Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{10}{13}\right)+\left(\frac{3}{-7}\right)\)
2. \(-\left(\frac{-10}{3}\right)-\left(\frac{-5}{11}\right)\)
3. \(-\left(\frac{8}{-13}\right)+\left(\frac{8}{-11}\right)\)
4. \(+\left(\frac{-14}{-9}\right)-\left(\frac{-3}{-4}\right)\)
5. \(-\left(\frac{-7}{-12}\right)-\left(\frac{-8}{-9}\right)\)
6. \(+\left(\frac{-2}{9}\right)-\left(\frac{10}{-3}\right)\)
7. \(+\left(\frac{11}{4}\right)-\left(\frac{-14}{-13}\right)\)
8. \(+\left(\frac{9}{10}\right)-\left(\frac{-6}{-7}\right)\)
9. \(-\left(\frac{8}{5}\right)+\left(\frac{-2}{7}\right)\)
10. \(+\left(\frac{7}{2}\right)+\left(\frac{5}{-11}\right)\)
11. \(-\left(\frac{-5}{-3}\right)+\left(\frac{8}{3}\right)\)
12. \(-\left(\frac{8}{-7}\right)-\left(\frac{-11}{-2}\right)\)

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Bereken

Verbetersleutel

1. \(+\left(\frac{10}{13}\right)+\left(\frac{3}{-7}\right)\\= \frac{10}{13}-\frac{3}{7}\\=\frac{70}{91}-\frac{39}{91}\\=\frac{70-39}{91}\\=\frac{31}{91}\)
2. \(-\left(\frac{-10}{3}\right)-\left(\frac{-5}{11}\right)\\= \frac{10}{3}+\frac{5}{11}\\=\frac{110}{33}+\frac{15}{33}\\=\frac{110+15}{33}\\=\frac{125}{33}\)
3. \(-\left(\frac{8}{-13}\right)+\left(\frac{8}{-11}\right)\\= \frac{8}{13}-\frac{8}{11}\\=\frac{88}{143}-\frac{104}{143}\\=\frac{88-104}{143}\\=\frac{-16}{143}\)
4. \(+\left(\frac{-14}{-9}\right)-\left(\frac{-3}{-4}\right)\\= \frac{14}{9}-\frac{3}{4}\\=\frac{56}{36}-\frac{27}{36}\\=\frac{56-27}{36}\\=\frac{29}{36}\)
5. \(-\left(\frac{-7}{-12}\right)-\left(\frac{-8}{-9}\right)\\= \frac{-7}{12}-\frac{8}{9}\\=\frac{-21}{36}-\frac{32}{36}\\=\frac{-21-32}{36}\\=\frac{-53}{36}\)
6. \(+\left(\frac{-2}{9}\right)-\left(\frac{10}{-3}\right)\\= \frac{-2}{9}+\frac{10}{3}\\=\frac{-2+10}{9}\\=\frac{8}{9}\)
7. \(+\left(\frac{11}{4}\right)-\left(\frac{-14}{-13}\right)\\= \frac{11}{4}-\frac{14}{13}\\=\frac{143}{52}-\frac{56}{52}\\=\frac{143-56}{52}\\=\frac{87}{52}\)
8. \(+\left(\frac{9}{10}\right)-\left(\frac{-6}{-7}\right)\\= \frac{9}{10}-\frac{6}{7}\\=\frac{63}{70}-\frac{60}{70}\\=\frac{63-60}{70}\\=\frac{3}{70}\)
9. \(-\left(\frac{8}{5}\right)+\left(\frac{-2}{7}\right)\\= \frac{-8}{5}-\frac{2}{7}\\=\frac{-56}{35}-\frac{10}{35}\\=\frac{-56-10}{35}\\=\frac{-66}{35}\)
10. \(+\left(\frac{7}{2}\right)+\left(\frac{5}{-11}\right)\\= \frac{7}{2}-\frac{5}{11}\\=\frac{77}{22}-\frac{10}{22}\\=\frac{77-10}{22}\\=\frac{67}{22}\)
11. \(-\left(\frac{-5}{-3}\right)+\left(\frac{8}{3}\right)\\= \frac{-5}{3}+\frac{8}{3}\\=\frac{-5+8}{3}\\=\frac{3}{3}\\=\frac{1}{1}\)
12. \(-\left(\frac{8}{-7}\right)-\left(\frac{-11}{-2}\right)\\= \frac{8}{7}-\frac{11}{2}\\=\frac{16}{14}-\frac{77}{14}\\=\frac{16-77}{14}\\=\frac{-61}{14}\)