Breuken haakjesregel (reeks 1)

Hoofdmenu Eentje per keer  🖨

Bereken

1. \(+\left(\frac{14}{9}\right)+\left(\frac{4}{5}\right)\)
2. \(-\left(\frac{-10}{3}\right)-\left(\frac{-7}{-9}\right)\)
3. \(-\left(\frac{7}{-5}\right)-\left(\frac{12}{-7}\right)\)
4. \(+\left(\frac{3}{-7}\right)-\left(\frac{-7}{3}\right)\)
5. \(-\left(\frac{-8}{-7}\right)-\left(\frac{-5}{-6}\right)\)
6. \(+\left(\frac{-12}{-5}\right)-\left(\frac{8}{3}\right)\)
7. \(-\left(\frac{-15}{-13}\right)-\left(\frac{-5}{-12}\right)\)
8. \(+\left(\frac{13}{9}\right)+\left(\frac{-14}{-13}\right)\)
9. \(+\left(\frac{13}{-8}\right)-\left(\frac{-6}{-11}\right)\)
10. \(-\left(\frac{-13}{5}\right)+\left(\frac{7}{-3}\right)\)
11. \(-\left(\frac{-7}{-8}\right)+\left(\frac{-12}{-7}\right)\)
12. \(-\left(\frac{10}{-13}\right)-\left(\frac{-14}{-3}\right)\)

---

Bereken

Verbetersleutel

1. \(+\left(\frac{14}{9}\right)+\left(\frac{4}{5}\right)\\= \frac{14}{9}+\frac{4}{5}\\=\frac{70}{45}+\frac{36}{45}\\=\frac{70+36}{45}\\=\frac{106}{45}\)
2. \(-\left(\frac{-10}{3}\right)-\left(\frac{-7}{-9}\right)\\= \frac{10}{3}-\frac{7}{9}\\=\frac{30}{9}-\frac{7}{9}\\=\frac{30-7}{9}\\=\frac{23}{9}\)
3. \(-\left(\frac{7}{-5}\right)-\left(\frac{12}{-7}\right)\\= \frac{7}{5}+\frac{12}{7}\\=\frac{49}{35}+\frac{60}{35}\\=\frac{49+60}{35}\\=\frac{109}{35}\)
4. \(+\left(\frac{3}{-7}\right)-\left(\frac{-7}{3}\right)\\= \frac{-3}{7}+\frac{7}{3}\\=\frac{-9}{21}+\frac{49}{21}\\=\frac{-9+49}{21}\\=\frac{40}{21}\)
5. \(-\left(\frac{-8}{-7}\right)-\left(\frac{-5}{-6}\right)\\= \frac{-8}{7}-\frac{5}{6}\\=\frac{-48}{42}-\frac{35}{42}\\=\frac{-48-35}{42}\\=\frac{-83}{42}\)
6. \(+\left(\frac{-12}{-5}\right)-\left(\frac{8}{3}\right)\\= \frac{12}{5}-\frac{8}{3}\\=\frac{36}{15}-\frac{40}{15}\\=\frac{36-40}{15}\\=\frac{-4}{15}\)
7. \(-\left(\frac{-15}{-13}\right)-\left(\frac{-5}{-12}\right)\\= \frac{-15}{13}-\frac{5}{12}\\=\frac{-180}{156}-\frac{65}{156}\\=\frac{-180-65}{156}\\=\frac{-245}{156}\)
8. \(+\left(\frac{13}{9}\right)+\left(\frac{-14}{-13}\right)\\= \frac{13}{9}+\frac{14}{13}\\=\frac{169}{117}+\frac{126}{117}\\=\frac{169+126}{117}\\=\frac{295}{117}\)
9. \(+\left(\frac{13}{-8}\right)-\left(\frac{-6}{-11}\right)\\= \frac{-13}{8}-\frac{6}{11}\\=\frac{-143}{88}-\frac{48}{88}\\=\frac{-143-48}{88}\\=\frac{-191}{88}\)
10. \(-\left(\frac{-13}{5}\right)+\left(\frac{7}{-3}\right)\\= \frac{13}{5}-\frac{7}{3}\\=\frac{39}{15}-\frac{35}{15}\\=\frac{39-35}{15}\\=\frac{4}{15}\)
11. \(-\left(\frac{-7}{-8}\right)+\left(\frac{-12}{-7}\right)\\= \frac{-7}{8}+\frac{12}{7}\\=\frac{-49}{56}+\frac{96}{56}\\=\frac{-49+96}{56}\\=\frac{47}{56}\)
12. \(-\left(\frac{10}{-13}\right)-\left(\frac{-14}{-3}\right)\\= \frac{10}{13}-\frac{14}{3}\\=\frac{30}{39}-\frac{182}{39}\\=\frac{30-182}{39}\\=\frac{-152}{39}\)