Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
- \(x(x+61)=66(x+1)\)
- \(x(x+15)=5(x-5)\)
- \(x(16x+7)=-49(x+1)\)
- \(-(2-39x)=-4x^2-(38-14x)\)
- \(\frac{11}{4}x=-\frac{1}{4}x^2-7\)
- \(x(16x-9)=-(x+1)\)
- \((-3x-3)(-5x+2)-x(14x-3)=-14\)
- \(x(2x+79)=72(x+1)\)
- \(-(14-10x)=-x^2-(18-8x)\)
- \(x(x+20)=4(x-16)\)
- \(-(13-15x)=-x^2-(29-5x)\)
- \(-(2-x)=-x^2-(-54-2x)\)
Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
Verbetersleutel
- \(x(x+61)=66(x+1) \\
\Leftrightarrow x^2+61x=66x+66 \\
\Leftrightarrow x^2-5x-66=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2-5x-66=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-5)^2-4.1.(-66) & &\\
& = 25+264 & & \\
& = 289 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-(-5)-\sqrt289}{2.1} & & = \frac{-(-5)+\sqrt289}{2.1} \\
& = \frac{-12}{2} & & = \frac{22}{2} \\
& = -6 & & = 11 \\ \\ V &= \Big\{ -6 ; 11 \Big\} & &\end{align} \\ -----------------\)
- \(x(x+15)=5(x-5) \\
\Leftrightarrow x^2+15x=5x-25 \\
\Leftrightarrow x^2+10x+25=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+10x+25=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (10)^2-4.1.25 & &\\
& = 100-100 & & \\
& = 0 & & \\ x & = \frac{-b\pm \sqrt{D}}{2.a} & & \\
& = \frac{-10}{2.1} & & \\
& = -5 & & \\V &= \Big\{ -5 \Big\} & &\end{align} \\ -----------------\)
- \(x(16x+7)=-49(x+1) \\
\Leftrightarrow 16x^2+7x=-49x-49 \\
\Leftrightarrow 16x^2+56x+49=0 \\\text{We zoeken de oplossingen van } \color{blue}{16x^2+56x+49=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (56)^2-4.16.49 & &\\
& = 3136-3136 & & \\
& = 0 & & \\ x & = \frac{-b\pm \sqrt{D}}{2.a} & & \\
& = \frac{-56}{2.16} & & \\
& = -\frac{7}{4} & & \\V &= \Big\{ -\frac{7}{4} \Big\} & &\end{align} \\ -----------------\)
- \(-(2-39x)=-4x^2-(38-14x) \\
\Leftrightarrow -2+39x=-4x^2-38+14x \\
\Leftrightarrow 4x^2+25x+36=0 \\\text{We zoeken de oplossingen van } \color{blue}{4x^2+25x+36=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (25)^2-4.4.36 & &\\
& = 625-576 & & \\
& = 49 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-25-\sqrt49}{2.4} & & = \frac{-25+\sqrt49}{2.4} \\
& = \frac{-32}{8} & & = \frac{-18}{8} \\
& = -4 & & = \frac{-9}{4} \\ \\ V &= \Big\{ -4 ; \frac{-9}{4} \Big\} & &\end{align} \\ -----------------\)
- \(\frac{11}{4}x=-\frac{1}{4}x^2-7 \\
\Leftrightarrow \frac{1}{4}x^2+\frac{11}{4}x+7=0 \\
\Leftrightarrow \color{red}{4.} \left(\frac{1}{4}x^2+\frac{11}{4}x+7\right)=0 \color{red}{.4} \\
\Leftrightarrow x^2+11x+28=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+11x+28=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (11)^2-4.1.28 & &\\
& = 121-112 & & \\
& = 9 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-11-\sqrt9}{2.1} & & = \frac{-11+\sqrt9}{2.1} \\
& = \frac{-14}{2} & & = \frac{-8}{2} \\
& = -7 & & = -4 \\ \\ V &= \Big\{ -7 ; -4 \Big\} & &\end{align} \\ -----------------\)
- \(x(16x-9)=-(x+1) \\
\Leftrightarrow 16x^2-9x=-x-1 \\
\Leftrightarrow 16x^2-8x+1=0 \\\text{We zoeken de oplossingen van } \color{blue}{16x^2-8x+1=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-8)^2-4.16.1 & &\\
& = 64-64 & & \\
& = 0 & & \\ x & = \frac{-b\pm \sqrt{D}}{2.a} & & \\
& = \frac{-(-8)}{2.16} & & \\
& = \frac{1}{4} & & \\V &= \Big\{ \frac{1}{4} \Big\} & &\end{align} \\ -----------------\)
- \((-3x-3)(-5x+2)-x(14x-3)=-14\\
\Leftrightarrow 15x^2-6x+15x-6 -14x^2+3x+14=0 \\
\Leftrightarrow x^2-9x+8=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2-9x+8=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-9)^2-4.1.8 & &\\
& = 81-32 & & \\
& = 49 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-(-9)-\sqrt49}{2.1} & & = \frac{-(-9)+\sqrt49}{2.1} \\
& = \frac{2}{2} & & = \frac{16}{2} \\
& = 1 & & = 8 \\ \\ V &= \Big\{ 1 ; 8 \Big\} & &\end{align} \\ -----------------\)
- \(x(2x+79)=72(x+1) \\
\Leftrightarrow 2x^2+79x=72x+72 \\
\Leftrightarrow 2x^2+7x-72=0 \\\text{We zoeken de oplossingen van } \color{blue}{2x^2+7x-72=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (7)^2-4.2.(-72) & &\\
& = 49+576 & & \\
& = 625 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-7-\sqrt625}{2.2} & & = \frac{-7+\sqrt625}{2.2} \\
& = \frac{-32}{4} & & = \frac{18}{4} \\
& = -8 & & = \frac{9}{2} \\ \\ V &= \Big\{ -8 ; \frac{9}{2} \Big\} & &\end{align} \\ -----------------\)
- \(-(14-10x)=-x^2-(18-8x) \\
\Leftrightarrow -14+10x=-x^2-18+8x \\
\Leftrightarrow x^2+2x+4=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+2x+4=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (2)^2-4.1.4 & &\\
& = 4-16 & & \\
& = -12 & & \\ & < 0 \\V &= \varnothing \end{align} \\ -----------------\)
- \(x(x+20)=4(x-16) \\
\Leftrightarrow x^2+20x=4x-64 \\
\Leftrightarrow x^2+16x+64=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+16x+64=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (16)^2-4.1.64 & &\\
& = 256-256 & & \\
& = 0 & & \\ x & = \frac{-b\pm \sqrt{D}}{2.a} & & \\
& = \frac{-16}{2.1} & & \\
& = -8 & & \\V &= \Big\{ -8 \Big\} & &\end{align} \\ -----------------\)
- \(-(13-15x)=-x^2-(29-5x) \\
\Leftrightarrow -13+15x=-x^2-29+5x \\
\Leftrightarrow x^2+10x+16=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2+10x+16=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (10)^2-4.1.16 & &\\
& = 100-64 & & \\
& = 36 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-10-\sqrt36}{2.1} & & = \frac{-10+\sqrt36}{2.1} \\
& = \frac{-16}{2} & & = \frac{-4}{2} \\
& = -8 & & = -2 \\ \\ V &= \Big\{ -8 ; -2 \Big\} & &\end{align} \\ -----------------\)
- \(-(2-x)=-x^2-(-54-2x) \\
\Leftrightarrow -2+x=-x^2+54+2x \\
\Leftrightarrow x^2-x-56=0 \\\text{We zoeken de oplossingen van } \color{blue}{x^2-x-56=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (-1)^2-4.1.(-56) & &\\
& = 1+224 & & \\
& = 225 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-(-1)-\sqrt225}{2.1} & & = \frac{-(-1)+\sqrt225}{2.1} \\
& = \frac{-14}{2} & & = \frac{16}{2} \\
& = -7 & & = 8 \\ \\ V &= \Big\{ -7 ; 8 \Big\} & &\end{align} \\ -----------------\)