Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{3}\right)+\left(\frac{-9}{4}\right)\)
2. \(+\left(\frac{-13}{-2}\right)+\left(\frac{-9}{-14}\right)\)
3. \(+\left(\frac{3}{-13}\right)+\left(\frac{-15}{7}\right)\)
4. \(+\left(\frac{-9}{7}\right)-\left(\frac{-5}{11}\right)\)
5. \(-\left(\frac{-5}{-2}\right)-\left(\frac{3}{13}\right)\)
6. \(-\left(\frac{-6}{5}\right)-\left(\frac{12}{5}\right)\)
7. \(-\left(\frac{3}{-2}\right)+\left(\frac{-6}{5}\right)\)
8. \(-\left(\frac{-7}{-2}\right)-\left(\frac{12}{7}\right)\)
9. \(+\left(\frac{3}{-7}\right)+\left(\frac{9}{-11}\right)\)
10. \(-\left(\frac{9}{-7}\right)+\left(\frac{7}{-13}\right)\)
11. \(+\left(\frac{13}{4}\right)+\left(\frac{-2}{-13}\right)\)
12. \(-\left(\frac{4}{11}\right)+\left(\frac{11}{8}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{10}{3}\right)+\left(\frac{-9}{4}\right)\\= \frac{10}{3}-\frac{9}{4}\\=\frac{40}{12}-\frac{27}{12}\\=\frac{40-27}{12}\\=\frac{13}{12}\)
2. \(+\left(\frac{-13}{-2}\right)+\left(\frac{-9}{-14}\right)\\= \frac{13}{2}+\frac{9}{14}\\=\frac{91}{14}+\frac{9}{14}\\=\frac{91+9}{14}\\=\frac{100}{14}\\=\frac{50}{7}\)
3. \(+\left(\frac{3}{-13}\right)+\left(\frac{-15}{7}\right)\\= \frac{-3}{13}-\frac{15}{7}\\=\frac{-21}{91}-\frac{195}{91}\\=\frac{-21-195}{91}\\=\frac{-216}{91}\)
4. \(+\left(\frac{-9}{7}\right)-\left(\frac{-5}{11}\right)\\= \frac{-9}{7}+\frac{5}{11}\\=\frac{-99}{77}+\frac{35}{77}\\=\frac{-99+35}{77}\\=\frac{-64}{77}\)
5. \(-\left(\frac{-5}{-2}\right)-\left(\frac{3}{13}\right)\\= \frac{-5}{2}-\frac{3}{13}\\=\frac{-65}{26}-\frac{6}{26}\\=\frac{-65-6}{26}\\=\frac{-71}{26}\)
6. \(-\left(\frac{-6}{5}\right)-\left(\frac{12}{5}\right)\\= \frac{6}{5}-\frac{12}{5}\\=\frac{6-12}{5}\\=\frac{-6}{5}\)
7. \(-\left(\frac{3}{-2}\right)+\left(\frac{-6}{5}\right)\\= \frac{3}{2}-\frac{6}{5}\\=\frac{15}{10}-\frac{12}{10}\\=\frac{15-12}{10}\\=\frac{3}{10}\)
8. \(-\left(\frac{-7}{-2}\right)-\left(\frac{12}{7}\right)\\= \frac{-7}{2}-\frac{12}{7}\\=\frac{-49}{14}-\frac{24}{14}\\=\frac{-49-24}{14}\\=\frac{-73}{14}\)
9. \(+\left(\frac{3}{-7}\right)+\left(\frac{9}{-11}\right)\\= \frac{-3}{7}-\frac{9}{11}\\=\frac{-33}{77}-\frac{63}{77}\\=\frac{-33-63}{77}\\=\frac{-96}{77}\)
10. \(-\left(\frac{9}{-7}\right)+\left(\frac{7}{-13}\right)\\= \frac{9}{7}-\frac{7}{13}\\=\frac{117}{91}-\frac{49}{91}\\=\frac{117-49}{91}\\=\frac{68}{91}\)
11. \(+\left(\frac{13}{4}\right)+\left(\frac{-2}{-13}\right)\\= \frac{13}{4}+\frac{2}{13}\\=\frac{169}{52}+\frac{8}{52}\\=\frac{169+8}{52}\\=\frac{177}{52}\)
12. \(-\left(\frac{4}{11}\right)+\left(\frac{11}{8}\right)\\= \frac{-4}{11}+\frac{11}{8}\\=\frac{-32}{88}+\frac{121}{88}\\=\frac{-32+121}{88}\\=\frac{89}{88}\)