frac{3}{4}}.y^{\frac{-3}{2}}\\= y^{ \frac{3}{4} + (\frac{-3}{2}) }= y^{\frac{-3}{4}}\\=\frac{1}{\sqrt[4]{ y^{3} }}=\frac{1}{\sqrt[4]{ y^{3} }}.
\color{purple}{\frac{\sqrt[4]{ y }}{\sqrt[4]{ y }}} \\=\frac{\sqrt[4]{ y }}{|y|}\\---------------\)
- \(q^{-1}.q^{-1}\\= q^{ -1 + (-1) }= q^{-2}\\=\frac{1}{q^{2}}\\---------------\)
- \(x^{-1}.x^{\frac{-1}{3}}\\= x^{ -1 + (\frac{-1}{3}) }= x^{\frac{-4}{3}}\\=\frac{1}{\sqrt[3]{ x^{4} }}\\=\frac{1}{x.\sqrt[3]{ x }}=\frac{1}{x.\sqrt[3]{ x }}
\color{purple}{\frac{\sqrt[3]{ x^{2} }}{\sqrt[3]{ x^{2} }}} \\=\frac{\sqrt[3]{ x^{2} }}{x^{2}}\\---------------\)
- \(y^{\frac{3}{2}}.y^{-2}\\= y^{ \frac{3}{2} + (-2) }= y^{\frac{-1}{2}}\\=\frac{1}{ \sqrt{ y } }=\frac{1}{ \sqrt{ y } }.
\color{purple}{\frac{ \sqrt{ y } }{ \sqrt{ y } }} \\=\frac{ \sqrt{ y } }{|y|}\\---------------\)