Werk uit m.b.v. de rekenregels
- \(\left(y^{\frac{1}{3}}\right)^{\frac{3}{5}}\)
- \(\left(y^{\frac{1}{4}}\right)^{\frac{-1}{2}}\)
- \(\left(y^{-1}\right)^{\frac{1}{3}}\)
- \(\left(a^{1}\right)^{\frac{1}{3}}\)
- \(\left(y^{\frac{2}{5}}\right)^{1}\)
- \(\left(a^{\frac{-1}{2}}\right)^{\frac{-1}{2}}\)
- \(\left(a^{\frac{-1}{2}}\right)^{\frac{2}{5}}\)
- \(\left(a^{\frac{1}{2}}\right)^{1}\)
- \(\left(a^{\frac{-1}{3}}\right)^{\frac{1}{5}}\)
- \(\left(x^{\frac{-1}{2}}\right)^{\frac{1}{3}}\)
- \(\left(x^{\frac{2}{3}}\right)^{\frac{-3}{5}}\)
- \(\left(q^{-2}\right)^{\frac{5}{3}}\)
Werk uit m.b.v. de rekenregels
Verbetersleutel
- \(\left(y^{\frac{1}{3}}\right)^{\frac{3}{5}}\\= y^{ \frac{1}{3} . \frac{3}{5} }= y^{\frac{1}{5}}\\=\sqrt[5]{ y }\\---------------\)
- \(\left(y^{\frac{1}{4}}\right)^{\frac{-1}{2}}\\= y^{ \frac{1}{4} . (\frac{-1}{2}) }= y^{\frac{-1}{8}}\\=\frac{1}{\sqrt[8]{ y }}=\frac{1}{\sqrt[8]{ y }}.
\color{purple}{\frac{\sqrt[8]{ y^{7} }}{\sqrt[8]{ y^{7} }}} \\=\frac{\sqrt[8]{ y^{7} }}{|y|}\\---------------\)
- \(\left(y^{-1}\right)^{\frac{1}{3}}\\= y^{ -1 . \frac{1}{3} }= y^{\frac{-1}{3}}\\=\frac{1}{\sqrt[3]{ y }}=\frac{1}{\sqrt[3]{ y }}.
\color{purple}{\frac{\sqrt[3]{ y^{2} }}{\sqrt[3]{ y^{2} }}} \\=\frac{\sqrt[3]{ y^{2} }}{y}\\---------------\)
- \(\left(a^{1}\right)^{\frac{1}{3}}\\= a^{ 1 . \frac{1}{3} }= a^{\frac{1}{3}}\\=\sqrt[3]{ a }\\---------------\)
- \(\left(y^{\frac{2}{5}}\right)^{1}\\= y^{ \frac{2}{5} . 1 }= y^{\frac{2}{5}}\\=\sqrt[5]{ y^{2} }\\---------------\)
- \(\left(a^{\frac{-1}{2}}\right)^{\frac{-1}{2}}\\= a^{ \frac{-1}{2} . (\frac{-1}{2}) }= a^{\frac{1}{4}}\\=\sqrt[4]{ a }\\---------------\)
- \(\left(a^{\frac{-1}{2}}\right)^{\frac{2}{5}}\\= a^{ \frac{-1}{2} . \frac{2}{5} }= a^{\frac{-1}{5}}\\=\frac{1}{\sqrt[5]{ a }}=\frac{1}{\sqrt[5]{ a }}.
\color{purple}{\frac{\sqrt[5]{ a^{4} }}{\sqrt[5]{ a^{4} }}} \\=\frac{\sqrt[5]{ a^{4} }}{a}\\---------------\)
- \(\left(a^{\frac{1}{2}}\right)^{1}\\= a^{ \frac{1}{2} . 1 }= a^{\frac{1}{2}}\\= \sqrt{ a } \\---------------\)
- \(\left(a^{\frac{-1}{3}}\right)^{\frac{1}{5}}\\= a^{ \frac{-1}{3} . \frac{1}{5} }= a^{\frac{-1}{15}}\\=\frac{1}{\sqrt[15]{ a }}=\frac{1}{\sqrt[15]{ a }}.
\color{purple}{\frac{\sqrt[15]{ a^{14} }}{\sqrt[15]{ a^{14} }}} \\=\frac{\sqrt[15]{ a^{14} }}{a}\\---------------\)
- \(\left(x^{\frac{-1}{2}}\right)^{\frac{1}{3}}\\= x^{ \frac{-1}{2} . \frac{1}{3} }= x^{\frac{-1}{6}}\\=\frac{1}{\sqrt[6]{ x }}=\frac{1}{\sqrt[6]{ x }}.
\color{purple}{\frac{\sqrt[6]{ x^{5} }}{\sqrt[6]{ x^{5} }}} \\=\frac{\sqrt[6]{ x^{5} }}{|x|}\\---------------\)
- \(\left(x^{\frac{2}{3}}\right)^{\frac{-3}{5}}\\= x^{ \frac{2}{3} . (\frac{-3}{5}) }= x^{\frac{-2}{5}}\\=\frac{1}{\sqrt[5]{ x^{2} }}=\frac{1}{\sqrt[5]{ x^{2} }}.
\color{purple}{\frac{\sqrt[5]{ x^{3} }}{\sqrt[5]{ x^{3} }}} \\=\frac{\sqrt[5]{ x^{3} }}{x}\\---------------\)
- \(\left(q^{-2}\right)^{\frac{5}{3}}\\= q^{ -2 . \frac{5}{3} }= q^{\frac{-10}{3}}\\=\frac{1}{\sqrt[3]{ q^{10} }}\\=\frac{1}{q^{3}.\sqrt[3]{ q }}=\frac{1}{q^{3}.\sqrt[3]{ q }}
\color{purple}{\frac{\sqrt[3]{ q^{2} }}{\sqrt[3]{ q^{2} }}} \\=\frac{\sqrt[3]{ q^{2} }}{q^{4}}\\---------------\)