Breuken verm. (reeks 3)

Vermenigvuldig de breuken

\(\frac{8}{-9} . \left(\frac{-12}{3}\right).\frac{4}{5}\)

\(\frac{8}{-9} . \left(\frac{-12}{3}\right).\frac{4}{5}\\=+\frac{8}{9}.\frac{4}{1}.\frac{4}{5}\\=+\frac{8.4.4}{9.1.5}\\=\frac{128}{45}\)