Werk uit m.b.v. de rekenregels
- \(\dfrac{a^{\frac{-2}{3}}}{a^{\frac{1}{4}}}\)
- \(\dfrac{q^{\frac{2}{5}}}{q^{\frac{-1}{6}}}\)
- \(\dfrac{a^{\frac{1}{4}}}{a^{\frac{-4}{3}}}\)
- \(\dfrac{y^{\frac{-2}{5}}}{y^{\frac{5}{3}}}\)
- \(\dfrac{y^{\frac{-2}{3}}}{y^{\frac{2}{5}}}\)
- \(\dfrac{q^{\frac{4}{3}}}{q^{\frac{-2}{5}}}\)
- \(\dfrac{a^{\frac{-1}{4}}}{a^{\frac{1}{2}}}\)
- \(\dfrac{y^{1}}{y^{\frac{-5}{4}}}\)
- \(\dfrac{y^{\frac{1}{6}}}{y^{\frac{-2}{3}}}\)
- \(\dfrac{x^{-1}}{x^{\frac{1}{4}}}\)
- \(\dfrac{a^{\frac{-1}{5}}}{a^{\frac{-5}{6}}}\)
- \(\dfrac{x^{-1}}{x^{\frac{-5}{2}}}\)
Werk uit m.b.v. de rekenregels
Verbetersleutel
- \(\dfrac{a^{\frac{-2}{3}}}{a^{\frac{1}{4}}}\\= a^{ \frac{-2}{3} - \frac{1}{4} }= a^{\frac{-11}{12}}\\=\frac{1}{\sqrt[12]{ a^{11} }}=\frac{1}{\sqrt[12]{ a^{11} }}.
\color{purple}{\frac{\sqrt[12]{ a }}{\sqrt[12]{ a }}} \\=\frac{\sqrt[12]{ a }}{|a|}\\---------------\)
- \(\dfrac{q^{\frac{2}{5}}}{q^{\frac{-1}{6}}}\\= q^{ \frac{2}{5} - (\frac{-1}{6}) }= q^{\frac{17}{30}}\\=\sqrt[30]{ q^{17} }\\---------------\)
- \(\dfrac{a^{\frac{1}{4}}}{a^{\frac{-4}{3}}}\\= a^{ \frac{1}{4} - (\frac{-4}{3}) }= a^{\frac{19}{12}}\\=\sqrt[12]{ a^{19} }=|a|.\sqrt[12]{ a^{7} }\\---------------\)
- \(\dfrac{y^{\frac{-2}{5}}}{y^{\frac{5}{3}}}\\= y^{ \frac{-2}{5} - \frac{5}{3} }= y^{\frac{-31}{15}}\\=\frac{1}{\sqrt[15]{ y^{31} }}\\=\frac{1}{y^{2}.\sqrt[15]{ y }}=\frac{1}{y^{2}.\sqrt[15]{ y }}
\color{purple}{\frac{\sqrt[15]{ y^{14} }}{\sqrt[15]{ y^{14} }}} \\=\frac{\sqrt[15]{ y^{14} }}{y^{3}}\\---------------\)
- \(\dfrac{y^{\frac{-2}{3}}}{y^{\frac{2}{5}}}\\= y^{ \frac{-2}{3} - \frac{2}{5} }= y^{\frac{-16}{15}}\\=\frac{1}{\sqrt[15]{ y^{16} }}\\=\frac{1}{y.\sqrt[15]{ y }}=\frac{1}{y.\sqrt[15]{ y }}
\color{purple}{\frac{\sqrt[15]{ y^{14} }}{\sqrt[15]{ y^{14} }}} \\=\frac{\sqrt[15]{ y^{14} }}{y^{2}}\\---------------\)
- \(\dfrac{q^{\frac{4}{3}}}{q^{\frac{-2}{5}}}\\= q^{ \frac{4}{3} - (\frac{-2}{5}) }= q^{\frac{26}{15}}\\=\sqrt[15]{ q^{26} }=q.\sqrt[15]{ q^{11} }\\---------------\)
- \(\dfrac{a^{\frac{-1}{4}}}{a^{\frac{1}{2}}}\\= a^{ \frac{-1}{4} - \frac{1}{2} }= a^{\frac{-3}{4}}\\=\frac{1}{\sqrt[4]{ a^{3} }}=\frac{1}{\sqrt[4]{ a^{3} }}.
\color{purple}{\frac{\sqrt[4]{ a }}{\sqrt[4]{ a }}} \\=\frac{\sqrt[4]{ a }}{|a|}\\---------------\)
- \(\dfrac{y^{1}}{y^{\frac{-5}{4}}}\\= y^{ 1 - (\frac{-5}{4}) }= y^{\frac{9}{4}}\\=\sqrt[4]{ y^{9} }=|y^{2}|.\sqrt[4]{ y }\\---------------\)
- \(\dfrac{y^{\frac{1}{6}}}{y^{\frac{-2}{3}}}\\= y^{ \frac{1}{6} - (\frac{-2}{3}) }= y^{\frac{5}{6}}\\=\sqrt[6]{ y^{5} }\\---------------\)
- \(\dfrac{x^{-1}}{x^{\frac{1}{4}}}\\= x^{ -1 - \frac{1}{4} }= x^{\frac{-5}{4}}\\=\frac{1}{\sqrt[4]{ x^{5} }}\\=\frac{1}{|x|.\sqrt[4]{ x }}=\frac{1}{|x|.\sqrt[4]{ x }}
\color{purple}{\frac{\sqrt[4]{ x^{3} }}{\sqrt[4]{ x^{3} }}} \\=\frac{\sqrt[4]{ x^{3} }}{|x^{2}|}\\---------------\)
- \(\dfrac{a^{\frac{-1}{5}}}{a^{\frac{-5}{6}}}\\= a^{ \frac{-1}{5} - (\frac{-5}{6}) }= a^{\frac{19}{30}}\\=\sqrt[30]{ a^{19} }\\---------------\)
- \(\dfrac{x^{-1}}{x^{\frac{-5}{2}}}\\= x^{ -1 - (\frac{-5}{2}) }= x^{\frac{3}{2}}\\= \sqrt{ x^{3} } =|x|. \sqrt{ x } \\---------------\)