Gebruik de discriminant om volgende vierkantsvergelijkingen op te lossen
\(2x^2+21x+82=-4x+10\)
\(2x^2+21x+82=-4x+10\\
\Leftrightarrow 2x^2+25x+72=0 \\\text{We zoeken de oplossingen van } \color{blue}{2x^2+25x+72=0} \\ \\\begin{align}
D & = b^2 - 4.a.c & & \\
& = (25)^2-4.2.72 & &\\
& = 625-576 & & \\
& = 49 & & \\ \\
x_1 & = \frac{-b-\sqrt{D}}{2.a} & x_2 & = \frac{-b+\sqrt{D}}{2.a} \\
& = \frac{-25-\sqrt49}{2.2} & & = \frac{-25+\sqrt49}{2.2} \\
& = \frac{-32}{4} & & = \frac{-18}{4} \\
& = -8 & & = \frac{-9}{2} \\ \\ V &= \Big\{ -8 ; \frac{-9}{2} \Big\} & &\end{align} \\ -----------------\)