Breuken verm. (reeks 3)

Vermenigvuldig de breuken

\(\frac{6}{-13} . \left(\frac{-7}{-7}\right).\left(\frac{7}{-10}\right)\)

\(\frac{6}{-13} . \left(\frac{-7}{-7}\right).\left(\frac{7}{-10}\right)\\=+\frac{6}{13}.\frac{1}{1}.\frac{7}{10}\\=+\frac{6.1.7}{13.1.10}\\=\frac{42}{130}\\=\frac{21}{65}\)