Breuken verm. (reeks 3)

Hoofdmenu Eentje per keer 

Vermenigvuldig de breuken

  1. \(\frac{12}{-5} . \left(\frac{7}{-3}\right).\left(\frac{8}{-5}\right)\)
  2. \(\frac{-2}{-7} . \left(\frac{11}{-2}\right).\left(\frac{-10}{5}\right)\)
  3. \(\frac{12}{-7} . \left(\frac{5}{-9}\right).\frac{11}{9}\)
  4. \(\frac{-2}{-17} . \frac{6}{10}.\left(\frac{-9}{-8}\right)\)
  5. \(\frac{-10}{-17} . \left(\frac{6}{-8}\right).\left(\frac{-5}{5}\right)\)
  6. \(\frac{2}{-11} . \left(\frac{-6}{-10}\right).\left(\frac{-9}{7}\right)\)
  7. \(\frac{-5}{-6} . \frac{10}{7}.\left(\frac{-5}{10}\right)\)
  8. \(\frac{3}{-16} . \left(\frac{-7}{12}\right).\frac{4}{2}\)
  9. \(\frac{5}{14} . \left(\frac{-3}{11}\right).\left(\frac{-4}{12}\right)\)
  10. \(\frac{6}{11} . \left(\frac{-11}{-8}\right).\left(\frac{-10}{8}\right)\)
  11. \(\frac{4}{-9} . \left(\frac{-2}{-8}\right).\left(\frac{-5}{-12}\right)\)
  12. \(\frac{12}{-5} . \left(\frac{-6}{10}\right).\frac{5}{5}\)

Vermenigvuldig de breuken

Verbetersleutel

  1. \(\frac{12}{-5} . \left(\frac{7}{-3}\right).\left(\frac{8}{-5}\right)\\=-\frac{12.7.8}{5.3.5}\\=-\frac{672}{75}\\=-\frac{224}{25}\)
  2. \(\frac{-2}{-7} . \left(\frac{11}{-2}\right).\left(\frac{-10}{5}\right)\\=+\frac{2}{7}.\frac{11}{2}.\frac{2}{1}\\=+\frac{2.11.2}{7.2.1}\\=\frac{44}{14}\\=\frac{22}{7}\)
  3. \(\frac{12}{-7} . \left(\frac{5}{-9}\right).\frac{11}{9}\\=+\frac{12.5.11}{7.9.9}\\=\frac{660}{567}\\=\frac{220}{189}\)
  4. \(\frac{-2}{-17} . \frac{6}{10}.\left(\frac{-9}{-8}\right)\\=+\frac{2}{17}.\frac{3}{5}.\frac{9}{8}\\=+\frac{2.3.9}{17.5.8}\\=\frac{54}{680}\\=\frac{27}{340}\)
  5. \(\frac{-10}{-17} . \left(\frac{6}{-8}\right).\left(\frac{-5}{5}\right)\\=+\frac{10}{17}.\frac{3}{4}.\frac{1}{1}\\=+\frac{10.3.1}{17.4.1}\\=\frac{30}{68}\\=\frac{15}{34}\)
  6. \(\frac{2}{-11} . \left(\frac{-6}{-10}\right).\left(\frac{-9}{7}\right)\\=+\frac{2}{11}.\frac{3}{5}.\frac{9}{7}\\=+\frac{2.3.9}{11.5.7}\\=\frac{54}{385}\)
  7. \(\frac{-5}{-6} . \frac{10}{7}.\left(\frac{-5}{10}\right)\\=-\frac{5}{6}.\frac{10}{7}.\frac{1}{2}\\=-\frac{5.10.1}{6.7.2}\\=-\frac{50}{84}\\=-\frac{25}{42}\)
  8. \(\frac{3}{-16} . \left(\frac{-7}{12}\right).\frac{4}{2}\\=+\frac{3}{16}.\frac{7}{12}.\frac{2}{1}\\=+\frac{3.7.2}{16.12.1}\\=\frac{42}{192}\\=\frac{7}{32}\)
  9. \(\frac{5}{14} . \left(\frac{-3}{11}\right).\left(\frac{-4}{12}\right)\\=+\frac{5}{14}.\frac{3}{11}.\frac{1}{3}\\=+\frac{5.3.1}{14.11.3}\\=\frac{15}{462}\\=\frac{5}{154}\)
  10. \(\frac{6}{11} . \left(\frac{-11}{-8}\right).\left(\frac{-10}{8}\right)\\=-\frac{6}{11}.\frac{11}{8}.\frac{5}{4}\\=-\frac{6.11.5}{11.8.4}\\=-\frac{330}{352}\\=-\frac{15}{16}\)
  11. \(\frac{4}{-9} . \left(\frac{-2}{-8}\right).\left(\frac{-5}{-12}\right)\\=-\frac{4}{9}.\frac{1}{4}.\frac{5}{12}\\=-\frac{4.1.5}{9.4.12}\\=-\frac{20}{432}\\=-\frac{5}{108}\)
  12. \(\frac{12}{-5} . \left(\frac{-6}{10}\right).\frac{5}{5}\\=+\frac{12}{5}.\frac{3}{5}.\frac{1}{1}\\=+\frac{12.3.1}{5.5.1}\\=\frac{36}{25}\)
Oefeningengenerator wiskundeoefeningen.be 2025-07-31 10:48:21
Een site van Busleyden Atheneum Mechelen