Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
- \(-(7-3x)=-9x^2-(8-9x)\)
- \(10x^2-(12x-5)=9x(x-2)\)
- \(\frac{1}{4}x^2+\frac{9}{4}x-\frac{11}{2}=0\)
- \(x(x-15)=6(x-18)\)
- \(\frac{21}{4}x=-\frac{1}{4}x^2-\frac{55}{2}\)
- \((-x+4)(2x-2)-x(-14x-13)=4\)
- \(-2x=-\frac{1}{3}x^2+\frac{55}{3}\)
- \((-2x+5)(-4x-2)-x(4x-22)=-26\)
- \((-3x-4)(-5x+5)-x(14x-16)=-110\)
- \(x(x-6)=-4(x+1)\)
- \(\frac{1}{8}x^2+\frac{3}{4}x+1=0\)
- \(x(x+33)=27(x+1)\)
Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
Verbetersleutel
- \(-(7-3x)=-9x^2-(8-9x) \\
\Leftrightarrow -7+3x=-9x^2-8+9x \\
\Leftrightarrow 9x^2-6x+1=0 \\\text{We zoeken de oplossingen van } \color{blue}{9x^2-6x+1=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-6)^2-4.9.1 & &\\
& = 36-36 & & \\
& = 0 & & \\ x & = \frac{-b\pm \sqrt{D}}{2.a} & & \\
& = \frac{-(-6)}{2.9} & & \\
& = \frac{1}{3} & & \\V &= \Big\{ \frac{1}{3} \Big\} & &\end{align} \\ -----------------\)
- \(10x^2-(12x-5)=9x(x-2) \\
\Leftrightarrow 10x^2-12x+5=9x^2-18x \\
\Leftrightarrow x^2+6x+5=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+6x+5=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (6)^2-4.1.5 & &\\
& = 36-20 & & \\
& = 16 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-6-\sqrt16}{2.1} & & = \frac{-6+\sqrt16}{2.1} \\
& = \frac{-10}{2} & & = \frac{-2}{2} \\
& = -5 & & = -1 \\ \\ V &= \Big\{ -5 ; -1 \Big\} & &\end{align} \\ -----------------\)
- \(\frac{1}{4}x^2+\frac{9}{4}x-\frac{11}{2}=0\\
\Leftrightarrow \color{red}{4.} \left(\frac{1}{4}x^2+\frac{9}{4}x-\frac{11}{2}\right)=0 \color{red}{.4} \\
\Leftrightarrow x^2+9x-22=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+9x-22=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (9)^2-4.1.(-22) & &\\
& = 81+88 & & \\
& = 169 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-9-\sqrt169}{2.1} & & = \frac{-9+\sqrt169}{2.1} \\
& = \frac{-22}{2} & & = \frac{4}{2} \\
& = -11 & & = 2 \\ \\ V &= \Big\{ -11 ; 2 \Big\} & &\end{align} \\ -----------------\)
- \(x(x-15)=6(x-18) \\
\Leftrightarrow x^2-15x=6x-108 \\
\Leftrightarrow x^2-21x+108=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2-21x+108=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-21)^2-4.1.108 & &\\
& = 441-432 & & \\
& = 9 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-(-21)-\sqrt9}{2.1} & & = \frac{-(-21)+\sqrt9}{2.1} \\
& = \frac{18}{2} & & = \frac{24}{2} \\
& = 9 & & = 12 \\ \\ V &= \Big\{ 9 ; 12 \Big\} & &\end{align} \\ -----------------\)
- \(\frac{21}{4}x=-\frac{1}{4}x^2-\frac{55}{2} \\
\Leftrightarrow \frac{1}{4}x^2+\frac{21}{4}x+\frac{55}{2}=0 \\
\Leftrightarrow \color{red}{4.} \left(\frac{1}{4}x^2+\frac{21}{4}x+\frac{55}{2}\right)=0 \color{red}{.4} \\
\Leftrightarrow x^2+21x+110=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+21x+110=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (21)^2-4.1.110 & &\\
& = 441-440 & & \\
& = 1 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-21-\sqrt1}{2.1} & & = \frac{-21+\sqrt1}{2.1} \\
& = \frac{-22}{2} & & = \frac{-20}{2} \\
& = -11 & & = -10 \\ \\ V &= \Big\{ -11 ; -10 \Big\} & &\end{align} \\ -----------------\)
- \((-x+4)(2x-2)-x(-14x-13)=4\\
\Leftrightarrow -2x^2+2x+8x-8 +14x^2+13x-4=0 \\
\Leftrightarrow 12x^2+7x-12=0 \\\text{We zoeken de oplossingen van } \color{blue}{12x^2+7x-12=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (7)^2-4.12.(-12) & &\\
& = 49+576 & & \\
& = 625 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-7-\sqrt625}{2.12} & & = \frac{-7+\sqrt625}{2.12} \\
& = \frac{-32}{24} & & = \frac{18}{24} \\
& = \frac{-4}{3} & & = \frac{3}{4} \\ \\ V &= \Big\{ \frac{-4}{3} ; \frac{3}{4} \Big\} & &\end{align} \\ -----------------\)
- \(-2x=-\frac{1}{3}x^2+\frac{55}{3} \\
\Leftrightarrow \frac{1}{3}x^2-2x-\frac{55}{3}=0 \\
\Leftrightarrow \color{red}{3.} \left(\frac{1}{3}x^2-2x-\frac{55}{3}\right)=0 \color{red}{.3} \\
\Leftrightarrow x^2-6x-55=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2-6x-55=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-6)^2-4.1.(-55) & &\\
& = 36+220 & & \\
& = 256 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-(-6)-\sqrt256}{2.1} & & = \frac{-(-6)+\sqrt256}{2.1} \\
& = \frac{-10}{2} & & = \frac{22}{2} \\
& = -5 & & = 11 \\ \\ V &= \Big\{ -5 ; 11 \Big\} & &\end{align} \\ -----------------\)
- \((-2x+5)(-4x-2)-x(4x-22)=-26\\
\Leftrightarrow 8x^2+4x-20x-10 -4x^2+22x+26=0 \\
\Leftrightarrow 4x^2+16x+16=0 \\\text{We zoeken de oplossingen van } \color{blue}{4x^2+16x+16=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (16)^2-4.4.16 & &\\
& = 256-256 & & \\
& = 0 & & \\ x & = \frac{-b\pm \sqrt{D}}{2.a} & & \\
& = \frac{-16}{2.4} & & \\
& = -2 & & \\V &= \Big\{ -2 \Big\} & &\end{align} \\ -----------------\)
- \((-3x-4)(-5x+5)-x(14x-16)=-110\\
\Leftrightarrow 15x^2-15x+20x-20 -14x^2+16x+110=0 \\
\Leftrightarrow x^2-19x+90=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2-19x+90=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-19)^2-4.1.90 & &\\
& = 361-360 & & \\
& = 1 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-(-19)-\sqrt1}{2.1} & & = \frac{-(-19)+\sqrt1}{2.1} \\
& = \frac{18}{2} & & = \frac{20}{2} \\
& = 9 & & = 10 \\ \\ V &= \Big\{ 9 ; 10 \Big\} & &\end{align} \\ -----------------\)
- \(x(x-6)=-4(x+1) \\
\Leftrightarrow x^2-6x=-4x-4 \\
\Leftrightarrow x^2-2x+4=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2-2x+4=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-2)^2-4.1.4 & &\\
& = 4-16 & & \\
& = -12 & & \\ & < 0 \\V &= \varnothing \end{align} \\ -----------------\)
- \(\frac{1}{8}x^2+\frac{3}{4}x+1=0\\
\Leftrightarrow \color{red}{8.} \left(\frac{1}{8}x^2+\frac{3}{4}x+1\right)=0 \color{red}{.8} \\
\Leftrightarrow x^2+6x+8=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+6x+8=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (6)^2-4.1.8 & &\\
& = 36-32 & & \\
& = 4 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-6-\sqrt4}{2.1} & & = \frac{-6+\sqrt4}{2.1} \\
& = \frac{-8}{2} & & = \frac{-4}{2} \\
& = -4 & & = -2 \\ \\ V &= \Big\{ -4 ; -2 \Big\} & &\end{align} \\ -----------------\)
- \(x(x+33)=27(x+1) \\
\Leftrightarrow x^2+33x=27x+27 \\
\Leftrightarrow x^2+6x-27=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+6x-27=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (6)^2-4.1.(-27) & &\\
& = 36+108 & & \\
& = 144 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-6-\sqrt144}{2.1} & & = \frac{-6+\sqrt144}{2.1} \\
& = \frac{-18}{2} & & = \frac{6}{2} \\
& = -9 & & = 3 \\ \\ V &= \Big\{ -9 ; 3 \Big\} & &\end{align} \\ -----------------\)